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Class 7 Mathematics Chapter 0 of 15

Ganita Prakash II · Chapter 3 — Finding Common Ground

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Overview

This chapter is about what numbers have in common. It begins with real problems: the largest square tile that fits a room exactly, and the heaviest equal bags that can hold rice from two farms. These lead to the Highest Common Factor (HCF), the greatest number that divides all the given numbers. Listing factors becomes slow for large numbers, so you revisit primes and learn the division method for prime factorisation, and see that every number has only one prime factorisation. From it you build every factor of a number and then find the HCF directly by taking shared primes the fewest number of times. Problems about cloth strips, sweet-shop visits and the idli-vada game lead to the Lowest Common Multiple (LCM), which you find by taking every prime the greatest number of times. You then explore patterns and make general statements, for example that consecutive numbers have HCF 1 and that doubling two numbers doubles their HCF. Finally, a quick ladder procedure gives the HCF and LCM together, and you discover that for two numbers HCF × LCM equals their product. Along the way you meet the ideas of conjecture, counterexample and generalisation.

हिंदी में पढ़ें

साझा आधार की खोज: महत्तम समापवर्तक (म.स.) और लघुत्तम समापवर्त्य (ल.स.), अभाज्य गुणनखंडन से शीघ्रता से ज्ञात करना।

Learning Objectives

  • Find common factors and the HCF of numbers and use them in real problems
  • Find the prime factorisation of a number using the division method
  • List all the factors of a number from its prime factorisation
  • Find the HCF using prime factorisation
  • Find common multiples and the LCM and recognise LCM situations
  • Find the LCM using prime factorisation
  • Make and test general statements about HCF and LCM
  • Use the ladder procedure and the relation HCF × LCM = product of two numbers
  • Use the words conjecture, counterexample and generalisation correctly

Topics in this chapter

8 topics · tap a topic title to jump straight to it.

Topic 1 of 8
🔢1

Common factors and the HCF

By the end you canFind common factors and the HCF, and use it in sharing and tiling problems.

1Think first

What is the biggest square tile that can cover a 12 ft by 16 ft floor exactly?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Sameeksha wants to tile a room 12 ft wide and 16 ft long with square tiles, all the same size, with sides a whole number of feet. She wants as few tiles as possible. What size should she buy?

For tiles to fit the 12 ft side exactly, the tile side must divide 12. For the 16 ft side, it must divide 16. So the side must be a common factor of 12 and 16.

NumberFactors
121, 2, 3, 4, 6, 12
161, 2, 4, 8, 16
Common1, 2, 4

The tile could be 1 ft, 2 ft or 4 ft. The bigger the tile, the fewer tiles are needed, so she picks 4 ft. Along the width there are 12 ÷ 4 = 3 tiles and along the length 16 ÷ 4 = 4 tiles, so 3 × 4 = 12 tiles in all.

The HCF. The Highest Common Factor (HCF) of two or more numbers is the greatest of their common factors. It is also called the Greatest Common Divisor (GCD). Here the HCF of 12 and 16 is 4.

Another example. Lekhana buys 84 kg of rice from one farm and 108 kg from another. She packs it into bags of equal whole-number weight, each bag from one farm only, using as few bags as possible. The bag weight must be a common factor of 84 and 108: 1, 2, 3, 4, 6 or 12 kg. The fewest bags come from the heaviest weight, 12 kg, which is the HCF. She needs 84 ÷ 12 = 7 bags and 108 ÷ 12 = 9 bags, that is 16 bags.

Jumps on a number line. If treasures lie on 14 and 30, the longest jump from 0 that lands on both must divide both numbers, so it is the HCF, 2. For 28 and 42 it is 14, and for 7 and 11 it is only 1.

Why listing is not enough. Listing every factor works for small numbers, but it is slow for numbers such as 840, which has 32 factors, and it is easy to miss one. In the next topics we find a faster and more reliable way using primes.

Formulas to remember
  1. HCF = greatest common factor (also called GCD)
  2. Number of square tiles = (length ÷ HCF) × (breadth ÷ HCF)
Whena length must be cut into equal whole pieces that fit two sizesThenthe piece size is a common factor
Whenwe want the fewest piecesThenchoose the HCF

3Worked example

Find the HCF of 30 and 50 by listing factors.
Step 1Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30.
Step 2Factors of 50: 1, 2, 5, 10, 25, 50.
Step 3Common factors: 1, 2, 5, 10. The HCF is 10.
More examples
  • HCF of 12 and 16 is 4: twelve tiles of 4 ft cover a 12 ft × 16 ft room.
  • HCF of 84 and 108 is 12: 7 + 9 = 16 bags.
  • HCF of 28 and 42 is 14.

4Your turn

What is the HCF of 84 and 108?

5Remember this

One line to keepThe HCF is the largest number that divides all the given numbers exactly.
Common mistake. Picking the smallest common factor (1) or the largest factor of only one number.
Topic 2 of 8
🔢2

Primes and prime factorisation

By the end you canFind the prime factorisation of a number using the division method.

1Think first

If two classmates factorise 90 in different ways, will they end with the same primes?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

A prime is a number greater than 1 whose only factors are 1 and itself: 2, 3, 5, 7, 11, 13, and so on. A number greater than 1 that is not prime is composite. The number 1 is neither.

Prime factorisation. Every composite number can be written as a product of primes. Keep breaking any composite factor until only primes are left. For 90: 90 = 9 × 10 = 3 × 3 × 2 × 5. We could also start with 3 × 30 or 2 × 45, but we always end with the same primes, 2, 3, 3 and 5, only in a different order. This is a remarkable fact: every number has exactly one prime factorisation, apart from order.

The division method. Divide by a prime, write the quotient below, and repeat until the quotient is prime.

Divide byNumber
21200
2600
2300
2150
375
525
5

So 1200 = 2 × 2 × 2 × 2 × 3 × 5 × 5. Reading the primes down the left side and the last number at the bottom gives the factorisation. This is quicker and safer than splitting 1200 as 40 × 30 = 5 × 8 × 5 × 6 and then breaking 8 and 6 again.

Tips for the division method. Try the small primes in order: 2 while the number is even, then 3 (digit sum divisible by 3), then 5 (ends in 0 or 5), then 7, 11 and so on. Stop when the last quotient is prime. For 105: 105 ÷ 3 = 35, 35 ÷ 5 = 7, so 105 = 3 × 5 × 7.

Bigger is not always longer. Anshu guessed: ‘the larger a number, the longer its prime factorisation’. But 96 = 2 × 2 × 2 × 2 × 2 × 3 has six primes while the larger number 121 = 11 × 11 has only two. A statement made without proof is called a conjecture. One example that shows it is false is a counterexample, and one counterexample is enough to disprove a conjecture.

The prime factorisation of a prime number is just the number itself, for example 13 = 13.

Formulas to remember
  1. Every number greater than 1 has exactly one prime factorisation (apart from order)
Whena number is split in different waysThenthe final prime factors are always the same
Whenone example breaks a claimThenthe claim (conjecture) is false

3Worked example

Find the prime factorisation of 840.
Step 1840 ÷ 2 = 420, 420 ÷ 2 = 210, 210 ÷ 2 = 105.
Step 2105 ÷ 3 = 35, 35 ÷ 5 = 7, and 7 is prime.
Step 3So 840 = 2 × 2 × 2 × 3 × 5 × 7.
More examples
  • 90 = 2 × 3 × 3 × 5.
  • 1200 = 2 × 2 × 2 × 2 × 3 × 5 × 5.
  • 96 has six prime factors but 121 has only two.

4Your turn

Which is the prime factorisation of 60?

5Remember this

One line to keepEvery number breaks into primes in exactly one way; the division method finds them reliably.
Common mistake. Stopping with a composite factor such as 4 or 15 still in the list.
Topic 3 of 8
🔢3

Finding all factors from the prime factorisation

By the end you canList all the factors of a number from its prime factorisation and test whether a number is a factor.

1Think first

Can you tell whether 27 divides 840 without dividing?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

The prime factorisation of a number is like a box of building blocks: every factor of the number is built from some of those blocks. We call such a selection a subpart of the factorisation.

Example. 840 = 2 × 2 × 2 × 3 × 5 × 7. Is 28 = 2 × 2 × 7 a factor? Regroup the primes: 840 = (2 × 2 × 7) × (2 × 3 × 5) = 28 × 30. So 28 is a factor, and the leftover primes give the partner factor 30.

Is 2 × 2 × 2 = 8 a factor of 840? Yes, there are three 2s available. Is 3 × 3 × 3 = 27 a factor? No: 840 has only one 3, so we cannot pick three of them.

Listing every factor of 225. 225 = 3 × 3 × 5 × 5. Build subparts in order of size:

Number of primes usedFactors
none1
one3, 5
two3 × 3 = 9, 3 × 5 = 15, 5 × 5 = 25
three3 × 3 × 5 = 45, 3 × 5 × 5 = 75
four3 × 3 × 5 × 5 = 225

So the factors of 225 are 1, 3, 5, 9, 15, 25, 45, 75 and 225, nine in all. Because we built them systematically, we cannot miss one.

A neat way to count. From 3 × 3 we may take no 3, one 3 or two 3s: 3 choices. From 5 × 5 we also have 3 choices. Every combination gives a different factor, so 225 has 3 × 3 = 9 factors. In the same way 840 = 2 × 2 × 2 × 3 × 5 × 7 has 4 × 2 × 2 × 2 = 32 factors, and 360 = 2 × 2 × 2 × 3 × 3 × 5 has 4 × 3 × 2 = 24 factors.

Why it matters. If a factor of a number must use only its own primes, then a factor common to two numbers must be built from primes that both numbers share. This is the key idea behind finding the HCF quickly in the next topic.

Formulas to remember
  1. A factor of n uses only primes from n's factorisation, each at most as often as it appears
Whena number uses only primes present in n, no more times than they appearThenit is a factor of n
Whena number needs a prime more times than n has itThenit is not a factor of n

3Worked example

List all the factors of 90 using 90 = 2 × 3 × 3 × 5.
Step 1With no 2: from 3 × 3 × 5 the subparts are 1, 3, 5, 9, 15, 45.
Step 2With the 2: double each one to get 2, 6, 10, 18, 30, 90.
Step 3So the 12 factors of 90 are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
More examples
  • 840 = 28 × 30, since (2 × 2 × 7) × (2 × 3 × 5).
  • 27 is not a factor of 840: 840 has only one 3.
  • Factors of 225: 1, 3, 5, 9, 15, 25, 45, 75, 225.

4Your turn

Using 840 = 2 × 2 × 2 × 3 × 5 × 7, which is NOT a factor of 840?

5Remember this

One line to keepEvery factor is a subpart of the prime factorisation; build subparts systematically to list them all.
Common mistake. Forgetting the factors 1 and the number itself when listing.
Topic 4 of 8
🔢4

HCF using prime factorisation

By the end you canFind the HCF of two or more numbers from their prime factorisations.

1Think first

If 30 has only one 2, can the HCF of 30 and 72 have two 2s?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

A common factor of two numbers must be a subpart of both factorisations. The HCF is the largest such common subpart.

Example 1: 45 and 75. 45 = 3 × 3 × 5 and 75 = 3 × 5 × 5. The common subparts are 3, 5 and 3 × 5. With 1, the common factors are 1, 3, 5 and 15. The HCF is 15.

Example 2: 112 and 84. 112 = 2 × 2 × 2 × 2 × 7 and 84 = 2 × 2 × 3 × 7. The common subparts are 2, 7, 2 × 2, 2 × 7 and 2 × 2 × 7. The HCF is 2 × 2 × 7 = 28.

Example 3: 96 and 275. 96 = 2 × 2 × 2 × 2 × 2 × 3 and 275 = 5 × 5 × 11. They share no prime, so the only common factor is 1. Numbers whose HCF is 1 are called co-prime.

A direct rule. We need not list all the common subparts. Take each prime that appears in both numbers, as many times as it appears in the number that has fewer of it.

NumbersFactorisationsCommon primes, fewest timesHCF
30, 722 × 3 × 5; 2 × 2 × 2 × 3 × 3one 2, one 36
225, 7503 × 3 × 5 × 5; 2 × 3 × 5 × 5 × 5one 3, two 5s75
24, 1802 × 2 × 2 × 3; 2 × 2 × 3 × 3 × 5two 2s, one 312

Why the fewest? For 30 and 72, the HCF cannot contain two 2s, because 30 has only one 2. So it gets one 2. The same reasoning applies to every prime.

Three or more numbers. Use the same rule across all the numbers. For 42, 75 and 24: 42 = 2 × 3 × 7, 75 = 3 × 5 × 5, 24 = 2 × 2 × 2 × 3. Only 3 is in all three, once, so the HCF is 3.

A trap. 72 = 6 × 12 and 144 = 8 × 18 look as if they share nothing. But 6, 12, 8 and 18 are not primes. Breaking them down shows 72 = 2 × 2 × 2 × 3 × 3 and 144 = 2 × 2 × 2 × 2 × 3 × 3, with HCF 72. Always go all the way to primes.

Formulas to remember
  1. HCF = product of common primes, each taken the fewest times it appears
Whena prime appears in both factorisationsThentake it as many times as in the number with fewer of it
Whenthe numbers share no primeThenthe HCF is 1 and the numbers are co-prime

3Worked example

Find the HCF of 240 and 378.
Step 1240 = 2 × 2 × 2 × 2 × 3 × 5 and 378 = 2 × 3 × 3 × 3 × 7.
Step 2Common primes: 2 (fewest one time) and 3 (fewest one time).
Step 3HCF = 2 × 3 = 6.
More examples
  • HCF(45, 75) = 15.
  • HCF(112, 84) = 28.
  • HCF(96, 275) = 1: they are co-prime.

4Your turn

What is the HCF of 225 and 750?

5Remember this

One line to keepFor the HCF, keep only the shared primes, each as many times as the smaller count.
Common mistake. Taking each prime the largest number of times, which gives the LCM, not the HCF.
Topic 5 of 8
✖️5

Common multiples and the LCM

By the end you canFind common multiples and the LCM, and recognise LCM problems.

1Think first

Two lights blink every 6 and every 8 seconds. When will they next blink together?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Anshu stitches torans from cloth strips 6 cm long, and Guna from strips 8 cm long. They want to make torans of the same length. What is the shortest such length?

Anshu's torans can be 6, 12, 18, 24, 30, 36, 42, 48 cm, and so on: the multiples of 6. Guna's can be 8, 16, 24, 32, 40, 48 cm, and so on: the multiples of 8. Lengths in both lists are common multiples: 24, 48, 72, and so on. The shortest is 24 cm.

The LCM. The Lowest Common Multiple (LCM) of two or more numbers is the smallest of their common multiples. The LCM of 6 and 8 is 24. Notice that there is no largest common multiple, because the list goes on for ever.

Free gajak. A sweet shop gives free gajak every Monday, that is every 7 days. Kabamai visits every 10 days, and both happened today. Shop days come after 7, 14, 21, … days; her visits after 10, 20, 30, … days. They first coincide after 70 days, the LCM of 7 and 10.

The idli-vada game. Players count 1, 2, 3, … and say ‘idli’ on multiples of one number and ‘vada’ on multiples of the other. The first time they must say ‘idli-vada’ is at the LCM.

IdliVadaFirst ‘idli-vada’ (LCM)
4612
71177
1430210

HCF or LCM? A useful check is the size of the answer. Cutting or sharing into equal parts gives an answer that is no larger than the numbers: think HCF. Things repeating until they line up again give an answer that is no smaller than the numbers: think LCM.

Listing multiples is fine for small numbers, but for 14 and 30 you must go to 210. Prime factorisation gives the LCM much faster, as the next topic shows.

Formulas to remember
  1. LCM = lowest common multiple
  2. Sharing into equal parts → HCF; repeating events lining up → LCM
Whentwo things repeat at different intervalsThenthey meet again after the LCM of the intervals
Whenthe answer must be divisible by each given numberThenlook for a common multiple, usually the LCM

3Worked example

Two bells ring every 12 and 18 minutes. They ring together at 9:00. When do they next ring together?
Step 1Multiples of 12: 12, 24, 36, 48, …
Step 2Multiples of 18: 18, 36, 54, …
Step 3The first common multiple is 36, so they ring together again at 9:36.
More examples
  • LCM of 6 and 8 is 24: the shortest common toran.
  • LCM of 7 and 10 is 70 days.
  • LCM of 4 and 6 is 12.

4Your turn

What is the LCM of 7 and 10?

5Remember this

One line to keepThe LCM is the smallest number that all the given numbers divide into exactly.
Common mistake. Mixing up the LCM with the HCF when deciding which a problem needs.
Topic 6 of 8
🔢6

LCM using prime factorisation

By the end you canFind the LCM of two or more numbers from their prime factorisations.

1Think first

What must every common multiple of 14 and 35 contain?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

A multiple of a number contains all the primes of that number, plus possibly more. For example 36 = 2 × 2 × 3 × 3, and its multiple 648 = 36 × 18 = (2 × 2 × 3 × 3) × (2 × 3 × 3). The factorisation of 36 sits inside the factorisation of 648.

So a common multiple of two numbers must contain the whole factorisation of each. The LCM is the smallest product that does this.

Example: 14 and 35. 14 = 2 × 7 and 35 = 5 × 7. We need 2 × 7 inside, and 5 × 7 inside. The product 2 × 5 × 7 = 70 contains both, sharing the single 7. Removing any prime would lose one of them, so the LCM is 70. Products such as 2 × 7 × 5 × 7 × 3 are also common multiples, but larger.

A direct rule. For each prime that appears in either number, take it as many times as it appears in the number that has more of it.

Example: 96 and 360.

PrimeIn 96In 360Take
2five timesthree timesfive
3oncetwicetwo
5noneonceone

LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5 = 1440. Fewer 2s would not contain 96; more would make a larger common multiple.

Compare with the HCF. For 30 = 2 × 3 × 5 and 72 = 2 × 2 × 2 × 3 × 3: the HCF takes the fewest of each shared prime, 2 × 3 = 6. The LCM takes the most of every prime, 2 × 2 × 2 × 3 × 3 × 5 = 360.

Three numbers. The rule works for any number of values. For 105 = 3 × 5 × 7, 195 = 3 × 5 × 13 and 65 = 5 × 13, take 3, 5, 7 and 13 once each: LCM = 1365.

Using answers as primes. It is often fine to leave an LCM in factorised form, such as 2⁵ × 3² × 5, when a question asks for it that way.

Formulas to remember
  1. LCM = product of all primes, each taken the most times it appears
  2. HCF takes the fewest; LCM takes the most
Whena prime appears in either numberThenthe LCM takes it as many times as in the number with more of it
Whena number is a multiple of nThenits prime factorisation contains n's factorisation

3Worked example

Find the LCM of 36 and 54.
Step 136 = 2 × 2 × 3 × 3 and 54 = 2 × 3 × 3 × 3.
Step 2Most 2s: two (from 36). Most 3s: three (from 54).
Step 3LCM = 2 × 2 × 3 × 3 × 3 = 108.
More examples
  • LCM(14, 35) = 2 × 5 × 7 = 70.
  • LCM(96, 360) = 1440.
  • LCM(30, 72) = 360.

4Your turn

Which is the LCM of 2 × 2 × 3 and 2 × 3 × 3?

5Remember this

One line to keepFor the LCM, take every prime that appears, each as many times as the larger count.
Common mistake. Multiplying the two numbers and calling the product the LCM.
Topic 7 of 8
🧬7

Patterns and general statements about HCF and LCM

By the end you canDiscover, test and explain general statements about HCF and LCM.

1Think first

What is the HCF of any two numbers that differ by 1?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Mathematicians look for patterns and then try to explain them. A statement that holds in all cases is a general statement, and finding one is called generalisation.

When one number divides the other. The HCF of 6 and 18 is 6, and the LCM is 18. In general, for a number n and a multiple of it such as 5n, the HCF is n and the LCM is 5n. The HCF is the smaller number and the LCM is the larger.

More patterns to test with examples.

Pair of numbersHCFLCM
Two consecutive numbers, e.g. 8 and 91their product, 72
Two consecutive even numbers, e.g. 10 and 122half the product, 60
Two co-prime numbers, e.g. 4 and 91their product, 36
Two consecutive odd numbers, e.g. 15 and 171their product, 255

Why is the HCF of two consecutive numbers always 1? Any common factor would also divide their difference, which is 1. The same idea shows that two consecutive odd numbers, which differ by 2 and are both odd, also have HCF 1.

Doubling. If both numbers are doubled, each gets one extra 2 in its factorisation, and that 2 goes into the HCF. So the HCF doubles too. For 270 and 50, the HCF is 10; for 540 and 100, it is 20.

A shared multiplier. 14 × 6 and 14 × 9 clearly have 14 as a common factor. But 6 and 9 still share a 3, so the HCF is 14 × 3 = 42, not 14. The HCF equals the shared multiplier only when the leftover numbers are co-prime, as in 10 × 38 and 10 × 21, where the HCF is 10.

LCM and the product. The product of two numbers is always a common multiple, so the LCM is never larger than the product. It equals the product exactly when the numbers are co-prime.

Formulas to remember
  1. If a divides b: HCF = a, LCM = b
  2. Consecutive numbers: HCF = 1, LCM = product
  3. Doubling both numbers doubles the HCF
Whentwo numbers are co-primeThentheir HCF is 1 and their LCM is their product
Whenboth numbers are doubledThenthe HCF doubles

3Worked example

Find the HCF of 18 × 10 and 18 × 15 without multiplying out.
Step 118 is a common factor.
Step 2The leftover numbers 10 and 15 share a 5.
Step 3So the HCF is 18 × 5 = 90.
More examples
  • HCF(n, 5n) = n and LCM(n, 5n) = 5n.
  • HCF(270, 50) = 10 and HCF(540, 100) = 20.
  • HCF(14 × 6, 14 × 9) = 42.

4Your turn

What is the HCF of two consecutive even numbers such as 14 and 16?

5Remember this

One line to keepTest patterns with examples, then explain them using prime factors or differences.
Common mistake. Assuming the HCF of k × a and k × b is always k, without checking whether a and b share a factor.
Topic 8 of 8
➕8

A quick ladder for HCF and LCM, and HCF × LCM

By the end you canUse the division ladder to find HCF and LCM together, and use HCF × LCM = product.

1Think first

Can one short table give both the HCF and the LCM?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Here is an efficient way to get the HCF and the LCM together. Write the two numbers side by side and keep dividing both by a common factor until the two quotients share no factor.

Divide byNumbers
284, 180
242, 90
321, 45
7, 15

HCF = the product of the divisors on the left: 2 × 2 × 3 = 12.
LCM = the divisors on the left times the two numbers at the bottom: 2 × 2 × 3 × 7 × 15 = 1260.

Why it works. The left column collects exactly the primes the two numbers share, so it is the HCF. The bottom row holds the primes that belong to only one number. The LCM needs the shared part once plus all the leftover parts, which is exactly the left column times the bottom row.

Bigger steps are allowed. You need not divide by primes only. For 630 and 770, divide both by 10 to get 63 and 77, then by 7 to get 9 and 11, which share nothing. HCF = 10 × 7 = 70 and LCM = 10 × 7 × 9 × 11 = 6930. For 300 and 150, divide by 50 and then by 3 to reach 2 and 1, so HCF = 150 and LCM = 300.

A beautiful relation. For 105 = 3 × 5 × 7 and 95 = 5 × 19, the LCM is 3 × 5 × 7 × 19 = 1995 and the HCF is 5. The product 105 × 95 = 9975 = 1995 × 5. In general:

For any two numbers a and b
HCF × LCM = a × b

The reason is that, in the product, every shared prime appears twice and every unshared prime once. The HCF takes one copy of the shared primes and the LCM takes the other copy along with all the unshared ones. Check: for 12 and 18, HCF 6 × LCM 36 = 216 = 12 × 18.

Careful. This relation is for two numbers. For three numbers it usually fails.

Formulas to remember
  1. HCF = product of the ladder divisors
  2. LCM = ladder divisors × bottom numbers
  3. HCF × LCM = a × b (two numbers only)
Whenthe bottom pair in the ladder share no factorThenstop: the left column gives the HCF
Whenthe HCF and one number are knownThenthe LCM can be found from HCF × LCM = a × b

3Worked example

The HCF of two numbers is 6 and their product is 216. Find their LCM.
Step 1Use HCF × LCM = product of the numbers.
Step 26 × LCM = 216.
Step 3LCM = 216 ÷ 6 = 36.
More examples
  • Ladder for 84 and 180: HCF 12, LCM 1260.
  • 630 and 770: HCF 70, LCM 6930.
  • 105 × 95 = 9975 = HCF 5 × LCM 1995.

4Your turn

In a ladder for 18 and 24, the divisors are 2 and 3 and the bottom pair is 3, 4. What is the LCM?

5Remember this

One line to keepThe ladder gives the HCF from its left column and the LCM by also multiplying the bottom row.
Common mistake. Using HCF × LCM = product for three numbers.

Key Concepts

Factor
A number that divides another number exactly.
Common factor
A number that is a factor of each of the given numbers.
HCF (GCD)
The highest common factor of two or more numbers.
Prime number
A number greater than 1 whose only factors are 1 and itself.
Composite number
A number greater than 1 that has more than two factors.
Prime factorisation
Writing a number as a product of primes; it is unique apart from order.
Division method
Repeatedly dividing by primes to find the prime factorisation.
Subpart
A selection of primes from a prime factorisation; its product is a factor.
Co-prime numbers
Numbers whose HCF is 1.
Multiple
A number obtained by multiplying a given number by a counting number.
Common multiple
A number that is a multiple of each of the given numbers.
LCM
The lowest common multiple of two or more numbers.
Conjecture
A statement believed to be true but not yet proved.
Counterexample
An example that shows a statement is false.
Generalisation
Finding a statement that holds in all cases of a pattern.
HCF × LCM rule
For two numbers, HCF × LCM equals the product of the numbers.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. Find the largest square tile that exactly covers a 12 ft by 16 ft floor, and the number of tiles. / 12 ft × 16 ft के फ़र्श को पूरा ढकने वाली सबसे बड़ी वर्गाकार टाइल और टाइलों की संख्या ज्ञात कीजिए।
    Show answer

    The tile side is the HCF of 12 and 16, which is 4 ft, and the number of tiles is 3 × 4 = 12. / टाइल की भुजा 12 और 16 का म.स. (HCF) है, जो 4 ft है, और टाइलों की संख्या 3 × 4 = 12 है।

  2. Write the prime factorisation of 1200 by the division method. / भाग विधि से 1200 का अभाज्य गुणनखंडन लिखिए।
    Show answer

    Dividing by 2 four times, then by 3 and 5, gives 1200 = 2 × 2 × 2 × 2 × 3 × 5 × 5. / 2 से चार बार, फिर 3 और 5 से भाग देने पर 1200 = 2 × 2 × 2 × 2 × 3 × 5 × 5 मिलता है।

  3. List all the factors of 225 using its prime factorisation. / अभाज्य गुणनखंडन से 225 के सभी गुणनखंड लिखिए।
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    Since 225 = 3 × 3 × 5 × 5, its factors are 1, 3, 5, 9, 15, 25, 45, 75 and 225. / क्योंकि 225 = 3 × 3 × 5 × 5, इसके गुणनखंड 1, 3, 5, 9, 15, 25, 45, 75 और 225 हैं।

  4. Show that Anshu's claim ‘a larger number has a longer prime factorisation’ is false. / दर्शाइए कि अंशु का दावा ‘बड़ी संख्या का अभाज्य गुणनखंडन लंबा होता है’ गलत है।
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    96 = 2 × 2 × 2 × 2 × 2 × 3 has six primes, while the larger 121 = 11 × 11 has only two, so this counterexample disproves the claim. / 96 = 2 × 2 × 2 × 2 × 2 × 3 में छह अभाज्य हैं, जबकि बड़ी संख्या 121 = 11 × 11 में केवल दो हैं, अतः यह प्रति-उदाहरण दावे को गलत सिद्ध करता है।

  5. Find the HCF of 30 and 72 using prime factorisation. / अभाज्य गुणनखंडन से 30 और 72 का म.स. ज्ञात कीजिए।
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    30 = 2 × 3 × 5 and 72 = 2 × 2 × 2 × 3 × 3; the shared primes taken the fewest times are one 2 and one 3, so the HCF is 6. / 30 = 2 × 3 × 5 और 72 = 2 × 2 × 2 × 3 × 3; साझा अभाज्यों को न्यूनतम बार लेने पर एक 2 और एक 3 मिलते हैं, अतः म.स. 6 है।

  6. Find the LCM of 96 and 360. / 96 और 360 का ल.स. (LCM) ज्ञात कीजिए।
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    96 = 2⁵ × 3 and 360 = 2³ × 3² × 5, so taking each prime the most times gives LCM = 2⁵ × 3² × 5 = 1440. / 96 = 2⁵ × 3 और 360 = 2³ × 3² × 5, अतः प्रत्येक अभाज्य को अधिकतम बार लेने पर ल.स. = 2⁵ × 3² × 5 = 1440।

  7. Kabamai visits a shop every 10 days and free sweets are given every 7 days. After how many days will both happen together again? / कबामाई हर 10 दिन में दुकान जाती है और मुफ़्त मिठाई हर 7 दिन में मिलती है। कितने दिन बाद दोनों फिर एक साथ होंगे?
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    They coincide after the LCM of 7 and 10, which is 70 days, because 7 and 10 have no common factor. / वे 7 और 10 के ल.स. अर्थात् 70 दिन बाद एक साथ होंगे, क्योंकि 7 और 10 का कोई उभयनिष्ठ गुणनखंड नहीं है।

  8. Why is the HCF of two consecutive numbers always 1? / दो क्रमागत संख्याओं का म.स. सदा 1 क्यों होता है?
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    Any common factor of two numbers also divides their difference, and the difference of consecutive numbers is 1, so the only common factor is 1. / दो संख्याओं का कोई भी उभयनिष्ठ गुणनखंड उनके अंतर को भी विभाजित करता है, और क्रमागत संख्याओं का अंतर 1 है, अतः एकमात्र उभयनिष्ठ गुणनखंड 1 है।

  9. Use the ladder method to find the HCF and LCM of 630 and 770. / सीढ़ी विधि से 630 और 770 का म.स. और ल.स. ज्ञात कीजिए।
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    Dividing by 10 and then 7 leaves 9 and 11, so the HCF is 10 × 7 = 70 and the LCM is 70 × 9 × 11 = 6930. / 10 और फिर 7 से भाग देने पर 9 और 11 बचते हैं, अतः म.स. 10 × 7 = 70 और ल.स. 70 × 9 × 11 = 6930 है।

  10. A cowherd has fewer than 200 cows that split equally through 3, 5 and 7 gates. How many cows are there? / एक ग्वाले के पास 200 से कम गायें हैं जो 3, 5 और 7 द्वारों से बराबर बँटकर निकलती हैं। गायें कितनी हैं?
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    The number must be a common multiple of 3, 5 and 7; their LCM is 105 and the next is 210, so there are 105 cows. / संख्या 3, 5 और 7 का सार्व गुणज होनी चाहिए; इनका ल.स. 105 है और अगला 210 है, अतः गायें 105 हैं।

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