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Class 8 Mathematics Chapter 0 of 16

Ganita Prakash II · Chapter 3 — Proportional Reasoning-2

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Overview

This chapter takes proportional reasoning further. It begins with a quick recap: two ratios are proportional when both quantities change by the same factor, and the cross-multiplication test a × d = b × c checks this and finds a missing term. You then meet ratios in maps. The representative fraction, such as 1 : 60,00,000, turns a few centimetres on paper into real straight-line distances, and lets you draw your own classroom to scale. Next come ratios with more than two terms, like a spice mix of 8 : 4 : 2 : 1 or concrete of 1 : 1.5 : 3. You learn to scale them, simplify them and divide a total in such a ratio, with examples from paint, cricket practice, coins and the angles of a triangle. Pie charts follow naturally: dividing 360° in the ratio of the data gives the angle of each slice. Finally you discover inverse proportion, where one quantity goes up exactly as the other goes down and their product stays fixed: speed and time, workers and days, pumps and hours. You solve such problems, handle people or machines working together by adding their rates, and learn to tell direct and inverse proportion apart.

हिंदी में पढ़ें

मानचित्र का पैमाना, अनेक पदों वाले अनुपात, किसी पूर्ण का विभाजन, पाई चार्ट और व्युत्क्रम समानुपात, जिसमें एक राशि बढ़ने पर दूसरी घटती है।

Learning Objectives

  • Test whether two ratios are proportional and find a missing term
  • Use the representative fraction of a map to find real distances and make scale drawings
  • Scale and simplify ratios with three or more terms
  • Divide a quantity in a ratio with two or more terms
  • Calculate angles for a pie chart, draw it and interpret one
  • Recognise inverse proportion through the constant product x × y = k
  • Solve inverse proportion problems on workers, pumps, supplies and arrangements
  • Solve working-together problems by adding rates
  • Distinguish direct, inverse and non-proportional relationships

Topics in this chapter

8 topics · tap a topic title to jump straight to it.

Topic 1 of 8
⚖️1

Proportion recap: equal ratios

By the end you canTest whether two ratios are proportional and find a missing term.

1Think first

Will idlis made from 6 cups of rice and 3 cups of dal taste the same as those from 4 cups of rice and 2 cups of dal?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Idli batter is often made with 2 cups of rice for every 1 cup of urad dal, a ratio of 2 : 1. Viswanath uses 6 cups of rice and 3 cups of dal; Puneet uses 4 cups of rice and 2 cups of dal. Will their idlis taste the same?

Proportional relationship. When two related quantities change by the same factor, we say they are in a proportional relationship. Viswanath multiplied both amounts by 3, and Puneet multiplied both by 2, so both batters keep the ratio 2 : 1. We write 6 : 3 :: 4 : 2 and read it as ‘6 is to 3 as 4 is to 2’.

The cross-multiplication test. Two ratios a : b and c : d are proportional exactly when

a × d = b × c, which is the same as a/b = c/d.

For 6 : 3 and 4 : 2, we get 6 × 2 = 12 and 3 × 4 = 12. The products are equal, so the ratios are proportional.

  • Lemonade. 3 spoons of sugar for 2 glasses of water against 9 spoons for 6 glasses: 3 × 6 = 18 and 2 × 9 = 18, so they taste equally sweet.
  • Not proportional. 5 : 4 and 6 : 5: 5 × 5 = 25 but 4 × 6 = 24. The products differ, so the ratios are not equal (5 : 4 is slightly larger).

Why does the test work? a : b :: c : d means a/b = c/d. Multiply both sides by b × d and you get a × d = c × b.

Finding a missing term (the rule of three). If a : b :: c : d and three of the numbers are known, cross-multiplying finds the fourth: d = (b × c)/a. For example, if 5 workers move 4500 bricks in a day, then the number of workers for 18,000 bricks satisfies 4500 : 18000 :: 5 : x, so x = 18000 × 5/4500 = 20 workers. This is a direct proportion: more bricks need more workers, in the same ratio.

Direct proportion in symbols. If x and y are directly proportional, then x/y stays the same for every pair of values: x₁/y₁ = x₂/y₂ = k, a constant. Doubling one doubles the other; dividing one by 3 divides the other by 3.

Simplest form. Dividing both terms by their HCF gives the simplest form of a ratio: 6 : 3 becomes 2 : 1 and 12 : 18 becomes 2 : 3. Two ratios are proportional exactly when their simplest forms are the same.

This chapter extends these ideas in three directions: ratios with more than two terms, ratios in maps and pie charts, and a new kind of proportion where one quantity goes up as the other goes down.

Formulas to remember
  1. a : b :: c : d exactly when a × d = b × c
  2. Missing term: d = (b × c)/a
  3. Direct proportion: x/y = k (constant)
Whenboth quantities are multiplied by the same factorThentheir ratio stays the same and the relationship is proportional
Whena × d = b × cThenthe ratios a : b and c : d are proportional

3Worked example

A recipe uses 250 g of flour for 4 people. How much flour is needed for 10 people?
Step 14 : 10 :: 250 : x.
Step 2Cross-multiply: 4 × x = 10 × 250 = 2500.
Step 3x = 2500 ÷ 4 = 625 g of flour.
More examples
  • 6 : 3 :: 4 : 2 because 6 × 2 = 3 × 4
  • 3 : 2 :: 9 : 6 because 18 = 18
  • 5 : 4 and 6 : 5 are not proportional (25 ≠ 24)
  • 4500 : 18000 :: 5 : 20

4Your turn

Which ratio is proportional to 4 : 6?

5Remember this

One line to keepTwo ratios are proportional when cross-products are equal; that lets us find any missing term.
Common mistake. Adding the same number to both terms (2 : 1 to 4 : 3) instead of multiplying by the same factor.
Topic 2 of 8
➗2

Ratios in maps: the representative fraction

By the end you canUse the representative fraction of a map to change between map and real distances.

1Think first

What does ‘1 : 60,00,000’ printed in the corner of a map tell you?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Look at the corner of a printed map and you will often see something like 1 : 60,00,000. This is the map’s scale, written as a Representative Fraction (RF). It is the ratio of a distance on the map to the matching distance on the ground, in the same units.

Reading the RF. 1 : 60,00,000 means 1 cm on the map stands for 60,00,000 cm on the ground. Change units: 60,00,000 cm = 60,000 m = 60 km. So every centimetre on this map is 60 km of real distance.

UnitChangeValue
centimetresstart60,00,000 cm
metres÷ 10060,000 m
kilometres÷ 100060 km

Using it. If two cities are 4.5 cm apart on this map, the real distance is 4.5 × 60 = 270 km. To go the other way, a real distance of 150 km appears as 150 ÷ 60 = 2.5 cm on the map.

Straight-line distance. A map scale gives the geographical distance, measured in a straight line ‘as the crow flies’. The road distance is usually longer, because roads bend around hills, rivers and towns.

Different maps, same answer. A large atlas page might have RF 1 : 25,00,000 (1 cm = 25 km), while a small map of India might have 1 : 1,00,00,000 (1 cm = 100 km). The cities will be different distances apart on paper, but measuring and multiplying should give about the same real distance. Small differences come from measuring errors and thick printed dots.

Large and small scales. A town map with RF 1 : 25,000 shows much more detail: 1 cm = 25,000 cm = 250 m. A street 6 cm long on it is 6 × 250 = 1500 m = 1.5 km long.

Making your own scale drawing. To draw your classroom at a scale of 1 : 50, divide every real length by 50. A wall 8 m = 800 cm long becomes 800 ÷ 50 = 16 cm, and a desk 1 m long becomes 2 cm. Mark the board, desks, fans and lights with simple symbols in their scaled positions.

Why the RF has no units. Because both parts of the ratio are in the same unit, the units cancel. That is why the same RF works whether you measure in centimetres or inches: 1 inch on the map is 60,00,000 inches on the ground.

Formulas to remember
  1. Real distance = map distance × RF denominator (same unit)
  2. Map distance = real distance ÷ RF denominator
  3. 1 km = 1,00,000 cm
Whena map has RF 1 : nThenevery map length is multiplied by n to get the real length in the same unit
Whenthe second number of the RF is smallerThenthe map shows a smaller area in more detail

3Worked example

On a map with RF 1 : 40,00,000, two towns are 3.5 cm apart. Find the real straight-line distance.
Step 11 cm stands for 40,00,000 cm = 40 km.
Step 23.5 cm stands for 3.5 × 40 = 140 km.
Step 3The towns are about 140 km apart in a straight line.
More examples
  • 1 : 60,00,000 means 1 cm = 60 km
  • 4.5 cm on that map is 270 km
  • 1 : 25,000 means 1 cm = 250 m
  • Classroom at 1 : 50: 8 m wall becomes 16 cm

4Your turn

On a map with RF 1 : 50,000, what real distance does 1 cm show?

5Remember this

One line to keepAn RF 1 : n means one unit on the map is n of the same units on the ground.
Common mistake. Forgetting to convert centimetres to kilometres (divide by 1,00,000) after multiplying.
Topic 3 of 8
⚖️3

Ratios with more than two terms

By the end you canScale and simplify ratios with three or more terms.

1Think first

If a spice mix uses 8 : 4 : 2 : 1 and you have only half the chillies, what do you do with the rest?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Viswanath grinds a spice powder from 8 spoons of coriander seeds, 4 red chillies, 2 spoons of toor dal and 1 spoon of fenugreek (methi). The ratio coriander : chillies : dal : methi is 8 : 4 : 2 : 1. A ratio can have three, four or more terms, as long as all the quantities change by the same factor.

Scaling a many-term ratio. Puneet has only 2 red chillies, half of Viswanath’s 4. To get the same taste he halves everything: 4 spoons coriander, 2 chillies, 1 spoon dal and half a spoon of methi. So

8 : 4 : 2 : 1 :: 4 : 2 : 1 : 0.5.

In general, a : b : c : d :: p : q : r : s means a/p = b/q = c/r = d/s. Every term is multiplied (or divided) by the same number.

Simplest form. Divide all terms by their HCF. 12 : 10 : 8 : 6 : 4 has HCF 2, so it becomes 6 : 5 : 4 : 3 : 2.

Example 1: paint. A purple shade is made with red : blue : white = 2 : 3 : 5. Yasmin has 10 litres of white. White is 5 parts, so 1 part = 10 ÷ 5 = 2 litres. Red = 2 × 2 = 4 litres and blue = 3 × 2 = 6 litres. Total purple = 4 + 6 + 10 = 20 litres.

Example 2: concrete. Strong concrete for pillars and roofs uses cement : sand : gravel = 1 : 1.5 : 3. With 3 bags of cement, multiply every term by 3: 3 : 4.5 : 9. That is 3 + 4.5 + 9 = 16.5 bags of dry mix.

Example 3: a library. Odia : Hindi : English books = 3 : 2 : 1, and there are 288 Odia books. One part = 288 ÷ 3 = 96. So there are 2 × 96 = 192 Hindi books and 96 English books.

Method: find one part.

  • Find the term whose real amount is known.
  • Divide the amount by that term to get the size of one part.
  • Multiply each other term by one part.
  • Check that the new amounts are in the same ratio.

Decimals in ratios. A ratio like 1 : 1.5 : 3 is fine, but you can clear decimals by multiplying all terms by 2 to get 2 : 3 : 6. It is the same ratio.

Formulas to remember
  1. a : b : c :: p : q : r means a/p = b/q = c/r
  2. One part = known amount ÷ its term
Whenone term of a many-term ratio is known as a real amountThendividing by that term gives one part, which fixes all the others
Whenall terms are multiplied by the same numberThenthe ratio stays the same

3Worked example

A fruit punch uses mango : orange : pineapple juice = 4 : 3 : 1. How much of each is needed with 1.5 litres of orange juice?
Step 1Orange is 3 parts = 1.5 L, so 1 part = 0.5 L.
Step 2Mango = 4 × 0.5 = 2 L and pineapple = 1 × 0.5 = 0.5 L.
Step 3Total punch = 2 + 1.5 + 0.5 = 4 L.
More examples
  • 8 : 4 : 2 : 1 :: 4 : 2 : 1 : 0.5
  • Paint 2 : 3 : 5 with 10 L white: 4 L red, 6 L blue
  • Concrete 1 : 1.5 : 3 with 3 bags cement: 3 : 4.5 : 9
  • 12 : 10 : 8 : 6 : 4 = 6 : 5 : 4 : 3 : 2

4Your turn

Red : blue : white = 2 : 3 : 5 and you use 9 litres of blue. How much red is needed?

5Remember this

One line to keepFind the size of one part, then multiply every term by it.
Common mistake. Scaling only some terms of the ratio and leaving the others unchanged.
Topic 4 of 8
⚖️4

Dividing a whole in a given ratio

By the end you canDivide a total quantity in a ratio with two or more terms.

1Think first

How do you split 150 minutes of practice in the ratio 3 : 4 : 3 : 5?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Sometimes we know the total and must split it in a ratio. To divide 12 in the ratio 2 : 1, add the terms (2 + 1 = 3), find one part (12 ÷ 3 = 4) and multiply: 2 × 4 = 8 and 1 × 4 = 4. The same idea works for any number of terms.

Rule. To divide a quantity x in the ratio a : b : c : ..., the parts are

x × a/(a + b + c + ...), x × b/(a + b + c + ...), x × c/(a + b + c + ...), and so on.

Example 1: concrete. 110 units of concrete are needed with cement : sand : gravel = 1 : 1.5 : 3. The terms add to 5.5, so one part is 110 ÷ 5.5 = 20. Cement = 20 units, sand = 30 units, gravel = 60 units. Check: 20 + 30 + 60 = 110.

Example 2: paint. 50 ml of purple paint with red : blue : white = 2 : 3 : 5. The terms add to 10, so red = 50 × 2/10 = 10 ml, blue = 15 ml and white = 25 ml.

Example 3: a cricket session. A 150-minute practice is split as warm-up : batting : bowling : fielding = 3 : 4 : 3 : 5. The sum is 15, so one part is 10 minutes: 30, 40, 30 and 50 minutes.

Example 4: angles of a triangle. Construct a triangle with angles in the ratio 1 : 3 : 5. The angles add to 180° and the terms add to 9, so one part is 20°. The angles are 20°, 60° and 100°. Draw a base AB, make 20° at A and 60° at B; the rays meet at C, and the angle there is 100°.

Example 5: coins. 100 coins are ₹10, ₹5, ₹2 and ₹1 coins in the ratio 4 : 3 : 2 : 1. One part = 100 ÷ 10 = 10 coins, so there are 40, 30, 20 and 10 coins. The money is 400 + 150 + 40 + 10 = ₹600. Notice: we divide the number of coins in the ratio, not the money.

Side lengths. A triangle with sides in the ratio 3 : 4 : 5 can be drawn in many sizes (3, 4, 5 cm or 6, 8, 10 cm). They all have the same shape but not the same size, so they are not all congruent. A triangle with sides in the ratio 1 : 3 : 5 is impossible at any size, because 1 + 3 is less than 5: the two shorter sides cannot reach each other.

Always check that the parts add back to the whole.

Formulas to remember
  1. Part for term a = x × a/(a + b + c + ...)
  2. One part = total ÷ sum of terms
Whena total is divided in a ratioTheneach part equals the total times its term divided by the sum of terms
Whenthe parts are addedThenthey must give back the total

3Worked example

Divide ₹2400 among three friends in the ratio 3 : 4 : 5.
Step 1Sum of terms = 3 + 4 + 5 = 12.
Step 2One part = 2400 ÷ 12 = ₹200.
Step 3Shares: 3 × 200 = ₹600, 4 × 200 = ₹800, 5 × 200 = ₹1000.
Step 4Check: 600 + 800 + 1000 = 2400.
More examples
  • 110 in 1 : 1.5 : 3 gives 20, 30, 60
  • 50 ml in 2 : 3 : 5 gives 10, 15, 25 ml
  • 180° in 1 : 3 : 5 gives 20°, 60°, 100°
  • 100 coins in 4 : 3 : 2 : 1 make ₹600

4Your turn

The angles of a triangle are in the ratio 2 : 3 : 4. What is the largest angle?

5Remember this

One line to keepAdd the terms, divide the total by the sum, and multiply each term by that one part.
Common mistake. Dividing the total by one term instead of by the sum of all the terms.
Topic 5 of 8
🎨5

A slice of the pie: pie charts

By the end you canCalculate the angles of a pie chart, draw it and read one.

1Think first

How would you show the grades of 40 students as slices of a circle?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

A pie chart shows how a whole is shared out among parts, as slices of a circle. Its slices are an example of dividing a whole in a ratio: here the whole is the full angle of 360°.

The data. In a test, 40 students got these grades.

GradeABCDE
Students1210864

Step 1: the ratio. The angle of each slice must be proportional to the number of students. So divide 360° in the ratio 12 : 10 : 8 : 6 : 4, which simplifies (dividing by the HCF 2) to 6 : 5 : 4 : 3 : 2.

Step 2: the angles. The terms add to 20, so one part = 360° ÷ 20 = 18°.

GradeABCDE
Angle6 × 18° = 108°5 × 18° = 90°4 × 18° = 72°3 × 18° = 54°2 × 18° = 36°

Check: 108 + 90 + 72 + 54 + 36 = 360. Another way to get each angle: (students ÷ total) × 360°. For grade A, 12/40 × 360° = 108°.

Step 3: draw. Draw a circle and one radius. With a protractor at the centre, measure 108° from that radius and draw the second radius: that is slice A. From the new radius measure 90° for B, then 72° for C and 54° for D. What is left should be 36° for E. Colour and label each slice.

From percentages. If data is given in percent, each 1% is 3.6°. A TV survey says Entertainment 50%, Sports 25%, News 15%, Information 10%; the angles are 180°, 90°, 54° and 36°.

Reading a pie chart. A slice of 90° is a quarter of the whole, and 120° is a third. If a survey pie shows a 60° slice for ‘car’ and 18 children travel by car, then 60° stands for 18 children, so 360° stands for 18 × 6 = 108 children.

When to use a pie chart. Use it when the parts make up one whole and you want to show each part’s share. It is less useful for comparing parts that are close in size, or for data that changes over time.

Formulas to remember
  1. Angle of slice = (part ÷ whole) × 360°
  2. 1% of the whole = 3.6°
Whena part is a fraction f of the wholeThenits slice angle is f × 360°
Whena slice measures 90°Thenit shows one quarter of the whole

3Worked example

Of 360 people, 90 like summer, 120 like the rainy season and the rest like winter. Find the angles for a pie chart.
Step 1Winter = 360 − 90 − 120 = 150 people.
Step 2The total is 360 people, so each person is 1°.
Step 3Angles: summer 90°, rainy 120°, winter 150°. Check: 90 + 120 + 150 = 360.
More examples
  • Grades 12, 10, 8, 6, 4 out of 40: 108°, 90°, 72°, 54°, 36°
  • Each 1% = 3.6°
  • Seasons 90, 120, 150 out of 360 people: 90°, 120°, 150°
  • 60° slice = 18 children gives 108 children in all

4Your turn

In a pie chart, a slice is 72°. What fraction of the whole is it?

5Remember this

One line to keepEach slice angle = (part ÷ whole) × 360°, and all slices add to 360°.
Common mistake. Using 100 instead of 360 as the total angle of the circle.
Topic 6 of 8
🔢6

Inverse proportion: when one goes up, the other goes down

By the end you canRecognise inverse proportion and test it with the constant product.

1Think first

If you travel twice as fast, does the journey take twice as long or half as long?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Puneeth’s father rides from Lucknow to Kanpur, 90 km away, at 30 km/h and takes 3 hours. In a car at 60 km/h, does the time double too? No, faster travel means less time. Look at the table.

ModeWalkBicycleMotorcycleCar
Speed (km/h)5153060
Time (hours)18631.5
Speed × time90909090

From walking to cycling, speed is multiplied by 3 and time is divided by 3. From motorcycle to car, speed is multiplied by 2 and time is divided by 2. The two quantities change by the same factor, but in opposite directions. This is an inverse proportion.

The test. Two quantities x and y are inversely proportional when their product stays the same:

x × y = k, a constant.

Here k = 90 km, the fixed distance. So for any two pairs of values, x₁y₁ = x₂y₂. This also means x₁/x₂ = y₂/y₁: the ratio of the x values is the inverse of the ratio of the y values. For walking and car, 5/60 = 0.0833... and 1.5/18 = 0.0833... as well.

In words. If one quantity is multiplied by n, the other is multiplied by 1/n. Double one, halve the other; triple one, divide the other by 3.

Compare with direct proportion.

Direct proportionInverse proportion
What stays fixedthe quotient x/ythe product x × y
One is doubledthe other doublesthe other halves
Examplecost and number of pencilsspeed and time for a fixed trip

Checking a table. Is this table an inverse proportion? x: 40, 80, 25, 16 and y: 20, 10, 32, 50. The products are 800, 800, 800, 800, so yes. If one product is different, as with 25 × 12.5 = 312.5 next to 40 × 20 = 800, it is not.

Careful. ‘One goes up, the other goes down’ is not enough. As a candle burns for more minutes its height goes down, but burning twice as long does not halve its height, so the product of time and height is not fixed. For inverse proportion the product must stay the same.

Formulas to remember
  1. Inverse proportion: x × y = k
  2. x₁y₁ = x₂y₂
  3. x₁/x₂ = y₂/y₁
Whenx and y are inversely proportional and x is multiplied by nTheny is divided by n
Whenthe products x × y are the same for all pairsThenx and y are in inverse proportion

3Worked example

x and y are in inverse proportion and x = 16 when y = 9. Find y when x = 12, and x when y = 48.
Step 1k = 16 × 9 = 144.
Step 2When x = 12, y = 144 ÷ 12 = 12.
Step 3When y = 48, x = 144 ÷ 48 = 3.
More examples
  • Speed × time = 90 km for every mode of transport
  • 40 × 20 = 80 × 10 = 25 × 32 = 16 × 50 = 800
  • Double the speed, half the time

4Your turn

Which table shows inverse proportion? (x, y pairs)

5Remember this

One line to keepIn an inverse proportion the product x × y stays constant.
Common mistake. Calling any ‘one up, one down’ relationship inverse without checking that the product is constant.
Topic 7 of 8
🔢7

Solving inverse proportion problems

By the end you canSolve worker, pump, food and arrangement problems using the constant product.

1Think first

If 20 workers lay a road in 4 days, how long will 10 workers take?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Many everyday problems are inverse proportions: more workers finish a job in fewer days, more pumps fill a tank faster, more people use up food sooner. The method is always the same: the product stays the same.

Step-by-step method.

  • Decide whether the relation is direct or inverse: if one quantity doubles, does the other double or halve?
  • For inverse proportion, write x₁ × y₁ = x₂ × y₂.
  • Put in the three known values and solve for the fourth.
  • Check that the answer makes sense (more workers should mean fewer days).

Example 1: workers. 20 workers lay a road in 4 days. How long will 10 workers take? Fewer workers, more days: 20 × 4 = 10 × y, so y = 80 ÷ 10 = 8 days. Halving the workers doubles the time.

Example 2: pumps. 2 pumps fill a tank in 18 hours. With 2 more pumps (4 in all): 2 × 18 = 4 × x, so x = 9 hours.

Example 3: food. A hostel has food for 80 students for 15 days. If 20 more students join: 80 × 15 = 100 × x, so x = 1200 ÷ 100 = 12 days.

Example 4: chairs. Chairs are set in 25 rows of 12. With 20 chairs in a row, the number of rows is 25 × 12 ÷ 20 = 300 ÷ 20 = 15 rows.

Example 5: periods. A school day has 8 periods of 45 minutes. With 9 periods in the same time, each is 8 × 45 ÷ 9 = 360 ÷ 9 = 40 minutes.

Example 6: machines. 42 machines make a batch of toys in 63 days. To make it in 54 days: 42 × 63 = 54 × m, so m = 2646 ÷ 54 = 49 machines.

Assumptions. These answers assume every worker, pump or machine works at the same steady rate, and that adding more does not cause crowding or delays. Real life is not always so neat, which is why the answers are good estimates rather than promises. For the water tank shared by families, we must also assume each family uses the same amount every day.

Do not mix up the two kinds. If 24 pencils cost ₹120, then 20 pencils cost 120 × 20/24 = ₹100. That is direct, not inverse: fewer pencils cost less. And if a pump fills 2 tanks in 6 hours, it fills 5 tanks in 15 hours, also direct, because one pump and more tanks means more time.

Formulas to remember
  1. Inverse: x₁ × y₁ = x₂ × y₂
  2. Unknown y₂ = x₁ × y₁ ÷ x₂
Whenmore people share a fixed jobThenthe time taken falls in the same ratio (inverse proportion)
Whenmore people share fixed suppliesThenthe supplies last fewer days in the same ratio

3Worked example

A car takes 2 hours to reach a town at 60 km/h. How long will it take at 80 km/h?
Step 1Speed and time are inversely proportional for a fixed distance.
Step 260 × 2 = 80 × t, so 120 = 80t.
Step 3t = 1.5 hours, that is 1 hour 30 minutes.
More examples
  • 20 × 4 = 10 × 8 (workers and days)
  • 2 × 18 = 4 × 9 (pumps and hours)
  • 80 × 15 = 100 × 12 (students and days)
  • 25 × 12 = 15 × 20 (rows and chairs)
  • 42 × 63 = 49 × 54 (machines and days)

4Your turn

3 workers paint a fence in 4 days. How long will 4 workers take, at the same rate?

5Remember this

One line to keepFor inverse proportion, multiply the known pair and divide by the new value.
Common mistake. Using direct proportion (cross-multiplying as ratios) for an inverse situation, which gives more time with more workers.
Topic 8 of 8
⚙️8

Working together and choosing the right proportion

By the end you canSolve working-together problems and decide whether two quantities are directly or inversely proportional.

1Think first

If Ram takes 1 hour and Shyam 1.5 hours for a job, how long do they take together?No wrong answer. Think for a moment, then read on.

2The idea, in plain words

Ram cuts a basket of vegetables in 1 hour; Shyam takes 1.5 hours for the same basket. How long will they take working together? Adding the times (2.5 hours) is clearly wrong: together they must be faster than Ram alone.

Think in work per hour. Call the whole basket 1 unit of work.

  • Ram does the whole job in 1 hour, so he does 1 unit per hour.
  • Shyam does it in 1.5 hours, so he does 1 ÷ 1.5 = 2/3 unit per hour.
  • Together they do 1 + 2/3 = 5/3 units per hour.

Work done and time are directly proportional at a fixed rate: 5/3 : 1 :: 1 : x. So (5/3) × x = 1 and x = 3/5 hour = 36 minutes.

Two pumps. A small pump fills a tank in 3 hours and a large one in 2 hours. Per hour they fill 1/3 and 1/2 of the tank, together 1/3 + 1/2 = 5/6. So the tank fills in 6/5 hours = 1 hour 12 minutes.

Why this works. Time to finish and rate of work are inversely proportional: rate × time = 1 job. So we add the rates, never the times, and then take the inverse.

Direct or inverse? A checklist. Ask: if one quantity doubles, what happens to the other?

Pair of quantitiesRelationship
Number of taps and time to fill a tankInverse
Number of painters and days to paint a fixed wallInverse
Speed of a cyclist and time for a fixed routeInverse
Petrol in the tank and distance a car can goDirect
Length of cloth and price at a fixed rate per metreDirect
Pages in a book and time to read at a fixed speedDirect

Not every pair is proportional. Some quantities are related but neither directly nor inversely proportional. How long different animals sleep has nothing to do with their weight in any fixed ratio, and a person’s height does not double when their age doubles. Always test with the quotient (direct) or the product (inverse) before using a rule.

Summary of methods. Direct: x/y is constant, so cross-multiply ratios. Inverse: x × y is constant, so multiply and divide. Working together: add the rates and invert.

Formulas to remember
  1. Rate = 1 ÷ time for one job
  2. Combined rate = sum of the rates
  3. Time together = 1 ÷ combined rate
Whentwo people or machines work togetherThentheir rates of work add, and the time is 1 divided by the total rate
Whendoubling one quantity halves the otherThenthey are inversely proportional

3Worked example

Asha can paint a room in 6 hours and Bina in 3 hours. How long will they take together?
Step 1Asha paints 1/6 of the room per hour and Bina 1/3.
Step 2Together: 1/6 + 1/3 = 1/6 + 2/6 = 1/2 of the room per hour.
Step 3Time = 1 ÷ 1/2 = 2 hours.
More examples
  • Ram 1 h and Shyam 1.5 h together: 36 minutes
  • Pumps 3 h and 2 h together: 1 h 12 min
  • Taps and filling time: inverse
  • Cloth length and price: direct

4Your turn

Two taps fill a tank in 4 hours and 12 hours. How long do they take together?

5Remember this

One line to keepWhen working together, add the rates and invert; never add the times.
Common mistake. Adding or averaging the separate times instead of adding the rates of work.

Key Concepts

Ratio
A comparison of quantities by division, written a : b.
Proportion
A statement that two ratios are equal, written a : b :: c : d.
Cross-multiplication test
a : b :: c : d exactly when a × d = b × c.
Rule of three
Finding the fourth term of a proportion from the other three: d = (b × c)/a.
Direct proportion
Two quantities whose quotient stays constant; when one is multiplied by n, so is the other.
Representative Fraction (RF)
A map scale such as 1 : 60,00,000, comparing map distance with ground distance in the same unit.
Geographical distance
The straight-line distance between two places, as measured on a map.
Many-term ratio
A ratio with three or more terms, such as 8 : 4 : 2 : 1.
Simplest form
A ratio whose terms have no common factor other than 1, found by dividing by the HCF.
One part
The total (or a known amount) divided by the sum of the terms (or its own term).
Dividing in a ratio
Splitting x so that each part is x × term ÷ sum of terms.
Pie chart
A circle divided into slices whose angles show each part’s share of the whole.
Slice angle
(part ÷ whole) × 360°.
Inverse proportion
Two quantities whose product stays constant; when one is multiplied by n, the other is divided by n.
Constant of proportionality
The fixed value k in x/y = k (direct) or x × y = k (inverse).
Rate of work
The fraction of a job done per unit of time; 1 ÷ time for the whole job.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. Are 12 : 18 and 10 : 15 proportional? / क्या 12 : 18 और 10 : 15 समानुपाती हैं?
    Show answer

    Yes. The cross-products are 12 × 15 = 180 and 18 × 10 = 180, which are equal, and both ratios simplify to 2 : 3. / हाँ। तिर्यक गुणनफल 12 × 15 = 180 और 18 × 10 = 180 बराबर हैं, और दोनों अनुपात 2 : 3 में सरल होते हैं।

  2. On a map with RF 1 : 60,00,000, two cities are 5 cm apart. How far apart are they? / 1 : 60,00,000 निरूपक भिन्न वाले मानचित्र पर दो शहर 5 cm दूर हैं। वास्तविक दूरी कितनी है?
    Show answer

    1 cm stands for 60,00,000 cm, which is 60 km, so 5 cm stands for 5 × 60 = 300 km in a straight line. / 1 cm, 60,00,000 cm अर्थात् 60 km दर्शाता है, अतः 5 cm सीधी रेखा में 5 × 60 = 300 km दर्शाता है।

  3. A cricket session of 150 minutes is split as 3 : 4 : 3 : 5. How long is each part? / 150 मिनट का क्रिकेट सत्र 3 : 4 : 3 : 5 में बाँटा गया है। प्रत्येक भाग कितना है?
    Show answer

    The terms add to 15, so one part is 150 ÷ 15 = 10 minutes, giving 30, 40, 30 and 50 minutes. / पदों का योग 15 है, अतः एक भाग 150 ÷ 15 = 10 मिनट है, जिससे 30, 40, 30 और 50 मिनट मिलते हैं।

  4. A library has Odia, Hindi and English books in the ratio 3 : 2 : 1 and 288 Odia books. How many Hindi and English books are there? / एक पुस्तकालय में ओड़िया, हिंदी और अंग्रेज़ी पुस्तकें 3 : 2 : 1 में हैं और ओड़िया पुस्तकें 288 हैं। हिंदी और अंग्रेज़ी पुस्तकें कितनी हैं?
    Show answer

    One part is 288 ÷ 3 = 96, so there are 2 × 96 = 192 Hindi books and 96 English books. / एक भाग 288 ÷ 3 = 96 है, अतः 2 × 96 = 192 हिंदी और 96 अंग्रेज़ी पुस्तकें हैं।

  5. Can a triangle have sides in the ratio 1 : 3 : 5? Why? / क्या किसी त्रिभुज की भुजाएँ 1 : 3 : 5 के अनुपात में हो सकती हैं? क्यों?
    Show answer

    No. For any size the two shorter sides add to 4 parts, which is less than the longest side of 5 parts, so they cannot meet to close the triangle. / नहीं। किसी भी माप में दो छोटी भुजाओं का योग 4 भाग है, जो सबसे लंबी भुजा के 5 भागों से कम है, इसलिए वे मिलकर त्रिभुज नहीं बना सकतीं।

  6. Find the pie chart angles for Entertainment 50%, Sports 25%, News 15% and Information 10%. / मनोरंजन 50%, खेल 25%, समाचार 15% और सूचना 10% के लिए पाई चार्ट के कोण ज्ञात कीजिए।
    Show answer

    Each 1% is 3.6°, so the angles are 180°, 90°, 54° and 36°, which add up to 360°. / प्रत्येक 1% का कोण 3.6° है, अतः कोण 180°, 90°, 54° और 36° हैं, जिनका योग 360° है।

  7. Is the table x = 40, 80, 25, 16 and y = 20, 10, 32, 50 an inverse proportion? / क्या x = 40, 80, 25, 16 और y = 20, 10, 32, 50 वाली सारणी व्युत्क्रम समानुपात है?
    Show answer

    Yes, because every product x × y equals 800, so the product stays constant. / हाँ, क्योंकि प्रत्येक गुणनफल x × y = 800 है, अर्थात् गुणनफल स्थिर रहता है।

  8. Food lasts 80 students for 15 days. How long will it last if 20 more students join? / भोजन 80 विद्यार्थियों के लिए 15 दिन चलता है। 20 और विद्यार्थी आने पर कितने दिन चलेगा?
    Show answer

    The number of students and the days are inversely proportional, so 80 × 15 = 100 × x, giving x = 12 days. / विद्यार्थियों की संख्या और दिन व्युत्क्रम समानुपाती हैं, अतः 80 × 15 = 100 × x, जिससे x = 12 दिन मिलता है।

  9. A school has 8 periods of 45 minutes. How long is each period if there are 9 periods in the same time? / एक विद्यालय में 45 मिनट के 8 कालांश हैं। उतने ही समय में 9 कालांश हों तो प्रत्येक कितने मिनट का होगा?
    Show answer

    The total time is 8 × 45 = 360 minutes, so each of 9 periods lasts 360 ÷ 9 = 40 minutes. / कुल समय 8 × 45 = 360 मिनट है, अतः 9 कालांशों में प्रत्येक 360 ÷ 9 = 40 मिनट का होगा।

  10. A small pump fills a tank in 3 hours and a large one in 2 hours. How long do both take together? / एक छोटा पंप टंकी 3 घंटे में और बड़ा पंप 2 घंटे में भरता है। दोनों मिलकर कितना समय लेंगे?
    Show answer

    Together they fill 1/3 + 1/2 = 5/6 of the tank per hour, so they take 6/5 hours, which is 1 hour 12 minutes. / मिलकर वे प्रति घंटा 1/3 + 1/2 = 5/6 टंकी भरते हैं, अतः वे 6/5 घंटे अर्थात् 1 घंटा 12 मिनट लेंगे।

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