Overview
The previous chapter described motion; this one explains what causes it to change. The answer, found by Galileo and stated by Newton in 1687 as three laws, is force. The chapter begins with the idea of force as a push or pull that can change the speed, direction or shape of a body, and with the distinction between balanced forces, which produce no change of motion, and unbalanced forces, which do. Galileo's insight that a moving body needs no force to keep moving leads to Newton's first law and the concept of inertia, measured by mass, with everyday illustrations from a jerking bus to a tablecloth trick. Momentum — mass times velocity — is introduced, and from the rate of change of momentum the second law is derived in its working form F = ma, with the newton defined and applied to problems of accelerating cars, braking trains and cricket catches. The third law, that every action has an equal and opposite reaction, explains walking, swimming, the recoil of a gun and the flight of a rocket. The chapter closes with the law of conservation of momentum, derived from the second and third laws and applied to collisions, guns and rockets. The Odisha Board examination sets both explanations and numerical problems from this chapter, and the topics carry worked examples of every standard type.
Learning Objectives
- Define force and describe its effects, and distinguish balanced from unbalanced forces with examples.
- Explain Galileo's argument and state Newton's first law of motion with the concept of inertia.
- Relate inertia to mass and explain everyday phenomena such as jerks in a moving vehicle using inertia.
- Define momentum, state its unit and explain the second law of motion as the rate of change of momentum.
- Derive F = ma, define the newton and solve numerical problems on force, mass and acceleration.
- State the third law of motion and explain walking, swimming, gun recoil and rocket propulsion.
- Derive the law of conservation of momentum and apply it to collisions and explosions.
- Solve numerical problems on conservation of momentum including recoil velocity and combined bodies.
Topics in this chapter
12 topics · tap a topic title to jump straight to it.
Force: meaning and effects
In the previous chapter a body's velocity changed — a bus started, a stone fell, a car braked — and we described the change without asking its cause. The cause is force. In everyday language a force is a push or a pull. We push a door to open it, pull a bucket from a well, kick a football, stretch a rubber band, squeeze a lemon. In each case a force is applied by one body on another, and something changes.
Force cannot be seen; it is known by its effects. A force can: 1. set a body at rest in motion — a footballer kicks a stationary ball; 2. stop a moving body — a fielder catches a ball; 3. change the speed of a moving body — pedalling harder speeds a cycle, braking slows it; 4. change the direction of a moving body — a batsman deflects a ball, the Sun's pull bends the Earth's path into an orbit; 5. change the shape or size of a body — pressing a sponge, stretching a spring, flattening dough. The first four effects are changes of motion, that is, accelerations; the fifth is deformation. A force may act while bodies are in contact (a push, friction, the tension in a rope) or at a distance (gravity, magnetism, electric attraction).
Force is a vector quantity: to describe a force fully we must give its magnitude, its direction and its point of application. Pushing a door at the handle and at the hinge with the same force produce different results. The SI unit of force is the newton (N), defined later in the chapter; a force of about 1 N is the weight of a small apple, and a 1 kg mass weighs about 9.8 N.
Two facts about force run through everything that follows. First, a force always involves two bodies — the one that exerts it and the one on which it acts; a force does not exist by itself. Second, what matters for motion is the net force — the resultant of all the forces acting on a body — not any single force. A book on a table has two forces on it, its weight downward and the support of the table upward, and because they cancel the book does not move. A tug-of-war rope pulled equally from both sides stays still. This idea of forces adding up, or cancelling, leads to the distinction between balanced and unbalanced forces in the next topic.
A historical note: for two thousand years, following Aristotle, people believed that a force is needed to keep a body moving, because a cart stops when the horse stops pulling. Galileo, and then Newton, showed that this is wrong — the cart stops because of friction, another force — and that a force is needed only to change motion, not to maintain it. This reversal is the heart of the chapter.
- A stationary football set in motion by a kick (force starts motion); the same ball stopped by the goalkeeper (force stops motion).
- A spring stretched by hanging a weight and a clay ball flattened by a press (force changes shape).
- A book on a table: weight down and the table's push up are equal, the net force is zero and the book stays at rest.
- Force = a push or pull that can change the state of rest or motion, the direction of motion, or the shape of a body
- Force is a vector; SI unit newton (N); net force = vector sum of all forces on the body
Balanced and unbalanced forces
Several forces usually act on a body at once, and the body responds to their combined effect.
Balanced forces. When the forces acting on a body are equal in magnitude and opposite in direction so that their resultant is zero, they are called balanced forces. Balanced forces do not change the state of rest or of uniform motion of a body, though they may change its shape. A wooden block on a table pulled by two equal strings in opposite directions does not move. In a tug-of-war between two equally strong teams the rope stays where it is. A book lying on a table has its weight balanced by the upward push of the table. A parachutist falling at steady speed has the downward pull of gravity balanced by the upward air resistance. In every case the net force is zero and there is no acceleration; a body under balanced forces is either at rest or moving with constant velocity.
Unbalanced forces. When the forces do not cancel — one is greater than the other, or they act in different directions — the resultant is not zero, and the forces are unbalanced. An unbalanced force changes the state of motion: it produces acceleration in the direction of the net force. If one team in the tug-of-war pulls harder, the rope and the weaker team move in the direction of the stronger pull. If the block on the table is pulled by a stronger string on the right, it moves to the right. When a footballer kicks a resting ball, the unbalanced force of the kick starts it moving; the ball then slows and stops because the unbalanced force of friction from the ground acts against its motion.
Friction deserves attention here because it explains why the old idea of force seemed true. Push a box across the floor: it moves while you push and stops when you stop. It seems that force is needed to keep it moving. In fact two forces act on the box — your push forward and friction backward. While your push exceeds friction, the net force is forward and the box accelerates; when your push exactly equals friction the forces are balanced and the box moves at constant speed; when you stop pushing, friction is the only force, unbalanced and backward, and the box decelerates to rest. Friction is the force that stops things, and if it could be removed a moving body would go on moving for ever. Galileo's thought experiment in the next topic does exactly that.
A summary the examination asks for: balanced forces — resultant zero, no change in state of motion, may change shape; unbalanced forces — resultant not zero, produce acceleration, change the state of rest or motion. Whether a body accelerates is decided not by how many forces act on it but by whether their sum is zero.
- Tug-of-war with equal teams: rope at rest (balanced); one team stronger: rope moves that way (unbalanced).
- A car moving on a straight road at a steady 60 km/h: the engine's forward force exactly balances friction and air resistance; net force zero, no acceleration.
- A block pulled by 10 N to the right and 6 N to the left: net force 4 N to the right, and the block accelerates rightward.
- Balanced forces: resultant = 0 → no change in state of rest or uniform motion (shape may change)
- Unbalanced forces: resultant ≠ 0 → acceleration in the direction of the net force
- Friction is the unbalanced force that brings a moving body on a surface to rest
Galileo's insight and Newton's first law of motion
Galileo Galilei, in the early 1600s, studied the motion of balls on inclined planes and reasoned his way to a conclusion that overturned two thousand years of belief. A ball rolling down a slope speeds up; a ball rolling up a slope slows down. Now let a ball roll down one slope and up a second facing it: it climbs to nearly the same height it started from. Make the second slope less steep, and the ball travels farther along it to reach the same height. Make the second slope horizontal, and the ball, trying to reach a height it can never reach, would roll on for ever at constant velocity — if there were no friction. Since friction can never be removed completely in practice, the ball does eventually stop, but the less the friction, the farther it goes — a marble on a carpet stops soon, on a smooth floor it goes farther, on ice farther still. Galileo concluded that a body keeps moving with constant velocity when no net force acts on it; force is needed to change motion, not to keep it going.
Isaac Newton took Galileo's idea and made it the first of his three laws of motion, published in 1687 in the Principia. Newton's first law of motion states: An object remains in a state of rest or of uniform motion in a straight line unless compelled to change that state by an applied unbalanced force. In other words, all bodies resist a change in their state of motion; if at rest they tend to remain at rest, if moving they tend to keep moving at the same speed in the same direction. This tendency is called inertia, and the first law is therefore also called the law of inertia.
The law has two halves. The first — a body at rest stays at rest — matches everyday experience: a book on a table does not move by itself. The second — a body in motion keeps moving uniformly — seems to contradict experience, because moving things on Earth always stop; but they stop because of friction and air resistance, which are forces, not because motion runs out. In outer space, where there is no friction, a spacecraft coasts for years at constant velocity with its engines off, exactly as the law says.
The first law also gives a definition of force: force is that which changes, or tends to change, the state of rest or of uniform motion of a body. And it tells us when the net force on a body is zero — whenever the body is at rest or moving at constant velocity in a straight line. A car cruising at a steady 80 km/h on a straight highway has zero net force on it, even though its engine is working: the engine's push is exactly balanced by friction and air resistance. The moment the driver presses the accelerator or the brake, the forces become unbalanced and the velocity changes.
- A marble rolled on a carpet, a wooden floor and a polished marble floor travels increasingly far as friction decreases — Galileo's argument in practice.
- The Voyager spacecraft, launched in 1977, is still moving away from the Sun with its engines off: no net force, uniform motion.
- A hockey puck on ice slides a long way at nearly constant speed because friction is small.
- Newton's first law: a body remains at rest or in uniform motion in a straight line unless an unbalanced external force acts on it
- Galileo: with no friction, a ball on a horizontal plane would move with constant velocity for ever
- Net force = 0 ⇔ body at rest or moving with constant velocity
Inertia and mass; everyday examples of inertia
Inertia is the natural tendency of a body to resist any change in its state of rest or of uniform motion. All bodies have it, but not equally. It is harder to push a loaded truck than an empty one, harder to stop a rolling boulder than a rolling football, harder to move a full bucket than an empty one. The quantity that measures inertia is mass: the greater the mass of a body, the greater its inertia and the greater the force needed to change its motion. Mass is thus a measure of inertia, and its SI unit is the kilogram. This is the deepest meaning of mass, deeper than the amount of matter.
Inertia shows itself in three kinds of situation, and the examination asks for examples of each.
Inertia of rest — a body at rest tends to stay at rest. When a bus starts suddenly, passengers fall backward: their feet, in contact with the floor, move forward with the bus, but the upper body, by inertia, tends to stay at rest. When a carpet is beaten with a stick, the dust falls out: the carpet moves but the dust particles tend to remain at rest and separate from it. When a branch is shaken, ripe fruits and dry leaves fall. When a card resting on a tumbler with a coin on it is flicked, the card flies away but the coin, by inertia, drops into the tumbler. A tablecloth can be pulled quickly from under crockery, which stays in place.
Inertia of motion — a body in motion tends to keep moving. When a moving bus stops suddenly, passengers fall forward: their feet stop with the bus but their upper bodies continue to move. A runner who reaches the finishing line cannot stop at once. A passenger jumping from a moving bus falls forward, and must run a few steps in the direction of the bus's motion to avoid falling. An athlete runs some distance before a long jump to build up motion that carries her farther through the air. Mud sticking to a rotating wheel flies off along the tangent. A knife struck against a stone loosens the wet dough on it.
Inertia of direction — a body tends to keep its direction of motion. When a bus takes a sharp turn, passengers are thrown outward: their bodies tend to keep moving in the original straight line while the bus turns. Water on a spinning umbrella flies off along the tangent. Sparks from a grinding wheel fly off tangentially.
Seat belts and headrests. In a car crash the car stops in a fraction of a second but the passengers, by inertia of motion, continue forward and strike the windscreen or steering wheel. Seat belts hold the body to the seat and, being slightly elastic, spread the stopping force over a longer time. Headrests protect the neck when a car is struck from behind: the seat pushes the body forward but the head, by inertia of rest, stays back and would snap backward without support. These are the reasons the law requires belts and helmets.
- A passenger falls backward when a bus starts suddenly (inertia of rest) and forward when it brakes suddenly (inertia of motion).
- A coin on a card over a tumbler: flick the card and the coin drops straight into the glass, staying at rest while the card leaves.
- A loaded truck needs a far larger force to start or stop than a bicycle — mass measures inertia.
- Inertia = tendency of a body to resist change in its state of rest or uniform motion; mass is the measure of inertia
- Inertia of rest (bus starting, dusting a carpet); inertia of motion (bus stopping, jumping from a moving bus); inertia of direction (bus turning, mud from a wheel)
Momentum
A cricket ball moving slowly can be caught with bare hands; the same ball bowled fast can break a finger. A truck parked at the roadside is harmless; the same truck rolling slowly down a slope can crush a car. What matters in the impact of a moving body is not its mass alone or its velocity alone but the product of the two. This product is momentum, defined by Newton as the quantity of motion.
The momentum p of a body is the product of its mass m and its velocity v: p = mv. It is a vector quantity, in the direction of the velocity. Its SI unit is kilogram metre per second (kg m/s); there is no special name. A body at rest has zero momentum however large its mass, and a body of small mass at very high speed — a bullet — can have as much momentum as a heavy body moving slowly.
Worked example 1. A cricket ball of mass 0.16 kg bowled at 40 m/s: p = 0.16 × 40 = 6.4 kg m/s. A truck of mass 4000 kg rolling at 0.5 m/s: p = 4000 × 0.5 = 2000 kg m/s. A bullet of mass 0.02 kg at 300 m/s: p = 6 kg m/s — nearly the same as the cricket ball.
Worked example 2. Which has more momentum, a 1000 kg car at 20 m/s or a 10,000 kg truck at 1 m/s? Car: 20,000 kg m/s; truck: 10,000 kg m/s. The car, despite being ten times lighter.
Why is momentum, rather than velocity, the right measure of motion? Because the effect of a force depends on both mass and velocity. It takes more effort to stop a heavy body than a light one at the same speed, and more effort to stop a fast body than a slow one of the same mass — and momentum captures both. Newton found that the correct statement of his second law is in terms of momentum: the force acting on a body is proportional to the rate at which its momentum changes. A small force acting for a long time can produce the same change of momentum as a large force acting briefly — pushing a stalled car slowly up to speed, versus the sudden blow of a collision. This is developed in the next topic.
Change of momentum. If a body's velocity changes from u to v, its momentum changes from mu to mv, and the change is m(v − u). A ball of 0.5 kg thrown at 10 m/s and caught (v = 0) has a momentum change of 0.5 × (0 − 10) = −5 kg m/s; the catcher's hands must provide the force that produces this change. If the ball bounces back at 10 m/s the change is 0.5 × (−10 − 10) = −10 kg m/s, twice as much, because direction counts — momentum is a vector.
The idea that momentum is what a force changes, and the further idea that the total momentum of bodies acting on each other stays constant, are the two pillars of the rest of the chapter.
- Cricket ball 0.16 kg at 40 m/s: 6.4 kg m/s; bullet 0.02 kg at 300 m/s: 6 kg m/s — comparable momenta from very different masses.
- A 1000 kg car at 20 m/s (20,000 kg m/s) has twice the momentum of a 10,000 kg truck at 1 m/s (10,000 kg m/s).
- A 0.5 kg ball at 10 m/s stopped: momentum change 5 kg m/s; bounced straight back at 10 m/s: change 10 kg m/s.
- Momentum p = m v ; vector; SI unit kg m/s
- Change in momentum = m v − m u = m (v − u)
- Momentum of a body at rest = 0
Newton's second law of motion and F = ma
The first law says what happens when no net force acts. The second law says what happens when one does, and how much. Newton's second law of motion states: The rate of change of momentum of a body is directly proportional to the applied unbalanced force, and the change takes place in the direction of the force.
Derivation of F = ma. Consider a body of mass m moving with initial velocity u. An unbalanced force F acts on it for a time t and changes its velocity uniformly to v. Initial momentum = mu; final momentum = mv; change in momentum = mv − mu = m(v − u). Rate of change of momentum = m(v − u) / t. By the second law, F ∝ m(v − u) / t. But (v − u) / t is the acceleration a, so F ∝ ma, that is F = k ma, where k is a constant of proportionality. The unit of force is chosen so that k = 1: one unit of force is that which produces an acceleration of 1 m/s2 in a mass of 1 kg. With this choice, F = ma. The SI unit of force is the newton (N), and 1 N = 1 kg m/s2: the force that gives a mass of 1 kg an acceleration of 1 m/s2. The second law thus gives a way to measure force: force = mass × acceleration.
Notice three things in the equation. Force and acceleration are in the same direction. For a given force, the acceleration is inversely proportional to the mass — the same push accelerates a bicycle far more than a car, which is the quantitative form of inertia. And for a given mass, the acceleration is proportional to the force. If F = 0, then a = 0 and the velocity is constant: the first law is the special case of the second.
The momentum form, F = (mv − mu) / t = change in momentum ÷ time, is the more general statement and explains a set of everyday facts. The same change in momentum requires a smaller force if it is spread over a longer time. A fielder catching a fast cricket ball draws his hands backward with the ball, increasing the time over which the ball's momentum falls to zero and thereby reducing the force on his hands; a ball stopped abruptly hurts. A high jumper lands on a thick cushion and a long jumper on loose sand, which increase the stopping time and lower the force. Cars have crumple zones and air bags and passengers wear seat belts that stretch, so that in a crash the momentum is lost over a longer time and the force on the body is survivable. A karate expert striking bricks does the opposite — delivers the momentum change in the shortest possible time to produce a large force. Glassware is packed in straw or foam for the same reason. Time and force trade against each other for a fixed change in momentum.
The examination asks for the statement of the law, the derivation with the definition of the newton, and one of these applications explained in terms of time and force; the next topic supplies the numerical practice.
- Same 100 N force on a 10 kg box gives a = 10 m/s²; on a 50 kg box gives a = 2 m/s² — acceleration inversely proportional to mass.
- A fielder pulls his hands back while catching to lengthen the stopping time and lessen the force; catching stiffly hurts.
- Air bags in a car increase the time over which the passenger's momentum falls to zero, reducing the force on the body.
- Second law: F ∝ rate of change of momentum = (mv − mu)/t = m(v − u)/t = ma → F = ma (with k = 1)
- 1 newton = 1 kg m/s² = force that gives 1 kg an acceleration of 1 m/s²
- For a fixed change of momentum, F × t = constant: longer time → smaller force
Numerical problems on the second law
Problems on F = ma come in a few standard shapes: find F from m and a; find a and then use an equation of motion; find F from a change in momentum over a time; and find the stopping distance or time. Work in SI units — kilograms, metres, seconds, newtons — and convert grams to kilograms and km/h to m/s first.
Problem 1. A constant force acts on an object of mass 5 kg for 2 s and changes its velocity from 3 m/s to 7 m/s. Find the force. Then, if the force were applied for 5 s, what would the final velocity be? a = (7 − 3)/2 = 2 m/s2; F = ma = 5 × 2 = 10 N. For 5 s: v = u + at = 3 + 2 × 5 = 13 m/s.
Problem 2. Which would require a greater force — accelerating a 2 kg mass at 5 m/s2 or a 4 kg mass at 2 m/s2? F1 = 2 × 5 = 10 N; F2 = 4 × 2 = 8 N. The 2 kg mass at 5 m/s2 requires the greater force.
Problem 3. A motorcar of mass 1200 kg moving along a straight road at 90 km/h is brought to rest in 4 s by brakes. Find the change in momentum, the retardation and the braking force. u = 25 m/s, v = 0, t = 4. Change in momentum = m(v − u) = 1200 × (0 − 25) = −30,000 kg m/s. a = (0 − 25)/4 = −6.25 m/s2. F = ma = 1200 × (−6.25) = −7500 N; the minus sign shows the force opposes the motion.
Problem 4. A hammer of mass 500 g moving at 50 m/s strikes a nail and is stopped in 0.01 s. Find the force of the nail on the hammer. m = 0.5 kg. F = m(v − u)/t = 0.5 × (0 − 50)/0.01 = −2500 N; the nail exerts 2500 N on the hammer, and the hammer 2500 N on the nail.
Problem 5. A force of 5 N gives a mass m1 an acceleration of 10 m/s2 and a mass m2 an acceleration of 20 m/s2. What acceleration would it give if both masses were tied together? m1 = 5/10 = 0.5 kg; m2 = 5/20 = 0.25 kg; together 0.75 kg; a = 5/0.75 = 6.67 m/s2.
Problem 6. An automobile of mass 1500 kg is moving at 20 m/s; find the force needed to stop it in 50 m. Using v2 = u2 + 2as: 0 = 400 + 100a, a = −4 m/s2. F = 1500 × (−4) = −6000 N, a retarding force of 6000 N.
Problem 7. A stone of 1 kg is thrown at 20 m/s across the frozen surface of a lake and comes to rest after travelling 50 m. Find the force of friction. a = (0 − 400)/(2 × 50) = −4 m/s2; F = 1 × (−4) = −4 N, friction of 4 N opposing the motion.
Problem 8. An 8000 kg engine pulls a train of five wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40,000 N and the track offers a friction force of 5000 N, find the net accelerating force, the acceleration of the train, and the force of wagon 1 on wagon 2. Net force = 40,000 − 5000 = 35,000 N. Total mass = 8000 + 10,000 = 18,000 kg; a = 35,000/18,000 = 1.94 m/s2. Wagon 1 pulls wagons 2 to 5 (mass 8000 kg): force = 8000 × 1.94 = 15,556 N.
Problem 9. A bullet of 10 g travelling horizontally at 150 m/s strikes a wooden block and comes to rest in 0.03 s. Find the distance of penetration and the force of the wood on the bullet. a = (0 − 150)/0.03 = −5000 m/s2; s = ut + ½at2 = 150 × 0.03 − ½ × 5000 × 0.0009 = 4.5 − 2.25 = 2.25 m; F = 0.01 × (−5000) = −50 N.
In each case the chain is: find a (from the equations of motion or from the given velocities and time), then F = ma; or find the change in momentum and divide by time. State the sign and say what it means.
- 5 kg body from 3 to 7 m/s in 2 s: F = 10 N; after 5 s at that force, v = 13 m/s.
- 1200 kg car from 25 m/s to rest in 4 s: momentum change −30,000 kg m/s, force −7500 N.
- Engine and five wagons: net force 35,000 N, a = 1.94 m/s², pull on the last four wagons 15,556 N.
- F = ma ; a from (v − u)/t or from the equations of motion
- F = (mv − mu)/t ; change in momentum = F × t
- Net force = applied force − friction; a = net force / total mass
Newton's third law of motion
The first two laws describe what happens to one body. The third describes what happens between two. When you push against a wall, the wall pushes back against your hand — you feel it. When you press a spring balance against a table, its reading shows the table pressing back. Newton generalised this into his third law of motion: To every action there is an equal and opposite reaction — whenever one body exerts a force on a second body, the second body exerts a force of equal magnitude and opposite direction on the first.
Four points prevent the usual confusions. 1. Forces always occur in pairs; a single isolated force does not exist. 2. The action and reaction are equal in magnitude and opposite in direction. 3. They act on different bodies — the action on one, the reaction on the other — and therefore they never cancel each other; forces cancel only when they act on the same body. 4. They act simultaneously; neither comes first, and either may be called the action.
Why, then, does anything move, if every force is matched by an opposite one? Because the two forces act on two different bodies, and each body responds to the force on it according to its own mass. When a gun fires, the gun pushes the bullet forward and the bullet pushes the gun backward with an equal force; the bullet, being light, gets a large acceleration and the gun, being heavy, a small one — but it does move, and that is the recoil.
Examples. Walking: the foot pushes the ground backward (action); the ground pushes the foot forward (reaction), and this forward push moves us. On ice or wet mud the ground cannot push back effectively, and we slip. Swimming: the swimmer pushes water backward; the water pushes the swimmer forward. A bird flying pushes air downward and backward with its wings; the air pushes the bird upward and forward. Rowing: the oars push water backward; water pushes the boat forward. A rocket or jet expels hot gases backward at high speed; the gases push the rocket forward, which is why a rocket works in empty space where there is nothing to push against — it pushes against its own exhaust. Recoil of a gun, described above. A balloon released with its neck open shoots forward as the air rushes out backward. A boat and a sailor: when a sailor jumps from a boat to the shore, the boat moves backward, because the sailor pushes the boat backward as the boat pushes the sailor forward. A book on a table: the book presses the table with its weight; the table pushes the book up equally. A hammer and nail: the hammer strikes the nail and the nail exerts an equal force back on the hammer, which is why the hammer stops.
A demonstration with two spring balances hooked together and pulled shows the law directly: both read the same, whichever is pulled. Two students on roller skates who push each other move apart in opposite directions, the lighter one faster. The third law is the basis of the law of conservation of momentum, which follows.
- Walking: foot pushes ground backward, ground pushes foot forward; on ice the backward push finds no grip and the walker slips.
- A rocket: exhaust gases pushed backward push the rocket forward, even in the vacuum of space.
- A sailor jumping from a boat to the bank pushes the boat backward into the water as the boat pushes him forward.
- Third law: to every action there is an equal and opposite reaction; the two forces act on different bodies and never cancel
- Action and reaction are simultaneous and equal in magnitude, opposite in direction
Conservation of momentum: statement and derivation
Combine the second and third laws and a powerful result follows: in an interaction between two bodies on which no external force acts, the total momentum stays the same.
Law of conservation of momentum: In the absence of an external unbalanced force, the total momentum of a system of bodies remains constant — the total momentum before an interaction (a collision, an explosion, a push) equals the total momentum after it. Momentum may pass from one body to another, but the sum is unchanged.
Derivation. Consider two balls A and B of masses mA and mB moving in the same straight line with initial velocities uA and uB, with uA greater than uB so that A catches up and collides with B. During the collision, which lasts a short time t, A exerts a force FAB on B and, by the third law, B exerts an equal and opposite force FBA on A: FAB = −FBA. After the collision the velocities are vA and vB.
By the second law, the force on A is its rate of change of momentum: FBA = mA(vA − uA) / t. Likewise the force on B: FAB = mB(vB − uB) / t.
Since FAB = −FBA: mB(vB − uB) / t = −mA(vA − uA) / t. Cancelling t and rearranging: mBvB − mBuB = −mAvA + mAuA, that is
mAuA + mBuB = mAvA + mBvB.
The left side is the total momentum before the collision and the right side the total momentum after it; they are equal. The momentum lost by A is exactly gained by B. The derivation used only the second and third laws, so conservation of momentum is not a new assumption but a consequence of Newton's laws; it holds whenever the only forces are the internal ones between the bodies, whatever the nature of the collision — bouncing apart, sticking together, or exploding.
What conservation means in practice. If two bodies start at rest — a gun and its bullet, a boat and a sailor, two skaters — the total momentum is zero before, so it must be zero after: the two bodies move off with equal and opposite momenta, and the lighter one moves faster. If one body strikes another at rest and they stick together, the combined body moves with a velocity that keeps the total momentum the same, and since the mass is larger the velocity is smaller. Momentum is a vector, so directions must be given signs — usually one direction positive and the other negative — and a negative answer means motion in the negative direction.
The examination asks for the statement, the derivation with the diagram of the two balls before, during and after collision, and a numerical example; these follow in the last two topics.
- Two balls: A of 2 kg at 5 m/s hits B of 3 kg at rest; if A slows to 2 m/s, B must move at (10 − 4)/3 = 2 m/s so that total momentum stays 10 kg m/s.
- A gun and bullet at rest before firing: total momentum 0 before, so gun momentum + bullet momentum = 0 after; the gun recoils.
- Two skaters pushing apart from rest: the 40 kg skater moves at 2 m/s one way while the 80 kg skater moves at 1 m/s the other way — equal and opposite momenta of 80 kg m/s.
- Conservation of momentum: total momentum before = total momentum after, if no external force acts
- m_A u_A + m_B u_B = m_A v_A + m_B v_B
- Derivation: F_AB = −F_BA (third law) with F = m(v − u)/t (second law)
Applications of conservation of momentum: recoil and rockets
Recoil of a gun. Before firing, the gun and the bullet are at rest, so the total momentum of the system is zero. When the trigger is pulled, the expanding gases push the bullet forward and, by the third law, the gun backward; no external force acts on the gun-bullet system during the brief firing, so the total momentum must still be zero after firing. If the bullet of mass m leaves with velocity v and the gun of mass M recoils with velocity V, then 0 = mv + MV, so V = −mv / M. The minus sign shows that the gun moves opposite to the bullet. Because M is much larger than m, V is much smaller than v — a rifle recoils at about one metre per second while its bullet leaves at hundreds of metres per second — but the recoil is real and a shooter braces the butt against the shoulder to absorb it.
Worked example. A bullet of mass 20 g is fired horizontally at 150 m/s from a pistol of mass 2 kg. Find the recoil velocity of the pistol. m = 0.02 kg, v = 150 m/s, M = 2 kg. 0 = 0.02 × 150 + 2 × V; V = −3/2 = −1.5 m/s; the pistol recoils at 1.5 m/s in the direction opposite to the bullet.
Worked example. A gun of mass 100 kg fires a shell of 1 kg at 200 m/s. Recoil velocity = −(1 × 200)/100 = −2 m/s.
Rocket propulsion. A rocket carries fuel and an oxidiser; in the combustion chamber they burn to produce hot gases at very high pressure, which rush out of the nozzle at the rear at speeds of two to four kilometres per second. The gases carry momentum backward; to conserve the total momentum, the rocket gains an equal momentum forward. In the language of the third law, the rocket pushes the gases backward and the gases push the rocket forward. The rocket needs no air to push against, which is why it works in the vacuum of space where a jet engine or a propeller would be useless. The thrust depends on the mass of gas ejected per second and its speed; and as fuel is burnt the rocket's mass falls, so the same thrust gives a growing acceleration — which is why rockets are built in stages that are discarded when empty. India's PSLV and GSLV launch vehicles, and the Chandrayaan and Mangalyaan missions launched from Sriharikota, all ride on conservation of momentum. A toy balloon let go with its neck open, a garden sprinkler that spins as water jets out, and a boat that moves backward when a sailor jumps forward are humbler versions of the same principle.
Jet of water on a wall, the kick of a fire hose, the sideways push felt when a heavy bag is thrown from a stationary boat — each is an application of the same law: when part of a system is pushed one way, the rest goes the other way so that the total momentum is unchanged.
A caution about what conservation does not say: it does not say that each body keeps its momentum, only that the total does; nor does it apply if an external force acts during the interaction — friction from the ground on a gun mounted firmly, for instance, supplies an external force and the gun does not recoil freely. In problems the phrase no external force, or a very short interaction, is the signal to apply the law.
- Pistol 2 kg firing a 20 g bullet at 150 m/s: recoil 1.5 m/s backward.
- Gun 100 kg firing a 1 kg shell at 200 m/s: recoil 2 m/s.
- A PSLV rocket ejects tonnes of exhaust gas backward every second at about 3 km/s; the momentum given to the gas equals the momentum gained by the rocket.
- Recoil: 0 = m v + M V → V = −m v / M
- Rocket: momentum of ejected gas backward = momentum gained by rocket forward; works in vacuum
- Conservation applies only when no external unbalanced force acts during the interaction
Numerical problems on conservation of momentum
Set up every problem the same way: choose a positive direction; write the total momentum before, in kilograms and metres per second; write the total momentum after with unknowns; equate them; solve; interpret the sign.
Problem 1. Two objects of masses 100 g and 200 g move along the same line in the same direction with velocities 2 m/s and 1 m/s respectively. They collide, and after the collision the first object moves at 1.67 m/s. Find the velocity of the second. m1 = 0.1 kg, m2 = 0.2 kg. Momentum before = 0.1 × 2 + 0.2 × 1 = 0.2 + 0.2 = 0.4 kg m/s. Momentum after = 0.1 × 1.67 + 0.2 × v2 = 0.167 + 0.2 v2. Equating: 0.2 v2 = 0.4 − 0.167 = 0.233; v2 = 1.165 m/s in the original direction.
Problem 2. An object of mass 1 kg travelling at 10 m/s collides with a stationary wooden block of mass 5 kg and sticks to it; the two move together. Find the total momentum before and after, and the velocity of the combined object. Before: 1 × 10 + 5 × 0 = 10 kg m/s. After: by conservation, also 10 kg m/s. Combined mass 6 kg: v = 10/6 = 1.67 m/s.
Problem 3. A hockey ball of mass 200 g travelling at 10 m/s is struck by a stick so that it returns along the same path at 5 m/s. Find the change in momentum. Take the original direction as positive: initial momentum = 0.2 × 10 = 2 kg m/s; final momentum = 0.2 × (−5) = −1 kg m/s. Change = −1 − 2 = −3 kg m/s, that is 3 kg m/s in the direction of the return.
Problem 4. A girl of mass 40 kg jumps with a horizontal velocity of 5 m/s onto a stationary cart of mass 3 kg and sits on it. Find the velocity of the cart with the girl. Before: 40 × 5 + 3 × 0 = 200 kg m/s. After: (40 + 3) × v = 43 v. v = 200/43 = 4.65 m/s.
Problem 5. Two hockey players of opposite teams, one of 60 kg moving at 5 m/s and the other of 55 kg moving at 6 m/s in the opposite direction, collide and become entangled. In which direction and with what speed do they move? Take the first player's direction as positive. Before: 60 × 5 + 55 × (−6) = 300 − 330 = −30 kg m/s. After: 115 × v = −30; v = −0.26 m/s: they move in the direction of the second player at 0.26 m/s.
Problem 6. A truck of mass 3000 kg moving at 10 m/s collides with a car of mass 1000 kg moving at 5 m/s in the same direction; after the collision they move together. Velocity after? (30,000 + 5000)/4000 = 8.75 m/s.
Problem 7. Two objects each of mass 1.5 kg move in the same straight line but in opposite directions at 2.5 m/s each. They collide and stick together. Velocity after? Before: 1.5 × 2.5 + 1.5 × (−2.5) = 0. After: 3 × v = 0, so v = 0: the combined body is at rest, having equal and opposite momenta cancelled.
Problem 8. A bullet of 10 g is fired at 300 m/s into a wooden block of 990 g resting on a smooth surface and stays inside it. Find the velocity of the block. Before: 0.01 × 300 = 3 kg m/s. After: 1.0 × v = 3; v = 3 m/s.
Common errors: forgetting to convert grams to kilograms; giving both velocities the same sign when the bodies move in opposite directions; and adding masses when the bodies do not stick together. Always draw the before and after picture with arrows, and check that the answer's sign makes physical sense.
- 100 g at 2 m/s and 200 g at 1 m/s; first slows to 1.67 m/s after collision → second moves at 1.165 m/s.
- 1 kg at 10 m/s sticks to a 5 kg block at rest → combined velocity 10/6 = 1.67 m/s.
- Hockey ball 200 g from +10 m/s to −5 m/s: change in momentum −3 kg m/s.
- m1 u1 + m2 u2 = m1 v1 + m2 v2 ; if the bodies stick: m1 u1 + m2 u2 = (m1 + m2) v
- Opposite directions carry opposite signs; convert g → kg before substituting
- Change in momentum of one body = final − initial (with signs)
Summary of Newton's laws and their everyday applications
The three laws are best fixed by seeing them together, each with its statement, its key idea and its examples, and then applied to a few compound situations that the examination likes.
| Law | Statement | Key idea | Examples |
| First (law of inertia) | A body stays at rest or in uniform straight-line motion unless an unbalanced force acts on it | Inertia; mass measures it; defines force qualitatively | Passengers jerk in a bus; dust from a beaten carpet; coin and card |
| Second | Rate of change of momentum is proportional to the applied force, in its direction; F = ma | Measures force; 1 N = 1 kg m/s²; longer time means smaller force for the same momentum change | Catching a ball with hands drawn back; air bags; braking distances |
| Third | To every action there is an equal and opposite reaction, on different bodies | Forces come in pairs; they never cancel | Walking, swimming, rocket, recoil of a gun |
The law of conservation of momentum, derived from the second and third laws, says the total momentum of an isolated system is constant — the tool for collisions, explosions and recoil.
Compound applications. Why do we use helmets and seat belts? In a crash the vehicle stops in a fraction of a second; by the first law the rider or passenger continues forward (inertia of motion); the belt or the helmet's padding stops the body over a longer time, and by the second law the force is smaller (F = change in momentum ÷ time). Why is it dangerous to jump from a moving bus? The feet stop on touching the ground but the body, by inertia, keeps the bus's velocity and the person falls forward; running a few steps in the direction of motion lets the body slow gradually. Why does a cricketer pull his hands back? Second law, longer time, smaller force. Why does a gun kick? Third law and conservation of momentum. Why can a rocket fly in space? It pushes on its own exhaust, not on air. Why do passengers lurch outward on a turn? Inertia of direction; the seat and friction supply the inward force that turns them with the bus. Why is friction needed to walk? The ground can push us forward (third law) only if it grips the foot. Why does a heavy truck need bigger brakes than a car at the same speed? Greater mass means greater momentum and, for the same stopping time, greater force.
A note on friction and the first law. Friction appears in nearly every real example as the unbalanced force that stops things, and it is often blamed for making Newton's first law seem false. Reduce it — with wheels, oil, ice, air cushions — and moving bodies go farther; imagine it gone and they go for ever. The laws describe an ideal; friction is one of the forces that the laws must include, not an exception to them.
Units and symbols to carry into the examination: force F in newtons (N); mass m in kilograms (kg); acceleration a in m/s2; momentum p in kg m/s; 1 N = 1 kg m/s2; weight of 1 kg ≈ 9.8 N. The next chapter, gravitation, applies the second law to the force that the Earth exerts on everything near it.
- Seat belt: inertia carries the passenger forward (first law); the belt stops the body over a longer time, reducing the force (second law).
- Jumping from a moving bus: feet stop, body continues (inertia of motion) — run forward a few steps to avoid falling.
- Bigger brakes on a truck: larger mass means larger momentum to remove in the same time, hence a larger force.
- First law: F = 0 → constant velocity; Second law: F = ma = Δp/t; Third law: F_AB = −F_BA
- Conservation of momentum: Σ p before = Σ p after (no external force)
- Units: N, kg, m/s², kg m/s; 1 N = 1 kg m/s²
Key Concepts
- Force
- A push or pull that can change the state of rest or motion of a body, the direction of its motion, or its shape; a vector measured in newtons.
- Balanced forces
- Forces acting on a body whose resultant is zero, which do not change its state of rest or uniform motion but may change its shape.
- Unbalanced force
- A net force that is not zero, which produces an acceleration in its own direction.
- Friction
- The force that opposes the relative motion of two surfaces in contact and brings moving bodies on a surface to rest.
- Newton's first law
- A body remains at rest or in uniform motion in a straight line unless an unbalanced external force compels it to change that state.
- Inertia
- The tendency of a body to resist any change in its state of rest or of uniform motion, measured by its mass.
- Mass
- The measure of the inertia of a body, in kilograms; the greater the mass, the greater the force needed to change its motion.
- Momentum
- The product of the mass and velocity of a body, p = mv, a vector with unit kg m/s.
- Newton's second law
- The rate of change of momentum of a body is proportional to the applied unbalanced force and takes place in the direction of the force; F = ma.
- Newton (N)
- The SI unit of force, the force that gives a mass of 1 kg an acceleration of 1 m/s²; 1 N = 1 kg m/s².
- Newton's third law
- To every action there is an equal and opposite reaction; the two forces act on different bodies and never cancel.
- Action-reaction pair
- Two equal and opposite forces that two interacting bodies exert on each other simultaneously.
- Law of conservation of momentum
- The total momentum of a system of bodies remains constant if no external unbalanced force acts on it.
- Recoil
- The backward motion of a gun when a bullet is fired, so that the total momentum of gun and bullet stays zero.
- Rocket propulsion
- Forward motion of a rocket produced by ejecting hot gases backward at high speed, conserving momentum, which works even in vacuum.
- Impact time
- The time over which a change of momentum occurs; a longer time means a smaller force, as in catching a ball with hands drawn back.
- Inertia of rest
- The tendency of a body at rest to remain at rest, as when passengers fall backward in a bus that starts suddenly.
- Inertia of motion
- The tendency of a moving body to keep moving, as when passengers fall forward in a bus that stops suddenly.
- Inertia of direction
- The tendency of a moving body to keep its direction, as when passengers lean outward on a sharp turn.
- Net force
- The vector sum of all the forces acting on a body, which alone decides its acceleration.
End-of-Chapter Trial Paper & Test Questions
Topic-wise questions to test your understanding of every concept in this chapter.
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Distinguish between balanced and unbalanced forces with one example of each. / संतुलित और असंतुलित बलों में एक-एक उदाहरण सहित अंतर बताइए।
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Balanced forces are forces acting on a body that are equal in magnitude and opposite in direction so that their resultant is zero; they do not change the state of rest or of uniform motion of the body, though they may change its shape. For example, in a tug-of-war between two equally strong teams the rope does not move, and a book lying on a table stays at rest because its weight is balanced by the upward push of the table. Unbalanced forces are forces whose resultant is not zero; they change the state of motion of the body by producing an acceleration in the direction of the net force. For example, when one team in a tug-of-war pulls harder the rope moves towards it, and a football kicked from rest starts to move. / संतुलित बल किसी वस्तु पर लगने वाले ऐसे बल हैं जो परिमाण में समान और दिशा में विपरीत हों ताकि उनका परिणामी शून्य हो; वे वस्तु की विराम या एकसमान गति की अवस्था नहीं बदलते, यद्यपि उसका आकार बदल सकते हैं। उदाहरण के लिए, दो समान बलशाली टीमों की रस्साकशी में रस्सी नहीं हिलती, और मेज़ पर रखी पुस्तक विराम में रहती है क्योंकि उसका भार मेज़ के ऊपर की ओर धक्के से संतुलित है। असंतुलित बल वे बल हैं जिनका परिणामी शून्य नहीं है; वे नेट बल की दिशा में त्वरण उत्पन्न कर वस्तु की गति की अवस्था बदल देते हैं। उदाहरण के लिए, रस्साकशी में एक टीम के अधिक ज़ोर से खींचने पर रस्सी उसकी ओर चलती है, और विराम से ठोकर मारी गई फुटबॉल चलने लगती है।
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State Newton's first law of motion. Why is it called the law of inertia? Explain with Galileo's inclined plane argument why a body in motion does not need a force to keep moving. / न्यूटन का गति का प्रथम नियम लिखिए। इसे जड़त्व का नियम क्यों कहते हैं? गैलीलियो के आनत तल के तर्क से समझाइए कि गतिशील वस्तु को चलते रहने के लिए बल की आवश्यकता क्यों नहीं है।
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Newton's first law states that a body remains in its state of rest or of uniform motion in a straight line unless an unbalanced external force compels it to change that state. It is called the law of inertia because inertia is exactly this tendency of a body to resist a change in its state of rest or motion, and the law says that all bodies have it. Galileo argued that a ball rolling down one inclined plane and up another rises to nearly its original height; as the second plane is made less steep the ball travels farther to reach that height; and if the second plane were horizontal the ball, never reaching the height, would roll on for ever at constant velocity if there were no friction. Since moving bodies stop only because of friction, which is itself a force, no force is needed to keep a body moving; force is needed only to change its motion. / न्यूटन का प्रथम नियम कहता है कि कोई वस्तु अपनी विराम या सीधी रेखा में एकसमान गति की अवस्था में तब तक बनी रहती है जब तक कोई असंतुलित बाह्य बल उसे वह अवस्था बदलने के लिए विवश न करे। इसे जड़त्व का नियम इसलिए कहते हैं क्योंकि जड़त्व वस्तु की अपनी विराम या गति की अवस्था में परिवर्तन का विरोध करने की यही प्रवृत्ति है, और नियम कहता है कि सभी वस्तुओं में यह होती है। गैलीलियो ने तर्क दिया कि एक आनत तल से नीचे लुढ़ककर दूसरे पर चढ़ती गेंद लगभग अपनी मूल ऊँचाई तक पहुँचती है; दूसरे तल को कम ढालू करने पर गेंद उस ऊँचाई तक पहुँचने के लिए अधिक दूर जाती है; और यदि दूसरा तल क्षैतिज हो तो गेंद, ऊँचाई तक कभी न पहुँचकर, घर्षण न होने पर सदा स्थिर वेग से लुढ़कती रहेगी। चूँकि गतिशील वस्तुएँ केवल घर्षण के कारण रुकती हैं, जो स्वयं एक बल है, वस्तु को चलते रहने के लिए बल की आवश्यकता नहीं है; बल केवल उसकी गति बदलने के लिए चाहिए।
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Why do passengers fall backward when a bus starts suddenly and forward when it stops suddenly? Why is it advised to tie luggage on the roof of a bus with a rope? / बस के अचानक चलने पर यात्री पीछे और अचानक रुकने पर आगे क्यों गिरते हैं? बस की छत पर सामान को रस्सी से बाँधने की सलाह क्यों दी जाती है?
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When a bus starts suddenly, the feet of a standing passenger move forward with the floor of the bus, but the upper part of the body, by inertia of rest, tends to remain at rest, so the passenger falls backward. When a moving bus stops suddenly, the feet stop with the bus but the upper body, by inertia of motion, continues to move forward with the bus's earlier velocity, so the passenger falls forward. Luggage on the roof is tied with a rope because when the bus brakes suddenly, the luggage, by inertia of motion, tends to keep moving forward and would slide off the roof, and when the bus starts suddenly or takes a sharp turn it tends to stay behind or move outward; the rope supplies the force that makes the luggage change its motion along with the bus. / बस के अचानक चलने पर खड़े यात्री के पैर बस के फर्श के साथ आगे बढ़ जाते हैं, परंतु शरीर का ऊपरी भाग विराम के जड़त्व के कारण विराम में रहने की प्रवृत्ति रखता है, अतः यात्री पीछे गिरता है। चलती बस के अचानक रुकने पर पैर बस के साथ रुक जाते हैं परंतु ऊपरी शरीर गति के जड़त्व के कारण बस के पिछले वेग से आगे चलता रहता है, अतः यात्री आगे गिरता है। छत पर सामान रस्सी से इसलिए बाँधा जाता है क्योंकि बस के अचानक ब्रेक लगाने पर सामान गति के जड़त्व से आगे चलते रहने की प्रवृत्ति रखता है और छत से फिसल जाता, और बस के अचानक चलने या तीखे मोड़ पर वह पीछे रहने या बाहर की ओर जाने की प्रवृत्ति रखता है; रस्सी वह बल देती है जो सामान को बस के साथ अपनी गति बदलने पर विवश करता है।
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Define momentum and give its SI unit. A cricket ball of mass 160 g bowled at 40 m/s and a bullet of mass 20 g fired at 300 m/s — which has more momentum? / संवेग को परिभाषित कीजिए और इसकी SI इकाई दीजिए। 40 m/s से फेंकी गई 160 g की क्रिकेट गेंद और 300 m/s से दागी गई 20 g की गोली — किसका संवेग अधिक है?
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Momentum is the quantity of motion of a body, defined as the product of its mass and its velocity, p = mv; it is a vector in the direction of the velocity, and its SI unit is kilogram metre per second (kg m/s). For the cricket ball, m = 0.16 kg and v = 40 m/s, so p = 0.16 × 40 = 6.4 kg m/s. For the bullet, m = 0.02 kg and v = 300 m/s, so p = 0.02 × 300 = 6 kg m/s. The cricket ball has slightly more momentum, 6.4 kg m/s against 6 kg m/s, although the bullet is eight times lighter, because it moves much faster; this shows that momentum depends on both mass and velocity. / संवेग किसी वस्तु की गति की मात्रा है, जिसे उसके द्रव्यमान और वेग के गुणनफल p = mv के रूप में परिभाषित किया जाता है; यह वेग की दिशा में सदिश है, और इसकी SI इकाई किलोग्राम मीटर प्रति सेकंड (kg m/s) है। क्रिकेट गेंद के लिए m = 0.16 kg और v = 40 m/s, अतः p = 0.16 × 40 = 6.4 kg m/s। गोली के लिए m = 0.02 kg और v = 300 m/s, अतः p = 0.02 × 300 = 6 kg m/s। क्रिकेट गेंद का संवेग थोड़ा अधिक है, 6 kg m/s के मुकाबले 6.4 kg m/s, यद्यपि गोली आठ गुना हल्की है, क्योंकि वह कहीं तेज़ चलती है; इससे पता चलता है कि संवेग द्रव्यमान और वेग दोनों पर निर्भर करता है।
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State Newton's second law of motion and derive F = ma from it. Define one newton. / न्यूटन का गति का द्वितीय नियम लिखिए और इससे F = ma व्युत्पन्न कीजिए। एक न्यूटन को परिभाषित कीजिए।
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Newton's second law states that the rate of change of momentum of a body is directly proportional to the applied unbalanced force and takes place in the direction of the force. Let a body of mass m moving with initial velocity u be acted on by a force F for time t so that its velocity becomes v. Its initial momentum is mu and its final momentum is mv, so the change in momentum is m(v − u), and the rate of change of momentum is m(v − u)/t. By the second law, F ∝ m(v − u)/t. Since (v − u)/t is the acceleration a, F ∝ ma, or F = kma, where k is a constant. The unit of force is chosen so that k = 1, giving F = ma. One newton is the force which, acting on a body of mass 1 kg, produces in it an acceleration of 1 m/s²; thus 1 N = 1 kg m/s². / न्यूटन का द्वितीय नियम कहता है कि किसी वस्तु के संवेग परिवर्तन की दर लगाए गए असंतुलित बल के समानुपाती होती है और बल की दिशा में होती है। मान लीजिए प्रारंभिक वेग u से चलती m द्रव्यमान की वस्तु पर समय t तक बल F लगता है जिससे उसका वेग v हो जाता है। इसका प्रारंभिक संवेग mu और अंतिम संवेग mv है, अतः संवेग परिवर्तन m(v − u) है, और संवेग परिवर्तन की दर m(v − u)/t है। द्वितीय नियम से F ∝ m(v − u)/t। चूँकि (v − u)/t त्वरण a है, F ∝ ma, या F = kma, जहाँ k एक स्थिरांक है। बल की इकाई इस प्रकार चुनी जाती है कि k = 1 हो, जिससे F = ma मिलता है। एक न्यूटन वह बल है जो 1 kg द्रव्यमान की वस्तु पर लगकर उसमें 1 m/s² का त्वरण उत्पन्न करता है; अतः 1 N = 1 kg m/s²।
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Explain why a cricketer moves his hands backward while catching a fast ball, and why a high jumper lands on a cushioned bed. / समझाइए कि तेज़ गेंद पकड़ते समय क्रिकेट खिलाड़ी अपने हाथ पीछे क्यों खींचता है, और ऊँची कूद का खिलाड़ी गद्देदार बिस्तर पर क्यों उतरता है।
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By Newton's second law the force on a body equals the change in its momentum divided by the time in which the change occurs, F = (mv − mu)/t. When a fast ball is caught, its momentum must be reduced to zero; if the hands are held stiff this happens in a very short time and the force on the hands is large enough to hurt or injure. By drawing his hands backward with the ball, the cricketer increases the time over which the ball's momentum falls to zero, so the same change in momentum produces a much smaller force on his hands. In the same way, a high jumper landing on a cushioned bed or a long jumper on loose sand has the momentum of the body reduced to zero over a longer time than on hard ground, so the force on the body is smaller and injury is avoided. / न्यूटन के द्वितीय नियम से किसी वस्तु पर बल उसके संवेग परिवर्तन को उस परिवर्तन में लगे समय से भाग देने पर मिलता है, F = (mv − mu)/t। तेज़ गेंद पकड़ते समय उसका संवेग शून्य करना होता है; यदि हाथ कड़े रखे जाएँ तो यह बहुत कम समय में होता है और हाथों पर बल इतना अधिक होता है कि चोट लग सकती है। गेंद के साथ हाथ पीछे खींचकर क्रिकेट खिलाड़ी उस समय को बढ़ा देता है जिसमें गेंद का संवेग शून्य होता है, अतः उतना ही संवेग परिवर्तन उसके हाथों पर कहीं छोटा बल उत्पन्न करता है। इसी प्रकार गद्देदार बिस्तर पर उतरने वाले ऊँची कूद के खिलाड़ी या ढीली रेत पर उतरने वाले लंबी कूद के खिलाड़ी के शरीर का संवेग कठोर ज़मीन की तुलना में अधिक समय में शून्य होता है, अतः शरीर पर बल कम होता है और चोट से बचाव होता है।
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A motorcar of mass 1200 kg moving at 90 km/h is brought to rest in 4 s by applying brakes. Find the change in momentum and the braking force. / 90 km/h से चलती 1200 kg की मोटरकार ब्रेक लगाकर 4 s में रोक दी जाती है। संवेग परिवर्तन और ब्रेक बल ज्ञात कीजिए।
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First convert the initial velocity: u = 90 km/h = 90 × 5/18 = 25 m/s; the final velocity v = 0 and the time t = 4 s. Change in momentum = m(v − u) = 1200 × (0 − 25) = −30,000 kg m/s; the negative sign shows the momentum decreases. The acceleration a = (v − u)/t = (0 − 25)/4 = −6.25 m/s², a retardation of 6.25 m/s². The braking force F = ma = 1200 × (−6.25) = −7500 N, that is, a force of 7500 N acting opposite to the direction of motion; the same answer follows from F = change in momentum ÷ time = −30,000/4 = −7500 N. / पहले प्रारंभिक वेग बदलिए: u = 90 km/h = 90 × 5/18 = 25 m/s; अंतिम वेग v = 0 और समय t = 4 s। संवेग परिवर्तन = m(v − u) = 1200 × (0 − 25) = −30,000 kg m/s; ऋणात्मक चिह्न दिखाता है कि संवेग घटता है। त्वरण a = (v − u)/t = (0 − 25)/4 = −6.25 m/s², अर्थात 6.25 m/s² का मंदन। ब्रेक बल F = ma = 1200 × (−6.25) = −7500 N, अर्थात गति की दिशा के विपरीत 7500 N का बल; वही उत्तर F = संवेग परिवर्तन ÷ समय = −30,000/4 = −7500 N से मिलता है।
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State Newton's third law of motion. Explain how it applies to walking and to the launching of a rocket. / न्यूटन का गति का तृतीय नियम लिखिए। समझाइए कि यह चलने और रॉकेट के प्रक्षेपण पर कैसे लागू होता है।
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Newton's third law states that to every action there is an equal and opposite reaction: whenever one body exerts a force on a second body, the second exerts a force of equal magnitude and opposite direction on the first, the two forces acting on different bodies at the same time. In walking, the foot pushes the ground backward, which is the action; the ground pushes the foot forward with an equal force, which is the reaction, and this forward push moves the walker; on slippery ice the foot cannot push effectively and the walker slips. In a rocket, burning fuel produces hot gases that are expelled backward at high speed through the nozzle, which is the action; the gases push the rocket forward with an equal force, which is the reaction, and the rocket accelerates upward; since it pushes on its own exhaust and not on the air, it works even in the vacuum of space. / न्यूटन का तृतीय नियम कहता है कि प्रत्येक क्रिया की समान और विपरीत प्रतिक्रिया होती है: जब भी एक वस्तु दूसरी पर बल लगाती है, दूसरी पहली पर समान परिमाण और विपरीत दिशा का बल लगाती है, और ये दोनों बल एक ही समय भिन्न वस्तुओं पर लगते हैं। चलने में पैर ज़मीन को पीछे धकेलता है, जो क्रिया है; ज़मीन पैर को समान बल से आगे धकेलती है, जो प्रतिक्रिया है, और यही आगे का धक्का चलने वाले को आगे बढ़ाता है; फिसलन भरी बर्फ पर पैर प्रभावी धक्का नहीं दे पाता और व्यक्ति फिसल जाता है। रॉकेट में जलता ईंधन गर्म गैसें बनाता है जो नोज़ल से तीव्र गति से पीछे की ओर निकाली जाती हैं, जो क्रिया है; गैसें रॉकेट को समान बल से आगे धकेलती हैं, जो प्रतिक्रिया है, और रॉकेट ऊपर की ओर त्वरित होता है; चूँकि यह अपने ही निकास पर धक्का देता है, वायु पर नहीं, यह अंतरिक्ष के निर्वात में भी काम करता है।
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Action and reaction are equal and opposite, yet they do not cancel each other. Why? / क्रिया और प्रतिक्रिया समान और विपरीत हैं, फिर भी वे एक-दूसरे को निरस्त नहीं करतीं। क्यों?
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Two forces cancel each other only when they act on the same body, so that their resultant on that body is zero. Action and reaction, though equal in magnitude and opposite in direction, always act on two different bodies: the action is the force of the first body on the second, and the reaction is the force of the second body on the first. Each body therefore experiences only one of the pair, and each body accelerates according to the force on it and its own mass. For example, when a gun fires, the force on the bullet drives it forward with a large acceleration because its mass is small, while the equal force on the gun drives it backward with a small acceleration because its mass is large; neither force cancels the other, and both bodies move. / दो बल एक-दूसरे को केवल तब निरस्त करते हैं जब वे एक ही वस्तु पर लगें, ताकि उस वस्तु पर उनका परिणामी शून्य हो। क्रिया और प्रतिक्रिया, परिमाण में समान और दिशा में विपरीत होते हुए भी, सदैव दो भिन्न वस्तुओं पर लगती हैं: क्रिया पहली वस्तु का दूसरी पर बल है, और प्रतिक्रिया दूसरी वस्तु का पहली पर बल है। अतः प्रत्येक वस्तु इस युग्म का केवल एक बल अनुभव करती है, और प्रत्येक वस्तु अपने ऊपर लगे बल और अपने द्रव्यमान के अनुसार त्वरित होती है। उदाहरण के लिए, बंदूक चलने पर गोली पर लगा बल उसे बड़े त्वरण से आगे ले जाता है क्योंकि उसका द्रव्यमान छोटा है, जबकि बंदूक पर लगा समान बल उसे छोटे त्वरण से पीछे धकेलता है क्योंकि उसका द्रव्यमान बड़ा है; कोई भी बल दूसरे को निरस्त नहीं करता, और दोनों वस्तुएँ चलती हैं।
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State the law of conservation of momentum and derive it for two colliding bodies. / संवेग संरक्षण का नियम लिखिए और दो टकराती वस्तुओं के लिए इसे व्युत्पन्न कीजिए।
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The law of conservation of momentum states that when no external unbalanced force acts on a system of bodies, its total momentum remains constant; the total momentum before a collision equals the total momentum after it. Consider two bodies A and B of masses m_A and m_B moving in a straight line with velocities u_A and u_B, u_A being greater, so that A collides with B; after the collision, lasting a time t, their velocities are v_A and v_B. During the collision A exerts a force F_AB on B and, by the third law, B exerts an equal and opposite force F_BA on A, so F_AB = −F_BA. By the second law F_BA = m_A(v_A − u_A)/t and F_AB = m_B(v_B − u_B)/t. Substituting, m_B(v_B − u_B)/t = −m_A(v_A − u_A)/t, and cancelling t and rearranging gives m_A u_A + m_B u_B = m_A v_A + m_B v_B, which shows that the total momentum before the collision equals the total momentum after it. / संवेग संरक्षण का नियम कहता है कि जब किसी वस्तु-निकाय पर कोई बाह्य असंतुलित बल न लगे, तो उसका कुल संवेग स्थिर रहता है; टक्कर से पहले का कुल संवेग टक्कर के बाद के कुल संवेग के बराबर होता है। मान लीजिए m_A और m_B द्रव्यमान की दो वस्तुएँ A और B सीधी रेखा में u_A और u_B वेग से चल रही हैं, u_A अधिक है, ताकि A, B से टकराए; t समय की टक्कर के बाद उनके वेग v_A और v_B हैं। टक्कर के दौरान A, B पर बल F_AB लगाता है और तृतीय नियम से B, A पर समान और विपरीत बल F_BA लगाता है, अतः F_AB = −F_BA। द्वितीय नियम से F_BA = m_A(v_A − u_A)/t और F_AB = m_B(v_B − u_B)/t। प्रतिस्थापित करने पर m_B(v_B − u_B)/t = −m_A(v_A − u_A)/t, और t काटकर पुनर्व्यवस्थित करने पर m_A u_A + m_B u_B = m_A v_A + m_B v_B मिलता है, जो दिखाता है कि टक्कर से पहले का कुल संवेग टक्कर के बाद के कुल संवेग के बराबर है।
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A bullet of mass 20 g is fired horizontally with a velocity of 150 m/s from a pistol of mass 2 kg. Find the recoil velocity of the pistol. / 20 g की गोली 2 kg की पिस्तौल से 150 m/s के क्षैतिज वेग से दागी जाती है। पिस्तौल का प्रतिक्षेप वेग ज्ञात कीजिए।
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Before firing, both the pistol and the bullet are at rest, so the total momentum of the system is zero. Let the direction of the bullet be positive; mass of bullet m = 0.02 kg, velocity v = 150 m/s, mass of pistol M = 2 kg, recoil velocity V. By conservation of momentum the total momentum after firing is also zero: m v + M V = 0, so 0.02 × 150 + 2 × V = 0, giving 3 + 2V = 0 and V = −1.5 m/s. The pistol recoils with a velocity of 1.5 m/s in the direction opposite to that of the bullet; the negative sign indicates the opposite direction. / दागने से पहले पिस्तौल और गोली दोनों विराम में हैं, अतः निकाय का कुल संवेग शून्य है। गोली की दिशा को धनात्मक लीजिए; गोली का द्रव्यमान m = 0.02 kg, वेग v = 150 m/s, पिस्तौल का द्रव्यमान M = 2 kg, प्रतिक्षेप वेग V। संवेग संरक्षण से दागने के बाद कुल संवेग भी शून्य है: m v + M V = 0, अतः 0.02 × 150 + 2 × V = 0, जिससे 3 + 2V = 0 और V = −1.5 m/s। पिस्तौल गोली की विपरीत दिशा में 1.5 m/s के वेग से पीछे हटती है; ऋणात्मक चिह्न विपरीत दिशा दर्शाता है।
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Two hockey players of opposite teams, one of mass 60 kg moving at 5 m/s and the other of mass 55 kg moving at 6 m/s in the opposite direction, collide and become entangled. In which direction and with what speed will they move after the collision? / विपरीत टीमों के दो हॉकी खिलाड़ी, एक 60 kg का 5 m/s से और दूसरा 55 kg का विपरीत दिशा में 6 m/s से चलता हुआ, टकराकर उलझ जाते हैं। टक्कर के बाद वे किस दिशा में और किस चाल से चलेंगे?
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Take the direction of the first player as positive. Total momentum before the collision = 60 × 5 + 55 × (−6) = 300 − 330 = −30 kg m/s. After the collision the two move together with a combined mass of 60 + 55 = 115 kg and a common velocity v; by conservation of momentum, 115 v = −30, so v = −30/115 = −0.26 m/s. The negative sign shows that they move in the direction in which the second player, of mass 55 kg, was moving, with a speed of 0.26 m/s, because the second player had the greater momentum before the collision. / पहले खिलाड़ी की दिशा को धनात्मक लीजिए। टक्कर से पहले कुल संवेग = 60 × 5 + 55 × (−6) = 300 − 330 = −30 kg m/s। टक्कर के बाद दोनों 60 + 55 = 115 kg के संयुक्त द्रव्यमान और साझा वेग v से साथ चलते हैं; संवेग संरक्षण से 115 v = −30, अतः v = −30/115 = −0.26 m/s। ऋणात्मक चिह्न दिखाता है कि वे उस दिशा में चलते हैं जिसमें 55 kg का दूसरा खिलाड़ी चल रहा था, 0.26 m/s की चाल से, क्योंकि टक्कर से पहले दूसरे खिलाड़ी का संवेग अधिक था।