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Class 7 Mathematics Chapter 6 of 15

Chapter 6 — The Triangle And Its Properties

Overview

Introduction: This chapter introduces triangles — three-sided polygons — and their basic parts (vertices, sides, interior and exterior angles). It builds the foundation of plane geometry by exploring how triangles are classified, how their angles relate, and several key properties that govern their shape and size. Importance: Understanding triangles is central to geometry and is used in constructions, measurement, trigonometry (later), engineering and everyday problem solving. The chapter develops logical reasoning and proof skills through simple, clear arguments and constructions. Key themes: classification of triangles by sides (scalene, isosceles, equilateral) and by angles (acute, right, obtuse); the angle-sum property (interior angles add to 180°); the exterior-angle theorem; special properties of isosceles and equilateral triangles (equal sides and equal base angles); and the triangle inequality (sum of lengths of any two sides is greater than the third). What the student will learn: students will be able to identify and classify triangles, use a ruler and protractor to draw and measure triangles, prove and apply the sum of interior angles property, use the exterior-angle…

Learning Objectives

  • Define a triangle and identify its elements (vertices, sides, angles, interior and exterior regions).
  • Classify triangles by sides (equilateral, isosceles, scalene) and by angles (acute, obtuse, right) with examples.
  • State and apply the angle-sum property of a triangle to calculate unknown interior angles in exam-style problems.
  • State and use the exterior-angle theorem to find unknown angles and to justify angle relationships.
  • Prove that base angles of an isosceles triangle are equal and state and prove its converse.
  • Apply the triangle inequality property to determine whether three given lengths form a triangle and solve related problems.
  • Explain the concept of congruence of triangles and apply SSS, SAS and ASA criteria to test for congruence.
  • Construct triangles using ruler and compass under SSS, SAS and ASA conditions and justify the constructions.

Topics in this chapter

9 topics · tap a topic title to jump straight to it.

🔢1

Basic definitions and terminology

Triangle — definition: A triangle is a polygon with three sides and three vertices. It is named by its vertices, e.g., triangle ABC has vertices A, B and C and sides AB, BC and CA.

Parts of a triangle:

  • Vertices: The three corner points (A, B, C).
  • Sides: Line segments joining the vertices (AB, BC, CA).
  • Interior angles: Angles at the vertices (∠A, ∠B, ∠C).
  • Base: Any side chosen as the base (often BC is taken as base).
  • Altitude or height: The perpendicular from a vertex to the opposite side (or its extension).
  • Median: A line segment joining a vertex to the midpoint of the opposite side; it divides the side into two equal parts.
  • Angle bisector: A line that divides an angle into two equal angles.
  • Perpendicular bisector: A line perpendicular to a side at its midpoint; points on it are equidistant from the side's endpoints.
  • Exterior angle: An angle formed when a side of a triangle is extended; each exterior angle equals the sum of the two opposite interior angles.

Classification by sides:

  • Equilateral: All three sides equal; all angles 60°.
  • Isosceles: Two sides equal; base angles are equal.
  • Scalene: All three sides are different.

Classification by angles:

  • Acute triangle: All three angles are less than 90°.
  • Right triangle: One angle is 90°; the side opposite the right angle is the hypotenuse.
  • Obtuse triangle: One angle is greater than 90°.

Key properties:

  • The sum of the three interior angles of a triangle is 180°: ∠A + ∠B + ∠C = 180°.
  • An exterior angle equals the sum of the two opposite interior angles: exterior at A = ∠B + ∠C.
  • Triangle inequality: The sum of any two sides is greater than the third side: AB + BC > CA, BC + CA > AB, CA + AB > BC.
  • Perimeter = sum of all three sides.
  • Area (basic formula): area = (1/2) × base × height.

These definitions and properties form the foundation for understanding construction, measurement and congruence of triangles in later topics.

📌 Examples
  • Find the third angle: In triangle ABC, ∠A = 50° and ∠B = 60°. Then ∠C = 180° − (50° + 60°) = 70°.
  • Classify by sides/angles: A triangle with sides 5 cm, 5 cm and 8 cm is isosceles; if its angles are 30°, 60°, 90° it is right (90°) and also scalene if all sides differ.
  • Triangle inequality check: Can lengths 2 cm, 3 cm and 6 cm form a triangle? No, because 2 + 3 = 5 which is not greater than 6.
  • Real-life: A triangular roof truss uses triangular shapes because triangles are rigid — the shape does not change unless a side breaks.
  • Median example: In triangle ABC, if D is midpoint of BC, AD is a median. If BC = 10 cm and BD = 5 cm, AD joins A to midpoint D.
🧮 Formulas
  1. Sum of interior angles: ∠A + ∠B + ∠C = 180°
  2. Exterior angle: Exterior at A = ∠B + ∠C
  3. Triangle inequality: any two sides sum greater than the third (AB + BC > CA, etc.)
  4. Perimeter: P = AB + BC + CA
  5. Area (using base and height): Area = (1/2) × base × height
📊 Visual ideas
Draw triangle ABC with base BC horizontal. Label vertices A, B, C. Mark interior angles ∠A, ∠B, ∠C and show that their sum is 180°.
Draw an exterior angle by extending BC to a point D and show exterior angle at C equals ∠A + ∠B.
Draw a right triangle with right angle at B. Label hypotenuse AC and show height from B is equal to one leg.
Draw triangle ABC and construct median AD where D is midpoint of BC. Show BD = DC and label AD as median.
📐2

Classification of triangles

A triangle is a three-sided polygon. Triangles are classified in two common ways: by their sides and by their angles.

Classification by sides

  • Equilateral triangle: All three sides are equal. All three interior angles are equal (each 60°).
  • Isosceles triangle: Two sides are equal. The angles opposite the equal sides (base angles) are equal.
  • Scalene triangle: All three sides are of different lengths and all three angles are different.

Classification by angles

  • Acute triangle: All three interior angles are less than 90°.
  • Right triangle: One interior angle is exactly 90° (a right angle).
  • Obtuse triangle: One interior angle is greater than 90° (an obtuse angle).

Important properties (Class 7 level)

  • The sum of the interior angles of any triangle is 180°.
  • An exterior angle of a triangle equals the sum of the two opposite interior angles.
  • In an isosceles triangle, the base angles are equal.
  • In an equilateral triangle, all sides and all angles are equal (each angle = 60°).
  • Triangle inequality: the sum of the lengths of any two sides is always greater than the third side.
  • Perimeter of a triangle = sum of its three side lengths. Area (basic formula) = 1/2 × base × height.

How to identify quickly

  • Look at side lengths (or mark equal-looking sides) to decide equilateral / isosceles / scalene.
  • Estimate angles; if you see a right-angle square marker, it is a right triangle. If one angle looks bigger than a right angle it is obtuse; if all look acute it is acute.
📌 Examples
  • Equilateral: A triangular road sign of equal sides (or an equilateral triangular tile). Each angle = 60°.
  • Isosceles: A tent roof where two sides slope equally; the two sloping edges are equal, so the base angles are equal.
  • Scalene: A randomly cut triangular piece of a picture frame with all sides different.
  • Right triangle: A ramp meeting the ground forms a right triangle with the vertical support and the ground (one 90° angle).
  • Obtuse triangle: A long, flattened triangular country flag where one corner spreads out making an angle > 90°.
  • Real life: A slice of pizza is roughly an isosceles triangle; triangular trusses in bridges use various triangle types for strength.
🧮 Formulas
  1. Sum of interior angles: ∠A + ∠B + ∠C = 180°
  2. Exterior angle property: Exterior angle = sum of the two opposite interior angles
  3. Perimeter: P = a + b + c (where a, b, c are side lengths)
  4. Area (basic): Area = 1/2 × base × height
  5. Triangle inequality: a + b > c, b + c > a, c + a > b
  6. Equilateral: a = b = c and each angle = 60°
📊 Visual ideas
Sketch diagrams (hand-drawn or digital) showing and labelling examples of each type by sides: equilateral, isosceles, scalene. Label side lengths or equal marks (small dashes) on equal sides.
Sketch diagrams showing and labelling examples by angles: acute, right (mark the 90° square), obtuse. Label angles (use degree signs) to show the differences.
Coordinate-plot examples (plot on graph paper or a coordinate plane): - Equilateral: A(0,0), B(2,0), C(1,1.732) — all sides ≈ 2 units. - Isosceles: A(0,0), B(4,0), C(2,3) — AB is base, AC = BC. - Scalene: A(0,0), B(5,0), C(2,1) — all sides different. - Right triangle: A(0,0), B(3,0), C(0,4) — right angle at A. - Acute triangle: A(0,0), B(4,0), C(2,3) — all angles < 90°. - Obtuse triangle: A(0,0), B(5,0), C(2,1) — one angle > 90° at C. (Plot these points, join them in order, and measure or calculate slopes/lengths to verify types.)
Interactive suggestion: Use a dynamic geometry tool (GeoGebra) to drag vertices and observe how side lengths and angles change; highlight when two sides become equal (isosceles) or when an angle becomes 90° (right triangle).
📐3

Angle sum property of a triangle

Statement: The sum of the three interior angles of any triangle is 180°.

Why this is true (simple proof using a parallel line):

  1. Take triangle ABC. We want to show ∠A + ∠B + ∠C = 180°.
  2. Through vertex C draw a line parallel to side AB (call it l). Since l || AB, the angle formed at C by this line and AC is equal to ∠A (they are alternate interior angles). Similarly, the angle formed at C by this line and BC equals ∠B.
  3. Those two angles at C together with ∠C lie on a straight line l and therefore add up to 180° (a straight angle). So ∠A + ∠B + ∠C = 180°.

Key consequences (corollaries):

  • Each interior angle of a triangle is less than 180° and, in fact, less than 180° by the sum of the other two.
  • An exterior angle of a triangle equals the sum of the two opposite interior angles (Exterior Angle Theorem).
  • The sum of the three exterior angles (one at each vertex) taken in the same orientation is 360°.

Class 7 level remark: This property holds for all triangles (scalene, isosceles, equilateral, acute, obtuse, right) and is used to find a missing angle when the other two are known.

📌 Examples
  • Example 1 — Find the third angle: In triangle ABC, &ang;A = 50&deg; and &ang;B = 60&deg;. Find &ang;C. Solution: &ang;C = 180&deg; − (50&deg; + 60&deg;) = 70&deg;.
  • Example 2 — Isosceles triangle: In an isosceles triangle two base angles are 55&deg; each. Find the vertex angle. Solution: Vertex angle = 180&deg; − (55&deg; + 55&deg;) = 70&deg;.
  • Example 3 — Using exterior angle: In triangle PQR, the exterior angle at R is 110&deg;. If &ang;P = 40&deg;, find &ang;Q. Solution: Exterior at R = &ang;P + &ang;Q, so &ang;Q = 110&deg; − 40&deg; = 70&deg;. Check: &ang;P + &ang;Q + &ang;R = 40 + 70 + (180 − 110) = 180&deg;.
🧮 Formulas
  1. Sum of interior angles: &ang;A + &ang;B + &ang;C = 180&deg;
  2. Exterior angle theorem: An exterior angle = sum of the two opposite interior angles (e.g., exterior at A = &ang;B + &ang;C).
  3. Sum of exterior angles (one at each vertex, same orientation) = 360&deg;
  4. If two angles are known, the third angle = 180&deg; − (sum of the two known angles).
📊 Visual ideas
Static diagram: Draw triangle ABC. Through C draw a line parallel to AB. Label alternate interior angles at C equal to &ang;A and &ang;B, and show they plus &ang;C form a straight line (180&deg;). This illustrates the proof.
Interactive applet suggestion: Geogebra/Desmos app with draggable vertices A, B, C that displays the three interior angles numerically and a live sum that always shows 180&deg;. Include a toggle to show a parallel line through a vertex and mark alternate interior angles.
Bar/stack visualization: Represent the three interior angles as colored segments of a 180&deg; semicircle (or stacked bars) so students can visually see the segments adding to a straight angle.
Protractor activity graphic: Show a triangle with measured angles and overlay a protractor image; students can measure two angles and compute the third using 180&deg; − (sum).
📐4

Exterior angle property

Definition: An exterior angle of a triangle is formed when one side of the triangle is produced (extended) beyond a vertex. For example, in triangle ABC if side BC is extended to D, the angle ACD (outside the triangle) is an exterior angle at C.

Exterior angle property (Class 7 level): The measure of an exterior angle of a triangle is equal to the sum of the measures of the two opposite interior (non-adjacent) angles.

Simple proof (using angle sum of triangle):

  • In triangle ABC, extend BC to D to form exterior angle ACD.
  • Interior angles of triangle: ∠A + ∠B + ∠C = 180°.
  • Angles on a straight line: ∠ACD + ∠C = 180° (linear pair).
  • From the two equations, ∠ACD = 180° − ∠C = (∠A + ∠B + ∠C) − ∠C = ∠A + ∠B.
  • Hence exterior angle ∠ACD = ∠A + ∠B (sum of two opposite interior angles).

Corollaries:

  • An exterior angle of a triangle is greater than either of the two opposite interior angles (since it equals their sum).
  • This property helps find unknown angles quickly when one exterior and one interior (or two interiors) are known.

Why it matters: This property is a basic and frequently used result in geometry—useful in solving angle-chasing problems, proving facts about polygons, and in real-life applications like construction and design.

📌 Examples
  • Example 1: In triangle ABC, ∠A = 50° and ∠B = 60°. If BC is extended to D, find the exterior angle ∠ACD. Solution: ∠ACD = ∠A + ∠B = 50° + 60° = 110°.
  • Example 2: In triangle PQR, BC is extended at C and the exterior angle is 120°. If ∠P = 45°, find ∠Q. (Let exterior at R = 120°, opposite interior are ∠P and ∠Q.) Solution: 120° = 45° + ∠Q ⇒ ∠Q = 75°.
  • Example 3 (use to check inequality): In triangle XYZ, an exterior angle equals 130°. Show it is greater than each opposite interior angle. Since it equals the sum of the two opposite interior angles, and both are positive, each opposite interior angle must be < 130° (and in fact each < 130° and their sum = 130°).
🧮 Formulas
  1. Sum of interior angles of triangle: ∠A + ∠B + ∠C = 180°
  2. Exterior angle property: exterior angle = sum of two opposite interior angles (e.g., if BC is extended, ∠ACD = ∠A + ∠B)
  3. Exterior-angle inequality: exterior angle > each of the two opposite interior angles
  4. If exterior at vertex V is E and adjacent interior is I, then E = 180° − I
📊 Visual ideas
Diagram 1 (basic): Draw triangle ABC. Extend side BC to a point D. Mark interior angles ∠A, ∠B, ∠C and the exterior ∠ACD. Label a numeric example (e.g., ∠A = 50°, ∠B = 60°) and show ∠ACD = 110°.
Diagram 2 (proof steps): Same triangle with two small sketches: (a) show ∠A + ∠B + ∠C = 180°; (b) show ∠ACD + ∠C = 180°; then highlight that both right-hand sides are 180° to conclude ∠ACD = ∠A + ∠B. Use arrows or colour to link corresponding parts.
Interactive graph suggestion: Use GeoGebra—place triangle with draggable vertices A, B, C and a point D on line BC extended. Add dynamic text that computes ∠A, ∠B and exterior ∠ACD to visually confirm ∠ACD = ∠A + ∠B as you move vertices.
Coordinate example (to plot): Choose A(0,0), B(4,0), C(1,3). Plot triangle ABC, calculate and display interior angles (use slope/dot-product or GeoGebra), extend BC beyond C to D (e.g., D = C + (C−B)) and display the exterior angle at C to verify the property numerically.
📐5

Properties of isosceles and equilateral triangles

Definitions

An isosceles triangle has two equal sides (called the legs) and a third side called the base. An equilateral triangle has all three sides equal.

Key properties of an isosceles triangle (say triangle ABC with AB = AC)

  • Base angles are equal: ∠ABC = ∠ACB (base-angle theorem).
  • The altitude from the vertex A to the base BC also acts as the median and angle bisector: it is perpendicular to BC, bisects BC, and bisects ∠A. In other words, the perpendicular from A to BC meets BC at its midpoint.
  • If two angles of a triangle are equal, the sides opposite them are equal (converse): equality of angles implies the triangle is isosceles.
  • There is exactly one line of symmetry (the axis through the vertex and midpoint of the base).

Key properties of an equilateral triangle (side length a)

  • All sides equal and all interior angles are 60°.
  • Altitude, median, perpendicular bisector and angle bisector from any vertex coincide.
  • Centroid, incenter, circumcenter and orthocenter all coincide at the same point.
  • Three lines of symmetry (one through each vertex and opposite side midpoint) and rotational symmetry of order 3.

Why these hold (brief idea)

The equal-side → equal-angle result is proved by splitting the isosceles triangle along the altitude from the apex. This creates two congruent right triangles (by SSS or RHS), from which equal angles and equal segments follow. For equilateral triangles the same argument applied to any side shows all such special lines coincide because all three sides and three angles are identical.

📌 Examples
  • Isosceles: A triangular roof truss where the two sloping beams are equal in length; the ridge line is the axis of symmetry.
  • Isosceles: An isosceles triangular sign (e.g., some road signs) where the two sloping sides are equal.
  • Equilateral: A perfectly regular triangular tile or a triangular warning sign designed as an equilateral triangle.
  • Equilateral: Faces of a regular tetrahedron are equilateral triangles (examples in crystals or toys).
🧮 Formulas
  1. Base-angle theorem (isosceles): If AB = AC in triangle ABC, then ∠ABC = ∠ACB.
  2. Converse: If two angles of a triangle are equal, then the sides opposite them are equal (triangle is isosceles).
  3. Area (any triangle): Area = (1/2) × base × height.
  4. Isosceles height: For isosceles with equal sides = a and base = b, height h = sqrt(a^2 - (b^2 / 4)).
  5. Isosceles area: Area = (1/2) × b × h = (1/2) × b × sqrt(a^2 - (b^2 / 4)).
  6. Equilateral: each angle = 60°.
📊 Visual ideas
Isosceles triangle plot suggestion: Coordinates A = (0, h), B = (-b/2, 0), C = (b/2, 0), where b is base and h = sqrt(a^2 - (b^2/4)). Draw triangle ABC, draw altitude from A to midpoint M = (0,0); mark right angle at M and mark equal angles at B and C with small arcs. Use labels AB = AC to show equal sides.
Equilateral triangle plot suggestion: Coordinates A = (0,0), B = (a,0), C = (a/2, (sqrt(3)/2)a). Draw medians from each vertex to midpoint of opposite side; they will meet at the same center point. Label each angle 60° and show symmetry axes through each vertex and midpoint.
Plotting tips (Matplotlib sketch): Use the given coordinates, plot lines between vertices with plt.plot, draw altitudes/medians as lines to midpoints, use plt.scatter to mark centroid, and annotate angles with small circular arcs or text. For isosceles, illustrate congruent right triangles by shading or drawing matching tick marks on equal sides. For equilateral, show three identical tick marks on all sides and label height using a dashed line.
Coordinate checks: For isosceles example choose a = 5, b = 6 → h = sqrt(5^2 - 3^2) = 4; plot A=(0,4), B=(-3,0), C=(3,0). For equilateral choose a=4 → vertices (0,0),(4,0),(2,2*sqrt(3)) with height = 2*sqrt(3) ≈ 3.464.
📐6

Relationship between sides and opposite angles

Basic notation: In triangle ABC, side a = BC (opposite ∠A), b = CA (opposite ∠B), c = AB (opposite ∠C).

Main ideas:

  • Equal sides ⇄ equal opposite angles: If two sides of a triangle are equal, then the angles opposite those sides are equal. (Isosceles triangle property.)
  • Greater side ⇄ greater opposite angle: In any triangle, the greater side is opposite the greater angle, and conversely the greater angle is opposite the greater side.

Why these are true (sketches of proofs):

  1. Equal sides ⇒ equal opposite angles: If AB = AC in triangle ABC, compare triangle ABC with itself by swapping B and C. Using side-side-side (or simple symmetry), the triangles are congruent so ∠B = ∠C.
  2. Greater side ⇒ greater opposite angle (proof idea): Suppose AB > AC in triangle ABC. Mark point D on AB so that AD = AC. Triangle ADC is isosceles, so ∠ACD = ∠ADC. But ∠ABC (the whole angle at B) is larger than ∠ADC (part of it). Therefore ∠ABC > ∠ACB. So the angle opposite the longer side AB is larger than the angle opposite the shorter side AC.
  3. Converse (greater angle ⇒ greater side): If ∠B > ∠C then the side opposite ∠B (which is b = AC) is longer than the side opposite ∠C (c = AB). A proof uses contradiction: if AC ≤ AB, previous result would give ∠B ≤ ∠C, contradiction; hence AC > AB.

Important remarks:

  • All comparisons assume a non-degenerate triangle (three non-collinear points).
  • These relations let you compare unknown sides or angles: if you can compare two angles you can compare the opposite sides, and vice versa.
📌 Examples
  • Isosceles roof truss: If two rafters of a roof are equal in length, the base angles where they meet the horizontal beam are equal — helps in symmetric design.
  • Triangular park: If one fence side of a triangular plot is longer than another, the angle at the vertex opposite the longer side is larger — useful when planning corner angles.
  • Surveying sighting: When surveying from a point, if two observed lines to boundary points are equal in length, the viewing angles to those points are equal; if one sighting is longer, the opposite angle seen at the observer is larger.
🧮 Formulas
  1. Notation: In triangle ABC, a = BC, b = CA, c = AB; angles A, B, C are at vertices A, B, C respectively.
  2. Equal sides ⇄ equal opposite angles: a = b ⇔ ∠A = ∠B (and similar for other pairs).
  3. Greater side ⇔ greater opposite angle: if a &gt; b then ∠A &gt; ∠B (and conversely if ∠A &gt; ∠B then a &gt; b).
  4. Always: a, b, c &gt; 0 and triangle inequality: a &lt; b + c, b &lt; c + a, c &lt; a + b (useful background).
  5. Angle sum: ∠A + ∠B + ∠C = 180° (useful when comparing remaining angles).
📊 Visual ideas
Static labeled triangle diagram: Draw triangle ABC with sides a = BC, b = CA, c = AB; use arrows showing 'opposite' relationships (a opposite ∠A, etc.).
Interactive slider graph: Keep two sides fixed and vary the third side using a slider; display updated angle measures to show that increasing a side increases the opposite angle. (Tool suggestion: GeoGebra.)
Bar chart comparison: Bars for side lengths a, b, c next to bars for corresponding angle measures A, B, C to visualize the correlation between longer sides and larger opposite angles.
Construction sketch for proof: Triangle ABC with AB &gt; AC; mark D on AB with AD = AC; show isosceles triangle ADC and indicate ∠ABC &gt; ∠ADC = ∠ACB to illustrate the inequality.
📐7

Triangle inequality

Definition: In any triangle, the sum of the lengths of any two sides is always greater than the length of the third side. If the sides are a, b and c, then

a + b > c,   b + c > a,   c + a > b.

Why it is true (intuitive proof): The straight line is the shortest distance between two points. To go from vertex A to vertex C directly you take side AC. If you go from A to C via B you travel AB + BC, which must be longer than AC. The same reasoning applies to each pair of sides. Thus each side is less than the sum of the other two.

Important note: If the sum of two sides equals the third (for example a + b = c), the three points lie on a straight line and do not form a triangle (this is called a degenerate triangle). For a valid (non-degenerate) triangle the inequalities are strict (>).

📌 Examples
  • Numeric check: sides 3 cm, 4 cm and 6 cm. Check: 3+4=7>6, 4+6=10>3, 6+3=9>4 → these satisfy triangle inequality, so a triangle can be formed.
  • Non-example: lengths 2 cm, 3 cm and 6 cm. Check: 2+3=5 which is not greater than 6 → cannot form a triangle (segments would be collinear if 2+3=6).
  • Real-life (travel): Towns A, B and C. Direct distance A–C is always less than the distance A–B plus B–C. So taking a detour via B is longer than going straight from A to C.
  • Real-life (construction): In a roof truss, members meeting at a joint must satisfy triangle inequalities. If one member is too long compared to the other two, a stable triangular bracing can't be formed.
  • Practical (fencing): If you have three straight fence pieces, you can form a triangular pen only if each piece is shorter than the sum of the other two.
🧮 Formulas
  1. a + b > c
  2. b + c > a
  3. c + a > b
  4. |a - b| < c < a + b (equivalent compact form: the third side is greater than the difference of the other two and less than their sum)
  5. Perimeter P = a + b + c; from inequalities we get P > 2a, P > 2b, P > 2c (each side is less than half the perimeter)
📊 Visual ideas
Draw a triangle ABC and label sides a = BC, b = CA, c = AB. Beside it show the inequalities a &lt; b + c, etc., with arrows indicating that the path via the third vertex is longer than the direct side.
Number-line / bar model: place segments of length a and b end-to-end; show that their combined length is longer than a single segment of length c if a + b &gt; c. Use this to illustrate a non-triangle when the combined bar is shorter than the third bar.
Interactive slider idea: fix two side lengths (say a and b) and use a slider for c. Shade the allowed range of c between |a - b| and a + b. As the slider moves outside the shaded range, show the triangle disappearing (cannot form).
2D region plot: plot (x,y) for two side lengths x and y on axes and show vertical bounds for third side z as |x-y| &lt; z &lt; x+y. Shade the region between z = x + y and z = |x - y| to visualise allowed values for the third side (use simple 2D slices for class demonstration).
🔢8

Converse statements and corollaries

What is a converse statement?
Every theorem has the form "If P then Q." The converse swaps hypothesis and conclusion: "If Q then P." A converse may be true or false; if true it is often proved separately.

What is a corollary?
A corollary is a result that follows easily from a theorem (or from a theorem plus a little extra reasoning).

Common theorems, their converses and corollaries in triangles (Class 7 level)

  • 1. Base-Angles Theorem (Isosceles triangle theorem)
    Theorem: In triangle ABC, if AB = AC (two sides equal) then ∠B = ∠C (base angles are equal).
    Converse: If ∠B = ∠C then AB = AC (if two base angles are equal the opposite sides are equal — the triangle is isosceles).
    Corollary: If two sides are equal then the altitude/median/angle-bisector from the vertex between those sides are the same line (in an isosceles triangle the altitude from apex to base is also the median and the angle-bisector).
  • 2. Midpoint (Mid-segment) Theorem
    Theorem: If D and E are midpoints of AB and AC in triangle ABC, then DE ∥ BC and DE = (1/2)·BC.
    Converse (useful form): If a line through the midpoint of one side of a triangle is parallel to a second side, it meets the third side at its midpoint. (So: a line through midpoint of AB parallel to BC meets AC at its midpoint.)
    Corollary: The segment joining midpoints of two sides divides the triangle into two smaller triangles of equal area.
  • 3. Exterior-Angle Remark and corollary
    Theorem (exterior angle): An exterior angle of a triangle equals the sum of the two opposite interior angles and is greater than either of them.
    Corollaries: (a) Any exterior angle > any one opposite interior angle. (b) If an angle is equal to the sum of two other angles, it can be an exterior angle formed by extending the appropriate side.
  • 4. Relationship between equal angles and symmetrical properties
    Corollary from base-angles theorem: If a triangle has two equal angles, it is symmetric about the perpendicular from the apex to the base; construction and measurement properties follow (useful in compass-and-straightedge constructions).

How to use converse and corollary in problem solving
- To prove a side is equal, you can try to prove equal opposite angles and then use the converse of the base-angles theorem.
- If you know a segment is parallel and one endpoint is a midpoint, use the midpoint converse to get the other midpoint.
- Use corollaries to get quick facts (equal areas, combined equalities) without re-proving the full theorem.

Note on logic: Always check whether a converse is valid before using it. If it is not stated as a true theorem, provide a short proof or counterexample.

📌 Examples
  • Isosceles roof: A symmetrical roof has two equal sloping sides (AB = AC). By the base-angles theorem, the angles where the roof meets each wall are equal. Conversely, if those meeting angles are measured equal, the sloping sides are equal (useful to check symmetry).
  • Midpoint example in construction: In a triangular garden ABC, if you mark midpoints D (on AB) and E (on AC) and join them, DE is parallel to BC and is half its length. If a path through D is drawn parallel to BC and meets AC at E, then E is the midpoint of AC (use of the converse).
  • Making a tent (practical use of converse): If the two base angles where poles meet the ground are equal, then the two pole lengths are equal — this helps ensure stable symmetric tent design.
🧮 Formulas
  1. Base-angles theorem: AB = AC ⇒ ∠B = ∠C
  2. Converse: ∠B = ∠C ⇒ AB = AC
  3. Mid-segment theorem: If D, E are midpoints of AB, AC then DE ∥ BC and DE = (1/2)·BC
  4. Midpoint converse (useful form): If D is midpoint of AB and a line through D is parallel to BC and meets AC at E, then E is midpoint of AC
  5. Exterior-angle relation: Exterior angle at A = ∠B + ∠C and exterior angle > ∠B, exterior angle > ∠C
📊 Visual ideas
Isosceles triangle diagram: Draw triangle ABC with AB = AC. Mark equal sides with ticks and equal base angles ∠B, ∠C with identical arc marks. Label and show the altitude/median/angle-bisector from A meeting BC at D (all coincide).
Converse check diagram: Draw triangle ABC where ∠B = ∠C (mark arcs). Show that AB and AC are equal by constructing perpendicular bisectors or by reflecting one side about the angle bisector.
Midpoint theorem diagram: Triangle ABC with points D on AB and E on AC marked as midpoints. Draw DE and show DE ∥ BC and DE = 1/2 BC; add measurements or use coordinates: A(0,0), B(4,0), C(1,3) ⇒ D(mid AB)=(2,0), E(mid AC)=(0.5,1.5), BC length≈√((4−1)^2+(0−3)^2)=√(9+9)=√18, DE length≈0.5·√18.
Coordinate-plot suggestion: Use coordinates to demonstrate converse/midpoint facts. Example: For triangle A(0,0), B(6,0), C(2,4): midpoints D(3,0) and E(1,2) ⇒ DE slope = (2−0)/(1−3)=−1, BC slope = (4−0)/(2−6)=−1 ⇒ DE ∥ BC and DE = 1/2·BC (compute lengths). Plot points and join segments to visualize.
🔢9

Problems, proofs and applications

Overview: This topic deals with solving problems about triangles, proving fundamental properties, and seeing how those properties are useful in real life. Key properties include the sum of interior angles, the exterior-angle theorem, the triangle inequality, and special facts about isosceles and scalene triangles. Understanding proofs helps you apply these facts correctly in constructions and problem solving.

1. Sum of interior angles = 180° (Proof)
Let triangle ABC be given. Through vertex C draw a line parallel to AB. The angle at A and the angle formed at C with that parallel line are alternate interior angles, so they are equal. Similarly the angle at B equals the other angle formed at C. Thus the three interior angles of triangle ABC form a straight line at C, so their sum = 180°.

2. Exterior-angle theorem (Proof)
If at vertex B of triangle ABC we extend side BC to D, then angle ABD (the exterior angle at B) equals the sum of the two opposite interior angles (angle A + angle C). Proof: Using the straight-line relation at B, angle ABD = 180° − angle ABC. From (1), angle A + angle B + angle C = 180°, so angle A + angle C = 180° − angle B = angle ABD.

3. Triangle inequality (Proof)
In any triangle, the sum of lengths of any two sides is greater than the third side. For example, AB + BC > AC. Proof (geometric idea): Place triangle ABC with A and B along a line and extend AB past B to a point D so that BD = BC. Then AC is shorter than AD = AB + BD = AB + BC, so AB + BC > AC. This works for any choice of two sides.

4. Isosceles triangle property (Proof)
If two sides of a triangle are equal (say AB = AC), then base angles are equal (angle B = angle C). Proof idea: Draw perpendicular/ or use triangle congruence: triangles formed by dropping a perpendicular from A to BC or by considering triangles ABC and ACB show corresponding sides and angles equal.

Common problem types include: proving equal angles or sides, computing a missing angle using angle-sum or exterior-angle theorem, checking inequalities for side lengths, and constructing triangles with given data (side-side-side, side-angle-side, etc., where permissible).

Applications: Designing roof trusses (isosceles shapes), measuring heights/ distances indirectly, checking structural stability (triangle inequalities ensure members reach), navigation and surveying (triangulation uses triangle angle relations), and constructing rigid frames (triangles provide rigidity).

How to approach problems:

  1. Draw a clear diagram and label all known quantities.
  2. Look for parallel lines, straight lines, or equal sides/angles to apply theorems.
  3. Use the angle-sum (180°) and exterior-angle theorem to find missing angles.
  4. Use the triangle inequality when comparing side lengths or deciding feasibility of construction.
  5. When asked to prove, state given information, what to prove, and give a sequence of logical steps referring to earlier theorems.

Tips for proofs: Use parallel-line arguments (alternate interior/ corresponding angles), extend sides to form exterior angles, and use congruence of smaller triangles where appropriate.

📌 Examples
  • Finding a missing angle: In triangle ABC, angle A = 50° and angle B = 60°. Find angle C. (Use angle-sum: C = 180° − 50° − 60° = 70°.)
  • Using exterior-angle theorem: At vertex B extend BC to D. If angle A = 40° and angle C = 55°, find exterior angle ABD. (ABD = A + C = 95°.)
  • Checking feasibility: Can lengths 3 cm, 4 cm and 8 cm form a triangle? (No — 3 + 4 = 7 ≤ 8, violates triangle inequality.)
  • Isosceles application: A triangular roof has two equal rafters. If each rafter makes base angles of 65°, the apex angle = 180° − 65° − 65° = 50°. Useful when cutting rafters to length.
  • Measuring indirectly: Stand some distance from a tall tree and measure a horizontal distance and the angle of elevation to the top. Using triangle angle relations (and later trigonometry) one can find the tree height—foundation for surveying.
  • Comparing sides and angles: In triangle ABC if angle A is the largest, then side BC is the longest. This helps decide which member of a triangular frame needs stronger material.
🧮 Formulas
  1. Sum of interior angles: ∠A + ∠B + ∠C = 180°
  2. Exterior angle theorem: An exterior angle = sum of the two opposite interior angles (e.g., ∠ABD = ∠A + ∠C).
  3. Triangle inequality: For any triangle with sides a, b, c: a + b > c, b + c > a, c + a > b.
  4. Isosceles triangle: If AB = AC then ∠B = ∠C (and converse: equal angles imply equal opposite sides).
  5. Perimeter: Perimeter P = AB + BC + CA.
  6. Area (basic): Area = 1/2 × base × height (useful in some triangle applications).
📊 Visual ideas
Draw triangle ABC with A(0,0), B(4,0), C(1,3). Label sides and angles. Use a protractor on the drawing or compute slopes to verify that angle A + angle B + angle C ≈ 180° (calculate slopes to get angles numerically).
To illustrate the exterior-angle theorem: Draw triangle ABC, extend BC to D. Mark angles A and C and measure exterior angle ABD; show ABD equals A + C. Coordinates: A(0,0), B(3,0), C(1,2), D(5,0).
To verify triangle inequality on a coordinate plane: Use triangle with A(0,0), B(3,0), C(1,2). Compute distances AB, BC, CA using distance formula and check AB + BC > AC, etc. (AB=3, BC≈2.236, AC≈2.236 so 3+2.236>2.236 holds.)
Parallel-line proof diagram: Draw triangle ABC and through C draw line l parallel to AB. Mark alternate interior angles equal to angles A and B, then show they sum with angle C to form a straight line (180°). This is ideal as an annotated diagram.

Key Concepts

Triangle
A polygon with three sides and three angles formed by three non-collinear points.
Side
A line segment that forms the boundary of a triangle, joining two vertices.
Sum of interior angles
The sum of the three interior angles of any triangle is 180 degrees.
Exterior angle
An angle formed by one side of a triangle and the extension of an adjacent side.
Exterior angle theorem
An exterior angle of a triangle equals the sum of the two opposite interior angles.
Triangle inequality
The sum of the lengths of any two sides of a triangle is greater than the third side.
Acute triangle
A triangle in which all three interior angles are less than 90°.
Obtuse triangle
A triangle that has one angle greater than 90° and the other two acute.
Right triangle
A triangle with one interior angle equal to 90°.
Hypotenuse
The side opposite the right angle in a right-angled triangle; the longest side.
Equilateral triangle
A triangle with all three sides equal and all three interior angles equal (each 60°).
Isosceles triangle
A triangle with at least two equal sides; the angles opposite equal sides are equal.
Scalene triangle
A triangle with all three sides of different lengths and all three angles different.
Median
A line segment from a vertex to the midpoint of the opposite side.
Altitude (height)
A perpendicular segment from a vertex to the line containing the opposite side.
Perpendicular bisector
A line that is perpendicular to a side of a triangle and divides that side into two equal parts.
Angle bisector
A ray or line segment that divides an angle into two equal angles.
Centroid
The point of intersection of the three medians of a triangle; it is the triangle's center of mass and divides each median in a 2:1 ratio (vertex to centroid : centroid to midpoint).
Circumcenter
The point where the perpendicular bisectors of the sides of a triangle meet; it is the center of the circle passing through all three vertices (circumcircle).
Incenter
The point where the angle bisectors of a triangle meet; it is the center of the inscribed circle (incircle) tangent to all three sides.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. In triangle ABC, ∠A = 55° and ∠B = 70°. What is ∠C? / त्रिभुज ABC में ∠A = 55° और ∠B = 70° है। ∠C क्या है? (a) 55° (b) 45° (c) 65° (d) 125°
    Show answer

    (a) 55° — The angle sum property states ∠A + ∠B + ∠C = 180°. So ∠C = 180° – 55° – 70° = 55°. / कोण योग गुण: ∠A + ∠B + ∠C = 180°। अतः ∠C = 180° – 55° – 70° = 55°।

  2. An exterior angle of a triangle is 110°. If one opposite interior angle is 45°, what is the other? / एक त्रिभुज का बाह्य कोण 110° है। यदि एक विपरीत आंतरिक कोण 45° है, तो दूसरा क्या है? (a) 55° (b) 65° (c) 70° (d) 45°
    Show answer

    (b) 65° — Exterior angle = sum of two opposite interior angles. So the other angle = 110° – 45° = 65°. / बाह्य कोण = दोनों विपरीत आंतरिक कोणों का योग। अतः दूसरा कोण = 110° – 45° = 65°।

  3. Which of the following sets of lengths CANNOT form a triangle? / निम्नलिखित में से कौन-सा समुच्चय त्रिभुज नहीं बना सकता? (a) 3 cm, 4 cm, 6 cm (b) 5 cm, 7 cm, 10 cm (c) 2 cm, 3 cm, 6 cm (d) 6 cm, 7 cm, 8 cm
    Show answer

    (c) 2 cm, 3 cm, 6 cm — The triangle inequality requires the sum of any two sides to be greater than the third. Here 2 + 3 = 5 which is NOT greater than 6, so no triangle is possible. / त्रिभुज असमानता: किन्हीं दो भुजाओं का योग तीसरी भुजा से अधिक होना चाहिए। 2 + 3 = 5 > 6 नहीं है, इसलिए त्रिभुज नहीं बनेगा।

  4. Fill in the blank: In an isosceles triangle, the two angles opposite the equal sides are called ______ angles. / रिक्त स्थान भरें: समद्विबाहु त्रिभुज में, बराबर भुजाओं के सामने के दोनों कोण ______ कोण कहलाते हैं।
    Show answer

    Base / आधार — In an isosceles triangle, the angles at the base (opposite the equal sides) are equal and called base angles. / समद्विबाहु त्रिभुज में आधार पर (बराबर भुजाओं के सामने) के कोण समान होते हैं और आधार कोण कहलाते हैं।

  5. Fill in the blank: Each interior angle of an equilateral triangle measures ______ degrees. / रिक्त स्थान भरें: समबाहु त्रिभुज के प्रत्येक आंतरिक कोण का माप ______ डिग्री है।
    Show answer

    60 — Since all three angles are equal and they sum to 180°, each angle = 180° ÷ 3 = 60°. / तीनों कोण समान हैं और उनका योग 180° है, इसलिए प्रत्येक कोण = 180° ÷ 3 = 60°।

  6. True or False: A triangle can have two obtuse angles. / सत्य या असत्य: किसी त्रिभुज में दो अधिक कोण हो सकते हैं।
    Show answer

    False / असत्य — Each obtuse angle is more than 90°, so two obtuse angles would already exceed 180°, which violates the angle sum property. A triangle can have at most one obtuse angle. / दो अधिक कोणों का योग 180° से अधिक होगा, जो कोण-योग गुण के विरुद्ध है।

  7. The sides of a triangle are 5 cm, 12 cm and 13 cm. What type of triangle is it, and why? / एक त्रिभुज की भुजाएं 5 cm, 12 cm और 13 cm हैं। यह किस प्रकार का त्रिभुज है और क्यों?
    Show answer

    It is a right-angled triangle / यह समकोण त्रिभुज है — Check: 5² + 12² = 25 + 144 = 169 = 13². Since the square of the longest side equals the sum of squares of the other two, it is a right triangle (converse of Pythagoras). / 5² + 12² = 169 = 13², इसलिए यह समकोण त्रिभुज है।

  8. In a triangle, the exterior angle at vertex C is 120°. The two opposite interior angles are equal. Find both interior angles. / एक त्रिभुज में शीर्ष C पर बाह्य कोण 120° है। दोनों विपरीत आंतरिक कोण समान हैं। दोनों कोण ज्ञात करें।
    Show answer

    Each opposite interior angle = 60° — The exterior angle equals the sum of the two opposite interior angles: 120° = ∠A + ∠B. Since ∠A = ∠B, we get 2∠A = 120°, so ∠A = ∠B = 60°. / बाह्य कोण = विपरीत आंतरिक कोणों का योग: 120° = ∠A + ∠B = 2∠A, इसलिए प्रत्येक कोण = 60°।

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