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Class 10 Science Chapter 16 of 27

Chapter 10 — Electricity

Overview

Chapter: Electricity (Class 10 Science, NCERT) Introduction: This chapter develops the basic concepts of electric current, potential difference and resistance and shows how they govern the behaviour of simple electrical circuits. It introduces Ohm’s law, the concept of resistivity, methods of combining resistors, and the heating effect of current. Practical aspects such as using ammeters and voltmeters, calculating power and energy consumption, and simple safety measures are included. Importance: Electricity is fundamental to everyday life and technological systems. Understanding these concepts helps students analyze circuits, compute energy use and bills, design safe connections (series/parallel), and form the foundation for more advanced topics in physics and electrical engineering. Key themes: Ohm’s law and V–I characteristics; resistance and resistivity; series and parallel combinations of resistors; measurement with ammeter and voltmeter; electric power and Joule heating; energy, unit conversions (J, kWh) and household applications; safety (fuses, earthing) and practical problem solving. What the student will learn: definitions and SI units of current, potential difference…

Learning Objectives

  • Define electric current, state its SI unit and indicate the conventional direction of current flow
  • Explain electric potential difference (voltage) and state its SI unit; calculate voltage across circuit elements
  • Apply Ohm's law to calculate current, potential difference or resistance and plot and interpret V–I graphs
  • Distinguish between ohmic and non‑ohmic conductors using their V–I characteristics
  • State the factors on which resistance depends and derive the relation R = ρL/A; explain resistivity
  • Calculate equivalent resistance for resistors connected in series and in parallel and solve related numerical problems
  • Determine the emf and internal resistance of a cell from experimental data and explain terminal potential difference
  • Analyze and solve circuit problems involving combinations of resistors to find currents, voltage drops and equivalent resistance

Topics in this chapter

15 topics · tap a topic title to jump straight to it.

⚡1

Electric current

Definition: Electric current is the rate of flow of electric charge through a conductor. It is the amount of charge that passes through a cross-section of a conductor per unit time.

Symbol and unit: Current is denoted by I and its SI unit is ampere (A). 1 A = 1 coulomb per second.

Microscopic picture: In metallic conductors, free electrons move randomly; when an electric field is applied they acquire a small average drift velocity superimposed on random motion. This net movement of charge carriers (electrons) constitutes electric current. By convention, current direction is taken as the direction positive charges would move (conventional current), opposite to electron flow in metals.

Mathematical definition: If a charge Q passes a cross-section in time t, the average current I = Q/t. For time-varying current, instantaneous current i(t) = dQ/dt.

Ohm's law (for ohmic conductors): For many conductors at constant temperature, current is proportional to the potential difference (voltage) across it: V = IR, where R is the resistance. Resistances add in series and combine via reciprocal sum in parallel.

Resistance and factors affecting it: Resistance R depends on the material and geometry: R = ρ L / A, where ρ is resistivity (material property), L is length and A is cross-sectional area. For metals resistivity and hence resistance generally increase with temperature; in semiconductors resistivity typically decreases with temperature.

Power dissipation: A current I through an element with voltage V across it dissipates electric power P = VI. Using Ohm's law, P can be written as P = I²R or P = V²/R.

Steady (DC) and time-varying (AC) currents: Direct current (DC) has a constant direction and magnitude (e.g., cells, batteries), while alternating current (AC) periodically reverses direction (e.g., mains supply). The instantaneous current in AC varies with time; RMS values are used to describe effective heating power.

Measurement: Current is measured with an ammeter connected in series with the circuit element. Practical safety devices like fuses and circuit breakers protect circuits from excessive current.

Common misconceptions & notes: (1) Current is not the same as voltage: voltage is the cause (potential difference), current is the effect (flow of charge). (2) The same current flows through all elements in a series circuit; in parallel circuits the total current splits among branches.

📌 Examples
  • Bulb in a torch: battery provides voltage, causing current through the filament which heats up and emits light (current determines brightness).
  • Mobile phone charger: current from adapter charges the phone’s battery; too high current can overheat cells (regulated charging circuits control current).
  • Electric kettle: large current through the heating element dissipates power (P = I²R) and heats water quickly.
  • Household wiring: mains AC supplies currents to appliances; currents determine power consumption and require appropriate wire thickness and fuses.
  • Electrolyte in batteries: current is carried by ions in solution (not electrons) during chemical reactions inside the cell.
  • Fuse or MCB: protect circuits by interrupting current when it exceeds a safe value to prevent damage or fire.
🧮 Formulas
  1. I = Q / t (average current)
  2. i(t) = dQ/dt (instantaneous current)
  3. V = I R (Ohm's law for ohmic conductors)
  4. P = V I = I^2 R = V^2 / R (electric power)
  5. R = ρ L / A (resistance in terms of resistivity)
  6. Series resistors: R_eq = R1 + R2 + ...
📊 Visual ideas
V–I graph for an ohmic conductor: x-axis = V (voltage), y-axis = I (current). Expect a straight line through the origin; slope = 1/R. Use to show linear relationship and constant resistance.
V–I graph for a filament lamp (non-ohmic): x-axis = V, y-axis = I. Curve is nonlinear: at low V nearly linear, at higher V slope decreases (resistance increases with temperature).
I–t graph for DC source: x-axis = time, y-axis = I. For steady DC current the plot is a horizontal line (constant current). For switched circuits show step changes when switches open/close.
I vs R (for fixed V): x-axis = R, y-axis = I. Hyperbolic decay: I = V/R. Use to show inverse relation between current and resistance.
⚡2

Electric potential and potential difference

Electric potential (V) at a point is defined as the work done by an external agent in bringing a unit positive charge from infinity (where potential is taken as zero) to that point, without acceleration. It is a scalar quantity and its SI unit is the volt (1 V = 1 J/C).

Mathematically: V = W/q, where W is the work done (in joules) and q is the test charge (in coulombs).

Potential difference (ΔV) between two points A and B is the work done by an external agent in taking a unit positive charge from A to B. It is equal to the difference of potentials at the two points:

ΔV = VB − VA = Wext/q, where Wext is the work done by the external force in moving charge q from A to B. If a charge q moves through a potential difference ΔV, its change in electric potential energy is ΔU = q·ΔV.

Relation with electric field: Electric field and potential are related. The potential difference between two nearby points separated by displacement ds in the direction of the field is dV = −E·ds (in one dimension, E = −dV/ds). For a uniform field between parallel plates, the magnitude of potential difference is |ΔV| = E·d, where d is the plate separation.

Potential of a point charge: For an isolated point charge Q (with potential zero at infinity): V(r) = kQ/r, where k = 1/(4πε0) and r is distance from the charge. This potential decreases as r increases (for positive Q).

Equipotential surfaces: Surfaces on which potential is the same everywhere are called equipotential surfaces. No work is required to move a charge along an equipotential. Equipotentials are always perpendicular to electric field lines.

In circuits: The potential difference between two points in a circuit gives the driving force that causes current. The electromotive force (EMF) of a source is the work done per unit charge in moving charge inside the source; terminal potential difference may differ from EMF when internal resistance exists.

📌 Examples
  • Battery in a torch: The battery provides a potential difference between its terminals; this potential difference drives electrons through the bulb, producing light.
  • Capacitor: Two plates at different potentials store charge; the potential difference V between plates stores energy U = 1/2 C V^2.
  • Parallel-plate arrangement: A uniform electric field between plates separated by distance d gives ΔV = E·d (useful in cathode-ray tubes and parallel-plate capacitors).
  • Point charge: The potential around a single positive charge falls as V = kQ/r; this explains why test charge experiences less potential far away.
  • Lightning: Large potential differences between clouds and ground cause breakdown of air leading to discharge (lightning).
  • Electrostatic precipitator: Uses potential differences to charge dust particles and collect them on plates.
🧮 Formulas
  1. V = W/q (Electric potential = work per unit charge) [Unit: volt (V) = J/C]
  2. ΔV = VB − VA = Wext/q (Potential difference between points A and B)
  3. ΔU = q·ΔV (Change in electric potential energy of charge q)
  4. V(r) = kQ/r (Potential due to a point charge; k = 1/(4πε0))
  5. ΔV = −∫(E·ds) (General relation between field and potential)
  6. For uniform field: |ΔV| = E·d (e.g., between parallel plates separated by d)
📊 Visual ideas
V vs r for a point charge: plot V = kQ/r (hyperbola) showing V → ∞ as r → 0 and V → 0 as r → ∞.
V vs distance between parallel plates: straight line (linear) — potential changes uniformly with distance; slope gives E (E = −dV/dx).
Potential along a line of a uniform field: linear decrease (or increase) — useful to show sign and magnitude of potential difference between two points.
Equipotential surfaces and field lines diagram: concentric spheres (equipotentials) around a point charge with radial field lines perpendicular to surfaces.
⚡3

Electric circuit and circuit diagrams

What is an electric circuit?
An electric circuit is a closed path that allows electric charges (current) to flow from a source of electrical energy (like a cell or battery) through conductors and electrical components (resistors, lamps, switches, etc.) and back to the source. If the path is broken, the circuit is open and current stops.

Basic components

  • Source: cell or battery (provides electromotive force, EMF).
  • Conductors: wires (usually copper) that connect components.
  • Load: device that consumes electrical energy (bulb, resistor, motor).
  • Switch: opens or closes the circuit to control current.
  • Protective devices: fuse or circuit breaker to prevent excessive current.
  • Measuring instruments: ammeter (measures current) and voltmeter (measures potential difference).

Conventional current direction
Conventional current is taken as the flow of positive charge from the positive terminal of the battery, through the circuit, to the negative terminal.

Pictorial vs schematic (circuit) diagrams
A pictorial diagram shows the actual appearance and relative positions of components; a schematic diagram uses standard symbols to show how components are electrically connected. Schematic diagrams are preferred for analysis because they are clear and unambiguous.

Important schematic symbols (commonly used)

  • Cell / Battery (short and long parallel lines)
  • Resistor (zig-zag or rectangle)
  • Wire (solid line)
  • Switch (open/closed break in wire)
  • Bulb / Lamp (circle with a cross)
  • Ammeter (circle with 'A', connected in series)
  • Voltmeter (circle with 'V', connected in parallel)
  • Fuse (a strip or small rectangle in series) and earth/ground symbol

Series and parallel connections
Series: components connected end-to-end so the same current flows through each. Equivalent resistance adds: R_eq = R1 + R2 + ...
Parallel: components connected across the same two points so the potential difference across each is the same. Reciprocal rule: 1/R_eq = 1/R1 + 1/R2 + ... . In parallel, total current splits among branches.

Practical consequences

  • In series, if one component (like a bulb) fails (opens), the entire circuit stops working.
  • In parallel (household wiring), each appliance works independently — one appliance failing does not cut power to others.
  • Ammeter must be placed in series (low internal resistance); voltmeter in parallel (high internal resistance).

How to draw a neat circuit diagram

  • Use standard symbols and straight lines.
  • Show clear connections and junctions (dots) where wires meet.
  • Label instruments and polarity of sources (+ and –).
  • Indicate where ammeter and voltmeter are connected in experimental circuits.

Simple analysis with Ohm's law
Ohm's law relates voltage (V), current (I) and resistance (R): V = I R. Using this and series/parallel rules you can compute currents, voltages across elements and equivalent resistance of simple circuits.

📌 Examples
  • Torch (flashlight): one or more cells in series powering a bulb through a switch — a simple closed circuit.
  • Household wiring: appliances are connected in parallel so each gets full supply voltage and can be operated independently.
  • String of old-style Christmas lights: many bulbs in series — if one bulb fused the entire string went out (modern strings use parallel or bypass circuits).
  • Car electrical system: a 12 V battery supplies many loads in parallel (headlights, horn, radio) and has fuses and switches for protection and control.
🧮 Formulas
  1. Ohm's law: V = I × R (Voltage = Current × Resistance)
  2. Current: I = V / R
  3. Resistance (series): R_eq = R1 + R2 + ... + Rn
  4. Resistance (parallel): 1 / R_eq = 1 / R1 + 1 / R2 + ... + 1 / Rn
  5. Electric power: P = V × I = I^2 × R = V^2 / R
  6. Charge and energy (useful for problems): Q = I × t (charge = current × time); E = V × I × t (energy)
📊 Visual ideas
I–V characteristic of an ohmic resistor: plot Current (I) on the vertical axis and Potential Difference (V) on the horizontal axis. For an ohmic conductor the graph is a straight line through the origin; slope = 1/R.
I–V plot of a non-ohmic device (e.g., filament bulb): axes as above; curve is nonlinear — at higher V the filament’s resistance increases, bending the curve.
Equivalent resistance vs number of identical resistors (series): x-axis = number of resistors (n), y-axis = R_eq. For identical resistors R each, R_eq = nR (a straight line upward).
Equivalent resistance vs number of identical resistors (parallel): x-axis = number of resistors (n), y-axis = R_eq. For identical resistors R each, R_eq = R/n (a hyperbola-like decrease approaching zero as n increases).
🔬4

Ohm's law

Ohm's law: For a metallic conductor kept at a constant temperature, the electric current (I) through it is directly proportional to the potential difference (V) across its ends. Mathematically, I ∝ V (at constant temperature), which leads to the fundamental relation V = IR.

Meaning of terms: V is the potential difference in volts (V), I is the current in amperes (A), and R is the electrical resistance in ohms (Ω). Resistance is a measure of how much a conductor opposes the flow of electric charge. For a given conductor R = V / I (constant for that conductor at fixed temperature).

Experimental verification (simple circuit):

  • Apparatus: battery or variable DC source, ammeter (in series), voltmeter (in parallel across the conductor), connecting wires, and a resistor or nichrome wire whose V–I behaviour is to be measured.
  • Procedure: Vary the source voltage in steps, record the corresponding current each time (keep the conductor’s temperature approximately constant).
  • Observation: Plot V (y-axis) versus I (x-axis). For an ohmic conductor the plot is a straight line through the origin. The slope of the V–I line is the resistance R (slope = V / I). Equivalently, the slope of I versus V is the conductance (1/R).

Microscopic idea (brief): In metals, free electrons drift under an applied electric field. Collisions of electrons with the lattice (ions, impurities) dissipate energy and produce resistance. If scattering conditions remain the same (constant temperature), the drift velocity — and thus current — is proportional to the applied field (and hence V), giving Ohm’s law.

Limitations: Ohm's law holds for ohmic materials (most metallic conductors) at constant temperature. Many devices (e.g., semiconductor diodes, filament lamps, thermistors) are non-ohmic — their V–I relationship is not linear because their resistance changes with voltage, current or temperature.

Applications: Ohm's law is used to calculate currents, voltages and resistances in circuits, to design resistor values, to size wiring and fuses, and to analyze simple circuit behavior.

📌 Examples
  • A copper wire (metallic conductor) carrying current: doubling the applied voltage doubles the current (ohmic behaviour) provided temperature is constant.
  • Using Ohm’s law to find current: A 12 V battery connected to a 6 Ω resistor draws I = V/R = 12/6 = 2 A.
  • Calculating resistance: A lamp draws 0.5 A at 230 V; its resistance at that operating temperature is R = V/I = 230/0.5 = 460 Ω (note: filament lamps are usually non-ohmic when cold).
  • Designing a series circuit: For two resistors 4 Ω and 6 Ω in series on a 10 V source, total R = 10 Ω, so I = 10/10 = 1 A throughout the circuit.
  • Safety/current rating: If an appliance draws 10 A at 230 V, the effective resistance is R = 230/10 = 23 Ω; fuses and wires are chosen based on expected currents.
  • Non-ohmic example: A diode’s V–I plot is strongly nonlinear — Ohm’s law (simple proportionality) does not apply over all voltages.
🧮 Formulas
  1. Ohm's law: V = I R
  2. Equivalent forms: I = V / R ; R = V / I
  3. Conductance: G = 1 / R (unit: siemens, S)
  4. Power (using Ohm's law): P = V I = I^2 R = V^2 / R
  5. Resistance in terms of resistivity (related topic): R = ρ L / A (ρ = resistivity, L = length, A = cross-sectional area)
📊 Visual ideas
V–I graph for an ohmic conductor: straight line passing through the origin. X-axis: I (A). Y-axis: V (V). Slope = R (Ω). Interpretation: linear relation V ∝ I.
I–V graph (I on Y, V on X) for an ohmic conductor: straight line through origin. Slope = 1/R (conductance). Useful to show inverse relation interpretation.
V–I graph for a filament bulb (non-ohmic): curve that is nonlinear — at low V the current increases faster, but as the filament heats up the slope decreases (resistance increases). Axes: same as above; annotate region showing temperature rise.
I–V characteristic of a diode (non-ohmic): almost zero current for small forward V, then sharp rise after threshold; reverse bias shows tiny current until breakdown. Good to contrast with straight-line Ohmic behaviour.
🔬5

Resistance and resistivity

What is resistance?
Resistance is the property of a conductor that opposes the flow of electric current. It determines how much current flows for a given potential difference across the conductor. The SI unit of resistance is the ohm (symbol: Ω).

Ohm's law (for ohmic conductors)
For many conductors (called ohmic), the current through them is directly proportional to the potential difference across them provided temperature and other physical conditions remain constant. Mathematically, V ∝ I or V = IR, where V is potential difference, I is current, and R is resistance. This relation defines the resistance R = V/I.

Factors affecting resistance

  • Length (L): Resistance is directly proportional to the length of the conductor. Longer conductor → larger resistance.
  • Cross-sectional area (A): Resistance is inversely proportional to the cross-sectional area. Thicker conductor → smaller resistance.
  • Material: Different materials offer different intrinsic opposition to current. This property is expressed by resistivity.
  • Temperature: For most metals resistance increases with temperature; for some materials (e.g., thermistors) it decreases with temperature.

Resistivity (ρ)
Resistivity is a material property that quantifies how strongly a material resists current. It is defined for a uniform wire by the relation R = ρL/A. The SI unit of resistivity is ohm-meter (Ω·m). Low resistivity means good conductor (e.g., copper, silver); high resistivity means poor conductor or insulator.

Microscopic view
On the microscopic level, electrons moving under an electric field collide with atoms, impurities and lattice vibrations. Those collisions dissipate electrical energy as heat and manifest macroscopically as resistance.

Non-ohmic behavior
Not all devices obey Ohm's law. For example, a filament bulb has resistance that changes with temperature; its V–I graph is nonlinear. Semiconductor devices (diodes, transistors) are also non-ohmic.

Typical equations and units

  • Resistance: R = V/I, unit: ohm (Ω).
  • Resistivity: R = ρL/A → ρ = RA/L, unit: ohm-meter (Ω·m).
  • Temperature dependence (approx. for metals): R = R0(1 + αΔT), where α is temperature coefficient of resistance.

Practical importance
Understanding resistance and resistivity helps in designing electrical wiring, choosing materials for heating elements, making resistors for circuits, preventing excessive heating in appliances, and using sensors (thermistors, RTDs) that rely on resistance change with temperature.

📌 Examples
  • Copper wire used for household wiring — low resistivity, chosen to minimize energy loss.
  • Filament of an incandescent bulb — its resistance increases as it heats up; non-ohmic behavior.
  • Heating element in electric kettle — made of high-resistance alloy so it converts electrical energy to heat.
  • Thermistor in a thermostat — resistance changes significantly with temperature and is used for temperature sensing.
  • Graphite in a pencil or carbon resistor — higher resistivity than metals; used where moderate resistance is needed.
🧮 Formulas
  1. Ohm's law: R = V / I
  2. Resistance of a uniform conductor: R = ρ L / A
  3. Resistivity from measurement: ρ = R A / L
  4. Series resistances: R_total = R1 + R2 + ...
  5. Parallel resistances: 1 / R_total = 1 / R1 + 1 / R2 + ...
  6. Temperature dependence (metal, approx.): R = R0 (1 + α ΔT)
📊 Visual ideas
V vs I (ohmic conductor): straight line through origin. Slope = V/I = R. Plot V on vertical axis and I on horizontal axis.
V vs I (non-ohmic device, e.g., filament lamp): nonlinear curve. Shows increasing slope as filament heats up (effective R increases).
R vs L for fixed A and material: straight line through origin. Slope = ρ/A. Plot R (vertical) against length L (horizontal).
R vs 1/A for fixed L and material: straight line through origin. Slope = ρ L. Plot R (vertical) vs 1/A (horizontal).
🔬6

Factors affecting resistance

What is resistance? Resistance (R) is a measure of how strongly an object opposes the flow of electric current. Its SI unit is ohm (Ω). Ohm's law relates voltage (V), current (I) and resistance: V = I·R for ohmic conductors.

Main factors that affect resistance

  • Length (L): Resistance is directly proportional to the length of the conductor. A longer wire has more collisions between electrons and the atomic lattice, so R increases with L. Mathematically: R ∝ L.
  • Cross‑sectional area (A): Resistance is inversely proportional to the cross‑sectional area. A thicker wire provides more paths for electrons, so R decreases as A increases. Mathematically: R ∝ 1/A. For a circular wire A = πd²/4, so R ∝ 1/d² where d is diameter.
  • Material (resistivity, ρ): Different materials offer different intrinsic opposition to current, described by resistivity ρ (unit: Ω·m). Metals (copper, aluminum) have low ρ; insulators have very high ρ. R ∝ ρ.
  • Temperature (T): Resistance changes with temperature. For most metals resistance increases with temperature (positive temperature coefficient). For some semiconductors and thermistors, resistance decreases as temperature rises (negative coefficient). For small temperature changes: R(T) = R0[1 + α(T − T0)], where α is the temperature coefficient of resistance.
  • Impurities, crystal structure and mechanical condition: Alloying, impurities, strain, or defects increase scattering and usually increase resistance. Very thin films or rough wires behave differently from ideal uniform conductors.

Combined formula: For a uniform conductor of length L and cross‑sectional area A made of a material of resistivity ρ, the resistance is given by:

R = ρ · L / A

Practical consequences: Power loss in a conductor carrying current I is P = I²R. Thus using low‑resistance, short, and thick conductors (and low‑ρ materials) reduces energy loss — important in power transmission. Conversely, resistive heating elements use high‑ρ materials and suitable geometry to produce heat.

📌 Examples
  • House wiring: Thick copper cables (large A, low ρ) are used to keep resistance and power loss small. A long extension lead increases resistance and may warm up if current is large.
  • Power transmission lines: Use conductors with low resistivity (aluminium or copper) and large cross‑section to reduce I²R losses. High‑voltage transmission reduces current (thus reducing losses).
  • Electric heater / kettle: Use high‑resistivity alloy (nichrome) in a long coiled form to get significant resistance and generate heat (R = ρL/A).
  • Fuse: A thin wire (small A) with relatively large resistance for its size heats and melts when current exceeds a safe value, protecting the circuit.
  • Filament bulb: When switched on, the tungsten filament heats up and its resistance increases (non‑linear I–V relationship).
  • Thermistor: A temperature-dependent resistor used for temperature sensing—NTC thermistors decrease resistance with increasing temperature (negative α).
🧮 Formulas
  1. Ohm’s law: V = I · R
  2. Resistance of uniform conductor: R = ρ · L / A (ρ = resistivity, unit: Ω·m)
  3. Circular wire area: A = π · d² / 4 ⇒ R ∝ 1 / d²
  4. Temperature dependence (approx., small ΔT): R(T) = R0 [1 + α (T − T0)] (α = temperature coefficient, unit: °C⁻¹)
  5. Power dissipated as heat: P = I² · R = V² / R = V · I
📊 Visual ideas
R versus L: straight line through the origin (linear). Plot R on y‑axis and L on x‑axis; slope = ρ/A. Show two lines for different A (thinner wire steeper slope).
R versus A: hyperbolic decreasing curve. Plot R on y‑axis and A on x‑axis; R falls rapidly as area increases. Provide inset showing relation for diameter (R ∝ 1/d²).
R versus temperature for a metal: approximately straight line with positive slope. Plot R on y‑axis and T on x‑axis; label slope αR0. For a semiconductor/NTC thermistor show a curve that decreases with T (negative temperature coefficient).
I–V graph: For an ohmic resistor, a straight line through origin (linear). For a filament lamp, a curved I–V characteristic that flattens at high V (non‑ohmic) because resistance rises with temperature.
🔬7

Series and parallel combinations of resistors

Basic idea
Resistors can be connected in two simple ways: in series (end-to-end) or in parallel (side-by-side). These combinations change the net (equivalent) resistance seen by a source and how current and voltage distribute in the circuit.

Series combination
When resistors R1, R2, ... are connected one after another, the same current I flows through each resistor. The equivalent resistance R_eq (series) is the sum of resistances:
R_eq = R1 + R2 + ... + Rn

Voltage divides across series resistors: V_total = V1 + V2 + ... where Vi = I * Ri. Larger resistances get proportionally larger voltage drops (voltage divider).

Parallel combination
When resistors are connected with both ends joined (parallel), the voltage across each resistor is the same (V). The total current I_total is the sum of branch currents: I_total = I1 + I2 + ... where Ii = V / Ri. The reciprocal of equivalent resistance is the sum of reciprocals:
1 / R_eq = 1 / R1 + 1 / R2 + ... + 1 / Rn

For two resistors in parallel: R_eq = (R1 * R2) / (R1 + R2).

Key properties & intuition

  • Series: R_eq increases as you add resistors (current decreases for fixed voltage).
  • Parallel: R_eq decreases as you add resistors (total current increases for fixed voltage).
  • In series current is common; in parallel voltage is common.
  • Power dissipated: P = V * I = I^2 * R = V^2 / R. In series, P_i = I^2 * Ri. In parallel, P_i = V^2 / Ri.
  • Special cases: a branch with resistance = 0 behaves like a short circuit; an open branch (infinite R) carries no current.

Worked numeric examples

Example 1 (series): R1 = 4 Ω, R2 = 6 Ω, battery V = 12 V.
R_eq = 4 + 6 = 10 Ω. Current I = V / R_eq = 12 / 10 = 1.2 A.
Voltage drops: V1 = I * R1 = 1.2 * 4 = 4.8 V, V2 = 1.2 * 6 = 7.2 V (4.8 + 7.2 = 12 V).

Example 2 (parallel): R1 = 4 Ω, R2 = 6 Ω, battery V = 12 V.
1 / R_eq = 1/4 + 1/6 = 5/12 → R_eq = 12/5 = 2.4 Ω.
Total current I_total = V / R_eq = 12 / 2.4 = 5 A. Branch currents: I1 = 12/4 = 3 A, I2 = 12/6 = 2 A (3 + 2 = 5 A).

When circuits are mixed
Many practical circuits combine series and parallel parts. Reduce stepwise: replace a simple series or parallel block by its R_eq, redraw, and repeat until a single R_eq remains.

Safety and applications
Parallel wiring is used in homes so each appliance gets full mains voltage and can operate independently. Series wiring is used where same current is required through components (e.g., some string circuits), but complete series strings are avoided for mains lighting because one failure may turn off the whole string.

📌 Examples
  • Home wiring: appliances are wired in parallel so each gets full voltage and can be switched independently.
  • Christmas lights (older types): often in series — if one bulb fused the whole string went out; modern strings use series-parallel to avoid this.
  • Torch (flashlight) batteries: cells are placed in series to add voltages (e.g., two 1.5 V cells give 3.0 V).
  • Electronic circuits: voltage dividers (series resistors) provide lower voltages; parallel resistors share current and protect loads.
  • Worked numeric example (series): R1=4Ω, R2=6Ω, V=12V → R_eq=10Ω, I=1.2A, V1=4.8V, V2=7.2V.
  • Worked numeric example (parallel): R1=4Ω, R2=6Ω, V=12V → R_eq=2.4Ω, I_total=5A, I1=3A, I2=2A.
🧮 Formulas
  1. Ohm's law: V = I * R
  2. Series equivalent: R_eq(series) = R1 + R2 + ... + Rn
  3. Voltage in series: Vi = I * Ri and V_total = sum(Vi)
  4. Parallel equivalent: 1 / R_eq(parallel) = 1 / R1 + 1 / R2 + ... + 1 / Rn
  5. Two-resistor parallel: R_eq = (R1 * R2) / (R1 + R2)
  6. Current in parallel branch: Ii = V / Ri and I_total = sum(Ii)
📊 Visual ideas
V–I characteristic for a single resistor: plot V (y-axis) vs I (x-axis) — straight line through origin with slope equal to R. Show two lines for two resistors with different slopes.
R_eq vs number of equal resistors: (a) series: linear increase (plot R_eq on y-axis, number n on x-axis for R each = R0: R_eq = n * R0). (b) parallel: hyperbolic decrease approaching 0 as n increases (R_eq = R0 / n).
Voltage division in series: bar or line plot showing V1 and V2 proportions for R1 and R2 (x-axis: position along series chain, y-axis: voltage).
Current division in parallel: bar chart of branch currents I1, I2 for given V and different R values (x-axis branches, y-axis current).
🔬8

Internal resistance and emf of a cell

Emf (E): Emf (electromotive force) of a cell is the chemical energy converted to electrical energy per unit charge when no current is drawn (open-circuit). It is measured in volts (V). Emf is the maximum potential difference the cell can provide.

Internal resistance (r): A real cell is not an ideal voltage source — it has some internal resistance due to the electrolyte, electrodes and connections. This resistance is called the internal resistance (r) and is measured in ohms (Ω). When current flows, some energy is lost inside the cell across r, so the terminal voltage across the cell drops.

Terminal voltage and relations: If a cell of emf E and internal resistance r is connected to an external resistor R and current I flows, the terminal voltage V (voltmeter reading across the cell terminals) is:

V = E − I r

Ohm's law for the external circuit gives:

I = E / (R + r)

These two relations come from the loop equation: E = I(R + r) = I R + I r. The part I R appears across the external resistor and I r is dropped inside the cell.

Power: Power delivered to the external resistor is Pext = I2 R. Power dissipated inside the cell is Pint = I2 r. The total power supplied by the cell is Ptotal = E I.

Maximum power transfer: The external device receives maximum power when R = r. The maximum power delivered to R then is:

P_max = E2 / (4 r) (when R = r)

Determination of E and r (experimental method):

  • Measure the open-circuit terminal voltage (no load) — this equals emf E (approx.).
  • Connect different known resistances R, measure current I and terminal voltage V for each.
  • Plot V (y-axis) versus I (x-axis). The graph is a straight line: V = E − r I. The y-intercept gives E and the slope is −r.

Why internal resistance matters (qualitative): When a device draws heavy current (small R), the I r drop is large, so the terminal voltage falls significantly and the device may underperform. Internal resistance also causes heating and reduces battery life.

📌 Examples
  • Phone battery: When running a heavy app or camera flash, the phone voltage momentarily drops because internal resistance causes a larger I·r drop; performance or brightness may reduce.
  • Car starter: Starter motor draws very large current; a car battery must have very low internal resistance (≈ 0.01–0.05 Ω) so the terminal voltage does not collapse when starting the engine.
  • Flashlight (torch): As the battery discharges its internal resistance increases, so the bulb gets dimmer even if the battery’s emf hasn’t changed much.
  • Worked numerical example: A cell has emf E = 1.5 V. With an external resistor R = 5.0 Ω the measured current is I = 0.25 A. Find the internal resistance r and terminal voltage V. Solution: Terminal voltage V = I·R = 0.25×5.0 = 1.25 V. Then r = (E − V)/I = (1.5 − 1.25)/0.25 = 1.0 Ω. Terminal voltage under that load is 1.25 V.
🧮 Formulas
  1. V = E − I r (terminal voltage when current I flows)
  2. I = E / (R + r) (current in the external circuit)
  3. E = I (R + r) (loop equation)
  4. P_ext = I^2 R (power delivered to external resistor)
  5. P_int = I^2 r (power dissipated inside the cell)
  6. P_total = E I (total electrical power supplied by the cell)
📊 Visual ideas
V vs I (terminal voltage on y-axis, current on x-axis): straight line with intercept E (at I = 0) and slope −r. Use measured (I, V) points and draw best-fit line; y-intercept = E, magnitude of slope = internal resistance r.
I vs 1/(R + r) or I vs 1/(R + constant): show that current decreases nonlinearly with increasing R; better to plot I vs 1/(R + r) when r known.
Power delivered to external resistor vs R: plot P_ext = I^2 R = [E^2 R]/(R + r)^2 versus R. This curve peaks at R = r showing maximum power transfer; include a marker at R = r and annotate P_max = E^2/(4r).
Schematic diagram: draw a cell represented by an ideal emf E in series with a small resistor r, connected to an external resistor R, with an ammeter in series and a voltmeter across the cell (voltmeter reads V). Label drops E, I r and I R.
📏9

Measurement of resistance

What is being measured? Resistance (R) of a conductor tells how much it opposes the flow of electric current. For many conductors (ohmic conductors) at constant temperature, voltage across the conductor is proportional to current through it (Ohm's law): V ∝ I.

Basic principle: R = V / I where V is potential difference across the resistor and I is the current through it. In experiment we vary V, measure corresponding I, plot V versus I and obtain R from the graph.

Common experimental methods:

  • Ammeter–Voltmeter method: Connect the unknown resistor, an ammeter in series and a voltmeter in parallel with the resistor. Use a variable source (rheostat or variable supply). For several settings record V and I, plot V (y-axis) vs I (x-axis). For an ohmic conductor the plot is a straight line through origin; slope = R.
  • Accuracy notes for ammeter–voltmeter method: Real ammeters and voltmeters have internal resistances (Ra and Rv). Two practical errors arise: (a) some current flows through the voltmeter (if Rv not very large) so ammeter reads total current; (b) the voltmeter may include the ammeter resistance in its reading if connected differently. To correct or reduce errors use a high-resistance voltmeter and a low-resistance ammeter, keep voltmeter always across only the resistor, and prefer the arrangement that prevents voltmeter current from passing through the ammeter.
  • Wheatstone bridge (for high accuracy): A balanced bridge compares the unknown resistance Rx with known resistances. At balance (no current through galvanometer) the ratio of two known arms equals the ratio of the other two arms, giving Rx from the known values. This method is preferred for small resistances or high-precision measurement.

Practical procedure (Ammeter–Voltmeter method):

  1. Set up circuit with battery, rheostat, ammeter in series, unknown resistor R_x, and voltmeter connected across R_x.
  2. Adjust rheostat to get several different currents. For each record ammeter reading I and voltmeter reading V.
  3. Plot V (y-axis) vs I (x-axis). For linear graph slope = R_x. Alternatively calculate R = V/I for stable reading.
  4. Keep temperature as constant as possible (resistance changes with temperature).

Sources of error and how to reduce them:

  • Internal resistances of meters — use meters with suitable ranges (high-range voltmeter, low-resistance ammeter) and apply corrections when required (formulas given below).
  • Heating of the resistor as current flows — take readings quickly or use small currents.
  • Contact and connection resistances — use clean tight connections, four-terminal (Kelvin) method for very low resistances.

When Ohm's law does not hold: For non-ohmic devices (e.g., filament bulb, diode), V–I graph is non-linear; resistance depends on V or I (or temperature).

📌 Examples
  • Measuring resistance of a metallic wire: Connect a wire as the unknown resistor, vary current with a rheostat, record V and I, plot V vs I. If the line is straight through origin, slope = R of the wire. Example: measured pairs (V,I) = (0.5 V,0.10 A), (1.0 V,0.20 A) give R = V/I = 5 Ω.
  • Correcting for voltmeter loading: Suppose voltmeter resistance Rv = 10 kΩ, voltmeter reads V = 5.0 V and ammeter reads I_total = 0.520 A. Current through voltmeter Iv = V/Rv = 0.0005 A, so actual current through resistor I_R = I_total - Iv = 0.5195 A and true R = V/I_R ≈ 9.62 Ω.
  • Using a Wheatstone bridge: Known resistors R1 = 100 Ω, R2 = 200 Ω, R3 = 150 Ω and Rx is unknown. At balance Rx = (R2/R1) * R3 = (200/100)*150 = 300 Ω.
🧮 Formulas
  1. Ohm's law: R = V / I
  2. Resistivity: ρ = R * A / L (so R = ρ * L / A)
  3. Series resistances: R_series = R1 + R2 + ...
  4. Parallel resistances: 1/R_parallel = 1/R1 + 1/R2 + ...
  5. Power in resistor: P = VI = I^2 R = V^2 / R
  6. Correction for finite voltmeter resistance (voltmeter in parallel with resistor): true R = V / (I - V/Rv) where Rv is voltmeter resistance, V is voltmeter reading and I is ammeter reading
📊 Visual ideas
V vs I (for an ohmic conductor): straight line through origin. Plot V (y-axis) and I (x-axis). Slope = R.
I vs V (same data): straight line; slope = 1/R. Useful if you prefer current on vertical axis.
V vs I for a filament bulb: curved (non-linear) graph — shows resistance increases with temperature/current.
Circuit sketch: Ammeter in series with the resistor and voltmeter in parallel with the resistor. (Draw standard symbols: circle with A for ammeter, circle with V for voltmeter.)
🔋10

Electric power

Definition: Electric power is the rate at which electrical energy is converted into some other form (heat, light, mechanical work) per unit time. It tells how fast work is done by an electric current.

Basic formula and units: If W is the work (or energy) done in time t, electric power P is P = W / t. The SI unit of power is watt (W), where 1 W = 1 J s-1. In electrical circuits power can be expressed in terms of voltage (V), current (I) and resistance (R):

  • P = V I (power = potential difference × current)
  • Using Ohm's law (V = IR): P = I2 R
  • Also P = V2 / R

Derivation (short): The electrical work done in moving charge Q through a potential difference V is W = QV. If Q flows in time t, current I = Q / t, so W / t = V (Q / t) = V I. Hence P = V I. Substituting V = IR gives the alternate forms above.

Electrical energy and units used in billing: Energy consumed by an appliance of power P operating for time t is E = P t. For household billing power is often given in kilowatts (kW) and time in hours (h), so energy is measured in kilowatt-hour (kWh). 1 kWh = 1000 W × 3600 s = 3.6 × 106 J.

Practical meaning & appliances: The power rating on an appliance (for example 60 W for a bulb) is the rate at which it consumes electrical energy. Higher power means more energy use per second and usually a brighter lamp or more heat produced. Choosing appliances and calculating electricity cost requires using P and time: Cost = (P in kW × hours) × rate per kWh.

Safety and efficiency notes: Devices with large power draw require thicker wires, proper fuses, and safe sockets because large current may cause heating. Two appliances with the same resistance behave differently depending on voltage and current: at fixed voltage P decreases with larger resistance (P = V2/R), while at fixed current P increases with R (P = I2R).

📌 Examples
  • A 60 W bulb connected to a 230 V supply draws current I = P/V = 60 / 230 ≈ 0.26 A.
  • A 1 kW (1000 W) heater running for 3 hours consumes energy E = P t = 1000 W × 3 h = 3 kWh = 3 × 3.6 × 10^6 J = 10.8 MJ. If electricity costs $0.12 per kWh, the cost = 3 × $0.12 = $0.36.
  • Compare two resistive heaters on the same 230 V line: R1 = 50 Ω gives P1 = V^2/R1 = 230^2 / 50 ≈ 1058 W; R2 = 100 Ω gives P2 ≈ 529 W. The lower-resistance heater draws more power and more current.
  • Using P = I^2 R: If a device draws 5 A through a 10 Ω resistor, power dissipated as heat is P = I^2 R = 5^2 × 10 = 250 W.
🧮 Formulas
  1. P = W / t (power = energy or work done per unit time)
  2. P = V I (power = potential difference × current)
  3. P = I^2 R (using V = IR)
  4. P = V^2 / R (using V = IR)
  5. E = P t (electrical energy = power × time)
  6. 1 kWh = 3.6 × 10^6 J
📊 Visual ideas
Power (P) vs Resistance (R) for fixed supply voltage V: plot P = V^2 / R. Axes: x = R (Ω), y = P (W). Shape: hyperbola decreasing (power falls as resistance increases). Example: V = 230 V, R from 1 Ω to 1000 Ω.
Power (P) vs Resistance (R) for fixed current I: plot P = I^2 R. Axes: x = R (Ω), y = P (W). Shape: straight line through origin (linear increase). Example: I = 2 A, R from 0 to 200 Ω.
Power (P) vs Voltage (V) for fixed resistance R: plot P = V^2 / R. Axes: x = V (V), y = P (W). Shape: parabola (P ∝ V^2). Example: R = 50 Ω, V from 0 to 240 V.
Power (P) vs Current (I) for fixed resistance R: plot P = I^2 R. Axes: x = I (A), y = P (W). Shape: parabola (P ∝ I^2). Example: R = 10 Ω, I from 0 to 10 A.
⚡11

Heating effect of electric current and Joule's law

Definition: When an electric current passes through a conductor, electrical energy is partly converted into heat energy. This phenomenon is called the heating effect of electric current.

Joule's law (statement): The heat produced in a conductor in a given time is directly proportional to the square of the current passing through the conductor, to the resistance of the conductor, and to the time for which the current flows. In symbolic form: H ∝ I2 R t.

Derivation (using Ohm's law and electric power):

  • Instantaneous electrical power dissipated as heat: P = V I.
  • Using Ohm's law V = I R, P = I (I R) = I2 R.
  • Energy (heat) produced in time t: H = P t = I2 R t. This is Joule's law in equation form.
  • Alternate forms: H = V I t and H = V2 t / R (using V = I R).

Units: Heat (H) is measured in joules (J). Current I in amperes (A), resistance R in ohms (Ω), time t in seconds (s). Power P in watts (W), where 1 W = 1 J/s.

Physical reason: Charges (electrons) moving through a resistive material collide with ions and lattice atoms, losing kinetic energy that appears as internal energy (heat) of the material.

Relation to temperature rise: The heat produced can raise the temperature of the conductor. If the conductor (or body) of mass m and specific heat capacity c has temperature rise ΔT, then H = m c ΔT. Combining with Joule's law: I2 R t = m c ΔT (useful to estimate temperature rise).

Simple experimental demonstration: Connect a length of nichrome wire to a battery and ammeter, measure current I and time t, and observe temperature rise (or melting of wax/fuse). Vary I (by changing voltage or wire length) and note how heat production changes (H ∝ I2).

Important notes:

  • For a fixed current, heat produced increases with resistance. For a fixed voltage, heat produced decreases with increasing resistance (H = V2 t / R).
  • Joule heating is the principle behind many heating devices but is a loss in power-distribution lines. Wires carrying large currents may heat up and must be sized to avoid overheating.
📌 Examples
  • Electric iron: Electrical energy converts to heat in the heating element (H ∝ I^2 R t) to iron clothes.
  • Electric kettle and immersion rod: Resistive element heats water; heat produced raises water temperature (I^2 R t = m c ΔT).
  • Toaster and electric stove: Resistive coils produce heat to toast or cook food.
  • Incandescent bulb filament: Current through thin tungsten filament produces heat and light (filament glows because it is very hot).
  • Fuse: Designed to melt when excessive current flows; heating (I^2 R t) causes the fuse wire to reach melting point and break the circuit, protecting devices.
  • Overheated power lines: High current causes I^2 R losses and heating; may require thicker conductors or cooling.
🧮 Formulas
  1. Joule's law: H = I^2 R t
  2. Alternate forms: H = V I t and H = V^2 t / R
  3. Electric power: P = V I = I^2 R = V^2 / R
  4. Heat–temperature relation: H = m c ΔT
  5. Combined for temperature rise: I^2 R t = m c ΔT
📊 Visual ideas
Heat H (y-axis) vs Current I (x-axis) for fixed R and t: parabolic curve (H ∝ I^2). Label axes and show H = I^2 R t as guide.
Heat H (y-axis) vs Time t (x-axis) for fixed I and R: straight line through origin (H ∝ t). Show slope = I^2 R.
Heat H (y-axis) vs Resistance R (x-axis) for fixed I and t: straight line (H ∝ R). Slope = I^2 t.
Heat H (y-axis) vs Voltage V (x-axis) for fixed R and t: parabolic curve (H ∝ V^2).
⚡12

Household electric circuits and safety

Overview
A household electric circuit supplies electric energy from the mains (typically 230 V AC, 50 Hz) to appliances through three conductors: live (L), neutral (N) and earth (E). Live carries current to the appliance, neutral returns it to the supply, and earth provides a low-resistance path to ground for fault currents to protect people and equipment.

Basic wiring and connections

  • Distribution: mains meter → main switch → distribution board (fuse/MCB/ELCB/RCD) → branch circuits for lights, sockets and heavy appliances.
  • Parallel connection: Most household loads (lamps, fans, sockets) are connected in parallel so each device receives the full supply voltage and can operate independently.
  • Switch placement: Switches are placed in the live wire so that when switched off the appliance is isolated from the live supply.

Common fault types

  • Open circuit: wire broken or switch off — device does not work.
  • Short circuit: live to neutral/earth contact with very low resistance causing a sudden large current — risk of fire and damage.
  • Overload: too many devices/draw exceeds rated current of circuit causing heating and possible fuse/MCB trip.
  • Earth fault (leakage): current flows from live to earth — shock hazard unless protective device acts.

Protective devices and how they work

  • Fuse: a thin wire (or strip) sized to melt when current exceeds its rating for a short time. It provides simple, inexpensive overcurrent protection. Replace only with the correct rating.
  • MCB (Miniature Circuit Breaker): an automatic switch that trips on overcurrent. It can be reset after tripping and protects against overload and short circuit.
  • RCD/ELCB (Residual Current Device/Earth Leakage Circuit Breaker): detects imbalance between live and neutral currents (indicating leakage to earth) and trips quickly to prevent electric shock. Typical sensitivity for personal protection is ~30 mA.
  • Earthing: connecting the metal body of an appliance to earth ensures that in case of internal insulation failure the fault current flows to earth, causing fuse/MCB to operate and reducing shock risk.

Safety practices

  • Use proper fuses/MCBs with correct ratings; do not bypass or replace with higher ratings to avoid fire risk.
  • Install RCDs for bathrooms, kitchens and outdoor circuits where leakage/shock risk is higher.
  • Ensure all metal-bodied appliances are earthed or are double-insulated if earthing is not provided.
  • Do not touch electrical appliances with wet hands, avoid overloading sockets, and use certified plugs and wiring.
  • Switch off the main supply before doing wiring work; call a qualified electrician for faults.

Why parallel wiring for household loads?
In a parallel circuit each appliance gets full supply voltage; turning one off does not affect others. If bulbs were in series, voltage and brightness would change and one failure would break the entire string.

Energy and cost
Household energy consumption is calculated from electrical power and time. Managing high-power devices (heaters, air conditioners) and using energy-efficient appliances reduces consumption and risk of overloading circuits.

📌 Examples
  • Two table lamps are connected to the same room socket in parallel: each lamp gets 230 V and can be switched on/off independently.
  • A short circuit occurs when the live wire inside a fan comes into contact with its metal body (earth fault). If the body is earthed, large fault current flows to earth and the MCB/fuse trips, preventing shock.
  • A kettle (2 kW) and a heater (1.5 kW) are plugged into the same socket rated 13 A (≈3 kW at 230 V). Using both may overload the circuit and trip the MCB or blow the fuse.
  • An RCD (30 mA sensitivity) installed for bathroom sockets trips instantly if a person contacting a live conductor allows leakage current to flow to earth, preventing a lethal shock.
  • A blown fuse in a room indicates either an overloaded circuit or a short; replacing the fuse with a higher-rated one is dangerous because it disables proper protection.
  • Household earthing example: a washing machine with metal body has its frame connected to earth. If live wire insulation fails and touches the frame, earth provides a path so protective devices trip quickly.
🧮 Formulas
  1. Ohm's law: V = I × R (voltage = current × resistance)
  2. Electric power: P = V × I
  3. Alternative power forms: P = I^2 × R and P = V^2 / R
  4. Energy consumed: E = P × t (energy = power × time); E in joules or kWh for billing (1 kWh = 3.6 × 10^6 J)
  5. Series resistances: R_total = R1 + R2 + ...
  6. Parallel resistances: 1 / R_total = 1 / R1 + 1 / R2 + ...
📊 Visual ideas
I–V graph for an ohmic conductor (straight line through origin) vs I–V curve for an incandescent bulb (non-linear: slope decreases as filament heats). Useful to show why filament resistance increases with temperature.
P vs R at fixed voltage (P = V^2 / R): shows power delivered to a load decreases as resistance increases (hyperbolic shape).
Current vs time for a short circuit: sharp spike until protective device (fuse/MCB) acts — illustrate typical operating/clearing time differences between fuse (melting) and MCB (magnetic trip).
Voltage distribution in series circuit: bar chart showing voltage drops across series resistors summing to supply voltage.
🔬13

Conductors, insulators and semiconductors

Overview
Materials are classified by how well they allow electrical charge to move. Conductors allow easy flow of charge (current), insulators resist charge flow, and semiconductors lie between the two and can be engineered (by doping, temperature, or fields) to change their conductivity.

Microscopic reason (simple band picture)

  • Atoms have electrons in energy bands. The valence band is the highest filled band and the conduction band is the next higher empty band.
  • Conductor (metal): valence and conduction bands overlap or there are free electrons — electrons move easily under an electric field.
  • Insulator: a wide band gap (large energy difference) exists between valence and conduction bands — electrons cannot jump the gap under ordinary conditions, so current is negligible.
  • Semiconductor: a small band gap (Eg) — only a small energy (thermal or via doping) is needed to promote electrons to the conduction band so conductivity is moderate and strongly temperature-dependent.

Charge carriers and conduction mechanisms

  • Conductors: conduction mainly by free electrons (in metals) or by ions in electrolytes.
  • Insulators: extremely few free carriers; charge does not flow under normal electric fields.
  • Semiconductors: intrinsic (pure) semiconductors have few carriers produced by thermal excitation. Doping with donor (n-type) or acceptor (p-type) atoms increases carrier concentration and hence conductivity.

Temperature dependence

  • Metals: as temperature increases, lattice vibrations increase, scattering increases and resistivity (R) increases approximately linearly: R(T) ≈ R0[1 + α(T − T0)], where α is the temperature coefficient of resistivity.
  • Semiconductors: increasing temperature generates more electron–hole pairs, so conductivity increases strongly (roughly exponentially) with temperature: σ ∝ e^{−Eg/(2kT)} (Eg = band gap, k = Boltzmann constant).
  • Insulators: behave like semiconductors with a very large Eg, so carrier generation is negligible at ordinary temperatures.

Practical implications

  • Conductors are used for wires and contacts (e.g., copper, aluminum, silver) because of low resistance.
  • Insulators are used to coat wires and prevent leakage (e.g., rubber, plastic, glass).
  • Semiconductors are the basis of electronic devices (diodes, transistors, solar cells, LEDs) because their conductivity can be precisely controlled by doping, temperature, and applied voltages.

Key measurable quantities

  • Resistance (R) — how much a component resists current (ohms, Ω).
  • Resistivity (ρ) — material property: R = ρ(L/A) for a uniform rod of length L and cross-section A.
  • Conductivity (σ) — σ = 1/ρ; higher σ means easier current flow.

Note for Class 10: The above band ideas are a simple qualitative model to explain why materials behave differently. Important practical differences are seen in V–I characteristics (Ohmic vs non-Ohmic behavior) and in how conductivity changes with temperature.

📌 Examples
  • Conductors: Copper wires in electrical circuits, aluminum power lines, silver contacts. (Reason: many free electrons → low resistance.)
  • Insulators: Rubber or plastic insulation on wires, glass insulators on high‑voltage pylons, dry wood. (Reason: very few free charge carriers.)
  • Semiconductors (intrinsic): Pure silicon and germanium crystals used in teaching and basic components.
  • Semiconductors (doped): Silicon doped with phosphorus (n‑type) or boron (p‑type) used to make diodes, transistors and ICs.
  • Other examples: Graphite (a non‑metal that conducts), electrolytes/acid solutions (conduct by ions), human body (conducts because of ionic fluids).
  • Everyday device: LED (light‑emitting diode) — a p–n junction semiconductor that emits light when forward biased; solar cell — converts light to electricity using semiconductor junctions.
🧮 Formulas
  1. Ohm's law: V = I × R (Voltage V in volts, current I in amperes, resistance R in ohms Ω)
  2. Resistance of a uniform conductor: R = ρ × (L / A) (ρ = resistivity, L = length, A = cross‑sectional area)
  3. Conductivity: σ = 1 / ρ (σ in siemens per metre, S·m⁻¹)
  4. Temperature dependence (metals, approx.): R(T) = R0 [1 + α (T − T0)] (α = temperature coefficient)
  5. Temperature dependence (semiconductors, qualitative): σ(T) ∝ exp(−Eg / (2 k T)) (Eg = band gap energy, k = Boltzmann constant, T in K)
📊 Visual ideas
V–I characteristic: Conductor (Ohmic) — a straight line through the origin. Label axes: Voltage (V) horizontal, Current (I) vertical. This shows I ∝ V with constant slope 1/R.
V–I characteristic: Semiconductor diode (non‑Ohmic) — low current for small forward V, sharp rise after turn‑on (~0.7 V for silicon), and very small reverse current (leakage) until breakdown. Label axes and indicate forward/reverse regions.
Conductivity (or resistivity) vs Temperature: Plot three curves on one graph. Metals: conductivity decreases (resistivity increases) roughly linearly with T. Insulators: very low conductivity across ordinary T. Semiconductors: conductivity increases rapidly with T (exponential trend). Axes: Temperature (°C or K) horizontal, Conductivity (σ) vertical (log scale helps show differences).
Energy band diagrams: Three small sketches side by side showing valence and conduction bands. Conductor: bands overlap or partially filled band. Semiconductor: small band gap Eg between valence and conduction bands. Insulator: large band gap. Label Eg for semiconductor and insulator.
🔥14

Materials used for resistors and heating elements

Overview

Resistors and heating elements convert electrical energy into thermal energy, but their material requirements differ because their roles differ. Resistors (used to control current or provide precise resistance) require materials with stable, predictable resistance and often a low temperature coefficient of resistance (TCR). Heating elements require materials with relatively high resistivity, high melting/softening temperature, good mechanical strength at high temperature and acceptable oxidation resistance.

Key material properties

  • Resistivity (ρ): Resistance R = ρL/A. Higher ρ gives larger resistance for a given geometry.
  • Temperature coefficient of resistance (α): Describes how R changes with temperature. Precision resistors need very small α (nearly constant R over temperature).
  • Melting point and mechanical strength: Heating elements must withstand high temperature without melting or breaking.
  • Oxidation/corrosion resistance: Prolongs life of heating elements at elevated temperatures.
  • Workability and cost: Ease of manufacturing (winding, film deposition) and economic factors matter.

Materials commonly used for resistors

  • Manganin (Cu–Mn–Ni alloy) and Constantan (Cu–Ni alloy): Very low TCR and stable; used for precision/standard resistors and ammeter/shunt resistors.
  • Metal-film and metal-oxide films: Deposited on ceramic cores to make precise, stable fixed resistors used in electronics.
  • Carbon composition and carbon film: Used in general-purpose resistors; carbon composition has larger noise and worse stability but can tolerate pulse energy.
  • Wire-wound resistors (often using nickel–chromium alloys for the wire): Used when high power dissipation is needed and precise resistance is required.

Materials commonly used for heating elements

  • Nichrome (Ni–Cr alloy): Widely used in toasters, electric heaters, hair dryers and ovens. Advantages: high resistivity, high melting point, good mechanical strength and acceptable oxidation resistance.
  • Kanthal (Fe–Cr–Al alloy): Used in industrial furnaces and some domestic heaters; excellent high-temperature strength and oxidation resistance.
  • Tungsten: Very high melting point; used for incandescent lamp filaments where the element must glow white-hot (also used in vacuum/hard environments).
  • Ceramic/metal-sheathed elements: Resistive wire (nichrome/Kanthal) embedded in ceramic or enclosed in metal tubes for immersion heaters, kettles, and industrial heaters.

How choice matches application

Precision electronic circuits use low-TCR alloys (manganin/constantan) or film resistors for stable resistance. Devices meant to heat (kettles, irons) use high-resistivity, high-melting alloys (nichrome, Kanthal) formed to maximize heat generation and durability. Lamp filaments use tungsten because it can operate at very high temperature and emit visible light.

📌 Examples
  • Toaster/space heater: nichrome coil — high resistivity and high temperature tolerance produce heat when current passes.
  • Electric kettle/immersion heater: Kanthal or nichrome wire embedded in ceramic or metal sheath — long-lived at high temperatures and resistant to oxidation.
  • Incandescent bulb filament: tungsten wire — extremely high melting point allows white-hot operation to emit light.
  • Precision laboratory resistor and standard resistors: manganin or constantan — very low temperature coefficient so resistance remains stable with temperature changes.
  • Power resistor (load banks): wire-wound resistors using Ni–Cr on ceramic cores — handle large power dissipation without large changes in resistance.
🧮 Formulas
  1. Ohm's law: V = I × R
  2. Resistance (geometry & resistivity): R = ρ × L / A (ρ = resistivity, L = length, A = cross-sectional area)
  3. Temperature dependence (approx., for small ranges): R_t = R_0[1 + α (t - t_0)] (α = temperature coefficient of resistance)
  4. Electrical power (dissipated as heat): P = V × I = I^2 × R = V^2 / R
📊 Visual ideas
R versus temperature for three material types: (a) manganin/constantan — nearly flat line (very small slope), (b) typical metal like copper or nichrome — roughly linear positive slope, (c) tungsten filament — steeper positive slope at high temperature (nonlinear at very high T).
R versus length for a uniform conductor (straight line): illustrates R ∝ L (fixed area and material).
Power dissipated (P) versus resistance (R) for fixed supply voltage: P = V^2 / R, showing P decreases as R increases (hyperbolic curve); useful to show how element resistance affects heating under a given voltage.
I–V characteristic: Ohmic resistor — straight line through origin; filament lamp (tungsten) — curve that becomes less steep at higher voltages (nonlinear) due to temperature rise increasing resistance.
🔬15

Practical skills and numerical problems

Overview: Practical skills in the Electricity chapter focus on measuring current and potential difference, drawing and interpreting V–I graphs, determining resistance from measurements, assembling series/parallel circuits, and solving numerical problems on resistance, current, power and energy. The numerical problems apply Ohm's law and combination rules to calculate currents, voltages, equivalent resistances and power consumption.

Key practical skills:

  • Correctly connecting an ammeter (in series) and a voltmeter (in parallel) to measure current through and potential difference across a component.
  • Varying applied voltage, recording corresponding current, and plotting a V–I graph to verify Ohm's law for an ohmic conductor.
  • Determining resistance from the slope of the V–I graph (plot V on vertical axis, I on horizontal: slope = R).
  • Assembling resistors in series and parallel to find equivalent resistance and measuring currents and voltage drops experimentally.
  • Calculating electric power and energy consumption for devices using P = VI, P = I^2R or P = V^2/R, and E = Pt.
  • Estimating uncertainties: repeat measurements, use suitable ranges on meters, and account for systematic errors (meter internal resistance, loose connections, contact resistance).

Typical experimental procedure (V–I graph / verifying Ohm's law):

  1. Set up circuit: variable DC source → rheostat (or variable resistor) → test wire/resistor → ammeter in series. Connect voltmeter across the test resistor.
  2. Start with lowest voltage. Record V (voltmeter) and I (ammeter) for several values as you increase voltage.
  3. Tabulate readings and plot V (y-axis) vs I (x-axis). For an ohmic conductor, points lie approximately on a straight line through the origin.
  4. Find slope of the best-fit straight line; slope = ΔV/ΔI = R (resistance). Use two distant, well-measured points to reduce error.
  5. Compare measured R with nominal/theoretical value; discuss deviations (heating, non-ohmic behavior, meter loading).

Precautions & common sources of error:

  • Ensure proper polarity and correct meter ranges; do not exceed meter limits.
  • Tighten connections to reduce contact resistance; avoid heating the resistor during quick repeated runs (it changes R).
  • Use sufficiently spaced data points for accurate slope; repeat readings for reliability and take average where appropriate.
  • Remember ammeter must be in series and have low resistance; voltmeter in parallel and have high resistance to minimise circuit disturbance.

Approach to numerical problems:

  • Identify what is given (V, I, individual resistances, time, power rating) and what is asked (I, R, P, energy).
  • Choose appropriate formula (Ohm's law, series/parallel rules, power formulas, energy = Pt).
  • Show intermediate steps with units, and check answers for physical plausibility (e.g., currents positive and not exceeding battery capability).
  • For combination networks, simplify stepwise (series/parallel) and use Kirchhoff ideas only if needed for more complex configurations.
📌 Examples
  • Example 1 — Verify Ohm's law (numerical): Given readings V = 1.0 V, 2.0 V, 3.0 V and corresponding I = 0.20 A, 0.40 A, 0.60 A. Show R. Solution: Plot V vs I or compute R = V/I. For each pair R = 1.0/0.20 = 5.0 Ω, 2.0/0.40 = 5.0 Ω, 3.0/0.60 = 5.0 Ω. Constant R indicates ohmic behavior; R = 5.0 Ω.
  • Example 2 — Find resistance from V–I graph: Two points on V–I graph are (I1 = 0.1 A, V1 = 0.5 V) and (I2 = 0.3 A, V2 = 1.5 V). Solution: slope = ΔV/ΔI = (1.5 − 0.5)/(0.3 − 0.1) = 1.0/0.2 = 5.0 Ω. So R = 5.0 Ω.
  • Example 3 — Series resistors: R1 = 4 Ω, R2 = 6 Ω connected to 12 V battery. Find current and voltage drop across each. Solution: R_eq = R1 + R2 = 10 Ω. Current I = V/R_eq = 12/10 = 1.2 A. Voltage drop across R1 = I*R1 = 1.2*4 = 4.8 V; across R2 = 1.2*6 = 7.2 V (they add to 12 V).
  • Example 4 — Parallel resistors: R1 = 6 Ω, R2 = 3 Ω across 12 V. Find currents and R_eq. Solution: I1 = V/R1 = 12/6 = 2.0 A; I2 = 12/3 = 4.0 A. Total I = 6.0 A. R_eq from 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 → R_eq = 2 Ω.
  • Example 5 — Power and energy: A 60 W bulb is connected to 230 V mains. (a) Find current through the bulb. (b) Energy used in 5 hours. Solution: (a) I = P/V = 60/230 ≈ 0.261 A. (b) Energy E = P * t = 60 W * 5 h = 300 Wh = 0.3 kWh (or in joules: 300 Wh × 3600 s/h = 1,080,000 J).
  • Practical-skill example — Connecting meters: To measure current through a resistor with a battery: (1) Break the circuit and insert ammeter in series with the resistor. (2) Connect voltmeter across the resistor (not across the whole circuit unless desired). (3) Start with low source voltage/range, record readings, then increase carefully. Ensure correct meter polarity and range selection.
🧮 Formulas
  1. Ohm's law: V = I R (V in volts, I in amperes, R in ohms)
  2. Series resistors: R_eq = R1 + R2 + ... + Rn
  3. Parallel resistors: 1/R_eq = 1/R1 + 1/R2 + ... + 1/Rn
  4. Electric power: P = V I = I^2 R = V^2 / R (P in watts)
  5. Electric energy: E = P t (E in joules if P in watts and t in seconds) or E (kWh) = P(kW) × t(h)
  6. From V–I graph (V on y-axis, I on x-axis): slope = ΔV/ΔI = R
📊 Visual ideas
V–I graph for an ohmic conductor: Axes: I (x-axis, A), V (y-axis, V). Expected shape: straight line through origin. Use sample points like (0.1 A, 0.5 V), (0.2 A, 1.0 V), (0.3 A, 1.5 V). Slope = R.
V–I graph for a non-ohmic device (e.g., filament bulb): Axes same as above. Expected shape: curve (nonlinear) — slope increases or decreases with I, showing resistance changes with temperature.
Resistance vs length of wire: Axes: Length of wire l (x-axis, cm or m), Resistance R (y-axis, Ω). Expected shape: straight line through origin (R ∝ l) if cross-section and material constant. Slope gives resistivity/area factor.
Series/parallel comparison graph (optional classroom demo): Bar chart of equivalent resistance vs configuration. Example bars: single R = 5 Ω, two in series = 10 Ω, two in parallel = 2.5 Ω — helps visualise how combinations change R.

Key Concepts

Electric current
Rate of flow of electric charge through a conductor; measured in amperes (A).
Electric charge
Fundamental property of matter that causes electric forces; measured in coulombs (C).
Potential difference (Voltage)
Work done per unit charge in moving a charge between two points; measured in volts (V).
Electromotive force (EMF)
Energy supplied by a source per unit charge when no current flows; ideal source voltage, measured in volts.
Resistance
Property of a material that opposes the flow of electric current; measured in ohms (Ω).
Resistivity
Intrinsic property of a material that determines its resistance for a given size and shape; unit ohm-meter (Ω·m).
Ohm's law
For an ohmic conductor at constant temperature, voltage across it (V) is proportional to current (I): V = IR.
Conductor
Material that allows electric charges to flow easily due to low resistance.
Insulator
Material that does not allow electric charges to flow freely because of very high resistance.
Semiconductor
Material with conductivity between conductors and insulators; conductivity can be changed by doping or temperature.
Series connection
Arrangement where components are connected end-to-end so the same current flows through each; voltages divide.
Parallel connection
Arrangement where components are connected across the same two points so each has the same voltage; currents divide.
Equivalent resistance
Single resistance that can replace a network of resistors to produce the same overall current and voltage behavior.
Internal resistance
Resistance inside a battery or cell that reduces terminal voltage when current flows; denoted r.
Ammeter
Instrument used to measure current; connected in series in a circuit and has very low resistance.
Voltmeter
Instrument used to measure potential difference between two points; connected in parallel and has high resistance.
Electric power
Rate at which electrical energy is converted to another form (heat, light); P = VI = I²R = V²/R, measured in watts (W).
Energy consumed
Total electrical energy used over time: E = P × t = V I t; often measured in kilowatt-hour (kWh).
Fuse
Safety device with a thin wire that melts when excessive current flows, breaking the circuit to prevent damage or fire.
Short circuit
Accidental low-resistance path connecting two points of different potential that allows a large current to flow.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. Define electric current and state its SI unit. What is the conventional direction of current? / विद्युत धारा को परिभाषित कीजिए तथा इसका SI मात्रक बताइए। धारा की परंपरागत दिशा क्या है?
    Show answer

    Electric current is the rate of flow of electric charge through a conductor, I = Q/t, and its SI unit is the ampere (A), where 1 A = 1 coulomb per second; conventional current is taken in the direction in which positive charge would flow, i.e. opposite to electron flow. / विद्युत धारा किसी चालक से आवेश के प्रवाह की दर है, I = Q/t, तथा इसका SI मात्रक ऐम्पियर (A) है, जहाँ 1 A = 1 कूलॉम प्रति सेकंड; परंपरागत धारा उस दिशा में ली जाती है जिसमें धनावेश प्रवाहित होगा, अर्थात इलेक्ट्रॉन प्रवाह के विपरीत।

  2. State Ohm's law and describe the V–I graph for an ohmic conductor. / ओम का नियम बताइए तथा एक ओमीय चालक के लिए V–I ग्राफ का वर्णन कीजिए।
    Show answer

    Ohm's law states that, at constant temperature, the current through a conductor is directly proportional to the potential difference across it, so V = IR; the V–I graph for an ohmic conductor is a straight line through the origin whose slope equals the resistance R. / ओम का नियम कहता है कि स्थिर ताप पर किसी चालक से धारा उसके सिरों के बीच विभवांतर के समानुपाती होती है, अतः V = IR; ओमीय चालक का V–I ग्राफ मूल बिंदु से होकर जाने वाली सीधी रेखा है जिसकी ढाल प्रतिरोध R के बराबर होती है।

  3. On what factors does the resistance of a conductor depend? Write the relation. / किसी चालक का प्रतिरोध किन कारकों पर निर्भर करता है? संबंध लिखिए।
    Show answer

    Resistance depends on the length L (directly proportional), cross-sectional area A (inversely proportional), the material (through resistivity ρ) and temperature; the relation is R = ρL/A. / प्रतिरोध लंबाई L (समानुपाती), अनुप्रस्थ काट क्षेत्रफल A (व्युत्क्रमानुपाती), पदार्थ (प्रतिरोधकता ρ द्वारा) तथा ताप पर निर्भर करता है; संबंध R = ρL/A है।

  4. Why are appliances in a household connected in parallel rather than in series? / घरेलू उपकरण श्रेणीक्रम के बजाय समांतर क्रम में क्यों जोड़े जाते हैं?
    Show answer

    In parallel each appliance receives the full supply voltage and can be switched on or off independently, and the failure of one appliance does not stop the others, whereas in series the same current flows through all and one failure breaks the whole circuit. / समांतर क्रम में प्रत्येक उपकरण को पूर्ण आपूर्ति वोल्टता मिलती है तथा उसे स्वतंत्र रूप से चालू/बंद किया जा सकता है, और एक उपकरण के खराब होने पर अन्य नहीं रुकते, जबकि श्रेणीक्रम में सभी से समान धारा बहती है तथा एक के खराब होने पर पूरा परिपथ टूट जाता है।

  5. Two resistors of 4 Ω and 6 Ω are connected in parallel across a 12 V battery. Find the equivalent resistance and the total current. / 4 Ω तथा 6 Ω के दो प्रतिरोध 12 V बैटरी के सिरों पर समांतर क्रम में जुड़े हैं। तुल्य प्रतिरोध तथा कुल धारा ज्ञात कीजिए।
    Show answer

    1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4 Ω; total current I = V/R_eq = 12/2.4 = 5 A. / 1/R_eq = 1/4 + 1/6 = 5/12, अतः R_eq = 12/5 = 2.4 Ω; कुल धारा I = V/R_eq = 12/2.4 = 5 A।

  6. State Joule's law of heating and write its mathematical form. / जूल के तापन नियम को बताइए तथा इसका गणितीय रूप लिखिए।
    Show answer

    Joule's law states that the heat produced in a conductor is directly proportional to the square of the current, the resistance, and the time for which the current flows: H = I²Rt. / जूल का नियम कहता है कि किसी चालक में उत्पन्न ऊष्मा धारा के वर्ग, प्रतिरोध तथा धारा प्रवाह के समय के समानुपाती होती है: H = I²Rt।

  7. An electric heater of 1 kW operates for 3 hours. Calculate the energy consumed in kWh and the cost at 5 rupees per kWh. / 1 kW का विद्युत हीटर 3 घंटे चलता है। kWh में खपत ऊर्जा तथा 5 रुपये प्रति kWh की दर से लागत ज्ञात कीजिए।
    Show answer

    Energy E = P × t = 1 kW × 3 h = 3 kWh; cost = 3 × 5 = 15 rupees. / ऊर्जा E = P × t = 1 kW × 3 h = 3 kWh; लागत = 3 × 5 = 15 रुपये।

  8. Why is the filament of an electric bulb made of tungsten, and why is a series alloy like nichrome used in heating elements? / विद्युत बल्ब का तंतु टंगस्टन का क्यों बनाया जाता है तथा तापन तत्वों में नाइक्रोम जैसी मिश्रधातु क्यों प्रयोग की जाती है?
    Show answer

    Tungsten has a very high melting point and high resistivity, so it can be heated to a high temperature to glow without melting; nichrome has high resistivity and does not oxidise easily at high temperatures, so it produces large heat (H ∝ R) and lasts long as a heating element. / टंगस्टन का गलनांक बहुत उच्च तथा प्रतिरोधकता अधिक होती है, अतः इसे बिना पिघले उच्च ताप तक गर्म करके दीप्त किया जा सकता है; नाइक्रोम की प्रतिरोधकता अधिक होती है तथा उच्च ताप पर सरलता से ऑक्सीकृत नहीं होती, अतः यह अधिक ऊष्मा (H ∝ R) उत्पन्न करता है तथा तापन तत्व के रूप में दीर्घ समय चलता है।

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