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Class 9 Mathematics Chapter 15 of 15

Chapter 15 — Probability

Overview

This chapter introduces the basic ideas of probability for Class 9 students. It explains random experiments, outcomes, sample space and events, and gives the classical (equally likely) definition of probability: P(E) = number of favourable outcomes / total number of outcomes. The chapter stresses understanding through simple examples and activities — tossing coins, rolling dice, and drawing balls from a bag — and contrasts experimental (empirical) results with theoretical calculation. Learning probability builds logical thinking, helps in decision making under uncertainty, and lays the foundation for more advanced topics in statistics and probability.

Learning Objectives

  • Define probability and related terms: trial, outcome, sample space and event.
  • Explain the difference between theoretical (classical) and experimental (empirical) probability.
  • State and apply the formula P(E) = number of favourable outcomes / total number of equally likely outcomes to compute probabilities.
  • Determine the sample space for single and combined random experiments (e.g., coin tosses, dice rolls, drawing a card).
  • Calculate probabilities of simple events in standard contexts: single coin tosses, single die rolls and single-card draws.
  • Compute experimental probability from observed frequencies and compare it with theoretical probability.
  • Apply the complement rule to find P(E') = 1 − P(E) and solve related problems.
  • Apply the addition rule for mutually exclusive events to find P(A ∪ B) when A and B cannot occur together.

Topics in this chapter

12 topics · tap a topic title to jump straight to it.

🎲1

Introduction to Probability

What is Probability? Probability measures how likely an event is to happen. It is a number between 0 and 1 (inclusive), where 0 means the event cannot happen and 1 means it is certain.

Basic terms

  • Experiment: Any process with observable outcomes (e.g., toss a coin, roll a die).
  • Sample space (S): The set of all possible outcomes of an experiment (e.g., for a die S = {1,2,3,4,5,6}).
  • Event (E): Any subset of the sample space (e.g., "getting an even number" = {2,4,6}).
  • Equally likely outcomes: Outcomes having the same chance (common assumption for fair coin, fair die, shuffled deck approximations).

Theoretical (classical) probability

If all outcomes are equally likely, the probability of an event E is given by:
P(E) = number of favourable outcomes (n(E)) / total number of outcomes (n(S)).

Experimental (empirical) probability

Based on observed frequency in repeated trials. If an event E occurs f times in N trials, experimental probability ≈ f / N. As N grows large, experimental probability tends to theoretical probability (law of large numbers idea).

Important properties

  • 0 ≤ P(E) ≤ 1 for any event E.
  • P(S) = 1 and P(∅) = 0 (S = certain event, ∅ = impossible event).
  • Complement rule: For event E, its complement E' (event E does not occur) satisfies P(E') = 1 − P(E).
  • If A and B are mutually exclusive (cannot happen together), P(A ∪ B) = P(A) + P(B).

How to find probability — simple steps

  1. Describe the experiment and list the sample space S.
  2. Identify the favourable outcomes for event E and count n(E).
  3. Count total outcomes n(S) (assuming equally likely outcomes).
  4. Compute P(E) = n(E)/n(S) and simplify if needed.

Short solved examples (classical)

  1. Coin toss: S = {H, T}. Probability of getting a head = 1/2.
  2. Die roll: S = {1,2,3,4,5,6}. Probability of getting an even number = n(E)=3 → P = 3/6 = 1/2.
  3. Bag of 5 balls (2 red, 3 blue): If one ball is drawn at random, P(red) = 2/5.

Relation between theoretical and experimental

Use experimental probability when theoretical calculation is hard or to check theory: repeat the experiment many times, record relative frequency, and compare.

Why this matters (real-life uses)

Probability is used in weather forecasting (chance of rain), games of chance, risk assessment (insurance, finance), quality control, and many decisions under uncertainty.

📌 Examples
  • Tossing a fair coin once. Sample space S = {H, T}. Probability of head P(H) = 1/2.
  • Rolling a fair six-sided die. Probability of getting 4 is 1/6. Probability of an odd number (1,3,5) is 3/6 = 1/2.
  • Drawing one ball from a bag containing 3 red and 2 green balls. P(red) = 3/5.
  • Randomly picking a card from a well-shuffled standard deck (52 cards). Probability of drawing a king = 4/52 = 1/13.
  • Experimental example: Toss a coin 100 times and get 56 heads. Experimental probability of head ≈ 56/100 = 0.56 (compare with theoretical 0.5).
  • Weather example: If historical data show it rained on 30 of the last 100 days in a month, an empirical chance of rain on a similar day ≈ 30/100 = 0.30.
🧮 Formulas
  1. P(E) = n(E) / n(S) (classical probability when outcomes are equally likely)
  2. 0 ≤ P(E) ≤ 1
  3. P(S) = 1, P(∅) = 0
  4. Complement rule: P(E') = 1 − P(E)
  5. If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
  6. Experimental probability: P(E) ≈ frequency of E / total trials (f / N)
📊 Visual ideas
Bar chart of outcomes: useful for discrete experiments (coin toss counts, die faces). X-axis: outcomes (1–6), Y-axis: frequency or relative frequency. Compare theoretical probabilities as a second series.
Histogram of relative frequencies from repeated trials: show convergence of experimental probability to theoretical value as number of trials increases (plot relative frequency vs. number of trials).
Pie chart: display proportion of different outcomes in an experiment (e.g., proportion of colors when drawing balls repeatedly).
Venn diagram: visualize events, complements and intersections (helpful to explain P(E'), mutually exclusive events).
🔢2

Random Experiment and Outcome

Random experiment is a process or activity which can be repeated under the same conditions and has one or more possible results, but the exact result cannot be predicted with certainty in advance. Examples: tossing a coin, rolling a die, drawing a card from a shuffled pack.

Outcome (or elementary event) is a single possible result of a random experiment. Each outcome is usually denoted by a symbol such as ω (omega). The sample space S is the set of all possible outcomes of the experiment. For a coin toss S = {Heads, Tails}; for a single die roll S = {1,2,3,4,5,6}.

Key properties: (1) Every outcome of the experiment is an element of S. (2) Outcomes are mutually exclusive: in one trial only one outcome occurs. (3) The sample space is exhaustive: it contains every outcome that can occur.

An event is any subset of the sample space (one or more outcomes). For example, in a die roll, the event “even number” is E = {2,4,6}. When all outcomes are equally likely, probability of an event can be computed by counting outcomes.

Notation summary: S = sample space, ω ∈ S denotes an outcome, E ⊆ S denotes an event, n(S) = number of elements (outcomes) in S, n(E) = number of favorable outcomes for event E.

📌 Examples
  • Tossing a fair coin once: possible outcomes S = {H, T}. Each trial yields one outcome (H or T).
  • Rolling a fair six-faced die: outcomes S = {1,2,3,4,5,6}. The outcome is the face value that appears.
  • Drawing one card from a well-shuffled standard deck: outcomes are the 52 different cards (e.g. Ace of Spades).
  • Selecting one student at random from a class: outcomes are the names (or IDs) of all students present.
  • Spin a 4-section spinner labelled {A, B, C, D}: outcomes S = {A, B, C, D}.
🧮 Formulas
  1. S = {ω1, ω2, ..., ωn} (sample space listing all outcomes)
  2. If outcomes are equally likely: P(E) = n(E) / n(S), where n(E) is number of favorable outcomes and n(S) total outcomes.
  3. Probability of each elementary outcome (if equally likely) = 1 / n(S).
  4. Sum of probabilities of all mutually exclusive elementary outcomes = 1, i.e. Σ P(ωi) = 1.
📊 Visual ideas
Tree diagram for two successive coin tosses showing branches HH, HT, TH, TT (labels on edges and leaves).
Bar chart (histogram) of observed frequencies of die faces after many rolls to illustrate empirical outcomes approaching theoretical ones.
Venn diagram representing sample space S as a rectangle and an event E as a subset (circle) inside it.
Circular spinner diagram partitioned into sectors labelled with outcomes (good to show unequal-likelihood sectors if needed).
🚀3

Sample Space (S)

Definition: A sample space (denoted by S or Ω) of a random experiment is the set of all possible outcomes of that experiment. Each element of S is called an outcome or a sample point.

Notation and examples: If you toss a coin once, S = {Heads, Tails}. If you roll a fair six-sided die once, S = {1, 2, 3, 4, 5, 6}.

Types of sample spaces:

  • Finite sample space: has a finite number of outcomes (e.g. a die: 6 outcomes).
  • Countably infinite sample space: outcomes can be listed in sequence (e.g. toss a coin until first Head: outcomes = {H, TH, TTH, TTTH, ...}).
  • Uncountably infinite (continuous) sample space: outcomes form a continuum (e.g. the exact time in seconds when a bus arrives on an interval [0,60]).

How to represent S: S can be listed as a set (curly braces), described by a rule (set-builder notation), or shown with a tree diagram for sequential experiments. For combined experiments, use the Cartesian product: if experiment A has outcomes S1 and experiment B has outcomes S2, then S = S1 × S2 (list of ordered pairs).

Why S matters: Probability of any event is defined relative to the sample space. For equally likely outcomes, P(event E) = number of favourable outcomes / total number of outcomes = n(E) / n(S).

📌 Examples
  • Toss a coin once: S = {H, T}.
  • Roll a die once: S = {1,2,3,4,5,6}.
  • Toss two coins: S = {HH, HT, TH, TT} (order matters if coins are distinguished).
  • Roll two dice: S = {(1,1),(1,2),...,(6,6)} — 36 outcomes (6×6).
  • Pick a card from a standard 52-card deck: S = {all 52 distinct cards}.
  • Measure the lifetime of a bulb (continuous): S = {t | t ≥ 0} (uncountably many outcomes).
🧮 Formulas
  1. P(E) = n(E) / n(S) (for equally likely outcomes)
  2. Number of outcomes for n independent binary trials (coin tosses) = 2^n
  3. Number of outcomes for n independent fair six-sided dice = 6^n
  4. If S1 and S2 are sample spaces for two independent experiments, combined sample space S = S1 × S2 and n(S) = n(S1) × n(S2)
  5. For finite S: n(S) = total number of distinct outcomes listed in S
📊 Visual ideas
Venn diagram: draw a rectangle for S and shade a subset to represent an event E. Use labels for S and E to show relation between sample space and events.
Tree diagram: for sequential experiments (e.g., tossing two coins or tossing a coin then rolling a die) draw branches for each outcome at every stage to list all outcomes clearly.
Outcome table (matrix): for two dice, draw a 6×6 table with rows = outcomes of die1 and columns = outcomes of die2; each cell represents one ordered pair outcome.
Bar chart (histogram) for discrete sample spaces: plot outcomes on x-axis and frequencies or probabilities on y-axis (e.g., probability distribution of sum of two dice).
🔢4

Events

What is an event? An event is any collection (set) of one or more outcomes of a random experiment. If S is the sample space (set of all possible outcomes), then an event E is a subset of S: E ⊆ S. A single outcome is called a simple (or elementary) event; a set of outcomes is called a compound event.

Common types of events

  • Certain event: E = S. It always occurs and P(E) = 1.
  • Impossible event: E = Ø. It never occurs and P(E) = 0.
  • Complementary event: For event E, the complement E' (or Ec) contains all outcomes in S that are not in E. E and E' are mutually exclusive and exhaustive, and P(E) + P(E') = 1.
  • Mutually exclusive (disjoint) events: Two events A and B are mutually exclusive if they cannot occur together, i.e., A ∩ B = Ø. For such events P(A ∪ B) = P(A) + P(B).
  • Exhaustive events: A collection of events is exhaustive if their union equals the sample space S (one of them must occur).

Probability of an event (for equally likely outcomes): If n(S) denotes the number of outcomes in the sample space and n(E) the number of favourable outcomes for event E, then

P(E) = n(E) / n(S)

This probability always satisfies 0 ≤ P(E) ≤ 1.

Basic probability rules:

  • P(E') = 1 − P(E).
  • For any two events A and B: P(A ∪ B) = P(A) + P(B) − P(A ∩ B). If A and B are mutually exclusive, P(A ∩ B) = 0, so P(A ∪ B) = P(A) + P(B).

Events are represented using set notation and often pictured with Venn diagrams to show intersections, unions and complements. Understanding events helps translate everyday uncertain situations (like tossing a coin, rolling a die, drawing a card) into calculable probabilities.

📌 Examples
  • Tossing a fair coin: S = {H, T}. Event E = 'get a head' = {H}. P(E) = 1/2.
  • Rolling a fair die: S = {1,2,3,4,5,6}. Event A = 'roll an even number' = {2,4,6}, so P(A) = 3/6 = 1/2.
  • Drawing a card from a well-shuffled 52-card deck: Event B = 'draw a spade' has n(B)=13, so P(B)=13/52 = 1/4.
  • Weather example (everyday event): If long-term data show rain on 30 out of 100 similar days, event R = 'it rains' has empirical probability P(R) ≈ 30/100 = 0.3.
  • Mutually exclusive example: When rolling a die, events 'roll a 2' and 'roll a 5' are mutually exclusive. P(2 or 5) = P(2) + P(5) = 1/6 + 1/6 = 1/3.
🧮 Formulas
  1. P(E) = n(E) / n(S) (for equally likely outcomes)
  2. 0 ≤ P(E) ≤ 1
  3. P(E') = 1 − P(E) (complement rule)
  4. P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
  5. If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
📊 Visual ideas
Venn diagram: Draw a rectangle for sample space S and circles for events A and B. Use shading to illustrate A ∩ B, A ∪ B and complement A'. This visually shows union, intersection and complement relationships.
Bar chart of probabilities: For a fair six-sided die show six bars for outcomes 1–6 (each height = 1/6). Use grouped shading to show probability of an event like 'even numbers' by summing relevant bars.
Pie chart: Represent the probability distribution of mutually exclusive outcomes (e.g., suits in a card deck: four equal slices) and highlight the slice(s) corresponding to an event.
Tree diagram (for sequential experiments): For two-step experiments (e.g., toss a coin then roll a die) draw branches for each outcome to list compound outcomes and compute event probabilities by summing branch probabilities.
🔢5

Equally Likely Outcomes

Definition: When all outcomes of an experiment have the same chance of occurring, they are called equally likely outcomes. The probability of an event is then computed by counting outcomes.

Sample space and outcomes: Let S be the sample space (set of all possible outcomes). If every outcome in S is equally likely, and E is an event (a subset of S), then the probability of E is

P(E) = n(E) / n(S)

where n(E) is the number of outcomes favorable to E and n(S) is the total number of outcomes.

When this applies (classical probability):

  • Experiments with symmetry: fair coin, fair die, well-shuffled deck of cards, spinner divided into equal sectors.
  • Discrete finite sample spaces where you can list or count outcomes and each outcome is equally likely.

Useful consequences and simple rules:

  • Complement rule: P(E') = 1 − P(E).
  • If A and B are mutually exclusive events, P(A ∪ B) = P(A) + P(B). (Compute each using counts.)
  • For independent experiments with equally likely outcomes (e.g., two fair coin tosses), the sample space size is the product of sizes of individual sample spaces.

Limitations: Not all experiments have equally likely outcomes. If outcomes have different probabilities (biased coin, nonuniform spinner, different-sized balls), you cannot use the simple count formula.

Connection to frequency interpretation: If you repeat an experiment many times, the relative frequency of an event (number of times E occurs divided by total trials) tends to approach the theoretical probability when outcomes are equally likely (law of large numbers).

📌 Examples
  • Toss a fair coin: S = {H, T}, n(S)=2. Probability of Head: P(H)=1/2.
  • Roll a fair six-sided die: S = {1,2,3,4,5,6}, n(S)=6. P(4)=1/6. P(even)= {2,4,6} ⇒ 3/6 = 1/2.
  • Draw one card from a well-shuffled standard deck (52 cards): Event E = 'draw a king'. n(E)=4, n(S)=52 ⇒ P(E)=4/52=1/13.
  • Spinner divided into 8 equal sectors: probability of landing on any given sector = 1/8.
  • Two fair coin tosses: S = {HH, HT, TH, TT}, n(S)=4. Event 'exactly one head' = {HT, TH} ⇒ P = 2/4 = 1/2.
  • Urn with 3 red and 3 blue identical balls (draw one at random): n(S)=6, P(red)=3/6 = 1/2 (equally likely because balls are identical in selection).
🧮 Formulas
  1. Classical probability for equally likely outcomes: P(E) = n(E) / n(S)
  2. Complement rule: P(E') = 1 − P(E)
  3. Mutually exclusive events: P(A ∪ B) = P(A) + P(B) (use counts if equally likely)
  4. Independent repeated experiments: n(S_total) = n(S1) × n(S2) × ... and P(of an outcome) = product of individual probabilities
  5. Relative frequency (empirical probability) ≈ number of occurrences of E / total trials (approaches theoretical probability as trials ↑)
📊 Visual ideas
Bar chart for a fair six-sided die: x-axis = outcomes 1–6, y-axis = probability; six equal bars at height 1/6. Useful to show equality of single-outcome probabilities.
Pie chart for a spinner with equal sectors: show 8 equal slices each labeled 1/8. Good for visualizing share of each outcome within the whole sample space.
Tree diagram for two fair coin tosses: first branch H/T, second branch H/T, leaves = {HH, HT, TH, TT} with equal probabilities 1/4. Use to illustrate compound equally likely outcomes.
Line graph of relative frequency vs number of trials: x-axis = number of trials, y-axis = relative frequency of a chosen event (e.g., 'head'); plot shows fluctuation early and convergence toward 1/2 with many trials (law of large numbers).
🎲6

Classical (Theoretical) Definition of Probability

Definition. If an experiment has a finite number of equally likely outcomes, the probability of an event E is defined as:

P(E) = number of favourable outcomes for E / total number of possible outcomes

Symbolically, if S is the sample space and n(A) denotes the number of elements in a set A, then

P(E) = n(E) / n(S)

Conditions for use:

  • The sample space S must be finite.
  • All outcomes in S must be equally likely.

How to apply (steps):

  1. Describe the sample space S and count n(S).
  2. Describe the event E and count n(E) (favourable outcomes).
  3. Compute P(E) = n(E)/n(S) and, if needed, simplify the fraction.

Basic properties (derived from the definition):

  • 0 ≤ P(E) ≤ 1 for any event E.
  • P(S) = 1 and P(∅) = 0.
  • If E' is the complement of E, then P(E') = 1 − P(E).
  • If A and B are mutually exclusive (disjoint), P(A ∪ B) = P(A) + P(B).
  • In general, P(A ∪ B) = P(A) + P(B) − P(A ∩ B).

When classical definition is not appropriate: If outcomes are not equally likely or the sample space is infinite, the classical formula n(E)/n(S) does not apply directly; a different (empirical or axiomatic) approach is used.

📌 Examples
  • Toss a fair coin once. S = {H, T}, n(S)=2. Event E = {getting a Head}. n(E)=1. P(E)=1/2.
  • Roll a fair six-faced die. S={1,2,3,4,5,6}, n(S)=6. Event E = {even number}={2,4,6}, n(E)=3. P(E)=3/6=1/2.
  • A bag contains 3 red and 2 blue identical-looking marbles. Pick one at random. S has 5 equally likely outcomes (each marble). Event E = {red}. n(E)=3. P(E)=3/5.
  • Pick one card from a well-shuffled standard 52-card deck. Event E = {a king}. n(E)=4. P(E)=4/52=1/13.
  • Choose a random day of the week. Event E = {weekend}. S has 7 days, n(E)=2. P(E)=2/7.
🧮 Formulas
  1. P(E) = n(E) / n(S)
  2. 0 ≤ P(E) ≤ 1
  3. P(S) = 1, P(∅) = 0
  4. P(E') = 1 − P(E) (complement rule)
  5. If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
  6. General addition rule: P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
📊 Visual ideas
Bar chart of probabilities for each face of a fair die (six bars of height 1/6) to visualise equal likelihood.
Pie chart showing probability slices for red and blue marbles (sizes proportional to counts, e.g. 3/5 and 2/5).
Venn diagram inside a rectangle (sample space) to show an event, its complement, intersection and union.
Tree diagram for two coin tosses to display the sample space {HH, HT, TH, TT} and probabilities of events like 'at least one head'.
🎲7

Basic Properties of Probability

Probability measures how likely an event is to occur. For any random experiment, we define a sample space S (set of all possible outcomes) and an event A (a subset of S). The probability P(A) is a number between 0 and 1 that quantifies the chance of A happening.

Key basic properties:

  • Range: 0 ≤ P(A) ≤ 1 for any event A. If P(A)=0 the event is impossible; if P(A)=1 the event is certain.
  • Probability of the sample space: P(S) = 1, because something in S must occur.
  • Probability of the empty set: P(∅) = 0.
  • Complement rule: For the complement A' (events in S but not in A), P(A) + P(A') = 1. So P(A') = 1 − P(A).
  • Addition rule (general): For any two events A and B, P(A ∪ B) = P(A) + P(B) − P(A ∩ B). This avoids double counting outcomes in both A and B.
  • Mutually exclusive (disjoint) events: If A and B cannot happen together (A ∩ B = ∅), then P(A ∪ B) = P(A) + P(B).
  • Monotonicity: If A ⊆ B then P(A) ≤ P(B).

These properties follow from the axioms of probability and are used to compute and reason about probabilities in simple experiments (coin tosses, dice rolls, card draws) and in real-life situations (reliability, weather forecasts, risk assessment).

📌 Examples
  • Coin toss: S = {H, T}. P(H) = 1/2, P(T) = 1/2. Range: 0 ≤ P(H) ≤ 1 and P(H) + P(H') = 1 (1/2 + 1/2 = 1).
  • Single die roll: S = {1,2,3,4,5,6}. Event A = {even} = {2,4,6}, so P(A) = 3/6 = 1/2. Complement A' = {odd}, P(A') = 1/2 and P(A)+P(A')=1.
  • Deck of cards: Event B = {draw an Ace} has P(B) = 4/52 = 1/13. Complement rule: P(not Ace) = 1 − 1/13 = 12/13.
  • Mutually exclusive example: Draw a card, A = {King}, C = {Ace}. Since A ∩ C = ∅, P(A or C) = P(A) + P(C) = 4/52 + 4/52 = 8/52 = 2/13.
  • General addition example: From a die, let D = {2,4,6} (even) and E = {4,5,6}. P(D)=1/2, P(E)=1/2. Intersection D∩E={4,6} so P(D∩E)=2/6=1/3. Then P(D∪E)=1/2+1/2−1/3=2/3.
  • Real-life empirical example: Flip a fair coin 100 times. If heads appear 48 times, empirical P(H) ≈ 48/100 = 0.48 (close to theoretical 0.5).
🧮 Formulas
  1. 0 ≤ P(A) ≤ 1
  2. P(S) = 1
  3. P(∅) = 0
  4. P(A') = 1 − P(A) (complement)
  5. P(A ∪ B) = P(A) + P(B) − P(A ∩ B) (general addition rule)
  6. If A and B are mutually exclusive (A ∩ B = ∅): P(A ∪ B) = P(A) + P(B)
📊 Visual ideas
Number line from 0 to 1 showing a point at P(A) and its complement at 1−P(A) — useful to visualise the complement rule.
Bar chart of probabilities for each outcome of a fair six-sided die (six bars equal height at 1/6) to show P(S)=1 when bars sum to 1.
Pie chart of sample space partitioned into event A and its complement A' to show proportions P(A) and P(A').
Venn diagram with two overlapping circles A and B: shade A ∪ B and show regions for A∩B and A−B to illustrate P(A∪B)=P(A)+P(B)−P(A∩B).
🔢8

Complementary Events

Definition: Two events A and A' (read “A complement” or “not A”) are complementary if exactly one of them occurs for every outcome in the sample space S. That is, A and A' are mutually exclusive and together exhaustive: A ∩ A' = Ø and A ∪ A' = S.

Notation: A', A^c, or Ā denotes the complement of A (the event “A does not occur”).

Key property (probability): Since A and A' are exhaustive and mutually exclusive, their probabilities add to 1:

  • P(A) + P(A') = 1
  • so P(A') = 1 − P(A)

Why this holds (intuitive): The probability of something happening (A) plus the probability of it not happening (A') must account for every possibility in S, so the sum is the total probability 1.

When to use: Often it is easier to find P(A') and then get P(A) as 1 − P(A'), especially when A' has fewer or simpler outcomes.

Simple example (die): Let A = “roll an even number” on a fair six-sided die. Outcomes for A: {2,4,6} so P(A) = 3/6 = 1/2. Then P(A') = 1 − 1/2 = 1/2 (A' = {1,3,5}).

📌 Examples
  • Coin toss: A = 'get Heads'. P(A) = 1/2, so P(A') = 1 − 1/2 = 1/2 (A' = 'get Tails').
  • Dice: A = 'roll a 6'. P(A) = 1/6, so P(A') = 1 − 1/6 = 5/6 (A' = 'roll 1,2,3,4 or 5').
  • Card: A = 'draw an Ace' from a standard 52-card deck. P(A) = 4/52 = 1/13, so P(A') = 12/13.
  • Weather: If P(rain tomorrow) = 0.3, then P(no rain tomorrow) = 1 − 0.3 = 0.7.
  • Exam: If probability that a student passes = 0.85, probability that they fail = 0.15 (complement).
🧮 Formulas
  1. P(A) + P(A') = 1
  2. P(A') = 1 − P(A)
  3. P(A ∩ A') = 0 (mutually exclusive)
  4. P(A ∪ A') = 1 (exhaustive)
  5. Notation: A' or A^c denotes complement of A
📊 Visual ideas
Venn diagram: Draw rectangle for sample space S and a circle inside for event A. Shade the area inside the rectangle but outside the circle to represent A'. Label probabilities P(A) and P(A') so that their areas sum to the whole rectangle (1).
Pie chart: Divide a circle into two sectors sized by P(A) and P(A') to show they together make a full circle (100%).
Bar chart: Two bars side-by-side for P(A) and P(A') whose heights add up to 1 — useful when comparing numeric probabilities.
Number line from 0 to 1: Mark P(A) as a segment from 0 to P(A) and the next segment to 1 as P(A') = 1 − P(A).
🎲9

Experimental (Empirical) Probability

What is Experimental (Empirical) Probability?

Experimental probability (also called empirical or relative-frequency probability) is the probability of an event estimated from the results of an experiment or observation. It is found by performing the experiment a number of times, counting how often the event occurs, and dividing by the total number of trials.

Definition and formula

If an event E occurs n(E) times in N repeated trials, the experimental probability of E is

Pexp(E) = n(E) / N

Key ideas

  • Experimental probability is based on actual data (observed frequency), not on theoretical reasoning about equally likely outcomes.
  • Relative frequency = number of favourable outcomes observed ÷ total trials.
  • As the number of trials increases, the experimental probability tends to approach the theoretical probability (Law of Large Numbers).
  • Limitations: results depend on the number of trials and how the experiment is conducted (sampling bias, measurement errors).

How to do an experiment

  1. Define the event E clearly (e.g., getting a head when tossing a coin).
  2. Decide number of trials N and perform the experiment N times.
  3. Count n(E) = number of times E occurred.
  4. Compute Pexp(E) = n(E)/N. Optionally convert to decimal or percent.
  5. Compare with theoretical probability (if known) and comment on differences due to randomness and sample size.

Law of Large Numbers (informal)

When an experiment is repeated many times, the experimental probability of an event tends to get closer to its theoretical probability. Small samples can show large fluctuations; larger samples give more stable estimates.

📌 Examples
  • Toss a coin 100 times. If heads appears 56 times, experimental probability of head = 56/100 = 0.56 (56%). Compare with theoretical probability 1/2 = 0.5.
  • Roll a fair die 120 times. If the face '4' appears 18 times, experimental probability of getting 4 = 18/120 = 0.15. Theoretical probability = 1/6 ≈ 0.1667.
  • Survey 200 students asking whether they prefer Football. If 82 say 'Yes', experimental probability a randomly chosen student prefers Football = 82/200 = 0.41.
  • Inspect 500 bulbs from a factory; 12 are defective. Experimental probability a randomly chosen bulb is defective = 12/500 = 0.024 (2.4%). Useful for quality control.
🧮 Formulas
  1. Experimental probability: P_exp(E) = n(E) / N (n(E) = number of times event E occurred; N = total trials)
  2. Relative frequency (percentage): % = (n(E) / N) × 100
  3. Complement (experimental): P_exp(E') = 1 − P_exp(E) (when E' is the complement of E)
  4. For mutually exclusive events A and B (from experiment): P_exp(A ∪ B) = P_exp(A) + P_exp(B) (if A and B cannot occur together in one trial)
📊 Visual ideas
Bar chart of frequencies: x-axis = outcomes (e.g., 1,2,3,4,5,6 for a die), y-axis = observed counts. Shows which outcomes occurred most/least.
Relative-frequency bar chart: same x-axis (outcomes), y-axis = n(outcome)/N. Useful to compare with theoretical probabilities drawn as lines.
Line graph of running (cumulative) relative frequency: x-axis = number of trials, y-axis = running P_exp(E). Plot how the estimate stabilizes as trials increase to illustrate the Law of Large Numbers.
Histogram (grouped data): for continuous or grouped discrete measurements (e.g., number of defective items per batch), showing frequency distribution.
🔢10

Counting Outcomes and Listing Techniques

What is being counted? In probability we count the possible outcomes of a random experiment. The set of all possible outcomes is called the sample space (denoted S). An event is a subset of S. If all outcomes in S are equally likely, probability of an event E is P(E) = n(E) / n(S), where n(X) denotes the number of elements of set X.

Why list outcomes? Listing outcomes helps ensure you have found the complete sample space and that no outcome is counted twice. For small experiments it gives a direct way to compute probabilities by counting.

Common listing techniques

  • Complete listing (enumeration): Write every outcome explicitly (useful when S is small).
  • Tree diagram: Draw branches for sequential choices. Each path from root to leaf represents one outcome. Count leaves to get n(S).
  • Tabular (matrix) method: Use a table/grid for two-step experiments (e.g. two dice → 6×6 grid = 36 outcomes).
  • Systematic listing: Use a fixed order (alphabetical or numeric) to avoid duplicates and omissions.
  • Fundamental principle of counting (multiplication rule): If an experiment has stages with a choices in stage 1, b choices in stage 2, ..., then total outcomes = a × b × ... (when choices are independent and order matters). This replaces explicit listing when numbers are larger.

Important notes:

  • Decide whether order matters (e.g., arrangement AB is different from BA) and whether repetition is allowed. These affect counting.
  • Always check that listed outcomes are equally likely before using simple ratio formula for probability.
📌 Examples
  • Tossing two coins: List outcomes = {HH, HT, TH, TT}. n(S)=4. Probability of exactly one head = {HT, TH} so n(E)=2 → P=2/4=1/2.
  • Rolling two dice: Use a 6×6 table or tree. n(S)=36. Probability that sum is 7: outcomes = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} → 6/36 = 1/6.
  • Forming 2-letter arrangements from A,B,C without repetition: Use tree or systematic listing: AB, AC, BA, BC, CA, CB → n(S)=6. If repetition allowed (letters can repeat) n(S)=3×3=9 (AA, AB, AC, BA, …).
  • Choosing an outfit: 3 shirts, 2 trousers, 2 pairs of shoes. By multiplication rule total outfits = 3 × 2 × 2 = 12. (E.g., list by shirts first, then trousers, then shoes.)
  • Picking one card from a standard deck (if treated as equally likely): n(S)=52. Probability of a spade = 13/52 = 1/4.
🧮 Formulas
  1. Sample space size: n(S) = number of possible outcomes.
  2. Probability (equally likely outcomes): P(E) = n(E) / n(S).
  3. Multiplication (fundamental) principle: If experiment has stages with a, b, c, ... choices then total outcomes = a × b × c × ...
  4. If order matters without repetition for k positions from n objects: n × (n-1) × (n-2) × ... (k factors).
  5. Addition for counts (mutually exclusive): n(A ∪ B) = n(A) + n(B). More generally: n(A ∪ B) = n(A) + n(B) − n(A ∩ B).
📊 Visual ideas
Tree diagram: Draw levels for each sequential choice; label branches and count leaf nodes to get n(S). Useful for coin tosses, letter arrangements.
6×6 grid (matrix) for two dice: Rows = outcomes of die1 (1–6), Columns = die2 (1–6). Each cell is an ordered pair (i,j); color or highlight cells that satisfy an event (e.g., sum=7).
Table for simple product experiments: Rows list choices of stage 1, columns stage 2; fill cells with combined outcomes to ensure completeness.
Venn diagram: Use for visualizing unions and intersections of events (helps count n(A ∪ B) and n(A ∩ B)).
🔢11

Standard Examples and Problem Types

What is Probability? Probability measures how likely an event is to occur. For a well-defined experiment with a sample space S (all possible equally likely outcomes) and an event E (a subset of S), the classical probability is P(E) = n(E) / n(S), where n(.) denotes number of outcomes.

Key ideas:

  • Sample space (S): all possible outcomes of an experiment (e.g., for a fair die S = {1,2,3,4,5,6}).
  • Equally likely outcomes: classical formula assumes outcomes have equal chance.
  • Experimental (empirical) probability: found by repeating the experiment many times: P(E) ≈ (frequency of E)/(total trials).
  • Complementary event: E' (not E). P(E') = 1 − P(E).
  • Mutually exclusive events: A and B cannot happen together. Then P(A ∪ B) = P(A) + P(B).

Standard problem types you will meet in Class 9:

  1. Single simple event with equally likely outcomes (coin, die, spinner).
  2. Drawing objects from a bag — count favorable and total outcomes.
  3. Events using complements (e.g., “at least one” problems solved by 1 − P(none)).
  4. Combined events when outcomes are listed as ordered pairs (two tosses, two dice) — build sample space as Cartesian product.
  5. Experimental probability tasks — perform trials, record frequencies, compare with theoretical values.
  6. Mutually exclusive events and simple additions of probabilities.

Problem-solving steps (concise):

  1. Define the experiment and identify S.
  2. List/count n(S) and n(E) (favourable outcomes).
  3. Check if outcomes are equally likely; if yes, use P(E)=n(E)/n(S).
  4. Use complements or combinations if direct counting is hard.
  5. Give final answer as a fraction, decimal or percentage, simplified.
📌 Examples
  • Coin toss: What is probability of getting a head in one toss? S = {H, T}, n(S)=2, favourable n(E)=1 → P(H)=1/2.
  • One die: Probability of getting an even number? S={1,2,3,4,5,6}, favourable={2,4,6} so P=3/6=1/2.
  • Bag of balls: A bag has 3 red and 2 blue identical balls. One ball is drawn at random. P(red)=3/(3+2)=3/5.
  • Two tosses: Probability of getting at least one head in two tosses. S={(H,H),(H,T),(T,H),(T,T)}, P(at least one H)=1−P(no H)=1−P(T,T)=1−1/4=3/4.
  • Two dice: Probability that sum is 7 when two fair dice are rolled. Sample space has 36 ordered pairs. Favourable pairs for sum 7 = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} =6 → P=6/36=1/6.
  • Card from deck: Probability of drawing an Ace from a standard 52-card deck. n(E)=4, n(S)=52 → P=4/52=1/13.
🧮 Formulas
  1. Classical probability: P(E) = n(E) / n(S), when outcomes are equally likely.
  2. Complement rule: P(E') = 1 − P(E).
  3. Addition rule for mutually exclusive events: P(A ∪ B) = P(A) + P(B) if A and B are mutually exclusive.
  4. For 'at least one' in repeated independent trials: P(at least one) = 1 − P(none).
  5. Experimental probability: P(E) ≈ (frequency of E) / (total number of trials).
  6. (Optional/advanced) Independent events multiplication: P(A ∩ B) = P(A) × P(B) if A and B are independent.
📊 Visual ideas
Bar chart of outcome frequencies after many trials (e.g., counts of faces 1–6 after 600 die rolls) to compare experimental vs theoretical probabilities.
Pie chart showing proportion of outcomes (useful for small sample spaces like coin or single die) to visualize probability share.
Tree diagram for sequential experiments (e.g., two tosses or draw-with-replacement) to enumerate sample space and compute probabilities.
Venn diagram for events A and B to illustrate union, intersection and complements (useful for addition rule and complements).
🔢12

Problem-Solving Strategies

What the topic covers: Problem-solving strategies in probability teach systematic ways to model random experiments, count outcomes, and compute probabilities accurately using basic rules (equally likely outcomes, complement, addition for disjoint events, multiplication for sequential events).

Step-by-step strategy (use this checklist for each problem)

  • 1. Read and identify the experiment. What is being done (tossing, drawing, rolling)? How many trials?
  • 2. Define the sample space S. List all possible outcomes explicitly if small, or describe them (e.g., all ordered pairs for two dice).
  • 3. Check the equally-likely assumption. If outcomes are equally likely, P(E)=n(E)/n(S). If not, consider weighting or empirical frequency.
  • 4. Count favourable outcomes n(E). Use listing, symmetry, multiplication principle, combinations, or complementary counting to simplify.
  • 5. Use rules to compute probability. Apply P(E)=n(E)/n(S), or use complement, addition or multiplication rules as appropriate.
  • 6. Draw a diagram if needed. Tree diagrams for sequential experiments, Venn diagrams for unions/intersections, tables for two-dimensional sample spaces, area models for geometric probability.
  • 7. Check the answer. Probabilities must be between 0 and 1; reasonableness check using symmetry or complementary probabilities often helps.

Common short-cuts and tips

  • Use complement: When "at least one" or "not" problems are present, it is often easier to compute P(E') and subtract from 1.
  • Exploit symmetry: Symmetric outcomes (e.g., fair coin or fair die) let you count one type then multiply by symmetry factor.
  • Use tree diagrams: For sequential events (with or without replacement), trees show all ordered outcomes and probabilities clearly.
  • Area/proportional models: For continuous or geometric problems, represent outcomes by areas; probability = shaded area / total area.

When to use which diagram

  • Tree diagram — sequential experiments (ordered outcomes, dependent or independent draws).
  • Venn diagram — events involving union/intersection/complement relationships.
  • Matrix/table (grid) — two independent discrete variables (e.g., two dice).
  • Area model — geometric probability (points chosen at random inside a region).

Following these organized steps prevents common mistakes (forgetting order, double-counting, or assuming equal likelihood incorrectly) and makes even non-trivial problems manageable.

📌 Examples
  • 1) Coin tossed twice. Find probability of at least one head. Solution: Sample space S = {HH, HT, TH, TT} (n(S)=4). Use complement: P(at least one head)=1-P(no head)=1-P(TT)=1-1/4=3/4.
  • 2) One fair die rolled. Find probability of an even number. S={1,2,3,4,5,6}, favourable={2,4,6} so P=3/6=1/2.
  • 3) Bag with 3 red, 5 blue, 2 green marbles. One marble drawn at random. Probability of blue = number of blue / total = 5/10 = 1/2.
  • 4) Two draws without replacement from a bag with 3 red and 2 blue. Probability both are red. Count combinations: C(3,2)/C(5,2)=3/10. (Or sequential: (3/5)*(2/4)=6/20=3/10.)
  • 5) Two fair dice thrown. Probability sum equals 7. Use 6x6 grid: favourable ordered pairs {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} so P=6/36=1/6.
🧮 Formulas
  1. P(E) = n(E) / n(S) (for equally likely outcomes)
  2. P(E') = 1 - P(E) (complement rule)
  3. If A and B disjoint: P(A ∪ B) = P(A) + P(B)
  4. For independent sequential events A and B: P(A and B) = P(A) × P(B)
  5. Counting principle for ordered choices: if first can occur in m ways and second in n ways, total = m × n
📊 Visual ideas
Tree diagram: two coin tosses (branches HH, HT, TH, TT) labeled with probabilities 1/4 each; useful to show complement or sequential probabilities.
Venn diagram: two overlapping circles for events A and B to visualize P(A), P(B), P(A∩B) and P(A∪B).
6×6 table (grid) for two dice: rows = die1, columns = die2; mark sums or favourable cells to count outcomes (useful for sums).
Bar chart (probability histogram): empirical probabilities from repeated trials (e.g., relative frequencies after 100 tosses) to compare with theoretical values.

Key Concepts

Random experiment
An action or process that leads to one of several possible outcomes, where the outcome cannot be predicted with certainty beforehand.
Trial
A single performance or repetition of a random experiment.
Outcome (Sample point)
A single possible result of a random experiment.
Sample space
The set of all possible outcomes of a random experiment, usually denoted by S.
Elementary (Simple) event
An event that consists of exactly one outcome (one sample point).
Compound event
An event that consists of two or more outcomes (a subset of the sample space with multiple points).
Event
Any collection (subset) of one or more outcomes from the sample space; it may be elementary or compound.
Favorable outcomes
Outcomes in the sample space that satisfy the condition described by an event.
Equally likely outcomes
Outcomes that have the same chance of occurring in a random experiment.
Certain event
An event that is sure to occur; it contains all outcomes of the sample space (probability 1).
Impossible event
An event that cannot occur; it contains no outcomes (probability 0).
Complement of an event
The set of all outcomes in the sample space that are not in the event; denoted A' or A^c.
Mutually exclusive events
Two events that cannot occur at the same time; their intersection is empty.
Exhaustive events
A collection of events whose union equals the entire sample space (they cover all possible outcomes).
Classical (Theoretical) probability
Probability defined as number of favorable equally likely outcomes divided by total number of equally likely outcomes.
Empirical (Experimental) probability
Probability estimated from actual experiments; equals frequency of the event divided by total trials.
Relative frequency
The ratio of the number of times an event occurs to the total number of trials; used to estimate empirical probability.
Probability of an event (basic formula)
For equally likely outcomes, P(event) = (number of favorable outcomes) / (total number of outcomes in S).
Union of events (A or B)
Event that either A occurs, or B occurs, or both; contains outcomes in A ∪ B.
Intersection of events (A and B)
Event that both A and B occur simultaneously; contains outcomes in A ∩ B.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. The classical definition of probability of an event E is: / किसी घटना E की शास्त्रीय प्रायिकता की परिभाषा है: (a) Number of trials / Number of events / परीक्षणों की संख्या / घटनाओं की संख्या (b) Number of favourable outcomes / Total number of equally likely outcomes / अनुकूल परिणामों की संख्या / कुल समसंभाव्य परिणामों की संख्या (c) Total outcomes / Favourable outcomes / कुल परिणाम / अनुकूल परिणाम (d) 1 / Number of outcomes / 1 / परिणामों की संख्या
    Show answer

    (b) Number of favourable outcomes / Total number of equally likely outcomes / अनुकूल परिणामों की संख्या / कुल समसंभाव्य परिणामों की संख्या — P(E) = n(E)/n(S), where n(E) is the count of favourable outcomes and n(S) is the total count of outcomes in the sample space. / P(E) = n(E)/n(S), जहाँ n(E) अनुकूल परिणामों की संख्या और n(S) प्रतिदर्श समष्टि में कुल परिणामों की संख्या है।

  2. A fair die is rolled once. What is the probability of getting an even number? / एक निष्पक्ष पासा एक बार फेंका जाता है। सम संख्या आने की प्रायिकता क्या है? (a) 1/6 (b) 1/3 (c) 1/2 (d) 2/3
    Show answer

    (c) 1/2 — Sample space S = {1,2,3,4,5,6}, n(S) = 6. Even numbers = {2,4,6}, n(E) = 3. P(E) = 3/6 = 1/2. / प्रतिदर्श समष्टि S = {1,2,3,4,5,6}, n(S) = 6। सम संख्याएँ = {2,4,6}, n(E) = 3। P(E) = 3/6 = 1/2।

  3. A bag has 3 red and 5 blue identical balls. One ball is drawn at random. What is the probability of drawing a red ball? / एक थैले में 3 लाल और 5 नीली एकसमान गेंदें हैं। एक गेंद यादृच्छिक रूप से निकाली जाती है। लाल गेंद निकलने की प्रायिकता क्या है? (a) 3/5 (b) 5/8 (c) 3/8 (d) 1/3
    Show answer

    (c) 3/8 — Total balls = 3+5 = 8; favourable (red) = 3; P(red) = 3/8. / कुल गेंदें = 8; अनुकूल (लाल) = 3; P(लाल) = 3/8।

  4. Fill in the blank: For any event E, P(E) + P(E') = _____, where E' is the complement of E. / रिक्त स्थान भरें: किसी भी घटना E के लिए, P(E) + P(E') = _____, जहाँ E', E का पूरक है।
    Show answer

    1 — The event and its complement are mutually exclusive and exhaustive, so their probabilities sum to 1. P(E') = 1 − P(E). / घटना और उसका पूरक परस्पर अपवर्जी और सम्पूर्ण हैं, इसलिए उनकी प्रायिकताओं का योग 1 होता है। P(E') = 1 − P(E)।

  5. Fill in the blank: The set of all possible outcomes of a random experiment is called the _____. / रिक्त स्थान भरें: किसी यादृच्छिक प्रयोग के सभी संभावित परिणामों के समुच्चय को _____ कहते हैं।
    Show answer

    sample space (प्रतिदर्श समष्टि) — The sample space S lists every outcome that can occur in the experiment; events are subsets of S. / प्रतिदर्श समष्टि S में वे सभी परिणाम सूचीबद्ध होते हैं जो प्रयोग में घटित हो सकते हैं; घटनाएँ S के उपसमुच्चय होती हैं।

  6. True or False: The probability of an impossible event is 1. / सत्य या असत्य: असंभव घटना की प्रायिकता 1 होती है।
    Show answer

    False / असत्य — The probability of an impossible event is 0 (it can never occur). The probability of a certain event is 1. / असंभव घटना की प्रायिकता 0 होती है (यह कभी नहीं घटती)। निश्चित घटना की प्रायिकता 1 होती है।

  7. A coin is tossed twice. List the sample space and find the probability of getting exactly one head. / एक सिक्के को दो बार उछाला जाता है। प्रतिदर्श समष्टि की सूची बनाइए और ठीक एक चित आने की प्रायिकता ज्ञात कीजिए।
    Show answer

    Sample space S = {HH, HT, TH, TT}, n(S) = 4. / प्रतिदर्श समष्टि S = {HH, HT, TH, TT}, n(S) = 4। Favourable outcomes (exactly one head) = {HT, TH}, n(E) = 2. / अनुकूल परिणाम (ठीक एक चित) = {HT, TH}, n(E) = 2। P(E) = 2/4 = 1/2. / P(E) = 1/2।

  8. A card is drawn at random from a well-shuffled deck of 52 cards. What is the probability of drawing a king? / 52 पत्तों की एक अच्छी तरह फेंटी गई ताश की गड्डी से एक पत्ता यादृच्छिक रूप से निकाला जाता है। बादशाह (किंग) निकलने की प्रायिकता क्या है?
    Show answer

    There are 4 kings in a deck of 52 cards. / 52 पत्तों की गड्डी में 4 बादशाह होते हैं। P(king) = n(E)/n(S) = 4/52 = 1/13. / P(बादशाह) = 4/52 = 1/13।

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