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Class 6 Mathematics Chapter 10 of 14

Chapter 10 — Mensuration

Open the lesson Play with this chapter — pictures, sound and practice.

Overview

This unit on Mensuration introduces Class 6 students to measuring lengths, perimeters, areas of plane figures and volumes of simple solids. It teaches standard units (mm, cm, m), unit conversion, and the correct use of formulas for rectangles, squares, triangles, circles and composite shapes. The unit also covers surface area and volume of cubes and cuboids, and shows how mensuration is applied in everyday tasks like fencing, tiling, packing and painting. Emphasis is on drawing neat diagrams, labelling dimensions, choosing the right formula, performing careful arithmetic and checking answers for reasonableness. Students practise estimation and learn to split complex shapes into simpler parts. By the end, learners will solve routine classroom problems and apply mensuration in daily life scenarios, gaining confidence with units, formulas and step-by-step methods.

Learning Objectives

  • Identify and name common plane figures and simple solids used in mensuration problems.
  • Measure lengths using standard units and convert between millimetre, centimetre and metre.
  • Calculate perimeters of squares, rectangles and triangles using correct formulas.
  • Apply area formulas to find areas of rectangles, squares, triangles and circles.
  • Divide composite shapes into simple parts and compute their total or remaining area.
  • Compute total surface area and lateral surface area of cubes and cuboids when needed.
  • Calculate volumes of cubes and cuboids and express answers in cubic units.
  • Estimate results and check the reasonableness of calculations in mensuration problems.

Topics in this chapter

11 topics · tap a topic title to jump straight to it.

⚖️1

Introduction to Mensuration

What mensuration studies and why it matters

Mensuration is the part of mathematics that deals with measuring sizes: how long something is, how much surface it covers and how much space it holds. These measures are called length, area and volume. You meet mensuration in daily life when you measure the length of a ribbon, the area of a floor to buy tiles, or the capacity of a water tank. Learning mensuration helps you solve such problems using simple steps and formulas.

Core ideas you will learn

You will learn standard units of measurement and how to convert between them. You will learn formulas to find perimeter (the distance around a shape), area (how much surface a shape covers) and volume (how much space a solid occupies). You will practise drawing neat diagrams, labelling lengths and heights, and splitting complex shapes into smaller ones that you can measure easily.

How to approach mensuration problems

Read the question carefully and underline the given measurements. Draw the figure if not shown, label all known lengths and mark the units. Decide whether the question asks for perimeter, area, surface area or volume. Convert all measures to the same unit before using a formula. Do the arithmetic step by step, write the unit with the final answer, and check whether the result looks reasonable by estimating an approximate value.

Practical value

Mensuration links mathematics to real life: carpentry uses lengths and areas, farmers use area for fields, builders use surface area and volume for materials, and households use volume to know how much water a container can hold. Regular practice will make using these formulas quick and reliable.

📌 Examples
  • Measuring a ribbon of 150 cm and converting it to metres gives 1.5 m; this helps decide whether it fits a gift box.
  • Sketch a rectangular garden to label length and breadth before calculating area for sowing seeds.
📊 Visual ideas
Draw a simple rectangle and label its length and breadth to show how area will be found.
Sketch a cuboid and label length, breadth and height for later volume calculation.
🔢2

Measuring Length and Units

Standard units of length and their relations

In mensuration we measure distances using standard units. The most common units are millimetre (mm), centimetre (cm) and metre (m). These are related: 10 millimetres make 1 centimetre, and 100 centimetres make 1 metre. Thus, 1 m = 100 cm and 1 cm = 10 mm. Knowing these relations helps you convert measurements to the same unit before doing area or volume calculations.

Why conversion is important

If one side of a rectangle is given in metres and another in centimetres, you cannot multiply them directly. Convert both to the same unit first. For example, if length = 2 m and breadth = 50 cm, change 2 m to 200 cm or 50 cm to 0.5 m before multiplying. This prevents unit mistakes and gives the correct square or cubic units in the answer.

Measuring with instruments

Use a ruler, tape or metre rod to measure lengths. Place the zero mark at one end and read the value at the other end. For longer objects use a tape measure that shows metres and centimetres. When reading instruments, estimate to the nearest small division and write the unit; if the measurement falls between marks, write it as a decimal or fraction according to class instructions.

Practice converting and recording

Work with many examples: convert 350 cm to metres, or 1.25 m to centimetres. Practice changing centimetres to millimetres and vice versa. Always write the converted number with its unit so you do not lose track. When dealing with area or volume, remember the units square (cm2, m2) and cubic (cm3, m3) and apply conversions carefully—e.g., 1 m2 = 10000 cm2 because each side length multiplies by 100.

📌 Examples
  • Convert 2.75 m to cm: 2.75 × 100 = 275 cm.
  • Change 340 mm to cm: 340 ÷ 10 = 34 cm.
🧮 Formulas
  1. 1 m = 100 cm
  2. 1 cm = 10 mm
  3. 1 m2 = 100 cm × 100 cm = 10000 cm2
📊 Visual ideas
Draw a 30 cm ruler and mark 0, 10, 20 and 30 cm divisions.
Sketch two line segments, one 120 cm and another 1.2 m, and label both with the same unit.
⏹️3

Perimeter of Plane Figures

Definition and idea of perimeter

Perimeter is the total distance around a closed plane figure. Imagine walking around a garden; the length you walk along the boundary is the perimeter. To find the perimeter, you add the lengths of all sides. This simple idea applies to polygons like triangles, quadrilaterals, and regular shapes such as squares and rectangles.

Formulas for common shapes

For a square with side s, each side is equal so perimeter = 4 × s. For a rectangle with length l and breadth b, the opposite sides are equal so perimeter = l + b + l + b = 2(l + b). For a triangle with three sides a, b and c, perimeter = a + b + c. For regular polygons (all sides equal) the perimeter is the number of sides times the side length. Always ensure units of all sides are the same before adding.

Problem solving steps

1. Draw the shape if not given and label sides. 2. Convert all side measurements to one unit. 3. Use the formula or add the side lengths. 4. Write the result with the correct unit. For fences or borders, the required length is the perimeter. If the object needs multiple rounds of border (for example, two parallel lines of wire), multiply the perimeter by the number of rounds required.

Practical tips and examples

Perimeter problems often appear with real-life contexts: fencing a garden, framing a picture, or placing a border around a field. Check whether the problem asks for inside perimeter or outside; sometimes edges may not be included. For irregular shapes, break them into straight segments, label each length and add them up carefully. Estimating a rough value first helps detect arithmetic mistakes.

📌 Examples
  • Perimeter of rectangle 9 m by 4 m: 2(9 + 4) = 26 m.
  • Perimeter of equilateral triangle with side 7 cm: 3 × 7 = 21 cm.
🧮 Formulas
  1. Perimeter of square = 4 × side
  2. Perimeter of rectangle = 2 × (length + breadth)
  3. Perimeter of triangle = side1 + side2 + side3
📊 Visual ideas
Draw a rectangle and show arrows along the boundary indicating perimeter.
Draw an irregular polygon, label lengths of each side and show summation for perimeter.
🟦4

Area — Concept and Units

Understanding area

Area is the measure of the surface inside a plane figure. If you cover a tabletop with square tiles, the number of tiles you use equals the area (in tile units). Area tells us how much material is needed to cover a surface such as paint for a wall or grass seed for a field. The important idea is that area counts square units placed on the surface.

Square units and their meaning

When length is measured in centimetres, area is in square centimetres (cm2). When length is in metres, area is in square metres (m2). A square of side 1 cm has area 1 cm2. Because 1 m = 100 cm, a square of side 1 m contains 100 × 100 = 10000 small squares of 1 cm side, so 1 m2 = 10000 cm2. Keep these relations in mind while converting units for area problems.

Counting and approximating areas

On graph paper, you can count full squares inside a shape to find its area. For shapes that do not align with the grid, split into simple parts or estimate fractional squares. When using formulas it is essential that the given lengths are in the same unit. If you must change units for area, remember the square effect: when lengths are multiplied by 100 to convert metres to centimetres, the area multiplies by 10000.

Common uses and checks

Area is used for buying material such as carpets and tiles, calculating land for farming, and measuring painted surfaces. After computing area, always check the units and do a quick estimation: for a rectangle about 5 m by 4 m, you would expect about 20 m2, so a result near that confirms the calculation. Practice many examples to become comfortable moving between units and interpreting square measures.

📌 Examples
  • A rectangle 7 cm by 3 cm covers 21 small squares on grid paper, so area = 21 cm2.
  • Convert 3 m2 to cm2: 3 × 10000 = 30000 cm2.
🧮 Formulas
  1. 1 m2 = 100 cm × 100 cm = 10000 cm2
📊 Visual ideas
Draw a 6×4 square grid and shade a 4×3 rectangle to count area = 12 small squares.
Draw two 1 m × 1 m squares and show that combined area = 2 m2.
📐5

Area of a Rectangle and Square

Rectangle area

The area of a rectangle equals its length multiplied by its breadth. This is because a rectangle can be tiled by equal rows or columns of small squares. Measure the length and breadth in the same units and multiply to get the area in square units. For example, a carpet 4 m long and 2.5 m wide has area 4 × 2.5 = 10 m2.

Square as a special rectangle

A square is a rectangle with all sides equal. If the side is s, area = s × s = s2. This is called squaring the side. Since the square is a special rectangle, formulas and reasoning for rectangles apply directly to squares. Practise visualising a square tiled by smaller unit squares to see why side × side counts the number of unit squares.

Application and unit care

When measures are in different units, convert them first. For example if length is 120 cm and breadth is 1.5 m, convert 1.5 m to 150 cm or 120 cm to 1.2 m, and then multiply. The result’s unit will be squared; if both lengths are in cm the area is in cm2. For buying tiles or cloth, always use the area in the seller’s unit and allow a little extra for cutting and mistakes.

Practice tips

Draw each rectangle or square and label sides before calculating. Use small numbers first to build confidence, then move to decimals and mixed units. Compare your answer with a quick estimate: a 3 m by 2 m rectangle should be about 6 m2. If the exact answer is far from the estimate, re-check conversions and arithmetic.

📌 Examples
  • Rectangle 8 m × 3 m: area = 24 m2.
  • Square side 5 cm: area = 5 × 5 = 25 cm2.
🧮 Formulas
  1. Area of rectangle = length × breadth
  2. Area of square = side × side = side2
📊 Visual ideas
Draw a rectangle, label length and breadth and fill it with unit squares to show area = l × b.
Draw a square and divide it into smaller equal squares to visualize side2.
📐6

Area of a Triangle

Understanding the area formula

The area of a triangle is given by one half of the product of its base and corresponding height. Here, the height (or altitude) is the perpendicular distance from the chosen base to the opposite vertex. The formula comes from the fact that two identical triangles placed together along a side form a parallelogram whose area is base × height; each triangle is therefore half that area.

Using the formula correctly

Choose a side to be the base and draw the perpendicular from the opposite vertex to this base. Measure the base and the height in the same units. Then compute area = 1/2 × base × height. If you are given the base and not the height, look for information to calculate or draw the height. Many exam problems give height directly or make it easy to find from right angles in the figure.

Right and non-right triangles

For a right triangle, one side can be the base and the other perpendicular side the height. For other triangles, you may need to draw the altitude. When the altitude falls outside the triangle (in obtuse triangles), use the perpendicular to the extension of the base and take the correct positive height for the formula. In Class 6 most problems use straightforward bases and heights given inside the triangle.

Practical checks and examples

Always check units: base and height in metres give area in square metres. Estimate by rounding values to check reasonableness. Practice splitting composite shapes into triangles and rectangles to use this formula for parts. With repeated practice, identifying the base-height pair and applying the formula will become easy and reliable.

📌 Examples
  • Triangle base 12 cm, height 5 cm: area = 1/2 × 12 × 5 = 30 cm2.
  • Right triangle with legs 6 cm and 8 cm: taking legs as base and height, area = 1/2 × 6 × 8 = 24 cm2.
🧮 Formulas
  1. Area of triangle = 1/2 × base × height
📊 Visual ideas
Draw a triangle, drop a perpendicular from the top vertex to the base and label base and height.
Sketch two identical triangles joined to form a parallelogram to show why area is half.
⭕7

Area of a Circle (Introductory)

Parts of a circle and basic ideas

A circle is the set of all points at the same distance from a centre. The distance from the centre to the edge is the radius r. The diameter d passes through the centre and is twice the radius (d = 2r). To find areas of round shapes we use the special number π (pi), which relates circumference and diameter and appears in area formulas too.

Area formula and how to use it

For Class 6 the area of a circle is given by Area = πr2. The radius must be in proper units. You may be asked to use π = 22/7 or π = 3.14 depending on the question. If the diameter is given, first divide by 2 to get the radius, then substitute into the formula. The result will be in square units (for example cm2 or m2).

Why r squared?

The r2 term comes because area grows with the square of length: doubling the radius makes the circle four times larger in area. One way to picture this is to cut the circle into many thin sectors and rearrange them to form a rough rectangle with one side approximately πr and the other r, giving area close to πr × r = πr2. While the full proof uses more advanced geometry, this idea helps remember the formula.

Applications and practice

Circles appear in wheels, plates, ponds and round fields. Learn to convert diameter to radius and choose the value of π required. After calculating the area, check units and estimate roughly: a circle of radius 7 cm has area about 3.14×49 ≈ 154 cm2 (using π = 22/7 gives exact 154 cm2). Practice with different π values to see small differences in answers.

📌 Examples
  • Circle radius 5 cm with π = 3.14: area = 3.14 × 5 × 5 = 78.5 cm2.
  • Circle diameter 14 cm with π = 22/7: radius = 7 cm, area = (22/7) × 7 × 7 = 154 cm2.
🧮 Formulas
  1. Diameter = 2 × radius
  2. Area of circle = π × radius × radius = πr2
📊 Visual ideas
Draw a circle, show centre O, mark a radius and a diameter clearly.
Draw small concentric circles to show increase of area with radius.
🟦8

Area of Composite Figures

What are composite figures?

Composite figures are shapes made by joining simple shapes like rectangles, triangles, semicircles and circles. To find the area of such a figure, break it into simple parts whose areas you can calculate, then add areas of parts that are included and subtract the areas of parts that are removed (holes or cut-outs).

Step-by-step method

1. Draw the composite figure clearly and label all given dimensions. 2. Identify simple shapes (rectangles, triangles, semicircles) that make up the figure. 3. Write the area formula for each simple shape and compute using the given dimensions, taking care with units. 4. Add areas that form the whole shape and subtract any parts taken away. 5. Give the final answer with the correct square unit and do a quick estimate to check reasonableness.

Practical tips and common cases

Many questions show a rectangle with a semicircle attached or cut out, or a figure made of a rectangle and a triangle. Mark shared dimensions carefully so you do not recompute the same part twice. For semicircles, find the radius and use area = (1/2)πr2. If a part is repeated several times, compute once and multiply by the number of repeats. When numbers are not integers, use decimals or fractions and keep consistent units throughout the problem.

Checking and estimation

After calculating the combined area, compare with a rough estimate. For example, a rectangle 10 m by 4 m with a semicircle of radius 2 m attached will have rectangle area 40 m2 and semicircle area about (1/2)π(2)2 ≈ 6.28 m2, giving total ≈ 46.28 m2; if your calculation is far from this estimate, re-check lengths and unit conversions. Drawing and labelling carefully prevents most mistakes.

📌 Examples
  • Rectangle 12 m × 6 m with a semicircle radius 3 m on one side: total area = 12×6 + (1/2)π(3)2.
  • Square 8 cm with a triangular cut of area 6 cm2 removed: remaining area = 64 − 6 = 58 cm2.
📊 Visual ideas
Draw a rectangle with a semicircle attached and label rectangle and semicircle parts separately.
Sketch a square with a triangular cut corner, mark dimensions and show subtraction of area.
🟦9

Surface Area and Volume of Cubes and Cuboids

Faces and surface area

A cube and a cuboid are common solids with flat rectangular faces. Surface area is the sum of the areas of all faces. Total surface area (TSA) includes every face, while lateral surface area (LSA) includes only the side faces excluding top and bottom. These measures are useful when wrapping, painting or packing boxes.

Cube: surfaces and volume

A cube has six congruent square faces. If the edge length is a, the area of one face is a2. Therefore TSA = 6a2. The lateral surface area (if we consider four side faces) is 4a2. The volume measures how much space the cube holds; volume of a cube is a × a × a = a3. Units for area are square units and for volume are cubic units.

Cuboid: faces and volume

A cuboid has three different dimensions: length l, breadth b and height h. Its faces are rectangles in three pairs. The total surface area is TSA = 2(lb + bh + hl) because each pair contributes twice. The lateral surface area (excluding top and bottom) equals 2h(l + b). The volume equals l × b × h. Always ensure dimensions are in the same unit before using formulas. If dimensions are in cm, TSA is in cm2 and volume in cm3.

Practical use and checks

These formulas help to find how much paper is needed to wrap a box (TSA), how much paint to cover the sides of a cupboard (LSA), or how much a box can hold (volume). After calculating, round off sensibly, include proper units and do a quick estimate: a cuboid 10 cm × 5 cm × 2 cm has volume 100 cm3 and TSA around 2(50 + 10 + 20) = 160 cm2. If your computed values differ largely from an estimate, re-check steps and unit consistency.

📌 Examples
  • Cube edge 4 cm: TSA = 6 × 4 × 4 = 96 cm2, Volume = 4 × 4 × 4 = 64 cm3.
  • Cuboid 12 cm × 5 cm × 3 cm: TSA = 2(12×5 + 5×3 + 3×12) = 2(60 +15 +36) = 222 cm2; Volume = 12×5×3 = 180 cm3.
🧮 Formulas
  1. Total surface area of cube = 6 × a2
  2. Total surface area of cuboid = 2(l b + b h + h l)
  3. Lateral surface area of cuboid = 2h(l + b)
  4. Volume of cube = a3
  5. Volume of cuboid = l × b × h
📊 Visual ideas
Draw a cuboid, label length, breadth and height, and show each face area.
Draw the net of a cube showing six equal squares to visualize TSA.
🔢10

Practical Problems: Fencing, Tiling and Painting

Applying mensuration to daily tasks

Mensuration appears in many practical questions: fencing a garden needs perimeter, tiling a floor needs area, and painting walls needs area of vertical surfaces. To solve these, read the problem carefully, draw the figure and label all given measurements. Decide which quantity to find (perimeter, area, surface area or volume) and use the correct formula.

Fencing and borders

For fencing, the required length of material equals the perimeter of the field. If the fence has two rows or if gates reduce the needed fence, adjust accordingly. Always convert units to match the rope, wire or wood available. If the field is irregular, break the boundary into straight segments and add them.

Tiling and flooring

To find the number of tiles, compute the floor area and divide by one tile area. Remember to convert both to the same square unit. Allow extra tiles for cutting and breakage. For rectangular floors, area = length × breadth; for composite floors, split into parts and sum areas. If tiles are in cm and room in m, convert first.

Painting walls

For a simple rectangular room, area of four walls combined equals perimeter of the base × height (LSA). Subtract door and window areas if they are not painted. Multiply by number of coats if the question asks. Use consistent units and round sensibly. After solving, do a quick estimate: a room 4 m by 3 m with height 3 m has wall area ≈ 2(4+3)×3 = 42 m2; this helps check calculations.

📌 Examples
  • Fence for square garden side 15 m: fence length = 4×15 = 60 m.
  • Room 5 m × 4 m, tiles 0.25 m2: floor area = 20 m2; tiles needed = 20 ÷ 0.25 = 80 tiles.
📊 Visual ideas
Draw a rectangular room and label length, breadth and height; show wall area = perimeter × height.
Sketch a tiled floor and one tile with its dimensions to demonstrate division of areas.
👑11

Estimating, Checking Answers and Avoiding Mistakes

Estimating results

Estimation is a quick way to check whether an answer is sensible. Round measurements to nearby easy numbers and do a rough calculation. For example, if sides are 9.6 m and 4.3 m, estimate area by 10 × 4 = 40 m2 before calculating the exact product 41.28 m2. If the exact answer is far from the estimate, re-check the work.

Common mistakes and how to avoid them

Students often forget to convert units, use diameter instead of radius for circle formulas, forget the 1/2 in triangle area, or omit units in the answer. To avoid these: always write units with given data, convert lengths to the same unit before multiplying, remember radius = diameter ÷ 2 for circles, and draw the height for triangles. Underline key values in word problems and label your diagram clearly.

Checking arithmetic and logic

After solving, do a reverse check or a quick mental calculation. For area, check units (should be squared); for volume, check cubed units. For surface area problems, check whether you counted all faces. If possible, compute the value in another unit to confirm a consistent result. Keep work neat so you can follow steps later and spot mistakes quickly.

Practice and strategy

Regular short practice sessions help reduce errors. Learn main formulas by heart but always write them down before solving a question to avoid memory slips. Use estimation regularly and practice converting units so that these steps become automatic during exams. Being systematic—draw, label, convert, compute, check—will make mensuration problems straightforward and reliable.

📌 Examples
  • Estimate 7.9 × 3.2 by 8 × 3 = 24; exact = 25.28, close to estimate.
  • If diameter = 14 cm, mark radius = 7 cm before using area = πr2 to avoid wrong substitution.
📊 Visual ideas
Draw a circle and write both diameter and radius clearly to avoid confusion.
Sketch a rectangle with rounded figures and show how rounding is used to estimate area.

Key Concepts

Perimeter
The total distance around a closed plane figure.
Area
The amount of surface covered by a plane figure, measured in square units.
Volume
The amount of space occupied by a solid, measured in cubic units.
Square unit
A unit used for area, like cm2 or m2, formed by a square of the chosen length unit.
Cubic unit
A unit used for volume, like cm3 or m3, formed by a cube of the chosen length unit.
Radius
The distance from the centre of a circle to any point on the circle.
Diameter
A straight line through the centre of a circle joining two points on the circle; it equals twice the radius.
Base (of triangle)
The chosen side of a triangle on which the height is drawn for area calculation.
Height / Altitude
The perpendicular distance from a base to the opposite vertex in a triangle.
Total Surface Area
The sum of the areas of all faces of a solid.
Lateral Surface Area
The total area of the side faces of a solid, excluding top and bottom where applicable.
Composite Figure
A shape formed by combining two or more simple geometric figures.
π (Pi)
A constant approximately equal to 3.14 or 22/7 used in circle calculations.
Unit conversion
Changing a measurement from one unit to another using fixed relations, for example 1 m = 100 cm.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. Find the area of a rectangle of length 12 cm and breadth 5 cm. / 12 सेमी लंबाई और 5 सेमी चौड़ाई वाले आयत का क्षेत्रफल ज्ञात कीजिए।
    Show answer

    Area = length × breadth = 12 × 5 = 60 cm2. / क्षेत्रफल = लंबाई × चौड़ाई = 12 × 5 = 60 सेमी2।

  2. A square has side 9 m. What is its perimeter and area? / एक वर्ग की भुजा 9 मी है। इसका परिमाप और क्षेत्रफल क्या है?
    Show answer

    Perimeter = 4 × 9 = 36 m. Area = 9 × 9 = 81 m2. / परिमाप = 4 × 9 = 36 मी। क्षेत्रफल = 9 × 9 = 81 मी2।

  3. Find the area of a triangle with base 10 cm and height 6 cm. / आधार 10 सेमी और ऊँचाई 6 सेमी वाले त्रिभुज का क्षेत्रफल ज्ञात कीजिए।
    Show answer

    Area = 1/2 × base × height = 1/2 × 10 × 6 = 30 cm2. / क्षेत्रफल = 1/2 × आधार × ऊँचाई = 1/2 × 10 × 6 = 30 सेमी2।

  4. A circle has diameter 14 cm. Find its area using π = 22/7. / एक वृत्त का व्यास 14 सेमी है। π = 22/7 लेते हुए इसका क्षेत्रफल ज्ञात कीजिए।
    Show answer

    Radius = 14/2 = 7 cm. Area = πr2 = (22/7) × 7 × 7 = 154 cm2. / त्रिज्या = 14/2 = 7 सेमी। क्षेत्रफल = πr2 = (22/7) × 7 × 7 = 154 सेमी2।

  5. A cuboid measures 10 cm by 6 cm by 4 cm. Find its volume. / एक घनाभ का आयाम 10 सेमी × 6 सेमी × 4 सेमी है। इसका आयतन ज्ञात कीजिए।
    Show answer

    Volume = l × b × h = 10 × 6 × 4 = 240 cm3. / आयतन = लंबाई × चौड़ाई × ऊँचाई = 10 × 6 × 4 = 240 सेमी3।

  6. Find the total surface area of a cube of edge 5 cm. / 5 सेमी भुजा वाले घन का कुल पृष्ठीय क्षेत्रफल ज्ञात कीजिए।
    Show answer

    Total surface area = 6 × a2 = 6 × 5 × 5 = 150 cm2. / कुल पृष्ठीय क्षेत्रफल = 6 × a2 = 6 × 5 × 5 = 150 सेमी2।

  7. A rectangular field is 80 m long and 50 m wide. Find the length of fence required to go around it once. / एक आयताकार खेत 80 मी लंबा और 50 मी चौड़ा है। उसके चारों तरफ एक बार बाड़ लगाने के लिए कितना तार चाहिए?
    Show answer

    Perimeter = 2(l + b) = 2(80 + 50) = 2 × 130 = 260 m. / परिमाप = 2(ल + प) = 2(80 + 50) = 260 मीटर।

  8. How many square tiles of side 25 cm are needed to cover a floor of 5 m by 4 m? / 25 सेमी भुजा वाले कितने वर्ग टाइल्स 5 मी × 4 मी के फर्श को ढकने के लिए चाहिए?
    Show answer

    Floor area = 5 × 4 = 20 m2 = 20 × 10000 = 200000 cm2. Tile area = 25 × 25 = 625 cm2. Number of tiles = 200000 ÷ 625 = 320 tiles. / फर्श क्षेत्रफल = 5 × 4 = 20 मी2 = 20 × 10000 = 200000 सेमी2. टाइल क्षेत्रफल = 25 × 25 = 625 सेमी2. टाइलों की संख्या = 200000 ÷ 625 = 320 टाइलें।

  9. A composite shape is made of a rectangle 10 cm by 6 cm with a right triangle (base 4 cm, height 3 cm) attached on one end. Find the total area. / एक यौगिक आकृति 10 सेमी × 6 सेमी वाले आयत और उसके एक छोर पर जोड़े गए समकोण त्रिभुज (आधार 4 सेमी, ऊँचाई 3 सेमी) से बनी है। कुल क्षेत्रफल ज्ञात कीजिए।
    Show answer

    Rectangle area = 10 × 6 = 60 cm2. Triangle area = 1/2 × 4 × 3 = 6 cm2. Total area = 60 + 6 = 66 cm2. / आयत का क्षेत्रफल = 10 × 6 = 60 सेमी2. त्रिभुज का क्षेत्रफल = 1/2 × 4 × 3 = 6 सेमी2. कुल क्षेत्रफल = 60 + 6 = 66 सेमी2।

  10. Estimate the area of a rectangle of length 9.6 m and breadth 4.3 m and then give the exact area. / 9.6 मी लंबाई और 4.3 मी चौड़ाई वाले आयत का क्षेत्रफल अनुमान लगाइए और फिर सही क्षेत्रफल दीजिए।
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    Estimate by rounding: 10 × 4 = 40 m2 (approx). Exact area = 9.6 × 4.3 = 41.28 m2. / राउंड करके अनुमान: 10 × 4 = 40 मी2 (प्रायः). सही क्षेत्रफल = 9.6 × 4.3 = 41.28 मी2।

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