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Class 6 Mathematics Chapter 10 of 18

Chapter 10 — Equations

Open the lesson Play with this chapter — pictures, sound and practice.

Overview

This unit introduces students to equations and how they represent unknown quantities using numbers and symbols. Starting from the idea of a simple balance and missing numbers in sums, the unit builds the language of equations: variables, constants, expressions and the equals sign. Students learn to form equations from simple statements and word problems, and practise methods to find the unknown by using inverse operations — addition with subtraction, multiplication with division — and by keeping both sides equal. Emphasis is on understanding, checking answers, and applying equations to everyday situations such as sharing, finding a missing addend, or simple mixture problems. The unit matters because equations are the basic tool for algebra; they develop logical thinking and problem-solving skills, and prepare students for higher classes where these ideas are used to study patterns, functions and geometry. By the end of the unit, learners should comfortably read an equation, set up an equation from words, solve one-step and simple two-step equations, and verify their results. Activities include model drawing, number balance diagrams, and word problems to connect arithmetic to algebraic thinking.

Learning Objectives

  • Recognize and use the equals sign to show balance between two expressions.
  • Identify unknowns and write simple equations to represent given situations.
  • Solve one-step equations using inverse operations and explain each step.
  • Apply addition-subtraction and multiplication-division to find unknowns in equations.
  • Check solutions by substituting the found value back into the original equation.
  • Translate short word problems into equations and solve them correctly.
  • Use a balance model or number line to show why operations preserve equality.
  • Explain the role of variables, constants and coefficients in simple equations.

Topics in this chapter

14 topics · tap a topic title to jump straight to it.

🟰1

What is an equation?

Meaning: An equation is a mathematical sentence that shows two things are equal. It uses the equals sign '=' to state that the expressions on both sides have the same value. Equations can be true statements like 7 + 3 = 10 or can include an unknown number such as x + 5 = 12. The unknown is a value we want to find.

Why we use equations: Equations help us write problems from everyday life in a short and clear way. Instead of saying ‘a number plus five gives twelve’, we write it as x + 5 = 12. This makes it easier to solve and check answers.

Parts of an equation: The left side and the right side are separated by the equals sign. Each side may have numbers, unknowns (also called variables), and operations like addition and multiplication. For example, in 3 + y = 8, '3 + y' is the left side and '8' is the right side.

True and false equations: An equation is true if both sides actually have the same value; it is false if they do not. For example, 4 + 2 = 7 is false. If an unknown is present, we find a number that makes the equation true; that number is called the solution.

Simple checks: After solving, always substitute the found number back into the equation to check. This confirms the solution makes both sides equal.

📌 Examples
  • Example 1: 5 + 4 = 9 is true because both sides equal 9.
  • Example 2: x + 3 = 7. Solve x: x = 4, because 4 + 3 = 7.
  • Example 3: 6 = 2 × 3 is an equation showing equality of multiplication and number.
  • Example 4: 8 − y = 5. Solve y: y = 3.
🧮 Formulas
  1. Equation: expression = expression
  2. Solution: value of unknown that makes the equation true
📊 Visual ideas
Draw two boxes with an equals sign between; place expressions in each to show balance
A simple number statement on a number line showing both sides equal (e.g., 2 + 3 on number line reaching 5)
🔢2

Unknowns and variables

What is an unknown? An unknown is a number we do not yet know. In equations we use a letter or a blank to show the unknown. Common letters are x, y or a. The letter stands for a particular number that makes the equation true. Using a letter lets us write the problem clearly and work with it with rules of arithmetic.

Why letters? Letters are convenient placeholders. They allow us to express patterns and repeat problems with different numbers. For example, writing x + 2 = 5 shows the form of the problem without fixing the number. Using letters also helps when the unknown stands for different things: money, age, number of objects, etc. Choose a simple letter and state what it represents before forming the equation.

How variables behave: A variable stands for one fixed value in a given problem. If we write x + 4 = 9 and say x is the number of marbles, then x must be 5 for that specific problem. In another problem the same letter may represent a different number; the meaning depends on the context provided each time.

Finding the unknown: Use the inverse operation. If the unknown is added to a number, subtract that number to find the unknown. If it is multiplied, divide. This operation must be done on both sides of the equation to keep equality. Practice this with small whole numbers until the steps become automatic.

Multiple unknowns and simple cases: In class 6 we mainly work with one unknown. If there appear two blanks in a puzzle, try to use information to reduce to one unknown, or use trial with small numbers. For now, learn to identify the unknown, assign a clear letter, and write expressions that describe the story in the question.

Practical tips: Always name the unknown in words before using a letter, for example 'Let x = number of apples.' Write the check after solving: replace the letter by the found number and calculate both sides to confirm equality. This habit prevents careless mistakes and builds understanding.

📌 Examples
  • Example 1: Let x be the unknown in x + 6 = 11. Then x = 5.
  • Example 2: y × 4 = 20. Then y = 5 because 5 × 4 = 20.
🧮 Formulas
  1. If a + x = b then x = b − a
  2. If a × x = b then x = b ÷ a
📊 Visual ideas
Draw a box labelled 'unknown' and arrows showing inverse operations to obtain its value
A simple balance scale with one side showing 'x + 3' and the other side '7' to illustrate solving for x
🔢3

Using the balance model

Balance idea: Think of an equation as a two-pan balance. Both pans must be equal (balanced) for the equation to be true. If one side contains 'x + 3' and the other side contains '10', the pans are balanced only when the unknown x has a value that makes the two sides equal. The balance model helps visualise why we must do the same thing to both sides of an equation.

Doing the same thing to both sides: If you add 2 to one pan, add 2 to the other pan too; if you remove 5 from the right pan, remove 5 from the left as well. In algebra, this means when we add, subtract, multiply or divide one side of an equation by a number, we must do the same operation on the other side. This keeps the pans balanced and the equality true.

Undoing operations safely: To find the unknown, reverse the operations that hide it. If x has 4 added to it (x + 4), remove 4 from both sides. If x is multiplied by 5 (5x), divide both sides by 5. Doing these steps on both sides keeps the balance. The balance model explains why inverse operations work and why they must be applied equally.

Visual steps and teaching method: Draw a picture of the two pans. Write the expression on each pan. Show an arrow with the operation you will apply to both pans (for example, an arrow labelled '−3' from each pan). After carrying out the operation, redraw the pans to show the new expressions. Repeat until the unknown stands alone on one pan. This step-by-step drawing helps students who learn visually.

Limits and cautions: Do not divide by zero or perform different operations on each side. Explain that dividing by zero is not allowed because it does not make sense in the balance model. Also, when working with subtraction, note carefully which number is removed from both sides so signs are correct. The balance picture helps avoid the common error of changing only one side.

Practice activities: Use physical objects (blocks or counters) on two trays to represent each side. Let students add or remove the same number of blocks from both trays and observe balance. This hands-on experience makes the idea concrete and improves understanding before moving to symbolic equations.

📌 Examples
  • Example 1: For x + 5 = 12, show x + 5 on left pan and 12 on right. Remove 5 from both pans to get x = 7.
  • Example 2: For 3x = 15, show 3 groups of x on left and 15 on the right. Divide both pans by 3 groups to get x = 5.
🧮 Formulas
  1. If A = B then A + c = B + c for any number c
  2. If A = B then A − c = B − c for any number c
  3. If A = B then A × c = B × c and A ÷ c = B ÷ c (c ≠ 0)
📊 Visual ideas
Sketch a two-pan balance; show 'x + 3' on left pan and '8' on right; draw arrows showing removal of 3 from both sides
Balance drawing for '2x' on one pan and '10' on the other; show dividing both sides by 2
➕4

Solving simple one-step equations (addition/subtraction)

One-step equations: These equations need only one inverse operation to find the unknown. The most common forms are x + a = b and x − a = b. The inverse of adding is subtracting, and the inverse of subtracting is adding. Using these inverses on both sides isolates the unknown.

Step-by-step method: 1) Identify the operation applied to the unknown. 2) Choose the inverse operation. 3) Apply the inverse to both sides of the equation. 4) Simplify to find the unknown. 5) Check by substitution. For example, in x + 9 = 14 the inverse of +9 is −9; subtract 9 from both sides to get x = 5, then check: 5 + 9 = 14.

Working with unknown on either side: If the unknown appears on the right side as in 7 = y + 2, apply the inverse on both sides: subtract 2 to get y = 5. The steps are exactly the same whether the unknown is on the left or right; remember to perform the change on both sides.

Using number lines and mental check: A number line can show the movement: start at the known result and move backward when undoing an addition. For example in x + 6 = 11, start at 11 and move 6 steps back to reach x = 5. This visual aid helps students who prefer spatial reasoning.

Common mistakes and fixes: Students sometimes subtract from one side only or write the inverse incorrectly. Encourage writing the full step — for example x + 5 − 5 = 12 − 5 — to show the same action on both sides. Teach them to always state the inverse operation and show it performed on both sides.

Practice progression: Start with small whole numbers until the method is secure. Then give problems where subtraction appears first like 12 − x = 7; teach adding x then subtracting constants or directly rearranging as x = 12 − 7 depending on which approach is clearer for the student.

📌 Examples
  • Example 1: x + 9 = 14. Subtract 9 from both sides: x = 5. Check: 5 + 9 = 14.
  • Example 2: 12 − x = 7. Add x to both sides then subtract 7 or rewrite: x = 12 − 7 = 5.
🧮 Formulas
  1. If x + a = b then x = b − a
  2. If x − a = b then x = b + a
📊 Visual ideas
Number line showing a move forward for addition and backward for subtraction to reach the solution
Balance drawing for x + 4 = 9 then removing 4 from both pans
✖️5

Solving simple one-step equations (multiplication/division)

Multiplication and division equations: These are one-step equations where the unknown is multiplied or divided by a number. Common forms are ax = b and x ÷ a = b. To find the unknown, use the inverse operation: divide when the unknown is multiplied and multiply when the unknown is divided.

Detailed method: For ax = b (where a ≠ 0), divide both sides by a to get x = b ÷ a. For x ÷ a = b, multiply both sides by a to get x = a × b. Always perform the same arithmetic on both sides to keep the equation balanced. Write each step clearly: for example 5x = 35 → (5x) ÷ 5 = 35 ÷ 5 → x = 7.

Working with non-whole answers: If b is not divisible by a, the answer may be a fraction or decimal. For example 3x = 10 gives x = 10 ÷ 3 = 10/3. Teach students that fractions are acceptable answers and show how to check by multiplying back: 3 × (10/3) = 10.

Using grouping picture: Draw equal groups to explain multiplication. If 4x = 20, draw 4 equal boxes representing x and show they together total 20; then ask how many are in one box. This helps children who find abstract division hard. For x ÷ 5 = 6, show that when x is shared into 5 equal parts, each part is 6; combine parts (6 × 5) to get x = 30.

Common errors and tips: A common mistake is to divide one side only. Emphasise performing the same division or multiplication on both sides. Also caution against dividing by zero; never divide both sides by 0. For better understanding, practise inverse operations on the number line and with small manipulatives.

Contextual examples: Use real-life stories: 'If 5 packets contain 30 biscuits, how many in one packet?' leads to 5x = 30. 'If a piece of cloth is cut into 4 equal parts of 3 m each, what was the original length?' gives x ÷ 4 = 3 → x = 12.

📌 Examples
  • Example 1: 4x = 28. Divide both sides by 4: x = 7. Check: 4 × 7 = 28.
  • Example 2: x ÷ 5 = 6. Multiply both sides by 5: x = 30. Check: 30 ÷ 5 = 6.
🧮 Formulas
  1. If a × x = b then x = b ÷ a (a ≠ 0)
  2. If x ÷ a = b then x = a × b
📊 Visual ideas
Draw a balance with '5x' on one side and '35' on the other, then an arrow showing division by 5
Number line showing equal jumps when solving x ÷ 4 = 6 by multiplying 6 × 4
🟰6

Two-step equations (combining operations)

What is a two-step equation? A two-step equation requires two inverse operations to isolate the unknown. These equations often have the unknown multiplied and then a number added or subtracted, for example 2x + 3 = 11. Solving needs undoing the operations in reverse order of their appearance.

Reverse the operations: The principle is to undo the last operation first. For 2x + 3 = 11, the last operation performed on x was adding 3, so we first subtract 3 from both sides: 2x = 8. Next, undo the multiplication by dividing both sides by 2 to obtain x = 4. Always perform each inverse operation on both sides to keep equality.

Stepwise plan for students: 1) Read the equation and identify the operations. 2) Decide the inverse operations and the order to apply them. 3) Apply the first inverse to both sides and simplify. 4) Apply the second inverse to both sides and simplify. 5) Check by substituting the found value back into the original equation.

Different forms to practise: Work on equations that show subtraction first or division first, such as 3x − 5 = 16 (add 5 then divide by 3) or x/2 + 4 = 10 (subtract 4 then multiply by 2). Also try equations with the unknown on the right, e.g., 12 = 3x + 6; subtract 6 then divide by 3. Practising different layouts builds flexibility.

Common pitfalls: Students sometimes divide before removing added constants, which leads to incorrect answers. Teach them to identify what operation directly affects the unknown and undo that last. Encourage writing each intermediate result to avoid skipping steps. Also keep attention to negative results when subtraction gives negative numbers.

Visual helps and checks: Use the balance drawing to show two-step undoing: first remove the added number from both pans, then split groups to undo multiplication. Always finish by substituting the solution into the original equation to confirm both sides are equal.

📌 Examples
  • Example 1: 2x + 3 = 11. Subtract 3: 2x = 8. Divide by 2: x = 4.
  • Example 2: 3x − 4 = 11. Add 4: 3x = 15. Divide by 3: x = 5.
🧮 Formulas
  1. Undo in reverse order: for ax + b = c, first do c − b then ÷ a giving x = (c − b) ÷ a
📊 Visual ideas
Balance showing '2x + 3' on left and '11' on right; show removal of 3 then division by 2
A step flow diagram: start → subtract b → divide by a → solution
🟰7

Forming equations from word problems

Translate words into maths: Forming an equation from a word problem is a key skill. Start by reading the problem slowly and underlining important words. Decide what the unknown is and name it with a letter: for example, 'Let x be the number of apples'. This helps keep the work clear.

Look for keywords: Words that show operations: 'more than', 'sum', 'together' suggest addition; 'left', 'difference', 'less than' suggest subtraction; 'times', 'each', 'product' suggest multiplication; 'shared equally', 'divided among' suggest division. Also watch for phrases like 'twice', 'thrice', or 'one-third' which directly give multiplication or division expressions.

Write expressions step-by-step: Convert each sentence into a short expression. If the story has more than one sentence, write one expression per sentence. Then combine expressions with the equals sign where the problem indicates equality. For example, 'A number increased by 5 gives 20' becomes x + 5 = 20. Another example: 'Three times a number is equal to 21' becomes 3x = 21.

Check units and context: If the problem involves rupees, years, or objects, mention units in the working to avoid confusion. For example, if x denotes rupees, write x rupees to remind yourself and the reader. If an answer is fractional but objects cannot be split, re-read the problem — maybe the equation was set up wrongly or rounding is needed based on context.

Use small examples to test: If unsure, use a simple trial value to see if your understanding of the story is correct. For example, if the problem says 'He has 3 times more than her and together they have 20', pick a small number for one person and test. This trial helps shape the correct equation before formal solving.

Practice translating full sentences: Make a habit of writing the equation line after underlining the key words, then solve and check by substituting the answer into the original text to see if all parts match. This double-checking prevents mistakes in translation.

📌 Examples
  • Example 1: Ravi has x sweets. He gets 6 more and then has 14. Equation: x + 6 = 14. Solve: x = 8.
  • Example 2: A box has 4 times a number of pens equals 24. Equation: 4x = 24. Solve: x = 6.
📊 Visual ideas
Draw a simple picture showing objects grouped (e.g., groups of pens) to form the equation
Number line check showing the result when substitution is done
🧴8

Checking and verifying solutions

Why checking matters: Checking is the process of putting the obtained value back into the original equation to confirm both sides are equal. It catches arithmetic mistakes and errors made while forming the equation from words. Developing the habit of checking improves accuracy and builds confidence.

How to check step-by-step: 1) Take the solution value found for the unknown. 2) Substitute it carefully in every place the unknown appears in the original equation. 3) Follow the operations precisely and simplify both sides. 4) Compare the two simplified results. If they are equal, the solution is correct; if not, review the steps to find the mistake.

Checks with one-step and two-step problems: For x + 7 = 12, substitute x = 5 to get 5 + 7 = 12 and check the equality. For 2x + 3 = 11 with x = 4, substitute to get 2×4 + 3 = 8 + 3 = 11. For fraction answers, ensure to perform fraction arithmetic correctly during substitution to avoid false errors.

What to do if the check fails: If substitution does not give equality, trace back. Check whether the equation was formed correctly from the word problem. If the equation is correct, re-calculate the arithmetic steps. Look for common slips: wrong sign when moving terms, dividing by the wrong number, or arithmetic errors in addition/subtraction or multiplication/division.

Using checks as partial credit: In exams, writing a clear check may earn marks for method even if the final answer had a small arithmetic mistake. Teach students to write the check line below the solution as standard practice. This shows understanding of the process and provides an easy way for teachers to award method marks.

Tips for effective checking: Use neat substitution and write intermediate calculations. For multi-part word problems, check each condition of the problem with the found solution. For example if the problem gives two conditions, substitute into both to ensure the answer satisfies all parts. Encourage students to add a short comment like 'Check: LHS = RHS' when the check is successful.

📌 Examples
  • Example 1: Solve x + 7 = 12 → x = 5. Check: 5 + 7 = 12 ✓
  • Example 2: Solve 3x = 15 → x = 5. Check: 3 × 5 = 15 ✓
📊 Visual ideas
Flow of steps ending with 'substitute answer and check' box
Short calculation written under the solved equation to show checking
🟰9

Equations with unknown on both sides

Understanding unknowns on both sides: Sometimes an equation has the variable appear on both left and right sides, for example 3x + 2 = x + 10. The goal remains to find the number that makes both sides equal. To do that, move all terms with the unknown to one side and constants to the other, using addition or subtraction on both sides.

Step-by-step method: 1) Choose a side to keep the unknown terms (commonly the left). 2) Subtract or add the same term from both sides to remove the variable from the other side. For 3x + 2 = x + 10, subtract x from both sides: 2x + 2 = 10. 3) Then move constants: subtract 2 from both sides giving 2x = 8. 4) Finally divide both sides by 2 to get x = 4. Each step must be shown clearly to avoid mistakes.

Combining like terms: After moving variables to one side, combine like terms before doing the final inverse operation. Like terms are those with the same variable to the same power. For example, 5x − 2x = 3x. Combining reduces the equation to a simpler form that is easier to solve.

Special cases to notice: Some equations reduce to identities or contradictions. For instance, 2x + 3 = 2x + 3 is true for every x — it is an identity. On the other hand, 2x + 3 = 2x + 5 leads to 3 = 5 after cancelling 2x, which is impossible; such an equation has no solution. Teach students to recognise these outcomes when simplification removes the variable completely.

Practical tips: Use subtraction carefully and keep track of signs. If subtracting x from both sides, write (3x + 2) − x = (x + 10) − x to show the equal action. Also always check the final value in the original equation, especially for problems where variable cancellation gives identity or no-solution cases. This check confirms whether the equation had one solution, all solutions, or none.

📌 Examples
  • Example 1: 3x + 2 = x + 10. Subtract x: 2x + 2 = 10. Subtract 2: 2x = 8. Divide 2: x = 4.
  • Example 2: 5 + y = 2y − 1. Subtract y: 5 = y − 1. Add 1: y = 6.
📊 Visual ideas
Balance showing '3x + 2' and 'x + 10' then arrows indicating subtraction of x from both sides
Step flow: collect like terms → simplify → solve
➗10

Simple equations leading to fractions

When fractions appear: Some equations give solutions that are fractions rather than whole numbers. For example, 3x = 10 leads to x = 10 ÷ 3 = 10/3. Explain that a fraction represents a part of a whole and is a valid number for the solution. Fractions can be shown as proper fractions, improper fractions or mixed numbers, depending on what the teacher prefers.

How to solve and write answers: Follow the usual method: isolate the unknown and perform division if necessary. If ax = b and b is not divisible by a, write x = b/a. Encourage students to leave answers as simple fractions rather than forcing decimals, unless the context asks for decimal form. For example 10/3 is acceptable; it can also be written as 3 1/3 if mixed numbers are taught.

Clearing fractions from an equation: If the unknown appears inside fractions, multiply both sides by the common denominator to clear fractions and simplify the work. For example, in x/2 + 3 = 7, multiply both sides by 2 to obtain x + 6 = 14, then solve to get x = 8. This method reduces mistakes when working with multiple fractional terms.

Handling checking with fractions: Substitute the fraction back and multiply or add carefully. Show students how to simplify steps when substituting: for x = 10/3 in 3x = 10, compute 3 × (10/3) = 10 by cancelling the 3. For other checks, use common denominators to add or subtract fractions correctly.

Contextual suitability: Remind students that some real-world problems expect whole-number answers (e.g., people or chairs). If a fractional solution appears, re-evaluate whether the model was correct or whether rounding is needed. Teachers can discuss what rounding rules apply in practical situations, but for pure arithmetic, keep fractional answers exact.

Practice suggestions: Use simple denominators like 2, 3 and 4 first. Give problems both where the solution is a whole number and where it is a fraction, and ask the student to check each answer by substitution.

📌 Examples
  • Example 1: 3x = 10 → x = 10/3. Check: 3 × (10/3) = 10.
  • Example 2: x/4 = 5 → multiply both sides by 4 → x = 20.
🧮 Formulas
  1. If a × x = b then x = b ÷ a which can be written as fraction b/a
📊 Visual ideas
Number line showing fraction 10/3 located between 3 and 4
Table showing multiplication to check fraction solutions
💰11

Word problems: ages, money and sharing

Age problems: Age problems often use phrases such as 'years older', 'years younger', 'three years ago', or 'after five years'. Let the present age of a person be x and then write expressions for past or future ages by subtracting or adding years. For example, if A is 5 years older than B and A = 12, then B = x and the equation is x + 5 = 12. For two-person problems with both ages unknown, assign letters to both and use the relationship given to form equations.

Money problems: Money problems use rupees and paise; keep units consistent. When a sentence says 'has 7 rupees more', write x + 7. For 'twice as much' write 2x. If the problem mixes rupees and paise, convert paise to rupees (or vice versa) before forming the equation. Clearly label the variable as 'x rupees' to avoid confusion during solving.

Sharing problems: For equal sharing, if total T is shared among n people, each gets T ÷ n. If one person gets x and another gets x + 3, and their total is known, set x + (x + 3) = total and solve. For ratio sharing, introduce simple ratios such as 2:3 then convert into expressions like 2k and 3k, but keep examples basic for class 6 and explain what 'k' signifies.

Step-by-step approach for word problems: 1) Read the problem twice and underline key facts. 2) Choose variables and state what they mean. 3) Translate each sentence to a mathematical expression. 4) Combine expressions into an equation and solve. 5) Substitute the found value into the original conditions to check all parts of the problem are satisfied.

Real-life examples and units: Use everyday contexts—sweets, pencils, rupees, ages—to make the problems relatable. Remind students to include units in final answers (e.g., 'x = 12 years' or 'x = 20 rupees'). If an answer is fractional but context requires a whole number, discuss whether rounding or reinterpretation is needed.

Common classroom tasks: Ask students to write their own small stories requiring an equation and swap with a partner to solve. This strengthens translation from language to mathematics and encourages precise thinking about what the unknown represents.

📌 Examples
  • Example 1: Sumita is 4 years older than Ravi. If Sumita is 12, Ravi's age x satisfies x + 4 = 12 → x = 8.
  • Example 2: 24 sweets shared equally among 4 children. Each gets x: 4x = 24 → x = 6.
📊 Visual ideas
Simple diagram: two children with sweets labelled x and x + 3 to form equation x + (x + 3) = total
Table listing ages or money values before and after an operation
🟰12

Practice with puzzles and simple equations

Using puzzles to learn: Puzzles make algebra interesting and help students think in steps. Puzzles commonly give a description that can be translated into an equation. For example: 'Find a number which, when added to its double, gives 21.' If x is the number, write x + 2x = 21. Turning such sentences into equations becomes routine with practice.

How to solve puzzle sentences: 1) Read the sentence and identify key phrases such as 'its double', 'three times', 'decreased by', or 'increased by'. 2) Assign a letter to the unknown and build the expression. 3) Simplify like terms if needed and then solve with the usual inverse operations. 4) Check by substituting the result back into the original sentence to ensure all conditions are satisfied.

Create-your-own puzzles: Encourage students to write short riddles where the answer is a number (e.g., 'I am thinking of a number; its triple minus 5 is 16. What is the number?'). Swapping these puzzles in pairs helps students learn different phrasings and improves translation skills.

Timed drills and group work: Short timed exercises with many simple puzzles increase speed and confidence. Group activities where each student contributes one line of a multi-step story also improve collaborative problem solving. Begin with one-step puzzles and gradually add two-step puzzles as confidence grows.

Comparing guessing vs algebra: Show how algebra is faster and more reliable than guesswork: for example, solving x + 3x = 48 gives x = 12 quickly, whereas guessing may take longer. Discuss how algebra gives a method that works for many problems, not just single cases.

Encourage clear presentation: Write each translation and the solving steps neatly and always finish with a check to demonstrate the answer fits the puzzle. This habit helps in examinations and builds good mathematical practice.

📌 Examples
  • Example 1: 'A number plus its triple is 48.' Equation: x + 3x = 48 → 4x = 48 → x = 12.
  • Example 2: 'Twice a number decreased by 4 equals 10.' Equation: 2x − 4 = 10 → 2x = 14 → x = 7.
📊 Visual ideas
Short flowchart: puzzle → write equation → solve → check
A simple table of guesses then algebraic solving to show efficiency
🔢13

Common mistakes and how to avoid them

Frequent errors: Students commonly make mistakes such as performing an operation on one side only, changing signs incorrectly when moving terms, or applying inverse operations in the wrong order for multi-step equations. Other errors include arithmetic slips, failing to combine like terms, or forgetting to check the final answer. Recognising these helps to correct them early.

Using the balance idea to prevent errors: Remind students that an equation is like a balance. Always do the same thing to both sides. If you subtract a number from the left side, subtract it from the right side too. Writing the action explicitly — for example, (3x + 2) − 2 = (x + 10) − 2 — shows correct handling and reduces careless mistakes.

Careful handling of signs: When moving a term across the equals sign, teach students to perform the corresponding inverse operation on both sides rather than simply 'changing the sign'. For example, to move +x from the right to the left, subtract x from both sides. This removes ambiguity and avoids incorrect sign changes.

Show intermediate steps: Encourage writing each step clearly rather than skipping steps. Skipping can cause confusion and hide errors. Intermediate steps make it easier to find and correct mistakes and help teachers award method marks even if the final arithmetic is wrong.

Check after solving: Always substitute the found value back into the original equation. Checking quickly reveals whether the solution works. Teaching students the habit of writing a short check line after solving will catch many mistakes and reinforce understanding.

Practical classroom tips: Use colour to mark terms to be moved, or underline the operation that will be undone first. Give common wrong examples and ask students to explain why they are wrong. This active correction helps students internalise correct methods and reduces repeated errors.

📌 Examples
  • Example 1: Wrong: From x + 5 = 9, writing x = 5 − 9. Right: x = 9 − 5 = 4.
  • Example 2: Wrong moving: 3x + 2 = x + 8. Wrong step: 3x = 8 − 2. Right: subtract x and 2 correctly: 2x + 2 = 8 → 2x = 6.
📊 Visual ideas
Side-by-side wrong and right solution flow showing correct operations
Marking scheme table showing steps and checks to reduce error
🔢14

Revision and consolidation activities

Methods for revision: Use a mix of short exercises, group tasks, and oral questions. Flash questions on one-step equations keep skills fresh. Group tasks where each student solves a part of a multi-step problem help consolidate cooperative learning. Oral questioning forces clear explanation which strengthens conceptual understanding.

Consolidation structure: Prepare sets of questions that cover all types: identifying unknowns, forming equations from short stories, one-step addition/subtraction, one-step multiplication/division, two-step equations, unknowns on both sides, and basic fraction answers. Start with easy problems for warm-up, then include a few higher-difficulty problems to stretch learners. Include at least two word problems in each set to test translation skills.

Timed practice and assessment: Give a small timed quiz of 8–10 mixed problems to build speed and accuracy. Set clear expectations: students must write the variable meaning, show steps and include a check. Use a simple rubric so students know how marks are given: correct setup, correct steps, arithmetic, and final check each carry marks.

Homework and ongoing practice: Assign daily practice of two to four equations mixing different types. Keep a 'mistake log' notebook where students copy errors they made and write the correct method next to them; reviewing this before tests reduces repeated mistakes. Encourage peer checking: students can swap notebooks and check each other's solution and checks.

Active revision activities: Use card games where each card has a short story and students write the equation and solve in pairs. Another activity is 'equation relay' where one student writes the first step and the next continues. These make revision lively and help students remember steps through practice and collaboration.

Reflection and planning: After each revision session ask students to note one area they found easy and one area they need more practice in. Use this feedback to plan extra practice or small group remedial lessons.

📌 Examples
  • Example 1: Mixed short test: Solve x + 6 = 13; 4x = 20; 2x + 3 = 11; x/3 = 5.
  • Example 2: Group activity: Form an equation from a class-made story, solve and check together.
📊 Visual ideas
Revision checklist table with topic names, number of questions, and success tick boxes
Simple planner: daily practice boxes for equations, word problems and checking

Key Concepts

Equation
A mathematical statement that two expressions have the same value, shown with an equals sign.
Unknown/Variable
A letter or symbol used to represent a number we do not yet know.
Solution
The value of the unknown that makes the equation true.
Equals sign
The symbol '=' which shows that the expressions on both sides have equal value.
Expression
A combination of numbers, variables and operations that represents a value.
Constant
A fixed number in an expression or equation.
Coefficient
A number multiplied by a variable in an expression.
Inverse operation
An operation that undoes another, such as subtraction undoing addition.
Balance model
A visual idea that both sides of an equation must stay equal like a two-pan balance.
One-step equation
An equation that needs a single inverse operation to find the unknown.
Two-step equation
An equation that requires two inverse operations performed in order to find the unknown.
Check/Verification
Substituting the found value back into the original equation to confirm correctness.
Like terms
Terms that have the same variable raised to the same power and can be combined.
Identity
An equation true for all values of the variable, e.g., 2x + 3 = 2x + 3.
No solution
A situation when no value of the variable makes the equation true.

End-of-Chapter Trial Paper & Test Questions

Topic-wise questions to test your understanding of every concept in this chapter.

  1. Find the missing number: x + 7 = 15 / खाली जगह भरिए: x + 7 = 15
    Show answer

    Solution: x = 15 − 7 = 8. Check: 8 + 7 = 15. / हल: x = 15 − 7 = 8. जाँच: 8 + 7 = 15.

  2. Solve: 4x = 36 / हल कीजिए: 4x = 36
    Show answer

    Solution: x = 36 ÷ 4 = 9. Check: 4 × 9 = 36. / हल: x = 36 ÷ 4 = 9. जाँच: 4 × 9 = 36.

  3. Form an equation and solve: A number increased by 5 gives 20. / एक संख्या में 5 जोड़ने पर 20 मिलता है; समीकरण बनाइए और हल कीजिए।
    Show answer

    Let the number be x. Equation: x + 5 = 20. Solution: x = 15. Check: 15 + 5 = 20. / मान लीजिए संख्या x है. समीकरण: x + 5 = 20. हल: x = 15. जाँच: 15 + 5 = 20.

  4. Solve: 2x + 3 = 13 / हल kiजिए: 2x + 3 = 13
    Show answer

    Subtract 3: 2x = 10. Divide by 2: x = 5. Check: 2×5 + 3 = 10 + 3 = 13. / 3 घटाइए: 2x = 10. 2 से भाग करें: x = 5. जाँच: 2×5 + 3 = 13.

  5. If 3 times a number is 27, what is the number? / यदि किसी संख्या का तीन गुना 27 है, तो वह संख्या कितनी है?
    Show answer

    3x = 27 so x = 27 ÷ 3 = 9. Check: 3 × 9 = 27. / 3x = 27 इसलिए x = 27 ÷ 3 = 9. जाँच: 3 × 9 = 27.

  6. A number divided by 4 gives 6. Write and solve the equation. / किसी संख्या को 4 से भाग करने पर 6 मिलता है. समीकरण बनाइए और हल कीजिए।
    Show answer

    Let x be the number. x ÷ 4 = 6. Multiply both sides by 4: x = 24. Check: 24 ÷ 4 = 6. / मान लीजिए संख्या x है. x ÷ 4 = 6. दोनों पक्षों को 4 से गुणा करें: x = 24. जाँच: 24 ÷ 4 = 6.

  7. Rani has x rupees. After spending 12 rupees she has 38 rupees left. Find x. / रानी के पास x रुपये हैं. 12 रुपये खर्च करने के बाद उसके पास 38 रुपये बचे हैं. x खोजिए।
    Show answer

    Equation: x − 12 = 38. So x = 38 + 12 = 50. Check: 50 − 12 = 38. / समीकरण: x − 12 = 38. इसलिए x = 38 + 12 = 50. जाँच: 50 − 12 = 38.

  8. Solve: 3x + 2 = x + 10 / हल कीजिए: 3x + 2 = x + 10
    Show answer

    Subtract x: 2x + 2 = 10. Subtract 2: 2x = 8. Divide by 2: x = 4. Check: 3×4 + 2 = 12 + 2 = 14 and x + 10 = 4 + 10 = 14. / x घटाइए: 2x + 2 = 10. 2 घटाइए: 2x = 8. 2 से भाग करें: x = 4. जाँच: 3×4 + 2 = 14 तथा 4 + 10 = 14.

  9. A number plus its double is 48. Find the number. / एक संख्या और उसके तीन गुना का योग 48 है. वह संख्या ज्ञात कीजिए।
    Show answer

    Let the number be x. Then x + 3x = 48 → 4x = 48 → x = 12. Check: 12 + 36 = 48. / मान लें संख्या x है. x + 3x = 48 → 4x = 48 → x = 12. जाँच: 12 + 36 = 48.

  10. Solve and check: x/3 + 4 = 9 / हल कीजिए और जाँच कीजिए: x/3 + 4 = 9
    Show answer

    Subtract 4: x/3 = 5. Multiply by 3: x = 15. Check: 15/3 + 4 = 5 + 4 = 9. / 4 घटाइए: x/3 = 5. 3 से गुणा करें: x = 15. जाँच: 15/3 + 4 = 9.

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