Overview
This chapter introduces the basic ideas of probability for Class 9 students. It explains random experiments, outcomes, sample space and events, and gives the classical (equally likely) definition of probability: P(E) = number of favourable outcomes / total number of outcomes. The chapter stresses understanding through simple examples and activities — tossing coins, rolling dice, and drawing balls from a bag — and contrasts experimental (empirical) results with theoretical calculation. Learning probability builds logical thinking, helps in decision making under uncertainty, and lays the foundation for more advanced topics in statistics and probability.
Learning Objectives
- Define probability and related terms: trial, outcome, sample space and event.
- Explain the difference between theoretical (classical) and experimental (empirical) probability.
- State and apply the formula P(E) = number of favourable outcomes / total number of equally likely outcomes to compute probabilities.
- Determine the sample space for single and combined random experiments (e.g., coin tosses, dice rolls, drawing a card).
- Calculate probabilities of simple events in standard contexts: single coin tosses, single die rolls and single-card draws.
- Compute experimental probability from observed frequencies and compare it with theoretical probability.
- Apply the complement rule to find P(E') = 1 − P(E) and solve related problems.
- Apply the addition rule for mutually exclusive events to find P(A ∪ B) when A and B cannot occur together.
Topics in this chapter
12 topics · tap a topic title to jump straight to it.
Introduction to Probability
What is Probability? Probability measures how likely an event is to happen. It is a number between 0 and 1 (inclusive), where 0 means the event cannot happen and 1 means it is certain.
Basic terms
- Experiment: Any process with observable outcomes (e.g., toss a coin, roll a die).
- Sample space (S): The set of all possible outcomes of an experiment (e.g., for a die S = {1,2,3,4,5,6}).
- Event (E): Any subset of the sample space (e.g., "getting an even number" = {2,4,6}).
- Equally likely outcomes: Outcomes having the same chance (common assumption for fair coin, fair die, shuffled deck approximations).
Theoretical (classical) probability
If all outcomes are equally likely, the probability of an event E is given by:
P(E) = number of favourable outcomes (n(E)) / total number of outcomes (n(S)).
Experimental (empirical) probability
Based on observed frequency in repeated trials. If an event E occurs f times in N trials, experimental probability ≈ f / N. As N grows large, experimental probability tends to theoretical probability (law of large numbers idea).
Important properties
- 0 ≤ P(E) ≤ 1 for any event E.
- P(S) = 1 and P(∅) = 0 (S = certain event, ∅ = impossible event).
- Complement rule: For event E, its complement E' (event E does not occur) satisfies P(E') = 1 − P(E).
- If A and B are mutually exclusive (cannot happen together), P(A ∪ B) = P(A) + P(B).
How to find probability — simple steps
- Describe the experiment and list the sample space S.
- Identify the favourable outcomes for event E and count n(E).
- Count total outcomes n(S) (assuming equally likely outcomes).
- Compute P(E) = n(E)/n(S) and simplify if needed.
Short solved examples (classical)
- Coin toss: S = {H, T}. Probability of getting a head = 1/2.
- Die roll: S = {1,2,3,4,5,6}. Probability of getting an even number = n(E)=3 → P = 3/6 = 1/2.
- Bag of 5 balls (2 red, 3 blue): If one ball is drawn at random, P(red) = 2/5.
Relation between theoretical and experimental
Use experimental probability when theoretical calculation is hard or to check theory: repeat the experiment many times, record relative frequency, and compare.
Why this matters (real-life uses)
Probability is used in weather forecasting (chance of rain), games of chance, risk assessment (insurance, finance), quality control, and many decisions under uncertainty.
- Tossing a fair coin once. Sample space S = {H, T}. Probability of head P(H) = 1/2.
- Rolling a fair six-sided die. Probability of getting 4 is 1/6. Probability of an odd number (1,3,5) is 3/6 = 1/2.
- Drawing one ball from a bag containing 3 red and 2 green balls. P(red) = 3/5.
- Randomly picking a card from a well-shuffled standard deck (52 cards). Probability of drawing a king = 4/52 = 1/13.
- Experimental example: Toss a coin 100 times and get 56 heads. Experimental probability of head ≈ 56/100 = 0.56 (compare with theoretical 0.5).
- Weather example: If historical data show it rained on 30 of the last 100 days in a month, an empirical chance of rain on a similar day ≈ 30/100 = 0.30.
- P(E) = n(E) / n(S) (classical probability when outcomes are equally likely)
- 0 ≤ P(E) ≤ 1
- P(S) = 1, P(∅) = 0
- Complement rule: P(E') = 1 − P(E)
- If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
- Experimental probability: P(E) ≈ frequency of E / total trials (f / N)
Random Experiment and Outcome
Random experiment is a process or activity which can be repeated under the same conditions and has one or more possible results, but the exact result cannot be predicted with certainty in advance. Examples: tossing a coin, rolling a die, drawing a card from a shuffled pack.
Outcome (or elementary event) is a single possible result of a random experiment. Each outcome is usually denoted by a symbol such as ω (omega). The sample space S is the set of all possible outcomes of the experiment. For a coin toss S = {Heads, Tails}; for a single die roll S = {1,2,3,4,5,6}.
Key properties: (1) Every outcome of the experiment is an element of S. (2) Outcomes are mutually exclusive: in one trial only one outcome occurs. (3) The sample space is exhaustive: it contains every outcome that can occur.
An event is any subset of the sample space (one or more outcomes). For example, in a die roll, the event “even number” is E = {2,4,6}. When all outcomes are equally likely, probability of an event can be computed by counting outcomes.
Notation summary: S = sample space, ω ∈ S denotes an outcome, E ⊆ S denotes an event, n(S) = number of elements (outcomes) in S, n(E) = number of favorable outcomes for event E.
- Tossing a fair coin once: possible outcomes S = {H, T}. Each trial yields one outcome (H or T).
- Rolling a fair six-faced die: outcomes S = {1,2,3,4,5,6}. The outcome is the face value that appears.
- Drawing one card from a well-shuffled standard deck: outcomes are the 52 different cards (e.g. Ace of Spades).
- Selecting one student at random from a class: outcomes are the names (or IDs) of all students present.
- Spin a 4-section spinner labelled {A, B, C, D}: outcomes S = {A, B, C, D}.
- S = {ω1, ω2, ..., ωn} (sample space listing all outcomes)
- If outcomes are equally likely: P(E) = n(E) / n(S), where n(E) is number of favorable outcomes and n(S) total outcomes.
- Probability of each elementary outcome (if equally likely) = 1 / n(S).
- Sum of probabilities of all mutually exclusive elementary outcomes = 1, i.e. Σ P(ωi) = 1.
Sample Space (S)
Definition: A sample space (denoted by S or Ω) of a random experiment is the set of all possible outcomes of that experiment. Each element of S is called an outcome or a sample point.
Notation and examples: If you toss a coin once, S = {Heads, Tails}. If you roll a fair six-sided die once, S = {1, 2, 3, 4, 5, 6}.
Types of sample spaces:
- Finite sample space: has a finite number of outcomes (e.g. a die: 6 outcomes).
- Countably infinite sample space: outcomes can be listed in sequence (e.g. toss a coin until first Head: outcomes = {H, TH, TTH, TTTH, ...}).
- Uncountably infinite (continuous) sample space: outcomes form a continuum (e.g. the exact time in seconds when a bus arrives on an interval [0,60]).
How to represent S: S can be listed as a set (curly braces), described by a rule (set-builder notation), or shown with a tree diagram for sequential experiments. For combined experiments, use the Cartesian product: if experiment A has outcomes S1 and experiment B has outcomes S2, then S = S1 × S2 (list of ordered pairs).
Why S matters: Probability of any event is defined relative to the sample space. For equally likely outcomes, P(event E) = number of favourable outcomes / total number of outcomes = n(E) / n(S).
- Toss a coin once: S = {H, T}.
- Roll a die once: S = {1,2,3,4,5,6}.
- Toss two coins: S = {HH, HT, TH, TT} (order matters if coins are distinguished).
- Roll two dice: S = {(1,1),(1,2),...,(6,6)} — 36 outcomes (6×6).
- Pick a card from a standard 52-card deck: S = {all 52 distinct cards}.
- Measure the lifetime of a bulb (continuous): S = {t | t ≥ 0} (uncountably many outcomes).
- P(E) = n(E) / n(S) (for equally likely outcomes)
- Number of outcomes for n independent binary trials (coin tosses) = 2^n
- Number of outcomes for n independent fair six-sided dice = 6^n
- If S1 and S2 are sample spaces for two independent experiments, combined sample space S = S1 × S2 and n(S) = n(S1) × n(S2)
- For finite S: n(S) = total number of distinct outcomes listed in S
Events
What is an event? An event is any collection (set) of one or more outcomes of a random experiment. If S is the sample space (set of all possible outcomes), then an event E is a subset of S: E ⊆ S. A single outcome is called a simple (or elementary) event; a set of outcomes is called a compound event.
Common types of events
- Certain event: E = S. It always occurs and P(E) = 1.
- Impossible event: E = Ø. It never occurs and P(E) = 0.
- Complementary event: For event E, the complement E' (or Ec) contains all outcomes in S that are not in E. E and E' are mutually exclusive and exhaustive, and P(E) + P(E') = 1.
- Mutually exclusive (disjoint) events: Two events A and B are mutually exclusive if they cannot occur together, i.e., A ∩ B = Ø. For such events P(A ∪ B) = P(A) + P(B).
- Exhaustive events: A collection of events is exhaustive if their union equals the sample space S (one of them must occur).
Probability of an event (for equally likely outcomes): If n(S) denotes the number of outcomes in the sample space and n(E) the number of favourable outcomes for event E, then
P(E) = n(E) / n(S)
This probability always satisfies 0 ≤ P(E) ≤ 1.
Basic probability rules:
- P(E') = 1 − P(E).
- For any two events A and B: P(A ∪ B) = P(A) + P(B) − P(A ∩ B). If A and B are mutually exclusive, P(A ∩ B) = 0, so P(A ∪ B) = P(A) + P(B).
Events are represented using set notation and often pictured with Venn diagrams to show intersections, unions and complements. Understanding events helps translate everyday uncertain situations (like tossing a coin, rolling a die, drawing a card) into calculable probabilities.
- Tossing a fair coin: S = {H, T}. Event E = 'get a head' = {H}. P(E) = 1/2.
- Rolling a fair die: S = {1,2,3,4,5,6}. Event A = 'roll an even number' = {2,4,6}, so P(A) = 3/6 = 1/2.
- Drawing a card from a well-shuffled 52-card deck: Event B = 'draw a spade' has n(B)=13, so P(B)=13/52 = 1/4.
- Weather example (everyday event): If long-term data show rain on 30 out of 100 similar days, event R = 'it rains' has empirical probability P(R) ≈ 30/100 = 0.3.
- Mutually exclusive example: When rolling a die, events 'roll a 2' and 'roll a 5' are mutually exclusive. P(2 or 5) = P(2) + P(5) = 1/6 + 1/6 = 1/3.
- P(E) = n(E) / n(S) (for equally likely outcomes)
- 0 ≤ P(E) ≤ 1
- P(E') = 1 − P(E) (complement rule)
- P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
- If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
Equally Likely Outcomes
Definition: When all outcomes of an experiment have the same chance of occurring, they are called equally likely outcomes. The probability of an event is then computed by counting outcomes.
Sample space and outcomes: Let S be the sample space (set of all possible outcomes). If every outcome in S is equally likely, and E is an event (a subset of S), then the probability of E is
P(E) = n(E) / n(S)
where n(E) is the number of outcomes favorable to E and n(S) is the total number of outcomes.
When this applies (classical probability):
- Experiments with symmetry: fair coin, fair die, well-shuffled deck of cards, spinner divided into equal sectors.
- Discrete finite sample spaces where you can list or count outcomes and each outcome is equally likely.
Useful consequences and simple rules:
- Complement rule: P(E') = 1 − P(E).
- If A and B are mutually exclusive events, P(A ∪ B) = P(A) + P(B). (Compute each using counts.)
- For independent experiments with equally likely outcomes (e.g., two fair coin tosses), the sample space size is the product of sizes of individual sample spaces.
Limitations: Not all experiments have equally likely outcomes. If outcomes have different probabilities (biased coin, nonuniform spinner, different-sized balls), you cannot use the simple count formula.
Connection to frequency interpretation: If you repeat an experiment many times, the relative frequency of an event (number of times E occurs divided by total trials) tends to approach the theoretical probability when outcomes are equally likely (law of large numbers).
- Toss a fair coin: S = {H, T}, n(S)=2. Probability of Head: P(H)=1/2.
- Roll a fair six-sided die: S = {1,2,3,4,5,6}, n(S)=6. P(4)=1/6. P(even)= {2,4,6} ⇒ 3/6 = 1/2.
- Draw one card from a well-shuffled standard deck (52 cards): Event E = 'draw a king'. n(E)=4, n(S)=52 ⇒ P(E)=4/52=1/13.
- Spinner divided into 8 equal sectors: probability of landing on any given sector = 1/8.
- Two fair coin tosses: S = {HH, HT, TH, TT}, n(S)=4. Event 'exactly one head' = {HT, TH} ⇒ P = 2/4 = 1/2.
- Urn with 3 red and 3 blue identical balls (draw one at random): n(S)=6, P(red)=3/6 = 1/2 (equally likely because balls are identical in selection).
- Classical probability for equally likely outcomes: P(E) = n(E) / n(S)
- Complement rule: P(E') = 1 − P(E)
- Mutually exclusive events: P(A ∪ B) = P(A) + P(B) (use counts if equally likely)
- Independent repeated experiments: n(S_total) = n(S1) × n(S2) × ... and P(of an outcome) = product of individual probabilities
- Relative frequency (empirical probability) ≈ number of occurrences of E / total trials (approaches theoretical probability as trials ↑)
Classical (Theoretical) Definition of Probability
Definition. If an experiment has a finite number of equally likely outcomes, the probability of an event E is defined as:
P(E) = number of favourable outcomes for E / total number of possible outcomes
Symbolically, if S is the sample space and n(A) denotes the number of elements in a set A, then
P(E) = n(E) / n(S)
Conditions for use:
- The sample space S must be finite.
- All outcomes in S must be equally likely.
How to apply (steps):
- Describe the sample space S and count n(S).
- Describe the event E and count n(E) (favourable outcomes).
- Compute P(E) = n(E)/n(S) and, if needed, simplify the fraction.
Basic properties (derived from the definition):
- 0 ≤ P(E) ≤ 1 for any event E.
- P(S) = 1 and P(∅) = 0.
- If E' is the complement of E, then P(E') = 1 − P(E).
- If A and B are mutually exclusive (disjoint), P(A ∪ B) = P(A) + P(B).
- In general, P(A ∪ B) = P(A) + P(B) − P(A ∩ B).
When classical definition is not appropriate: If outcomes are not equally likely or the sample space is infinite, the classical formula n(E)/n(S) does not apply directly; a different (empirical or axiomatic) approach is used.
- Toss a fair coin once. S = {H, T}, n(S)=2. Event E = {getting a Head}. n(E)=1. P(E)=1/2.
- Roll a fair six-faced die. S={1,2,3,4,5,6}, n(S)=6. Event E = {even number}={2,4,6}, n(E)=3. P(E)=3/6=1/2.
- A bag contains 3 red and 2 blue identical-looking marbles. Pick one at random. S has 5 equally likely outcomes (each marble). Event E = {red}. n(E)=3. P(E)=3/5.
- Pick one card from a well-shuffled standard 52-card deck. Event E = {a king}. n(E)=4. P(E)=4/52=1/13.
- Choose a random day of the week. Event E = {weekend}. S has 7 days, n(E)=2. P(E)=2/7.
- P(E) = n(E) / n(S)
- 0 ≤ P(E) ≤ 1
- P(S) = 1, P(∅) = 0
- P(E') = 1 − P(E) (complement rule)
- If A and B are mutually exclusive: P(A ∪ B) = P(A) + P(B)
- General addition rule: P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Basic Properties of Probability
Probability measures how likely an event is to occur. For any random experiment, we define a sample space S (set of all possible outcomes) and an event A (a subset of S). The probability P(A) is a number between 0 and 1 that quantifies the chance of A happening.
Key basic properties:
- Range: 0 ≤ P(A) ≤ 1 for any event A. If P(A)=0 the event is impossible; if P(A)=1 the event is certain.
- Probability of the sample space: P(S) = 1, because something in S must occur.
- Probability of the empty set: P(∅) = 0.
- Complement rule: For the complement A' (events in S but not in A), P(A) + P(A') = 1. So P(A') = 1 − P(A).
- Addition rule (general): For any two events A and B, P(A ∪ B) = P(A) + P(B) − P(A ∩ B). This avoids double counting outcomes in both A and B.
- Mutually exclusive (disjoint) events: If A and B cannot happen together (A ∩ B = ∅), then P(A ∪ B) = P(A) + P(B).
- Monotonicity: If A ⊆ B then P(A) ≤ P(B).
These properties follow from the axioms of probability and are used to compute and reason about probabilities in simple experiments (coin tosses, dice rolls, card draws) and in real-life situations (reliability, weather forecasts, risk assessment).
- Coin toss: S = {H, T}. P(H) = 1/2, P(T) = 1/2. Range: 0 ≤ P(H) ≤ 1 and P(H) + P(H') = 1 (1/2 + 1/2 = 1).
- Single die roll: S = {1,2,3,4,5,6}. Event A = {even} = {2,4,6}, so P(A) = 3/6 = 1/2. Complement A' = {odd}, P(A') = 1/2 and P(A)+P(A')=1.
- Deck of cards: Event B = {draw an Ace} has P(B) = 4/52 = 1/13. Complement rule: P(not Ace) = 1 − 1/13 = 12/13.
- Mutually exclusive example: Draw a card, A = {King}, C = {Ace}. Since A ∩ C = ∅, P(A or C) = P(A) + P(C) = 4/52 + 4/52 = 8/52 = 2/13.
- General addition example: From a die, let D = {2,4,6} (even) and E = {4,5,6}. P(D)=1/2, P(E)=1/2. Intersection D∩E={4,6} so P(D∩E)=2/6=1/3. Then P(D∪E)=1/2+1/2−1/3=2/3.
- Real-life empirical example: Flip a fair coin 100 times. If heads appear 48 times, empirical P(H) ≈ 48/100 = 0.48 (close to theoretical 0.5).
- 0 ≤ P(A) ≤ 1
- P(S) = 1
- P(∅) = 0
- P(A') = 1 − P(A) (complement)
- P(A ∪ B) = P(A) + P(B) − P(A ∩ B) (general addition rule)
- If A and B are mutually exclusive (A ∩ B = ∅): P(A ∪ B) = P(A) + P(B)
Complementary Events
Definition: Two events A and A' (read “A complement” or “not A”) are complementary if exactly one of them occurs for every outcome in the sample space S. That is, A and A' are mutually exclusive and together exhaustive: A ∩ A' = Ø and A ∪ A' = S.
Notation: A', A^c, or Ā denotes the complement of A (the event “A does not occur”).
Key property (probability): Since A and A' are exhaustive and mutually exclusive, their probabilities add to 1:
- P(A) + P(A') = 1
- so P(A') = 1 − P(A)
Why this holds (intuitive): The probability of something happening (A) plus the probability of it not happening (A') must account for every possibility in S, so the sum is the total probability 1.
When to use: Often it is easier to find P(A') and then get P(A) as 1 − P(A'), especially when A' has fewer or simpler outcomes.
Simple example (die): Let A = “roll an even number” on a fair six-sided die. Outcomes for A: {2,4,6} so P(A) = 3/6 = 1/2. Then P(A') = 1 − 1/2 = 1/2 (A' = {1,3,5}).
- Coin toss: A = 'get Heads'. P(A) = 1/2, so P(A') = 1 − 1/2 = 1/2 (A' = 'get Tails').
- Dice: A = 'roll a 6'. P(A) = 1/6, so P(A') = 1 − 1/6 = 5/6 (A' = 'roll 1,2,3,4 or 5').
- Card: A = 'draw an Ace' from a standard 52-card deck. P(A) = 4/52 = 1/13, so P(A') = 12/13.
- Weather: If P(rain tomorrow) = 0.3, then P(no rain tomorrow) = 1 − 0.3 = 0.7.
- Exam: If probability that a student passes = 0.85, probability that they fail = 0.15 (complement).
- P(A) + P(A') = 1
- P(A') = 1 − P(A)
- P(A ∩ A') = 0 (mutually exclusive)
- P(A ∪ A') = 1 (exhaustive)
- Notation: A' or A^c denotes complement of A
Experimental (Empirical) Probability
What is Experimental (Empirical) Probability?
Experimental probability (also called empirical or relative-frequency probability) is the probability of an event estimated from the results of an experiment or observation. It is found by performing the experiment a number of times, counting how often the event occurs, and dividing by the total number of trials.
Definition and formula
If an event E occurs n(E) times in N repeated trials, the experimental probability of E is
Pexp(E) = n(E) / N
Key ideas
- Experimental probability is based on actual data (observed frequency), not on theoretical reasoning about equally likely outcomes.
- Relative frequency = number of favourable outcomes observed ÷ total trials.
- As the number of trials increases, the experimental probability tends to approach the theoretical probability (Law of Large Numbers).
- Limitations: results depend on the number of trials and how the experiment is conducted (sampling bias, measurement errors).
How to do an experiment
- Define the event E clearly (e.g., getting a head when tossing a coin).
- Decide number of trials N and perform the experiment N times.
- Count n(E) = number of times E occurred.
- Compute Pexp(E) = n(E)/N. Optionally convert to decimal or percent.
- Compare with theoretical probability (if known) and comment on differences due to randomness and sample size.
Law of Large Numbers (informal)
When an experiment is repeated many times, the experimental probability of an event tends to get closer to its theoretical probability. Small samples can show large fluctuations; larger samples give more stable estimates.
- Toss a coin 100 times. If heads appears 56 times, experimental probability of head = 56/100 = 0.56 (56%). Compare with theoretical probability 1/2 = 0.5.
- Roll a fair die 120 times. If the face '4' appears 18 times, experimental probability of getting 4 = 18/120 = 0.15. Theoretical probability = 1/6 ≈ 0.1667.
- Survey 200 students asking whether they prefer Football. If 82 say 'Yes', experimental probability a randomly chosen student prefers Football = 82/200 = 0.41.
- Inspect 500 bulbs from a factory; 12 are defective. Experimental probability a randomly chosen bulb is defective = 12/500 = 0.024 (2.4%). Useful for quality control.
- Experimental probability: P_exp(E) = n(E) / N (n(E) = number of times event E occurred; N = total trials)
- Relative frequency (percentage): % = (n(E) / N) × 100
- Complement (experimental): P_exp(E') = 1 − P_exp(E) (when E' is the complement of E)
- For mutually exclusive events A and B (from experiment): P_exp(A ∪ B) = P_exp(A) + P_exp(B) (if A and B cannot occur together in one trial)
Counting Outcomes and Listing Techniques
What is being counted? In probability we count the possible outcomes of a random experiment. The set of all possible outcomes is called the sample space (denoted S). An event is a subset of S. If all outcomes in S are equally likely, probability of an event E is P(E) = n(E) / n(S), where n(X) denotes the number of elements of set X.
Why list outcomes? Listing outcomes helps ensure you have found the complete sample space and that no outcome is counted twice. For small experiments it gives a direct way to compute probabilities by counting.
Common listing techniques
- Complete listing (enumeration): Write every outcome explicitly (useful when S is small).
- Tree diagram: Draw branches for sequential choices. Each path from root to leaf represents one outcome. Count leaves to get n(S).
- Tabular (matrix) method: Use a table/grid for two-step experiments (e.g. two dice → 6×6 grid = 36 outcomes).
- Systematic listing: Use a fixed order (alphabetical or numeric) to avoid duplicates and omissions.
- Fundamental principle of counting (multiplication rule): If an experiment has stages with a choices in stage 1, b choices in stage 2, ..., then total outcomes = a × b × ... (when choices are independent and order matters). This replaces explicit listing when numbers are larger.
Important notes:
- Decide whether order matters (e.g., arrangement AB is different from BA) and whether repetition is allowed. These affect counting.
- Always check that listed outcomes are equally likely before using simple ratio formula for probability.
- Tossing two coins: List outcomes = {HH, HT, TH, TT}. n(S)=4. Probability of exactly one head = {HT, TH} so n(E)=2 → P=2/4=1/2.
- Rolling two dice: Use a 6×6 table or tree. n(S)=36. Probability that sum is 7: outcomes = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} → 6/36 = 1/6.
- Forming 2-letter arrangements from A,B,C without repetition: Use tree or systematic listing: AB, AC, BA, BC, CA, CB → n(S)=6. If repetition allowed (letters can repeat) n(S)=3×3=9 (AA, AB, AC, BA, …).
- Choosing an outfit: 3 shirts, 2 trousers, 2 pairs of shoes. By multiplication rule total outfits = 3 × 2 × 2 = 12. (E.g., list by shirts first, then trousers, then shoes.)
- Picking one card from a standard deck (if treated as equally likely): n(S)=52. Probability of a spade = 13/52 = 1/4.
- Sample space size: n(S) = number of possible outcomes.
- Probability (equally likely outcomes): P(E) = n(E) / n(S).
- Multiplication (fundamental) principle: If experiment has stages with a, b, c, ... choices then total outcomes = a × b × c × ...
- If order matters without repetition for k positions from n objects: n × (n-1) × (n-2) × ... (k factors).
- Addition for counts (mutually exclusive): n(A ∪ B) = n(A) + n(B). More generally: n(A ∪ B) = n(A) + n(B) − n(A ∩ B).
Standard Examples and Problem Types
What is Probability? Probability measures how likely an event is to occur. For a well-defined experiment with a sample space S (all possible equally likely outcomes) and an event E (a subset of S), the classical probability is P(E) = n(E) / n(S), where n(.) denotes number of outcomes.
Key ideas:
- Sample space (S): all possible outcomes of an experiment (e.g., for a fair die S = {1,2,3,4,5,6}).
- Equally likely outcomes: classical formula assumes outcomes have equal chance.
- Experimental (empirical) probability: found by repeating the experiment many times: P(E) ≈ (frequency of E)/(total trials).
- Complementary event: E' (not E). P(E') = 1 − P(E).
- Mutually exclusive events: A and B cannot happen together. Then P(A ∪ B) = P(A) + P(B).
Standard problem types you will meet in Class 9:
- Single simple event with equally likely outcomes (coin, die, spinner).
- Drawing objects from a bag — count favorable and total outcomes.
- Events using complements (e.g., “at least one” problems solved by 1 − P(none)).
- Combined events when outcomes are listed as ordered pairs (two tosses, two dice) — build sample space as Cartesian product.
- Experimental probability tasks — perform trials, record frequencies, compare with theoretical values.
- Mutually exclusive events and simple additions of probabilities.
Problem-solving steps (concise):
- Define the experiment and identify S.
- List/count n(S) and n(E) (favourable outcomes).
- Check if outcomes are equally likely; if yes, use P(E)=n(E)/n(S).
- Use complements or combinations if direct counting is hard.
- Give final answer as a fraction, decimal or percentage, simplified.
- Coin toss: What is probability of getting a head in one toss? S = {H, T}, n(S)=2, favourable n(E)=1 → P(H)=1/2.
- One die: Probability of getting an even number? S={1,2,3,4,5,6}, favourable={2,4,6} so P=3/6=1/2.
- Bag of balls: A bag has 3 red and 2 blue identical balls. One ball is drawn at random. P(red)=3/(3+2)=3/5.
- Two tosses: Probability of getting at least one head in two tosses. S={(H,H),(H,T),(T,H),(T,T)}, P(at least one H)=1−P(no H)=1−P(T,T)=1−1/4=3/4.
- Two dice: Probability that sum is 7 when two fair dice are rolled. Sample space has 36 ordered pairs. Favourable pairs for sum 7 = {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} =6 → P=6/36=1/6.
- Card from deck: Probability of drawing an Ace from a standard 52-card deck. n(E)=4, n(S)=52 → P=4/52=1/13.
- Classical probability: P(E) = n(E) / n(S), when outcomes are equally likely.
- Complement rule: P(E') = 1 − P(E).
- Addition rule for mutually exclusive events: P(A ∪ B) = P(A) + P(B) if A and B are mutually exclusive.
- For 'at least one' in repeated independent trials: P(at least one) = 1 − P(none).
- Experimental probability: P(E) ≈ (frequency of E) / (total number of trials).
- (Optional/advanced) Independent events multiplication: P(A ∩ B) = P(A) × P(B) if A and B are independent.
Problem-Solving Strategies
What the topic covers: Problem-solving strategies in probability teach systematic ways to model random experiments, count outcomes, and compute probabilities accurately using basic rules (equally likely outcomes, complement, addition for disjoint events, multiplication for sequential events).
Step-by-step strategy (use this checklist for each problem)
- 1. Read and identify the experiment. What is being done (tossing, drawing, rolling)? How many trials?
- 2. Define the sample space S. List all possible outcomes explicitly if small, or describe them (e.g., all ordered pairs for two dice).
- 3. Check the equally-likely assumption. If outcomes are equally likely, P(E)=n(E)/n(S). If not, consider weighting or empirical frequency.
- 4. Count favourable outcomes n(E). Use listing, symmetry, multiplication principle, combinations, or complementary counting to simplify.
- 5. Use rules to compute probability. Apply P(E)=n(E)/n(S), or use complement, addition or multiplication rules as appropriate.
- 6. Draw a diagram if needed. Tree diagrams for sequential experiments, Venn diagrams for unions/intersections, tables for two-dimensional sample spaces, area models for geometric probability.
- 7. Check the answer. Probabilities must be between 0 and 1; reasonableness check using symmetry or complementary probabilities often helps.
Common short-cuts and tips
- Use complement: When "at least one" or "not" problems are present, it is often easier to compute P(E') and subtract from 1.
- Exploit symmetry: Symmetric outcomes (e.g., fair coin or fair die) let you count one type then multiply by symmetry factor.
- Use tree diagrams: For sequential events (with or without replacement), trees show all ordered outcomes and probabilities clearly.
- Area/proportional models: For continuous or geometric problems, represent outcomes by areas; probability = shaded area / total area.
When to use which diagram
- Tree diagram — sequential experiments (ordered outcomes, dependent or independent draws).
- Venn diagram — events involving union/intersection/complement relationships.
- Matrix/table (grid) — two independent discrete variables (e.g., two dice).
- Area model — geometric probability (points chosen at random inside a region).
Following these organized steps prevents common mistakes (forgetting order, double-counting, or assuming equal likelihood incorrectly) and makes even non-trivial problems manageable.
- 1) Coin tossed twice. Find probability of at least one head. Solution: Sample space S = {HH, HT, TH, TT} (n(S)=4). Use complement: P(at least one head)=1-P(no head)=1-P(TT)=1-1/4=3/4.
- 2) One fair die rolled. Find probability of an even number. S={1,2,3,4,5,6}, favourable={2,4,6} so P=3/6=1/2.
- 3) Bag with 3 red, 5 blue, 2 green marbles. One marble drawn at random. Probability of blue = number of blue / total = 5/10 = 1/2.
- 4) Two draws without replacement from a bag with 3 red and 2 blue. Probability both are red. Count combinations: C(3,2)/C(5,2)=3/10. (Or sequential: (3/5)*(2/4)=6/20=3/10.)
- 5) Two fair dice thrown. Probability sum equals 7. Use 6x6 grid: favourable ordered pairs {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} so P=6/36=1/6.
- P(E) = n(E) / n(S) (for equally likely outcomes)
- P(E') = 1 - P(E) (complement rule)
- If A and B disjoint: P(A ∪ B) = P(A) + P(B)
- For independent sequential events A and B: P(A and B) = P(A) × P(B)
- Counting principle for ordered choices: if first can occur in m ways and second in n ways, total = m × n
Key Concepts
- Random experiment
- An action or process that leads to one of several possible outcomes, where the outcome cannot be predicted with certainty beforehand.
- Trial
- A single performance or repetition of a random experiment.
- Outcome (Sample point)
- A single possible result of a random experiment.
- Sample space
- The set of all possible outcomes of a random experiment, usually denoted by S.
- Elementary (Simple) event
- An event that consists of exactly one outcome (one sample point).
- Compound event
- An event that consists of two or more outcomes (a subset of the sample space with multiple points).
- Event
- Any collection (subset) of one or more outcomes from the sample space; it may be elementary or compound.
- Favorable outcomes
- Outcomes in the sample space that satisfy the condition described by an event.
- Equally likely outcomes
- Outcomes that have the same chance of occurring in a random experiment.
- Certain event
- An event that is sure to occur; it contains all outcomes of the sample space (probability 1).
- Impossible event
- An event that cannot occur; it contains no outcomes (probability 0).
- Complement of an event
- The set of all outcomes in the sample space that are not in the event; denoted A' or A^c.
- Mutually exclusive events
- Two events that cannot occur at the same time; their intersection is empty.
- Exhaustive events
- A collection of events whose union equals the entire sample space (they cover all possible outcomes).
- Classical (Theoretical) probability
- Probability defined as number of favorable equally likely outcomes divided by total number of equally likely outcomes.
- Empirical (Experimental) probability
- Probability estimated from actual experiments; equals frequency of the event divided by total trials.
- Relative frequency
- The ratio of the number of times an event occurs to the total number of trials; used to estimate empirical probability.
- Probability of an event (basic formula)
- For equally likely outcomes, P(event) = (number of favorable outcomes) / (total number of outcomes in S).
- Union of events (A or B)
- Event that either A occurs, or B occurs, or both; contains outcomes in A ∪ B.
- Intersection of events (A and B)
- Event that both A and B occur simultaneously; contains outcomes in A ∩ B.
End-of-Chapter Trial Paper & Test Questions
Topic-wise questions to test your understanding of every concept in this chapter.
-
The classical definition of probability of an event E is: / किसी घटना E की शास्त्रीय प्रायिकता की परिभाषा है: (a) Number of trials / Number of events / परीक्षणों की संख्या / घटनाओं की संख्या (b) Number of favourable outcomes / Total number of equally likely outcomes / अनुकूल परिणामों की संख्या / कुल समसंभाव्य परिणामों की संख्या (c) Total outcomes / Favourable outcomes / कुल परिणाम / अनुकूल परिणाम (d) 1 / Number of outcomes / 1 / परिणामों की संख्या
Show answer
(b) Number of favourable outcomes / Total number of equally likely outcomes / अनुकूल परिणामों की संख्या / कुल समसंभाव्य परिणामों की संख्या — P(E) = n(E)/n(S), where n(E) is the count of favourable outcomes and n(S) is the total count of outcomes in the sample space. / P(E) = n(E)/n(S), जहाँ n(E) अनुकूल परिणामों की संख्या और n(S) प्रतिदर्श समष्टि में कुल परिणामों की संख्या है।
-
A fair die is rolled once. What is the probability of getting an even number? / एक निष्पक्ष पासा एक बार फेंका जाता है। सम संख्या आने की प्रायिकता क्या है? (a) 1/6 (b) 1/3 (c) 1/2 (d) 2/3
Show answer
(c) 1/2 — Sample space S = {1,2,3,4,5,6}, n(S) = 6. Even numbers = {2,4,6}, n(E) = 3. P(E) = 3/6 = 1/2. / प्रतिदर्श समष्टि S = {1,2,3,4,5,6}, n(S) = 6। सम संख्याएँ = {2,4,6}, n(E) = 3। P(E) = 3/6 = 1/2।
-
A bag has 3 red and 5 blue identical balls. One ball is drawn at random. What is the probability of drawing a red ball? / एक थैले में 3 लाल और 5 नीली एकसमान गेंदें हैं। एक गेंद यादृच्छिक रूप से निकाली जाती है। लाल गेंद निकलने की प्रायिकता क्या है? (a) 3/5 (b) 5/8 (c) 3/8 (d) 1/3
Show answer
(c) 3/8 — Total balls = 3+5 = 8; favourable (red) = 3; P(red) = 3/8. / कुल गेंदें = 8; अनुकूल (लाल) = 3; P(लाल) = 3/8।
-
Fill in the blank: For any event E, P(E) + P(E') = _____, where E' is the complement of E. / रिक्त स्थान भरें: किसी भी घटना E के लिए, P(E) + P(E') = _____, जहाँ E', E का पूरक है।
Show answer
1 — The event and its complement are mutually exclusive and exhaustive, so their probabilities sum to 1. P(E') = 1 − P(E). / घटना और उसका पूरक परस्पर अपवर्जी और सम्पूर्ण हैं, इसलिए उनकी प्रायिकताओं का योग 1 होता है। P(E') = 1 − P(E)।
-
Fill in the blank: The set of all possible outcomes of a random experiment is called the _____. / रिक्त स्थान भरें: किसी यादृच्छिक प्रयोग के सभी संभावित परिणामों के समुच्चय को _____ कहते हैं।
Show answer
sample space (प्रतिदर्श समष्टि) — The sample space S lists every outcome that can occur in the experiment; events are subsets of S. / प्रतिदर्श समष्टि S में वे सभी परिणाम सूचीबद्ध होते हैं जो प्रयोग में घटित हो सकते हैं; घटनाएँ S के उपसमुच्चय होती हैं।
-
True or False: The probability of an impossible event is 1. / सत्य या असत्य: असंभव घटना की प्रायिकता 1 होती है।
Show answer
False / असत्य — The probability of an impossible event is 0 (it can never occur). The probability of a certain event is 1. / असंभव घटना की प्रायिकता 0 होती है (यह कभी नहीं घटती)। निश्चित घटना की प्रायिकता 1 होती है।
-
A coin is tossed twice. List the sample space and find the probability of getting exactly one head. / एक सिक्के को दो बार उछाला जाता है। प्रतिदर्श समष्टि की सूची बनाइए और ठीक एक चित आने की प्रायिकता ज्ञात कीजिए।
Show answer
Sample space S = {HH, HT, TH, TT}, n(S) = 4. / प्रतिदर्श समष्टि S = {HH, HT, TH, TT}, n(S) = 4। Favourable outcomes (exactly one head) = {HT, TH}, n(E) = 2. / अनुकूल परिणाम (ठीक एक चित) = {HT, TH}, n(E) = 2। P(E) = 2/4 = 1/2. / P(E) = 1/2।
-
A card is drawn at random from a well-shuffled deck of 52 cards. What is the probability of drawing a king? / 52 पत्तों की एक अच्छी तरह फेंटी गई ताश की गड्डी से एक पत्ता यादृच्छिक रूप से निकाला जाता है। बादशाह (किंग) निकलने की प्रायिकता क्या है?
Show answer
There are 4 kings in a deck of 52 cards. / 52 पत्तों की गड्डी में 4 बादशाह होते हैं। P(king) = n(E)/n(S) = 4/52 = 1/13. / P(बादशाह) = 4/52 = 1/13।
Related Laws & Principles
Explore allFoundational laws & principles behind this chapter. Each one opens a full page — what it says, why it matters, five practice questions and the mistakes to avoid.