Overview
This chapter from Mathematics – VII (Class 7) introduces perimeter and area as fundamental measures of plane figures. It explains what perimeter and area mean, why units matter, and gives clear, practical formulas and methods for common shapes (squares, rectangles, parallelograms and triangles) and composite figures. The chapter is important because it builds essential measurement skills used in everyday tasks (fencing, flooring, gardening, land measurement) and forms the basis for later mensuration topics (surface area and volume). Students learn to apply and derive formulas, convert between units of area, decompose complex shapes, solve word problems, and use reasoning (for example, areas of triangles on the same base and between the same parallels) to compare areas and check answers.
Learning Objectives
- Define perimeter and area and state their standard unit measures and relations (linear vs square units)
- Explain the difference between perimeter and area with examples of plane figures
- Derive and state the formulae for the perimeter and area of a rectangle and a square
- Apply formulae to calculate the perimeter and area of rectangles and squares in numerical problems
- Calculate the area of a parallelogram and a triangle using base and corresponding height
- Solve problems to find one dimension (side, base, or height) of a rectangle, square, parallelogram, or triangle when area or perimeter is given
- Convert between common area units (cm², m², mm²) and apply conversions in calculations
- Estimate area and perimeter of simple figures using unit squares and compare with calculated values
Topics in this chapter
10 topics · tap a topic title to jump straight to it.
Perimeter (Basic)
Perimeter (Basic)
Key Point: Perimeter of square = 4 × side (P = 4s)
What is Perimeter?
The perimeter of a plane figure is the total length of its boundary. In simple terms, it is the distance around a shape. Perimeter is a linear measure and is expressed in units such as mm, cm, m or km.
How to find perimeter
- For polygons (shapes with straight sides): add the lengths of all the sides.
- For regular polygons (all sides equal): multiply the length of one side by the number of sides.
- For curved shapes like a circle, the perimeter is called the circumference and uses π (pi).
Important points
- All side lengths must be in the same unit before adding.
- Perimeter gives only the boundary length, not the area inside the shape.
- Composite figures: break the boundary into simple parts, find each part's length and add.
- Rectangle: A rectangle has length 12 m and breadth 8 m. Perimeter = 2 × (length + breadth) = 2 × (12 + 8) = 2 × 20 = 40 m.
- Square: A square has side 5 cm. Perimeter = 4 × side = 4 × 5 = 20 cm.
- Triangle: A triangle has sides 7 cm, 5 cm and 6 cm. Perimeter = 7 + 5 + 6 = 18 cm.
- Circle (circumference): A circle has radius 14 cm. Circumference = 2πr. Using π = 22/7: Circumference = 2 × (22/7) × 14 = 88 cm.
- Regular polygon: A regular pentagon with each side 6 cm. Perimeter = number of sides × side = 5 × 6 = 30 cm.
- Composite figure: A rectangle 10 m by 6 m has a semicircle of radius 3 m attached along one 6 m side. Perimeter = remaining three sides of rectangle (10 + 6 + 10) + curved part (semicircle circumference) = 26 + (πr + 2r) where semicircle boundary = πr + diameter. With r = 3 and π ≈ 3.14: semicircle boundary ≈ 3.14×3 + 6 ≈ 9.42 + 6 = 15.42. Total ≈ 26 + 15.42 = 41.42 m.
- \[Perimeter of square = 4 × side (P = 4s)\]
- \[Perimeter of rectangle = 2 × (length + breadth) (P = 2(l + b))\]
- \[Perimeter of triangle = sum of its three sides (P = a + b + c)\]
- \[Perimeter of regular polygon = number of sides × side length (P = n × s)\]
- \[Perimeter of parallelogram = 2 × (adjacent sides sum) (P = 2(a + b))\]
- \[Circumference of circle = 2πr = πd (use π ≈ 22/7 or 3.14)\]
Perimeter of Common Shapes
Perimeter of Common Shapes
Key Point: Square: P = 4a (a = side length)
What is Perimeter?
Perimeter is the total length around a two‑dimensional shape. It is found by adding the lengths of all the sides. Perimeter is measured in units of length (mm, cm, m, km).
General method
1. Identify all the boundary segments (sides or curved edges).
2. Measure or note their lengths in the same unit.
3. Add the lengths. If the shape is regular or has a formula, use the appropriate formula.
Why it matters (real life)
Perimeter is used when you want to put a fence around a garden, frame a picture, lay the edge strip on a table, or know how much ribbon is needed to go around a gift box. For circular objects (wheels, tracks) perimeter is called circumference.
Key tips for students
- Always check that all lengths are in the same unit before adding.
- For shapes made of several simple shapes (composite shapes), add the boundary parts that form the outer edge only.
- For curved edges (circles), use the circumference formula with π (pi ≈ 22/7 or 3.14).
Common shapes covered
- Square — all four sides equal
- Rectangle — opposite sides equal
- Triangle — sum of its three sides (special case: equilateral)
- Parallelogram — opposite sides equal
- Rhombus — all four sides equal (like a slanted square)
- Trapezium (trapezoid) — sum of four sides
- Circle — circumference (curved perimeter)
Worked approach (example idea)
To find the perimeter of a rectangular garden with length 12 m and breadth 8 m: add all sides or use P = 2(l + b) = 2(12 + 8) = 40 m. That is the length of fencing needed.
Note: Perimeter is different from area. Perimeter measures boundary length; area measures the surface covered.
- Rectangle: Find the perimeter of a rectangle with length 15 m and breadth 7 m. Solution: P = 2(l + b) = 2(15 + 7) = 2 × 22 = 44 m.
- Square: One side of a square is 6 cm. Find its perimeter. Solution: P = 4 × side = 4 × 6 = 24 cm.
- Triangle: A triangle has sides 8 cm, 6 cm and 7 cm. Find its perimeter. Solution: P = 8 + 6 + 7 = 21 cm.
- Circle (circumference): A circular track has radius 14 m. Find its circumference. Solution: C = 2πr = 2 × π × 14. Using π = 22/7, C = 2 × (22/7) × 14 = 88 m.
- Composite shape: A shape made by joining two rectangles along one side: rectangle A (10 m × 4 m) and rectangle B (6 m × 4 m) share the 4 m side. Perimeter = outer boundary = 10 + 4 + 6 + 4 + 10? (draw to check). Method: trace only the outer edges and add their lengths; here P = 2 × (10 + 4) + 2 × 6 − shared edges counted once → easier: draw and add outer segments carefully.
- \[Square: P = 4a (a = side length)\]
- \[Rectangle: P = 2(l + b) (l = length\]\[b = breadth/width)\]
- \[Triangle: P = a + b + c (a\]\[b\]\[c are the three sides)\]\[Equilateral triangle: P = 3a\]
- \[Parallelogram: P = 2(a + b) (a and b are adjacent sides)\]
- \[Rhombus: P = 4a (a = side length)\]
- \[Trapezium (trapezoid): P = a + b + c + d (sum of all four sides)\]
Area (Concept)
Area (Concept)
Key Point: Area of rectangle = length × breadth (A = l × b)
What is area? Area is the measure of the surface enclosed by a plane figure. In simple terms, area tells us how much two-dimensional space a shape covers.
Square unit and counting method: We measure area using square units (square centimetres cm², square metres m², etc.). Imagine covering a shape exactly with non-overlapping unit squares (1 cm by 1 cm, or 1 m by 1 m). The number of these unit squares that fit inside the shape gives its area.
Key ideas:
- Area is additive: the area of a region made of non-overlapping parts equals the sum of the areas of the parts.
- Perimeter vs Area: perimeter measures the length around a shape (one-dimensional); area measures the surface covered (two-dimensional).
- Orientation does not change area: you can rotate or shear a shape (without changing base or height appropriately) and its area remains the same.
How formulas arise (intuitions):
- Rectangle: If a rectangle has length l and breadth b, it can be filled by l rows of b unit squares → area = l × b.
- Square: A square is a special rectangle with all sides equal (side = a) → area = a².
- Parallelogram: By cutting a triangular piece and moving it, a parallelogram of base b and height h can be rearranged to a rectangle of same base and height → area = b × h.
- Triangle: Two congruent triangles placed together along corresponding heights form a parallelogram. So area of a triangle with base b and height h is half that of the parallelogram → area = (1/2) × b × h.
Working with irregular and composite shapes: Break the shape into rectangles, triangles, and other shapes with known formulas, find each area and add or subtract as needed.
Units and conversions: Always express area with the square of a length unit and convert carefully: e.g. 1 m = 100 cm so 1 m² = (100 cm)² = 10,000 cm². Common conversions: 1 km² = 1,000,000 m²; 1 ha (hectare) = 10,000 m².
- Rectangle: A garden is 12 m long and 8 m wide. Area = length × breadth = 12 × 8 = 96 m².
- Square: A tile is a square of side 0.5 m. Area = side² = 0.5 × 0.5 = 0.25 m².
- Triangle: A triangular flag has base 10 cm and height 6 cm. Area = (1/2) × base × height = (1/2) × 10 × 6 = 30 cm².
- Parallelogram: A parallelogram has base 8 cm and corresponding height 5 cm. Area = base × height = 8 × 5 = 40 cm².
- Composite shape: An L-shaped floor can be split into two rectangles: one 6 m × 4 m and another 3 m × 2 m. Total area = (6×4) + (3×2) = 24 + 6 = 30 m².
- \[Area of rectangle = length × breadth (A = l × b)\]
- \[Area of square = side² (A = a²)\]
- \[Area of parallelogram = base × height (A = b × h)\]
- \[Area of triangle = (1/2) × base × height (A = 1/2 × b × h)\]
- \[Area of composite figure = sum (or difference) of areas of component figures\]
- \[Unit conversions: 1 m² = 10,000 cm²\]\[1 km² = 1,000,000 m²\]\[1 m² = 100 dm²\]\[1 dm² = 100 cm²\]
Units of Area and Conversions
Units of Area and Conversions
Key Point: General rule: If 1 linear unit A = k linear units B, then 1 square A = k² square B.
What is area?
Area is the measure of the surface of a flat region. It is measured in square units — the area of a shape is the number of unit squares needed to cover it exactly without overlapping or gaps. A unit square of side 1 metre has area 1 square metre (1 m²).
Standard unit
The SI unit of area is the square metre (m²). Other commonly used units are square millimetre (mm²), square centimetre (cm²), square kilometre (km²), hectare (ha) and acre. For everyday small measures we use cm² or m²; for land we use hectare, acre or km².
How conversions work
Area units are derived from linear units, so when you convert area you square the linear conversion factor. If 1 linear unit A = k linear units B, then 1 square A = k² square B.
- Example: 1 m = 100 cm, so 1 m² = (100 cm)² = 10000 cm².
- Example: 1 km = 1000 m, so 1 km² = (1000 m)² = 1 000 000 m².
Common conversion relationships
- 1 m² = 10 000 cm² = 1 000 000 mm²
- 1 cm² = 100 mm²
- 1 km² = 1 000 000 m²
- 1 hectare (ha) = 10 000 m²
- 1 acre ≈ 4 046.856 m² (≈ 0.404686 ha)
Practical rule for conversion
- Write the linear conversion factor (how many of the smaller linear units make one larger linear unit).
- Square that factor to convert between corresponding square units.
- Multiply or divide by that squared factor depending on direction (larger→smaller: multiply; smaller→larger: divide).
Why this matters (intuitive view)
If you increase each side of a square by 10 times, its area increases by 10² = 100 times. That is why area scales with the square of the linear factor.
Tips
Always keep track of units and use the squared conversion factor. For land problems you will often convert between m², hectares and km². For small objects use cm² or mm².
- Convert 2500 cm² to m². Since 1 m² = 10 000 cm², divide by 10 000: 2500 cm² = 2500 ÷ 10 000 = 0.25 m².
- Convert 5 m² to cm². Since 1 m² = 10 000 cm², multiply: 5 m² = 5 × 10 000 = 50 000 cm².
- Convert 3.2 km² to m². Since 1 km² = 1 000 000 m², 3.2 km² = 3.2 × 1 000 000 = 3 200 000 m².
- Convert 2.5 hectares to m². 1 ha = 10 000 m², so 2.5 ha = 2.5 × 10 000 = 25 000 m². To convert to km², divide by 1 000 000: 25 000 ÷ 1 000 000 = 0.025 km².
- Convert 9000 mm² to cm². Since 1 cm² = 100 mm², divide by 100: 9000 mm² = 9000 ÷ 100 = 90 cm².
- Convert 4 acres to m² (approx). 1 acre ≈ 4046.856 m², so 4 acres ≈ 4 × 4046.856 = 16 187.424 m².
- \[General rule: If 1 linear unit A = k linear units B\]\[then 1 square A = k² square B.\]
- \[1 m² = (100 cm)² = 10 000 cm²\]
- \[1 m² = (1000 mm)²? (Incorrect) → correct: 1 m = 1000 mm\]\[so 1 m² = (1000 mm)² = 1 000 000 mm²\]
- \[1 km² = (1000 m)² = 1 000 000 m²\]
- \[1 hectare = 10 000 m²\]
- \[1 acre ≈ 4 046.856 m²\]
Area of Rectangle and Square
Area of Rectangle and Square
Key Point: Area of rectangle: A = length × breadth = l × b
What is area? The area of a plane figure is the amount of surface it covers. For rectangles and squares, area is measured by counting how many unit squares (like 1 cm × 1 cm squares) exactly cover the shape. The unit is written as square units (cm2, m2, mm2, etc.).
Rectangle: A rectangle is a quadrilateral with opposite sides equal and all angles 90°. If a rectangle has length l and breadth b, it can be filled by arranging b rows of l unit squares (or vice versa). So the total number of unit squares = l × b. Therefore:
Area of a rectangle = length × breadth = l × b
Square: A square is a special rectangle with all four sides equal. If each side is a, then it can be filled by a rows of a unit squares.
Area of a square = side × side = a2
Derivation idea (tiling): Visualise a rectangle of length l and breadth b drawn on graph paper. There are b horizontal rows; each row contains l unit squares. Multiplying rows by squares per row gives total unit squares covered: l × b.
Units and conversion: Always express area in square units. To convert, use (1 m = 100 cm) so 1 m2 = (100 cm) × (100 cm) = 10,000 cm2. Likewise, 1 cm2 = 100 mm2.
Useful rearrangements:
- If area and one side are known, the other side = area / (known side). Example: if A = 120 cm2 and l = 12 cm, then b = 120 / 12 = 10 cm.
- For a square, side = √area.
Difference between perimeter and area: Perimeter measures the boundary length (1D), area measures the surface covered (2D). Two rectangles can have the same perimeter but different areas.
Tips to solve problems: Always check and convert units before multiplying. Sketch the figure on grid paper to visualise unit squares. For word problems, write given values clearly (length, breadth, or area) and apply formulas directly.
- Find the area of a rectangle with length 12 cm and breadth 5 cm. Solution: Area = l × b = 12 × 5 = 60 cm2.
- Find the area of a square whose side is 8 m. Solution: Area = side2 = 8 × 8 = 64 m2.
- A rectangular garden is 15 m long and 8 m wide. How much grass seed is needed to cover it if 1 m2 requires 0.2 kg of seed? Area = 15 × 8 = 120 m2. Seed = 120 × 0.2 = 24 kg.
- The area of a rectangle is 72 cm2 and its length is 9 cm. Find the breadth. Breadth = area / length = 72 / 9 = 8 cm.
- Two square tiles have sides 30 cm and 45 cm. Which tile covers more area and by how much? Areas: 30 cm tile = 900 cm2, 45 cm tile = 2025 cm2. Difference = 2025 − 900 = 1125 cm2.
- Convert: A rectangular room measures 4 m by 3 m. What is its area in cm2? Area in m2 = 4 × 3 = 12 m2. In cm2: 12 × 10,000 = 120,000 cm2.
- \[Area of rectangle: A = length × breadth = l × b\]
- \[Area of square: A = side × side = a2\]
- \[If A and l are known for a rectangle\]\[breadth b = A / l (and vice versa)\]
- \[Side of square from area: a = √A\]
- \[Unit conversions: 1 m2 = 10,000 cm2\]\[1 cm2 = 100 mm2\]
- \[(Extension) Area of square in terms of diagonal d: A = d2 / 2\]
Area of Parallelogram and Triangle
Area of Parallelogram and Triangle
Key Point: Area of parallelogram = base × height => A = b × h
Basic idea: Area measures the amount of flat surface inside a 2D shape in square units (cm², m², etc.). For a parallelogram and a triangle we use the base and the perpendicular height.
Parallelogram: A parallelogram is a four-sided figure with opposite sides parallel. If a parallelogram has base b and corresponding height h (the perpendicular distance between the pair of parallel sides), its area is the product of base and height: area = b × h. Intuition: by cutting a triangle from one end and moving it to the other, a parallelogram can be turned into a rectangle of size b by h, so area equals that rectangle's area.
Triangle: A triangle with base b and height h (perpendicular from the chosen base to the opposite vertex) has area equal to half the area of a parallelogram with the same base and height: area = 1/2 × b × h. Intuition: two congruent triangles with the same base and height combine to make a parallelogram of base b and height h, so each triangle is half that area.
Important notes: The base can be any side chosen as the base; the height must be the perpendicular distance from that base to the opposite vertex or side. Always use the same units for base and height; area units are square units.
- Example 1 (Parallelogram): Parallelogram ABCD has base AB = 8 cm and height (perpendicular distance between AB and CD) = 3 cm. Area = base × height = 8 × 3 = 24 cm².
- Example 2 (Triangle): Triangle PQR has base PQ = 6 m and corresponding height from R = 4 m. Area = 1/2 × base × height = 1/2 × 6 × 4 = 12 m².
- Example 3 (Using another side as base): In triangle ABC, side AC = 10 cm. If the perpendicular height from B to AC is 5 cm, area = 1/2 × 10 × 5 = 25 cm². (We can choose any side as base but must use its perpendicular height.)
- Example 4 (Right triangle): Right triangle with legs 5 cm and 12 cm (legs are perpendicular). Taking one leg as base and the other as height: area = 1/2 × 5 × 12 = 30 cm².
- Example 5 (Word problem): A parallelogram-shaped garden has base 15 m and height 8 m. How much turf (in m²) is needed? Area = 15 × 8 = 120 m².
- \[Area of parallelogram = base × height => A = b × h\]
- \[Area of triangle = 1/2 × base × height => A = 1/2 × b × h\]
- \[Units: If b and h are in cm\]\[area is in cm²\]\[if in m\]\[area is in m².\]
- \[Relationship: Area(triangle with base b and height h) = 1/2 × Area(parallelogram with same b and h)\]
Area of Composite and Irregular Figures
Area of Composite and Irregular Figures
Key Point: Area of rectangle = length × breadth (A = l × b)
What are composite and irregular figures?
Composite figures are shapes made by joining two or more simple plane figures (rectangles, triangles, circles, etc.). Irregular figures are shapes that do not have a regular name but can be broken down into simple shapes. To find their area we divide (decompose) the figure into simple parts, find each part's area, then add or subtract as needed.
General method (step-by-step)
- Make sure all dimensions are in the same units (convert if needed).
- Decompose the figure into familiar shapes (rectangles, triangles, semicircles, etc.). Draw the partition lines clearly.
- Label dimensions on each simple shape. If a length is not given directly, use subtraction/addition of other lengths to find it.
- Use the area formula for each simple shape to compute its area.
- If the composite figure includes a cut-out (hole), subtract the area of the hole from the whole. Otherwise, add areas of the parts.
- Write the final answer with correct square units (cm², m², etc.).
Important tips
- Always check units and convert (e.g., m to cm) before calculating.
- Use a grid overlay or count unit squares for irregular shapes when dimensions are not given.
- Choose decomposition that gives simple dimensions (horizontal/vertical cuts for rectilinear shapes usually work best).
- For curved parts (semicircles, quarter-circles), use circle-area formulas and appropriate fractions of π.
- Example 1 — L-shaped figure (sum of rectangles): An L-shape is formed by joining rectangle A (8 cm × 5 cm) and rectangle B (3 cm × 5 cm) side by side. Area = area(A) + area(B) = (8×5) + (3×5) = 40 + 15 = 55 cm².
- Example 2 — Rectangle with a semicircular cut-out (use subtraction): A rectangle 20 cm by 10 cm has a semicircular hole along the shorter side with diameter 10 cm. Area(rectangle) = 20×10 = 200 cm². Area(semicircle) = (1/2)×π×(r²) with r = 5 cm → (1/2)×π×25 ≈ (1/2)×3.14×25 = 39.25 cm². Remaining area ≈ 200 − 39.25 = 160.75 cm².
- Example 3 — Irregular shape by counting unit squares: A drawn shape on a 1 cm grid covers 37 full squares and 6 half-squares (each half-square ≈ 0.5 cm²). Area = 37 + (6×0.5) = 37 + 3 = 40 cm².
- \[Area of rectangle = length × breadth (A = l × b)\]
- \[Area of square = side² (A = s²)\]
- \[Area of triangle = (1/2) × base × height (A = 1/2 × b × h)\]
- \[Area of parallelogram = base × height (A = b × h)\]
- \[Area of trapezium = (1/2) × (sum of parallel sides) × height (A = 1/2 × (a + b) × h)\]
- \[Area of circle = π × r² (use π ≈ 22/7 or 3.14)\]
Problems Involving Perimeter and Area
Problems Involving Perimeter and Area
Key Point: Perimeter of a rectangle = 2 × (length + width)
Perimeter is the total length around a 2-D shape. It is found by adding the lengths of all the boundary sides. Units are linear (mm, cm, m, km).
Area is the measure of the surface covered by a shape. It is expressed in square units (cm², m², etc.).
General approach to solve problems:
- Identify the shape(s) involved and label known dimensions.
- Convert all measurements to the same units before calculating.
- Use the appropriate formula(s) for perimeter and/or area.
- For composite shapes, split the figure into simple shapes (rectangles, squares, triangles, circles if needed), find areas of parts and add or subtract as required.
- When unknowns are present, set up equations from perimeter/area relations and solve for the variable(s).
- Answer with correct units and check that the result is reasonable.
Common types of problems: finding perimeter or area given dimensions, finding a missing dimension given area or perimeter, cost problems (cost per unit length for fencing or cost per unit area for flooring), shaded-region problems (subtracting/adding areas), and composite-figure problems.
Tips: Always draw and label the figure. For perimeter, walk around the boundary in one direction to avoid missing sides. For area, ensure you add/subtract the correct parts for composite shapes and keep units consistent.
- Example 1 — Fencing a rectangular garden: A rectangular garden is 12 m long and 8 m wide. Find the length of fence needed and the cost if fencing costs Rs 50 per metre. Solution: Perimeter = 2(12 + 8) = 40 m. Cost = 40 × 50 = Rs 2000.
- Example 2 — Tiling a floor: A rectangular room is 6 m by 4 m. Tiles measure 50 cm × 50 cm. How many tiles are needed to cover the floor? Solution: Room area = 6 × 4 = 24 m² = 2400 × 100 cm²? (better convert tiles to m²). Tile area = 0.5 × 0.5 = 0.25 m². Number of tiles = 24 ÷ 0.25 = 96 tiles.
- Example 3 — Composite shape area (L-shape): A floor consists of a 10 m × 6 m rectangle with a 4 m × 2 m rectangle removed from one corner. Find the area to be covered. Solution: Area = 10 × 6 − 4 × 2 = 60 − 8 = 52 m².
- Example 4 — From perimeter to area (square): The perimeter of a square is 48 cm. Find its area. Solution: Side = 48 ÷ 4 = 12 cm. Area = 12 × 12 = 144 cm².
- Example 5 — Using algebra (rectangle): The perimeter of a rectangle is 50 m. The length is 5 m more than the width. Find dimensions and area. Solution: Let width = w, length = w + 5. Then 2(w + w + 5) = 50 ⇒ 2(2w + 5) = 50 ⇒ 2w + 5 = 25 ⇒ 2w = 20 ⇒ w = 10 m, length = 15 m. Area = 10 × 15 = 150 m².
- \[Perimeter of a rectangle = 2 × (length + width)\]
- \[Area of a rectangle = length × width\]
- \[Perimeter of a square = 4 × side\]
- \[Area of a square = side²\]
- \[Area of a triangle = (1/2) × base × height\]
- \[Perimeter of a triangle = sum of its three sides\]
Relationship between Perimeter and Area
Relationship between Perimeter and Area
Key Point: Rectangle: Perimeter P = 2(l + w), Area A = l × w
What they measure: Perimeter is the length around a closed figure (sum of its side lengths). Area is the amount of surface enclosed by the figure (measured in square units).
Main idea of their relationship: Perimeter and area are different quantities and do not change in the same way. For similar shapes (same shape but different sizes) the perimeter changes in direct proportion to the linear scale factor, while the area changes in proportion to the square of the scale factor. For a fixed perimeter, area is maximized by a shape that is as "round" as possible (for rectangles this is the square). For a fixed area, the shape with the smallest perimeter is also the most "regular" (for rectangles this is again the square).
Key consequences (explained simply):
- Scaling: If a figure is enlarged by a factor k (every linear dimension multiplied by k), then the new perimeter = k × (original perimeter) and the new area = k² × (original area).
- Fixed perimeter → maximum area: Among all rectangles with the same perimeter, the square has the greatest area. More generally, among all plane figures with a given perimeter, the circle has the largest area (isoperimetric fact).
- Fixed area → minimum perimeter: Among rectangles with the same area, the square has the smallest perimeter.
Short algebraic demonstration for rectangles (fixed perimeter P): Let length = x and width = w. If perimeter P is fixed, 2(x + w) = P so w = P/2 - x. Area A(x) = x·w = x(P/2 - x) = (P/2)x - x². This is a downward parabola in x with vertex at x = P/4. So the maximum area occurs when x = w = P/4 (a square). The maximum area value = (P/4)·(P/4) = P²/16.
Algebraic note for fixed area S: For a rectangle with area S = x·w, perimeter P = 2(x + w) = 2(x + S/x). The expression x + S/x is minimized when x = √S (by AM-GM or calculus), giving the minimum perimeter P_min = 4√S (again a square).
Practical summary: Perimeter and area are related, but increasing perimeter does not always increase area proportionally — shape matters. For similar shapes area grows faster (square of factor) than perimeter (first power of factor).
- Example 1 (fixed perimeter): Perimeter = 20 cm. If rectangle is 1 cm × 9 cm, area = 9 cm². If rectangle is 5 cm × 5 cm (square), area = 25 cm². Among rectangles with P = 20 cm, the square gives the largest area.
- Example 2 (fixed area): Area = 36 cm². If rectangle is 1 cm × 36 cm, perimeter = 74 cm. If rectangle is 6 cm × 6 cm (square), perimeter = 24 cm. The square gives the smallest perimeter for the same area.
- Example 3 (scaling): A square of side 2 cm has perimeter 8 cm and area 4 cm². If scaled by k = 3 (side 6 cm), new perimeter = 24 cm (=3×8) and new area = 36 cm² (=3²×4).
- \[Rectangle: Perimeter P = 2(l + w)\]\[Area A = l × w\]
- \[Square: Perimeter P = 4a\]\[Area A = a²\]
- \[Triangle: Perimeter P = a + b + c\]\[Area A = 1/2 × base × height\]
- \[Circle: Circumference C = 2πr\]\[Area A = πr²\]
- \[Scaling (similar figures): If linear scale = k\]\[then Perimeter → k × P\]\[Area → k² × A\]
- \[Maximum area for a fixed rectangle perimeter P: A_max = P² / 16 (when rectangle is a square)\]
Practical Skills, Estimation and Problem-solving Strategies
Practical Skills, Estimation and Problem-solving Strategies
Key Point: Perimeter of rectangle = 2 × (length + breadth)
This topic teaches how to measure, estimate and solve perimeter and area problems efficiently using simple practical skills and systematic strategies. It emphasizes choosing suitable units, making quick estimates to check answers, and breaking complex shapes into simpler parts for calculation.
- Practical measuring skills: Use a ruler, tape, thread or graph paper depending on the figure. For curved boundaries use a flexible tape or thread and then measure the thread against a scale. For flat regions, overlay a grid (square paper) to count unit squares.
- Estimation techniques: Round dimensions to convenient numbers to get an approximate area/perimeter. Use lower and upper bounds (e.g., if length is 12.3 m, treat as about 12–13 m) to check if the exact answer is reasonable. For irregular shapes, approximate by the closest regular shapes or by counting full and partial grid squares.
- Problem-solving strategy (a simple Polya approach):
- Understand the problem: identify what is asked (perimeter or area) and the units given.
- Plan: decide which formula(s) apply or whether to decompose the shape into simpler shapes (rectangles, triangles, etc.).
- Execute: carry out calculations carefully, convert units if needed (cm to m, cm² to m²), and add/subtract areas when combining shapes.
- Review: estimate to see if the result is reasonable, check units and calculations, and consider alternative approaches if needed.
- Decomposition and composition: For L-shaped, T-shaped or other irregular regions, split the figure into rectangles/triangles whose areas you know, compute each, then add or subtract appropriately.
- Unit awareness: Perimeter units are linear (m, cm); area units are square (m², cm²). When dimensions are in different units convert them before using formulas.
- Sanity checks: Use a quick estimate (rounding) or compare with the bounding rectangle: area of any shape must be less than area of its bounding rectangle and greater than area of any inscribed rectangle.
Using these skills makes working with perimeter and area faster, reduces errors, and helps you choose simpler methods for complex shapes.
- Rectangular garden: Exact and estimated area. Given 12.3 m by 4.8 m. Estimate: 12 × 5 = 60 m². Exact: 12.3 × 4.8 = 59.04 m². The estimate shows the exact value is reasonable.
- Fencing a park (perimeter): Park is 25 m by 18 m. Perimeter = 2(25 + 18) = 2 × 43 = 86 m of fence required. Quick check: (25+18)≈(25+20)=45 ⇒ 2×45=90 close to 86.
- L-shaped room (decomposition): An L-shape can be split into two rectangles: R1 = 6 m × 4 m = 24 m², R2 = 3 m × 4 m = 12 m². Total area = 24 + 12 = 36 m².
- Using grid paper to estimate irregular area: On 1 cm² grid, count full squares = 35, half squares ≈ 10. Approx area ≈ 35 + 10×0.5 = 40 cm².
- Unit conversion for area: A tabletop is 5000 cm². Convert to m²: 1 m² = 10000 cm², so 5000 cm² = 0.5 m². This check helps compare to other areas measured in m².
- \[Perimeter of rectangle = 2 × (length + breadth)\]
- \[Area of rectangle = length × breadth\]
- \[Perimeter of square = 4 × side\]
- \[Area of square = side × side = side²\]
- \[Area of triangle = (1/2) × base × height (for triangles with known height)\]
- \[Area of parallelogram = base × height\]
Key Concepts
- Perimeter
- Total length around a 2D shape; sum of all its side lengths.
- Area
- Amount of surface covered by a 2D shape; measured in square units.
- Rectangle
- Quadrilateral with opposite sides equal and four right angles.
- Square
- Quadrilateral with all four sides equal and four right angles.
- Triangle
- Polygon with three sides; area = 1/2 * base * height.
- Parallelogram
- Quadrilateral with opposite sides parallel and equal; area = base * height.
- Trapezium (Trapezoid)
- Quadrilateral with one pair of parallel sides; area = 1/2*(sum of parallel sides)*height.
- Circle
- Set of all points in a plane at a fixed distance (radius) from a fixed center.
- Radius
- Distance from the center of a circle to any point on it.
- Diameter
- Line segment passing through the center with endpoints on the circle; equals 2*radius.
- Circumference
- Perimeter (boundary length) of a circle; C = 2πr = πd.
- Base
- Side of a polygon chosen as reference for measuring height or computing area.
- Height (Altitude)
- Perpendicular distance from the chosen base to the opposite vertex or side.
- Unit Square
- A square of side 1 unit used as the standard building block for measuring area.
- Units of Area
- Standard measurements for area such as mm², cm², m²; units are squared linear units.
- Composite Figure
- Figure made by combining simple shapes; area/perimeter found by adding/subtracting parts.
- Regular Polygon
- Polygon with all sides and all interior angles equal.
- Irregular Polygon
- Polygon whose sides and/or angles are not all equal.
- Perimeter of a Polygon
- Sum of the lengths of all the sides of the polygon.
- Conversion of Area Units
- Changing area from one square unit to another using squared conversion factors (factor²).
Practice Questions
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A rectangle has length 12 m and breadth 5 m. What is its area? / एक आयत की लंबाई 12 m और चौड़ाई 5 m है। उसका क्षेत्रफल क्या है? (a) 34 m² (b) 60 m² (c) 17 m² (d) 120 m²
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(b) 60 m² — Area of a rectangle = length × breadth = 12 × 5 = 60 m². / आयत का क्षेत्रफल = लंबाई × चौड़ाई = 12 × 5 = 60 m²।
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The perimeter of a square is 36 cm. What is the area of the square? / एक वर्ग का परिमाप 36 cm है। वर्ग का क्षेत्रफल क्या है? (a) 81 cm² (b) 72 cm² (c) 324 cm² (d) 9 cm²
Show answer
(a) 81 cm² — Perimeter = 4 × side, so side = 36 ÷ 4 = 9 cm. Area = side² = 9 × 9 = 81 cm². / परिमाप = 4 × भुजा, भुजा = 36 ÷ 4 = 9 cm। क्षेत्रफल = 9² = 81 cm²।
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A parallelogram has base 8 cm and height 6 cm. What is its area? / एक समांतर चतुर्भुज का आधार 8 cm और ऊंचाई 6 cm है। उसका क्षेत्रफल क्या है? (a) 24 cm² (b) 48 cm² (c) 28 cm² (d) 14 cm²
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(b) 48 cm² — Area of a parallelogram = base × height = 8 × 6 = 48 cm². / समांतर चतुर्भुज का क्षेत्रफल = आधार × ऊंचाई = 8 × 6 = 48 cm²।
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Fill in the blank: The area of a triangle with base b and height h is given by the formula ______. / रिक्त स्थान भरें: आधार b और ऊंचाई h वाले त्रिभुज का क्षेत्रफल सूत्र ______ द्वारा दिया जाता है।
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(1/2) × b × h — Two congruent triangles with the same base and height make a parallelogram of area b × h, so one triangle = half of that. / दो सर्वांगसम त्रिभुज मिलकर क्षेत्रफल b × h का समांतर चतुर्भुज बनाते हैं, इसलिए एक त्रिभुज = (1/2) × b × h।
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Fill in the blank: 1 m² = ______ cm². / रिक्त स्थान भरें: 1 m² = ______ cm²।
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10,000 — Since 1 m = 100 cm, area conversion requires squaring: 1 m² = (100 cm)² = 100 × 100 = 10,000 cm². / 1 m = 100 cm, इसलिए 1 m² = (100)² = 10,000 cm²।
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True or False: Two rectangles with the same perimeter must have the same area. / सत्य या असत्य: समान परिमाप वाले दो आयतों का क्षेत्रफल अवश्य समान होगा।
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False / असत्य — For example, a 1 cm × 9 cm rectangle (perimeter = 20 cm, area = 9 cm²) and a 5 cm × 5 cm square (perimeter = 20 cm, area = 25 cm²) have the same perimeter but different areas. / उदाहरण: 1×9 (परिमाप 20, क्षेत्रफल 9) और 5×5 (परिमाप 20, क्षेत्रफल 25) समान परिमाप के साथ भिन्न क्षेत्रफल।
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A triangular park has base 20 m and height 15 m. Find the area of the park. / एक त्रिकोणीय पार्क का आधार 20 m और ऊंचाई 15 m है। पार्क का क्षेत्रफल ज्ञात करें।
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Area = (1/2) × base × height = (1/2) × 20 × 15 = 150 m². / क्षेत्रफल = (1/2) × 20 × 15 = 150 m²। पार्क का क्षेत्रफल 150 m² है।
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An L-shaped floor is made of two rectangles: 10 m × 4 m and 5 m × 3 m. Find the total area. If tiling costs ₹200 per m², what is the total cost? / एक L-आकार का फर्श दो आयतों से बना है: 10 m × 4 m और 5 m × 3 m। कुल क्षेत्रफल ज्ञात करें। यदि फर्श बनाने का खर्च ₹200 प्रति m² हो, तो कुल लागत क्या है?
Show answer
Total area = (10 × 4) + (5 × 3) = 40 + 15 = 55 m². Total cost = 55 × ₹200 = ₹11,000. / कुल क्षेत्रफल = 40 + 15 = 55 m²। कुल लागत = 55 × ₹200 = ₹11,000।
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