Overview
This unit on Heat and Energy introduces the ideas of thermal energy, temperature, heat transfer and the behaviour of materials when they are heated or cooled. Students learn how substances expand, how heat flows by conduction, convection and radiation, and how to measure temperature and heat. The unit also covers specific heat capacity, latent heat, the first law ideas in simple form, calorimetry and practical applications such as thermal insulation and engines at a basic level. These topics matter because heat phenomena are part of everyday life: from cooking and weather to refrigerators, engines and home insulation. Understanding heat and energy helps students explain why substances change state, why metal tools get hot, why sea breezes form and how household devices save energy. The skills developed include careful measurement, drawing and interpreting heating curves, calculating heat quantities in customary problems, and explaining experimental observations. The unit builds a foundation for later study in thermodynamics and physical chemistry by giving clear concepts, simple quantitative relations and examples of energy conservation. Practical work in this unit also develops lab technique, accuracy and scientific reasoning, which are useful across all sciences.
Learning Objectives
- Describe temperature and thermal energy and distinguish between them.
- Explain and give examples of conduction, convection and radiation of heat.
- Investigate and explain thermal expansion in solids, liquids and gases.
- Measure heat changes using specific heat capacity and apply the formula Q = mcΔT in calculations.
- Explain latent heat of fusion and vaporisation and use latent heat values in problems.
- Model simple calorimetry experiments to determine specific heat or latent heat.
- Apply the idea of energy conservation to heat flow and basic engine cycles qualitatively.
- Explain practical applications of heat transfer such as insulation, thermostats and cooling systems.
Topics in this chapter
18 topics · tap a topic title to jump straight to it.
Nature of Heat and Temperature
What is temperature?
Temperature is a property that tells us how hot or cold a body is. Microscopically, it measures the average kinetic energy of particles: faster motion gives higher temperature. Temperature determines the direction of heat flow—heat moves from a body at higher temperature to one at lower temperature until equilibrium is reached.
What is heat?
Heat is energy in transit, transferred between systems because of a temperature difference. Heat is not a property of a body like temperature; it is a process quantity that depends on a transfer. Heat can change the temperature of a body, cause a change of state (melting or boiling), or do work if allowed. Units commonly used are joules (J) and calories (cal), where 1 cal ≈ 4.184 J.
Distinguishing heat and temperature
It is important to separate the two ideas. Temperature measures how energetic particles are on average. Heat is the total energy transferred. A large cold lake may contain more internal thermal energy than a small hot cup of tea because of its mass, but the cup has higher temperature. Temperature is intensive (independent of amount) while heat is extensive (depends on amount).
Temperature scales
There are several scales: Celsius (°C), Kelvin (K) and Fahrenheit (°F). In physics we use Kelvin when absolute zero is relevant. The conversion between Celsius and Kelvin is K = °C + 273.15. Temperature differences are the same in °C and K, so ΔT in °C equals ΔT in K.
Measuring temperature
Thermometers work by using a measurable change that depends on temperature: expansion of liquids, change in resistance of metals, or voltage changes in thermocouples. For accurate experiments ensure good thermal contact between thermometer and the body being measured, avoid direct heating or cooling of the thermometer stem, and allow time for equilibrium so the thermometer reads the true temperature of the object.
Everyday observations
When two objects at different temperatures touch, heat flows until they reach the same temperature. This explains why a cold object placed in warm air warms up and a hot object cools. Understanding heat and temperature is the first step to analysing energy exchange in everyday tasks like cooking, heating and refrigeration.
- A cup of water at 80°C cools to 40°C when left in a room. Explain in terms of heat transfer between water and air.
- Compare thermal energy of 1 kg of water at 20°C and 0.1 kg of copper at 95°C: which has more heat energy? (Discuss qualitatively.)
- Convert 25°C to Kelvin and -10°C to Kelvin.
- Explain why a metal spoon feels colder than a wooden spoon at the same room temperature.
- K = °C + 273.15
- Heat is energy transferred; common units: 1 cal = 4.184 J
Kinetic Model and Internal Energy
Kinetic model of matter
The kinetic model explains macroscopic behaviour by assuming matter is made of many tiny particles—atoms or molecules—that are always in motion. In solids, particles vibrate about fixed positions; in liquids they move past one another while remaining close; in gases they move freely and far apart. The differences in motion explain properties such as rigidity, viscosity and compressibility.
Temperature and particle motion
Temperature relates directly to the average kinetic energy of these particles. Higher temperature means particles move faster on average. This connection helps predict how pressure, volume and temperature of gases relate through simple laws: for instance, at a given volume, increasing particle speeds increases pressure because collisions with container walls become more forceful and frequent.
Internal energy
Internal energy is the total microscopic energy inside a system: the sum of kinetic energy of all particles plus potential energy due to interactions between them. Internal energy is a property of the system and increases when heat is added or work is done on the system. For example, heating a solid increases vibration amplitudes (kinetic energy) and may increase potential energy if bonds are stretched.
Heating effects
When heat is supplied, energy goes into increasing particle kinetic energy (raising temperature) or into increasing potential energy (changing structure during phase change). During melting and boiling, temperature stays constant while energy goes into changing the arrangement and separation of particles rather than increasing their speed. This explains why adding heat to ice at 0°C melts it without temperature rise.
Relation to pressure
In gases, higher temperature increases molecule speed and pressure (if volume fixed). If the gas can expand, it may do work on the surroundings and cool down. Compression does work on a gas, increasing internal energy and temperature; this is observed when pumping air into a tyre—the pump gets warm.
Microscopic understanding of phase processes
Evaporation removes higher-energy molecules from a liquid, lowering average kinetic energy and cooling the liquid. Condensation deposits energy as vapour molecules join a liquid. Understanding these microscopic exchanges helps explain macroscopic processes like sweating, cooling towers and refrigeration cycles in qualitative terms.
- Explain why evaporation cools a liquid using particle motion.
- Why does compressing air in a bicycle pump make it warm? Describe in terms of particle energy.
- A substance melts at constant temperature though heat is being supplied—explain using internal energy.
- Describe why boiling water at high altitude takes longer: relate to particle interactions and atmospheric pressure.
- No new algebraic formula; internal energy changes when heat is added or work done: ΔU = Q - W (qualitative for Class 9)
Methods of Heat Transfer
Overview of modes
Heat can be transferred in three distinct ways: conduction, convection and radiation. Each mode has different physical causes and common examples. Real situations often involve a combination of these mechanisms.
Conduction
Conduction is heat transfer through a material by direct contact—energy moves from particle to particle. In solids, particles vibrate and pass energy to neighbours; in metals free electrons also carry energy rapidly. Good conductors (copper, aluminium) transfer heat quickly; poor conductors (wood, rubber, air) act as insulators. Conduction is important when two parts of a solid are at different temperatures or when heat flows from a hot surface into a solid object.
Microscopic view of conduction
In a metal rod with one end heated, metal atoms at the hot end vibrate more and free electrons gain energy and move, transferring kinetic energy along the rod. The result is a temperature gradient along the length. The rate of heat transfer by conduction depends on the material and geometry: thicker cross-sectional area increases transfer, while longer path and insulating materials reduce it.
Convection
Convection occurs only in fluids (liquids and gases) and involves bulk motion. When a fluid is heated, it expands, becomes less dense and rises; cooler denser fluid flows down to replace it, forming convection currents. Forced convection occurs when a pump or fan moves the fluid. Natural (free) convection drives weather systems, boiling water circulation, and room heating by radiators.
Examples of convection
Warm air rising above a heater and cool air sinking near the floor produce circulation that distributes heat in a room. In a pot of boiling soup, hotter fluid rises and cooler fluid descends, mixing the contents. Ocean currents and atmospheric cells are large-scale convection phenomena driven by solar heating differences.
Radiation
Radiation transfers energy by electromagnetic waves without requiring a medium. All bodies emit thermal radiation depending on their temperature. Hotter bodies emit more radiation and at shorter wavelengths. Radiation explains how the Sun heats Earth across vacuum. Surfaces that are dark and matte absorb and emit radiation efficiently; shiny surfaces reflect it.
Comparing modes and combined effects
Conduction dominates in solids, convection in fluids with flow, and radiation becomes important at high temperatures or across vacuum. In everyday examples, a kettle on a stove receives conduction from the metal, convection circulates hot water inside, and the kettle emits radiation to surroundings. Understanding which mode dominates helps design insulation and heating systems effectively.
- Explain why wearing layered clothing keeps a person warm in winter (mention conduction and trapped air).
- Describe how a room is warmed by a radiator using convection currents.
- Why does a shiny aluminium foil wrap keep food warmer compared to a dark cloth? Discuss radiation.
- Explain why a metal pan heats faster on a gas flame than a ceramic pot, in terms of conduction.
- Qualitative descriptions; no numerical formula required here for Class 9.
Thermal Expansion of Solids
Introduction to expansion
When solids are heated, their dimensions increase. This behaviour—thermal expansion—occurs because heating increases atomic vibrations and average separation between atoms or molecules. Expansion affects lengths, areas and volumes. Engineers must account for expansion when designing structures, machines and devices that experience temperature changes.
Linear expansion
Linear thermal expansion refers to change in length. For small temperature ranges, the increase in length ΔL is proportional to original length L and temperature change ΔT. The proportionality constant α is the coefficient of linear expansion which depends on the material. The relation ΔL = α L ΔT works well for metals, glass and many solids over ordinary temperature ranges.
Area and volume expansion
Similarly, area expansion of a thin plate is approximately ΔA ≈ 2α A ΔT, and volume expansion is approximately ΔV ≈ 3α V ΔT when the material expands uniformly in three dimensions. These formulas are approximations valid for small ΔT and isotropic materials (same properties in all directions).
Material differences and examples
Different materials have different α values: metals like aluminium and copper expand more than glass or concrete. Brass and steel have different expansion coefficients, which can cause stress when they are joined. For composite structures or where temperature changes are large, designers allow expansion gaps or use flexible connections to avoid cracking or buckling.
Practical devices and demonstrations
Examples demonstrate expansion clearly: railway tracks have small gaps so rails can lengthen in summer; bridges include expansion joints; metal lids sometimes stick on glass jars when heated because the metal expands more. Bimetallic strips exploit differential expansion: two bonded metals with different α bend when heated and are used in thermostats and temperature-controlled switches.
Limitations and nonlinearities
For very large temperature changes or anisotropic materials, expansion can be nonlinear and the simple linear formulas may not be accurate. Also, materials under external stress or constraint can develop thermal stress if expansion is prevented. Understanding these limitations helps in safe engineering design and correct interpretation of experiments in the lab.
- A 2 m iron rod is heated by 50°C. If α for iron is 12 × 10^-6 /°C, calculate its increase in length.
- Explain why gaps are left between concrete slabs on a pavement.
- Describe how a bimetallic strip in a thermostat causes a switch to operate.
- Why do metal lids sometimes stick to glass jars when heated?
- ΔL = α L ΔT
- Area expansion for small ΔT: ΔA ≈ 2α A ΔT
- Volume expansion for solids: ΔV ≈ 3α V ΔT (approximate)
Thermal Expansion of Liquids and Gases
Expansion in liquids
Liquids expand on heating because increased thermal motion makes molecules occupy, on average, more space. Compared with solids, liquids typically have larger coefficients of volume expansion. The relation ΔV = β V ΔT describes this volume change approximately for small temperature changes, where β is the coefficient of volume expansion for the liquid. Practical instruments like liquid-in-glass thermometers rely on predictable expansion of liquids such as mercury or alcohol.
Anomalous behaviour of water
Water behaves unusually near freezing: it contracts as cooled down to about 4°C, reaching maximum density at that temperature, then expands as it approaches 0°C and forms ice. This anomalous expansion causes ice to float and lakes to freeze from the top down, protecting aquatic life. Engineers and environmental scientists consider this property when dealing with cold climates and freshwater systems.
Gases and large expansion
Gases expand much more than liquids or solids for the same temperature change because their particles are much farther apart and move more freely. Under constant pressure, the volume of a gas is proportional to its absolute temperature (Charles's law): V ∝ T (in Kelvin). If the volume is fixed, increasing temperature raises the pressure (Gay-Lussac's law). The behaviour of ideal gases is summarised by pV = nRT, but for many class 9 problems qualitative use of Charles's law suffices.
Practical consequences
Hot air balloons rise because heating the air inside reduces its density compared with surrounding cooler air, providing buoyant lift. Tyre pressures rise on hot days because the air temperature inside increases while volume changes little. Pipelines carrying liquids must be designed to accommodate thermal expansion to prevent leaks and stresses.
Measuring and designing for expansion
Allowances for expansion are built into constructions: gaps between sections of pavement, flexible couplings in pipes and expansion joints in bridges. Thermometers exploit liquid expansion in a narrow capillary to give readable changes. In precision instruments thermal expansion must be minimised by using low-expansion materials or compensating designs.
Limitations
The simple linear relations for ΔV are valid for small temperature ranges; for large ranges or near phase changes more complex behaviour appears. Gases at high pressure or very low temperature may deviate from ideal behaviour, requiring advanced formulas for accurate prediction.
- Explain why a hot air balloon ascends when the air inside is heated.
- A sealed tin contains air at 20°C. If temperature rises to 40°C and volume constant, describe qualitatively what happens to pressure.
- Why does ice float on water? Mention density changes near freezing.
- Design reason: why are gaps left in long plastic pipes?
- ΔV = β V ΔT (liquids)
- For gases at constant pressure: V ∝ T (in K), Charles's law
Specific Heat Capacity
Definition and meaning
Specific heat capacity is the amount of heat needed to raise the temperature of unit mass of a substance by one degree Celsius (or one Kelvin). Denoted by c, its SI unit is J kg^-1 K^-1. It is an intrinsic property that depends on the material and indicates how readily the material changes temperature when heat is added.
Interpreting specific heat
A substance with high specific heat, like water, requires a lot of heat to change its temperature. This is why oceans moderate climate and why water is used in heating and cooling systems. Materials with low specific heat heat up or cool down quickly for the same amount of heat added.
Using the formula Q = mcΔT
The heat Q required to change the temperature of mass m by ΔT is Q = mcΔT. This formula assumes no change of state and that specific heat is approximately constant over the temperature range. In experiments, ensure consistent units: mass in kilograms, c in J kg^-1 K^-1, and ΔT in °C or K.
Lab determination: calorimetry
We determine specific heat by mixing or by heating a sample and transferring heat to a known mass of water. In a simple method, a hot metal sample of known mass and temperature is placed in water held in an insulated calorimeter. Heat lost by metal equals heat gained by water and calorimeter; rearranging the energy balance gives c for the metal. Accuracy improves by accounting for calorimeter heat capacity and reducing heat loss to surroundings.
Examples and applications
Specific heat explains everyday observations: sand heats quickly during the day (low c) and cools quickly at night, while water warms slowly and cools slowly (high c). Designing engines, heat exchangers and climate control systems requires knowing specific heats of working materials. In cooking, the choice of pan material and its thickness affects how evenly food heats due to different specific heats and conductivities.
Limitations and temperature dependence
Specific heat can vary with temperature, so for high precision or large temperature ranges the variation must be considered. For many school problems values are treated as constant over the working range. Always report specific heat with units and reasonable significant figures based on experimental precision.
- Calculate heat needed to raise 2 kg of water from 20°C to 80°C (use c of water = 4200 J kg^-1 K^-1).
- A 0.5 kg copper block at 100°C is dropped into 1 kg water at 20°C; final temperature is 25°C. Calculate specific heat of copper given water's c = 4200 J kg^-1 K^-1 (neglect calorimeter).
- Explain why it takes longer to heat a pot of water than a similar mass of iron.
- Why do coastal areas have less temperature variation than inland regions?
- Q = mcΔT
- Units: c in J kg^-1 K^-1
Latent Heat and Change of State
Concept of latent heat
Latent heat is the energy absorbed or released by a substance during a change of state at constant temperature. The term 'latent' means hidden because the temperature does not change during the process; instead, energy goes into changing the internal structure or the potential energy of particles.
Types: fusion and vaporisation
Two common forms are latent heat of fusion (melting/freezing) and latent heat of vaporisation (boiling/condensation). Latent heat of fusion L_f is the heat required per unit mass to change a solid to liquid at its melting point. Latent heat of vaporisation L_v is the heat required per unit mass to change a liquid to gas at its boiling point. Both are measured in J kg^-1.
Microscopic explanation
During melting, added energy helps break rigid bonds in the solid lattice, increasing potential energy rather than kinetic energy, so temperature remains constant while structure changes. In boiling, still more energy is needed to separate molecules sufficiently to form vapour; therefore L_v is usually much larger than L_f for the same substance.
Calculations and use
The heat Q required for mass m to change state is Q = mL, where L is the appropriate latent heat. In calorimetry problems, latent heats are combined with sensible heat (Q = mcΔT) when a process involves both temperature change and a phase change. For practical calculations include energy needed to raise or cool components to the phase change temperature.
Applications and safety
Latent heat explains why sweating cools the body—evaporation of sweat uses latent heat taken from the skin. Steam carries large latent heat and delivers more energy on condensation than the same mass of hot water, making steam burns severe. Engineers use phase-change materials for thermal storage and in cooling systems to exploit latent heat capacity.
Measuring latent heat
Latent heat is measured by calorimetry: supply known heat to a mass undergoing phase change at constant temperature and measure mass changed. Alternatively, mix ice with warm water and apply energy balance to deduce latent heat. Errors come from heat loss to surroundings and incomplete insulation; corrections improve accuracy.
- Calculate heat required to melt 0.2 kg ice at 0°C if latent heat of fusion of ice is 3.3 × 10^5 J kg^-1.
- Explain why sweating cools the body in hot weather using latent heat of vaporisation.
- A sample of water at 100°C is completely vaporised; compare heat required per kg to raise water from 20°C to 100°C then vapourise it.
- Why is steam at 100°C more dangerous than boiling water at 100°C?
- Q = mL
- Units: L in J kg^-1
Heat Capacity and Calorimetry
Heat capacity vs specific heat
Heat capacity C of a body is the amount of heat required to raise its temperature by one degree: C = mc for a homogeneous object, where m is its mass and c is specific heat. Heat capacity depends on both material and amount, while specific heat is intrinsic to the material. Heat capacity has units J K^-1.
Principles of calorimetry
Calorimetry measures heat exchanged in physical and chemical processes. The basic principle is conservation of energy: in an isolated system heat lost by hot bodies equals heat gained by cold bodies. In practice, calorimeters are insulated containers designed to reduce heat exchange with the environment so that measured temperature changes reflect internal transfers only.
Simple calorimeter setup
A typical classroom calorimeter uses a metal or plastic cup with insulation, a thermometer and a lid to minimise convection. The calorimeter itself absorbs heat; its effect is accounted for using its heat capacity or water-equivalent mass. Accurate experiments correct for heat lost to surroundings and for heat taken by the calorimeter vessel and thermometer.
Energy balance equations
When a hot object of mass m1 and specific heat c1 at temperature T1 is placed in water mass m2 at T2 in a calorimeter, equilibrium temperature T_f is reached. The balance is heat lost by hot object = heat gained by water + heat gained by calorimeter: m1 c1 (T1 - T_f) = m2 c2 (T_f - T2) + C_cal (T_f - T_initial_cal). From this equation one can find unknown specific heat or calorimeter constant.
Experiments and accuracy
Common experiments: determine specific heat of a metal, find latent heat of fusion of ice by mixing, and determine calorimeter heat capacity. To improve accuracy: use good insulation, stir gently to reach uniform temperature, measure masses precisely, and repeat trials. Consider systematic errors like heat loss during transfer of a hot sample; corrections or comparative methods reduce these errors.
Applications and interpretation
Calorimetry not only measures specific and latent heats but also is used in chemistry for enthalpy changes, in food science for caloric content, and in engineering for energy storage assessments. Understanding heat capacities helps compare materials for thermal management and design of heating or cooling systems.
- A hot copper block of mass 0.3 kg at 100°C is placed in 0.5 kg water at 20°C. Final temperature is 30°C. Find specific heat of copper.
- Describe how you would determine the heat capacity of a calorimeter using mixing method.
- Explain why stirring is important during a calorimetry experiment.
- If calorimeter has water equivalent 0.02 kg, include it in the energy balance for calculations.
- Heat balance: heat lost = heat gained
- m1 c1 (T1 - Tf) = m2 c2 (Tf - T2) + C_cal (Tf - T_initial_cal) where C_cal is calorimeter heat capacity
- Heat capacity C = mc
First Law Ideas and Energy Conservation (Qualitative)
Conservation of energy concept
The first law of thermodynamics states that energy cannot be created or destroyed, only transferred or transformed. In simple terms for Class 9, whenever heat is supplied to a system, the total energy of the system and surroundings changes but the sum is conserved. When analysing heating problems assume that heat lost by one part is gained by another if the system is isolated.
Heat and work as energy transfers
Energy can cross the boundary of a system as heat or as work. Heat flows due to temperature differences; work involves forces acting through distances, such as compression of a gas. In many school problems we ignore work or treat it qualitatively: compressing a gas does work on it and raises internal energy; friction does mechanical work that converts kinetic energy into internal energy (heat).
Energy bookkeeping in problems
When solving calorimetry or heating problems write an energy balance: sum of heats gained equals sum of heats lost, plus or minus work if present. For example, in mixing a hot object with cold water, the heat lost by the hot object equals heat gained by the water and calorimeter. Careful accounting avoids sign errors and ensures units are consistent.
Everyday examples
Conservation helps explain why adding a lid to a pot reduces fuel use—the lid lowers heat loss so more of the supplied heat raises the food's temperature. In car brakes, kinetic energy is converted by friction into thermal energy which must be dissipated; brake systems and cooling designs handle that heat. Refrigerators transfer heat from the cold inside to the warmer room by doing work through a compressor.
Limits and assumptions
At Class 9 we use a simplified view: ignore microscopic details and treat systems as closed when possible. The full first law includes internal energy change ΔU = Q - W, where Q is heat added and W is work done by the system. Introducing this idea qualitatively prepares students for later study of thermodynamics in higher classes.
Practical reasoning
Always identify the system boundary and list all energy transfers. Consider whether heat escapes to surroundings or whether work is done. This habit prevents mistakes and builds a clear physical picture before algebraic manipulation.
- Explain why mixing two liquids at different temperatures leads to a single equilibrium temperature using energy conservation.
- Describe how friction in brakes converts kinetic energy into heat and how heat is dissipated.
- Why does using a lid on a cooking pot save fuel? Relate to reduced heat loss.
- Discuss how insulating a house saves energy by reducing heat transfer through walls and roof.
- Qualitative energy conservation: heat lost = heat gained (when system closed and no work).
Heating Curves and Phase Diagrams
Heating curve basics
A heating curve shows how the temperature of a substance changes as heat is added at a steady rate. It typically plots temperature on the vertical axis and heat supplied (or time at constant heating) on the horizontal axis. The curve has rising segments where temperature increases and flat segments (plateaus) where phase changes occur at constant temperature while latent heat is absorbed.
Reading stages on a heating curve
Start with a solid at low temperature. As heat is supplied, temperature rises until the melting point. At the melting point the temperature stays constant while the solid converts to liquid; this plateau corresponds to latent heat of fusion. After all solid melts, further heating raises the liquid temperature until boiling point. At the boiling point another plateau appears while liquid turns to vapour; this is latent heat of vaporisation. After vaporisation, temperature of vapour rises again if heating continues.
Quantitative interpretation
The slope of temperature-increasing segments depends on mass and specific heat: small specific heat or small mass gives a steep slope (quick temperature rise). The length of plateaus depends on amount of substance and latent heat: larger mass or higher latent heat requires more energy to complete the phase change, giving a longer plateau for the same heating rate.
Phase diagrams (qualitative)
A phase diagram maps pressure versus temperature regions in which a substance exists as solid, liquid or gas. Lines on the diagram show conditions where two phases coexist (e.g., melting line, boiling line). The triple point marks temperature and pressure where all three phases coexist. For everyday pressures, increasing pressure raises the boiling point of liquids—this is why a pressure cooker cooks faster by raising the boiling point of water.
Practical experiments
Students can build heating curves by heating a substance and recording temperature vs time. Accurate results need steady heating, good insulation and careful observation of plateaus. Heating curves provide a clear visual link between heat added and state changes and are a useful tool to understand latent heat and energy storage in phase changes.
Applications
Heating curves are relevant in metallurgy, food processing and climate studies. For example, understanding latent heat of melting and freezing helps explain seasonal energy exchanges in nature and design of heating systems that control phase changes in industrial processes.
- Sketch and explain a heating curve for water from -10°C to 110°C showing locations of latent heat absorption.
- Explain what happens on the heating curve when heat supply stops during a plateau segment.
- Why does pressure cooker cook food faster? Relate to boiling point changes with pressure.
- Describe qualitatively a phase diagram showing regions for solid, liquid and gas and the meaning of the triple point (basic idea).
- No new algebraic formula beyond Q = mcΔT and Q = mL used on segments.
Thermal Conductivity and Insulation
Thermal conductivity explained
Thermal conductivity is a property that measures how effectively a material transfers heat by conduction. Materials with high conductivity, like copper and aluminium, transfer heat rapidly; materials with low conductivity, like wood, wool and polystyrene, transfer heat slowly and act as insulators. Conductivity is determined by how easily particles and electrons can exchange energy within the material.
Factors affecting steady heat conduction
In steady conduction through a slab, the rate of heat transfer depends on the temperature difference, the cross-sectional area, the thickness of the material and its thermal conductivity. While the full Fourier's law is treated in higher classes, the practical trends are: increasing area increases heat flow; increasing thickness decreases heat flow; and materials with lower conductivity reduce heat flow. These ideas guide choices in thermal insulation and heat sink design.
Insulation principles
Insulation reduces heat loss by restricting all three modes of heat transfer. Good insulation traps still air (a poor conductor) in pockets to reduce conduction and convection. Reflective surfaces reduce radiation. For highest insulation, vacuum layers prevent conduction and convection almost entirely; this principle is used in Thermos flasks and some building panels.
Common applications
Buildings use materials like foam, mineral wool and double-glazed windows to reduce heat loss. Clothing uses trapped air layers and low-conductivity fabrics. Thermos flasks combine a vacuum and reflective surfaces. Heat sinks use high-conductivity metals with large surface area and fins to increase heat transfer to the surrounding air, aiding cooling of electronics.
Design trade-offs
Insulation improves energy efficiency but adds cost and thickness. In some systems, quick heat removal is desired (engines, electronics), so designers use conductive materials and active cooling. In others, like homes or storage tanks, insulation minimises unwanted heat flow. The best choice balances thermal performance, weight, cost and durability.
Class experiments
Students can compare cooling rates of hot water in different containers to see the effect of conductivity and insulating layers. Observations should control for lid, surface area and starting temperature. Discussing results in terms of conductivity and insulation principles reinforces theoretical learning with practical evidence.
- Compare cooling of hot water in a metal cup and a thermos flask and explain difference.
- Explain why double-glazed windows reduce heat loss from a room.
- Describe why wearing several layers of clothing keeps a person warmer than a single thick layer.
- Why are heat sinks on computer processors made of metal with large surface area?
- No specific formula required for Class 9; qualitative relations discussed.
Practical Heat Experiments and Safety
Typical practicals
Classroom experiments for heat include measuring linear expansion of solids, determining specific heat of a metal by calorimetry, finding latent heat of fusion of ice, observing conduction along rods and convection in liquids, and recording heating curves. Each experiment links theory to observations and strengthens measurement and reasoning skills.
Preparing for experiments
Good preparation includes reading the procedure, checking apparatus for damage, and ensuring correct materials (balances, thermometers, calorimeters). Estimate expected values to choose suitable ranges for measurements. Prepare data tables and sketch diagrams so that recording results is systematic and errors are easier to spot.
Performing experiments accurately
Key practices: measure masses and temperatures carefully; ensure thermal contact between objects and thermometers; stir liquids gently to obtain uniform temperature; allow sufficient time for equilibrium; and use insulated containers to reduce heat loss. When heating solids, support them properly and avoid sudden cooling which may crack glassware.
Sources of error and how to reduce them
Common errors: heat lost to surroundings during transfer, thermometer not immersed properly, not accounting for calorimeter heat capacity, and timing inaccuracies. Reduce errors by working quickly yet carefully when transferring hot samples, using lids on calorimeters, calibrating thermometers if possible, and repeating measurements to obtain averages.
Safety precautions
Follow basic safety: wear goggles and heatproof gloves when handling hot objects; use tongs and clamps; never point a heated test tube at anyone; keep flammable materials away from burners; and be cautious with steam and boiling liquids. Clean up spills promptly and handle broken glassware safely. Know locations of safety equipment like fire extinguishers and first-aid kits.
Recording and reporting
Present data in neat tables with units, show calculations step by step, and quote final results with correct units and uncertainty estimates when possible. Discuss possible errors and suggest improvements. A clear lab report including objective, method, raw data, processing, result and conclusion demonstrates understanding and scientific practice.
- Outline steps to measure the specific heat of a metal using a calorimeter and list sources of error.
- List safety precautions when heating a beaker on a Bunsen burner.
- Explain how to reduce heat loss when measuring latent heat of fusion of ice.
- Describe how to calibrate a simple thermometer using ice point and boiling point (qualitative).
- Use Q = mcΔT and Q = mL in calculations; include calorimeter heat in balance: heat_lost = heat_gained + calorimeter
Heat Engines and Efficiency (Introductory)
Definition and concept
A heat engine converts thermal energy into mechanical work by exploiting a temperature difference between a hot source and a cold sink. Energy supplied as heat partly becomes useful work and partly is rejected as waste heat. While detailed thermodynamic cycles are beyond Class 9, the basic energy flow and the idea of efficiency are important and accessible.
Energy balance in engines
If a heat engine receives heat Q_H from a high-temperature source and rejects heat Q_C to a cold sink, the work done by the engine is W = Q_H - Q_C by conservation of energy. This shows that some heat must be expelled to the cold reservoir; no engine can convert all input heat into work because Q_C cannot be zero for a continuous cyclic process.
Efficiency
Efficiency η measures how effectively a heat engine converts heat input into useful work: η = W / Q_H = 1 - Q_C / Q_H. Efficiency is a dimensionless fraction often expressed as a percentage. Higher efficiency means less fuel is needed for the same work. Real engines have efficiencies far below 100% due to friction, heat losses, incomplete combustion and other irreversibilities.
Practical examples
Car engines, steam turbines, and gas turbines are examples where fuel combustion provides heat. In a car, chemical energy of petrol becomes heat, then partly becomes mechanical work to move the car; much energy is lost as heat in the exhaust and radiator. Improving insulation, better combustion control and lowering friction increase real efficiency.
Refrigerators and heat pumps
Reverse devices move heat from cold to hot regions using work input; a refrigerator removes heat from the inside and dumps it to the room slightly above ambient temperature. This requires work done by a compressor. Understanding engines and reverse cycles qualitatively helps explain household appliances and energy use.
Environmental and practical considerations
Engine efficiency affects fuel consumption and emissions. Higher efficiency reduces greenhouse gas emissions per unit work. Simple calculations of efficiency, even at Class 9 level, show why waste heat recovery and energy-saving measures are important in industry and daily life.
- A heat engine receives 500 J of heat and performs 150 J of work. Calculate its efficiency.
- Explain why a fridge must reject heat to the surroundings even while cooling the inside.
- Describe qualitatively why no engine can be 100% efficient.
- Discuss ways to increase efficiency of a simple steam engine in principle (reduce losses).
- Energy balance: Q_H = W + Q_C
- Efficiency: η = W / Q_H = 1 - Q_C / Q_H
Climate, Weather and Heat Transfer
Solar heating and uneven warming
The Sun is the primary energy source for Earth's climate. Solar radiation warms land and ocean surfaces differently because of differing heat capacities and reflectivity (albedo). Land heats and cools faster than water because water has higher specific heat. These differences create temperature gradients that drive atmospheric motion and weather patterns.
Convection and atmospheric circulation
Warm air near the surface rises due to lower density, and cooler air sinks, forming convection cells. On local scales this causes sea breezes and land breezes: during the day land warms faster, creating low pressure and a breeze from sea to land; at night the reverse happens. On global scales, differential heating of equator and poles drives large-scale circulation and trade winds.
Role of latent heat
Latent heat released during condensation of water vapour fuels storms: when moist air rises and cools, water vapour condenses releasing latent heat that warms the air and encourages further rising, leading to cloud formation and storm development. This release of latent heat is central to the dynamics of hurricanes and thunderstorms.
Greenhouse effect, basic idea
Certain atmospheric gases (carbon dioxide, methane, water vapour) absorb and re-radiate infrared radiation from Earth, trapping heat and raising surface temperatures. The natural greenhouse effect keeps Earth warm enough for life; increases in greenhouse gases from human activity enhance this warming, influencing climate patterns and extremes.
Human influences and urban effects
Urban areas often show higher temperatures than surrounding rural areas (urban heat island) because buildings and pavements absorb and retain heat, and vegetation is reduced. Local land use, deforestation and irrigation change local temperature and humidity by altering heat capacity, evapotranspiration and surface albedo.
Practical links
Understanding heat transfer helps design passive heating and cooling: orienting buildings to sun, using thermal mass to store heat, employing insulation and reflective surfaces, and planning green cover to reduce urban warming. These measures save energy and make living spaces comfortable while responding to regional climate conditions.
- Explain how a sea breeze forms during the daytime using heat transfer ideas.
- Why is the city area often warmer than surrounding countryside at night? Discuss causes.
- Describe how forest cover affects local temperature and humidity.
- Explain in simple terms how the greenhouse effect warms the Earth.
- No new numerical formulas; use concepts of heat transfer and specific heat where needed.
Evaporation, Boiling and Humidity
Evaporation explained
Evaporation is the process where molecules at the surface of a liquid gain enough energy to escape into the gas phase at temperatures below the boiling point. Because the most energetic molecules leave first, the average kinetic energy of the remaining liquid decreases and cooling occurs. Evaporation rate depends on temperature, surface area, air movement and humidity.
Boiling and vapour pressure
Boiling occurs when the vapour pressure of the liquid equals external pressure and bubbles of vapour form throughout the liquid. The boiling point is the temperature at which this happens for the current pressure. At lower atmospheric pressure (high altitude) the boiling point falls, so water boils at lower temperatures on mountains.
Humidity and comfort
Humidity is the amount of water vapour in air. Absolute humidity is mass of vapour per volume; relative humidity compares current vapour amount with maximum possible at that temperature. High relative humidity makes evaporation from skin slower, reducing cooling and causing discomfort. Air conditioning often removes moisture to improve comfort.
Evaporative cooling and applications
Sweating cools the body because evaporation uses latent heat of vaporisation drawn from the skin. Fans increase evaporation by moving air away from the skin surface. Evaporative coolers use water evaporation to cool air in dry climates. Industrial drying, clothes drying and cooling towers in power plants all use evaporation principles.
Practical observations and safety
Evaporation causes humidity to vary with temperature: warm air can hold more water vapour. Boiling liquids produce hot vapour that can cause burns; steam carries latent heat and is dangerous on contact with skin. In cooking, lower boiling points at high altitudes require adjustments in cooking times and techniques.
Measurement and prediction
Meteorological charts use humidity and temperature to predict dew point and precipitation. Understanding evaporation and boiling helps in everyday tasks like drying clothes, using fans, and operating pressure cookers which increase boiling point by raising pressure, thereby cooking food faster.
- Explain why wet clothes dry faster on a windy day compared to a calm day.
- Why does the body cool when sweat evaporates? Mention latent heat.
- Describe why a kettle boils faster at sea level than on a high mountain (consider pressure).
- How does relative humidity affect comfort in hot weather?
- Qualitative treatment; use Q = mL if calculating heat involved in evaporation or boiling.
Radiation, Absorption and Emission
Nature of thermal radiation
Thermal radiation is electromagnetic radiation emitted by all bodies because of their temperature. This emission occurs at all temperatures, but the intensity and distribution across wavelengths depend strongly on temperature. Hotter objects emit more radiation overall and shift their emission towards shorter wavelengths. For temperatures common on Earth, most thermal radiation is in the infrared part of the spectrum, which we feel as heat but cannot see.
Emission and absorption
Every surface both emits and absorbs radiation. The rate at which a surface emits or absorbs depends on its temperature and its surface properties. Dark, rough or matte surfaces generally absorb and emit radiation efficiently; shiny or polished surfaces reflect much of the radiation. This is why a black surface in sunlight heats up faster than a white or reflective one: it absorbs a larger fraction of incident solar radiation.
Emissivity and absorptivity
Two useful qualitative concepts are emissivity and absorptivity. Emissivity describes how well a real surface emits radiation compared to an ideal black body at the same temperature. Absorptivity describes how well it absorbs incoming radiation. In simple terms, a good absorber is also a good emitter at the same wavelength. These ideas help in selecting coatings and materials for thermal control—for example, black-painted solar collectors to absorb sunlight, and shiny foils to reflect heat.
Radiation without a medium
Unlike conduction and convection, radiation needs no material medium. This allows heat from the Sun to travel through the vacuum of space to warm Earth. In vacuum or high-altitude situations, radiative exchanges become the dominant way objects lose or gain heat. Spacecraft use reflective surfaces and radiators to manage heat because they cannot rely on convection to carry away excess heat.
Practical effects and observations
Students can observe several simple facts: wearing white or light-coloured clothes reflects sunlight and keeps one cooler; a polished metal roof reflects more solar radiation than a dark roof; on clear nights, ground surfaces lose heat faster by radiation to the cold sky than they do on cloudy nights because clouds act like a radiative blanket. Infrared thermometers or cameras make radiative heat patterns visible, showing warm and cool regions on objects.
Design applications
Knowledge of radiative properties is used in building design, cooking devices, solar energy systems and thermal insulation. Combining reflective layers with insulating air gaps reduces both radiation and conduction. In passive solar design, surfaces and glazing are chosen to maximise solar gain in winter and minimise overheating in summer. Understanding both emission and absorption is essential to control heat flow efficiently.
Safety and experiments
Simple classroom experiments: compare temperatures of black and white surfaces under the same lamp, or measure cooling of polished versus matte cans placed outdoors at night. Discuss how emissivity affects readings from infrared thermometers. These hands-on observations reinforce the concepts of absorption, emission and radiative balance in everyday contexts.
- Explain why wearing a white shirt on a hot sunny day feels cooler than a black shirt.
- Describe why vacuum flasks have a shiny inner surface to reduce heat loss.
- How does a solar cooker use radiation to heat food?
- Explain why on a clear night the ground cools faster by radiation than on a cloudy night.
- Qualitative treatment; mention that radiation intensity rises strongly with temperature (detailed Stefan-Boltzmann law is for higher classes).
Practical Applications: Cooking, Refrigeration and Insulation
Cooking and heat transfer
Cooking processes use conduction, convection and radiation in various combinations. A frying pan transfers heat by conduction from its base to the food; boiling uses convection within the liquid to distribute heat; grilling uses radiation from hot elements or flames. Choosing cookware with good conductivity and even heat distribution reduces hot spots and improves cooking quality.
Pressure cookers and boiling point
A pressure cooker traps steam, raising pressure inside the pot; this increases the boiling point of water so food reaches higher temperatures and cooks faster. This is a direct application of how external pressure affects boiling temperature and is widely used in Indian kitchens for energy-efficient cooking.
Refrigeration principles
Refrigerators move heat from the interior (cold space) to the ambient room (warmer space) by using a refrigerant that evaporates and condenses. The cycle requires work from a compressor. Although the detailed thermodynamic cycle is advanced, the basic idea is that evaporation inside the fridge absorbs heat (cooling the interior) and condensation outside releases it.
Insulation in buildings and devices
Insulation reduces unwanted heat flow. In houses, walls, roofs and windows are insulated to lower heating bills and improve comfort. Insulating hot water tanks or using lids on cooking vessels prevents heat loss. Industrial applications use multi-layer insulation and vacuum panels for high performance. Proper insulation balances cost, space and thermal efficiency.
Everyday energy saving
Simple measures save energy: using lids while cooking, covering hot water tanks, using pressure cookers, choosing appliances with good thermal performance, and wearing appropriate clothing for climate. Awareness of how heat flows helps make choices that reduce fuel consumption and greenhouse gas emissions.
Trade-offs and safety
Designers balance insulation and heat transfer depending on needs: fast cooling requires good conduction and convection removal, while storage needs low heat transfer. Safety matters: pressure cookers must have safety valves and be used correctly to prevent accidents. Refrigeration systems require proper maintenance to avoid leaks and inefficiency.
- Explain why pressure cookers cook food faster using boiling point and trapped steam ideas.
- Describe why refrigerators must have coils at the back to release heat.
- List household measures to reduce heat loss in winter.
- Why are cooking pans often made of metals with good conductivity and sometimes with non-stick coatings?
- Qualitative applications; Q = mcΔT and Q = mL appear in energy computations for cooking and refrigeration cycles at basic level.
Revision: Solving Heat Problems
General approach
Solving heat problems effectively requires a clear step-by-step method. First identify the system and list known quantities with units (masses, temperatures, specific heats, latent heats). Decide whether the process involves sensible heat (temperature change) or latent heat (phase change) or both. Choose appropriate formulas: Q = mcΔT for temperature changes and Q = mL for phase changes. Use energy conservation to relate heat lost and gained, and solve for the unknown.
Common problem categories
Typical questions include: computing heat required to raise temperature of a mass, mixing problems where hot and cold substances reach equilibrium, calorimetry to determine specific heat, phase change calculations using latent heat, and thermal expansion problems using ΔL = αLΔT. Recognising which category a problem belongs to speeds up solution.
Energy balance and sign conventions
Write clear energy balance equations: heat lost by hot body = heat gained by cold body (+ calorimeter or surroundings). Keep track of signs: when using magnitudes in heat balance take positive values for heat amounts and set up equality between lost and gained; when using signed Q, be consistent with direction. Check units at each step—mass in kg, specific heat in J kg^-1 K^-1, temperatures in °C (ΔT in °C or K).
Worked problem structure
Show intermediate steps: substitute numerical values with units, perform calculations showing powers of ten, and write final answer with correct units and sensible significant figures. Estimate whether the result is reasonable by comparing with rough benchmarks (e.g., heating 1 kg water by 1°C needs about 4200 J).
Common pitfalls and checks
Watch for omitted calorimeter heat, forgetting latent heat when a state change occurs, mixing masses without temperature equilibrium, or using wrong units. If an answer seems unphysical (negative temperature or absurdly large energy), recheck equations and units. Repeating problems with varied numbers builds skill and speed.
Practice and connection to experiments
Link numerical practice to lab experiences: relate calculated heats to observed temperature changes, and compare experimental calorimetry results with theoretical predictions while discussing sources of error. This builds intuition for orders of magnitude and fosters better understanding of the physical meaning behind equations.
- Outline steps and solve: 0.5 kg water at 30°C is heated to 80°C. Calculate heat required.
- Solve mixing problem: 200 g hot lead at 150°C placed in 500 g water at 20°C; final temperature 25°C. Find specific heat of lead.
- Calculate expansion: 1.5 m brass rod heated from 20°C to 120°C with α for brass = 19 × 10^-6 /°C. Find ΔL.
- A 100 g ice at 0°C is added to 300 g water at 30°C. Find final temperature (qualitative or simple calculation using latent heat).
- Q = mcΔT
- Q = mL
- ΔL = α L ΔT
- Heat balance: heat_lost = heat_gained
Key Concepts
- Temperature
- A measure of the average kinetic energy of particles in a substance.
- Heat
- Energy transferred between bodies due to a temperature difference.
- Internal energy
- Total energy of microscopic motion and interactions of particles in a body.
- Specific heat capacity
- Heat required to raise unit mass of a substance by 1°C or 1 K.
- Latent heat
- Heat absorbed or released during a change of state at constant temperature per unit mass.
- Conduction
- Heat transfer through a medium by particle collisions or electron movement with no bulk motion.
- Convection
- Heat transfer by bulk movement of a fluid due to density differences caused by temperature changes.
- Radiation
- Transfer of energy by electromagnetic waves that does not require a medium.
- Thermal expansion
- Increase in size of an object when its temperature increases.
- Coefficient of linear expansion
- Fractional change in length per degree temperature change for a material.
- Calorimetry
- Experimental method to measure heat exchanged between bodies and determine specific or latent heat.
- Heat capacity
- Heat required to raise the temperature of an object by one degree; equals mc for uniform bodies.
- Efficiency
- Ratio of useful work output to heat input for a heat engine.
- Evaporation
- Surface phenomenon where molecules escape from liquid to gas below boiling point, causing cooling.
- Boiling point
- Temperature at which liquid's vapour pressure equals external pressure and bubbles form throughout.
Practice Questions
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A 200 g copper block at 100°C is placed in 500 g of water at 20°C. What is the final temperature if specific heat of copper is 390 J kg^-1 K^-1 and water is 4200 J kg^-1 K^-1? / 100°C पर रखा हुआ 200 ग्राम तांबे का ब्लॉक 20°C पर मौजूद 500 ग्राम पानी में डाला जाता है। यदि तांबे का विशिष्ट उष्मा 390 J kg^-1 K^-1 और पानी का 4200 J kg^-1 K^-1 है, तो अन्तिम तापमान क्या होगा?
Show answer
Use heat lost by copper = heat gained by water. m_c c_c (T_i,c - T_f) = m_w c_w (T_f - T_i,w). Put m_c=0.2 kg, c_c=390, T_i,c=100; m_w=0.5 kg, c_w=4200, T_i,w=20. 0.2×390×(100 - T_f)=0.5×4200×(T_f - 20). Solve: 78(100 - T_f)=2100(T_f - 20). 7800 - 78T_f = 2100T_f - 42000. 7800 + 42000 = 2178 T_f. 49800 = 2178 T_f. T_f ≈ 22.86°C. / तांबे से छोड़ा गया ताप = पानी द्वारा ग्रहण किया गया ताप। समीकरण: 0.2×390×(100 - T_f)=0.5×4200×(T_f - 20)। 78(100 - T_f)=2100(T_f - 20)। हल करने पर T_f ≈ 22.86°C।
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Calculate heat required to raise temperature of 3 kg water from 25°C to 75°C. Use c = 4200 J kg^-1 K^-1. / 3 кг पानी का तापमान 25°C से 75°C तक बढ़ाने के लिए कितनी ऊष्मा चाहिए? c = 4200 J kg^-1 K^-1 लो।
Show answer
Q = mcΔT = 3×4200×(75 - 25)=3×4200×50=630000 J or 6.3×10^5 J. / Q = mcΔT = 3×4200×50 = 630000 J = 6.3×10^5 J।
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A 0.25 m long brass rod (α = 19×10^-6 /°C) is heated from 20°C to 120°C. Find its increase in length. / एक 0.25 m लंबा पीतल का छड़ (α = 19×10^-6 /°C) 20°C से 120°C तक गरम किया जाता है। लंबाई में वृद्धि कितनी होगी?
Show answer
Use ΔL = α L ΔT. ΔT = 100°C. ΔL = 19×10^-6 × 0.25 × 100 = 19×10^-6 × 25 = 475×10^-6 m = 4.75×10^-4 m = 0.475 mm. / ΔL = αLΔT = 19×10^-6×0.25×100 = 4.75×10^-4 m = 0.475 mm।
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Explain why ice floats on water and why maximum density of water occurs near 4°C. / समझाइए कि बर्फ पानी पर तैरती क्यों है और पानी का अधिकतम घनत्व लगभग 4°C पर क्यों होता है।
Show answer
Ice floats because its solid structure is more open—molecules form a lattice with greater average separation, making ice less dense than liquid water. Water reaches maximum density near 4°C because cooling from higher temperatures reduces molecular motion and allows closer packing until about 4°C; below 4°C hydrogen-bonded structures open up and density decreases as it approaches freezing. / बर्फ इसलिए तैरती है क्योंकि उसकी ठोस संरचना खुली होती है—अणु एक लट्टिस बनाते हैं जिसमें औसत दूरी अधिक होती है, इसलिए बर्फ का घनत्व तरल पानी से कम होता है। पानी का अधिकतम घनत्व लगभग 4°C पर होता है क्योंकि ऊपर के तापमान से ठंडा होने पर अणु करीब आते हैं और घनत्व बढ़ता है, पर 4°C के नीचे हाइड्रोजन बॉन्डिंग के कारण संरचना फिर खुलने लगती है और घनत्व घटता है।
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Define specific latent heat of fusion and give its unit. / 'Fusion का विशिष्ट गुप्त ऊष्मा' परिभाषित कीजिए और इसका मात्रक बताइए।
Show answer
Specific latent heat of fusion is the heat required to change unit mass of a substance from solid to liquid at its melting point without change in temperature. Unit is joule per kilogram (J kg^-1). / विशिष्ट गुप्त ऊष्मा (फ्यूज़न) वह ऊष्मा है जो किसी पदार्थ के एक इकाई द्रव्यमान को उसके गलने के बिंदु पर बिना तापमान परिवर्तन के ठोस से द्रव में बदलने के लिए चाहिए। मात्रक J kg^-1 है।
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A heat engine absorbs 2000 J from a hot source and rejects 1500 J to the cold sink. What is its efficiency? / एक हीट इंजन गर्म स्रोत से 2000 J ऊष्मा ग्रहण करता है और ठंडे सिंक को 1500 J निकाल देता है। इसकी दक्षता कितनी है?
Show answer
Efficiency η = 1 - Q_C / Q_H = 1 - 1500/2000 = 1 - 0.75 = 0.25 = 25%. Alternatively W = Q_H - Q_C = 500 J, η = W/Q_H = 500/2000 = 0.25. / दक्षता η = 1 - Q_C/Q_H = 1 - 1500/2000 = 0.25 = 25%। या W = 2000 - 1500 = 500 J, η = 500/2000 = 25%।
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Why does sweating cool the body? / पसीना सूखने से शरीर ठंडा क्यों होता है?
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Sweat evaporates from the skin and evaporation requires latent heat of vaporisation. The energy needed for evaporation is taken from the skin as heat, lowering the skin's temperature and cooling the body. Evaporation is faster with wind and low humidity. / पसीना त्वचा से वाष्पीभूत होता है और वाष्पीकरण के लिए वाष्पीकरण की गुप्त ऊष्मा चाहिए। यह ऊष्मा त्वचा से ली जाती है जिससे त्वचा का तापमान घटता है और शरीर ठंडा होता है। हवा होने और आर्द्रता कम होने पर वाष्पीकरण तेज होता है।
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A student places a hot metal spoon and a wooden spoon in boiling water. Which feels hotter when taken out and why? / एक छात्र उबलते पानी में एक गरम धातु की चम्मच और एक लकड़ी की चम्मच डालता है। निकालने पर कौन सी चम्मच अधिक गर्म महसूस होगी और क्यों?
Show answer
The metal spoon will feel hotter to touch because metals have higher thermal conductivity and transfer heat to the skin faster, producing a stronger sensation of heat. The wooden spoon has low conductivity and transfers heat slowly, so it feels less hot though its temperature may be similar. / धातुई चम्मच त्वचा को ऊष्मा अधिक तेज़ी से स्थानांतरित करती है क्योंकि धातुओं की ऊष्म चालकता अधिक होती है, इसलिए वह अधिक गर्म महसूस होती है। लकड़ी की चम्मच की चालकता कम होने से वह धीरे-धीरे ही गर्मी स्थानांतरित करती है और कम गर्म लगती है।
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Calculate heat required to convert 0.1 kg of ice at 0°C to water at 0°C. Latent heat of fusion of ice = 3.3×10^5 J kg^-1. / 0°C पर 0.1 kg बर्फ को 0°C पर पानी में बदलने के लिए कितनी ऊष्मा चाहिए? बर्फ का गलन गुप्त ऊष्मा = 3.3×10^5 J kg^-1।
Show answer
Q = mL = 0.1 × 3.3×10^5 = 3.3×10^4 J = 33000 J. / Q = mL = 0.1×3.3×10^5 = 3.3×10^4 J = 33000 J।
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Explain with a diagram how a thermos flask reduces both conduction and radiation. / एक चित्र के साथ समझाइए कि कैसे एक थर्मस फ्लास्क चालकता और विकिरण दोनों को कम करती है।
Show answer
A thermos flask has a double-walled container with a vacuum or insulating material between walls to prevent conduction and convection. The inner surface is shiny to reflect thermal radiation, reducing radiative heat loss. The narrow neck and stopper reduce heat transfer by blocking conduction and convection. (Students should draw cross-section showing inner and outer walls, vacuum space, shiny surfaces and stopper.) / थर्मस फ्लास्क में दो दीवारें होती हैं जिनके बीच वैक्यूम या इन्सुलेशन भरा होता है जिससे चालकता और संवहन रुकते हैं। भीतरी सतह पॉलिश या चमकदार होती है जो विकिरण को परावर्तित कर उसे कम करती है। संकीर्ण गला और ढक्कन संवहन व चालकता को और घटाते हैं। (छात्र क्रॉस-सेक्शन बनाकर भीतरी/बाहरी दीवारें, वैक्यूम स्थान, चमकदार सतह और ढक्कन दिखाएँ।)
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