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Chapter 3 — Study of Acids, Bases and Salts

Class 10 · Chemistry

Overview

This unit introduces acids, bases and salts: their nature, properties, reactions and importance in everyday life and industry. You will learn how to identify acids and bases using indicators and pH, how neutralisation produces salts and water, and how different salts form from combinations of acids and bases or by reactions of metals, oxides and carbonates with acids. The unit covers preparation methods for common laboratory salts, solubility behaviour and crystallisation techniques, hydrolysis of salts and how salt composition affects solution acidity or basicity. Practical laboratory techniques such as titration and writing ionic and net ionic equations are emphasised. Students will also study acid-base strength, conjugate pairs and simple equilibrium calculations that explain why some salts give acidic or basic solutions. Safety, waste disposal and environmental effects such as acid rain are part of the curriculum to build responsible laboratory practice. Understanding this unit matters because acids, bases and salts are found in food, medicines, cleaning products, soils and industrial processes; learning these concepts helps students solve real-life problems such as neutralising spills, treating water and deciding safe handling of household chemicals.

Learning Objectives

  • Describe the characteristic properties of acids and bases and identify them using indicators.
  • Calculate and interpret pH values and represent acidity or basicity on the pH scale.
  • Write balanced chemical, ionic and net ionic equations for reactions involving acids, bases and salts.
  • Explain neutralisation and predict the salt produced from given acid-base combinations.
  • Prepare common salts in the laboratory by various methods and obtain pure crystalline salts.
  • Classify salts by origin and predict whether their aqueous solutions will be acidic, basic or neutral.
  • Explain hydrolysis of salts qualitatively and use Ka, Kb and Kw relationships where required.
  • Perform titration experiments and use titration data to calculate concentrations of acids or bases.

Topics in this chapter

16 topics · tap a topic title to jump straight to it.

🧪1

Fundamental Definitions: Acids, Bases and Salts

Basic definitions and working ideas
Begin by understanding what is meant by acids, bases and salts in aqueous chemistry. An acid, in simple terms for Class 10, is a substance that increases the concentration of hydrogen ions (H+) or hydronium ions (H3O+) when dissolved in water. A base increases the concentration of hydroxide ions (OH-) or accepts H+ from water. A salt is the ionic compound produced when the hydrogen ion of an acid is replaced by a metal or another cation during neutralisation or other reactions.

Everyday significance
Many everyday substances are acids, bases or salts. Citrus juice and vinegar are acidic; household ammonia and many soaps are basic; table salt is a familiar ionic salt. Recognising these common forms helps relate laboratory observations to real life.

Observable properties
Acids typically taste sour (but never taste chemicals in the lab), change blue litmus red, turn methyl orange red and conduct electricity in solution. Bases taste bitter and feel slippery, turn red litmus blue and often change phenolphthalein to pink. Salts show varied properties: some are soluble and conduct electricity in solution, others are insoluble and form precipitates.

Strong and weak types
Classify acids and bases as strong or weak according to how completely they ionise in water. Strong acids like HCl and HNO3 ionise almost completely; weak acids like acetic acid ionise only partially. Similarly, NaOH and KOH are strong bases that dissociate fully, while ammonia is a weak base that reacts with water to form OH- only to a limited extent. Strength affects conductivity, pH and reaction behaviour.

Formation of salts
Salts form by neutralisation, displacement and other reactions. For example, when a metal reacts with an acid it forms a salt and hydrogen gas. When a metal oxide reacts with an acid it forms salt and water. Understanding these patterns allows you to predict which salt will form from given reagents.

Practical classroom approach
Focus on naming common acids, bases and salts, recognising their observable tests with indicators, and writing simple equations. This foundation supports later topics such as titration, hydrolysis and salt preparation.

📌 Examples
  • HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) showing salt formation by neutralisation
  • Vinegar (contains CH3COOH) turns blue litmus red illustrating acidic behaviour
  • Ammonia solution turns red litmus blue showing basic property
🧮 Formulas
  1. Acid (general): HA ⇌ H+ + A-
  2. Base (ionic): MOH → M+ + OH-
  3. Neutralisation: Acid + Base → Salt + Water
📊 Visual ideas
Schematic of ionic dissociation of a strong acid into H+ and its anion
Diagram showing neutralisation where H+ + OH- → H2O
📏2

Indicators, pH Scale and Measurement

Understanding pH
The pH scale is a way to express how acidic or basic a solution is using a single number: pH = -log10[H+]. At 25°C, neutral pure water has [H+] = 1.0×10^-7 M, so pH 7. Values below 7 indicate acidic solutions (higher [H+]) and values above 7 indicate basic solutions (higher [OH-]). Each pH unit represents a tenfold change in hydrogen ion concentration, so pH 3 is ten times as acidic as pH 4.

Methods of measuring pH
There are several practical tools: litmus papers and universal indicator papers give approximate pH by colour comparison; single indicators like phenolphthalein and methyl orange change colour over a limited pH range and are useful in titrations; a pH meter provides accurate digital pH readings if properly calibrated and maintained. Understand limitations: temperature affects pH readings and indicators give qualitative or semi-quantitative results only.

Indicators and their ranges
Different indicators suit different pH ranges. Litmus is a simple indicator: blue litmus turns red in acids and red litmus turns blue in bases. Methyl orange changes from red in strong acid to yellow in neutral/alkaline region (useful for strong acid–weak base titrations). Phenolphthalein is colourless in acid and turns pink around pH 8–10 (useful for weak acid–strong base titrations). Universal indicator is a mixture that gives different colours across the whole pH range and is useful for estimating pH at a glance.

Practical examples and interpretation
Measuring pH of common substances helps build intuition: lemon juice pH ≈ 2–3 (acidic), milk ≈ 6–6.5 (slightly acidic), pure water pH 7, household soap solutions pH 9–10 (basic). In experiments, choose an indicator whose transition range includes the expected equivalence pH for accurate end-point detection.

Calculations with pH
Remember relationships: pH + pOH = 14 at 25°C and [H+] = 10^{-pH}. Using these relations you can convert between [H+], [OH-], pH and pOH. This quantitative understanding connects indicator colours to ion concentrations and helps explain reaction outcomes in titrations and hydrolysis.

📌 Examples
  • Red litmus turns blue in NaOH and blue litmus turns red in HCl
  • Phenolphthalein is colourless in vinegar (acid) and pink in dilute NaOH
  • pH comparison: lemon juice pH ~2.5, distilled water pH 7, soap solution pH ~9
🧮 Formulas
  1. pH = -log10[H+]
  2. \[[H+] = 10^{-pH}\]
  3. pH + pOH = 14 (at 25°C)
📊 Visual ideas
pH scale labelled with typical household substances and indicator colour ranges
Plot showing exponential decrease of [H+] with increasing pH
💧3

Ionisation, Dissociation and Water's Role

How acids and bases behave in water
When acids and bases dissolve in water, they either ionise or dissociate into their constituent ions. Strong acids such as HCl and HNO3 ionise nearly completely: HCl → H+ + Cl-. Strong ionic bases like NaOH dissociate fully into Na+ and OH-. Weak acids (e.g., CH3COOH) and weak bases (e.g., NH3) establish equilibria in water with only partial ionisation: CH3COOH ⇌ H+ + CH3COO- and NH3 + H2O ⇌ NH4+ + OH-.

Water's self-ionisation and Kw
Water itself undergoes self-ionisation: 2H2O ⇌ H3O+ + OH- often simplified to H2O ⇌ H+ + OH-. The product of hydrogen and hydroxide ion concentrations is constant at a given temperature, Kw = [H+][OH-] = 1.0×10^-14 at 25°C. This constant means that if [H+] increases, [OH-] decreases proportionally. In pure water both concentrations are 1.0×10^-7 M.

Equilibrium constants Ka and Kb
For weak acids and bases, measure strength by equilibrium constants. For a weak acid HA, Ka = [H+][A-]/[HA]. For a weak base B, Kb = [BH+][OH-]/[B]. These constants quantify how far the equilibrium lies to the right (more ionisation) or left (less ionisation). The product Ka × Kb for a conjugate pair equals Kw.

Approximate calculations
In many Class 10 problems you can use simplifications. For a weak acid of concentration c with Ka ≪ c, let x be [H+] produced; Ka ≈ x^2/c so x ≈ sqrt(Ka·c). This gives a quick estimate of pH and is valid when the percentage ionisation is small. Always check the approximation by ensuring x ≪ c; otherwise solve the full quadratic expression from Ka = x^2/(c-x).

Consequences in experiments
The degree of ionisation affects conductivity, pH and reaction rates. Strong electrolytes conduct better and react faster in acid-base reactions. Understanding dissociation and ionisation in water explains why some salts hydrolyse, why titration curves have specific shapes, and why buffers maintain pH. Emphasise using correct ionic forms when writing equations for reactions in solution.

📌 Examples
  • Complete ionisation: HCl(aq) → H+(aq) + Cl-(aq)
  • Partial ionisation: CH3COOH(aq) ⇌ H+(aq) + CH3COO-(aq)
  • Water ionisation: H2O ⇌ H+ + OH- with [H+]=[OH-]=1.0×10^-7 M at 25°C
🧮 Formulas
  1. Ka = [H+][A-]/[HA]
  2. Kb = [BH+][OH-]/[B]
  3. Kw = [H+][OH-] = 1.0×10^-14 (at 25°C)
  4. Ka × Kb = Kw
📊 Visual ideas
Schematic showing equilibrium position for weak and strong acids in water
Plot illustrating how [H+] and [OH-] vary inversely as pH changes
🧂4

Neutralisation Reactions and Salt Formation

Neutralisation concept
Neutralisation is the reaction where an acid and a base react to form a salt and usually water. The essential ionic process is H+ combining with OH- to form H2O. For strong acids and bases the net ionic equation is simply H+ + OH- → H2O. Neutralisation reactions are often exothermic, releasing heat.

Types of neutralisation
Neutralisation can involve strong or weak reactants. With a strong acid and strong base (e.g., HCl + NaOH), both ionise fully and the resulting salt solution is typically neutral. With a strong acid and weak base (e.g., HCl + NH3) an acidic salt such as NH4Cl forms and the solution tends to be acidic. With a weak acid and strong base (e.g., CH3COOH + NaOH) a basic salt such as sodium acetate forms and the solution tends to be basic. For weak acid + weak base the final pH depends on relative Ka and Kb values.

Writing molecular, ionic and net ionic equations
Practice writing balanced molecular equations and then converting to ionic forms by splitting soluble strong electrolytes into ions. Remove spectator ions to obtain the net ionic equation highlighting the main chemical change. For example: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) becomes H+(aq) + OH-(aq) → H2O(l) as the net ionic equation.

Salt formation patterns
Salts inherit the cation from the base and the anion from the acid. Therefore, using different acids or bases gives different salts: H2SO4 + 2NaOH → Na2SO4 + 2H2O gives sodium sulphate; CuO + H2SO4 → CuSO4 + H2O yields copper(II) sulphate when a metal oxide reacts with an acid. Metals reacting with acids give metal salts and hydrogen gas: Zn + H2SO4 → ZnSO4 + H2.

Applications and titration
Neutralisation is the basis for titration, where a solution of known concentration neutralises another to determine its concentration. In everyday life neutralisation is used in antacids, agriculture (adding lime to acidic soil), waste treatment and various industrial processes. Understanding the stoichiometry and predicting the resulting salt are essential skills in this unit.

📌 Examples
  • HCl + NaOH → NaCl + H2O (strong acid + strong base → neutral salt)
  • HCl + NH3 → NH4Cl (strong acid + weak base → acidic salt)
  • CH3COOH + NaOH → CH3COONa + H2O (weak acid + strong base → basic salt)
🧮 Formulas
  1. General: Acid + Base → Salt + Water
  2. Net ionic (strong acid + strong base): H+ + OH- → H2O
📊 Visual ideas
Titration curve for strong acid versus strong base with steep rise at equivalence
Schematic showing ion recombination forming a salt lattice plus water
🧂5

Methods for Preparing Salts in the Lab

Overview of preparation methods
In Class 10 you meet several practical ways to prepare salts: (1) Neutralisation of an acid by a base or metal oxide/hydroxide, (2) Reaction of a metal with an acid, (3) Reaction of a carbonate or bicarbonate with acid, (4) Double displacement reactions where one product is an insoluble salt that precipitates. Each method suits particular salts depending on reactants and solubility.

Neutralisation with concentration and crystallisation
To prepare soluble salts like sodium chloride or copper sulphate, neutralise the acid with the base and remove excess reactant if present. Filter to remove insoluble residues and concentrate the filtrate by gentle evaporation until near saturation. Allow the hot concentrated solution to cool slowly so crystals form. Filter, wash crystals with small amounts of cold distilled water to remove impurities, and dry them carefully at a suitable temperature to avoid loss of water of crystallisation if a hydrate is desired.

Precipitation method
For insoluble salts like barium sulphate, mix aqueous solutions of two soluble salts whose ions form an insoluble product. The insoluble salt precipitates and can be separated by filtration, washed and dried. Use solubility rules to predict which combinations give precipitates. Precipitation is fast and useful for qualitative tests and for preparing insoluble salts for analysis.

Metal + acid and carbonate reactions
Reactive metals such as zinc or magnesium react with acids to produce the corresponding metal salt and hydrogen gas; collect gas only when safe to do so. Carbonates and bicarbonates react with acids to give salt, water and carbon dioxide. These reactions are used to prepare chlorides and nitrates from metal carbonates and acids.

Purity and hydrates
Impurities remain in the mother liquor during crystallisation. Slow cooling and seeding encourage formation of pure crystals. Many salts form hydrates—crystals that incorporate water molecules—so heating must be controlled. For example, copper(II) sulphate pentahydrate is blue but loses water to become white anhydrous CuSO4 on strong heating.

Safety and waste
Follow safety rules: wear goggles and gloves, add acid to water when diluting, avoid inhaling vapours, and neutralise wastes before disposal as per school guidelines. Small-scale preparations illustrate principles; industrial methods scale and include purification steps absent in school labs.

📌 Examples
  • Make CuSO4·5H2O by reacting CuO with dilute H2SO4, filtering, concentrating and crystallising
  • Obtain BaSO4 by mixing BaCl2(aq) and Na2SO4(aq); BaSO4 precipitates as a white solid
  • Prepare NaCl by neutralising NaOH with HCl, evaporating the solution and crystallising
🧮 Formulas
  1. Metal oxide + Acid → Salt + Water (e.g., CuO + H2SO4 → CuSO4 + H2O)
  2. Carbonate + Acid → Salt + Water + CO2 (e.g., CaCO3 + 2HCl → CaCl2 + H2O + CO2)
  3. Metal + Acid → Salt + H2 (e.g., Zn + H2SO4 → ZnSO4 + H2)
📊 Visual ideas
Flow chart of crystallisation steps: reaction → filtration → concentration → crystallisation → filtration → drying
Sketch of precipitate forming when two soluble salt solutions are mixed
🔬6

Solubility, Solubility Rules and Crystallisation

Definition and temperature dependence
Solubility is the maximum amount of solute that dissolves in a given amount of solvent at a particular temperature to form a saturated solution. For many solid salts, solubility increases with temperature, though exceptions exist. Gas solubility in water typically decreases with increasing temperature. Solubility curves graph the amount dissolved per 100 g water versus temperature and are essential for planning crystallisation.

Simple solubility rules
Certain ions produce salts that are generally soluble: all sodium, potassium and ammonium salts are soluble, and nitrates and acetates are usually soluble. Chlorides, bromides and iodides are generally soluble except with Ag+, Pb2+ and Hg2+. Sulphates are usually soluble except BaSO4, PbSO4 and CaSO4 (sparingly soluble). Carbonates, phosphates and sulphides are mostly insoluble except when combined with alkali metals or ammonium. These rules let you predict precipitation on mixing solutions.

Precipitation and net ionic representation
When two solutions are mixed and an insoluble salt forms, write the molecular equation and convert to ionic form to identify spectator ions. The net ionic equation shows the ions that form the precipitate. For example mixing AgNO3 and NaCl yields AgCl(s): Ag+ + Cl- → AgCl(s). Filtering separates the precipitate; wash and dry it if required.

Crystallisation technique
To obtain pure crystals, use the solubility–temperature relationship. Dissolve solute in hot water to near saturation, filter to remove insoluble impurities, then cool slowly so crystals form while impurities remain in solution. Filter out crystals and wash them with a little cold solvent. Slow crystallisation and proper washing increase purity; rapid cooling may trap impurities.

Industrial and environmental significance
Solubility controls processes such as mineral extraction, wastewater treatment and manufacture of fertilisers. In the environment, solubility influences nutrient mobility in soils and the fate of pollutants. Understanding solubility rules helps predict which ions will remain in solution and which will precipitate under given conditions.

📌 Examples
  • AgNO3(aq) + NaCl(aq) → AgCl(s)↓ + NaNO3(aq) showing precipitation of insoluble AgCl
  • Using a solubility curve of KNO3 to find how much crystallises on cooling a hot saturated solution
  • BaCl2 + Na2SO4 → BaSO4(s)↓ + 2NaCl where BaSO4 precipitates because it is insoluble
🧮 Formulas
  1. Saturated solution: contains the maximum dissolved solute for a given temperature
  2. Solubility depends on lattice energy vs hydration energy for ionic salts
📊 Visual ideas
Solubility curve of KNO3 versus temperature used to plan crystallisation
Sketch of precipitate forming in a beaker when two solutions are mixed
🧂7

Hydrolysis of Salts and Predicting Solution pH

What is salt hydrolysis?
Hydrolysis of salts refers to reactions in which ions produced from a dissolved salt react with water to give H+ or OH- and thus change the pH of the solution. Whether hydrolysis occurs and its direction depend on the strengths of the parent acid and base from which the salt was formed.

Classification by parent acid/base strengths
Use this practical rule: if a salt comes from a strong acid and a strong base, its solution is neutral (e.g., NaCl). If it comes from a strong acid and a weak base, the cation hydrolyses to produce H+ and the solution is acidic (e.g., NH4Cl). If from a weak acid and a strong base, the anion hydrolyses to produce OH- and the solution is basic (e.g., NaCH3COO). For salts of weak acid + weak base, both ions hydrolyse and the pH depends on the relative magnitudes of Ka and Kb.

Mechanisms and simple equilibria
Examples: CH3COO- + H2O ⇌ CH3COOH + OH- (anion hydrolysis giving OH-); NH4+ + H2O ⇌ NH3 + H3O+ (cation hydrolysis giving H3O+). The extent of hydrolysis depends on ion concentrations and the Ka/Kb values related by Ka×Kb=Kw. For classroom work, qualitative prediction is usually sufficient; for quantitative problems, set up equilibrium expressions and solve using Ka or Kb and concentration.

Applications and tests
Hydrolysis explains why solutions of ammonium salts taste sour or why acetate solutions feel slippery and test basic. It is important in water chemistry and agriculture; for example, salt accumulation in soil can shift pH and affect crop growth. In analytical chemistry recognition of hydrolysis is crucial when choosing indicators for titrations and when preparing buffer solutions.

Observational cues
Use indicators or pH paper to test whether a salt solution is acidic or basic. Combine knowledge of parent acid and base strengths with observed pH to identify likely hydrolysis. Emphasise clear reasoning: identify parent acid/base, decide which ion hydrolyses, show the hydrolysis reaction and conclude the pH tendency.

📌 Examples
  • NH4Cl(aq) gives acidic solution because NH4+ hydrolyses: NH4+ + H2O ⇌ NH3 + H3O+
  • NaCH3COO(aq) gives basic solution because CH3COO- hydrolyses: CH3COO- + H2O ⇌ CH3COOH + OH-
  • NaCl(aq) is neutral because neither Na+ nor Cl- hydrolyses significantly
🧮 Formulas
  1. Anion hydrolysis: A- + H2O ⇌ HA + OH-
  2. Cation hydrolysis: B+ + H2O ⇌ BOH + H+
📊 Visual ideas
Bar diagram comparing pH of NaCl (≈7), NH4Cl (<7) and NaCH3COO (>7)
Flowchart: identify parent acid/base → determine hydrolysing ion → predict pH
🧪8

Conjugate Acid-Base Pairs and Strength Relationships

Conjugate pairs explained
When an acid donates a proton it becomes its conjugate base; when a base accepts a proton it becomes its conjugate acid. For HA ⇌ H+ + A-, HA and A- form a conjugate acid-base pair. Recognising conjugate pairs helps explain why some salts hydrolyse and why buffers work.

Inverse relationship of strengths
An important idea is that the stronger an acid is, the weaker its conjugate base will be. Strong acids such as HCl have negligible tendency to reaccept a proton, so Cl- is a very weak base and does not hydrolyse to affect pH. By contrast, weak acids like acetic acid have conjugate bases (acetate) that are relatively stronger and can hydrolyse to produce OH- in solution.

Ka, Kb and their product
For a conjugate pair Ka and Kb are linked by Kw: Ka × Kb = Kw (at a given temperature). This relation allows calculation of one constant if the other is known, and gives a quantitative basis to the inverse-strength idea. For example, if a weak acid has Ka = 1.8×10^-5, the Kb of its conjugate base is Kw/Ka ≈ 5.6×10^-10 at 25°C.

Implications for salts and buffers
Knowing conjugate strengths helps predict whether a salt will give acidic, basic or neutral solution and is central to buffer behaviour. A buffer contains a weak acid and its conjugate base (or weak base and its conjugate acid). The balance between them allows the solution to resist pH change when small amounts of acid or base are added.

Class 10 focus
Emphasise qualitative reasoning and simple numerical examples to illustrate relationships. Practice identifying conjugate pairs in chemical equations, using Ka/Kb conceptually to predict hydrolysis and relating these ideas to real examples such as acetate and ammonium salts. Detailed equilibrium calculations requiring logarithms are included only in manageable classroom problems.

📌 Examples
  • CH3COOH (weak acid) and CH3COO- (conjugate base); CH3COO- hydrolyses to give OH-
  • HCl (strong acid) and Cl- (very weak conjugate base) where Cl- does not hydrolyse
  • Using Ka × Kb = Kw to find Kb for acetate if Ka of acetic acid is known
🧮 Formulas
  1. Conjugate pair: HA ⇌ H+ + A-
  2. Ka × Kb = Kw
📊 Visual ideas
Diagram showing inverse relationship of Ka and Kb for conjugate pairs
Sketch of buffer region on titration curve where pH changes slowly
⚖️9

Titration Technique, Indicators and Calculations

Principle of titration
Titration is a controlled laboratory method to find the concentration of an acid or base by reacting it with a reagent of known concentration called the titrant. The titrant is delivered in measured volumes from a burette into the analyte until stoichiometric neutralisation is achieved. The equivalence point is the theoretical moment when moles of H+ equal moles of OH- according to the balanced equation; the end point is signalled by an indicator or a pH change and should coincide closely with the equivalence point.

Apparatus and accurate procedure
Essential apparatus includes a clean, calibrated burette for precise volume delivery, a pipette to transfer a measured volume of analyte into a conical flask, a white tile to view colour change clearly, and a suitable indicator. Rinse the burette with titrant and the pipette with analyte before use. Fill the burette, note the initial reading, add titrant slowly with constant swirling of the flask, and stop when the indicator changes colour persistently. Record the final burette reading and calculate the volume used. Repeat titration to obtain concordant results and take the mean of close readings for accuracy.

Choice of indicator and equivalence pH
Select an indicator whose transition range contains the expected pH at equivalence. For a strong acid vs strong base titration the equivalence pH is about 7 so indicators like methyl orange or phenolphthalein can be used. For a weak acid titrated with a strong base the equivalence pH is >7 and phenolphthalein (pH 8.2–10) is appropriate. For a strong acid vs weak base the equivalence pH is <7 so methyl orange (pH 3.1–4.4) is better. Universal indicator shows a range of colours but its large colour change can make precise end-point detection harder.

Calculations and stoichiometry
Use mole relationships to calculate unknown concentrations. For mono-basic acid and mono-basic base, apply M1V1 = M2V2 (with volumes in litres and M as mol L^-1). For polyprotic acids or polybasic bases include stoichiometric factors: M1V1 × n1 = M2V2 × n2 where n is number of reactive H+ or OH- per formula unit. Convert volumes to litres when using molarity units or adopt consistent units for the algebra. Show working with correct significant figures and units.

Sources of error and good laboratory practice
Common errors include parallax reading of burette, overshooting the end point, not rinsing the apparatus, using the wrong indicator, and temperature effects. To reduce error: read the burette at eye level, add titrant dropwise near the end point, repeat titrations for concordant values and wash glassware between experiments. A well-run titration demonstrates the link between chemical stoichiometry and precise quantitative analysis.

📌 Examples
  • Titrating 25.0 cm3 of an unknown monoprotic acid with 0.10 M NaOH that uses 30.0 cm3: M_acid = (0.10×30.0)/25.0 = 0.12 M
  • For titrating 20.0 cm3 of 0.1 M H2SO4 with NaOH, account for two H+ per H2SO4: 0.1×20×2 = 0.1×V_NaOH → V_NaOH = 40 cm3
  • Choosing phenolphthalein for titration of acetic acid with NaOH since equivalence pH >7
🧮 Formulas
  1. M1V1 × n1 = M2V2 × n2 (general titration equation)
  2. For monoprotic systems: M1V1 = M2V2
📊 Visual ideas
Titration curve showing pH vs volume of titrant with steep slope near equivalence
Schematic of burette, conical flask and correct reading method to avoid parallax
⚗️10

Ionic and Net Ionic Equations in Aqueous Reactions

Role of ionic equations
Many reactions in aqueous solution involve ions rather than intact molecules. Writing full ionic equations makes visible which species exist as free ions and which recombine to form new substances. Net ionic equations, obtained by removing spectator ions, present the essential chemical change and make it simpler to understand reaction mechanisms, predict products and balance charge and mass at the ionic level.

Procedure to derive net ionic equations
Start with a balanced molecular equation including physical states (aq, s, g, l). Next, split all strong electrolytes (soluble salts, strong acids and strong bases) into their constituent ions for the ionic equation. Keep weak electrolytes, undissolved solids, liquids and gases in molecular form. Identify and cancel spectator ions—those present unchanged on both sides—to reveal the net ionic equation which contains only species that participate in the chemical change.

Common categories of net ionic reactions
Typical net ionic reactions include neutralisation (H+ + OH- → H2O), precipitation (e.g., Ag+ + Cl- → AgCl(s)), and gas evolution (e.g., CO3^2- + 2H+ → CO2(g) + H2O). Recognising the category helps predict the product: precipitation yields an insoluble solid, neutralisation yields water and a salt in solution, and reactions of carbonates with acids produce carbon dioxide gas.

Examples with stepwise reasoning
Mixing BaCl2 and Na2SO4: write the molecular equation BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq). Ionic equation shows Ba2+(aq) + 2Cl-(aq) + 2Na+(aq) + SO4^2-(aq) → BaSO4(s) + 2Na+(aq) + 2Cl-(aq). Cancel Na+ and Cl- to get net ionic: Ba2+(aq) + SO4^2-(aq) → BaSO4(s). This highlights that barium and sulphate ions form the precipitate while sodium and chloride remain spectators.

Importance in analytical and preparative chemistry
Net ionic equations guide qualitative tests for ions (e.g., chloride, sulphate, carbonate) and support quantitative work such as gravimetric analysis where a precipitate is collected and weighed. In salt preparation, ionic thinking explains why certain impurities remain in solution and how precipitation can remove or separate ions. Practice converting molecular to ionic and net ionic forms to build fluency and clear chemical reasoning.

📌 Examples
  • Molecular: Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g) Net ionic: CO3^2-(aq) + 2H+(aq) → H2O(l) + CO2(g)
  • BaCl2(aq) + Na2SO4(aq) → 2NaCl(aq) + BaSO4(s) Net ionic: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
  • HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) Net ionic: H+(aq) + OH-(aq) → H2O(l)
🧮 Formulas
  1. Write soluble ionic compounds as dissociated ions in ionic equations; keep solids, gases and weak electrolytes in molecular form
  2. Net ionic equation obtained by cancelling spectator ions
📊 Visual ideas
Flowchart showing molecular → ionic → net ionic equation construction
Diagram showing spectators remain in solution while precipitate forms
🧪11

Acids, Bases and Salts in Everyday Life and Industry

Household acids, bases and salts
Students meet acids, bases and salts in many familiar items. Citrus fruits and vinegar are acidic; soaps and many cleaning agents are basic; table salt is a common ionic salt. Baking soda (sodium bicarbonate) neutralises stray acids in cooking or cleaning; washing soda (sodium carbonate) is used for laundry. Recognising these items by their properties (taste, indicator tests, effect on materials) connects classroom concepts to everyday experience.

Biological examples and pH control
The human body relies on acid-base chemistry: stomach acid (HCl) aids digestion and kills microbes, while blood maintains a tightly controlled pH near 7.4 using buffer systems (bicarbonate/carbonic acid). Enzymes work within narrow pH ranges, so even small pH changes can disrupt biological processes. Medicines such as antacids (Mg(OH)2, CaCO3) neutralise excess stomach acid, illustrating practical neutralisation.

Industrial applications of acids and bases
Industries use acids and bases in large quantities. Sulphuric acid is central to fertiliser manufacture and metal processing; hydrochloric acid is used in pickling and cleaning metals; sodium hydroxide is key for soap and paper manufacture. Salts like ammonium sulphate and potassium nitrate supply nitrogen and potassium for agriculture. Industrial chemistry scales the laboratory reactions but follows the same principles of neutralisation, precipitation and crystallisation.

Environmental concerns and mitigation
Acid rain results from atmospheric conversion of sulphur and nitrogen oxides into acids; it lowers soil and water pH, damages vegetation and corrodes buildings. Industrial effluents with acidic or alkaline character must be treated before discharge, often by neutralisation and removal of hazardous ions. Agricultural runoff containing fertiliser salts affects lake ecology. Awareness and treatment technologies reduce damage and are part of environmental chemistry.

Safety and responsible use at home and school
Many household chemicals are corrosive in concentrated form. Never mix cleaners without guidance—mixing bleach with acids can release chlorine gas. Use gloves and goggles when handling concentrated reagents in school. Teach students simple safe practices like neutralising small acid spills with baking soda and reading labels for hazard information.

Practical classroom activities
Measure pH of local water, soft drinks and soaps to build practical skills. Perform neutralisation demonstrations with safe reagents and discuss real-world connections like lime application to acidic soil. These activities deepen understanding and promote safe, environmentally aware behaviour.

📌 Examples
  • Using baking soda to neutralise excess vinegar during cooking
  • Antacid tablets containing magnesium hydroxide neutralise stomach acid: Mg(OH)2 + 2HCl → MgCl2 + 2H2O
  • Lime (calcium oxide/hydroxide) added to acidic soil raises pH improving crop yield
🧮 Formulas
  1. Neutralisation examples like antacid action: Mg(OH)2 + 2HCl → MgCl2 + 2H2O
  2. Agricultural liming concept: Ca(OH)2 + 2H+ → Ca2+ + 2H2O (conceptual)
📊 Visual ideas
Bar chart comparing pH of household liquids such as lemon juice, milk, soap solution and water
Sketch linking emissions → acid rain → effects on plants and buildings
🧪12

Reactions of Metals and Carbonates with Acids

Metals with acids: general behaviour
Many metals react with dilute mineral acids to produce a corresponding metal salt and hydrogen gas. The general pattern is: Metal + Acid → Salt + H2. Whether a metal reacts depends on its tendency to lose electrons (reactivity). Metals higher than hydrogen in the reactivity series (such as magnesium, zinc, iron) will displace hydrogen from acids, whereas metals lower than hydrogen (such as copper, silver, gold) will not react with dilute acids under normal conditions.

Observations and experimental evidence
When a reactive metal is added to acid, bubbling or effervescence shows hydrogen gas evolving. The gas can be tested (with care and teacher permission) by collecting a small sample and applying a lit splint; a characteristic 'pop' indicates hydrogen. The solution gradually gains metal cations, forming salts such as zinc sulphate, magnesium chloride or iron(II) sulphate depending on the metal and acid used. Temperature and concentration affect reaction rate.

Predicting products and stoichiometry
Write balanced equations to predict products: Zn + H2SO4 → ZnSO4 + H2; Mg + 2HCl → MgCl2 + H2. Use mole ratios to calculate amounts of hydrogen produced or salt formed. For metals with multiple oxidation states, pay attention to typical oxidation behaviour (e.g., iron forms Fe2+ in dilute acid unless oxidising conditions are present).

Carbonates and bicarbonates with acids
Carbonates and bicarbonates react with acids to form salt, water and carbon dioxide gas. The general equations are: Carbonate + Acid → Salt + H2O + CO2 and Bicarbonate + Acid → Salt + H2O + CO2. For instance CaCO3 + 2HCl → CaCl2 + H2O + CO2 and NaHCO3 + HCl → NaCl + H2O + CO2. Effervescence and the formation of CO2 are easy experimental signs; CO2 turns lime water milky, confirming its presence.

Environmental and practical relevance
These reactions have practical applications: acid treatment of ores produces soluble metal salts; carbonates neutralise acidic wastes; and effervescence in baking uses bicarbonates as leavening agents. Environmentally, acid rain reacts with carbonate rocks and building materials causing erosion by dissolving carbonates and releasing CO2. Understanding these reactions helps explain corrosion, mineral weathering and some industrial extraction methods.

Safety and classroom practice
Handle acids and reactive metals with care: wear goggles and gloves, perform reactions in a fume-ventilated area and avoid collecting flammable hydrogen gas near open flames. When testing for carbonates, add dilute acid and observe effervescence; capture gas only with proper apparatus and supervision. Emphasise stoichiometric reasoning and safe technique in laboratory exercises.

📌 Examples
  • Zn + H2SO4 → ZnSO4 + H2 (metal displacing hydrogen from acid)
  • CaCO3 + 2HCl → CaCl2 + H2O + CO2 (carbonate with acid producing CO2)
  • No reaction: Cu + HCl → no reaction under normal conditions because copper is less reactive
🧮 Formulas
  1. Metal + Acid → Salt + Hydrogen
  2. Carbonate + Acid → Salt + Water + CO2
  3. Bicarbonate + Acid → Salt + Water + CO2
📊 Visual ideas
Schematic reactivity series showing metals above hydrogen will displace H2 from acids
Sketch of lime water test turning milky when CO2 passes through
🧂13

Preparation, Properties and Hydrates of Important Salts

Overview of important salts
This topic studies common salts such as sodium chloride, copper(II) sulphate pentahydrate, potassium nitrate and calcium carbonate. Examine how each salt is prepared, its appearance, solubility, and behaviour on heating. This connects preparation methods to real material properties and practical uses in agriculture, laboratories and industry.

Hydrates: nature and significance
Hydrated salts contain definite numbers of water molecules trapped in their crystal lattice. For example copper(II) sulphate pentahydrate (CuSO4·5H2O) is bright blue because water molecules coordinate to Cu2+ and affect light absorption. Heating the hydrate can remove water to give the anhydrous salt (CuSO4), which is white or grey. Some hydrates change colour on losing water; this property is useful as a visual test for dehydration or for indicating moisture.

Preparation methods linked to properties
Prepare salts by neutralisation followed by crystallisation, precipitation, or by direct reaction of elements where suitable. For example, CuSO4·5H2O is made by reacting copper oxide with dilute sulphuric acid and then crystallising the solution. KNO3 is often prepared by reaction and then purified by exploiting its steep solubility increase with temperature; hot saturated solution is cooled for crystallisation, yielding relatively pure, well-formed crystals.

Care in drying and storage
Some salts are deliquescent (absorb moisture) and must be stored in dry containers, while others effloresce (lose water) when exposed to air. When collecting crystals, wash with small amounts of cold solvent to remove mother liquor, and dry at temperatures that do not remove waters of crystallisation unless the anhydrous form is desired. Label containers and store salts away from incompatible materials.

Physical properties and uses
Observe colour, crystalline form, solubility and conductivity. Copper sulphate is used in agriculture as a fungicide and in school labs for demonstrations; sodium chloride is essential in food and industry; potassium nitrate is a fertiliser and oxidiser. Properties such as solubility versus temperature and hydration behaviour determine how salts are used and handled commercially.

Laboratory practice to ensure purity
For pure crystals: remove insoluble impurities by hot filtration, concentrate the clear filtrate to near saturation, allow slow cooling for large crystals, collect by filtration, wash with cold solvent and dry. Record observations such as colour change on heating to identify hydrates and practice safe handling and disposal of residues.

📌 Examples
  • Preparation of CuSO4·5H2O by reacting CuO with dilute H2SO4 followed by crystallisation
  • Obtaining NaCl crystals by evaporating the solution from neutralisation of NaOH and HCl
  • Using solubility-temperature relation to crystallise KNO3 from hot saturated solution
🧮 Formulas
  1. Hydrate notation: CuSO4·5H2O
  2. Thermal dehydration example: CuSO4·5H2O → CuSO4 + 5H2O (on heating)
📊 Visual ideas
Solubility curve of KNO3 showing increased solubility at higher temperature used for recrystallisation
Diagram of blue hydrated CuSO4 crystals and white anhydrous salt after heating
🧪14

Acidic, Basic and Neutral Salts: Classification and Prediction

Classifying salts by resulting pH
Salts dissolved in water may make the solution acidic, basic or neutral depending on the strengths of the parent acid and base. Use the practical rule: strong acid + strong base → neutral salt; strong acid + weak base → acidic salt; weak acid + strong base → basic salt; weak acid + weak base → pH depends on Ka and Kb values of the parents.

Reasoning through conjugate species
This behaviour follows from conjugate acid-base ideas. A salt contains the cation from the base and the anion from the acid. If the cation is the conjugate acid of a weak base (e.g., NH4+), it can donate H+ to water and produce an acidic solution. If the anion is the conjugate base of a weak acid (e.g., CH3COO-), it can accept H+ from water producing OH- and making the solution basic. For neutral salts like NaCl, both ions are very weak conjugates and do not hydrolyse significantly.

Predictive examples
NH4Cl: NH4+ hydrolyses giving acidic solution. NaCH3COO: CH3COO- hydrolyses giving basic solution. Na2SO4: neutral because both Na+ and SO4^2- are conjugates of strong base/acid (NaOH and H2SO4 respectively). When both parents are weak, for example ammonium acetate, the resulting pH depends on relative Ka and Kb: compare values to decide whether solution is slightly acidic, neutral or basic.

Testing and confirmation
Use indicators or pH paper to test predictions. Qualitative answers are typically sufficient in Class 10: identify parent acid and base strengths, state which ion hydrolyses and whether pH will be <7, =7 or >7. For higher precision, calculations using Ka and Kb can be performed, but these are limited to simpler problems at this level.

Applications
This understanding helps in choosing salts for buffers, anticipating taste and chemical behaviour of food additives, and managing soil pH in agriculture. It also guides indicator choice in titrations: knowing expected equivalence pH helps select an indicator whose transition range matches that pH.

📌 Examples
  • NH4Cl solution acidic; NaCH3COO solution basic; NaCl solution neutral
  • NH4NO3 (from strong acid HNO3 and weak base NH3) gives acidic solution
  • NH4CH3COO (weak acid + weak base) pH depends on Ka and Kb magnitudes
🧮 Formulas
  1. Rule summary: Strong acid + Strong base → neutral salt; Strong acid + Weak base → acidic salt; Weak acid + Strong base → basic salt
  2. Hydrolysis examples: CH3COO- + H2O ⇌ CH3COOH + OH-; NH4+ + H2O ⇌ NH3 + H3O+
📊 Visual ideas
Flowchart to predict pH of a salt: identify parent acid/base strengths → decide which ion hydrolyses → predict pH
Bar chart comparing pH of NaCl, NH4Cl and NaCH3COO solutions
🔬15

Introduction to Buffers and Simple Equilibrium Calculations

Buffer concept (qualitative)
A buffer is a solution that resists changes in pH when small amounts of acid or base are added. Typical laboratory buffers are mixtures of a weak acid and its conjugate base (e.g., acetic acid + sodium acetate) or a weak base and its conjugate acid (e.g., ammonia + ammonium chloride). The equilibrium between the acid and its conjugate base absorbs added H+ or OH- and stabilises pH within a limited range.

How buffers work
When H+ is added to an acetate buffer, the acetate ion reacts to form acetic acid: H+ + CH3COO- → CH3COOH, minimising pH change. When OH- is added, acetic acid reacts: CH3COOH + OH- → CH3COO- + H2O, again resisting pH shift. The effective buffering range lies approximately within ±1 pH unit of the pKa of the weak acid in the buffer.

Introducing simple equilibrium calculations
Class 10 includes introductory equilibrium work for weak acids and bases. For a weak acid HA with initial concentration c that ionises to produce x amount of H+, write Ka = x^2/(c - x). If Ka ≪ c, approximate x ≈ sqrt(Ka·c). Then pH = -log10[H+]. Apply similar reasoning for weak bases to estimate [OH-] and pH, using Kb and Kw relations. Always check the approximation by comparing x to c; if x is not much smaller than c, solve the quadratic equation for accurate results.

Ka, Kb and Kw relationships
For conjugate pairs Ka and Kb are related by Ka × Kb = Kw at a given temperature. Use Kw = 1.0×10^-14 at 25°C to interconvert acid and base strengths. These relations underpin predictions about salt hydrolysis and buffer behaviour and allow simple numerical problems that are appropriate for Class 10 practice.

Practical classroom focus
Teach buffer principles with simple demonstrations: prepare an acetate buffer and show pH change on small additions of acid/base. Work through sample calculations for dilute weak acid solutions using the approximation method. Emphasise concept over heavy algebra, ensuring students can set up equations, apply approximations, and understand when approximations fail.

📌 Examples
  • Acetic acid + sodium acetate make a buffer that resists pH change on small additions of acid or base
  • Estimate pH of 0.10 M acetic acid (Ka = 1.8×10^-5): x ≈ sqrt(Ka·c) ≈ 1.34×10^-3 M, pH ≈ 2.87
  • Use Kw to find [OH-] if [H+] = 1.0×10^-5 M: [OH-] = 1.0×10^-14 / 1.0×10^-5 = 1.0×10^-9 M
🧮 Formulas
  1. Ka = [H+][A-]/[HA]
  2. Kb = [BH+][OH-]/[B]
  3. Ka × Kb = Kw
  4. pH = -log10[H+]
📊 Visual ideas
Sketch of buffer region on a titration curve showing flatter pH change
Graph for solubility vs temperature used earlier in crystallisation (relevant to preparing salts)
🌍16

Safety, Disposal and Environmental Effects

Laboratory safety rules
Handling acids, bases and salts requires common-sense safety. Always wear safety goggles, gloves and an apron. Add acid to water slowly when diluting concentrated acids; never pour water into concentrated acid as heat and splashing can occur. Use fume hoods or well-ventilated areas for volatile or strong acids and bases. Keep incompatible chemicals apart and be familiar with first-aid measures for chemical splashes.

Disposal of wastes
Neutralise small volumes of acidic or alkaline wastes before disposal according to school or institutional rules, bringing pH close to neutral. Never pour reactive metal residues, strong oxidisers or large volumes of concentrated acid/base down the drain. Label waste containers and follow local guidelines for hazardous waste. Neutralisation followed by appropriate dilution and disposal may be allowed for small, non-hazardous school lab wastes.

Environmental impacts
Acid rain, formed by conversion of SO2 and NOx emissions to sulphuric and nitric acids, lowers the pH of rain and harms forests, aquatic ecosystems and buildings. Industrial effluents containing acidic or alkaline wastes can alter the chemistry of receiving waters and soils. Proper treatment—neutralisation, precipitation, filtration and biological treatment—reduces environmental harm. Agricultural runoff containing fertiliser salts impacts aquatic life by changing ionic strength and nutrient levels.

Green chemistry and mitigation
Industries adopt pollution-control measures such as flue-gas desulphurisation, catalytic converters and wastewater neutralisation tanks. In the laboratory, minimise waste by using microscale procedures, recycle reagents where possible, and substitute less hazardous chemicals. Teaching environmental stewardship and correct disposal habits prepares students for responsible practice.

Emergency procedures and classroom practice
Know the location of eyewash stations, safety showers and spill kits. For skin contact with acids or bases rinse immediately with plenty of water and seek help. For small acid spills neutralise carefully with sodium bicarbonate and mop up; for base spills neutralise with dilute acid if instructed and safe. Regularly discuss these procedures so that students are prepared and confident during practical work.

📌 Examples
  • Neutralising a small acid spill using sodium bicarbonate until effervescence stops, then cleaning up
  • Industrial example: neutralising acidic wastewater with lime (Ca(OH)2) before discharge
  • Household caution: do not mix bleach with acids because chlorine gas can form
📊 Visual ideas
Flowchart of steps to take after skin contact with acid or base: rinse → notify teacher → seek further care
Schematic showing neutralisation treatment of acidic effluent by addition of base and subsequent precipitation of metal hydroxides

Key Concepts

Acid
A substance that increases hydrogen ion concentration ([H+]) in aqueous solution.
Base
A substance that increases hydroxide ion concentration ([OH-]) in aqueous solution or accepts H+.
Salt
An ionic compound formed by the neutralisation of an acid by a base or by other ion-exchange reactions.
pH
A logarithmic measure of acidity defined as pH = -log10[H+].
Indicator
A substance that changes colour at specific pH ranges and indicates acidity or basicity qualitatively.
Neutralisation
The reaction of hydrogen ions and hydroxide ions to form water, generally producing a salt as well.
Hydrolysis (of salts)
Reaction of ions from a dissolved salt with water that produces H+ or OH- changing the solution pH.
Ka
The acid dissociation constant measuring the strength of a weak acid in water.
Kb
The base dissociation constant measuring the strength of a weak base in water.
Kw
The ion-product constant of water, Kw = [H+][OH-], equal to 1.0×10^-14 at 25°C.
Conjugate acid-base pair
Two species related by the gain or loss of a proton, for example HA and A-.
Titration
A quantitative technique to determine concentration by neutralising with a standard solution.
Solubility
The maximum amount of solute that can dissolve in a specified amount of solvent at a given temperature.
Precipitation
Formation of an insoluble solid when two solutions containing ions are mixed.
Hydrate
A crystalline salt that includes fixed numbers of water molecules in its structure.
Buffer
A solution that resists pH change on addition of small amounts of acid or base.

Practice Questions

  1. Write the ionic and net ionic equation for the reaction between aqueous solutions of sodium sulphate and barium chloride. / सोडियम सल्फेट और बेरियम क्लोराइड के जलीय घोल के बीच प्रतिक्रिया के आयनिक और नेट आयनिक समीकरण लिखिए।
    Show answer

    Ionic equation: 2Na+(aq) + SO4^2-(aq) + Ba2+(aq) + 2Cl-(aq) → 2Na+(aq) + 2Cl-(aq) + BaSO4(s). / आयनिक समीकरण: 2Na+(aq) + SO4^2-(aq) + Ba2+(aq) + 2Cl-(aq) → 2Na+(aq) + 2Cl-(aq) + BaSO4(s). Net ionic equation: Ba2+(aq) + SO4^2-(aq) → BaSO4(s). / नेट आयनिक समीकरण: Ba2+(aq) + SO4^2-(aq) → BaSO4(s).

  2. Predict the pH nature (acidic, basic or neutral) of a 0.1 M solution of ammonium chloride and explain why. / 0.1 M अमोनियम क्लोराइड का जलयुक्त घोल अम्लीय, क्षारीय या तटस्थ होगा, अनुमान लगाइए और कारण बताइए।
    Show answer

    Ammonium chloride solution is acidic because NH4+ is the conjugate acid of the weak base NH3 and hydrolyses with water to produce H3O+, lowering pH. Reaction: NH4+ + H2O ⇌ NH3 + H3O+. / अमोनियम क्लोराइड का घोल अम्लीय होगा क्योंकि NH4+ कमजोर क्षार NH3 का संयुग्म अम्ल है और यह जल के साथ हाइड्रोलाइसिस करके H3O+ बनाता है, जिससे pH घटता है। प्रतिक्रिया: NH4+ + H2O ⇌ NH3 + H3O+.

  3. Calculate the pH of pure water at 25°C. / 25°C पर शुद्ध पानी का pH निकालिए।
    Show answer

    At 25°C pure water has [H+] = 1.0 × 10^-7 M, so pH = -log10(1.0×10^-7) = 7.00. / 25°C पर शुद्ध पानी का [H+] = 1.0 × 10^-7 M होता है, इसलिए pH = -log10(1.0×10^-7) = 7.00।

  4. Describe a safe laboratory method to prepare and obtain pure crystals of copper(II) sulphate starting from copper oxide and dilute sulphuric acid. / कॉपर(II) ऑक्साइड और पतला सल्फ्यूरिक एसिड लेकर कॉपर(II) सल्फेट की शुद्ध क्रिस्टल बनाने और प्राप्त करने का सुरक्षित प्रायोगिक तरीका बताइए।
    Show answer

    React copper oxide with dilute H2SO4 until excess CuO remains (indicated by no further dissolution). Filter the hot solution to remove unreacted CuO. Concentrate the filtrate by gentle evaporation, then allow the concentrated solution to cool slowly to crystallise blue CuSO4·5H2O. Filter crystals, wash with small amount of cold distilled water and dry. Use goggles, gloves and work in a fume-ventilated area. / कॉपर ऑक्साइड को पतले H2SO4 के साथ तब तक मिलाइए जब तक अधिकतम का विलयन न बन जाए (अर्थात् अधिक CuO बचने पर रिएक्शन बंद)। गर्म घोल को फिल्टर करके अवशिष्ट CuO हटा दीजिए। छानने के बाद छन्न द्रव को धीरे-धीरे उबालकर संतृप्त कीजिए और फिर ठंडा होने दीजिए ताकि नीली क्रिस्टल (CuSO4·5H2O) बनें। क्रिस्टल छानकर ठंडे आसुत जल से धोकर सुखाइए। सुरक्षा: चश्मा और दस्ताने पहनें तथा अच्छी हवा वाले स्थान पर कार्य करें।

  5. What colour change would you expect when phenolphthalein is added to (a) dilute HCl (b) dilute NaOH? / जब फेनोल्फथेलीन (phenolphthalein) डाला जाए तो (a) पतला HCl में और (b) पतला NaOH में किस रंग परिवर्तन की अपेक्षा करेंगे?
    Show answer

    (a) In dilute HCl (acidic) phenolphthalein remains colourless. (b) In dilute NaOH (basic) phenolphthalein turns pink. / (a) पतले HCl में फेनोल्फथेलीन रंगहीन रहता है। (b) पतले NaOH में फेनोल्फथेलीन गुलाबी हो जाता है।

  6. A sample of unknown acid of volume 25.0 cm3 is titrated with 0.10 M NaOH and requires 30.0 cm3 to reach end point. If the acid is monoprotic, find its molarity. / 25.0 cm3 अज्ञात एक-प्रोटिक अम्ल का 0.10 M NaOH से टिट्रेशन करने पर 30.0 cm3 NaOH की आवश्यकता पड़ी; अम्ल एक-प्रोटिक है। अम्ल की मोलरता ज्ञात कीजिए।
    Show answer

    Use M1V1 = M2V2: M_acid × 25.0 cm3 = 0.10 M × 30.0 cm3. So M_acid = (0.10 × 30.0)/25.0 = 0.12 M. / M1V1 = M2V2 लागू करें: M_अम्ल × 25.0 = 0.10 × 30.0. अतः M_अम्ल = (0.10 × 30.0)/25.0 = 0.12 M।

  7. Explain why barium sulphate is used as a test for sulphate ions in solution and how the test is performed. / किसी घोल में सल्फेट आयनों के परीक्षण के लिए BaSO4 का उपयोग क्यों किया जाता है और यह परीक्षण कैसे किया जाता है, समझाइए।
    Show answer

    Barium sulphate (BaSO4) is highly insoluble, so adding barium chloride to a solution containing sulphate ions produces a white precipitate of BaSO4: Ba2+(aq) + SO4^2-(aq) → BaSO4(s). To perform the test, add dilute HCl to the sample first to remove carbonate that would give CO2 and interfere, then add BaCl2 solution; formation of white precipitate that is insoluble in acid confirms sulphate. / BaSO4 बहुत कम घुलनशील है, अतः BaCl2 मिलाने पर सल्फेट आयुओं वाली उपस्थिति में सफेद अवक्षेप स्थायी रूप से BaSO4 बनता है: Ba2+(aq) + SO4^2-(aq) → BaSO4(s)। परीक्षण में पहले नमूने में पतला HCl मिलाकर कार्बोनेट हटाया जाता है (जो बाधा बन सकता है), फिर BaCl2 मिलाया जाता है; यदि सफेद अवक्षेप स्थायी रूप से बनता है और एसिड में घुलता नहीं है तो सल्फेट का परीक्षण सकारात्मक माना जाता है।

  8. Explain qualitatively why a salt formed from a weak acid and a strong base gives a basic solution. Give an example. / गुणात्मक रूप से समझाइए कि कमजोर अम्ल और मजबूत क्षार से बनने वाला लवण क्षारीय घोल क्यों देता है। एक उदाहरण दीजिए।
    Show answer

    A salt from a weak acid and strong base contains the conjugate base of the weak acid; this anion hydrolyses with water to produce OH- making the solution basic. Example: sodium acetate (NaCH3COO) contains CH3COO- which reacts: CH3COO- + H2O ⇌ CH3COOH + OH-, producing OH-. / कमजोर अम्ल और मजबूत क्षार से बनता लवण उस कमजोर अम्ल का संयुग्म क्षार होता है; यह अयन जल के साथ हाइड्रोलाइसिस करके OH- बनाता है जिससे घोल क्षारीय होता है। उदाहरण: सोडियम एसेटेट (NaCH3COO) में CH3COO- होता है जो जल के साथ CH3COO- + H2O ⇌ CH3COOH + OH- करता है, जिससे OH- बनते हैं।

  9. Identify the spectator ions in the reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l). / प्रतिक्रिया में NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) दर्शाइए कि कौन-से स्पेकटेटर आयन हैं।
    Show answer

    Write ionic forms: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → Na+(aq) + Cl-(aq) + H2O(l). Spectator ions are Na+ and Cl- since they appear unchanged on both sides. Net ionic: H+ + OH- → H2O. / आयनिक रूप: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → Na+(aq) + Cl-(aq) + H2O(l). स्पेकटेटर आयन Na+ और Cl- हैं क्योंकि वे दोनों ओर अपरिवर्तित हैं। नेट आयनिक: H+ + OH- → H2O।

  10. A student finds that a salt sample dissolves in water and the solution turns blue litmus paper red. What does this indicate about the salt and what further test would you perform? / एक छात्र पाता है कि एक लवण नमूना पानी में घुलता है और घोल नीले लिट्मस कागज को लाल कर देता है। यह लवण के बारे में क्या संकेत देता है और आप कौन-सा अतिरिक्त परीक्षण करेंगे?
    Show answer

    Turning blue litmus red shows the solution is acidic, so the salt likely contains a cation that hydrolyses to produce H+ (e.g., NH4+). The salt may be from a strong acid and weak base. Further test: add a small amount of NaOH; if NH3 gas is released (smell, or test with moist red litmus turning blue), it indicates ammonium salt. Alternatively measure pH with universal indicator or pH paper for confirmation. / नीला लिट्मस लाल होना दर्शाता है कि घोल अम्लीय है; इसलिए लवण में ऐसा कॅटायन हो सकता है जो हाइड्रोलाइसिस करके H+ देता है (उदा. NH4+)। संभवतः यह मजबूत अम्ल और कमजोर क्षार से बना लवण है। अतिरिक्त परीक्षण: थोड़ा NaOH मिलायें; यदि NH3 गैस निकलती है (गंध से या नम लाल लिट्मस का नीला होना), तो यह अमोनियम लवण की पुष्टि होगी। वैकल्पिक रूप से यूनिवर्सल इंडिकेटर या pH पेपर से pH मापकर पुष्टि कीजिए।

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