Overview
This unit studies alcohols, phenols and ethers — three families of oxygen-containing organic compounds important in chemistry, biology and industry. You will learn how these compounds are named, how their molecular structures and bonding affect physical and chemical properties, and how they are prepared in the laboratory and industrially. The unit explains reactions characteristic to each class: for alcohols, substitution, elimination, oxidation and esterification; for phenols, acidity, electrophilic aromatic substitution and coupling reactions; for ethers, formation and cleavage. Mechanisms such as nucleophilic substitution (SN1, SN2), electrophilic aromatic substitution and free radical or ionic oxidations are introduced and applied. Practical skills include identifying functional groups, predicting products, balancing reaction equations and suggesting synthetic routes. The unit also links theory to real-world applications: alcohols and phenols as solvents, antiseptics and intermediates; ethers as solvents and anaesthetics; and environmental or safety aspects like flammability and toxicity. Mastery of this unit prepares you for solving board-level problems, writing reaction mechanisms and designing syntheses, all of which are core skills for Class 12 Chemistry and for further studies in chemistry and related fields.
Learning Objectives
- Classify alcohols, phenols and ethers and name representative compounds using IUPAC rules.
- Explain how structure and bonding determine acidity, boiling point and solubility of alcohols, phenols and ethers.
- Describe and apply laboratory and industrial methods for the preparation of alcohols, phenols and ethers.
- Predict and write mechanisms for common reactions: substitution, elimination, oxidation of alcohols; electrophilic substitution of phenols; and cleavage of ethers.
- Balance equations, identify reagents and conditions and propose multi-step syntheses involving these functional groups.
- Use physical and chemical tests to distinguish between alcohols, phenols and ethers.
- Relate the chemical behaviour of these compounds to real-life uses and safety considerations.
Topics in this chapter
19 topics · tap a topic title to jump straight to it.
Introduction and Classification
What are alcohols, phenols and ethers?
Alcohols are organic compounds with a hydroxyl group (–OH) bonded to a saturated carbon atom. Phenols are compounds where the –OH group is bonded directly to an aromatic ring (commonly a benzene ring). Ethers contain an oxygen atom bonded to two carbon atoms (R–O–R'). Although the functional group oxygen is common to all three, their chemical behaviour differs strongly because of the kinds of carbon atoms to which oxygen is attached and the electronic environment around it.
Classification of alcohols
Alcohols can be classified in several useful ways. By degree: primary (1°) alcohols have the –OH-bearing carbon attached to one other carbon; secondary (2°) have it attached to two; tertiary (3°) to three. By structure: aliphatic alcohols (open chain), cyclic alcohols, allylic and benzylic alcohols (where –OH is next to a double bond or aromatic ring respectively). Polyhydric alcohols contain more than one –OH group and are named diols, triols etc. These classifications are important because reactivity—such as ease of oxidation or the mechanism of substitution—depends on them.
Classification of phenols
Phenols are often classified by the number and positions of –OH groups on the aromatic ring: mono-, di- and polyhydroxy phenols; ortho-, meta- and para- describe relative positions. Some phenols have additional functional groups that strongly influence acidity and reactivity (e.g., nitrophenols are much more acidic).
Classification of ethers
Ethers may be symmetrical (both alkyl groups same) or unsymmetrical. They can be aliphatic or aryl ethers (where one side is aromatic). Cyclic ethers such as epoxides (three-membered) or tetrahydrofuran (five-membered) are distinct because ring strain and geometry change their reactivity compared to acyclic ethers. Epoxides are more reactive toward nucleophiles.
Why classification matters
Knowing the class helps predict physical properties (boiling point, solubility) and chemical behaviour (which reactions occur and by which mechanism). For instance, primary alcohols are easily oxidised to aldehydes, whereas tertiary alcohols resist oxidation; phenols are acidic and activate the ring toward electrophiles; ethers are good aprotic solvents but are cleaved by strong acids. Proper classification is the first step in solving synthesis and reaction-prediction problems.
- Methanol CH3–OH (a primary alcohol); ethanol CH3CH2–OH (primary)
- Isopropyl alcohol (2-propanol) CH3–CHOH–CH3 (secondary)
- Tert-butanol (2-methyl-2-propanol) (tertiary); phenol C6H5–OH (aromatic alcohol)
- Diethyl ether CH3CH2–O–CH2CH3 (symmetrical ether); anisole C6H5–OCH3 (aryl ether)
- Functional groups: Alcohol: –OH attached to sp3 carbon; Phenol: –OH attached to aromatic ring; Ether: R–O–R'
Nomenclature of Alcohols, Phenols and Ethers
IUPAC naming of alcohols
Naming alcohols starts by identifying the longest carbon chain that contains the hydroxyl carbon. Number the chain so that the carbon bearing the –OH has the lowest possible number. The parent name replaces the final 'e' of the alkane with 'ol' and includes a locant to show the position: CH3CH2CH2OH is propan-1-ol while CH3CHOHCH3 is propan-2-ol. For molecules with more than one –OH, use diol, triol etc. and give locants for each: butane-1,3-diol. Cyclic alcohols use 'cyclo' prefixes and number the ring so –OH is at C-1 (e.g., cyclohexanol is cyclohexan-1-ol by IUPAC style).
Trivial and common names
Many simple alcohols still use common names: methyl alcohol (methanol), ethyl alcohol (ethanol), isopropyl alcohol (propan-2-ol). For benzylic alcohols, common names like benzyl alcohol (C6H5CH2OH) are widely used. Text problems may present either system; understand both.
Phenol nomenclature
Phenol (C6H5OH) is the parent name for the simplest aromatic alcohol. Substituted phenols are named by numbering the ring to give substituents the lowest set of locants, or by using ortho (o-), meta (m-) and para (p-) prefixes for disubstituted rings. For multiple hydroxyls, use prefixes such as dihydroxybenzene with locants: 1,4-dihydroxybenzene (para-dihydroxybenzene) is commonly called hydroquinone.
Ether nomenclature
Ethers can be named in two ways. The common name lists the two alkyl groups alphabetically followed by 'ether' (e.g., methyl ethyl ether). The preferred IUPAC method treats the smaller alkoxy group as a substituent: methoxyethane for CH3OCH2CH3. For aryl ethers, the aryl part is named followed by 'oxy' + alkane (e.g., phenoxyethane). For complex molecules, the alkoxy substituent is included in the full systematic name and appropriately numbered.
Practical naming tips
If in doubt, find the longest chain containing the functional group. For competing functional groups, consult functional group priority (–OH usually outranks ethers for parent naming when both present). Use parentheses for alkoxy substituents when they are complex: (2-methylpropoxy) etc. Practice converting between common and IUPAC names to become fluent in exam settings.
- CH3CH2CH2OH = propan-1-ol; CH3CHOHCH3 = propan-2-ol
- C6H5OH = phenol; 1,2-dihydroxybenzene = catechol
- CH3OCH2CH3 = methoxyethane (IUPAC) or methyl ethyl ether (common)
- Alcohol naming: parent chain + locant + -ol (e.g., butan-2-ol)
- Phenol naming: benzene as parent, use locants or o-, m-, p- (e.g., p-nitrophenol)
- Ether naming (IUPAC): alkoxy + parent alkane (e.g., methoxypropane)
Structure and Bonding: Alcohols
Hybridisation and bonding
In alcohols the oxygen atom is sp3-hybridised. It forms two sigma bonds (C–O and O–H) and carries two lone pairs. The bond angles about oxygen are roughly tetrahedral (~104–110°) but slightly compressed by lone pair repulsion. The electronegativity difference between oxygen and carbon makes the C–O bond polar; oxygen bears partial negative charge while carbon is slightly positive.
Hydrogen bonding and physical properties
One of the key consequences of the –OH group is hydrogen bonding. Alcohols can form intermolecular O–H···O hydrogen bonds, raising boiling points significantly compared to hydrocarbons or ethers of similar molar mass. Small alcohols are miscible with water because they can hydrogen-bond to water; as the alkyl chain length increases the hydrophobic part reduces solubility. Branching also reduces boiling point because it lowers surface contact and reduces van-der-Waals interactions.
Electronic effects and acidity
The O–H bond in alcohols is somewhat acidic, but far less so than phenols. Alkyl groups are weakly electron-donating by inductive effect (+I), which slightly destabilises the alkoxide ion and so alcohols have pKa around 16–18 (ethanol ~16). The inductive effect is small compared to resonance effects in conjugated systems; therefore an allylic or benzylic alcohol will show different reactivity because adjacent unsaturation or aromatic rings can stabilise intermediates formed during reactions.
Steric effects and reactivity
Steric hindrance around the –OH influences reaction rates and mechanisms. Primary alcohols undergo SN2-type reactions more readily; tertiary alcohols are hindered and often react by SN1 mechanisms where the leaving group departs to form a carbocation. Tertiary alcohols are also resistant to oxidation because there is no hydrogen attached to the carbon bearing –OH; oxidation would need C–C bond cleavage.
Spectroscopic features
Alcohols show a broad O–H stretch in IR between 3200–3600 cm−1. In 1H NMR the hydroxyl proton is exchangeable and appears as a broad signal whose position depends on hydrogen-bonding environment and solvent; it disappears on addition of D2O. Carbon–oxygen single bond C–O stretching appears in the IR at lower frequency (1000–1300 cm−1). These features help identify alcohol functional groups experimentally.
- Compare boiling points: n-butanol (117 °C) vs diethyl ether (35 °C) — hydrogen bonding in alcohol raises b.p.
- Ethanol (CH3CH2OH) dissolves in water due to hydrogen bonding; octanol (C8H17OH) is less soluble
- Tertiary butanol is more sterically hindered and resists oxidation compared to primary butanol
- Hybridisation of O in alcohols: sp3
- Hydrogen bond representation: O–H⋯O
- Acidity trend in alcohols: water ≈ alcohols > alkanes (alcohols are weak acids, pKa ~16 for ethanol)
Structure and Bonding: Phenols
Hybridisation and resonance
In phenol the oxygen is effectively sp2-hybridised because one of its lone pairs can overlap with the aromatic π-system. This delocalisation allows resonance structures in which the oxygen donates electron density into the ring; the conjugation stabilises certain intermediates and influences reactivity. The resonance forms show positive character on oxygen and negative charge distributed at ortho and para carbons when phenol loses a proton to give phenoxide.
Acidity via resonance stabilisation
The increased acidity of phenol compared to aliphatic alcohols arises because the phenoxide ion is resonance-stabilised: the negative charge is delocalised over several atoms of the benzene ring. This stabilisation lowers the energy of the conjugate base and hence increases acidity (phenol pKa ~10, whereas ethanol pKa ~16). Substituents on the ring further modify acidity: electron-withdrawing groups (e.g., –NO2) stabilise the phenoxide more and lower the pKa, while electron-donating groups (e.g., –OCH3) raise the pKa.
Directing effects and reactivity
Because the oxygen atom donates electron density into the ring, phenol strongly activates the ring towards electrophilic aromatic substitution (EAS) at ortho and para positions. This makes reactions like nitration, sulfonation and halogenation occur more rapidly than in benzene and often leads to poly-substitution unless the reaction is controlled. The reactivity pattern can be understood by resonance structures showing increased electron density at ortho/para positions.
Hydrogen bonding and physical properties
Phenols engage in hydrogen bonding and often show higher boiling points and lower volatility than corresponding aromatic hydrocarbons. The –OH can form intermolecular hydrogen bonds, and intramolecular hydrogen bonding occurs in o-substituted phenols stabilising particular conformations. Solubility in water depends on the balance between hydrophilic –OH and hydrophobic aromatic ring.
Spectroscopy and identification
Phenols show broad O–H stretches in IR, usually at slightly higher frequencies than aliphatic alcohols if hydrogen bonding is weaker. In NMR the aromatic proton signals shift according to substitution; the O–H proton is exchangeable and can disappear with D2O. The FeCl3 test gives a characteristic colour with many phenols due to complex formation with iron, useful for qualitative identification.
- Phenol (C6H5OH) is more acidic than ethanol because the phenoxide ion is resonance-stabilised
- p-Nitrophenol is more acidic than phenol because –NO2 withdraws electron density by -I and -R effects
- Phenol nitration gives mainly ortho and para nitrophenols due to activation by –OH
- Acidity order: phenol (pKa ~10) >> ethanol (pKa ~16)
- Resonance: phenoxide ion resonance forms delocalise negative charge to ortho/para carbons
Structure and Bonding: Ethers
Hybridisation and molecular geometry
In simple acyclic ethers the oxygen atom is sp3 hybridised, forming two sigma bonds to carbon and carrying two lone pairs. The C–O–C bond angle is typically near 110°, somewhat less than the tetrahedral 109.5° due to lone-pair repulsion. The C–O bonds are polar because oxygen is more electronegative than carbon; however, when the R groups are non-polar, the overall molecule can be relatively non-polar.
Intermolecular interactions and physical effects
Ethers cannot donate hydrogen bonds because they lack an O–H proton, but they can accept hydrogen bonds from donors such as water or alcohols. This is why small ethers (e.g., dimethyl ether) have some solubility in water. Without hydrogen-bond donation, ethers have much lower boiling points than alcohols of comparable molar mass. Ethers are often volatile and good solvents for nonpolar organics.
Cyclic ethers and ring strain
Cyclic ethers such as epoxides (three-membered rings) show significant ring strain because the bond angles are far from ideal tetrahedral angles. This strain makes epoxides much more reactive toward nucleophiles and acids; ring-opening reactions relieve strain and are widely used synthetically. Larger rings like tetrahydrofuran (THF) are less strained and serve as common polar aprotic solvents.
Chemical stability and reactivity
Under neutral conditions ethers are relatively inert. They resist attack by bases and are stable to many oxidants that would react with alcohols. However, under strong acidic conditions (HI, HBr), ethers are protonated and cleaved to give alkyl halides and alcohols; the pathway (SN1 or SN2) depends on the substitution pattern of the alkyl groups. Epoxides are an exception: they open easily to give functionalised alcohols, with regiochemistry depending on acidic or basic conditions.
Practical roles and hazards
Ethers serve as excellent solvents for Grignard reagents and many lab reactions because they stabilise organometallic species through lone-pair coordination. A key safety concern is peroxide formation: ethers exposed to air slowly form peroxides that are explosive when concentrated. Therefore ethers must be stored properly, tested for peroxides and purified before distillation.
- Diethyl ether, CH3CH2–O–CH2CH3, has low boiling point (35 °C) compared to ethanol (78 °C)
- Dimethyl ether, CH3–O–CH3, is a gas at room temperature and used as aerosol propellant
- Ethyl methyl ether cleaves with HI to give methyl iodide and ethanol
- Ether general formula: R–O–R'
- Acidic cleavage: R–O–R' + HX → R–X + R'–OH (mechanism depends on substitution)
Methods of Preparation: Alcohols (I) — Hydration and Reduction
Hydration of alkenes
Hydration of alkenes is a versatile route to alcohols. Under acid-catalysed conditions (H3O+), water adds across the double bond following Markovnikov's rule: the proton adds to give the more stable carbocation intermediate and water then bonds to the carbocation, ultimately giving the more substituted alcohol after deprotonation. For example, propene in acid gives propan-2-ol. Care is needed because carbocation intermediates can rearrange, changing product distribution.
Oxymercuration-demercuration and hydroboration-oxidation
To avoid rearrangements, oxymercuration-demercuration is used: addition of mercuric acetate followed by reduction (NaBH4) gives Markovnikov hydration without rearrangement. Hydroboration-oxidation (BH3/THF then H2O2, OH–) gives anti-Markovnikov addition: boron adds to the less substituted carbon and is replaced by –OH on oxidation, yielding alcohols with reversed regiochemistry relative to acid hydration.
Reduction of carbonyl compounds
Carbonyl reduction is a primary laboratory method to prepare alcohols with control over oxidation level. Aldehydes are reduced to primary alcohols and ketones to secondary alcohols. NaBH4 is a mild, chemoselective reducing agent (reacts with aldehydes and ketones but not esters or carboxylic acids under normal conditions). LiAlH4 is much stronger and reduces esters and acids as well; it requires dry ether and careful work-up. Catalytic hydrogenation (H2, Pd/C, Pt or Ni) can also reduce carbonyls to alcohols under pressure and appropriate solvent.
Grignard reagents and carbonyl addition
Grignard reagents (RMgX) add to carbonyls to form alkoxides which after acidic work-up give alcohols. Reaction with formaldehyde yields primary alcohols, with other aldehydes gives secondary alcohols, and with ketones gives tertiary alcohols. Careful control of moisture and reactive functional groups is essential because Grignard reagents react with water and protic groups.
Industrial and practical considerations
Choice of method depends on the desired regiochemistry, substituent tolerance and scale. Hydroboration-oxidation is chosen when anti-Markovnikov regiochemistry is needed; oxymercuration when rearrangement avoidance is essential. In industry, hydration with catalysts and fermentation for ethanol are common depending on feedstock and economics. Safety notes: LiAlH4 reacts violently with water and must be handled under dry, inert atmospheres.
- Hydroboration-oxidation: CH3CH=CH2 → (BH3, THF) → (H2O2, OH−) → CH3CH2CH2OH (1-propanol, anti-Markovnikov)
- Reduction: CH3COCH3 (propanone) + NaBH4 → CH3CHOHCH3 (isopropyl alcohol)
- Grignard: CH3MgBr + CH3CHO → after hydrolysis gives CH3CH(OH)CH3 (propan-2-ol)
- Hydration (acid-catalysed): RCH=CH2 + H2O → RCH(OH)CH3 (Markovnikov)
- Hydroboration-oxidation (anti-Markovnikov): RCH=CH2 → RCH2CH2OH
- Reduction: R–C(=O)–H + [H] → R–CH2–OH (aldehyde to primary alcohol)
Methods of Preparation: Alcohols (II) — From Haloalkanes, Addition and Fermentation
From haloalkanes by nucleophilic substitution
Alcohols can be prepared by nucleophilic substitution of haloalkanes with hydroxide ion: R–X + OH− → R–OH. Primary haloalkanes undergo SN2 reaction more readily, giving good yields of primary alcohols when treated with aqueous or alcoholic NaOH. Secondary haloalkanes may give mixtures of substitution and elimination; tertiary haloalkanes often follow SN1 or eliminate to alkenes. Reflux conditions and solvent choice influence the balance between substitution and elimination.
Hydrolysis of esters and reduction of derivatives
Ester hydrolysis (acidic or basic) produces alcohols as one of the products: RCOOR' + H2O → RCOOH + R'OH. Reduction of esters or carboxylic acids with LiAlH4 converts them to primary alcohols. These approaches are useful for transforming functionality: for example, converting a protecting ester back to the free alcohol uses hydrolysis conditions.
Biological fermentation
Ethanol is produced commercially by fermentation of sugars by yeast under anaerobic conditions: C6H12O6 → 2 C2H5OH + 2 CO2. This process is central to beverage alcohol production and renewable biofuel manufacture. Conditions such as temperature, yeast strain and sugar source affect yield and by-products. Distillation and purification are needed to obtain fuel-grade ethanol.
Specialized routes to alcohols
Benzylic alcohols can be prepared by reduction of benzaldehydes or by oxidation of alkylbenzenes under controlled conditions to give benzyl alcohol. Sandmeyer hydrolysis (diazotisation of aromatic amines followed by hydrolysis) offers access to phenolic alcohols from anilines. Tosylate formation (R–OTs) converts a poor leaving group –OH into a good one, enabling nucleophilic substitution to give alcohols or other products in later steps.
Practical advice
SN2 substitution requires good nucleophiles and polar aprotic solvents for highest rates; aqueous hydroxide encourages solvolysis and elimination for hindered substrates. Industrial routes prioritise cost, feedstock availability and minimal side-products; for laboratory synthesis choose methods that maintain sensitive groups and avoid rearrangement if regioselectivity is required.
- Hydrolysis: CH3CH2Cl + NaOH (aq) → CH3CH2OH + NaCl
- Ester hydrolysis: CH3COOCH2CH3 + H2O (acid) → CH3COOH + CH3CH2OH
- Fermentation: C6H12O6 (glucose) → 2 C2H5OH + 2 CO2 (yeast)
- SN2 substitution: R–X + OH− → R–OH + X−
- Fermentation: C6H12O6 → 2 C2H5OH + 2 CO2
Physical Properties of Alcohols, Phenols and Ethers
Boiling points and intermolecular forces
Hydrogen bonding is the defining factor that separates alcohols and phenols from ethers in terms of boiling point. Alcohols and phenols have O–H groups that engage in hydrogen bonding, causing higher boiling points than ethers of similar molar mass. Ethers cannot donate hydrogen bonds and so have lower boiling points. For instance, ethanol boils at 78 °C, while diethyl ether boils at 35 °C. In phenols, aromatic character and stronger hydrogen-bonding interactions often raise boiling points relative to analogous alcohols.
Solubility in water and hydrophobic effects
Small alcohols and phenols dissolve in water due to hydrogen bonding with water molecules; however, as the hydrocarbon portion increases, hydrophobic forces dominate and water solubility decreases. Ethers like diethyl ether are only slightly soluble in water because although they can accept hydrogen bonds, they cannot donate them. Solubility is crucial for extraction, distillation and reaction solvent choice in the lab.
Acidity and basicity
Phenols are considerably more acidic than aliphatic alcohols because the phenoxide ion is resonance-stabilised. Typical pKa values: ethanol ~16, phenol ~10. Ethers are essentially neutral and do not deprotonate under normal conditions. The lone pairs on oxygen make alcohols and ethers weak bases and good ligands for metal ions, but their basicity is modest compared to amines.
Density, refractive index and volatility
Alcohols and ethers typically have densities slightly less than or near 1 g cm−3 (depends on molecular weight). Refractive index increases with molar mass and conjugation. Volatility of ethers is higher than that of comparable alcohols, making ethers useful as fast-evaporating solvents but also requiring careful handling because of flammability and inhalation risk.
Laboratory implications
Physical properties determine how compounds are separated: distillation exploits differences in boiling point; extraction uses differential solubility in polar vs non-polar solvents. Hydrogen bonding affects chromatography and retention times. Understanding these trends helps predict behaviour of molecules during purification and reaction work-up.
- Ethanol is miscible with water; butanol is only slightly soluble
- Phenol (C6H5OH) has higher boiling point and is less volatile than benzene
- Diethyl ether forms a separate organic layer when mixed with water
- Representative pKa values: ethanol ~16, phenol ~10
- Hydrogen bonding increases boiling point relative to non-hydrogen-bonding analogues
Reactions of Alcohols: Acid–Base Behaviour and Esterification
Acid–base properties
Alcohols can act as very weak acids, donating the O–H proton to strong bases to form alkoxide ions (R–O−). Reaction with metallic sodium produces alkoxides and hydrogen gas: 2 R–OH + 2 Na → 2 R–O−Na+ + H2. Phenols, being more acidic, react with milder bases such as NaOH to form phenoxide salts. These acid–base behaviours are used in separation techniques: deprotonation moves phenols into the aqueous layer as salts, enabling separation from neutral organics.
Formation and use of alkoxides
Alkoxides are strong nucleophiles and bases; they are central reagents in many syntheses. For example, sodium ethoxide (CH3CH2O−Na+) is used in Williamson ether synthesis to make ethers and in elimination (E2) reactions to form alkenes. Alkoxide preparation requires dry conditions: alkoxides are formed by treating alcohols with NaH, Na metal or strong bases in aprotic solvents.
Fischer esterification
Alcohols react with carboxylic acids in the presence of a strong acid catalyst (commonly concentrated H2SO4) to form esters and water: R–OH + R'COOH ⇌ R'COOR + H2O. Fischer esterification is reversible and an equilibrium; Le Chatelier’s principle explains driving the reaction to completion by removing water or using excess alcohol. The mechanism involves protonation of the carbonyl, nucleophilic attack by alcohol, proton transfers and elimination of water to give the ester.
Formation of alkyl halides and sulfonate esters
Conversion of alcohols to alkyl halides is widely used. Reagents like SOCl2 or PCl5 convert alcohols to chlorides; PBr3 converts them to bromides, often with inversion of configuration for primary and secondary alcohols via an SN2-like pathway. Alternatively, conversion of –OH into a sulfonate ester (tosylate R–OTs or mesylate R–OMs) creates a very good leaving group while retaining stereochemistry; this enables subsequent substitution by a nucleophile under milder conditions.
Dehydration to alkenes
Under strong acid and heat, alcohols eliminate water to form alkenes. For secondary and tertiary alcohols, an E1 mechanism predominates with carbocation intermediate and possible rearrangements; for primary alcohols an E2 mechanism may be observed under certain conditions. Zaitsev’s rule predicts formation of the more substituted, more stable alkene in many elimination reactions.
- Fischer esterification: CH3CH2OH + CH3COOH (H2SO4) ⇌ CH3COOCH2CH3 + H2O (ethyl acetate)
- Formation of alkoxide: 2 CH3CH2OH + 2 Na → 2 CH3CH2O−Na+ + H2
- Dehydration: CH3CH(OH)CH3 (2°) → CH3CH=CH2 + H2O (acid, heat)
- Esterification equilibrium: R–OH + R'COOH ⇌ R'COOR + H2O (H+ catalyst)
- Alkoxide formation: R–OH + Na → R–O−Na+ + 1/2 H2
Reactions of Alcohols: Oxidation and Substitution Mechanisms
Oxidation of alcohols: dependence on degree
The pathway and products of oxidation depend on whether the alcohol is primary, secondary or tertiary. Primary alcohols can be oxidised first to aldehydes and then further to carboxylic acids with strong oxidants (e.g., KMnO4, K2Cr2O7/H2SO4). With controlled oxidants and conditions (e.g., PCC, Dess–Martin), oxidation can be stopped at the aldehyde stage. Secondary alcohols oxidise to ketones. Tertiary alcohols lack a hydrogen on the carbon bonded to –OH and therefore do not undergo direct oxidation to a carbonyl without breaking C–C bonds; they are generally resistant to mild oxidants.
Typical oxidising agents and tests
Common laboratory oxidants include potassium permanganate (KMnO4), acidified potassium dichromate (K2Cr2O7/H2SO4) and PCC (pyridinium chlorochromate) for milder oxidation. Dichromate changes colour from orange to green when reduced, serving as a qualitative test for oxidisable alcohols. Tollens' reagent (Ag(NH3)2+) and Fehling's solution test for aldehydes (but not ketones), allowing experimental distinction between oxidation products.
Substitution mechanisms (SN1 vs SN2)
Conversion of alcohols to alkyl halides or other substituted products can proceed by SN2 or SN1 mechanisms, depending on substrate and conditions. Primary alcohols typically undergo substitution by SN2 after converting –OH into a better leaving group (e.g., tosylate) or by using reagents like PBr3. Secondary and tertiary alcohols often react by SN1 under acidic conditions: protonation of –OH gives water, which leaves to form a carbocation intermediate that is then attacked by a nucleophile. Carbocation rearrangements are possible and must be considered in product prediction.
Stereochemical outcomes and control
SN2 reactions lead to inversion of configuration at a stereogenic carbon; SN1 reactions yield racemisation or partial racemisation due to planar carbocation intermediates. Choice of reagent (PBr3 vs HBr) and solvent (polar protic vs aprotic) helps control pathway and stereochemical outcome. Protecting groups and choice of leaving groups help manage selectivity in multi-step syntheses.
Practical synthetic considerations
When designing a synthesis step, choose oxidants and substitution reagents based on chemoselectivity and sensitivity of other functional groups. Use mild reducing/oxidising agents to avoid unwanted over-reaction. Consider step economy and avoid conditions that lead to rearrangements unless they are purposeful in the synthetic plan.
- Oxidation: CH3CH2OH + [O] → CH3CHO (ethanal) → CH3COOH (ethanoic acid) with strong oxidant
- SN2 substitution: CH3CH2OH → (PBr3) → CH3CH2Br (inversion at chiral centre if present)
- SN1 example: (CH3)3C–OH + H+ → (CH3)3C+ → reacts with Br− to give (CH3)3C–Br
- Primary alcohol oxidation: RCH2OH + [O] → RCHO → RCOOH (strong oxidants)
- Secondary alcohol oxidation: R1R2CHOH + [O] → R1R2C=O (ketone)
Preparation and Reactions of Phenols (I) — Preparation Methods
Industrial preparation: the cumene process
The most important industrial route to phenol is the cumene process. Cumene (isopropylbenzene) is oxidised in air to cumene hydroperoxide and then acid-cleaved to give phenol and acetone. This route is favoured for its economy and the valuable acetone co-product. The overall simplified sequence is: cumene → cumene hydroperoxide → phenol + acetone. Process control is essential to manage peroxidic intermediates and to optimise yields.
Laboratory routes: diazotisation and hydrolysis
At laboratory scale phenol is often prepared by conversion of aniline to a diazonium salt followed by hydrolysis. The sequence is: nitration (if starting from benzene) → reduction to aniline → diazotisation (NaNO2 + HCl, 0–5 °C) to give Ar–N2+, then warm hydrolysis replaces –N2+ with –OH to yield phenol. Diazotisation must be performed at low temperatures and diazonium salts handled in solution to avoid hazards.
Other methods: Kolbe–Schmitt and aromatic nucleophilic substitution
The Kolbe–Schmitt reaction synthesises salicylic acid by carboxylation of sodium phenoxide with CO2 under pressure and heat; subsequent acidification yields salicylic acid (ortho-hydroxybenzoic acid), a precursor to aspirin. Nucleophilic aromatic substitution can convert activated chlorobenzenes into phenols under harsh conditions if electron-withdrawing groups stabilise the intermediate. Historically, many synthetic routes combine nitration and diazotisation steps to position substituents before final conversion to phenol.
Specialised oxidations and catalytic methods
Aromatic hydroxylation methods (using peracids, catalytic systems or directed metal-catalysed oxidations) can introduce –OH at specific positions on the ring under appropriate conditions. Research-level methods include transition-metal-catalysed C–H activation to install hydroxyl groups directly, but these are less common in school-level synthesis problems.
Practical considerations
Select a route based on scale, regioselectivity and safety. Cumene process is industrially dominant, while diazotisation is a flexible laboratory method allowing positional control after suitable substituent management. Always consider handling of peroxides, control of temperature, and safe disposal of nitrous by-products in these processes.
- Sandmeyer hydrolysis: C6H5NH2 → (NaNO2, HCl, 0–5 °C) → C6H5N2+Cl− → heat → C6H5OH
- Cumene process: cumene → (O2) → cumene hydroperoxide → (H+) → phenol + acetone
- Kolbe–Schmitt: sodium phenoxide + CO2 (high P, 125–150 °C) → sodium salicylate → acidification → salicylic acid
- Sandmeyer hydrolysis sequence: ArNH2 → ArN2+ → ArOH
- Cumene overall: C6H5CH(CH3)2 + O2 → C6H5OH + (CH3)2CO (simplified)
Preparation and Reactions of Phenols (II) — Electrophilic Substitution and Coupling
Activation of the aromatic ring by –OH
The hydroxyl group in phenol strongly donates electron density into the aromatic ring via resonance. This activates the ring toward electrophilic aromatic substitution (EAS), especially at the ortho and para positions. Consequently, reactions like nitration, halogenation and sulfonation occur much more readily for phenol than for benzene, and often lead to mixtures of ortho and para products unless the reaction is carefully controlled.
Nitration, halogenation and regioselectivity
Nitration of phenol with dilute nitric acid at low temperature primarily gives ortho and para nitrophenols; para is often favoured due to steric factors and reaction conditions. Bromination is particularly fast: phenol reacts with Br2 in water to give 2,4,6-tribromophenol under uncontrolled conditions. To obtain monobromo- or mononitro-products, milder reagents, lower temperatures or protecting groups (e.g., acetylation of –OH) are used to slow reaction and control regioselectivity.
Azo coupling and dye chemistry
Phenoxide ions are powerful nucleophiles and react with diazonium salts to form azo compounds — coloured molecules used as dyes. The coupling occurs preferentially at the para position unless it is blocked, in which case ortho coupling occurs. Such reactions form the basis for many industrial dyes and laboratory tests. Formation of azo dyes involves electrophilic attack of the diazonium species on the activated phenoxide ring followed by proton transfer to restore aromaticity.
Protecting groups and functional group interconversion
Because phenol is highly reactive, synthetic chemists often protect the hydroxyl group (e.g., convert to an ether or ester) to carry out other transformations on the ring without uncontrolled substitutions. For example, acetylation to phenyl acetate reduces activating power, allowing selective reactions elsewhere; later the acetyl group can be removed under basic or acidic conditions to regenerate phenol.
Practical laboratory control
To control substitution patterns, manipulate temperature, use stoichiometric amounts of reagents, or protect functional groups. Safety is essential when handling nitrating mixtures and bromine. Understanding resonance, steric factors and reagent strength helps predict whether mono-, di- or tri-substitution will occur under given conditions.
- Phenol + Br2 (aqueous) → 2,4,6-tribromophenol unless conditions controlled
- Phenoxide + ArN2+ → Ar–N=N–Ar' (azo coupling) giving coloured azo dyes
- Nitration: phenol + HNO3 (dilute, low T) → mainly o- and p-nitrophenols
- Directing: –OH directs ortho and para in EAS
- Azo coupling: ArO− + Ar'–N2+ → Ar–O–N=N–Ar' (structure shown conceptually)
Acidity of Phenols — Factors and Quantitative Aspects
Resonance stabilisation of phenoxide
The acidity of phenol stems from the stability of its conjugate base, the phenoxide ion. When phenol loses a proton, the negative charge is delocalised by resonance across the aromatic ring and onto the ortho and para carbons; this spreading of charge stabilises the anion and lowers the energy of the conjugate base. Thus phenol (pKa ~10) is appreciably more acidic than typical aliphatic alcohols (pKa ~16).
Substituent effects—inductive and resonance
Substituents on the benzene ring influence acidity by inductive (-I or +I) and resonance (-R or +R) effects. Electron-withdrawing groups such as –NO2, –CN, –COOR withdraw electron density and stabilise the negative charge on phenoxide, increasing acidity (lower pKa). Electron-donating groups such as –CH3 or –OCH3 release electron density and destabilise the phenoxide ion, reducing acidity (higher pKa). Position matters: groups at ortho and para can exert resonance effects on the phenoxide ion, while meta substituents mainly exert inductive effects.
Steric and hydrogen-bonding effects
Bulky ortho substituents can hinder solvation and hydrogen bonding of the phenoxide or phenol, which may have subtle effects on acidity. Intramolecular hydrogen bonding (e.g., in o-hydroxybenzoic acid) can stabilise certain forms and affect acidity relative to para or meta isomers. Solvent also matters: polar protic solvents stabilise ions and influence measured pKa values compared to nonpolar media.
Quantitative relations and Hammett correlation
The Hammett equation relates changes in reaction rates or equilibrium constants (including acidity) to substituent constants (σ) and a reaction constant (ρ): log(K/K0) = ρσ. For acidity of substituted phenols, this provides a semi-quantitative way to predict how different substituents will change pKa. A positive ρ for acidity means electron-withdrawing substituents increase acidity.
Applications and experimental consequences
Understanding acidity guides separations and synthetic transformations: phenols are deprotonated by NaOH to form water-soluble phenoxide salts allowing extraction from neutral organics. Knowledge of substituent effects helps in designing molecules with desired acidity for pharmaceuticals, dyes and materials chemistry.
- Phenol pKa ≈ 10 vs ethanol pKa ≈ 16 — phenol is much stronger acid
- p-Nitrophenol is more acidic than phenol due to –NO2 stabilising phenoxide
- Phenol reacts with NaOH to form sodium phenoxide which dissolves in water
- Deprotonation: C6H5OH + OH− ⇌ C6H5O− + H2O
- Hammett: log(K/K0) = ρσ (qualitative relation for substituent effect)
Reactions of Ethers — Cleavage and Ring-Opening
Acidic cleavage of ethers
Ethers are generally unreactive under neutral conditions, but strong hydrogen halides (HI, HBr) cleave ethers. The mechanism depends on substitution: when one side is primary, SN2 attack by the halide on the less hindered carbon gives R–X and R'–OH; when a tertiary centre is present, the reaction proceeds via SN1 with carbocation formation on the more substituted carbon, followed by nucleophilic capture. Symmetrical ethers may require two equivalents of HX for full conversion. HI is a stronger and faster cleaving agent than HBr; HCl is less effective.
Equation examples and regiochemistry
A general equation: R–O–R' + HX → R–X + R'–OH. For unsymmetrical ethers under SN2 conditions, halide attacks the less hindered alkyl group. For example, methyl tert-butyl ether with HBr attacks the methyl side to give methyl bromide and tert-butanol; if the tertiary side forms a stable carbocation, attack on that side can dominate under SN1-favouring conditions.
Epoxide (three-membered cyclic ether) ring-opening
Epoxides are highly strained and much more reactive. Under acidic conditions, protonation of the epoxide oxygen increases electrophilicity and the nucleophile attacks at the more substituted carbon (the carbon that better stabilises positive charge) — giving regioselectivity reflecting carbocation-like character. Under basic or neutral nucleophilic conditions, ring opening follows an SN2-like pathway with attack at the less substituted carbon. These complementary regiochemistries are exploited in synthesis to access specific substitution patterns.
Peroxide formation and stability issues
A practical hazard with ethers is peroxide formation on exposure to air and light. Peroxide impurities can concentrate during distillation and are potentially explosive. Therefore ethers should be tested for peroxides before distillation or concentration and purified (e.g., by washing with reducing agents) if needed. Storage in dark, inert atmosphere and adding stabilisers reduce peroxide risk.
Other reactions and solvent uses
Ethers are useful as relatively inert solvents for many organic reactions and for stabilising organometallic reagents (e.g., Grignard reagents) through coordination of oxygen lone pairs. Some ethers undergo oxidation under harsh conditions or can be cleaved by strong Lewis acids; choice of reaction conditions determines whether ethers remain intact or are converted to other products.
- Cleavage: CH3CH2–O–CH3 + HBr → CH3CH2Br + CH3OH (ethyl methyl ether cleaved, bromide attacks primary side)
- Epoxide opening (acidic): protonated epoxide attacked by H2O gives more substituted alcohol after work-up
- Epoxide opening (basic nucleophile): attack at less hindered carbon yields substituted alcohol after hydrolysis
- Acidic cleavage: R–O–R' + HX → R–X + R'–OH
- Epoxide opening under base: nucleophile attacks less substituted carbon (SN2)
Synthetic Applications: Williamson Ether Synthesis and Protecting Groups
Williamson ether synthesis principle
The Williamson ether synthesis is a fundamental method to prepare ethers by reacting an alkoxide with an alkyl halide in an SN2 displacement: R–O− + R'–X → R–O–R' + X−. The alkoxide is formed by deprotonating an alcohol with a strong base (NaH, Na metal, or K metal), and the alkyl halide is typically primary to favour SN2 and avoid elimination. Choosing which part becomes the alkoxide and which the electrophile is important for successful synthesis and yield.
Strategic choices and stereochemistry
Because the Williamson reaction proceeds by SN2, steric hindrance slows the reaction; secondary or tertiary alkyl halides often give elimination rather than substitution. If a chiral electrophile is used, SN2 attack causes inversion of configuration at the stereocentre. When planning synthesis, put the more hindered fragment on the alkoxide part and use a primary halide as electrophile to avoid side reactions and improve yields.
Protecting groups for alcohols
Protecting an alcohol prevents it reacting during later steps of a multi-step synthesis. Common protecting groups include silyl ethers (e.g., TBDMS — tert-butyldimethylsilyl), benzyl ethers (removable by hydrogenolysis), and acetyl esters (removed by hydrolysis). A good protecting group is stable under the intended reaction conditions and removable under mild, orthogonal conditions that do not affect other functional groups. For example, convert R–OH to R–OTBDMS to protect it from strong base or oxidants, then deprotect with TBAF (tetrabutylammonium fluoride).
Applications in complex synthesis
Protecting groups are widely used in the synthesis of complex molecules: protect a primary alcohol while oxidising a secondary alcohol elsewhere, then deprotect. The Williamson synthesis is used to install ethers selectively once an alcohol is converted to its alkoxide; it is a key technique for building molecules with ether linkages such as glycosides and polymer precursors.
Practical considerations
Use dry, aprotic solvents for Williamson reactions (e.g., dry THF) and ensure complete deprotonation to form the alkoxide. Monitor for elimination side-products and choose bases and temperatures accordingly. Protecting group strategies add steps but can greatly simplify the overall route and improve selectivity and yield in complex syntheses.
- Williamson: CH3CH2O−Na+ + CH3I → CH3CH2OCH3 + NaI (ethoxy methyl ether formation)
- Protecting: R–OH → R–OTBDMS (protect) → carry out other reactions → R–OH (deprotect with TBAF)
- Synthesis strategy: form alkoxide from less hindered alcohol and react with primary halide to avoid elimination
- Williamson reaction: R–O− + R'–X → R–O–R' + X−
- Protection-deprotection: R–OH → (protecting group) → R–O–PG → (deprotect) → R–OH
Laboratory Identification and Functional Group Tests
Distinguishing alcohols, phenols and ethers
Several practical tests help identify these functional groups. Sodium metal reacts with alcohols to produce hydrogen gas and alkoxides (observed as bubbling); ethers do not react. Phenols react with aqueous NaOH to give phenoxide salts that dissolve in water — a key separation test: shake the unknown with NaOH; if it dissolves, it is likely phenolic. Phenol also gives a characteristic violet colour with neutral FeCl3 solution due to complex formation; most alcohols do not give this colour.
Tests to distinguish primary, secondary and tertiary alcohols
Lucas test (ZnCl2 with conc. HCl) differentiates by reaction rate: tertiary alcohols form turbidity immediately (via rapid SN1 substitution), secondary alcohols react more slowly, and primary alcohols show little change at room temperature. Oxidation tests help too: primary alcohols can be oxidised to aldehydes and then acids under strong oxidants; secondary alcohols give ketones; tertiary alcohols resist oxidation under mild conditions. These tests are often qualitative but useful in the lab.
Tests specific to ethers
Ethers are relatively inert; they typically do not react in the above tests. However, one must check for peroxides: treat a small sample with KI/starch/acetic acid to detect peroxides (iodine formation indicates peroxides). Peroxide-containing ethers are dangerous and must be handled with care. Spectroscopic methods such as IR and NMR also distinguish ethers (absence of O–H stretch, C–O stretch present) and show characteristic chemical shifts for α-protons.
Spectroscopic identification
IR spectroscopy: alcohols and phenols show O–H stretches — alcohols typically a broad band ~3200–3600 cm−1; phenols show a broad O–H often shifted by hydrogen-bonding and may appear slightly different. Ethers show strong C–O stretching bands between 1050–1150 cm−1. 1H NMR: O–H protons are exchangeable and disappear with D2O; aromatic patterns indicate phenol substitution; alpha protons to oxygen appear downfield relative to simple alkyl protons. Mass spectrometry fragment patterns also assist identification.
Safety and practical notes
Handle corrosive reagents (acids, oxidants) and flammable solvents with care in a fume hood. Test for peroxides in ethers before distillation. Keep records of qualitative tests and confirm functional group identity with spectroscopic data for accurate conclusions.
- FeCl3 test: phenol + FeCl3 → violet complex; ethanol gives no colour
- Lucas test: t-butanol + ZnCl2/HCl → immediate turbidity (tertiary), 2° slower, 1° no immediate change
- Sodium metal: alcohol reacts to give H2 gas; ether does not
- FeCl3 test: Ar–OH + FeCl3 → coloured complex (qualitative)
- Phenol deprotonation: Ar–OH + NaOH → Ar–O−Na+ + H2O
Industrial and Biological Importance, Safety and Environmental Aspects
Industrial significance
Alcohols, phenols and ethers are key building blocks and solvents in chemical industries. Ethanol is produced on large scale as a solvent, in beverages and as a fuel additive (bioethanol). Phenol is a precursor to phenolic resins, synthetic dyes, pharmaceuticals and detergents. Ethers such as diethyl ether and tetrahydrofuran (THF) are important solvents in laboratories and manufacturing; some specialized ethers are intermediates in organic synthesis and polymer production.
Biological roles
Hydroxyl groups are widespread in biomolecules: sugars and carbohydrates contain multiple –OH groups affecting solubility and reactivity; steroid and lipid chemistry often involves alcohol functions. Phenolic structures appear in natural products (e.g., flavonoids, salicylic acid) and often provide antioxidant or antiseptic properties. Epoxides and some ethers appear in natural toxins and pharmaceuticals, demonstrating both utility and potential toxicity depending on structure and dose.
Safety hazards and laboratory practices
Many alcohols and ethers are flammable; ethers are highly volatile and form explosive mixtures with air. Ethers are prone to peroxide formation on exposure to oxygen and light; peroxides concentrate upon distillation and are shock-sensitive, so regular testing and removal are essential. Phenols are corrosive and can be toxic and should be handled with gloves and in a fume hood. Proper storage, grounding during transfers, and adherence to MSDS guidelines are necessary for safe handling.
Environmental considerations
Volatile organic compounds (VOCs) including some ethers and alcohols contribute to air pollution and photochemical smog. Phenolic wastes are toxic to aquatic life and require treatment before disposal. Green chemistry aims to reduce hazardous solvent use, use renewable feedstocks (e.g., bioethanol), and develop catalytic, atom-economical processes to minimise waste. Recycling and waste-treatment technologies mitigate environmental impacts.
Regulatory and economic context
Regulations govern emissions, solvent use, and disposal of toxic phenolic wastes; industrial processes factor in coproduct value (e.g., acetone in cumene process) and energy efficiency. Understanding both chemical behaviour and regulatory environment helps chemists design safer, more sustainable processes and choose appropriate substitutes for hazardous reagents.
- Cumene process produces phenol and acetone at industrial scale for plastics manufacturing
- Bioethanol production from fermentation used as renewable fuel additive
- Peroxide formation in stored diethyl ether requires testing and removal prior to distillation
Reaction Mechanisms: SN1, SN2, Electrophilic Aromatic Substitution and Radical Oxidation
SN2 mechanism (bimolecular nucleophilic substitution)
SN2 is a concerted, single-step reaction in which a nucleophile attacks the electrophilic carbon from the backside as the leaving group departs. The transition state involves partial bonds to nucleophile and leaving group. The rate law is second order: rate = k[nucleophile][substrate]. SN2 favours primary and methyl substrates, strong nucleophiles and polar aprotic solvents. Stereochemistry: inversion of configuration at a stereocentre results from the backside attack.
SN1 mechanism (unimolecular nucleophilic substitution)
SN1 involves a two-step sequence: first the leaving group departs to form a carbocation, then the nucleophile attacks. The rate-determining step is unimolecular (rate = k[substrate]). SN1 favours tertiary substrates that form stable carbocations and occurs in polar protic solvents that stabilise ions. Carbocation rearrangements and racemisation at chiral centres are characteristic features.
Electrophilic aromatic substitution (EAS)
EAS reactions involve the attack of an electrophile on the aromatic ring to form a non-aromatic sigma complex (arenium ion), followed by deprotonation to restore aromaticity. The rate-determining step is formation of the sigma complex. Electron-donating groups (like –OH) increase reaction rate and direct ortho/para, while electron-withdrawing groups slow reaction and direct meta. Resonance structures of the sigma complex explain regioselectivity and reactivity trends.
Radical and ionic oxidation mechanisms
Oxidation of organic substrates can proceed via ionic hydride transfer to metal oxidants (e.g., Cr6+ to Cr3+) or via radical pathways depending on reagents and conditions. Oxidative cleavage of C–C bonds often involves radical intermediates or high-valent metal-oxo species. Controlled oxidants allow selective conversion of alcohols to carbonyls, while strong, non-selective oxidants produce carboxylic acids and cleavage products. Mechanistic understanding helps predict whether aldehyde or acid will form under given conditions.
Application of mechanisms in synthesis
Mechanistic knowledge allows prediction of products, stereochemistry and side reactions. For example, choose PBr3 or SOCl2 for conversion of alcohols to halides when retention/inversion matters; choose NaBH4 vs LiAlH4 based on functional group tolerance. Practice drawing arrow-pushing steps to become proficient at explaining and predicting reaction pathways in examinations and lab work.
- SN2: CH3Br + OH− → CH3OH + Br− (backside attack, inversion not applicable for methyl)
- SN1: (CH3)3C–Cl → (CH3)3C+ + Cl− → (CH3)3C–OH after water attack
- EAS: nitration of phenol proceeds via formation of sigma complex at ortho/para followed by deprotonation
Problem-Solving and Multi-Step Synthesis Involving Alcohols, Phenols and Ethers
Approach to synthesis problems
Begin with retrosynthesis: visualise breaking bonds that can be formed easily in a forward reaction (disconnections). Identify the functional groups in the target molecule and consider classic methods to construct them: Williamson for ethers, Grignard addition for alcohol formation, reduction of carbonyls, hydration of alkenes, and diazotisation routes for phenols. Work backwards step by step to propose simpler precursors and reagents that give the target after forward reactions.
Common disconnections and synthetic building blocks
For ethers, disconnect the R–O bond to give an alkoxide and an alkyl halide precursor (Williamson). For alcohols, consider carbonyl precursors (aldehydes, ketones, esters) reducible to alcohols, or alkenes hydrated in the desired regiochemistry. For phenols, diazotisation or the cumene route may be applicable depending on starting materials and substitution pattern. Choose disconnections that avoid problematic steps like rearrangements or harsh reagents that would damage other functional groups.
Protecting group strategies and chemoselectivity
Select protecting groups when multiple functional groups would interfere with a planned reaction. For example, protect a primary alcohol as a silyl ether while oxidising a secondary alcohol elsewhere. Ensure protecting and deprotecting steps are compatible with other transformations in the sequence. Keep the number of protection steps to a minimum to improve overall yield and economy.
Practical reagent choices and selectivity
Match reagents to desired selectivity: NaBH4 reduces aldehydes and ketones but not esters; LiAlH4 reduces esters and acids as well. Use PCC for oxidation to aldehydes without over-oxidation. Use oxymercuration to avoid carbocation rearrangements in hydration. Consider solvent and temperature to favour SN2 over elimination in substitution reactions. Sketch mechanisms for key steps to verify feasibility and stereochemical outcomes.
Practice tips for exams
Solve varied synthesis problems, justify each step with reagents and conditions, and draw mechanisms for critical transformations. Prepare a reagent table summarising common transformations (e.g., PBr3 for alcohol to bromide with inversion, NaBH4 vs LiAlH4 differences). The ability to propose plausible, stepwise syntheses with clear reasoning is essential for board examinations and practical laboratory planning.
- Synthesize tert-butanol from propene: CH3–CH=CH2 → (H2O, H+) → not suitable — better route: isobutene hydration or hydroboration-oxidation of isobutene
- Make anisole from phenol: phenol + CH3I + K2CO3 → C6H5–O–CH3 (methylation) via Williamson variant
- Prepare 1-phenyl-1-propanol by addition of phenylmagnesium bromide to propanal followed by hydrolysis
Key Concepts
- Alcohol
- An organic compound with a hydroxyl group (–OH) attached to an sp3 carbon atom.
- Phenol
- An aromatic compound in which a hydroxyl group is directly bonded to a benzene ring.
- Ether
- A compound with an oxygen atom bonded to two carbon atoms (R–O–R').
- Primary, Secondary, Tertiary (alcohol)
- Classification based on the number of carbon atoms attached to the carbon bearing the –OH: 1°, 2°, 3° respectively.
- Hydrogen bonding
- A strong intermolecular interaction where a hydrogen atom bonded to electronegative atom interacts with lone pair on another electronegative atom.
- Markovnikov and anti-Markovnikov addition
- Rules predicting regiochemistry of addition to alkenes: Markovnikov gives OH to more substituted carbon; anti-Markovnikov gives OH to less substituted carbon.
- SN1 mechanism
- A two-step nucleophilic substitution via formation of a carbocation intermediate, rate depends only on substrate.
- SN2 mechanism
- A single-step nucleophilic substitution with backside attack, inversion of configuration, rate depends on both nucleophile and substrate.
- Phenoxide ion
- The conjugate base of phenol, stabilised by resonance over the aromatic ring.
- Fischer esterification
- Acid-catalysed equilibrium reaction between an alcohol and carboxylic acid forming an ester and water.
- Williamson ether synthesis
- Formation of an ether from an alkoxide ion and an alkyl halide via SN2 mechanism.
- Oxidation of alcohols
- Chemical process where primary alcohols form aldehydes then acids, secondary alcohols form ketones, tertiary resist oxidation.
- Diazotisation
- Conversion of aromatic amine to diazonium salt (Ar–N2+) used for substitution such as hydrolysis to phenol.
- Epoxide
- A three-membered cyclic ether with high ring strain and reactivity toward ring-opening.
- Peroxide formation in ethers
- Reaction of ethers with oxygen over time forming dangerous peroxides that must be tested for and removed.
- Hammett equation
- A quantitative relationship relating substituent effects on reaction rates or equilibria to substituent constants.
Practice Questions
-
Give the IUPAC name of CH3CH(OH)CH2CH3 / CH3CH(OH)CH2CH3 का IUPAC नाम बताइए
Show answer
English: Identify the longest chain containing the –OH; number so the OH carbon has the lowest possible number. The molecule is a four-carbon chain with the –OH on C-2, so the IUPAC name is butan-2-ol. Hindi: –OH युक्त सबसे लंबा कार्बन शृंखला खोजिए और –OH कार्बन को सबसे छोटा लोकेन्ट दीजिए। यह चार-कार्बन शृंखला है जिसमें –OH C-2 पर है, अतः IUPAC नाम butan-2-ol है।
-
Explain why phenol is more acidic than ethanol / समझाइए कि फेनोल एथनॉल से अधिक अम्लीय क्यों है
Show answer
English: Phenol is more acidic because after deprotonation its conjugate base (phenoxide ion) is resonance-stabilised: the negative charge is delocalised over the aromatic ring, lowering its energy. Ethoxide ion from ethanol lacks resonance delocalisation and therefore is much less stabilized, making ethanol a weaker acid. Additionally, electron withdrawal by the aromatic system and solvation effects make phenol more easily deprotonated in water. Hindi: फेनोल अधिक अम्लीय है क्योंकि डि-प्रोटोनेशन के बाद उसका संयुग्म क्षार (फेनॉक्साइड आयन) रेजोनेंस द्वारा स्थिर होता है; नकारात्मक आवेश अरوماتिक रिंग पर फैला रहता है जिससे इसकी ऊर्जा कम हो जाती है। एथनॉल से बनने वाला एथॉक्साइड आयन ऐसी रेजोनेंस स्थिरता नहीं रखता, अतः कम स्थिर होता है और एथनॉल कम अम्लीय होता है। अतिरिक्त रूप से अरोमैटिक तंत्र और सॉल्वेशन प्रभाव भी फेनोल को पानी में आसानी से डि-प्रोटोनेट करने में मदद करते हैं।
-
Write equations to show how you would convert chlorobenzene to phenol in the laboratory / प्रयोगशाला में क्लोरोबेंजीन को फेनोल में बदलने के लिये आप कौन-कौन से समीकरण लिखेंगे
Show answer
English: A practical laboratory sequence is: 1) Nitration: C6H5Cl + HNO3 → o-/p-nitrochlorobenzene (mixture). 2) Reduce nitro to amino: C6H4Cl–NO2 → C6H4Cl–NH2 (via Sn/HCl or Fe/HCl). 3) Diazotisation: C6H4Cl–NH2 + NaNO2 + HCl (0–5 °C) → C6H4Cl–N2+Cl−. 4) Hydrolysis (warm): C6H4Cl–N2+ → C6H4Cl–OH (phenol derivative). If starting directly from aniline (no chlorine), the core diazotisation then hydrolysis gives phenol: C6H5NH2 + NaNO2 + HCl → C6H5N2+Cl− → (warm) → C6H5OH. Hindi: एक प्रयोगशाला क्रम इस प्रकार है: 1) नाइट्रेशन: C6H5Cl + HNO3 → o-/p-नाइट्रोक्लोरोबेंजीन (मिश्रण)। 2) नाइट्रो का न्यूनीकरण: C6H4Cl–NO2 → C6H4Cl–NH2 (Sn/HCl या Fe/HCl से)। 3) डाइएजो타इज़ेशन: C6H4Cl–NH2 + NaNO2 + HCl (0–5 °C) → C6H4Cl–N2+Cl−। 4) हाइड्रोलाइसिस (गरम करने पर): C6H4Cl–N2+ → C6H4Cl–OH (फेनोल व्युत्पन्न)। यदि सीधे एनिलीन से शुरू करते हैं तो: C6H5NH2 + NaNO2 + HCl → C6H5N2+Cl− → (गरम) → C6H5OH।
-
Predict products of bromination of phenol with Br2 in aqueous solution / जल मिश्रण में ब्रोमिनेशन पर फेनोल से कौन-से उत्पाद बनेंगे, बताइए
Show answer
English: Phenol is strongly activating and gives electrophilic bromination at ortho and para positions. In aqueous bromination with excess Br2 the reaction proceeds rapidly to give 2,4,6-tribromophenol as the major product. With controlled, limited bromine and low temperature mono-brominated ortho and para isomers (mainly para) can be obtained. Overall with excess Br2: C6H5OH + 3 Br2 → 2,4,6-C6H2Br3OH + 3 HBr. Hindi: फेनोल बहुत सक्रिय है और इलेक्ट्रोफिलिक ब्रोमिनेशन ऑर्थो और पारा स्थानों पर होता है। जल में अधिशेष Br2 के साथ यह त्वरित रूप से 2,4,6-tribromophenol देता है। नियंत्रित मात्रा और कम तापमान पर मोनो-ब्रोमिनेशन कराकर ऑर्थो/पारा समिश्रण (अक्सर पारा प्रधान) प्राप्त किया जा सकता है। कुल समीकरण (अधिशेष Br2 के साथ): C6H5OH + 3 Br2 → 2,4,6-C6H2Br3OH + 3 HBr।
-
Suggest a reagent to convert propan-2-ol into propanone and write the equation / propan-2-ol को propanone में बदलने के लिए एक अभिकर सुझाइए और समीकरण लिखिए
Show answer
English: Use an oxidising agent such as acidified potassium dichromate or PCC. With strong oxidant (acidified dichromate): 3 CH3CH(OH)CH3 + K2Cr2O7 + 4 H2SO4 → 3 CH3COCH3 + Cr2(SO4)3 + K2SO4 + 7 H2O (overall stoichiometric form). More simply: CH3CH(OH)CH3 + [O] → CH3COCH3 (propanone). PCC will oxidise secondary alcohol to ketone under milder conditions without further oxidation. Hindi: इसके लिए अम्लित पोटैशियम डाइक्रोमेट (K2Cr2O7/H2SO4) या PCC जैसी ऑक्सीडाइज़िंग एजेंट का उपयोग कर सकते हैं। मजबूत ऑक्सीडेंट के साथ (संक्षेप): CH3CH(OH)CH3 + [O] → CH3COCH3 (propanone)। PCC जैसे नरम ऑक्सीडेंट से सेकेंडरी अल्कोहल को कीटोन में बदला जा सकता है बिना आगे के ऑक्सीकरण के।
-
Describe Williamson ether synthesis and give a practical example / Williamson इथर संश्लेषण का वर्णन कीजिए और व्यावहारिक उदाहरण दीजिए
Show answer
English: Williamson ether synthesis builds an ether by reacting an alkoxide ion with an alkyl halide via an SN2 mechanism: R–O− + R'–X → R–O–R' + X−. The alkoxide is prepared by deprotonation of an alcohol with a strong base (e.g., NaH or Na metal). This reaction works best with primary alkyl halides; secondary or tertiary halides favour elimination. Practical example: preparation of methyl ethyl ether—generate sodium ethoxide by treating ethanol with sodium metal, then react with methyl iodide: CH3CH2O−Na+ + CH3I → CH3CH2OCH3 + NaI. This proceeds by SN2 displacement of I− by ethoxide. Hindi: Williamson इथर संश्लेषण में अल्कॉक्साइड आयन और अल्किल हलाइड SN2 द्वारा अभिक्रिया कर इथर बनाते हैं: R–O− + R'–X → R–O–R' + X−। अल्कॉक्साइड अल्कोहल के प्रोटोनेशन द्वारा प्राप्त किया जाता है (NaH, Na)। यह प्राथमिक अल्किल हलाइड के साथ सर्वश्रेष्ठ है। व्यावहारिक उदाहरण: मेथाइल इथाइल ईथर की तैयारी—एथेनॉल को सोडियम से अल्कॉक्साइड बनाकर फिर मिथाइल आयोडाइड के साथ अभिक्रिया: CH3CH2O−Na+ + CH3I → CH3CH2OCH3 + NaI। यह SN2 मार्ग में होता है।
-
How would you distinguish between ethanol, phenol and diethyl ether using simple laboratory tests? / सरल प्रयोगशाला परीक्षणों द्वारा आप इथेनॉल, फेनोल और डायएथिल ईथर में कैसे अंतर करेंगे?
Show answer
English: Use three simple tests: 1) FeCl3 test: add neutral FeCl3 solution—phenol gives a violet colour (complex), ethanol and diethyl ether give no colour. 2) Sodium hydroxide test: shake with NaOH solution—phenol dissolves forming sodium phenoxide (aqueous layer), ethanol does not form a water-soluble salt with NaOH, and diethyl ether remains immiscible. 3) Sodium metal test: add a small piece of sodium metal—ethanol reacts vigorously producing hydrogen bubbles; diethyl ether shows no reaction; phenol reacts slowly with sodium but the FeCl3 and NaOH tests are definitive. Using these three, you can identify each compound. Hindi: तीन सरल परीक्षण करें: 1) FeCl3 परीक्षण: तटस्थ FeCl3 डालें—फेनोल वायलेट रंग देता है; एथेनॉल और डायएथिल ईथर कोई रंग नहीं देते। 2) NaOH परीक्षण: नमक-क्षार के साथ हिलाएँ—फेनोल NaOH में घुलकर सोडियम फेनॉक्साइड बनाता है; एथेनॉल ऐसे घुलता नहीं; डायएथिल ईथर ऑर्गेनिक परत में रहता है। 3) सोडियम धातु परीक्षण: थोड़ा सोडियम डालें—एथेनॉल जोरदार प्रतिक्रिया कर H2 बुलबुले देता है; डायएथिल ईथर प्रतिक्रिया नहीं करता; फेनोल थोड़ा प्रतिक्रिया कर सकता है पर FeCl3/NaOH परीक्षण अधिक स्पष्ट हैं। इन तीनों से आप तीनों योगिकों की पहचान कर सकते हैं।
-
Provide a two-step synthesis of tert-butyl chloride from tert-butanol and write mechanisms briefly / tert-butanol से tert-butyl chloride का दो-स्तरीय संश्लेषण दीजिए और संक्षेप में यंत्रविज्ञान लिखिए
Show answer
English: Step 1 (protonation): Treat tert-butanol with concentrated HCl; the hydroxyl is protonated: (CH3)3C–OH + H+ → (CH3)3C–OH2+. Step 2 (carbocation formation and capture): Water departs to form a tertiary carbocation: (CH3)3C–OH2+ → (CH3)3C+ + H2O. Chloride ion then attacks the carbocation to give tert-butyl chloride: (CH3)3C+ + Cl− → (CH3)3C–Cl. Mechanism: an SN1 pathway with carbocation intermediate; racemisation would occur for a chiral centre and rearrangements are not relevant for tert-butyl since the carbocation is already tertiary. Alternatively, PCl5 or SOCl2 can substitute the hydroxyl with chloride via different mechanisms but often give similar product. Hindi: कदम 1 (प्रोटोनेशन): tert-butanol को सांद्र HCl दें; –OH प्रोटोनेट हो जाता है: (CH3)3C–OH + H+ → (CH3)3C–OH2+। कदम 2 (कार्बोकैटायन बनना और क्लोराइड का कैप्चर): पानी निकलकर तृतीयक कार्बोकैटायन बनता है: (CH3)3C–OH2+ → (CH3)3C+ + H2O। फिर Cl− कार्बोकैटायन पर हमला कर tert-butyl chloride बनाता है: (CH3)3C+ + Cl− → (CH3)3C–Cl। मेकानिज्म SN1 प्रकार का है जिसमें कार्बोकैटायन मध्यस्थ बनता है।
-
A student obtains a liquid that gives a broad O–H stretch in IR and a mass spectrum peak at M+ = 46. Suggest the compound and justify / एक विद्यार्थी को एक तरल मिला जिसमें IR में विस्तृत O–H खिंचाव और मास स्पेक्ट्रोम में M+ = 46 पीक है। यौगिक सुझाइए और कारण बताइए
Show answer
English: A molecular ion peak at 46 corresponds to formula C2H6O (molar mass 46). The presence of a broad O–H stretch in IR indicates an O–H group (alcohol or phenol). Combining these data, ethanol (CH3CH2OH) fits: it has M = 46 and shows a broad O–H stretch due to hydrogen bonding. Dimethyl ether (CH3OCH3) has the same formula but no O–H stretch in IR, so it is excluded. Therefore the compound is most likely ethanol. Hindi: M+ = 46 से सूत्र C2H6O (मास 46) आता है। IR में व्यापक O–H पट्टी एक O–H समूह (अल्कोहल/फेनोल) संकेत करती है। इन तथ्यों को मिलाकर इथेनॉल (CH3CH2OH) उपयुक्त है: इसका M = 46 है और यह O–H हाइड्रोजन-बंधन के कारण IR में व्यापक बैंड दिखाता है। डाइमेथाइल ईथर का समान सूत्र है पर उसमें O–H बैंड नहीं होगा, अतः उसे बाहर रखा जा सकता है। इसलिए यौगिक संभावित रूप से इथेनॉल है।
-
Balance and identify products: C6H5OH + CH3COCl → ? / संतुलित समीकरण लिखिए और उत्पाद बताइए: C6H5OH + CH3COCl → ?
Show answer
English: Phenol reacts with acetyl chloride to give phenyl acetate (an ester) and HCl: C6H5OH + CH3COCl → C6H5OCOCH3 + HCl. This is an acylation of the phenolic oxygen. The equation is balanced as written (1:1). The product is phenyl acetate (phenyl ethanoate). Hindi: फेनोल और एसीटिल क्लोराइड अभिक्रियाशील होकर फेनिल एसीटेट (एक एस्टर) और HCl बनाते हैं: C6H5OH + CH3COCl → C6H5OCOCH3 + HCl। यह फेनोल के ऑक्सीजन का एसाइलेशन है और दिया गया समीकरण 1:1 अनुपात में संतुलित है। उत्पाद फेनिल एसीटेट (phenyl ethanoate) है।
-
Explain why tert-butanol does not undergo oxidation to a ketone under mild conditions / क्यों tert-butanol हल्के ऑक्सीकरण अवस्था में कीटोन में परिवर्तित नहीं होता, समझाइए
Show answer
English: Oxidation of an alcohol to a carbonyl requires removal of a hydrogen atom from the carbon bearing the hydroxyl (a C–H bond adjacent to the oxygen). Tertiary alcohols like tert-butanol have no hydrogen on that carbon (the carbon bearing –OH is bonded to three carbon groups), so direct oxidation to a ketone is not possible without breaking a C–C bond. Such C–C cleavage requires much stronger, harsher oxidants and conditions. Therefore tert-butanol is resistant to oxidation under mild oxidising conditions. Hindi: किसी अल्कोहल का कीटोन में ऑक्सीकरण उस कार्बन से हाइड्रोजन हटाने पर निर्भर करता है जिसपर –OH जुड़ा होता है। तृतीयक अल्कोहल (tert-butanol) के उस कार्बन पर ऐसा हाइड्रोजन नहीं होता क्योंकि वह तीन कार्बन समूहों से जुड़ा होता है; इसलिए सीधे कीटोन में ऑक्सीकरण संभव नहीं है बिना C–C बंध टूटे। C–C टूटना बहुत कठोर ऑक्सीडेशन परिस्थितियाँ माँगता है; इसलिए tert-butanol हल्के शर्तों में ऑक्सीकरण का विरोध करता है।
Related Laws & Principles
Explore allFoundational laws & principles connected to this chapter — tap to open in the Laws Explorer.