Overview
This unit explores how electric currents produce magnetic effects and how magnetic fields interact with charges and materials. Beginning with magnetic fields around currents and progressing to forces on moving charges and current-carrying conductors, the unit develops the concepts of magnetic field lines, Biot–Savart law, Ampère's circuital law, and the magnetic field of solenoids and toroids. It covers the motion of charged particles in magnetic fields, the concept and operation of the cyclotron, and the working principles of devices such as the galvanometer, ammeter, and moving-coil loudspeaker. The unit also examines magnetic properties of materials — diamagnetism, paramagnetism and ferromagnetism — and introduces hysteresis and magnetic circuits. Finally, electromagnetic induction and Faraday's and Lenz's laws are treated with applications including eddy currents and transformers. Understanding these topics is crucial for grasping how electrical machines, motors, generators, and many electronic devices work. It also links electricity and magnetism, preparing students for advanced studies in electromagnetism and practical engineering applications.
Learning Objectives
- Describe magnetic field lines and determine field direction using right-hand rules.
- Apply Biot–Savart law and Ampère's circuital law to calculate magnetic fields of simple current configurations.
- Calculate the force on a moving charge and on a current-carrying conductor in a magnetic field.
- Explain motion of charged particles in uniform magnetic fields and solve related numerical problems.
- Describe the principles and working of moving-coil galvanometer and its conversion to ammeter and voltmeter.
- Classify materials by magnetic behaviour and explain ferromagnetism and hysteresis qualitatively.
- Apply Faraday's law and Lenz's law to predict direction and magnitude of induced emf and current.
- Explain working of devices such as cyclotron, transformer and simple motors using magnetic principles.
Topics in this chapter
20 topics · tap a topic title to jump straight to it.
Magnetic Field and Field Lines
What is a magnetic field?
A magnetic field is a vector field around magnets and current-carrying conductors where magnetic forces appear. It is represented by vectors B that give both magnitude and direction. Conceptually, you can imagine placing a tiny compass needle at different points; the needle aligns with the magnetic field showing its direction. Magnetic fields are produced by moving charges and intrinsic magnetic moments of particles.
Field lines: representation and rules
To visualise a field, we draw magnetic field lines. These are imaginary curves whose tangent at any point shows the direction of the magnetic field there. Field lines have these properties: (1) They form closed loops; outside a bar magnet they emerge from the north pole and enter the south pole, and inside the magnet they continue from south back to north. (2) Field lines never cross; crossing would imply two directions for B at a point which is impossible. (3) The density of lines represents field strength — closer lines mean a stronger field. (4) The direction of a line indicates the direction a free north magnetic pole would move.
Field around simple sources
For a small bar magnet, the pattern is dipolar: strong near the poles and weaker away. For a long straight current-carrying conductor, the magnetic field lines are concentric circles around the wire. For a circular current loop, the lines loop through the centre along the axis and close outside around the loop. The superposition principle applies: the field due to several sources is the vector sum of individual fields, so patterns add.
Right-hand rules and directions
Right-hand rules help determine directions: for a straight conductor point your thumb along conventional current and curled fingers show the circular magnetic field direction. For a coil or solenoid, curl fingers in direction of current around turns; your thumb points along the axis in the direction of the resultant magnetic field (shows north pole of coil). For force on moving charges, a different right-hand rule (for v × B) applies; these rules are consistent and essential for solving problems.
Field strength and sources
Magnetic field strength decreases with distance for many sources. For example, for a long straight wire B falls as 1/r, while for a dipole it falls faster. The medium matters: in materials with high permeability the same current produces larger B. Understanding field lines and their properties prepares students to apply quantitative laws such as Biot–Savart and Ampère's law, and to visualise forces and torques in devices like motors and galvanometers.
- Sketch the magnetic field lines around a bar magnet and label north and south poles.
- Use the right-hand rule to show direction of field around a straight wire carrying current upwards.
- Describe how field line density changes when a magnet is cut into two pieces.
- Draw field lines for two like poles placed close to each other.
- Magnetic field direction given by right-hand rule (qualitative).
Biot–Savart Law
Purpose and context
The Biot–Savart law gives a fundamental way to calculate the magnetic field produced at some point by a small segment of a current-carrying conductor. It is especially useful for steady currents and for geometries where you can integrate the contributions of many small current elements. The law is analogous in spirit to Coulomb's law for electric fields, but gives a vector contribution dB from each current element.
Mathematical statement (conceptual)
Consider a small current element I dl located at some point. The contribution dB at point P at distance r from the element is proportional to the current I, the length dl, and the sine of the angle between dl and the vector r that points from the element to P; it is inversely proportional to r^2. The direction of dB is perpendicular to the plane formed by dl and r, following the right-hand rule. The precise vector form is dB = (μ0 / 4π) (I dl × r̂) / r^2. For practical board problems you use this to set up integrals with the appropriate geometry and limits.
Applying Biot–Savart in examples
Key canonical problems where Biot–Savart is applied include: (1) infinite straight wire — integrate along the wire using symmetry to obtain B = μ0 I / (2π r); (2) circular loop — integrate around the loop to find B on the axis and at the centre B = μ0 I / (2 R) for a single turn; (3) finite straight segment — integrate between limits to get expression involving angles; (4) arc of circle — compute partial loop contribution proportional to arc angle. The integration leverages geometry: often the magnitude of dl × r̂ and r can be written in simple forms using trigonometric substitutions.
Symmetry and simplifications
Symmetry often simplifies the Biot–Savart integral. For an infinitely long wire each current element gives a contribution whose azimuthal components add and radial or axial components cancel, leaving a clean circular field. For a circular loop on its axis all contributions have components that add along the axis and cancel radially, giving an axial field expression. Recognising which components cancel saves time and reduces integrals to one variable.
Limitations and utility
Biot–Savart law is exact for steady currents in vacuum or linear media and forms the basis of magnetostatic field calculations. For complex geometries or when time-varying fields are involved Maxwell’s extension and vector potential methods may be more efficient. In ICSE/ISC problems, use Biot–Savart for standard geometries and combine with Ampère's law where symmetry permits a simpler route.
- Use Biot–Savart law to derive B at distance r from an infinitely long straight wire: B = μ0 I / (2π r).
- Compute magnetic field at centre of a circular loop of radius R carrying current I: B = μ0 I / (2 R).
- Find B at a point on the axis of a circular current loop at distance x from centre (setup integration).
- Calculate field due to a finite straight current segment at a point perpendicular to its midpoint (outline).
- dB = (μ0 / 4π) * (I dl × r̂) / r^2
- For infinite straight wire: B = μ0 I / (2π r)
- At centre of circular loop: B = μ0 I / (2 R)
Ampère's Circuital Law
Understanding Ampère's law
Ampère's circuital law links magnetic field around a closed loop to the net steady current passing through the area enclosed by the loop. It is an integral law given by ∮ B · dl = μ0 I_enclosed for magnetostatics. Physically, it says that circulation of the magnetic field along a closed path is proportional to the current threading that path. It is powerful when applied to situations with high symmetry where the integral simplifies.
Choosing an Amperian path
The key to using Ampère's law effectively is choosing the correct closed path (Amperian loop). Select a path that follows the symmetry of the field so that B is constant along parts of the path or zero along others. For a straight long wire choose a circular path centred on the wire; for a solenoid pick a rectangular loop partly inside and partly outside the coil; for a toroid use a circular path concentric with the toroid. With those choices the line integral simplifies to B times path length or to zero on segments where B is negligible.
Derivations with Ampère's law
Examples derived with Ampère's law include: (1) Field around infinitely long straight wire: taking a circle of radius r yields B(2π r) = μ0 I, so B = μ0 I / (2π r). (2) Field inside a long solenoid with n turns per unit length and current I: choose a rectangle with one side inside where B is approximately constant and parallel to the side and the other outside where B ≈ 0; then B × length = μ0 n I × length, giving B = μ0 n I. (3) Field inside a toroid: taking a circular Amperian path at radius r inside the core gives B(2π r) = μ0 N I so B = μ0 N I / (2π r) inside, and approximately zero outside due to circular symmetry and confined flux.
Limits and Maxwell’s correction
Note that the simple form ∮ B · dl = μ0 I_enclosed assumes steady currents and negligible changing electric fields. Maxwell introduced the displacement current term to generalise Ampère's law for time-varying fields: ∮ B · dl = μ0 (I_enclosed + ε0 dΦ_E/dt). For magnetostatic problems on the board, you can usually ignore displacement current and use the simpler form. Ampère's law is complementary to Biot–Savart; choose whichever gives simpler calculation based on symmetry.
Practical tips for problem solving
Identify symmetry (cylindrical, planar, or toroidal), choose an Amperian path aligned with B, evaluate ∮ B · dl as product of B and path length where possible, and compute I_enclosed carefully considering number of turns and current direction. Remember the sign convention from right-hand rule for orientation of loop and direction of current enclosed.
- Apply Ampère's law to derive B around an infinite straight wire: B = μ0 I / (2π r).
- Use Ampère's law to find B inside a long solenoid: B = μ0 n I.
- Derive B inside a toroid: B = μ0 N I / (2π r).
- Explain why B outside an ideal long solenoid is approximately zero.
- Ampère's law: ∮ B · dl = μ0 I_enclosed
- Inside long solenoid: B = μ0 n I
- Inside toroid (at radius r): B = μ0 N I / (2π r)
Magnetic Field on the Axis of a Circular Current Loop and a Solenoid
Magnetic field on the axis of a circular loop
Consider a single circular loop of radius R carrying current I. To find the field at a point P on the axis at distance x from the centre, apply Biot–Savart law by integrating contributions from each element of the loop. Due to symmetry, horizontal components cancel and only the axial components add. The result is B_x = (μ0 I R^2) / (2 (R^2 + x^2)^{3/2}) directed along the axis. This expression shows the field is maximum at x = 0 (centre) where B = μ0 I / (2 R) and decreases with x. Far from the loop (x >> R), the field falls off approximately as 1/x^3, characteristic of a dipole.
Multiple turns and solenoid
A solenoid is made by closely packing many circular loops (turns) along a cylinder. For a solenoid with n turns per unit length and current I, the fields from individual loops superpose. For a long solenoid (length much greater than radius), the magnetic field inside is nearly uniform and directed along the axis: B ≈ μ0 n I. Outside, the fields from loops largely cancel producing a much weaker external field. The uniformity inside and negligible outside are reasons solenoids are used to create controlled magnetic regions for experiments and devices.
Finite solenoid effects
For a solenoid of finite length the axial field varies along the axis; it is strongest near the centre and reduces toward the ends. Using superposition of ring expressions one can derive the axial field at any point in terms of contributions from all turns or via integration treating the coil as continuous. The finite-length formula involves difference of terms with geometry depending on the distances to the ends. Edge effects are important in practical solenoids and must be considered in precision apparatus.
Practical considerations
Adding a high-permeability core inside a solenoid increases B substantially because μ of the core multiplies B in linear regions. However, core materials saturate and show hysteresis so behaviour is nonlinear at high fields. In designing coils, number of turns, current, coil length and core material are parameters to achieve required field strength and uniformity. Experimental measurement of solenoid field using Hall probes or small compasses verifies theoretical predictions.
- Calculate B at the centre of a circular loop of radius 0.05 m carrying 2 A: B = μ0 I / (2 R).
- Estimate B inside a solenoid of 500 turns and length 0.5 m carrying 1 A: n = 1000 turns/m, B = μ0 n I.
- Sketch axial variation of B for a finite solenoid showing maximum at centre and fall near ends.
- Explain qualitatively why field outside a long solenoid is nearly zero.
- \[On axis of loop at distance x: B = (μ0 I R^2) / (2 (R^2 + x^2)^{3/2})\]
- At centre of loop: B = μ0 I / (2 R)
- Inside long solenoid: B = μ0 n I
Force on a Moving Charge in a Magnetic Field; Lorentz Force
Lorentz force law
The Lorentz force describes how a charged particle experiences force in electric and magnetic fields. In the absence of electric field or considering only magnetic effects, a charge q moving with velocity v in a magnetic field B experiences magnetic force F = q (v × B). This vector cross product means the force is perpendicular to both v and B; its magnitude is q v B sinθ where θ is the angle between v and B. The direction follows the right-hand rule for a positive charge; for electrons the force is opposite to that predicted for positive charges.
No work by magnetic force
Since F is perpendicular to v, the magnetic force does no work on the particle and therefore cannot change its speed; it only alters the direction of motion. This fact is important in understanding circular and helical motions produced by magnetic fields. The kinetic energy remains constant in purely magnetic forces, though potential energy in combined fields could change if electric fields are present.
Circular motion for v ⟂ B
If velocity is perpendicular to a uniform magnetic field, the particle moves in a circle. Equating magnetic force q v B to centripetal force m v^2 / r gives radius r = m v / (q B). The angular frequency of rotation (cyclotron frequency) is ω = q B / m and period T = 2π m / (q B), independent of speed (non-relativistic). This is exploited in devices like cyclotrons to accelerate particles by applying an oscillating electric field at fixed frequency.
Helical motion for oblique velocities
If v has components parallel and perpendicular to B, the component perpendicular to B causes circular motion while the parallel component produces uniform motion along B, resulting in a helical trajectory. The pitch of the helix (distance advanced per revolution) is p = v_parallel × T. Such motion explains behaviour of charged particles in Earth's magnetic field where they spiral along field lines and are trapped in radiation belts.
Applications and consequences
Understanding forces on moving charges is essential for designing mass spectrometers, particle accelerators, magnetic confinement devices, and cathode-ray tubes. In conductors, forces on moving charges translate to forces on current-carrying wires (force on a length l: F = I l × B) which underlie operation of motors and deflection devices. When solving numerical problems, carefully track signs, directions and use right-hand rules to deduce direction of forces and resulting motion.
- Calculate radius of path for an electron (mass 9.11e-31 kg, charge 1.6e-19 C) with speed 1e7 m/s in a 0.1 T field: r = m v / (q B).
- Find cyclotron frequency for a proton in 1 T field: ω = q B / m.
- Describe motion when velocity is parallel to magnetic field (no deflection).
- Determine pitch of helix for v_perp = 2e6 m/s, v_parallel = 1e6 m/s in a given B with known period.
- Lorentz force: F = q (v × B)
- Magnitude: F = q v B sin θ
- Radius of circular path: r = m v / (q B)
- Cyclotron frequency: ω = q B / m ; Period: T = 2π m / (q B)
Force Between Parallel Currents and Magnetic Moment
Force between parallel currents
When two long straight parallel conductors carry currents I1 and I2, each produces a magnetic field that acts on the other. The magnetic field at distance r from wire 1 is B1 = μ0 I1 / (2π r). The force on wire 2 per unit length is then F/L = I2 B1 = μ0 I1 I2 / (2π r). The sign of the force depends on current directions: currents in the same direction attract, while opposite directions repel. This interaction forms the basis for the ampere definition and many practical devices.
Physical origin
Microscopically, the force arises because moving charges in one conductor experience magnetic forces due to the field created by the other conductor. The symmetry and inverse dependence on distance result from the circular field pattern of a long straight wire. The mutual forces are equal and opposite in accordance with Newton's third law when considering the entire electromagnetic system (including field momentum in time-dependent cases).
Magnetic moment of current loops
A current loop behaves like a magnetic dipole. The magnetic moment μ of a loop is defined as μ = I A where A is the vector area (magnitude equal to loop area and direction given by right-hand rule). The magnetic moment characterises how a loop interacts with external magnetic fields. In a uniform magnetic field B the loop experiences a torque τ = μ × B tending to align μ with B. The magnitude of this torque is τ = μ B sinθ where θ is angle between μ and B.
Energy and alignment
The potential energy of a magnetic dipole in a field is U = - μ · B. This means the lowest energy configuration is when μ is aligned with B. When the dipole is rotated away from alignment, work must be done against the torque, storing energy which can be released when allowed to align. This principle is used in electric motors and in measuring instruments such as galvanometers where torque on current loops produces measurable deflection.
Applications and measurement
Force between currents is used in sensitive force measurements and the ampere standard. Magnetic moments explain behaviour of loops in magnetic traps, the operation of magnetic compasses, and design of torque-based instruments. In circuit problems, equivalent expressions F = μ0 I1 I2 L / (2π r) for finite lengths and torque τ = N I A B for coils with N turns are commonly used. Always check direction using appropriate right-hand rules and account for superposition when multiple loops or fields exist.
- Calculate force per metre between two parallel wires 0.5 m apart carrying 2 A and 3 A: F/L = μ0 I1 I2 / (2π r).
- Find torque on a rectangular loop of area 0.02 m^2 with current 5 A in a 0.1 T field at 30° to the plane: τ = μ B sin θ.
- Compute magnetic moment of a circular loop radius 0.1 m carrying 2 A: μ = I A = I π r^2.
- Explain direction of force for like vs unlike currents using right-hand rule.
- Force per unit length between parallel currents: F/L = μ0 I1 I2 / (2π r)
- Magnetic moment: μ = I A
- Torque on loop: τ = μ × B ; magnitude τ = μ B sin θ
- Potential energy: U = -μ · B
Hall Effect and Determination of Hall Coefficient
What is the Hall effect and why it matters
The Hall effect occurs when a current-carrying conductor or semiconductor is placed in a magnetic field perpendicular to the current: a transverse voltage appears across the sample. This phenomenon provides a direct method to determine the nature (positive or negative) and density of charge carriers in a material, and is widely used in sensors and characterisation of semiconductors.
Physical mechanism
Consider a thin rectangular slab carrying current I along its length. When a magnetic field B is applied perpendicular to the slab, charge carriers moving with drift velocity v_d experience a magnetic force q (v_d × B) pushing them toward one side. Charges accumulate until an electric field E_H develops which balances the magnetic force. In steady state q E_H = q v_d B, so E_H = v_d B. This transverse electric field gives rise to measurable Hall voltage VH across the width of the sample.
Hall coefficient and calculations
Define current density J = n q v_d where n is carrier density and q the carrier charge. Using E_H = v_d B and J = n q v_d we obtain E_H = (J B) / (n q). The Hall coefficient RH is defined as RH = E_H / (J B) = 1 / (n q). For a sample of thickness t and current I, the Hall voltage VH measured across width w is VH = E_H w = (RH I B) / t when geometry is accounted. Importantly, the sign of RH indicates the sign of q: negative for electron-dominated conduction (n-type) and positive for hole-dominated conduction (p-type).
Experimental determination and applications
In experiments VH is measured for known I, B and t to compute RH and hence carrier density n. Hall-effect sensors use this principle to measure magnetic fields or to detect position and speed in engineering applications. In semiconductor physics RH values help determine doping levels and mobility (combined with conductivity measurements), making the Hall effect a fundamental tool in electronics research and device fabrication.
Practical considerations
Real samples may show complications: multiple carrier types, non-uniform current distribution, and temperature dependence. Corrections may be needed for thin films or when the sample dimensions are comparable to mean free paths. Nonetheless, for many board-level problems the simple relation RH = 1 / (n q) and VH = (RH I B) / t suffices to calculate carrier density and infer sign of carriers reliably.
- Given I, B, t and measured VH compute Hall coefficient RH = VH t / (I B).
- Determine carrier density n from RH using n = 1 / (q RH) and state carrier type from sign of RH.
- Explain why Hall voltage changes sign when semiconductor is doped from n-type to p-type.
- Calculate Hall voltage for a sample carrying 0.5 A, B = 0.2 T, thickness 1 mm and RH known.
- Hall coefficient: RH = EH / (J B)
- Hall voltage: VH = RH (I B) / t
- Carrier density: n = 1 / (q RH)
Magnetism of Materials: Diamagnetism, Paramagnetism and Ferromagnetism
Overview of magnetic behaviour in materials
Materials respond to applied magnetic fields in different ways depending on their atomic structure and electronic configurations. The common classifications are diamagnetic, paramagnetic and ferromagnetic. Each type has distinct microscopic origin and macroscopic properties. Understanding these helps in choosing materials for cores, permanent magnets, and experimental apparatus.
Diamagnetism
Diamagnetism is a universal, weak effect present in all materials, arising from the induced motion of electrons when an external magnetic field is applied. According to Lenz's law, the induced orbital motion produces a magnetic moment that opposes the applied field, giving a small negative magnetic susceptibility (χ < 0). Diamagnetic materials are slightly repelled by magnetic fields and do not retain magnetisation after the field is removed. Examples include copper, bismuth and nitrogen in certain states. The effect is temperature independent and typically very weak compared to other types.
Paramagnetism
Paramagnetic materials contain atoms or ions with permanent magnetic moments (unpaired electron spins). In absence of a field these moments are randomly oriented due to thermal agitation. An external field tends to align them partially, producing a small net magnetisation in the direction of the field and a small positive susceptibility (χ > 0). Paramagnetism is temperature dependent; magnetisation follows Curie's law M ∝ B/T for simple paramagnets, meaning magnetisation decreases with increasing temperature as thermal disorder increases. Examples include aluminium and certain transition metal ions.
Ferromagnetism and domains
Ferromagnetic materials like iron, cobalt and nickel exhibit strong, spontaneous alignment of atomic moments due to quantum mechanical exchange interactions. Below a critical Curie temperature Tc these interactions produce large regions called domains in which moments are aligned. In an unmagnetised ferromagnet domains point in different directions, cancelling overall magnetisation. An applied field reorients domains, producing large net magnetisation. Ferromagnets show saturation magnetisation when nearly all moments align, and can retain magnetisation (remanence) when the field is removed, enabling permanent magnets. Their behaviour is nonlinear and shows hysteresis due to domain wall pinning and energy barriers.
Practical relevance
Choosing materials involves trade-offs: ferromagnets provide strong flux but introduce hysteresis losses; soft magnetic materials (low coercivity) are used where reversible magnetisation is needed (transformer cores), while hard magnetic materials (high coercivity) are used for permanent magnets. Paramagnetic and diamagnetic materials are used where minimal interference is required. The overall magnetic response is characterised by susceptibility χ and relative permeability μr = 1 + χ, which guide engineers and physicists in design calculations.
- Identify given materials (iron, copper, aluminum) as ferromagnetic, diamagnetic or paramagnetic and explain.
- Describe qualitatively how magnetisation changes in a ferromagnet as temperature approaches Curie point.
- Explain why a ferromagnet shows remanence and coercivity using domain idea.
- State why paramagnetism decreases with increasing temperature.
- Magnetic susceptibility χm relates magnetisation M to field H: M = χm H (material-dependent).
Hysteresis and Magnetic Domains
Domains and magnetisation process
Ferromagnetic materials are composed of many small regions called domains, each having aligned magnetic moments. In an unmagnetised specimen domains are oriented such that net magnetisation is small. Applying an external magnetic field causes domain walls to move and certain domains to grow at the expense of others, increasing net magnetisation. Domain rotation and wall motion are microscopic processes that give rise to macroscopic magnetic behaviour. Defects, impurities and stresses pin domain walls, making motion hysteretic.
Hysteresis loop and important quantities
When magnetisation M (or magnetic induction B) is plotted against applied field H for a ferromagnet and H is cycled, the curve traces a loop called the hysteresis loop. Key features: saturation magnetisation (when further increase in H yields negligible increase in M), remanence or residual magnetisation Br (value of B at H = 0 after magnetising), and coercivity Hc (negative H required to reduce B to zero). The loop area equals energy dissipated per cycle as heat due to irreversible domain movements and eddy current effects in AC conditions.
Energy loss and material choice
Hysteresis loss is a major component of iron losses in AC machines and transformers. Soft magnetic materials have narrow hysteresis loops (low Hc and low energy loss) and are preferred for transformer cores; these materials allow easy magnetisation and demagnetisation. Hard magnetic materials have wide loops (high Hc and large remanence) and are chosen for permanent magnets where retaining magnetisation is desired. Engineers tailor composition and heat treatment to obtain required hysteresis characteristics.
Barkhausen effect and microscopic jumps
As H changes smoothly, magnetisation often changes in sudden jumps due to abrupt domain wall movements overcoming pinning sites; this gives small audible noise and measurable discrete steps known as Barkhausen noise. This effect evidences discrete domain dynamics and is used in non-destructive testing and material characterisation.
Magnetic circuits and hysteresis
In magnetic circuit design the nonlinear B–H relation and hysteresis must be considered. Magnetic cores are laminated to reduce eddy current losses and operated within regions of B–H curve that minimise losses for efficient performance. Understanding hysteresis allows correct material selection for motors, transformers and permanent magnets, balancing energy loss, required flux and mechanical properties.
- Sketch a hysteresis loop and label saturation, remanence and coercivity.
- Compare suitability of soft iron vs steel for transformer core vs permanent magnet.
- Explain how domain wall motion leads to sudden jumps in magnetisation (Barkhausen effect).
- Calculate energy loss qualitatively from area of hysteresis loop times volume per cycle.
- Magnetic circuit relation: Φ = mmf / reluctance, analogous to I = V / R
- Reluctance ℜ = l / (μ A) where l is path length and A cross-sectional area
Magnetic Materials: Permeability and Susceptibility
Definitions and relations
Permeability and susceptibility quantify how materials respond to magnetic fields. Magnetic susceptibility χ relates magnetisation M to applied field H by M = χ H. Permeability μ relates magnetic flux density B to H via B = μ H. In vacuum μ = μ0 and in materials μ = μ0 μr where μr is relative permeability and μr = 1 + χ. These parameters are central to magnetic design because they tell how much a material concentrates magnetic flux compared to free space.
Interpretation of values
Diamagnetic materials have small negative χ and μr slightly less than 1, meaning they weaken applied fields slightly. Paramagnets have small positive χ and μr slightly greater than 1; their magnetisation is weak and temperature dependent. Ferromagnetic materials have large positive χ (not constant) and μr much greater than 1 in unsaturated regions; however μr depends strongly on H due to nonlinearity and saturation. Thus permeability is often treated as a function μ(H) in real cores rather than a single constant.
Measurement and frequency effects
Permeability can be measured by applying known H and measuring B. In AC applications the effective permeability may depend on frequency because of eddy currents and magnetic relaxation; high-frequency cores often require special materials (ferrites) with low eddy current losses and controlled μ. Temperature also affects permeability, especially near Curie temperature for ferromagnets where material becomes paramagnetic and μ drops dramatically.
Practical use in devices
High-permeability materials are used for transformer and inductor cores to provide a high flux density for a given magnetomotive force, thereby reducing required turns or current. However, designers must account for saturation (beyond which μ drops) and hysteresis losses. For shielding, materials with high μ can redirect magnetic field lines; thicker or multiple layers can improve shielding. Choosing material requires balancing μ, saturation induction, losses, mechanical properties and cost.
Formulas and constants
For calculations use B = μ0 μr H and M = χ H with μr = 1 + χ. Vacuum permeability μ0 = 4π × 10^-7 H/m. For many classroom problems treating μ and χ as constants suffices, but note when dealing with ferromagnets that nonlinearity and hysteresis make simple linear relations approximate only in limited ranges.
- Compute B in a material with μr = 500 under H = 100 A/m: B = μ0 μr H.
- State whether a material with χ = -1e-5 is diamagnetic or paramagnetic.
- Explain effect of saturation on apparent permeability in a ferromagnet.
- Compare relative permeability values for air, iron and copper qualitatively.
- Magnetisation: M = χ H
- B = μ H = μ0 μr H
- Relative permeability: μr = 1 + χ
- Vacuum permeability: μ0 = 4π × 10^−7 H m^−1
Magnetic Circuits and Analogy with Electric Circuits
Magnetic circuit concept
A magnetic circuit confines magnetic flux Φ along a closed path through magnetic materials and sometimes air gaps. The concept parallels electric circuits: magnetomotive force (mmf) F = N I, analogous to emf V, drives magnetic flux Φ through the circuit, while reluctance ℜ = l / (μ A) plays the role of electrical resistance R. Thus the magnetic circuit equation Φ = F / ℜ mirrors Ohm's law I = V / R and is useful for engineering calculations of flux in cores, gaps and windings.
Reluctance and its dependence
Reluctance depends on path length l, cross-sectional area A and permeability μ: ℜ = l / (μ A). A high-permeability core has small reluctance, concentrating flux effectively. An air gap of length l_g drastically increases total reluctance because μ0 is small compared to core μ; designers often include a controlled gap to limit flux and prevent core saturation. When computing total reluctance in series, add individual reluctances; for parallel paths flux divides inversely according to reluctances.
Analysing magnetic circuits
For a simple core with N turns and current I, mmf = N I produces flux Φ = N I / ℜ_total. When a gap is present, ℜ_total ≈ ℜ_core + ℜ_gap; often ℜ_gap dominates even if l_g is small because μ_gap ≈ μ0. For accurate results include fringing factor for small gaps and consider non-uniform cross-sections. The magnetic analogue facilitates quick estimates of flux, magnetising current, and required turns to achieve a desired induction.
Energy storage and inductance
Energy stored in a magnetic circuit volume V is U = (1/2) ∫ B · H dV. In linear regions this simplifies to (1/2) (B^2 / μ) V. For a coil on a core, inductance L relates flux linkage to current: L = N Φ / I, and stored energy U = (1/2) L I^2. Designing inductors and transformers uses this relation: increasing μ or N increases L and energy storage for given current, but saturation and losses limit practical performance.
Practical advice
When solving board-level problems, draw magnetic circuit, label mmf and individual reluctances, compute ℜ = l/(μ A) for each section, sum for series, and apply Φ = N I / ℜ. Keep track of units and use μ0 = 4π ×10^-7 H/m. Remember gaps increase reluctance disproportionately and are used to control flux and linearise behavior in practical cores.
- Calculate flux in a magnetic circuit with mmf = N I and total reluctance ℜ: Φ = N I / ℜ.
- Compute reluctance of an air gap of length l_g and area A: ℜg = l_g / (μ0 A).
- Explain why adding a small air gap reduces core saturation but increases reluctance.
- Analogy: for two reluctances in series compute total reluctance and flux for given mmf.
- Magnetomotive force: F = N I
- Reluctance: ℜ = l / (μ A)
- Magnetic flux: Φ = F / ℜ
- Stored magnetic energy (linear): U = (1/2) (B^2 / μ) V = (1/2) L I^2
Electromagnetic Induction: Faraday's Law and Lenz's Law
Faraday's law — statement and meaning
Faraday's law states that a changing magnetic flux through a circuit induces an emf in the circuit. In mathematical form ε = - dΦ_B/dt for a single loop; for N turns ε = - N dΦ_B/dt. The induced emf is proportional to the rate of change of flux linkage. This law underlies generators, transformers and many sensing devices. It links magnetic phenomena with electric circuits and shows how time-varying magnetic environments create electric effects.
Lenz's law — direction of induced emf
The negative sign in Faraday's law is Lenz's law: the induced emf acts so as to oppose the change of flux that produced it. If the flux through a loop increases, the induced current produces a magnetic field opposing that increase; if flux decreases, the induced field attempts to maintain it. Lenz's law ensures energy conservation: the induced current produces magnetic fields that resist the cause (motion or change) of induction, requiring work to overcome that opposition.
Types of induction
Self-induction occurs when changing current in a coil changes its own flux, producing a back emf ε = - L dI/dt where L is self-inductance. Mutual induction occurs when changing current in one coil induces emf in another nearby coil: ε_2 = - M dI_1/dt with mutual inductance M. These phenomena are central to transformer operation and coupling between circuits.
Applications and examples
In AC generators mechanical rotation changes flux linking coils producing alternating emf. Transformers transfer energy between circuits using mutual induction. Eddy currents — circulating currents induced in bulk conductors by changing flux — cause heating and energy loss but can be useful in induction heating and braking. Faraday's law also explains electromagnetic damping where induced currents oppose motion and extract kinetic energy as heat. Quantitatively, for simple geometries you compute flux Φ = ∫ B · dA and differentiate to find induced emf; for moving circuits include both explicit time-dependence of B and changing area or orientation.
Practical problem-solving tips
When applying Faraday's law identify what changes: field strength, area of loop, or orientation. Compute flux linkage NΦ and differentiate carefully. Use Lenz's law to determine direction of induced current; draw sketches showing field and induced field to get sign right. For circuits with resistance, induced current I = ε / R and heating power can be computed. For board exams concentrate on clear identification of changing flux and consistent sign conventions to apply Faraday–Lenz correctly.
- A coil with N turns experiences change in flux; compute induced emf using ε = - N dΦ/dt.
- Relate back emf in a solenoid to change of current using self-inductance L: ε = - L dI/dt.
- Use Lenz's law to state direction of induced current when a magnet is pushed into a coil.
- Explain eddy currents and how laminations reduce associated heating in transformer cores.
- Faraday's law: ε = - dΦ_B / dt
- For N turns: ε = - N dΦ_B / dt
- Self-inductance: ε = - L dI/dt
- Mutual inductance: ε_2 = - M dI_1/dt
Inductance: Self and Mutual Inductance
What is inductance?
Inductance measures how much magnetic flux links a circuit per unit current. For a coil the self-inductance L is defined by L = Φ / I for linear media, where Φ is total flux linkage (often N times the flux through one turn). Physically, when current changes in the coil, the changing flux induces an emf opposite to the change, ε = - L dI/dt, which resists rapid changes of current. This property is exploited in filters, chokes and timing circuits.
Factors affecting L
Self-inductance depends on coil geometry: number of turns N (L approximately scales with N^2), coil area A, length l and the core permeability μ. For a solenoid with N turns, length l and core permeability μ, a standard expression is L = μ N^2 A / l, valid when flux is approximately uniform and leakage small. Adding a high-permeability core increases L but introduces nonlinearity and hysteresis at high flux.
Mutual inductance and coupling
Mutual inductance M between two coils measures how much flux in coil 2 links due to unit current in coil 1: M = Φ_21 / I1. Reciprocity ensures M12 = M21. The magnitude of M depends on coil geometry, separation and relative orientation; it is often expressed in terms of coupling coefficient k = M / sqrt(L1 L2) with 0 ≤ k ≤ 1. When coils are tightly coupled (k close to 1) most flux links both coils, which is desired in transformers.
Energy stored in coupled coils
For a single inductor energy stored is U = (1/2) L I^2. For two coupled coils with currents I1 and I2 the magnetic energy includes cross terms: U = (1/2) L1 I1^2 + (1/2) L2 I2^2 + M I1 I2, assuming linear media. This expression shows mutual inductance can either increase or decrease total energy depending on current directions (sign of M I1 I2 term) and coupling.
Series and parallel combinations
When inductors are connected in series, total inductance depends on whether their fluxes aid or oppose each other: L_total = L1 + L2 ± 2 M for closely coupled coils, with sign depending on relative orientation. Uncoupled inductors simply add. In parallel combinations effective inductance uses reciprocal addition analogous to resistors, but coupling alters results. For many ICSE/ISC problems, use formulae for L of a solenoid, M between coaxial coils, and energy expressions to solve numerical questions, and remember coupling coefficient and sign conventions when currents circulate in opposite senses.
- Compute L for a solenoid of N turns, length l, area A and core permeability μ: L = μ N^2 A / l.
- Find induced emf in coil 2 given M and dI1/dt using ε2 = - M dI1/dt.
- Calculate energy stored in coupled coils using U = (1/2) L1 I1^2 + (1/2) L2 I2^2 + M I1 I2.
- Determine series inductance for two coils with known L1, L2 and M.
- Self inductance: L = Φ / I
- Induced emf (self): ε = - L dI/dt
- Mutual inductance: M = Φ_21 / I1 ; ε2 = - M dI1/dt
- Solenoid inductance: L = μ N^2 A / l
- Stored energy: U = (1/2) L I^2 ; coupled: U = (1/2) L1 I1^2 + (1/2) L2 I2^2 + M I1 I2
Alternating Current, Inductive Reactance and R-L Circuits
AC and inductors
In alternating current (AC) circuits an inductor opposes changes in current because a changing current produces a changing magnetic flux which induces a back emf. The opposition to AC is frequency-dependent and is measured by inductive reactance. For sinusoidal steady-state analysis use phasors where voltages and currents are represented as rotating vectors; inductors introduce phase shifts between voltage and current.
Inductive reactance
Inductive reactance X_L is defined as X_L = ω L = 2π f L where ω is angular frequency and f is frequency. The rms voltage across an inductor is V_L = I_rms X_L and the voltage leads the current by 90° in phase for an ideal inductor. Thus in a purely inductive circuit average power absorbed over a full cycle is zero because voltage and current are orthogonal in phase; instantaneous power oscillates but net energy per cycle is zero (neglecting resistive losses).
Series R-L circuit and impedance
For a series resistor R and inductor L connected to an AC source V = V0 sin ωt, total impedance is Z = R + j ω L. The magnitude |Z| = sqrt(R^2 + (ω L)^2) and the phase angle φ = arctan(ω L / R) indicates voltage leads current by φ. The rms current is I_rms = V_rms / |Z|. Real power dissipated is P = I_rms^2 R while reactive power Q = I_rms^2 X_L represents energy exchange between source and inductor. Power factor cos φ = R / |Z| indicates how effectively power is used; inductive loads have lagging power factor (current lags voltage).
Transient response in R-L circuits
When a DC source is suddenly applied to an R-L series circuit the current does not jump instantly because the inductor resists change. The time-dependent current for switch-on is i(t) = (V / R) (1 - e^{-t R / L}) with time constant τ = L / R. On switch-off, current decays exponentially with same time constant. Transients produce voltages that can be large if di/dt is large, motivating the use of flyback diodes or snubber circuits in practice to protect components.
Applications and design considerations
Understanding inductive reactance and R-L behaviour is essential in power systems, motor design, filters, and transient protection. Designers choose inductance and resistance to set time constants and frequency response. For board-level problems compute X_L, impedance, currents, phase angles, transient time constants and energies stored (U = 1/2 L I^2) to analyse AC and DC switching situations accurately.
- Compute X_L for L = 0.1 H at f = 50 Hz: X_L = 2π f L.
- Find current amplitude in series R-L circuit for given V0, R and L at frequency f.
- Describe transient current when DC is applied to series R-L circuit and compute time constant τ = L / R.
- Explain why in purely inductive AC circuit average power absorbed is zero.
- Inductive reactance: X_L = ω L = 2π f L
- Impedance of series R-L: Z = R + j ω L ; |Z| = sqrt(R^2 + (ω L)^2)
- Transient time constant: τ = L / R
- \[Current in transient: i(t) = (V / R) (1 - e^{-t/τ}) for switched-on DC\]
AC Generators and Motors: Basic Principles
Generators: converting mechanical to electrical energy
An AC generator (alternator) converts mechanical rotation into an alternating emf using electromagnetic induction. A coil of N turns and area A rotates with angular speed ω in a uniform magnetic field B. The magnetic flux through the coil varies sinusoidally as Φ(t) = B A cos ωt if the coil axis rotates, and Faraday's law gives emf ε = - N dΦ/dt = N B A ω sin ωt. Thus the output is sinusoidal with amplitude ε0 = N B A ω. Slip rings provide continuous connection to the external circuit allowing alternating voltage output. The frequency of output relates to mechanical speed and number of pole pairs of the rotor.
DC generators and commutation
In a DC generator a commutator replaces slip rings with a segmented conductor that reverses coil connection to the external circuit every half turn so that the output across brushes remains unidirectional (rectified) despite the alternating emf induced in each coil. Commutation is mechanical rectification and requires careful design to reduce sparking and wear at brushes.
Motors: electrical to mechanical energy
A motor performs the reverse: currents in coils placed in magnetic fields experience torque and produce rotation. For a current-carrying loop of area A with current I in field B, the torque magnitude is τ = N I A B sinθ and it tends to align the loop's magnetic moment with B. In DC motors the commutator reverses current in armature coils each half-turn to keep torque direction unidirectional. In AC motors rotating magnetic fields in the stator induce currents or synchronise rotor motion depending on the design (induction vs synchronous motors).
Power, efficiency and losses
Electrical power in AC circuits is P = V I cosφ where cosφ is power factor. In motors and generators losses include copper losses (I^2 R), iron losses (hysteresis and eddy currents in core), mechanical friction and windage. Design strategies to improve efficiency include using high-conductivity windings, low-loss core materials and proper cooling. For large machines, careful balancing of magnetic flux, winding arrangement and cooling systems is essential.
Practical points for board problems
Derive emf amplitude ε0 = N B A ω for simple loop rotations, relate frequency f to rpm and pole pairs, and use torque expressions τ = N I A B for current loops. Understand role of commutator for DC machines, slip rings for AC, and energy conversion principles. Quantitative problems typically involve computing emf, torque, power and relating mechanical speed to electrical frequency.
- Derive emf amplitude for a coil of area A rotating at angular speed ω in field B: ε0 = N B A ω.
- Explain how commutator in a DC motor reverses coil connection to maintain unidirectional torque.
- Describe principle of induction motor briefly where rotating magnetic field induces currents in rotor.
- Compute output frequency of generator rotating at 3000 rpm with 2 pole pairs: f = (rpm/60) × pole pairs.
- Induced emf amplitude in rotating coil: ε0 = N B A ω
- Instantaneous emf: ε(t) = ε0 sin ωt
- Electrical power in AC: P = V I cos φ
Moving-coil Galvanometer and Conversion to Ammeter and Voltmeter
Principle of moving-coil galvanometer
A moving-coil galvanometer detects and measures small DC currents by converting current into mechanical rotation. A coil of N turns suspended in a radial magnetic field carries current I and experiences torque τ = N I A B where A is coil area and B field strength. The coil is attached to a restoring spring with torque proportional to angular deflection θ: τ_restoring = k θ. In equilibrium N I A B = k θ so θ = (N A B / k) I, giving a linear relationship between current and deflection for small angles. A pointer attached to the coil indicates current on a calibrated scale.
Sensitivity and damping
Sensitivity is defined as deflection per unit current and can be improved by increasing number of turns, area or magnetic field, or by reducing spring constant. Damping (electromagnetic or mechanical) is necessary to prevent oscillations and to bring the pointer quickly to steady reading. Electromagnetic damping can be provided by eddy currents in conducting parts moving in magnetic fields, giving critically damped response when designed correctly.
Conversion to ammeter and voltmeter
To measure larger currents, connect a low resistance shunt Rs in parallel with the galvanometer so that most current bypasses the coil; a fraction Ig through the coil produces full-scale deflection while the rest flows through the shunt. For given full-scale current I_fs and galvanometer coil resistance Rg with required Ig, Rs = (Ig Rg) / (I_fs - Ig). To measure voltage, connect a large resistance R_series in series with the galvanometer so only a small current flows through the coil at the required voltage: R_series = (V_fs / Ig) - Rg. Proper selection of resistor values gives multiple ranges.
Practical considerations
Moving-coil instruments are accurate and have linear scales for DC measurements but do not respond to pure AC without rectification because torque depends on instantaneous current sign. They require stable, strong permanent magnets for field uniformity and careful mechanical design for low friction and predictable spring constant. For class problems use linear torque balance, simple algebra for shunt and series calculations, and remember units and sign conventions when converting ranges.
- Given galvanometer coil constant and desired full-scale current, calculate required shunt resistance Rs for conversion to ammeter.
- Calculate series resistance needed to convert galvanometer to voltmeter of given full-scale voltage.
- Explain why moving-coil instruments are preferred for DC measurement due to linear scale and accuracy.
- Describe effect of increasing number of turns on sensitivity.
- Torque balancing: k θ = N I A B ⇒ θ = (N A B / k) I
- Shunt for ammeter: Rs = (Ig Ro) / (I - Ig) for galvanometer current Ig and coil resistance Ro
- Series for voltmeter: R_series = (V_fs / Ig) - Ro where V_fs is full-scale voltage
Eddy Currents and Applications
Formation and nature of eddy currents
Eddy currents are loops of electric current induced inside conductors when the magnetic flux through the conductor changes with time or when the conductor moves through a non-uniform magnetic field. By Faraday's law a changing flux induces emf in the conductor; closed paths within the material allow circulating currents called eddy currents. The direction of these currents follows Lenz's law: they create magnetic fields that oppose the change that produced them.
Consequences: heating and damping
Eddy currents flow through the finite resistivity of the material and dissipate energy as heat (I^2 R losses). This causes unwanted heating and energy loss in transformer cores, rotors and other conducting parts exposed to changing fields. These losses increase with the square of frequency and with conductor thickness for simple geometries, making them significant in AC equipment. On the other hand eddy current damping is used beneficially in instruments and devices to provide smooth, contactless braking and damping of moving parts.
Reduction techniques
To reduce eddy currents designers use lamination: cores are built from thin insulated sheets stacked together so that eddy currents are confined to small loops within each lamina and their magnitude is greatly reduced. Alternatively, using materials with lower electrical conductivity (e.g., ferrites) or introducing slots cuts large current loops. For high-frequency applications core materials are chosen to have low conductivity and suitable magnetic properties to minimise both eddy current and hysteresis losses.
Useful applications
Eddy currents are exploited in induction heating where alternating magnetic fields induce strong currents in metal workpieces producing heat used for cooking or metal hardening. Magnetic braking systems use eddy currents induced in conducting plates moving through magnetic fields to produce non-contact braking forces proportional to speed; this is used in trains and amusement rides for smooth deceleration. Eddy current testing is a non-destructive technique used to detect cracks and defects by measuring changes in induced currents.
Quantitative aspects and design guidance
While exact eddy current loss calculations require solving Maxwell's equations for the conductor geometry, a useful qualitative relation indicates loss scales with frequency squared, thickness squared and field amplitude squared. Engineers reduce losses by decreasing lamina thickness, using high-resistivity materials, lowering frequency where possible, and designing flux paths to avoid large conducting loops. For board problems describe mechanisms and calculate basic qualitative effects; for quantitative questions use provided simplified relations or given geometrical parameters.
- Explain why transformer cores are laminated to reduce eddy current losses.
- Describe how induction heating works using eddy currents and their heating effect.
- Explain principle of magnetic braking using eddy current induced opposing forces.
- Qualitatively relate eddy current loss to frequency and thickness of conductor.
- Eddy current power loss scales roughly as P ∝ t^2 f^2 B^2 σ for simple geometries (qualitative indication where t is thickness, f frequency, σ conductivity).
Transformers: Working, Ideal Transformer and Efficiency
Transformer working principle
Transformers transfer electrical energy between circuits using mutual induction. An alternating current in the primary winding produces a time-varying magnetic flux in the core; this flux links the secondary winding and induces an emf by Faraday's law. Because the process relies on changing flux, transformers operate only with AC (or varying DC). The core's role is to provide a low-reluctance path that keeps flux linking primary and secondary coils for efficient energy transfer.
Ideal transformer relations
For an ideal transformer (perfect coupling, no losses, infinite permeability core) the voltage ratio equals the turns ratio: V1 / V2 = N1 / N2. Also, under ideal conditions power is conserved so V1 I1 = V2 I2, leading to current relation I2 / I1 = N1 / N2. A step-up transformer has N2 > N1 increasing voltage and reducing current; a step-down transformer does the opposite. These simple relations allow quick calculations of secondary voltage and current from primary values and turns ratios.
Real transformer losses and efficiency
Real transformers have several losses: copper losses (I^2 R) in windings, core losses (hysteresis and eddy current losses) in the magnetic core, leakage flux (imperfect coupling) causing reactive power, and stray losses like winding resistance heating and mechanical losses. Efficiency η = (output power / input power) × 100% is high for well-designed transformers, often above 95% or 98% at rated load. To reduce losses cores are laminated to reduce eddy currents and materials with low hysteresis loss (grain-oriented steels or ferrites) are used; low-resistance windings and good cooling also improve efficiency.
Design parameters and applications
Transformer design balances turns, core cross-sectional area, flux density and cooling requirements. Operating flux density must be kept below saturation levels to maintain linear behavior. Step-up transformers are used in power transmission to reduce I^2 R losses over long lines; step-down transformers supply usable voltages for homes and industry. Isolation transformers provide safety by separating circuits. For ICSE/ISC problems use ideal transformer relations for basic questions and include losses when required by problem statements.
Practical computation tips
Use V2 = (N2 / N1) V1 for voltage calculations and N1 I1 = N2 I2 for currents in ideal case. When efficiency or losses are given, compute input or output power accordingly. Consider core material and lamination if asked about loss reduction. Remember transformers do not change frequency and are most efficient near rated load where design minimises fractional losses.
- Given N1, N2 and V1 compute V2 for ideal transformer: V2 = (N2 / N1) V1.
- Compute secondary current for given primary current in ideal transformer using N1 I1 = N2 I2.
- Explain how transformer efficiency is reduced by eddy current losses and how laminations help.
- Determine whether a transformer is step-up or step-down given turns ratio.
- Ideal transformer voltage ratio: V1 / V2 = N1 / N2
- Current relation (ideal): N1 I1 = N2 I2
- Power (ideal): V1 I1 = V2 I2
- Efficiency: η = (P_out / P_in) × 100%
Applications: Cyclotron, Mass Spectrometer and Particle Motion
Cyclotron — principle and operation
A cyclotron accelerates charged particles using a constant magnetic field and an alternating electric field between two hollow D-shaped electrodes (dees). Particles are injected near the centre and experience an oscillating electric field each time they cross the gap, gaining kinetic energy and spiralling outward in the uniform magnetic field. The cyclotron frequency ω = q B / m determines the rate at which particles complete revolutions; for non-relativistic particles this is independent of speed, so a fixed-frequency accelerating voltage keeps the particle in phase. Practical cyclotrons are used to produce radioisotopes and in some medical applications, though relativistic effects limit maximum achievable energies.
Mass spectrometer — separating by m/q
Mass spectrometers separate charged particles or ions by their mass-to-charge ratio (m/q). A common simple configuration uses an ion source to accelerate ions to known kinetic energy, then subjects them to a magnetic field which bends their trajectories into arcs. The radius r = m v / (q B) depends on m/q for a given velocity v. By measuring radii or detector positions one can infer m/q and thus identify isotopes. More advanced spectrometers use electric sectors, time-of-flight methods or quadrupoles for higher resolution and mass range.
Charged particle motion and energy relations
Understanding trajectories requires the Lorentz force F = q v × B: with v ⟂ B you get circular motion radius r = m v / (q B). If kinetic energy KE is known and non-relativistic, v = sqrt(2 KE / m) so r = sqrt(2 m KE) / (q B). For relativistic speeds mass increases effectively and frequency changes, limiting simple cyclotron operation. Velocity selectors using crossed E and B fields select particles of velocity v = E / B before entering mass-analyser magnets, improving resolution.
Applications and practical notes
Cyclotrons and mass spectrometers are vital in research, medical isotope production, and material analysis. Problem-solving typically involves combining circular motion relations with energy or velocity expressions to compute radii, required magnetic fields, or voltages needed. Be careful to state non-relativistic assumptions when using KE = (1/2) m v^2 and note relativistic corrections if speeds are significant fractions of c.
- Compute radius of curvature for proton with given speed in magnetic field using r = m v / (q B).
- Describe how a velocity selector using crossed E and B fields selects particles with v = E / B.
- Explain cyclotron resonance condition and limitation due to relativistic effects.
- Outline mass spectrometer method to determine isotopic composition from measured radii.
- Radius in magnetic field: r = m v / (q B)
- Cyclotron frequency: ω = q B / m
- Velocity selector condition: v = E / B
- Kinetic energy (non-relativistic): KE = (1/2) m v^2
Summary of Laws and Boundary Conditions for Magnetic Fields
Key magnetostatic laws
Collecting the essential relations: the Biot–Savart law gives the magnetic field due to an element of current, dB = (μ0 / 4π) (I dl × r̂) / r^2, useful for direct integration in many geometries. Ampère's circuital law ∮ B · dl = μ0 I_enclosed simplifies calculations where symmetry allows. The Lorentz force F = q (v × B) gives forces on charges; for current elements use F = I l × B. Faraday's law ε = - dΦ/dt governs induction when flux changes. Constitutive relation B = μ H links field and magnetising force in materials. These laws together form the core toolkit for solving magnetism problems in the syllabus.
Boundary conditions at interfaces
At boundaries between two magnetic media certain components of B and H obey continuity relations. The normal component of B is continuous across the boundary if there are no magnetic monopoles: B1n = B2n. The tangential component of H has discontinuity equal to surface current density K: (H2t - H1t) = K × n̂. In absence of free surface current the tangential components of H are continuous. These boundary conditions help when solving problems with different materials, gaps or interfaces, for example flux entering a core from air or flux leakage at edges.
Energy and conservation
Magnetic flux is conserved in closed circuits but can leak in practical arrangements. Energy stored in magnetic fields in linear media is U = (1/2) ∫ B · H dV which reduces to (1/2) L I^2 for inductors. For time-varying fields Ampère's law requires Maxwell's correction (displacement current) making ∮ B · dl = μ0 (I_enclosed + ε0 dΦ_E/dt), connecting changing electric fields with magnetic circulation and ensuring charge conservation.
Problem-solving checklist
When faced with a field problem: (1) Identify symmetry to choose Biot–Savart or Ampère; (2) draw clear diagrams, show directions using right-hand rules and Lenz's law; (3) apply boundary conditions at material interfaces where needed; (4) compute flux and induced emf with Faraday's law for time-varying situations; (5) account for material properties using B = μ H. This approach streamlines solving ICSE/ISC problems and connects conceptual understanding with quantitative results.
- State which law (Biot–Savart or Ampère) is convenient for computing B for a long straight wire, circular loop and solenoid and why.
- Apply boundary condition B_normal continuous at interface to explain field lines entering a material with different μ.
- Use Lorentz force to determine direction of force on a positive charge moving in given B using right-hand rule.
- Explain role of displacement current qualitatively when magnetic field changes with time.
- Biot–Savart: dB = (μ0 / 4π) (I dl × r̂) / r^2
- Ampère's law: ∮ B · dl = μ0 I_enclosed
- Lorentz force: F = q (v × B)
- Faraday: ε = - dΦ/dt ; B = μ H
Key Concepts
- Magnetic field (B)
- A vector field representing magnetic influence at each point, experienced by moving charges and magnetic dipoles.
- Magnetic field strength (H)
- A measure of magnetising force related to B by B = μ H in materials.
- Biot–Savart law
- A law giving magnetic field contribution at a point from an infinitesimal current element.
- Ampère's circuital law
- An integral relation connecting line integral of B around a closed path to enclosed current.
- Lorentz force
- The force q(v × B) on a charge q moving with velocity v in magnetic field B.
- Magnetic moment (μ)
- A vector quantity I A for a current loop representing its strength and orientation as a dipole.
- Hall effect
- The generation of a transverse electric field across a current-carrying conductor in a magnetic field.
- Diamagnetism
- Weak negative magnetic response where induced moments oppose applied field.
- Paramagnetism
- Weak positive magnetic response due to partial alignment of permanent atomic moments.
- Ferromagnetism
- Strong magnetic ordering with spontaneous magnetisation and domain formation.
- Hysteresis
- The dependence of magnetisation on the history of applied field shown by a loop in B–H plot.
- Reluctance (ℜ)
- Magnetic analogue of resistance given by l/(μ A) opposing magnetic flux in a circuit.
- Faraday's law
- The induced emf equals negative rate of change of magnetic flux linked with a circuit.
- Self-inductance (L)
- Flux linkage per unit current in a coil, causing emf ε = - L dI/dt when current changes.
- Mutual inductance (M)
- Flux in one coil per unit current in another, governing induced emf between coupled coils.
- Inductive reactance (X_L)
- Frequency-dependent opposition to AC current in an inductor equal to ω L.
- Eddy currents
- Induced circulating currents in conductors produced by changing magnetic flux causing heating and drag.
- Transformer
- Device transferring AC power between circuits by mutual induction with voltage ratio equal to turn ratio.
Practice Questions
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A long straight wire carries a current of 5 A. Calculate the magnetic field at a point 2 cm from the wire. / एक लम्बा सीधे तार में 5 A धारा बह रही है। तार से 2 सेमी दूरी पर चुंबकीय क्षेत्र की तीव्रता ज्ञात कीजिए।
Show answer
Using B = μ0 I / (2π r). μ0 = 4π × 10^-7 H/m, I = 5 A, r = 0.02 m. B = (4π ×10^-7 × 5) / (2π × 0.02) = (2 ×10^-6 ×5) / 0.02 simplifies to B = 1 ×10^-4 / 0.02 = 5 ×10^-3 T = 5 mT. / B = μ0 I / (2π r) का प्रयोग करें। μ0 = 4π ×10^-7 H/m, I = 5 A, r = 0.02 m। गणना करने पर B = 5 ×10^-3 T = 5 mT मिलता है।
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Two parallel wires 10 cm apart carry currents 4 A and 6 A in the same direction. Find the force per metre between them. / दो समांतर तार जो 10 सेमी अलग हैं, उनमें क्रमशः 4 A और 6 A की धाराएँ समान दिशा में बह रही हैं। इनके बीच प्रति मीटर बल ज्ञात कीजिए।
Show answer
Force per unit length F/L = μ0 I1 I2 / (2π r). μ0 = 4π ×10^-7, I1=4 A, I2=6 A, r = 0.1 m. F/L = (4π ×10^-7 ×4 ×6) / (2π ×0.1) = (96π ×10^-7) / (2π ×0.1) = (48 ×10^-7) / 0.1 = 4.8 ×10^-5 N/m attractive. / F/L = μ0 I1 I2 / (2π r) लगाएं। गणना के बाद F/L = 4.8 ×10^-5 N/m होगा और चूँकि धाराएँ समान दिशा में हैं, बल आकर्षक है।
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A proton with speed 2 × 10^6 m/s moves perpendicular to a uniform magnetic field 0.2 T. Compute the radius of its circular path. (mass of proton = 1.67×10^-27 kg, charge = 1.6×10^-19 C) / एक प्रोटॉन जिसकी गति 2 × 10^6 m/s है, समकोण रूप से 0.2 T के एकसमान चुंबकीय क्षेत्र में जा रहा है। इसके चक्रीय पथ का त्रिज्या ज्ञात कीजिए। (प्रोटॉन का द्रव्यमान = 1.67×10^-27 kg, आवेश = 1.6×10^-19 C)
Show answer
Use r = m v / (q B). m =1.67×10^-27 kg, v=2×10^6 m/s, q=1.6×10^-19 C, B=0.2 T. r = (1.67×10^-27 ×2×10^6) / (1.6×10^-19 ×0.2) = (3.34×10^-21) / (3.2×10^-20) ≈ 0.104375 m ≈ 0.10 m. / r = m v / (q B) का प्रयोग करें। गणना से r ≈ 0.10 m आता है।
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A solenoid has 800 turns, length 0.4 m and carries current 0.5 A. Estimate the magnetic field inside (assume ideal long solenoid). / एक सोलिनॉइड में 800 घुमाव हैं, लंबाई 0.4 m है और वह 0.5 A धारा वहन करता है। अंदर का चुंबकीय क्षेत्र अनुमानित कीजिए (आदर्श दीर्घ सोलिनॉइड मानकर)।
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For long solenoid B = μ0 n I where n = N / l = 800 / 0.4 = 2000 turns/m. B = 4π ×10^-7 × 2000 × 0.5 = 4π ×10^-7 ×1000 = 4π ×10^-4 T ≈ 1.256 ×10^-3 T = 1.26 mT. / B = μ0 n I प्रयोग करें। n = 2000 turns/m, इसलिए B ≈ 1.26 ×10^-3 T = 1.26 mT।
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Explain using Lenz's law the direction of induced current when a bar magnet's north pole is pushed into a coil. / लेंज के नियम का उपयोग करते हुए समझाइए कि जब किसी कुंडली में एक बार चुंबक का उत्तर ध्रुव अंदर धकेला जाता है तो प्रेरित धारा की दिशा क्या होती है।
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As the north pole approaches, the magnetic flux through coil due to north pole increases into the coil. Lenz's law says induced current will produce a magnetic field opposing the increase, i.e., it will produce a north pole facing the approaching north pole. Therefore induced current direction is such that the near face of the coil acts like a north pole. Using right-hand rule, if viewed from magnet side, induced current will be anticlockwise for that requirement (direction depends on geometry). / जैसे ही उत्तर ध्रुव पास आता है, कुंडली में बहने वाला चुंबकीय फ्लक्स बढ़ता है। लेंज का नियम कहता है कि प्रेरित धारा ऐसे चुंबकीय क्षेत्र का निर्माण करेगी जो इस वृद्धि का विरोध करे; इसका अर्थ है कि कुंडली का समक्षीय चेहरा उत्तरध्रुव का जैसा व्यवहार करेगा। इसलिए प्रेरित धारा उस दिशा में होगी जो कुंडली के समक्ष एक उत्तरध्रुव बनाती हो। (दिशा को दाहिने हाथ के नियम से कुंडली के दृश्य के अनुसार निकाला जा सकता है)।
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A transformer has primary turns 500 and secondary turns 2000. If primary voltage is 230 V, find secondary voltage and state whether it is step-up or step-down. / एक ट्रांसफार्मर के प्राथमिक घुमाव 500 और द्वितीयक 2000 हैं। यदि प्राथमिक वोल्टेज 230 V है, तो द्वितीयक वोल्टेज ज्ञात कीजिए और बताइए कि यह step-up है या step-down।
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Voltage ratio V2 / V1 = N2 / N1 = 2000 / 500 = 4. So V2 = 4 × 230 V = 920 V. Since secondary voltage is higher, it is a step-up transformer. / V2 = (N2 / N1) V1 = 4 × 230 V = 920 V। चूँकि द्वितीयक वोल्टेज प्राथमिक से बड़ा है, यह step-up ट्रांसफार्मर है।
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A coil of inductance 0.2 H carries a current that decreases at 10 A/s. Find magnitude of induced emf. / 0.2 H का एक कुंडल ऐसी धारा वहन कर रहा है जो 10 A/s की दर से घट रही है। प्रेरित emf का परिमाण ज्ञात कीजिए।
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Self emf magnitude ε = L |dI/dt| = 0.2 × 10 = 2 V. / ε = L |dI/dt| = 0.2 × 10 = 2 V।
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Describe how eddy currents cause heating in a conducting plate moving in a magnetic field and one method to reduce this heating. / एक चुंबकीय क्षेत्र में गतिशील चालक प्लेट में एड्डी करंट्स कैसे गर्मी पैदा करते हैं और इस गर्मी को कम करने का एक तरीका बताइए।
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Changing magnetic flux through parts of the moving plate induces circulating currents (eddy currents) in loops inside the conductor. Due to finite resistance, these currents dissipate energy as heat (I^2 R losses), warming the plate. To reduce heating, the conductor can be laminated into thin insulated sheets or made of higher resistivity material, which prevents large circulating loops and reduces eddy currents. / प्लेट में बदलते चुंबकीय फ्लक्स के कारण कुंडीय धाराएँ उत्पन्न होती हैं जो चालक के अंदर चक्रीय मार्ग बनाती हैं; इनके कारण I^2 R हानि होती है जो गर्मी पैदा करती है। इसे कम करने के लिए प्लेट को पतली, अलग-अलग इन्सुलेटेड परतों में बनाना (लैमिनेशन) या अधिक प्रतिरोधी सामग्री का प्रयोग किया जाता है।
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A beam of electrons is to be focused using a uniform magnetic field to move in a circle of radius 0.05 m. If electron speed is 3 ×10^7 m/s, what field is required? (electron charge 1.6×10^-19 C, mass 9.11×10^-31 kg) / एक इलेक्ट्रॉन बीम को 0.05 m त्रिज्या के चक्रीय पथ पर केन्द्रित करने के लिए समकोण चुंबकीय क्षेत्र चाहिए। यदि इलेक्ट्रॉन की गति 3 ×10^7 m/s है, तो आवश्यक क्षेत्र ज्ञात कीजिए। (आवेश 1.6×10^-19 C, द्रव्यमान 9.11×10^-31 kg)
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Use r = m v / (q B) ⇒ B = m v / (q r). m = 9.11×10^-31, v = 3×10^7, q = 1.6×10^-19, r = 0.05. B = (9.11×10^-31 × 3×10^7) / (1.6×10^-19 × 0.05) = (2.733×10^-23) / (8×10^-21) ≈ 0.00341625 T ≈ 3.42 ×10^-3 T. / B = m v / (q r) का प्रयोग करें। गणना के बाद B ≈ 3.42 ×10^-3 T आता है।
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