Overview
This chapter introduces Thermodynamics — the branch of physical chemistry that studies energy changes and the direction (spontaneity) of chemical processes. It begins with basic definitions (system, surroundings, types of processes) and builds up to the first and second laws of thermodynamics, internal energy, enthalpy, calorimetry, Hess's law and entropy. Emphasis is on quantitative problem solving (calculating ΔU, ΔH, ΔS and using these to assess processes) and on conceptual understanding (state vs path functions, reversible vs irreversible processes, and criteria for spontaneity). Importance: Thermodynamics provides the fundamental rules that govern whether a reaction can occur and how much heat or work is exchanged. These principles are central to chemical energetics, electrochemistry, industrial processes, biological systems and environmental chemistry. Key themes: (1) Energy bookkeeping — how energy is stored, transferred as heat and work; (2) State functions vs path functions — why some properties depend only on initial and final states; (3) Enthalpy and calorimetry — measuring heat changes at constant pressure; (4) Hess's law and enthalpies of formation/bond enthalpies —…
Learning Objectives
- Define system, surroundings, boundary, and classify systems as open, closed or isolated with examples.
- Explain state functions and path functions and identify examples of each in thermodynamic processes.
- Distinguish between intensive and extensive properties and give examples relevant to thermodynamic problems.
- Differentiate between heat and work and state the sign conventions used in thermochemistry.
- Apply the first law of thermodynamics to calculate changes in internal energy (ΔU), heat (q) and work (w) for closed systems.
- Calculate work done during expansion or compression of gases under constant pressure and for reversible isothermal processes.
- Define enthalpy and relate ΔH to heat exchanged at constant pressure; calculate ΔH for simple chemical reactions.
- Apply Hess's law to determine enthalpy changes of reactions using stepwise reactions and manipulation of given equations.
Topics in this chapter
13 topics · tap a topic title to jump straight to it.
Introduction & Basic Terms
Fig 1 — Educational Diagram: Introduction & Basic Terms
Introduction & Basic Terms
Key Point: ΔU = q + w (First law for a closed system; q: heat added to system, w: work done on system)
Thermodynamics is the branch of chemistry (and physics) that studies energy changes, especially heat and work, associated with physical and chemical processes. It relates macroscopic properties of matter without requiring details of molecular motion.
Basic concepts
- System: The specific part of the universe under study (e.g., gas in a cylinder). Everything else is the surroundings. The system plus surroundings = the universe.
- Boundary: Real or imaginary surface separating system and surroundings; can be fixed or movable, permeable or impermeable.
- Types of systems:
- Open system: both mass and energy can cross the boundary (e.g., boiling pot without lid).
- Closed system: energy (heat/work) can cross but not mass (e.g., sealed piston containing gas).
- Isolated system: neither mass nor energy is exchanged (ideal: insulated, rigid container).
- State of a system: Defined by measurable properties (pressure P, volume V, temperature T, composition). If these are specified, the system is in a particular thermodynamic state.
- State function (property): Depends only on the current state, not on the path taken to reach it (e.g., internal energy U, enthalpy H, pressure, volume, temperature, entropy S).
- Path function: Depends on the path (process) between states (e.g., heat q and work w).
- Intensive vs Extensive properties:
- Intensive: independent of system size (T, P, density).
- Extensive: proportional to system size (mass, volume, internal energy, enthalpy). Extensive properties become intensive when expressed per unit mass or mole (e.g., molar volume).
- Thermodynamic process: Change of state of a system. Common idealized processes:
- Isothermal: constant temperature (T constant).
- Isobaric: constant pressure (P constant).
- Isochoric (isometric): constant volume (V constant).
- Adiabatic: no heat exchange (q = 0).
- Cyclic: system returns to initial state (net Δstate = 0).
- Equilibrium: A system is in thermodynamic equilibrium when macroscopic properties are unchanging in time. Types: mechanical (no net force), thermal (uniform temperature), chemical (no net reaction progress).
- Heat and Work: Modes of energy transfer between system and surroundings. Heat (q) is energy transfer due to temperature difference; work (w) is energy transfer resulting from force acting through a distance (e.g., PV work).
- Internal energy (U): Sum of all microscopic kinetic and potential energies of particles in the system. It is a state function.
- First Law (introductory): Energy is conserved. For a closed system, the change in internal energy equals heat added to the system plus work done on the system:
ΔU = q + w
(Sign convention: q > 0 when heat enters system; w > 0 when work is done on the system.)
Units: SI unit of energy is joule (J). Often heat capacity is expressed in J K-1 or J mol-1 K-1.
Why these terms matter: These definitions let us classify processes, choose appropriate equations, and apply laws (like the first and second laws) to predict energy changes in reactions and physical changes.
- Open system: Boiling water in an open pan — both steam (mass) and heat (energy) leave the system.
- Closed system: Gas in a sealed piston — heat and work can be exchanged, but mass is fixed.
- Isolated system: A well-insulated, sealed thermos — ideally no heat or mass exchange with surroundings.
- Isothermal process: Slow compression of a gas in a cylinder while keeping it in contact with a heat reservoir so T remains constant.
- Adiabatic process: Rapid compression of gas (no time for heat exchange) — temperature rises though no heat is added.
- \[ΔU = q + w (First law for a closed system\]\[q: heat added to system\]\[w: work done on system)\]
- \[w_{PV} = -∫_{V_i}^{V_f} P_{ext} dV (PV work\]\[for reversible w = -∫P_{int} dV)\]
- \[For constant pressure: q_p = ΔH (heat at constant pressure equals change in enthalpy H)\]
- \[Heat capacities: C = dq/dT\]\[C_V = (∂U/∂T)_V\]\[C_P = (∂H/∂T)_P\]
- \[For ideal gas (monoatomic): U = (3/2) nRT (internal energy depends only on T for ideal gases)\]
- \[Extensive vs Intensive: If X(λ system) = λ X(system) then X is extensive\]\[if X is invariant under scaling\]\[it is intensive\]
Properties of Systems
Fig 2 — Educational Diagram: Properties of Systems
Properties of Systems
Key Point: Ideal gas law: PV = nRT
Overview: A thermodynamic system is the portion of the universe under study; everything outside is the surroundings. The boundary separates system and surroundings and may be real or imaginary. Properties of systems are measurable quantities that describe the state of the system.
Types of systems:
- Open system: Exchanges mass and energy with surroundings (example: a boiling kettle where steam leaves).
- Closed system: Exchanges energy but not mass (example: a piston-cylinder assembly with fixed mass of gas).
- Isolated system: Exchanges neither mass nor energy (ideal example: a perfect thermos flask; real isolated systems are approximations).
Classification of properties:
- Intensive properties — independent of system size or amount: temperature, pressure, density, refractive index. These remain the same if the system is divided into parts at equilibrium.
- Extensive properties — depend on system size or amount: mass, volume, internal energy, enthalpy, entropy. If the system is doubled, an extensive property doubles.
- Extensive quantities can be converted to intensive form by dividing by amount: molar (per mole) or specific (per unit mass) properties, e.g., molar volume v = V/n, specific internal energy u = U/m.
State functions vs path functions:
- State functions depend only on the current state, not on how that state was reached: pressure (P), volume (V), temperature (T), internal energy (U), enthalpy (H), entropy (S). Changes in state functions depend only on initial and final states (ΔU, ΔH, ΔS).
- Path functions depend on the process taken: heat (q) and work (w). They are process-dependent and not unique to a state.
Important ideas:
- Equilibrium: A system in thermodynamic equilibrium has uniform intensive properties (no net macroscopic flows). Mechanical equilibrium means equal pressures; thermal equilibrium means equal temperatures.
- Additivity: Extensive properties are additive for non-interacting subsystems; intensive properties are not additive.
- For ideal gases, internal energy and enthalpy depend only on temperature (Joule's law), so ΔU and ΔH are functions of ΔT alone.
Why this matters: Knowing which quantities are state functions allows us to compute changes between states without tracking the detailed path. Classifying properties (intensive/extensive) helps in scaling problems and using molar or specific values in calculations.
- Open system: A running car engine where fuel and exhaust gases cross the control surface and heat is exchanged with surroundings.
- Closed system: Gas in a sealed piston where heat can be added and the piston can move (mass fixed), so the system exchanges energy (work, heat) but not mass.
- Isolated system: Idealized perfectly insulated container—no heat, no work, no mass exchange (approximation: a well-sealed Dewar flask).
- Intensive vs extensive: Two identical beakers of water at 25 °C — temperature (intensive) remains 25 °C for each beaker; volume (extensive) doubles when the beakers are combined.
- State vs path: Compressing a gas isothermally (slow, heat exchanged) versus adiabatically (no heat). The final pressure and volume may be the same for certain end states, but the heat and work exchanged differ (q and w depend on the path).
- \[Ideal gas law: PV = nRT\]
- \[First law (differential form): dU = δq + δw (U is a state function\]\[δq and δw are path-dependent)\]
- \[PV-work (mechanical work): w_PV = -∫ P_ext dV (negative when system expands against surroundings)\]
- \[Enthalpy definition: H = U + PV\]
- \[At constant pressure: q_p = ΔH\]
- \[For ideal gases: ΔU = n C_v ΔT and ΔH = n C_p ΔT\]
State Functions and Path Functions
Fig 3 — Educational Diagram: State Functions and Path Functions
State Functions and Path Functions
Key Point: First law: ΔE = q + w
Definition — State Function: A state function (state property) is a property whose value depends only on the current state of the system (specified by state variables such as pressure, volume, temperature, composition) and not on how the system reached that state. Examples: internal energy (E), enthalpy (H), pressure (P), temperature (T), volume (V), entropy (S), density.
Definition — Path Function: A path function depends on the specific process or path taken between two states. Its value is not determined solely by initial and final states. Examples: heat (q) and work (w). Different paths between the same states can give different amounts of heat or work.
Key distinctions:
- State functions: change depends only on initial and final states: ΔF = F(final) − F(initial).
- Path functions: you must know the path to evaluate them: q = ∫δq (path), w = ∫δw (path).
Mathematical idea (exact vs inexact differential):
- For a state function F(x,y): dF = M(x,y) dx + N(x,y) dy is an exact differential if ∂M/∂y = ∂N/∂x. Integration gives the same result along any path between two points.
- Heat and work are written with the symbol δ (inexact differential), e.g. δq, δw — these are path-dependent and not exact differentials.
Relation with First Law of Thermodynamics:
ΔE = q + w
Here ΔE is a state function (depends only on initial and final states). q and w are path functions. For PV work (mechanical work) usually w = -∫ P_ext dV; the value depends on the process.
Enthalpy: H = E + PV, therefore dH = dE + P dV + V dP. At constant pressure (dP = 0), the heat exchanged at constant pressure equals the change in enthalpy: q_p = ΔH.
Simple examples of dependence on path:
- Isothermal reversible compression of an ideal gas (T constant): w = -nRT ln(V2/V1). The heat q = -w so q depends on path (isothermal vs other).
- Adiabatic compression: q = 0, so ΔE = w. Same initial and final states achieved by a different process will give different q and w though ΔE will be same.
Practical meaning for experiments: When measuring energy changes between two states, it is convenient to use state functions (ΔE, ΔH) because their values are independent of how the change was performed. Heat and work must be evaluated from the known process (path).
Remember: State functions: path-independent. Path functions: path-dependent.
- Heating water in an open kettle (constant pressure): the heat absorbed q_p = ΔH. Enthalpy change depends only on initial (cold water) and final (hot water) states, not how heating was applied.
- Compressing a gas: If you compress isothermally (slow, with heat removal) the work done differs from fast adiabatic compression. ΔE (for closed system of ideal gas with same initial and final T) is path-independent, but q and w differ.
- Raising an object in gravity: gravitational potential energy (mgh) is a state function (depends only on height). Path taken up stairs or elevator does not change mgh. Work done by you and heat dissipated may depend on path.
- Neutralisation of acid and base in calorimeter: measured heat at constant pressure equals ΔH for the reaction; the enthalpy change is the same regardless of how quickly the reaction occurs.
- \[First law: ΔE = q + w\]
- \[For PV work: w = -∫ P_ext dV (path dependent)\]
- \[Isothermal reversible work for ideal gas: w_rev = -nRT ln(V2/V1)\]
- \[Enthalpy: H = E + PV → ΔH = ΔE + Δ(PV)\]\[at constant pressure ΔH = q_p\]
- \[Exact differential test for a function F(x,y): dF = M dx + N dy is exact if ∂M/∂y = ∂N/∂x\]
- \[State function change: ΔF = F(final) - F(initial) (independent of path)\]
Thermodynamic Processes
Fig 4 — Educational Diagram: Thermodynamic Processes
Thermodynamic Processes
Key Point: First law (CBSE convention): ΔU = q + w (q = heat absorbed by system; w = work done on system)
What is a thermodynamic process?
A thermodynamic process is a change that takes a system from one equilibrium state to another. It is described by how pressure (P), volume (V), temperature (T) and other state functions change. Processes can be represented on P–V, T–S or P–T diagrams and are classified by which variables remain constant or by heat/work exchange.
Important preliminaries and sign convention (CBSE/NCERT):
- First law (CBSE convention): ΔU = q + w, where q is heat absorbed by the system and w is work done on the system.
- Work for a mechanical (PV) process: w = −∫V1V2 Pext dV. For a reversible process Pext = Psystem.
- For an ideal gas, internal energy depends only on T: ΔU = nCvΔT and enthalpy ΔH = nCpΔT. Relation: Cp − Cv = R and γ = Cp/Cv.
Common types of processes
- Isothermal (T = constant): Temperature unchanged. For an ideal gas ΔU = 0 so q = −w. Reversible work done on system: wrev = −∫ P dV = −nRT ln(V2/V1).
- Isobaric (P = constant): Pressure unchanged. Work: w = −PΔV. Heat at constant pressure qp = ΔH = nCpΔT.
- Isochoric / Isometric (V = constant): Volume unchanged. No PV work: w = 0, so ΔU = q and q = nCvΔT.
- Adiabatic (q = 0): No heat exchanged. ΔU = w. For a reversible adiabatic (ideal gas): PVγ = constant and TVγ−1 = constant. Work (work done by gas): Wby = (P1V1 − P2V2)/(γ − 1). Using first law: w = ΔU = nCv(T2 − T1) (signs depend on chosen convention).
- Polytropic (PVn = constant): Generalized process. Special cases: n = 0 (isobaric), n = 1 (isothermal), n = γ (adiabatic), n → ∞ (isochoric). For n ≠ 1, reversible work done by gas: Wby = (P1V1 − P2V2)/(1 − n).
- Cyclic process: System returns to initial state. ΔU = 0 for a complete cycle, so net heat absorbed = −(net work done on system) or equivalently net work done by system = net heat absorbed.
- Reversible vs Irreversible: Reversible (quasi-static, infinitesimal gradients) are idealizations; irreversible processes involve friction, rapid changes, finite gradients and produce entropy.
Entropy and reversible heat:
For a reversible process dS = δqrev/T. In an isothermal reversible process at temperature T, qrev = TΔS.
Why these processes matter (Class 11 perspective):
Understanding these ideal processes helps analyze heat engines, refrigerators and many laboratory/engineering operations. They give simple relations between heat, work and state functions and form the basis to study energy conversion and entropy in later courses.
- Isothermal: Slow compression/expansion of gas in a cylinder submerged in a thermal bath (e.g., slow compression so heat flows to keep T constant).
- Isobaric: Boiling water at atmospheric pressure — temperature remains ≈ constant during phase change at 1 atm (practical constant-pressure heating).
- Isochoric: Heating gas in a rigid, sealed container (e.g., pressure cooker sealed volume; pressure rises but volume constant).
- Adiabatic: Rapid compression in a diesel engine cylinder (temperature rises because no time for heat exchange); adiabatic expansion in gas turbines.
- Cyclic: Otto cycle (idealized petrol engine) and Carnot cycle (reversible heat engine model).
- Polytropic: Real compressor/stroke processes often follow polytropic behaviour (intermediate between isothermal and adiabatic).
- \[First law (CBSE convention): ΔU = q + w (q = heat absorbed by system\]\[w = work done on system)\]
- \[Work (general PV work): w = −∫_{V1}^{V2} P_{ext} dV (for reversible process P_{ext} = P_{system})\]
- \[Ideal gas internal energy: ΔU = n C_v ΔT\]
- \[Enthalpy change (constant pressure): ΔH = n C_p ΔT and C_p − C_v = R\]
- \[Isothermal (ideal gas\]\[reversible) work: w_{rev} = −n R T ln(V2/V1)\]
- \[Isobaric work: w = −P ΔV\]
Internal Energy
Fig 5 — Educational Diagram: Internal Energy
Internal Energy
Key Point: ΔU = U_final − U_initial (state function; path independent)
Definition: Internal energy (U) of a system is the total energy contained within the system due to the microscopic motion and interactions of its molecules — the sum of all kinetic and potential energies of the particles. It is a state function: it depends only on the current state (e.g., T, P, V) and not on the path followed to reach that state.
Microscopic view: U = sum of translational, rotational, vibrational kinetic energies and molecular potential energies (intermolecular forces). For a sample: U = Σ(kinetic energy of particles + potential energy due to interactions).
Thermodynamic relations and sign convention:
- First law (for a closed system): ΔU = q + w, where q is heat added to the system and w is work done on the system. (Chemistry sign convention: q > 0 when heat is absorbed by the system; w > 0 when work is done on the system.)
- For mechanical (PV) work: w = -∫P_ext dV. Thus, for a constant external pressure, w = -P_ext ΔV. Combining: ΔU = q - P_ext ΔV (if w is taken as work done by the system in the −PΔV form).
- At constant volume (ΔV = 0): w = 0, so ΔU = q_v (heat at constant volume).
- At constant pressure: q_p = ΔH = ΔU + Δ(PV). For ideal gases Δ(PV) = Δ(nRT) = RT Δn (at constant T), so ΔH = ΔU + R T Δn_gas.
Dependence on state variables:
- For an ideal gas, internal energy depends only on temperature: U = U(T). Therefore ΔU = n C_v ΔT (C_v is molar heat capacity at constant volume).
- For real (non-ideal) substances, U can depend on both T and V (or T and P).
Key practical notes:
- Internal energy is measured in joules (J) in SI units.
- Because U is a state function, for any cyclic process ΔU = 0.
- Bomb calorimeter experiments measure ΔU (constant-volume heat) to determine reaction energies.
- Heating an ideal gas in a rigid, sealed container (constant volume): ΔV = 0 so w = 0 and ΔU = q_v. Temperature rises and internal energy increases by n C_v ΔT.
- Isothermal reversible expansion of an ideal gas: ΔT = 0 so ΔU = 0. Heat absorbed equals work done by the gas (q = −w).
- Adiabatic (no heat exchange) compression/expansion: q = 0 so ΔU = w. Compression (work done on system) increases U and temperature; expansion decreases U and temperature.
- Free (Joule) expansion of an ideal gas into vacuum: no work (w = 0) and no heat (q = 0), so ΔU = 0; temperature of an ideal gas remains unchanged (for real gases temperature may change).
- Combustion measured in a bomb calorimeter (constant-volume): the heat released at constant volume gives ΔU of the reaction directly.
- \[ΔU = U_final − U_initial (state function\]\[path independent)\]
- \[First law: ΔU = q + w (chemistry sign convention: q > 0 when heat absorbed\]\[w > 0 when work done on system)\]
- \[PV work: w = -∫P_ext dV\]\[for reversible processes w_rev = -∫P dV\]
- \[At constant volume: ΔU = q_v\]
- \[At constant pressure: q_p = ΔH = ΔU + Δ(PV)\]
- \[Ideal gas (dependence on T only): ΔU = n C_v ΔT (or per mole: ΔU_m = C_v,m ΔT)\]
First Law of Thermodynamics
Fig 6 — Educational Diagram: First Law of Thermodynamics
First Law of Thermodynamics
Key Point: ΔU = q + w
Statement: The First Law of Thermodynamics is a statement of energy conservation for thermodynamic systems: the change in internal energy of a system equals the heat added to the system plus the work done on the system.
Mathematically: ΔU = q + w.
Meaning and sign convention (chemistry convention):
- ΔU is the change in internal energy of the system. If ΔU > 0, the internal energy increases.
- q is heat exchanged: q > 0 when heat is absorbed by the system; q < 0 when heat is released.
- w is work done on the system: w > 0 if work is done on the system; w < 0 if the system does work on the surroundings.
PV (pressure–volume) work: For expansion/compression against an external pressure P_ext, the work is w = -∫ P_ext dV. For a constant external pressure this reduces to w = -P_ext ΔV. Thus if the system expands (ΔV > 0) it does work on the surroundings and w is negative.
Special cases:
- Isochoric (constant volume): ΔV = 0 → w = 0 → ΔU = q_v. Heat measured at constant volume equals change in internal energy.
- Isobaric (constant pressure): q_p = ΔH, where H = U + PV is enthalpy. For processes with only PV work, ΔH = ΔU + Δ(PV) and at constant pressure q_p = ΔH.
- Isothermal (constant T) for an ideal gas: internal energy depends only on temperature, so ΔU = 0 → q = -w. Heat absorbed equals work done by the system (signs considered).
- Adiabatic: q = 0 → ΔU = w. Work done changes internal energy directly.
- Cyclic process: initial and final states identical → ΔU = 0 → q = -w (net heat exchanged equals minus net work done on the system).
Internal energy and ideal gases: For an ideal gas internal energy depends only on temperature, so ΔU = n C_v ΔT, and ΔH = n C_p ΔT, with C_p - C_v = R for ideal gases.
Historical experiment: Joule's free expansion / mechanical equivalent of heat experiments demonstrated energy conservation between mechanical work and heat, supporting the First Law.
Practical note: The First Law does not tell the direction of processes (that is handled by the Second Law), but it gives the accounting of energy transfers in every process.
- Isochoric heating: Heating gas in a rigid, sealed container — volume constant, w = 0, so ΔU = q_v. Temperature rises according to ΔU = n C_v ΔT.
- Isobaric heating: Boiling water in an open beaker — pressure constant, heat supplied equals change in enthalpy q_p = ΔH.
- Isothermal reversible expansion of an ideal gas (piston moved slowly): ΔU = 0, w_rev = -nRT ln(V2/V1) and q_rev = -w_rev. Useful model for ideal-gas engines.
- Adiabatic compression in a bicycle pump: rapid compression with little heat exchange (q ≈ 0) increases internal energy and temperature: ΔU = w.
- Internal combustion engine cycle (approx.): fuel combustion supplies heat; parts of that energy become work on the piston and the rest increases internal energy or is lost as heat — energy accounting done using the First Law.
- \[ΔU = q + w\]
- \[w_PV = -∫ P_ext dV (for constant P_ext: w = -P_ext ΔV)\]
- \[For reversible PV work of ideal gas: w_rev = -∫ P_int dV = -nRT ln(V2/V1) (isothermal)\]
- \[ΔU = n C_v ΔT (ideal gas)\]
- \[ΔH = ΔU + Δ(PV) = n C_p ΔT (ideal gas)\]
- \[At constant volume: q_v = ΔU\]
Enthalpy
Fig 7 — Educational Diagram: Enthalpy
Enthalpy
Key Point: H = U + PV
What is enthalpy?
Enthalpy (H) is a thermodynamic state function defined as the sum of the internal energy (U) of a system and the product of its pressure (P) and volume (V): H = U + PV. It is a useful quantity for processes occurring at constant pressure because the change in enthalpy equals the heat exchanged with the surroundings at constant pressure.
Mathematical relations and simple derivation
H = U + PV. Differentiating: dH = dU + PdV + VdP.
From the first law, for a reversible process: dU = δq_rev + δw_rev = δq_rev - PdV. Substituting gives dH = δq_rev + VdP. At constant pressure (dP = 0):
ΔH_p = q_p (heat absorbed/released at constant pressure).
Sign convention
ΔH < 0: exothermic (heat released).
ΔH > 0: endothermic (heat absorbed).
Enthalpy of reaction
For a chemical reaction at constant pressure, ΔH(reaction) = H(products) − H(reactants). Standard enthalpy changes (ΔH°) are measured under standard conditions (1 bar, specified temperature, usually 298.15 K).
Useful derived relations
ΔH = ΔU + Δ(PV). For ideal gases, PV = nRT, so Δ(PV) = RΔ(nT) or for fixed n: Δ(PV) = nRΔT and enthalpy depends only on temperature (H = H(T)). For small temperature change and constant pressure:
ΔH ≈ Cp ΔT (or ΔH = ∫Cp dT).
Hess's law
Because enthalpy is a state function, the overall ΔH for a reaction is path independent. We can add enthalpy changes of steps to get the total ΔH. This is the basis for calculating enthalpies of formation and combustion using known data.
Units
SI unit: joule (J) or kilojoule per mole (kJ mol−1) for molar enthalpies.
Practical importance
Enthalpy is central to calorimetry (measuring heat changes at constant pressure), predicting whether reactions are heat-releasing or heat-absorbing, and in engineering calculations (heating/cooling, steam tables, HVAC).
- Combustion of methane: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l), ΔH°combustion ≈ −890 kJ mol−1 (exothermic; heat released in household heating, car engines).
- Formation of liquid water from H2 and O2: H2(g) + 1/2 O2(g) → H2O(l), ΔHf° = −285.8 kJ mol−1 (used in calculations of reaction enthalpies).
- Melting of ice at 0 °C: H2O(s) → H2O(l), ΔHfus ≈ +6.01 kJ mol−1 (endothermic; explains why ice cools its surroundings while melting).
- Neutralization of strong acid by strong base: H+ + OH− → H2O, ΔH ≈ −57 kJ mol−1 (exothermic; used in calorimetry experiments in lab).
- Instant cold packs (endothermic dissolution): ammonium nitrate dissolves in water absorbing heat, producing a cold sensation—this is an enthalpy change of solution.
- \[H = U + PV\]
- \[ΔH = ΔU + Δ(PV)\]
- \[At constant pressure: ΔH = q_p\]
- \[For ideal gases (fixed n): ΔH = ∫Cp dT\]\[and for small ΔT: ΔH ≈ Cp ΔT\]
- \[Enthalpy of reaction: ΔH_reaction = ΣΔH_products − ΣΔH_reactants\]
- \[Standard enthalpy of reaction: ΔH° = ΣνΔHf°(products) − ΣνΔHf°(reactants)\]
Heat Capacity and Specific Heats
Fig 8 — Educational Diagram: Heat Capacity and Specific Heats
Heat Capacity and Specific Heats
Key Point: C = dQ/dT (total heat capacity)
Definition and basic idea
Heat capacity (C) of a body is the amount of heat required to raise its temperature by 1 kelvin (or 1 °C): C = ΔQ/ΔT (or differential form C = dQ/dT). It is an extensive property and depends on the amount of substance and its nature. Units: J K⁻¹.
Specific heat
Specific heat (often called specific heat capacity, c) is the heat required to raise the temperature of unit mass of a substance by 1 K: c = C/m. Units: J kg⁻1 K⁻1. For one mole, molar heat capacity (C_m or C̄) is heat per mole per 1 K, units J mol⁻1 K⁻1.
Common relations
- C (total) = m c (mass × specific heat)
- C (total) = n Cm (moles × molar heat capacity)
- Heat exchanged for a temperature change (assuming constant c or C): ΔQ = m c ΔT = C ΔT = n Cm ΔT
Heat capacities at constant volume and pressure
For gases (and in thermodynamics) we distinguish heat capacity at constant volume, CV, and at constant pressure, CP. For one mole of an ideal gas:
- CP,m − CV,m = R (gas constant)
- For processes: at constant volume ΔQ = n CV,m ΔT; at constant pressure ΔQ = n CP,m ΔT
Relation to microscopic motion (equipartition)
For ideal gases, the equipartition theorem gives CV,m = (f/2)R where f is the number of degrees of freedom per molecule. Then CP,m = CV,m + R. Examples: monatomic (f=3) → CV,m=3/2 R, CP,m=5/2 R; diatomic (approx. at room T, f=5) → CV,m=5/2 R, CP,m=7/2 R.
Temperature dependence and real substances
Specific heats are approximately constant over moderate temperature ranges for many substances, but they generally depend on temperature. For solids, at high temperatures most elements approach the Dulong–Petit limit (molar heat capacity ≈ 3R ≈ 25 J mol⁻1 K⁻1). At low temperatures the molar heat capacity of solids falls off (Debye T³ law). Real gases show deviations from the ideal relations at high pressure / low temperature.
Measurement and sign
Heat capacity is measured by calorimetry. C = dQ/dT is always positive for ordinary materials (temperature increases when heat is added). In experiments one uses mixtures, calorimeters, and corrections for calorimeter heat capacity.
Practical notes
High specific heat means a substance can store more heat per unit mass (water ≈ 4186 J kg⁻1 K⁻1). Metals have relatively low specific heats (e.g., aluminium ≈ 900 J kg⁻1 K⁻1). This knowledge is used in heating/cooling design, thermal storage, and understanding climate (oceans' large heat capacity moderates temperature changes).
- Heating water on a stove: large specific heat of water (≈ 4186 J kg⁻1 K⁻1) means it takes much energy to raise its temperature compared to many solids.
- Car engine cooling: coolant and radiator materials are chosen considering their specific heats and heat-transfer properties to remove engine heat effectively.
- Cooking utensils: a steel pan (low specific heat, heats quickly) with a thick base (large total heat capacity) stores heat and distributes it to food.
- Calorimetry experiment: determine specific heat of a metal by mixing hot metal with cold water in a calorimeter and using m_metal c_metal (T_initial_metal − T_final) = (m_water c_water + C_cal) (T_final − T_initial_water).
- Climate moderation: oceans have huge heat capacity (mass × c) so they absorb/release large amounts of heat, reducing seasonal temperature swings.
- \[C = dQ/dT (total heat capacity)\]
- \[c = C/m (specific heat capacity per unit mass)\]
- \[C_m = C/n (molar heat capacity per mole)\]
- \[ΔQ = m c ΔT (heat for mass m with specific heat c)\]
- \[ΔQ = C ΔT = n C_m ΔT\]
- \[C = m c and C = n C_m\]
Enthalpy Changes in Chemical Reactions
Fig 9 — Educational Diagram: Enthalpy Changes in Chemical Reactions
Enthalpy Changes in Chemical Reactions
Key Point: H = U + PV
What is enthalpy (H)?
Enthalpy is a thermodynamic state function defined as H = U + PV, where U is internal energy, P pressure and V volume. For a given chemical system, the change in enthalpy (ΔH) between initial and final states depends only on those states, not on the path.
Enthalpy change and heat at constant pressure
At constant pressure, the heat exchanged with the surroundings (qp) equals the change in enthalpy: ΔH = qp. Thus, if ΔH < 0 the reaction is exothermic (releases heat); if ΔH > 0 it is endothermic (absorbs heat).
Relation between ΔH and ΔU
For gas-phase reactions, ΔH and ΔU (change in internal energy) are related by the PV term. For ideal gases:
ΔH = ΔU + Δ(PV) = ΔU + ΔngasRT,
where Δngas is change in moles of gaseous species, R the gas constant and T the temperature (K).
Standard enthalpies
Common standard enthalpy quantities (at 1 bar, usually 298 K) used in calculations:
- Standard enthalpy of formation ΔHf°: enthalpy change for forming 1 mole of a compound from its elements in their standard states (elements have ΔHf° = 0).
- Standard enthalpy of combustion ΔHc°: enthalpy change when 1 mole of substance burns in oxygen.
- Standard reaction enthalpy ΔH°rxn: enthalpy change for a balanced reaction under standard conditions.
Hess's law (state function)
Because enthalpy is a state function, the enthalpy change for a reaction equals the sum of enthalpy changes for any series of steps that lead from reactants to products. This allows calculation of ΔH for reactions that are difficult to measure directly.
Calculating ΔH°rxn from formation enthalpies
ΔH°rxn = Σ νp ΔHf°(products) − Σ νr ΔHf°(reactants), where ν are stoichiometric coefficients.
Approximate methods: bond enthalpies
Using average bond enthalpies (gas-phase average values) we approximate ΔH ≈ Σ (bond energies of bonds broken) − Σ (bond energies of bonds formed). This gives reasonable estimates but is less accurate than using tabulated ΔHf° values.
Temperature dependence: Kirchhoff's law
Enthalpy changes vary with temperature. If heat capacities are known, ΔH at a new temperature can be found by
ΔH(T2) = ΔH(T1) + ∫T1T2 ΔCp dT.
For approximately constant ΔCp: ΔH(T2) ≈ ΔH(T1) + ΔCp (T2 − T1).
Sign conventions and common magnitudes
• Exothermic: ΔH negative (e.g., combustion).
• Endothermic: ΔH positive (e.g., melting, evaporation, some dissolutions).
• Typical enthalpies: neutralization of strong acid + strong base ≈ −57 kJ/mol (per mole of water formed); formation of liquid water from elements ΔHf°(H2O, l) ≈ −285.8 kJ/mol.
Practical notes for Class 11
Understand how to (1) relate heat at constant pressure to ΔH, (2) use ΔH = ΣΔHf°(products) − ΣΔHf°(reactants), (3) apply Hess's law with stepwise reactions, (4) convert between ΔU and ΔH using ΔngasRT, and (5) use bond enthalpies for estimates.
- Combustion of methane (complete): CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l). Using standard formation enthalpies (ΔHf°: CH4 = −74.8 kJ/mol, CO2 = −393.5 kJ/mol, H2O(l) = −285.8 kJ/mol) gives ΔH°rxn = [−393.5 + 2(−285.8)] − [−74.8 + 0] = −890.3 kJ per mole CH4 (exothermic).
- Neutralization: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l). Standard enthalpy of neutralization for strong acid + strong base ≈ −57 kJ per mole of water formed (exothermic; basis for calorimetry in labs).
- Dissolution cold pack (endothermic): NH4NO3(s) → NH4+(aq) + NO3−(aq). Heat is absorbed from surroundings; temperature of pack falls (ΔH > 0).
- Hand warmers (exothermic): Oxidation of iron (Fe + 1/2 O2 → FeO(s) and further oxidation) releases heat used in disposable warmers (ΔH < 0).
- Melting of ice: H2O(s) → H2O(l). This is endothermic; ΔHfusion ≈ +6.01 kJ/mol at 0 °C.
- \[H = U + PV\]
- \[ΔH = H_final − H_initial\]
- \[At constant pressure: ΔH = q_p\]
- \[ΔH = ΔU + Δ(PV) → for ideal gases: ΔH = ΔU + Δn_gas·R·T\]
- \[Standard reaction enthalpy: ΔH°_rxn = Σ ν_products·ΔH_f°(products) − Σ ν_reactants·ΔH_f°(reactants)\]
- \[Bond enthalpy estimate: ΔH ≈ Σ (bond energies of bonds broken) − Σ (bond energies of bonds formed)\]
Hess's Law and Thermochemical Calculations
Fig 10 — Educational Diagram: Hess's Law and Thermochemical Calculations
Hess's Law and Thermochemical Calculations
Key Point: Hess's law (conceptual): ΔH_total = Σ ΔH_steps
What is Hess's Law?
Hess's Law states that the enthalpy change for a chemical reaction is the same, no matter how many steps or which route the reaction takes, provided initial and final conditions are the same. This is because enthalpy (H) is a state function and depends only on the initial and final states, not on the path.
Why it works (brief justification)
Because enthalpy is a state function, the net change in enthalpy for any overall reaction equals the algebraic sum of enthalpy changes for individual steps that add up to the overall reaction. Graphically, any two paths between the same reactants and products have the same vertical difference in an enthalpy diagram.
Rules for using Hess's Law
- If you reverse a reaction, change the sign of ΔH.
- If you multiply a reaction by a factor n, multiply ΔH by n.
- Add reactions algebraically (after making necessary reversals/multiplications). The ΔH for the overall reaction is the sum of the ΔH values for the modified individual reactions.
Common uses
Hess's Law is used to calculate enthalpy changes that are difficult to measure directly by combining known reactions (e.g., formation enthalpies, combustion enthalpies, bond energies approximations).
Relationship to standard enthalpies of formation
For a reaction at constant pressure: ΔH°reaction = Σ ΔHf°(products) − Σ ΔHf°(reactants). Because formation enthalpies are defined for producing 1 mole of substance from its elements in their standard states, tabulated ΔHf° values + Hess's Law let you compute many reaction enthalpies.
Approximation using bond enthalpies
An approximate ΔH for a gas-phase reaction can be estimated by: ΔHreaction ≈ Σ(D bonds broken) − Σ(D bonds formed), where D is average bond dissociation energy. This is approximate because bond energies depend on molecular environment.
Step-by-step example (numeric)
- Given: C(graphite) + O2 → CO2 ; ΔH°1 = −393.5 kJ
- Given: CO + 1/2 O2 → CO2 ; ΔH°2 = −283.0 kJ
- We want: C(graphite) + 1/2 O2 → CO (ΔH°?).
- Algebra: (1) − (2) gives C + 1/2 O2 → CO. Therefore ΔH° = ΔH°1 − ΔH°2 = −393.5 − (−283.0) = −110.5 kJ.
Practical notes
All ΔH values should use the same reference states and units (usually kJ mol−1). Use standard states (ΔH°) if mixing tabulated standard formation or combustion values. Watch stoichiometric coefficients and signs when manipulating equations.
- Determining the enthalpy of formation of methane from measured combustion enthalpies: use Hess's law to combine combustion of C and H2 with combustion of CH4 to get ΔHf(CH4).
- Calculating the heat released in fuel combustion indirectly: combine known formation enthalpies of reactants and products to get combustion ΔH° when direct calorimetry is difficult.
- Finding enthalpy for formation of CO (incomplete combustion) using known data for CO2 formation and CO oxidation (example shown above).
- Estimating reaction enthalpy for gas-phase reactions using bond enthalpies when tabulated ΔHf° are unavailable (approximate method).
- Heat of neutralization: use known formation enthalpies of water and ionic species to compute the enthalpy change for acid–base neutralization.
- \[Hess's law (conceptual): ΔH_total = Σ ΔH_steps\]
- \[Standard reaction enthalpy from formation enthalpies: ΔH°_reaction = Σ ΔHf°(products) − Σ ΔHf°(reactants)\]
- \[Reversing a reaction: if A → B has ΔH\]\[then B → A has ΔH' = −ΔH\]
- \[Scaling a reaction: if reaction R has ΔH\]\[then n·R has enthalpy n·ΔH\]
- \[Approximate bond-energy method: ΔH_reaction ≈ Σ D(bonds broken) − Σ D(bonds formed)\]
- \[Units: ΔH usually expressed in kJ mol−1\]
Bond Enthalpies and ΔH Estimation
Fig 11 — Educational Diagram: Bond Enthalpies and ΔH Estimation
Bond Enthalpies and ΔH Estimation
Key Point: Definition: D = enthalpy required to break 1 mol of a bond in the gas phase (kJ mol^-1).
What is bond enthalpy?
Bond enthalpy (also called bond dissociation enthalpy or bond energy, D) is the enthalpy change required to break one mole of a particular bond in a gaseous molecule into gaseous atoms, under standard conditions. It is expressed in kJ mol^-1 and is always positive because bond breaking is endothermic.
Average bond enthalpies
Measured bond enthalpies are usually average values because the energy required to break the same type of bond depends slightly on the molecular environment. For example, the C–H bond in methane has a slightly different dissociation energy than a C–H bond in benzene; tabulated values are averages over many compounds.
Estimating reaction enthalpy (ΔH) from bond enthalpies
We can estimate the enthalpy change of a reaction by considering which bonds are broken and which are formed. Breaking bonds absorbs energy (positive), forming bonds releases energy (negative). The approximate formula used is:
ΔH ≈ Σ D(bonds broken) − Σ D(bonds formed)
Steps to estimate ΔH:
- Write a balanced chemical equation and draw or identify all bonds broken in reactants and bonds formed in products.
- Use tabulated average bond enthalpies (kJ mol^-1) for each bond type.
- Sum energies of bonds broken, sum energies of bonds formed, then subtract: ΔH ≈ (broken) − (formed).
Sign convention and interpretation
If Σ(broken) > Σ(formed), ΔH is positive → reaction is endothermic (net energy absorbed). If Σ(broken) < Σ(formed), ΔH is negative → reaction is exothermic (net energy released). This method gives an estimate — not an exact value — because it uses average gas-phase bond energies and ignores effects such as phase changes, resonance stabilization, and intermolecular interactions.
Limitations and cautions
- Bond enthalpies are averages; the method is approximate, best for gas-phase reactions.
- It does not account for physical state (liquid/solid) or solvation effects, or work terms (PV) in condensed phases.
- Resonance, conjugation, and strained rings make actual energies deviate from tabulated averages.
- For more accurate ΔH values, use Hess's law with standard enthalpies of formation (ΔHf°) when available.
Relation to Hess's law
Bond enthalpy estimates are consistent with Hess's law conceptually: enthalpy is a state function. But Hess's law applied with standard enthalpies of formation (tabulated ΔHf°) gives exact standard reaction enthalpies, whereas bond enthalpy sums are approximate.
Typical tabulated values (examples)
H–H ≈ 436 kJ mol^-1, Cl–Cl ≈ 243 kJ mol^-1, H–Cl ≈ 431 kJ mol^-1, C–H ≈ 413 kJ mol^-1 (average), O=O ≈ 498 kJ mol^-1, C=O (in CO2) ≈ 799 kJ mol^-1 (approx average). Always use values from your textbook or data tables for calculations.
- Example 1 — Simple: H2 (g) + Cl2 (g) -> 2 HCl (g). Use bond enthalpies H–H = 436 kJ/mol, Cl–Cl = 243 kJ/mol, H–Cl = 431 kJ/mol. Bonds broken = H–H + Cl–Cl = 436 + 243 = 679 kJ. Bonds formed = 2 × H–Cl = 2 × 431 = 862 kJ. Estimated ΔH = 679 − 862 = −183 kJ (exothermic).
- Example 2 — Combustion of methane (approximate): CH4 + 2 O2 -> CO2 + 2 H2O. Using average bond enthalpies: 4×C–H (4×413) + 2×O=O (2×498) broken = 1652 + 996 = 2648 kJ. Bonds formed: CO2 has 2×C=O (2×799 = 1598) and 4×O–H in water (4×463 = 1852) total = 3450 kJ. ΔH ≈ 2648 − 3450 = −802 kJ (approx; actual ΔH°combustion ≈ −890 kJ/mol because of limitations of average values and phase effects).
- Real-life example — Fuel combustion: In car engines and power plants, chemical energy stored in fuel bonds (C–H, C–C) is released as bonds in CO2 and H2O are formed, producing heat and motion. Bond enthalpy reasoning explains why fuels release energy when oxidized.
- Real-life example — Industrial chemistry: In the Haber process (N2 + 3H2 -> 2NH3), strong N≡N bonds must be broken (high D), so catalysts and high temperatures/pressures are used to make the reaction practical.
- \[Definition: D = enthalpy required to break 1 mol of a bond in the gas phase (kJ mol^-1).\]
- \[Average bond enthalpy: D_avg(bond type) — typical values taken from tables (e.g.\]\[C–H ≈ 413 kJ mol^-1).\]
- \[ΔH (estimated) ≈ Σ D(bonds broken) − Σ D(bonds formed) (units: kJ mol^-1).\]
- \[Sign: If ΔH <\]\[0 → exothermic\]\[ΔH >\]\[0 → endothermic.\]
- \[Relation: Hess's law (exact method) uses standard enthalpies of formation: ΔH°rxn = Σ ΔHf°(products) − Σ ΔHf°(reactants).\]
Calorimetry and Experimental Determination of Heat Changes
Fig 12 — Educational Diagram: Calorimetry and Experimental Determination of Heat Changes
Calorimetry and Experimental Determination of Heat Changes
Key Point: q = m c ΔT (heat absorbed or released by a substance; m in g, c in J g^-1 K^-1, ΔT in K or °C)
What is calorimetry?
Calorimetry is the experimental science of measuring heat exchanged in physical and chemical processes. A calorimeter is an apparatus that measures temperature changes that result from heat flow between a system (reaction or body) and its surroundings. In chemical calorimetry we use measured temperature changes to calculate heat absorbed or released.
Basic concepts
- Heat (q): energy transfer because of temperature difference. Measured in joules (J) or calories (cal).
- Specific heat capacity (c): heat required to raise 1 g of a substance by 1 K (J g^-1 K^-1).
- Heat capacity (C): heat required to raise the temperature of an object by 1 K (J K^-1). For a sample, C = m c.
- Enthalpy (H) and reaction heat (ΔH): at constant pressure, the heat exchanged equals change in enthalpy (q_p = ΔH).
Key experimental setups
- Constant-pressure calorimeter (coffee-cup calorimeter): an insulated cup or beaker used for reactions in aqueous solution. Temperature change of the solution is measured; q_p ≈ ΔH(reaction).
- Constant-volume calorimeter (bomb calorimeter): a rigid, insulated vessel used for combustion reactions. Heat is transferred to a surrounding water bath; temperature rise of the bath is used to calculate heat of combustion. Because volume is fixed, the measured heat corresponds to ΔE (internal energy change); enthalpy can be obtained by correction if needed.
Calorimetric energy balance
Under ideal insulation (no heat loss to surroundings) the algebraic sum of heat changes is zero:
q_reaction + q_solution + q_calorimeter = 0
Using q = m c ΔT for sample and solution and q_cal = C_cal ΔT for the calorimeter (where C_cal is calorimeter constant), we solve for the unknown heat.
Common laboratory determinations
- Specific heat of a metal: a hot metal piece is dropped into known mass of water at lower temperature inside a calorimeter. Measure equilibrium temperature and apply heat balance to find c_metal.
- Enthalpy of neutralization: mixing acid and base in a calorimeter and measuring temperature rise gives q_p; dividing by moles gives molar enthalpy of neutralization.
- Enthalpy of combustion (bomb calorimetry): measure temperature rise of the calorimetric water bath when a known mass of fuel combusts inside the bomb; use calorimeter constant to find heat per gram or per mole.
Assumptions and corrections
- Perfect insulation is assumed but in practice there is heat loss; often corrected by extrapolating temperature vs time before and after reaction to the reaction moment.
- Mixing and thermal equilibration are assumed complete.
- For constant-pressure calorimetry in solution, PV work is negligible for condensed-phase reactions, so q_p = ΔH.
Practical procedure highlights
- Record initial temperatures of each component and calorimeter. Mix/react and monitor temperature until stable. Use the maximum (or equilibrium) temperature change ΔT, applying corrections for heat losses if needed.
- Include the calorimeter heat capacity (C_cal) when it is not negligible: the calorimeter itself absorbs heat.
- Take multiple trials and average; note sources of error like incomplete combustion, heat losses, evaporation, or stirring losses.
Connection to thermodynamics
Calorimetry provides experimental values of heat changes, which correspond to state functions (like enthalpy) for processes at constant pressure. These measured enthalpies can be used with Hess's law to obtain heats of formation, reaction, and combustion.
- Determining the specific heat capacity of a metal: Heat a metal rod to a high temperature, drop it into known mass of water in a calorimeter, measure equilibrium temperature and calculate c_metal using heat balance.
- Enthalpy of neutralization: Mix 50 mL of 1.0 M HCl with 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, measure temperature rise, and compute ΔH per mole of water formed.
- Combustion enthalpy of ethanol: Burn a known mass of ethanol in a bomb calorimeter, measure the water-bath temperature rise, and use the calorimeter constant to get ΔH_combustion (kJ mol^-1).
- Food energy measurement: Bomb calorimetry is used to determine the caloric content (kcal per gram) of food by combusting a sample and measuring heat released.
- Practical heat capacity insight: Water’s high specific heat moderates climate and is exploited in thermal storage systems and cooking applications (slow heating/cooling).
- \[q = m c ΔT (heat absorbed or released by a substance\]\[m in g\]\[c in J g^-1 K^-1, ΔT in K or °C)\]
- \[q_total = 0 → q_reaction + Σ q_everything_else = 0 (energy conservation in an isolated calorimeter)\]
- \[q_calorimeter = C_cal ΔT (C_cal is calorimeter constant\]\[J K^-1)\]
- \[For constant pressure: q_p ≈ ΔH (heat measured at constant pressure equals enthalpy change)\]
- \[Molar enthalpy: ΔH_molar = q_p / n (n = moles of limiting reactant or product basis)\]
- \[Specific heat of a hot metal from calorimetry: c_metal = ((m_water c_water + C_cal) (T_final - T_initial_water)) / (m_metal (T_initial_metal - T_final))\]
Applications and Problem-Solving Techniques
Fig 13 — Educational Diagram: Applications and Problem-Solving Techniques
Applications and Problem-Solving Techniques
Key Point: First law: ΔU = q + w (q positive when heat absorbed; w positive when work done ON system)
Overview
This topic explains how the basic thermodynamic concepts (heat, work, internal energy, enthalpy) are used to solve chemical problems and to analyse real processes. Emphasis is on choosing the right state function, applying the first law of thermodynamics, using calorimetry, and using Hess's law or standard enthalpies to compute enthalpy changes.
Key ideas and sign conventions
- System vs surroundings: define what you treat as the system.
- First law (energy conservation): ΔU = q + w. Here q is heat absorbed by system (q > 0 when absorbed), w is work done on system (w > 0 when done on system). For pressure–volume work done by the system, w = -P_ext ΔV.
- Enthalpy: H = U + PV. For processes at constant pressure, ΔH = q_p (heat exchanged at constant pressure).
- State functions (ΔU, ΔH): path-independent — use Hess's law to add reactions.
- Calorimetry and energy balance: q_reaction + q_surroundings = 0 for an isolated calorimeter.
General problem-solving procedure
- Step 1: Read carefully and define the system and what is asked (ΔU, ΔH, q, w, etc.).
- Step 2: Note process conditions: constant volume → use ΔU = q_v; constant pressure → use ΔH = q_p.
- Step 3: Choose the appropriate formula (first law, q = mcΔT, Hess's law, bond enthalpies, etc.).
- Step 4: Convert all quantities to consistent units (J, mol, K, Pa, m^3). Watch sign conventions.
- Step 5: If needed, use ideal gas relations (PV = nRT) to obtain work or Δ(PV) terms: for ideal gases Δ(PV) = Δ(n)RT when T is constant or use Δ(PV) explicitly.
- Step 6: For multi-step reactions use Hess's law or standard enthalpies: ΔH°rxn = ΣνΔHf°(products) − ΣνΔHf°(reactants).
- Step 7: Check reasonableness of result (sign and magnitude) and include units.
Common applications
- Calorimetry: determining enthalpy changes of reaction (combustion, neutralization, dissolution) using q = mcΔT.
- Gas expansion/compression: computing work w = -∫P_ext dV and ΔU from q and w.
- Using Hess's law or standard enthalpies to get ΔH of reactions not easily measured directly.
- Estimating reaction enthalpies from average bond enthalpies: ΔH ≈ ΣD(bonds broken) − ΣD(bonds formed).
Tips & common pitfalls
- Remember q_p = ΔH and q_v = ΔU (for non‑PV work, adjust accordingly).
- When a gas expands against constant external pressure, work done by system is positive for the system but w in the ΔU equation is negative (w = -P_extΔV).
- Hess's law: you may reverse or multiply equations, reversing changes sign and multiplying changes magnitude accordingly.
- Bond enthalpies give approximations because they are averages and depend on molecular environment.
- Example 1 — ΔU for a gas process: A system absorbs 5.00 kJ of heat and does 2.00 kJ of PV work on the surroundings. Using ΔU = q + w, and w (work done by system) = -2.00 kJ, ΔU = 5.00 + (-2.00) = +3.00 kJ.
- Example 2 — Constant pressure calorimetry (neutralization): 25.0 mL of 1.0 M HCl is mixed with 25.0 mL of 1.0 M NaOH in a calorimeter. If the temperature of the solution rises from 25.0 °C to 28.2 °C and the total solution mass is 50.0 g with specific heat 4.18 J g−1 K−1, q_solution = mcΔT = 50.0×4.18×3.2 = 668.8 J. q_reaction = -q_solution = -668.8 J. Moles of limiting reagent = 0.025 mol, so ΔH ≈ -668.8 J / 0.025 mol = -26.8 kJ mol−1 (enthalpy of neutralization, approximate).
- Example 3 — Using Hess's law: Given ΔH°f(CO2(g)) = -393.5 kJ mol−1 and ΔH°f(H2O(l)) = -285.8 kJ mol−1, calculate ΔH° for CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) if ΔH°f(CH4) = -74.8 kJ mol−1. Use ΔH°rxn = ΣΔH°f(prod) − ΣΔH°f(react): = [(-393.5) + 2(-285.8)] − [(-74.8) + 2(0)] = (-965.1) − (-74.8) = -890.3 kJ mol−1 (combustion enthalpy, approx).
- \[First law: ΔU = q + w (q positive when heat absorbed\]\[w positive when work done ON system)\]
- \[PV work (constant external pressure): w = -P_ext ΔV\]
- \[Enthalpy: H = U + PV\]
- \[Relation between ΔH and ΔU for ideal gases: ΔH = ΔU + Δ(PV) = ΔU + Δn_g RT\]
- \[Constant pressure heat: q_p = ΔH\]
- \[Constant volume heat: q_v = ΔU\]
Key Concepts
- System
- The portion of the universe chosen for study, separated from the surroundings by a boundary; can be open, closed or isolated.
- Surroundings
- Everything external to the system with which the system can exchange energy or matter (depending on system type).
- Boundary
- The real or imaginary surface that separates the system from its surroundings; may be fixed or movable and permeable or impermeable to heat/work/matter.
- Universe
- The system plus its surroundings; in thermodynamics it is considered as an isolated whole for analysis of energy and entropy changes.
- State Function
- A property that depends only on the current state of the system, not on how the state was reached (e.g., U, H, S, P, V, T).
- Path Function
- A property whose value depends on the process path taken between two states; heat (q) and work (w) are path functions.
- Thermodynamic Equilibrium
- A state in which a system has uniform macroscopic properties (no net flows) and no net change occurs over time; includes thermal, mechanical and chemical equilibrium.
- Internal Energy (U)
- Total microscopic energy of a system arising from kinetic and potential energies of molecules; a state function.
- Heat (q)
- Energy transferred between system and surroundings due to a temperature difference; positive when added to the system (chemistry sign convention may vary).
- Work (w)
- Energy transfer to or from a system by any means other than heat; for pressure–volume work in chemistry w = -PΔV (work done by system is negative).
- Enthalpy (H)
- A state function defined as H = U + PV; under constant pressure, the heat exchanged equals the change in enthalpy (ΔH ≈ q_p).
- First Law of Thermodynamics
- Law of energy conservation for thermodynamic processes: ΔU = q + w (change in internal energy equals heat added plus work done on the system).
- Second Law of Thermodynamics
- In any spontaneous process the total entropy of the universe (system + surroundings) increases; it introduces the concept of irreversibility and directionality of processes.
- Entropy (S)
- A state function that measures the degree of disorder or number of accessible microstates; for a reversible process ΔS = q_rev/T.
- Gibbs Free Energy (G)
- A thermodynamic potential defined as G = H - TS; at constant temperature and pressure, ΔG indicates spontaneity (ΔG < 0 spontaneous, ΔG = 0 equilibrium).
- Reversible Process
- An idealized process that proceeds infinitely slowly through a continuous series of equilibrium states and can be reversed without net change to system + surroundings.
- Irreversible Process
- A real process that proceeds with finite gradients (e.g., temperature or pressure) and cannot be exactly reversed without net changes in the universe.
- Isothermal Process
- A process occurring at constant temperature (ΔT = 0); heat exchange with surroundings may occur to maintain temperature.
- Adiabatic Process
- A process in which no heat is exchanged between system and surroundings (q = 0); temperature may change due to work done.
- Hess's Law
- The total enthalpy change for a chemical reaction is the same regardless of the reaction path; enthalpies are additive and can be combined algebraically.
Practice Questions
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Distinguish between a state function and a path function, giving one example of each. / अवस्था फलन और पथ फलन में अंतर बताइए तथा प्रत्येक का एक उदाहरण दीजिए।
Show answer
A state function depends only on the initial and final states (e.g., internal energy U or enthalpy H), while a path function depends on the route taken between states (e.g., heat q or work w). / अवस्था फलन केवल प्रारंभिक और अंतिम अवस्थाओं पर निर्भर करता है (जैसे आंतरिक ऊर्जा U या एन्थैल्पी H), जबकि पथ फलन अवस्थाओं के बीच अपनाए गए मार्ग पर निर्भर करता है (जैसे ऊष्मा q या कार्य w)।
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State the first law of thermodynamics and write its mathematical expression with sign conventions. / ऊष्मागतिकी का प्रथम नियम लिखिए तथा चिह्न परिपाटी सहित इसका गणितीय व्यंजक दीजिए।
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Energy is conserved: ΔU = q + w, where q is heat added to the system (positive when absorbed) and w is work done on the system (positive when done on it). / ऊर्जा संरक्षित रहती है: ΔU = q + w, जहाँ q निकाय में दी गई ऊष्मा है (अवशोषित होने पर धनात्मक) और w निकाय पर किया गया कार्य है (निकाय पर किए जाने पर धनात्मक)।
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Why is qp equal to ΔH at constant pressure? / स्थिर दाब पर qp, ΔH के बराबर क्यों होता है?
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Since H = U + PV, at constant pressure dH = dU + PdV = q (because work is −PdV), so the heat exchanged equals the enthalpy change, qp = ΔH. / चूँकि H = U + PV, स्थिर दाब पर dH = dU + PdV = q (क्योंकि कार्य −PdV है), अतः विनिमयित ऊष्मा एन्थैल्पी परिवर्तन के बराबर होती है, qp = ΔH।
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Calculate the work done when a gas expands against a constant external pressure of 2 atm from 5 L to 10 L (sign as per ΔU = q + w convention). / जब एक गैस 2 atm के स्थिर बाह्य दाब के विरुद्ध 5 L से 10 L तक प्रसारित होती है तो किए गए कार्य की गणना कीजिए (ΔU = q + w परिपाटी अनुसार चिह्न)।
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w = −P_ext ΔV = −2 atm × (10 − 5) L = −10 L atm; the work is negative because the gas does work on the surroundings. / w = −P_ext ΔV = −2 atm × (10 − 5) L = −10 L atm; कार्य ऋणात्मक है क्योंकि गैस परिवेश पर कार्य करती है।
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State Hess's law and explain why it is valid. / हेस का नियम लिखिए और समझाइए कि यह क्यों मान्य है।
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Hess's law states that the total enthalpy change of a reaction is the same regardless of the number of steps or path taken; it is valid because enthalpy is a state function depending only on initial and final states. / हेस का नियम कहता है कि किसी अभिक्रिया का कुल एन्थैल्पी परिवर्तन चरणों की संख्या या अपनाए गए पथ से स्वतंत्र रहता है; यह मान्य है क्योंकि एन्थैल्पी एक अवस्था फलन है जो केवल प्रारंभिक और अंतिम अवस्थाओं पर निर्भर करता है।
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Given C(graphite) + O₂ → CO₂, ΔH° = −393.5 kJ and CO + ½O₂ → CO₂, ΔH° = −283.0 kJ, find ΔH° for C + ½O₂ → CO. / दिया है C(ग्रेफाइट) + O₂ → CO₂, ΔH° = −393.5 kJ तथा CO + ½O₂ → CO₂, ΔH° = −283.0 kJ, तो C + ½O₂ → CO के लिए ΔH° ज्ञात कीजिए।
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Subtracting the second from the first: ΔH° = −393.5 − (−283.0) = −110.5 kJ. / पहली से दूसरी घटाने पर: ΔH° = −393.5 − (−283.0) = −110.5 kJ।
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For an ideal gas undergoing isothermal expansion, what is the value of ΔU and why? / समतापीय प्रसार से गुजर रही आदर्श गैस के लिए ΔU का मान क्या है और क्यों?
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ΔU = 0, because the internal energy of an ideal gas depends only on temperature, and temperature is constant in an isothermal process. / ΔU = 0, क्योंकि आदर्श गैस की आंतरिक ऊर्जा केवल ताप पर निर्भर करती है, और समतापीय प्रक्रम में ताप स्थिर रहता है।
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Relate ΔH and ΔU for a reaction involving gases and define Δn_gas. / गैसों से युक्त अभिक्रिया के लिए ΔH और ΔU में संबंध बताइए तथा Δn_gas को परिभाषित कीजिए।
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ΔH = ΔU + Δn_gas·RT, where Δn_gas is the difference between moles of gaseous products and moles of gaseous reactants. / ΔH = ΔU + Δn_gas·RT, जहाँ Δn_gas गैसीय उत्पादों के मोल और गैसीय अभिकारकों के मोल का अंतर है।
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