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Chapter 1 — Electric Charges And Fields

Class 12 · Physics

Overview

Chapter 1 — Electric Charges And Fields Master Diagram

This chapter introduces electric charge and the electric field — foundational concepts in electrostatics. It begins with the nature of charge (quantization and conservation), methods of charging and properties of conductors and insulators, then develops Coulomb's law and the principle of superposition for point charges. The idea of electric field as a vector field produced by charges is introduced, along with field lines, electric dipole and field of continuous charge distributions (linear, surface, volume). Electric flux and Gauss's law are presented and applied to high-symmetry charge distributions (infinite line, plane, sphere), and key consequences such as the behaviour of conductors in electrostatic equilibrium and electrostatic shielding are discussed. The chapter is important because it provides the basic tools and reasoning (vector algebra, symmetry, Gauss's law) used throughout electricity and magnetism, and develops problem-solving skills needed for advanced topics. By the end students will be able to explain and compute forces between charges, construct and interpret field lines, calculate fields for common distributions, apply Gauss's law effectively, and understand…

Learning Objectives

  • Define electric charge, and state the laws of conservation and quantization of charge with examples
  • Explain methods of charging (by rubbing, conduction and induction) and identify conductors, insulators and charging behaviour
  • State Coulomb's law in vector form and apply it to calculate the electrostatic force between two point charges
  • Apply the principle of superposition to compute net force and net electric field due to a system of discrete charges
  • Use the expression for electric field to calculate field due to a point charge and set up integrals for continuous charge distributions (line, surface, volume)
  • Derive expressions for the electric field on the axis and on the perpendicular bisector of an electric dipole and calculate torque and potential energy of a dipole in a uniform field
  • Sketch and interpret electric field lines for single charges, dipoles and charge configurations and relate them to field direction and strength
  • Define electric flux and use Gauss's law to calculate electric fields for highly symmetric charge distributions (infinite line, infinite plane, spherical symmetry)

Topics in this chapter

15 topics · tap a topic title to jump straight to it.

1

Electric charge

Fig 1.1 — Educational Diagram: Electric Charge, Quantization (q = n e) & Conservation

Fig 1.1 — Educational Diagram: Electric Charge, Quantization (q = n e) & Conservation

⚡ KEY PRINCIPLE

Quantization & Conservation of Charge

Quantization: Any electric charge q is an integral multiple of elementary charge: q = n · e (where e = 1.6 × 10⁻¹⁹ C).

Conservation: Total electric charge of an isolated system remains constant during any physical process.

What is electric charge?
Electric charge is a fundamental property of matter that causes it to experience a force in the presence of other charges. There are two kinds of charge: positive and negative. Like charges repel and unlike charges attract.

Quantitative definition and unit
The SI unit of charge is the coulomb (C). Charge is carried by particles — for example, the electron has charge −e and the proton has charge +e, where e = 1.602 × 10⁻¹⁹ C (the elementary charge).

Quantization of charge
Electric charge is quantized: any measurable charge q is an integer multiple of the elementary charge, q = n·e, where n is an integer (positive, negative or zero). This is an experimental fact relevant at atomic and macroscopic scales.

Conservation and additivity
Total electric charge is conserved in isolated systems — it cannot be created or destroyed (only transferred). Charge is additive: the net charge of a system is the algebraic sum of individual charges.

How objects become charged
Common methods of charging include:

  • By friction — rubbing two different materials transfers electrons from one to the other (triboelectric effect).
  • By conduction (contact) — touching a charged object to a conductor allows charge to flow and redistribute.
  • By induction — bringing a charged object near a conductor redistributes charges within the conductor; grounding can remove or supply charge.

Conductors and insulators
In conductors, charges (electrons) are mobile and can move freely; in electrostatic equilibrium, excess charge resides on the surface. In insulators (dielectrics), charges are localized and do not move freely.

📌 Examples
  • Rubbing a balloon on dry hair: electrons transfer to the balloon, making it negatively charged; the balloon sticks to a neutral wall due to induced charges.
  • Combing dry hair: the comb becomes charged by friction and can attract small bits of paper.
  • Lightning: charge separation in clouds (large-scale triboelectric and induction processes) leads to huge potential differences and rapid discharge between cloud and ground.
  • Van de Graaff generator: mechanically transports charge to a large hollow conductor producing high voltages used for demos and particle accelerators.
  • Electrostatic precipitator: charged particles in exhaust are attracted to oppositely charged plates to remove dust from industrial emissions.
🧮 Formulas
  1. \[q = n·e (quantization of charge)\]
    \[where e = 1.602176634×10^-19 C\]
  2. \[Coulomb's law (scalar): F = k·|q1·q2|/r^2\]
    \[where k = 1/(4·π·ε0) ≈ 8.988×10^9 N·m^2/C^2, ε0 = 8.854187817×10^-12 F/m\]
  3. \[Coulomb's law (vector): F⃗_12 = (1/(4·π·ε0))·(q1·q2/r^2)·r̂_12 (direction along line joining charges)\]
  4. \[Electric field: E⃗ = F⃗/q (field due to a point charge: E = (1/(4·π·ε0))·q/r^2 · r̂)\]
  5. \[Superposition principle: net force or field is vector sum of contributions from individual charges: F⃗_net = Σ F⃗_i\]
    \[E⃗_net = Σ E⃗_i\]
🔬2

Charging methods

Fig 1.2 — Educational Diagram: Methods of Charging (Friction, Conduction, Induction)

Fig 1.2 — Educational Diagram: Methods of Charging (Friction, Conduction, Induction)

⚡ KEY CONCEPT

Charging methods

Core Principle: Coulomb's law: F = k * (q1 * q2) / r^2, where k = 1 / (4πε0).

Overview: Charging methods are the ways in which neutral bodies acquire net electric charge. In Class 12 Physics the three standard methods are charging by friction (triboelectric charging), charging by conduction (contact), and charging by induction. Each method relies on transfer or redistribution of electrons and obeys charge conservation.

1. Charging by friction (triboelectric charging)

  • Mechanism: When two different materials are rubbed together, electrons may be transferred from one surface to the other depending on their tendency to gain or lose electrons (triboelectric series). One body becomes negatively charged (gains electrons) and the other positively charged (loses electrons).
  • Key features: Works mainly for insulators and dielectric surfaces; resulting charges tend to remain localized because charges cannot move freely.
  • Practical note: Amount of charge depends on material pair, contact area, pressure, rubbing speed, humidity (moist air reduces charging).

2. Charging by conduction (contact)

  • Mechanism: When a charged conductor touches another conductor, electrons flow until both reach the same electric potential. Total charge is conserved and redistributes between the conductors.
  • Identifying condition: After contact, conductors in electrical contact have equal potential (V1 = V2). For isolated spherical conductors, final charges divide in proportion to their capacitances.
  • Special case (identical conductors): If a charged conductor touches an identical uncharged conductor, the initial charge divides equally.

3. Charging by induction

  • Mechanism: A charged object brought near a neutral conductor causes redistribution (separation) of charges within the conductor without direct contact. If the conductor is then grounded while the charged object remains nearby, some charge flows to or from Earth; removing the ground and then the external charged object leaves the conductor with net charge of opposite sign to the nearby object.
  • Key features: No direct contact needed with the charging object; useful to produce charge of sign opposite to the inducing charge (by grounding during induction).

Other important points:

  • Conservation of charge always holds: the algebraic sum of charges before and after any process remains the same (unless charge is exchanged with the environment/earth).
  • In conductors, excess charge resides on the outer surface; electric field inside a conductor in electrostatic equilibrium is zero.
  • Insulators can be polarized: local bound charges appear but free charge mobility is low, so charges remain localized.

Summary of process steps (conduction vs induction):

  • Conduction/contact: Touch charged object to neutral conductor → charges flow until potentials equalize → separate; both are charged (same sign as original if no ground connection).
  • Induction (with grounding): Bring charged object near neutral conductor → connect conductor to ground so charges of appropriate sign flow to/from earth → disconnect ground → remove inducing object → conductor retains induced net charge (opposite sign to inducing charge).
📌 Examples
  • Rubbing a glass rod with silk: glass becomes positive, silk negative (charging by friction).
  • Touching a charged metal sphere to another uncharged metal sphere: charges redistribute (charging by conduction/contact).
  • Bringing a negatively charged rod near an earthed metal can, then grounding and removing the rod leaves the can positively charged (charging by induction).
  • Electrostatic precipitator: particles are charged (by corona/induction) and then collected on plates (industrial application of electrostatic charging).
  • Walking on a carpet and then getting a shock from a doorknob (triboelectric charging, discharge by conduction).
  • Van de Graaff generator: belt transfers charge to a hollow conductor (combination of triboelectric and conduction principles) used in demonstrations of high-voltage electrostatics.
🧮 Formulas
  1. \[Coulomb's law: F = k * (q1 * q2) / r^2\]
    \[where k = 1 / (4πε0).\]
  2. \[Conservation of charge: Q_total(initial) = Q_total(final).\]
  3. \[Surface charge density (for a surface area A): σ = Q / A.\]
  4. \[Potential–charge relation for a conductor (linear): V = Q / C\]
    \[where C is the conductor's capacitance (e.g.\]
    \[isolated sphere C = 4πε0 R).\]
  5. \[Charge division for conductors connected by a wire (equal potential): Q1/C1 = Q2/C2 (so Q1 = C1/(C1 + C2) * Q_total and Q2 = C2/(C1 + C2) * Q_total).\]
  6. \[Special case for identical spheres (same C): Q_final_on_each = Q_initial / 2 (when one charged\]
    \[one uncharged\]
    \[and they touch).\]
🔬3

Coulomb's law

Fig 1.3 — Educational Diagram: Coulomb

Fig 1.3 — Educational Diagram: Coulomb's Law of Electrostatic Force & Vector Formula

⚡ COULOMB'S LAW

Electrostatic Force Equation

Vector Formula: F₁₂ = (1 / 4πε₀) · (q₁ q₂ / r²) r̂₁₂

Key Constant: Electrostatic constant k = 1 / (4πε₀) ≈ 8.988 × 10⁹ N·m²/C², Permittivity of free space ε₀ = 8.854 × 10⁻¹² F/m.

Inverse-square decay of electrostatic force with distance r.

Statement: Coulomb's law gives the electrostatic force between two point charges. It states that the magnitude of the force between two point charges q1 and q2 separated by distance r in vacuum is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the separation.

Scalar form: F = k |q1 q2| / r^2, where k = 1 / (4 π ε0) ≈ 8.988 × 10^9 N m^2 C^{-2} and ε0 = 8.854 × 10^{-12} F m^{-1}.

Vector form: the force on charge q2 due to q1 is
F_21 = (1 / (4 π ε0)) * (q1 q2 / r^2) r̂, where r̂ is the unit vector pointing from q1 to q2. The sign of q1 q2 determines direction: like charges repel, unlike charges attract.

Superposition principle: For more than two charges, the net force on any charge is the vector sum of forces due to each other charge separately: F_net = Σ F_i (vector addition).

Effect of medium: In a dielectric medium of relative permittivity εr, replace ε0 by ε = εr ε0, or k becomes k = 1/(4 π ε). The force weakens by factor 1/εr.

  • Valid for: point charges or spherically symmetric charge distributions (treatable as point charges outside the sphere).
  • Limitations: does not include magnetic or relativistic effects; at very short distances quantum effects matter.
  • Units: force in newtons (N), charge in coulombs (C), distance in meters (m).

Physical significance: Coulomb's law is the electrostatic analogue of Newton's law of gravitation but with both attractive and repulsive interactions and much stronger coupling per unit source. It underpins the electric field concept: the electric field of a point charge q is E = k q / r^2 r̂.

📌 Examples
  • Example 1 (numeric): Two charges q1 = +5.0 µC and q2 = -3.0 µC are 10 cm apart in air. F = k |q1 q2| / r^2 = (8.988e9)*(5e-6*3e-6)/(0.10^2) ≈ 13.5 N. The force is attractive (opposite signs).
  • Example 2 (atomic scale): Force between electron and proton in hydrogen (r = Bohr radius 5.29e-11 m): F = k e^2 / r^2 ≈ 8.2e-8 N (attractive). This electrostatic force provides the centripetal force in the Bohr model.
  • Example 3 (superposition): Three identical positive charges placed at the vertices of an equilateral triangle—net force on any one charge is the vector sum of the two repulsive forces from the other charges; by symmetry, the net force points radially outward from the triangle center and can be computed using vector addition.
🧮 Formulas
  1. \[Scalar Coulomb's law: F = k |q1 q2| / r^2\]
    \[where k = 1/(4πϵ0) ≈ 8.988×10^9 N·m^2·C^{-2}\]
  2. \[Vector form: F_21 = (1/(4πϵ0)) * (q1 q2 / r^2) * r̂ (r̂ from q1 to q2)\]
  3. \[Electric field of a point charge: E = k q / r^2 r̂\]
  4. \[Potential energy of two point charges: U = k q1 q2 / r (reference U -> 0 as r -> ∞)\]
  5. \[In a medium with relative permittivity ϵ_r: k_medium = 1/(4πϵ0 ϵ_r)\]
  6. \[Superposition: F_net = Σ_i F_i (vector sum of forces from each charge)\]
🔬4

Principle of superposition

Fig 1.4 — Educational Diagram: Principle of Superposition for Multiple Charges

Fig 1.4 — Educational Diagram: Principle of Superposition for Multiple Charges

📜 THEOREM / LAW

Principle of superposition

Core Principle: Coulomb's law (magnitude): F = k |q1 q2| / r^2, where k = 1/(4πε0).

Definition: The principle of superposition states that the total electric force (or electric field or potential) at any point due to a system of charges equals the vector sum (or algebraic sum for scalar potential) of the contributions from each charge taken separately, as if the others were absent.

Why it holds (brief): Coulomb's law for point charges is linear and pairwise additive: the force between any two point charges depends only on those two charges. Because the laws are linear, effects from different sources add without producing new types of terms (no products of fields), so the net effect is a sum of individual effects.

Mathematical statement (point charges): For N point charges q_i located at positions r_i, the electric field at point r is

  • E(r) = Σ_{i=1}^N E_i(r) = Σ_{i=1}^N k q_i (r − r_i)/|r − r_i|^3, where k = 1/(4πε_0).
  • The force on a test charge q at r is F(r) = q E(r) = Σ_{i=1}^N F_i(r) = Σ_{i=1}^N k q q_i (r − r_i)/|r − r_i|^3.

Continuous charge distributions: Replace the sum by an integral: E(r) = k ∫ (ρ(r') (r − r')/|r − r'|^3) dV', and potential V(r) = k ∫ (ρ(r')/|r − r'|) dV'.

Potential superposition: Electric potential is a scalar and also obeys superposition: V_total(r) = Σ_i V_i(r) = k Σ_i q_i/|r − r_i|. Because V is scalar, superposition is an algebraic sum (signs included).

Conditions and limits:

  • Valid in classical electrostatics and in linear media where field responses add linearly.
  • Breaks down in nonlinear media (materials with nonlinear dielectric response) or in quantum regimes where interactions are not described by classical Coulomb addition.

How to apply (procedure):

  1. Compute the field (or force, or potential) produced by each individual charge at the point of interest.
  2. Express each contribution as a vector (for field/force) with correct direction and sign.
  3. Add all vector contributions component-wise to get the net field or force; add scalars for potential.

📌 Examples
  • Two point charges on x-axis: q1 at x=0 and q2 at x=d. Electric field at a point x is E(x)=E1(x)+E2(x) where E1 and E2 are calculated by Coulomb's law with proper directions. This can produce points where E=0 between charges (if charges have opposite signs or unequal magnitudes).
  • Electric dipole: field at points on the axis is the vector sum of fields due to the positive and negative charges. Superposition explains the characteristic dipole field pattern and the 1/r^3 far-field dependence when viewed as two close opposite charges.
  • Charging by induction or small bits of paper attracted to a charged comb: the net force on each paper piece results from the distribution of induced charges; the comb’s field plus the induced field add to produce the observed attraction.
  • Continuous distributions: electric field of a uniformly charged rod at a point on its axis is obtained by integrating contributions dE from each small element dq and summing (superposing) them to get E = ∫ dE.
  • Electrostatic deflection in a CRT: the electron feels the net electric field which is the superposition of fields produced by the two deflection plates (one positive, one negative).
🧮 Formulas
  1. \[Coulomb's law (magnitude): F = k |q1 q2| / r^2\]
    \[where k = 1/(4πε0).\]
  2. \[Vector force between two charges: F12 = k q1 q2 (r1 − r2) / |r1 − r2|^3.\]
  3. \[Superposition of forces: F_total = Σ_i F_i (vector sum over all pairwise forces from each source charge on the test charge).\]
  4. \[Electric field from point charges (superposition): E(r) = Σ_i E_i(r) = k Σ_i q_i (r − r_i)/|r − r_i|^3.\]
  5. \[Electric potential (scalar superposition): V(r) = Σ_i V_i(r) = k Σ_i q_i/|r − r_i|.\]
  6. \[Continuous distribution (integral form): E(r) = k ∫ (ρ(r') (r − r')/|r − r'|^3) dV'\]
    \[V(r) = k ∫ (ρ(r')/|r − r'|) dV'.\]
🔬5

Charge distributions and densities

Fig 1.5 — Educational Diagram: Continuous Charge Distributions (Linear λ, Surface σ, Volume ρ)

Fig 1.5 — Educational Diagram: Continuous Charge Distributions (Linear λ, Surface σ, Volume ρ)

⚡ KEY CONCEPT

Charge distributions and densities

Core Principle: Linear density: λ = dQ/dl ; dq = λ dl ; Q = ∫_line λ(l) dl ; units: C m^-1

What is a charge distribution?
When many charges are spread over a region (along a line, over a surface or throughout a volume) we describe the arrangement as a charge distribution. If charges are few and separated we treat them as discrete point charges; if they are closely packed we treat the distribution as continuous and use charge densities.

Types of distributions and their densities

  • Linear charge density (λ): for charge spread along a line (wire, rod). Definition: λ = dQ/dl. Element: dQ = λ dl. Unit: C m-1.
  • Surface charge density (σ): for charge on a surface (sheet, conductor surface). Definition: σ = dQ/dA. Element: dQ = σ dA. Unit: C m-2.
  • Volume charge density (ρ): for charge distributed in a volume (charged insulating solid, space charge). Definition: ρ = dQ/dV. Element: dQ = ρ dV. Unit: C m-3.

Integral relations
To get total charge from a density integrate over the appropriate domain:
Q = ∫_line λ(l) dl, Q = ∫_surface σ( r ) dA, Q = ∫_volume ρ( r ) dV.

Uniform distributions (constant densities)
If the density is uniform, simple relations hold: λ = Q/L, σ = Q/A, ρ = Q/V.

Special notes

  • In electrostatic equilibrium in a conductor all excess charge resides on the surface — described by a surface density σ.
  • Point charges are represented in continuous language using the Dirac delta: ρ( r ) = q δ( r − r0 ).
  • For thin objects you can relate densities approximately: for a thin sheet of thickness t, ρ ≈ σ/t; for a thin wire of radius a, σ ≈ λ/(2πa) (if charge resides on the surface).

Use with Coulomb's law and Gauss's law
Charge densities let you compute fields by integrating Coulomb's law or by using Gauss's law with symmetry. Example results used often in Class 12: field of an infinite line E = λ/(2πε0 r), infinite sheet E = σ/(2ε0) (one-sided conductor: E = σ/ε0), on-axis field of a ring and field inside/outside uniformly charged sphere (see formulas list).

Practical measurement/visualisation
Graphical plots of ρ(x), σ(θ) or λ(x) help visualize where charge is concentrated. Sketching field magnitude versus distance for standard distributions clarifies how geometry affects fields.

📌 Examples
  • A uniformly charged thin rod of length L: use linear density λ = Q/L. Field at a point on axis found by integrating dE from each element dQ = λ dl.
  • Charged metal sphere in electrostatic equilibrium: all excess charge resides on the surface → described by surface density σ(θ). Outside it behaves like a point charge Q at centre.
  • Two parallel charged plates (capacitor): each plate approximated as infinite sheet with surface density σ, producing a uniform field E = σ/2ε0 from each plate (net between plates E = σ/ε0).
  • A charged ring used in experiments: total charge Q distributed uniformly on ring; on-axis field is often used to introduce integration with λ.
  • Photocopier / laser printer: toner (charged powder) distributions on a drum or paper are examples of surface charge distributions controlling deposition.
  • Lightning and clouds: charge separated in volumes and surfaces in the atmosphere — modeled as volume (ρ) and surface (σ) distributions for field calculations.
🧮 Formulas
  1. \[Linear density: λ = dQ/dl\]
    \[dq = λ dl\]
    \[Q = ∫_line λ(l) dl\]
    \[units: C m^-1\]
  2. \[Surface density: σ = dQ/dA\]
    \[dq = σ dA\]
    \[Q = ∫_surface σ( r ) dA\]
    \[units: C m^-2\]
  3. \[Volume density: ρ = dQ/dV\]
    \[dq = ρ dV\]
    \[Q = ∫_volume ρ( r ) dV\]
    \[units: C m^-3\]
  4. \[Uniform densities: λ = Q/L , σ = Q/A , ρ = Q/V\]
  5. \[Point-charge in density form: ρ( r ) = q δ( r − r0 )\]
  6. \[Infinite line (electric field): E = λ / (2πε0 r) (radial)\]
6

Electric field (E)

Fig 1.6 — Educational Diagram: Electric Field (E = F/q0) & Radial Field of Point Charge

Fig 1.6 — Educational Diagram: Electric Field (E = F/q0) & Radial Field of Point Charge

⚡ KEY CONCEPT

Electric field (E)

Core Principle: Definition: E = F / q0

Definition: An electric field at a point in space is a vector quantity that represents the electric force per unit positive test charge placed at that point. If a small positive test charge q0 experiences an electric force F, the electric field E is E = F/q0. The field exists even if no test charge is present.

Nature and direction: E is a vector. The direction of E at a point is the direction of the force on a positive test charge. Field lines show direction: they originate on positive charges and terminate on negative charges; the density of lines indicates field strength.

Point charge (Coulomb's law): For a point charge q located at the origin, the electric field at position r (distance r from the charge) is radial and given by E = (1/4πε0) (q / r^2) r̂. Here ε0 is the permittivity of free space and r̂ is the unit vector from the charge to the point.

Superposition principle: The net electric field due to several charges is the vector sum of fields due to individual charges: E_total = Σ E_i. This also applies to continuous charge distributions (integral form).

Fields of common charge distributions (qualitative):

  • Infinite line of charge (linear density λ): E ∝ 1/r, directed radially outward/inward.
  • Infinite uniformly charged plane (surface density σ): E is uniform and equals σ/(2ε0) on each side of a single infinite plane; between two oppositely charged parallel plates E = σ/ε0 (approximately uniform).
  • Uniformly charged thin spherical shell: outside it behaves like a point charge (E ∝ 1/r^2); inside the shell E = 0.
  • Electric dipole (moment p = q·2a): far-field on axis E ∝ 1/r^3; on perpendicular bisector E has opposite sign and magnitude ∝ 1/r^3.

Relation with electric potential: Electric field is the negative gradient of electric potential: E = -∇V. In one dimension, E_x = -dV/dx. This links field lines to equipotential surfaces (E is perpendicular to equipotentials).

Gauss's law (useful for symmetry): The electric flux through a closed surface equals the enclosed charge divided by ε0: ∮ E · dA = Q_enclosed / ε0. This is often used to compute E for symmetric charge distributions (sphere, infinite line, infinite plane).

Energy density: The energy stored per unit volume in an electric field is u = (1/2) ε0 E^2.

Units: Electric field is measured in newtons per coulomb (N/C) or volts per metre (V/m). Both are equivalent.

Important practical points: Field inside a conductor in electrostatic equilibrium is zero; any excess charge resides on the surface. Field direction and magnitude determine forces on charges, motion of charged particles in devices, and electrostatic interactions in everyday technology.

📌 Examples
  • Lightning: strong electric fields build between clouds and ground; when breakdown strength of air is exceeded, a discharge (lightning) occurs.
  • Parallel-plate capacitor: nearly uniform electric field between the plates stores electrical energy and is used in sensors and timing circuits.
  • Cathode-ray tubes / electron beam devices: electric fields accelerate and steer charged particles (electrons) to form images.
  • Electrostatic precipitator: electric fields charge dust particles and collect them on plates for air pollution control.
  • Inkjet printers: electric fields direct tiny charged ink droplets onto paper for precise printing.
🧮 Formulas
  1. \[Definition: E = F / q0\]
  2. \[Point charge: E(r) = (1 / (4πε0)) * (q / r^2) * r̂\]
  3. \[Force on charge: F = q E\]
  4. \[Superposition: E_total(r) = Σ E_i(r) (or integral for continuous distribution)\]
  5. \[Infinite line (linear density λ): E = λ / (2πε0 r) (radial)\]
  6. \[Infinite plane (surface density σ): E = σ / (2ε0) on each side of a single infinite plane\]
    \[between two opposite plates E = σ / ε0\]
7

Electric field lines and equipotential surfaces

Fig 1.7 — Educational Diagram: Electric Field Lines & Equipotential Surfaces

Fig 1.7 — Educational Diagram: Electric Field Lines & Equipotential Surfaces

⚡ KEY CONCEPT

Electric field lines and equipotential surfaces

Core Principle: Electric field from a point charge: E = k q / r^2 (radial), magnitude where k = 1 / (4πε0).

Overview
Electric field lines and equipotential surfaces are graphical tools used to visualize the electric field (E) and electric potential (V) produced by charges. Field lines show the direction and relative strength of the electric field, while equipotential surfaces connect points having the same electric potential.

Electric field lines (field lines)

  • Definition: A field line is an imaginary curve whose tangent at any point gives the direction of the electric field at that point.
  • Conventions: Field lines originate on positive charges and terminate on negative charges (or at infinity). The line direction indicates the force on a positive test charge.
  • Density and strength: The local density of field lines (number per unit area perpendicular to lines) represents the magnitude of E. Closer lines mean stronger field.
  • Properties: Field lines never cross. They are continuous and may start/stop only at charges. For a uniform field (e.g., between parallel plates) lines are parallel, equally spaced, and straight.

Equipotential surfaces

  • Definition: An equipotential surface is a surface on which the electric potential V has the same value at every point.
  • Work and motion: No work is done by the electric force when a charge moves along an equipotential (ΔV = 0 → W = qΔV = 0).
  • Shapes: For a single point charge, equipotentials are concentric spheres (in 3D) or circles (in plane cross-section). For a uniform field they are planes perpendicular to the field lines.
  • Properties: Equipotential surfaces are always perpendicular to electric field lines at their intersections.

Mathematical relation between E and V

  • Gradient relation: E = -grad V (vector form). The electric field points in the direction of greatest decrease of potential.
  • Line integral form: V(b) − V(a) = −∫_a^b E · dl. For uniform E along direction normal to equipotentials: ΔV = −E Δs. Often magnitude: E = −dV/dn, where dn is distance along the normal.

Important consequences

  • Because equipotentials are perpendicular to field lines, equipotential surfaces help sketch field patterns by drawing normals to them.
  • Inside a conductor in electrostatic equilibrium, E = 0 and the entire conductor is an equipotential. This is the basis for electrostatic shielding (Faraday cage).
  • Work required to move charge q between two equipotentials of potentials V1 and V2 is W = q(V1 − V2).

Typical diagrams students should be able to draw and interpret

  • Field lines and concentric equipotential circles for a single positive and for a single negative point charge.
  • Dipole field lines with corresponding nested equipotential contours (lobe-shaped surfaces around charges).
  • Two like charges and two unlike charges: symmetry of lines and equipotential geometry (saddle and null points).
  • Uniform field between parallel plates: straight field lines and equally spaced planar equipotentials.

Pedagogical tips
When sketching, mark arrowheads on field lines (direction of force on +q), draw equipotentials as smooth curves/surfaces, and check perpendicularity at intersections. Use denser lines where E is stronger.

📌 Examples
  • Point charge: Field lines radially outward from a positive point charge; equipotential surfaces are concentric spheres (or circles in 2D cross-section).
  • Electric dipole: Field lines emerge from the positive charge and terminate on the negative; equipotential surfaces form complex closed contours that are symmetric about the dipole axis.
  • Parallel-plate capacitor: Nearly uniform field between plates (straight, parallel field lines); equipotentials are planes parallel to the plates. Useful in experiments and capacitors.
  • Electrostatic shielding (Faraday cage): A hollow conductor in electrostatic equilibrium has E = 0 inside, so the interior is an equipotential—protects sensitive electronics.
  • Lightning rod and earthing: Sharp rod produces strong local field (dense field lines) to encourage charge discharge; earthing provides a path to take charge to the ground equipotential.
  • Cathode-ray tube and electron optics: Shaped equipotentials are used to control electron beams by creating desired field patterns.
🧮 Formulas
  1. \[Electric field from a point charge: E = k q / r^2 (radial)\]
    \[magnitude where k = 1 / (4πε0).\]
  2. \[Electric potential of a point charge: V = k q / r (taking V→0 at r→∞).\]
  3. \[Potential difference: V(b) − V(a) = −∫_a^b E · dl.\]
  4. \[Relation between field and potential (vector): E = −∇V.\]
  5. \[For uniform field between plates (approx): E = V / d and ΔV = −E d (magnitude form: E = |ΔV|/d).\]
  6. \[Work done to move charge q between potentials V1 and V2: W = q (V1 − V2) = ΔU (electric potential energy).\]
8

Electric dipole

Fig 1.8 — Educational Diagram: Electric Dipole Moment (p = q·2a) & Axial vs Equatorial Field

Fig 1.8 — Educational Diagram: Electric Dipole Moment (p = q·2a) & Axial vs Equatorial Field

⚡ DIPOLE FORMULAS

Dipole Moment, Torque & Fields

Dipole Moment Vector: p⃗ = q · 2a⃗ (Directed from negative charge -q to positive charge +q).

Torque in Uniform Field: τ⃗ = p⃗ × E⃗ ⇒ τ = pE sin θ (Maximum torque at θ = 90°).

Axial vs Equatorial Field: E_axial = (2 k p) / r³ vs E_eq = (k p) / r³ (Axial field is 2 times Equatorial field!).

Forces +qE and -qE form a couple producing net torque τ = pE sin θ.

Definition: An electric dipole consists of two equal and opposite point charges +q and −q separated by a small distance 2a. The line joining them is the dipole axis. For most dipole formulas we assume the observation distance r >> a.

Dipole moment: The dipole moment is a vector defined as p = q·2a (magnitude) and its direction is from the negative charge to the positive charge. Its SI unit is C·m.

Electric potential (far-field approximation): At a point given by spherical coordinates (r, θ) measured from the dipole centre (θ is the angle between r and p), the scalar potential for r >> a is

V(r,θ) = (1/4πε₀)·(p cosθ) / r²

Electric field (far-field): From V, the field components in spherical coordinates (r̂, θ̂) are

E_r = (1/4πε₀)·(2p cosθ) / r³
E_θ = (1/4πε₀)·(p sinθ) / r³

Or in vector form:

E(r) = (1/4πε₀)·[3(p·r̂) r̂ − p] / r³

Special lines: Axial line (θ = 0): E_axial = (1/4πε₀)·(2p) / r³ (directed along the axis).
Equatorial plane (θ = 90°): E_equatorial = (1/4πε₀)·(−p) / r³ (directed opposite to p).

Torque and potential energy in a uniform external field E: A dipole in a uniform field experiences a torque

τ = p × E (magnitude τ = pE sinθ)

and potential energy

U = −p·E = −pE cosθ

Distance dependence & validity: The dipole field and potential fall off rapidly with distance: E ∝ 1/r³ and V ∝ 1/r² for r >> a. Exact expressions (without approximation) can be obtained by summing contributions from the two charges, but the above are the standard dipole approximations used in Class 12 when 2a is very small compared to r.

Physical picture & field lines: Field lines originate on +q and terminate on −q; close to the dipole they curve from +q to −q forming the characteristic pattern. At large distances the dipole looks like a single entity with net zero charge but a nonzero dipole moment.

📌 Examples
  • Polar molecules (e.g., water H₂O): the molecule has a permanent electric dipole moment which determines interactions, orientation in electric fields and many physical properties.
  • Dielectric materials in external electric fields: atoms/molecules develop induced dipoles that align with the field and produce polarization.
  • Dipole antennas: short electric-dipole-like antenna elements radiate electromagnetic waves; near-field behaviour shows dipole-like 1/r³ dependence.
  • Electrostatic separators and sensors: small charged particle pairs or probes behave like dipoles for force/torque measurements.
🧮 Formulas
  1. \[Dipole moment: p = q·2a (direction: from −q to +q)\]
  2. \[Potential (far-field): V(r,θ) = (1/4πε₀)·(p cosθ) / r²\]
  3. \[Electric field (spherical components\]
    \[far-field): E_r = (1/4πε₀)·(2p cosθ) / r³\]
    \[E_θ = (1/4πε₀)·(p sinθ) / r³\]
  4. \[Electric field (vector): E(r) = (1/4πε₀)·[3(p·r̂) r̂ − p] / r³\]
  5. \[Axial line (θ=0): E_axial = (1/4πε₀)·(2p) / r³\]
  6. \[Equatorial plane (θ=90°): E_equatorial = (1/4πε₀)·(−p) / r³\]
9

Electric flux

Fig 1.9 — Educational Diagram: Electric Flux (Φ = E · A cos θ) & Area Vector

Fig 1.9 — Educational Diagram: Electric Flux (Φ = E · A cos θ) & Area Vector

⚡ KEY CONCEPT

Electric flux

Core Principle: Φ = E A cosθ (uniform E, flat surface)

Definition: Electric flux (Φ) through a surface is a measure of the number of electric field lines crossing that surface. It quantifies how much of the electric field penetrates the surface.

SI unit: newton·meter2/coulomb (N·m2/C) or volt·meter (V·m).

Flux for a uniform field and flat surface: If a uniform electric field E passes through a flat surface of area A, and the angle between the field vector and the outward normal to the surface is θ, the electric flux is

Φ = E A cosθ

This formula implies maximum flux when the field is normal (θ = 0) and zero flux when the field is parallel to the surface (θ = 90°).

General definition (for non-uniform fields or curved surfaces): For any surface S, divide it into infinitesimal area elements dA with local outward normal. The net flux is the surface integral

Φ = ∮S E · dA = ∮S E cosθ dA

Closed surfaces and Gauss's law: For a closed surface (a surface that fully encloses a volume) the net electric flux equals the net charge enclosed (qenc) divided by the permittivity of free space (ε0):

Φclosed = ∮closed E · dA = qenc / ε0

This is Gauss's law. It is especially useful for highly symmetric charge distributions (spherical, cylindrical, planar) to find electric fields.

Properties and useful points:

  • Flux can be positive, negative or zero depending on field direction relative to the outward normal.
  • For a point charge q at the center of a spherical surface, flux through the sphere is q/ε0, independent of the sphere's radius.
  • If no charge is enclosed by a closed surface, net flux through it is zero (field lines entering equal those leaving).
  • Local form of Gauss's law: ∇·E = ρ/ε0, where ρ is charge density.

How to apply: For problems, identify whether surface is open or closed, check symmetry (can simplify E), choose suitable Gaussian surface if using Gauss's law, or evaluate the surface integral directly for non-uniform cases.

📌 Examples
  • Uniform field through a tilted square: A square of area 0.02 m² is in a uniform field E = 500 N/C at angle 30° to the normal. Flux = E A cosθ = 500 × 0.02 × cos30° ≈ 8.66 N·m²/C.
  • Point charge inside a sphere: A point charge q = 5 μC at the centre of a spherical surface. Net flux through sphere = q/ε₀ ≈ 5×10⁻⁶ / (8.854×10⁻¹²) ≈ 5.65×10⁵ N·m²/C, independent of sphere radius.
  • Charge at center of cube: A point charge q at the centre of a cube. By symmetry, flux through each of the 6 faces = q/(6ε₀).
  • Open surface parallel to a uniform field: If a circular disk is parallel to the uniform field (θ = 90°), flux = 0 because field lines are tangent and do not cross the disk.
🧮 Formulas
  1. \[Φ = E A cosθ (uniform E\]
    \[flat surface)\]
  2. \[Φ = ∮_S E · dA = ∮_S E cosθ dA (general surface integral)\]
  3. \[Φ_closed = ∮_closed E · dA = q_enclosed / ε₀ (Gauss's law)\]
  4. \[For point charge: E = (1 / 4πε₀) · q / r²\]
    \[flux through any sphere around the charge = q / ε₀\]
  5. \[Differential form: ∇·E = ρ / ε₀\]
  6. \[Units: [Φ] = N·m²/C\]
🔬10

Gauss's law

Fig 1.10 — Educational Diagram: Gauss

Fig 1.10 — Educational Diagram: Gauss's Law of Electrostatics (Φ = ∮ E·dA = Q/ε0)

📜 GAUSS'S THEOREM

Total Electric Flux Formula

Statement: Total electric flux through any closed surface equals 1 / ε₀ times total charge enclosed by that surface.

Equation: Φ = ∮ E⃗ · dA⃗ = Q_enclosed / ε₀

4-step decision flowchart to derive field E for line, sheet, and sphere.

Definition: Gauss's law relates the electric flux through a closed surface to the total charge enclosed by that surface. In integral form: Φ = ∮ E · dA = Q_enc / ε0, where Φ is electric flux, E is electric field, dA is an outward area element, Q_enc is total enclosed charge and ε0 is the permittivity of free space.

Electric flux: Electric flux through a surface measures how many field lines pass through that surface. For a uniform field and flat area, flux Φ = E A cosθ, where θ is the angle between E and the outward normal.

Gaussian surface: A mathematical closed surface chosen to exploit symmetry (sphere, cylinder, plane slab) so that the dot product E·dA is easy to evaluate. Gauss's law is always true, but it is most useful when the field has high symmetry so E is constant over parts of the surface or perpendicular/parallel to them.

Using Gauss's law (steps):

  • Choose a Gaussian surface that matches the symmetry of the charge distribution (spherical for point/spherical charges, cylindrical for infinite line, pillbox for infinite plane).
  • Write Φ = ∮ E·dA and simplify using symmetry so E can be taken outside the integral on appropriate surface portions.
  • Compute Q_enc inside the surface (include volume or surface charge as needed).
  • Set Φ = Q_enc/ε0 and solve for E.

Common results obtained from Gauss's law:

  • Point charge (or uniformly charged sphere, outside): E = Q / (4πε0 r²) (radial, inverse-square).
  • Infinite line charge (linear density λ): E = λ / (2πε0 r) (radial, falls as 1/r).
  • Infinite plane sheet (surface density σ): E = σ / (2ε0) (constant, independent of distance).
  • Conductor in electrostatic equilibrium: electric field inside is zero; any net charge resides on the surface; just outside surface E = σ / ε0 (normal to surface).

Differential form: Using the divergence theorem, Gauss's law becomes ∇·E = ρ/ε0, where ρ is volume charge density. This form is useful in field pointwise analysis and in Maxwell's equations.

Limitations and remarks: Gauss's law always holds, but it yields simple algebraic results only when symmetry allows E to be constant or zero on chosen surface parts. For arbitrary charge distributions, direct use gives an integral equation that may be hard to solve.

📌 Examples
  • Lightning rod: A sharp conductor concentrates charge at its tip; Gauss's law and conductor properties explain strong local fields that help ionize air and provide a preferred path for lightning.
  • Faraday cage: A closed conducting shell shields its interior from external static electric fields because induced charges on the conductor's surface cancel the external field inside (E = 0 inside conductor).
  • Parallel-plate capacitor (ideal, large plates): Using two infinite plane sheets of opposite surface charge ±σ, Gauss's law gives a uniform field E = σ/ε0 between plates and nearly zero outside.
  • Coaxial cable: Using cylindrical Gaussian surfaces around the inner conductor, Gauss's law gives E ∝ 1/r in the region between conductors; helps determine capacitance per unit length.
  • Charged spherical conductor (e.g., charged metal sphere): External field is identical to that of a point charge Q at center: E = Q/(4πε0 r²); inside the conductor E = 0.
🧮 Formulas
  1. \[Electric flux: Φ = ∮ E · dA\]
  2. \[Integral form (Gauss's law): ∮ E · dA = Q_enc / ε0\]
  3. \[Differential form: ∇·E = ρ / ε0\]
  4. \[Point charge / spherical (outside): E = Q / (4πε0 r²) (radial)\]
  5. \[Uniformly charged solid sphere: E_inside (r<R) = (1/(4πε0)) (Q r / R³)\]
    \[E_outside (r≥R) = Q / (4πε0 r²)\]
  6. \[Infinite line charge (linear density λ): E = λ / (2πε0 r)\]
🔬11

Applications of Gauss's law

Fig 1.11 — Educational Diagram: Applications of Gauss

Fig 1.11 — Educational Diagram: Applications of Gauss's Law (Line, Sheet & Spherical Shell)

📜 THEOREM / LAW

Applications of Gauss's law

Core Principle: Gauss's law: ∮ E · dA = Q_enclosed / ε₀

Gauss's law (statement): The net electric flux through any closed surface (Gaussian surface) equals the enclosed charge divided by the permittivity of free space: ∮E · dA = Q_enclosed/ε₀. Gauss's law is especially powerful for calculating electric fields when the charge distribution has high symmetry (spherical, cylindrical, planar).

General procedure to apply Gauss's law:

  • Identify symmetry (spherical, cylindrical, or planar).
  • Choose a Gaussian surface that matches the symmetry so that E has constant magnitude on parts of the surface and contributions simplify.
  • Compute flux by evaluating ∮E·dA (often reduces to E·A times symmetry factor).
  • Compute the enclosed charge Q_enclosed.
  • Use E = Q_enclosed/(ε₀·A) or the equivalent result from the flux equation to get E.

Key applications and results (with the typical Gaussian surface used):

  • Uniformly charged thin spherical shell (spherical symmetry):
    • Gaussian surface: concentric sphere of radius r.
    • Outside (r > R): field behaves like a point charge: E = (1/(4πε₀))·Q/r².
    • Inside (r < R): E = 0 (no enclosed charge).
  • Uniformly charged solid (non-conducting) sphere (spherical symmetry):
    • Outside (r > R): same as point charge: E = (1/(4πε₀))·Q/r².
    • Inside (r < R): field increases linearly with r: E = (1/(4πε₀))·(Q·r/R³) = (ρ·r)/(3ε₀), where ρ is volume charge density.
  • Infinite line of charge (cylindrical symmetry):
    • Gaussian surface: coaxial cylinder of radius r and length L.
    • Field: E = λ/(2π ε₀ r), directed radially outward (λ = linear charge density).
  • Infinite charged plane (planar symmetry):
    • Gaussian surface: pillbox straddling the plane.
    • Field (single infinite sheet, both sides): E = σ/(2ε₀), constant and independent of distance; σ = surface charge density.
    • Two oppositely charged infinite plates (parallel-plate capacitor): inside E = σ/ε₀ (if plates are infinite), outside fields cancel.
  • Infinite cylindrical shell (conducting):
    • Inside hollow region (r < a): E = 0 (for conducting shell).
    • Outside (r > a): E = λ/(2π ε₀ r) as if all charge were on axis.
  • Conducting solid sphere:
    • All excess charge resides on the outer surface; inside conductor E = 0.
    • Outside field: E = (1/(4πε₀))·Q/r².
  • Coaxial cable (application of cylindrical symmetry):
    • Between inner radius a and outer radius b, if inner conductor carries +λ and outer carries -λ, then E(r) = λ/(2π ε₀ r) for a < r < b.
    • Inside conductors the field is zero; useful for shielding and transmission-line design.
  • Uniformly charged infinite slab (thickness 2a):
    • Field inside is linear with distance from center: E = ρ x/ε₀ (for |x| < a), where x is distance from mid-plane; outside it becomes constant E = ρ a/ε₀ = σ/2ε₀ (matches infinite sheet limit).

Important physical consequences and uses:

  • Electrostatic shielding (Faraday cage): conductor interior has E = 0, so sensitive electronics can be protected from external fields.
  • Capacitor design: field between parallel plates derived using Gauss's law gives capacitance per area, energy density (1/2)ε₀E².
  • Coaxial cable and transmission lines: field distribution and shielding derived from cylindrical Gauss law results.
  • Electrostatic precipitators and droplet/particle manipulation exploit field near plates and edges; lightning rods use field enhancement at sharp points (not directly from Gauss but consistent with surface charge concentration).

Limitations: Gauss's law always holds, but finding E easily from it requires high symmetry (spherical, cylindrical, planar). For arbitrary charge distributions, other methods (superposition, Coulomb's law, numerical methods) are needed.

📌 Examples
  • Electric field outside and inside a uniformly charged hollow metal sphere — shows that inside E = 0 and outside field behaves like a point charge.
  • Field of an infinitely long charged wire — using a cylindrical Gaussian surface yields E = λ/(2π ε₀ r), important for estimating fields around high-voltage lines.
  • Parallel-plate capacitor (ideal, infinite plates) — using a pillbox gives E between plates = σ/ε₀ and energy stored per unit volume = (1/2)ε₀E².
  • Coaxial cable — find E(r) between inner and outer conductors with cylindrical Gaussian surface; explains why cable shields confine fields.
  • Electrostatic shielding (Faraday cage) — Gauss's law implies conductor interior has zero net field in electrostatic equilibrium.
  • Uniformly charged solid sphere — E increases linearly inside (E ∝ r) and falls as 1/r² outside.
🧮 Formulas
  1. \[Gauss's law: ∮ E · dA = Q_enclosed / ε₀\]
  2. \[Point / spherical charge (outside): E = (1 / (4πε₀)) · Q / r²\]
  3. \[Thin spherical shell (inside): E = 0 (for r < R)\]
  4. \[Uniform solid sphere (inside\]
    \[r < R): E = (1 / (4πε₀)) · (Q · r / R³) = (ρ · r) / (3ε₀)\]
  5. \[Infinite line charge: E = λ / (2π ε₀ r)\]
  6. \[Infinite plane sheet: E = σ / (2ε₀) (one sheet\]
    \[field on each side)\]
🔬12

Conductors in electrostatic equilibrium

Fig 1.12 — Educational Diagram: Electrostatic Shielding (E=0 in Conductor Cavity & Faraday Cage)

Fig 1.12 — Educational Diagram: Electrostatic Shielding (E=0 in Conductor Cavity & Faraday Cage)

⚡ KEY CONCEPT

Conductors in electrostatic equilibrium

Core Principle: Inside conductor: E = 0

Definition: A conductor in electrostatic equilibrium is a conducting body in which charges are at rest and the electric field inside the conducting material is zero.

Key properties and reasoning:

  • Electric field inside is zero: Free charges in a conductor move until the internal electric field cancels. At equilibrium, E = 0 everywhere inside the conducting material.
  • All excess charge resides on the surface: Using Gauss's law for a Gaussian surface drawn entirely inside the conductor: flux = 0 ⇒ net enclosed charge = 0, so any excess charge must be on the conductor's surface.
  • Surface field is perpendicular: The electric field at the conductor surface is normal to the surface. If there were a tangential component, free charges would move along the surface and equilibrium would not exist.
  • Boundary condition: Just outside the surface the normal component of the electric field E_n satisfies E_n = σ/ε0, where σ is the surface charge density and ε0 is the permittivity of free space. (Inside the conductor E_n = 0, so the discontinuity equals σ/ε0.)
  • Equipotential: The entire conductor (including its surface and interior) is at the same electric potential V. Moving a charge inside the conductor requires no work.
  • Sharp points and curvature: Surface charge density and hence the local electric field are larger at regions of high curvature (sharp points). This is why corona discharge and strong fields occur at pointed conductors.
  • Hollow conductor and induced charges: If a charge q is placed in a cavity inside a hollow isolated conductor (not touching the conductor), an induced charge −q appears on the inner surface and a charge +q appears on the outer surface, so the net conductor charge remains unchanged. If the conductor is grounded, the induced charge may flow to ground.
  • Electrostatic shielding (Faraday cage): Because E = 0 inside a closed conductor, sensitive devices inside a conducting enclosure are shielded from external static electric fields.

Common derivations/arguments:

  • Gauss's law: For a Gaussian surface just beneath the conductor surface, flux = 0 ⇒ field inside = 0 ⇒ any flux originates from surface charges.
  • Work and potential: Since E = 0 inside, potential V is constant throughout the conductor. Therefore, V(surface) = V(internal point).

Practical consequences:

  • Design of lightning rods and grounding systems uses the fact that charges concentrate at points and that grounding removes excess charge.
  • Capacitors use conducting plates where charges live on surfaces, and the field between plates is used to store energy.
  • Faraday cages protect electronics from external static fields and electrostatic discharge.
📌 Examples
  • Lightning rod: a pointed conductor concentrates charge and produces very high local electric field so lightning preferentially strikes the rod; the rod is connected to ground, safely transferring charge to earth.
  • Faraday cage: a closed conducting mesh around sensitive equipment blocks external static electric fields, keeping the inside E ≈ 0 (electrostatic shielding).
  • Charged isolated conducting sphere: if a sphere of radius R carries charge Q, all charge is on its outer surface; field inside is zero, outside E(r)=Q/(4πε0 r^2).
  • Van de Graaff generator: uses a conductor to collect charge on the outer surface of a hollow sphere, raising its potential while the interior remains field-free.
  • Electrostatic painting: conductive car bodies are grounded so paint particles (charged) are attracted to and deposit on the surface due to surface charge distribution and field lines.
🧮 Formulas
  1. \[Inside conductor: E = 0\]
  2. \[Surface normal field (just outside): E_n = σ/ε0 (since E_inside = 0)\]
  3. \[Gauss for sphere (r ≥ R): E(r) = Q/(4πε0 r^2)\]
    \[for r < R: E(r) = 0\]
  4. \[Potential of a charged isolated conducting sphere: V = Q/(4πε0 R) (constant for r ≤ R)\]
  5. \[For a charge q inside a cavity of an isolated conductor: induced charge on inner surface = −q\]
    \[remaining induced charge appears on outer surface so total conductor charge is conserved\]
  6. \[Boundary condition (general): E_outside − E_inside = σ/ε0 (normal components)\]
    \[and tangential E at surface = 0\]
⚖️13

Continuous charge distribution: integration examples

Fig 1.13 — Educational Diagram: Electric Dipole in Uniform Field (Torque τ = p×E & Potential Energy)

Fig 1.13 — Educational Diagram: Electric Dipole in Uniform Field (Torque τ = p×E & Potential Energy)

⚡ KEY CONCEPT

Continuous charge distribution: integration examples

Core Principle: dq = λ dx (linear), dq = σ dA (surface), dq = ρ dV (volume)

What is a continuous charge distribution?
When charge is spread over a line, surface or volume (not concentrated at points), we treat it as a continuous distribution described by a density: linear λ (C/m), surface σ (C/m²) or volume ρ (C/m³). To find the electric field E (or potential V) we split the distribution into infinitesimal elements dq, find the contribution dE from each element using Coulomb's law, and integrate over the object.

General method (step-by-step)

  • Choose coordinates and an element of charge: dq = λ dx (line), dq = σ dA (surface), dq = ρ dV (volume).
  • Write dE from Coulomb's law: dE = (1/4πε0) (dq / r²) r̂. Express r (distance) and r̂ (direction cosines) in your variables.
  • Resolve dE into components if symmetry causes cancellation; keep only the nonzero component(s).
  • Integrate the component(s) over the entire distribution; apply limits and simplify. Use limits (→∞, R→∞) for special cases (infinite rod/plane).

Worked (canonical) examples — with key integrals and results

1. Field on the perpendicular bisector of a finite uniformly charged rod (rod of half-length L, linear density λ):

Geometry: rod along x from −L to +L, point P on y-axis at distance y from centre. Take dq = λ dx. Only the y-components add (x-components cancel).

Integral (vertical component): Ey = (1/4πε0) ∫−L+L (λ y dx)/(x² + y²)^(3/2) = (1/4πε0) · (2λL)/(y √(L² + y²)).

Limits: L → ∞ ⇒ infinite line: E = λ/(2πε0 y) (field varies as 1/y).

2. Field at a point on the axis of a uniformly charged finite rod (rod on x from 0 to L, point P at x = x0 > L):

dq = λ dx, distance r = x0 − x. Integration gives E = (1/4πε0) λ [1/(x0 − L) − 1/(x0)], directed away from the rod if λ>0.

3. Field on the axis of a uniformly charged ring (radius R, total charge Q):

Symmetry: horizontal components cancel; axial component adds. dq = (Q/2πR) R dθ. E(x) = (1/4πε0) · Q x /(x² + R²)^(3/2), where x is distance from center along axis. Maximum of E occurs at x = R/√2. For x ≫ R, E ≈ (1/4πε0) Q/x² (ring acts like point charge far away).

4. Field on the axis of a uniformly charged circular disk (radius R, surface density σ):

Consider the disk as concentric rings. Element ring of radius r, width dr has dq = σ (2πr dr). The axial field from the ring: dE = (1/4πε0) (dq x)/(x² + r²)^(3/2). Integrate r from 0 to R to get

E(x) = (σ/(2ε0)) [1 − x/√(x² + R²)], directed along axis. In the limit R → ∞ (infinite plane) this becomes E = σ/(2ε0), independent of x.

5. Field of a uniformly charged thin spherical shell:

By symmetry and Gauss's law (or by integrating Coulomb contributions), for radius a and total charge Q: outside (r > a) E = (1/4πε0) Q/r² (acts like point charge); inside (r < a) E = 0.

Important remarks

  • Choose symmetry to simplify integrals: translational (infinite rod), cylindrical (ring/disk), spherical (sphere) symmetries reduce vector integrals to scalars.
  • Always resolve vector dE into components when symmetry cancels some components.
  • Keep track of limits when integrating (finite→infinite cases).
📌 Examples
  • Finite rod (length 2L) on perpendicular bisector: E_y = (1/4πε0)·(2λL)/(y·√(L^2 + y^2)). Infinite-rod limit: E = λ/(2πε0 y).
  • Point on axis of finite rod (rod from x=0 to L, point at x0>L): E = (1/4πε0)·λ[1/(x0−L) − 1/x0] along axis.
  • Uniformly charged ring (radius R, total charge Q): on-axis field E(x) = (1/4πε0)· Q x /(x^2 + R^2)^(3/2).
  • Uniform disk (radius R, surface density σ): on-axis E(x) = (σ/(2ε0))·[1 − x/√(x^2 + R^2)]. Infinite-plane limit: E = σ/(2ε0).
  • Spherical shell (radius a, total charge Q): E = 0 for r < a; E = (1/4πε0)·Q/r^2 for r ≥ a.
🧮 Formulas
  1. \[dq = λ dx (linear)\]
    \[dq = σ dA (surface)\]
    \[dq = ρ dV (volume)\]
  2. \[Coulomb law (infinitesimal): dE = (1/4πε0)·(dq / r^2)·r̂\]
  3. \[Field of finite rod on perpendicular bisector: E = (1/4πε0)·(2λL)/(y·√(L^2 + y^2))\]
  4. \[Infinite line (λ): E = λ/(2πε0 r)\]
  5. \[Field on axis of ring (Q,R): E(x) = (1/4πε0)· Q x /(x^2 + R^2)^(3/2)\]
  6. \[Field on axis of disk (σ,R): E(x) = (σ/(2ε0))·[1 − x/√(x^2 + R^2)]\]
🔬14

Constants and units

Fig 1.14 — Educational Diagram: Parabolic Motion of Charged Particle in Uniform Electric Field

Fig 1.14 — Educational Diagram: Parabolic Motion of Charged Particle in Uniform Electric Field

⚡ KEY CONCEPT

Constants and units

Core Principle: Coulomb's law: F = k q1 q2 / r^2, where k = 1/(4π ε0) ≈ 8.99 × 10^9 N·m^2·C^−2

What this topic covers
In electrostatics we use a small set of physical constants and SI units to express charge, force, field and potential. These constants appear in Coulomb's law, expressions for electric field and potential of point charges, and in relations that include the permittivity of the medium.

Important constants

  • Elementary charge (e): magnitude of charge on a proton (and magnitude of electron charge). Exact SI value (2019 redefinition): e = 1.602176634 × 10-19 C. Electron charge = −e.
  • Permittivity of free space (ε0): characterizes how electric field lines behave in vacuum. ε0 ≈ 8.8541878128 × 10-12 F m-1 (farad per metre). It is also often written as units C2 N-1 m-2.
  • Coulomb constant (k): k = 1/(4π ε0) ≈ 8.9875517923 × 109 N m2 C-2 (commonly approximated as 9.0 × 109). It appears in Coulomb's law as the proportionality constant.
  • Relative permittivity (εr): dimensionless dielectric constant of a medium. Absolute permittivity ε = εr ε0.

SI units used in electrostatics (quick list)

  • Charge: coulomb (C). 1 C = 1 A · s (ampere-second).
  • Force: newton (N) = kg · m · s-2.
  • Electric field: newton per coulomb (N/C) or volt per metre (V/m).
  • Electric potential (voltage): volt (V) = J/C.
  • Capacitance: farad (F) = C/V.
  • Electric flux: N · m2 / C.

How the constants appear in formulas (conceptual)
Coulomb's law: the force between two point charges q1 and q2 separated by r is F = k q1 q2 / r2. The constant k (or equivalently ε0) sets the strength of the electrostatic interaction in vacuum. For a medium with permittivity ε, replace ε0 by ε (or equivalently divide k by εr).

Practical notes for students
When solving problems remember: (a) use sign for charge when calculating direction of field/force/potential; (b) use k ≈ 9 × 109 N m2 C-2 for quick calculations or compute from ε0 when accuracy is needed; (c) express charge in coulombs (convert μC, nC etc. to C: 1 μC = 10-6 C, 1 nC = 10-9 C).

📌 Examples
  • Coulomb force between two charges: two charges of +3.0 μC and −2.0 μC are 0.20 m apart. Using k = 9.0 × 10^9 N·m^2·C^−2, the magnitude of force is F = k q1 q2 / r^2 ≈ (9 × 10^9)(3×10^-6)(2×10^-6)/(0.2)^2 ≈ 1.35 N (attractive).
  • Electric field of a point charge: the field at distance r from a charge Q is E = k Q / r^2. For Q = 5.0 μC at r = 0.10 m, E ≈ (9 × 10^9)(5×10^-6)/(0.1)^2 ≈ 4.5×10^6 N/C.
  • Capacitor and permittivity: capacitance of a parallel plate capacitor C = ε A / d uses ε = ε_r ε_0. If a dielectric with ε_r = 2.5 fills the gap, C increases by factor 2.5 compared to vacuum.
  • Practical device — photocopier: uses electrostatic charges (created and controlled using known constants and voltages) to attract toner particles to charged parts of the paper.
  • Everyday phenomenon — comb and hair: after combing, small charges (countable multiples of e) build up; the Coulomb force between the charged comb and hair causes attraction, illustrating discrete charge and Coulomb constant effects.
🧮 Formulas
  1. \[Coulomb's law: F = k q1 q2 / r^2\]
    \[where k = 1/(4π ε0) ≈ 8.99 × 10^9 N·m^2·C^−2\]
  2. \[Permittivity relation: ε = εr ε0\]
    \[with ε0 ≈ 8.8541878128 × 10^−12 F·m^−1\]
  3. \[Electric field of point charge: E = k Q / r^2 (radial\]
    \[direction by sign of Q)\]
    \[units: N/C or V/m\]
  4. \[Electric potential of point charge: V = k Q / r (relative to infinity)\]
    \[units: V = J/C\]
  5. \[Potential energy of two point charges: U = k q1 q2 / r\]
  6. \[Electric flux (through surface): Φ = ∮ E · dA\]
    \[unit: N·m^2·C^−1\]
🔬15

Problem-solving techniques and symmetry

Fig 1.15 — Educational Diagram: Dielectric Polarization & Net Reduced Field (E = E0 / K)

Fig 1.15 — Educational Diagram: Dielectric Polarization & Net Reduced Field (E = E0 / K)

⚡ KEY CONCEPT

Problem-solving techniques and symmetry

Core Principle: Coulomb's law (point charge): F = (1/4πε0)·(q1 q2 / r^2) r̂, and field E = (1/4πε0)·(q / r^2) r̂

Overview: In electrostatics many problems become tractable by combining basic problem-solving techniques with symmetry arguments. Symmetry tells you the direction of the electric field and which coordinates it can depend on, so you can choose methods (Coulomb's law or Gauss's law) and coordinate systems that simplify calculations.

Key ideas and steps to solve problems:

  1. Identify the charge distribution and any symmetry: spherical, cylindrical (axial), planar (translational), or discrete (dipole, ring).
  2. Decide if direct superposition (Coulomb's law) or Gauss's law is appropriate. Use Gauss's law when symmetry makes the field constant on a chosen surface or normal to it.
  3. Choose a coordinate system and a Gaussian surface that matches the symmetry (sphere for spherical symmetry, cylinder for cylindrical symmetry, plane/box for planar symmetry).
  4. Use symmetry to determine field direction and dependence: e.g., spherical symmetry → E radial and depends only on r; infinite plane → E perpendicular and constant; infinite line → E radial in plane perpendicular to line and depends on r only.
  5. Write down Coulomb's law or the integral form of Gauss's law. If using Gauss's law, compute flux = ∮ E·dA = Q_enclosed/ε0. Solve for E and check units and limiting behavior.
  6. For configurations without sufficient symmetry use superposition: break distribution into simple parts, compute fields (analytically or by symmetry) and add vectorially. Use components and unit vectors as needed.
  7. Check special cases and limits: far-field behavior, r→0 or r→∞, field continuity at boundaries, and physical constraints (e.g., field inside conductor = 0).

Symmetry types and consequences:

  • Spherical symmetry: Field is radial, depends only on radial distance r. Gauss's law with spherical surface gives E(r) easily. Example: uniformly charged sphere (insulating) and conducting sphere.
  • Cylindrical symmetry: Field is radial outward from axis, depends only on radial distance ρ (in cylindrical coordinates). Use a coaxial Gaussian cylinder to find E(ρ).
  • Planar/translational symmetry: For an infinite plane of charge field is perpendicular to plane and independent of distance. Use a pillbox Gaussian surface.
  • Reflection/rotational symmetry: Helps place zero components: e.g., for an infinite charged sheet with a hole or for rings/dipoles along symmetry axes.

Other useful techniques: superposition principle, decomposition into components, use of image charges for conductors with simple planar or spherical boundaries (method of images), dimensional analysis and limiting cases, and sketching field lines to visualize direction and relative strength.

When to use Gauss's law vs Coulomb's law:

  • Use Gauss's law when symmetry forces E constant on portions of the Gaussian surface or E is everywhere normal (spheres, infinite cylinders, infinite planes).
  • Use Coulomb's law (integration) or superposition when the distribution lacks the requisite symmetry (finite rods, rings, dipoles) or for on-axis fields of symmetric finite objects.

Common pitfalls: assuming symmetry that does not exist (e.g., finite sheet ≠ infinite sheet), wrong Gaussian surface, ignoring vector nature of fields, failing to include sign of enclosed charge, and not checking boundary/limit behavior.

📌 Examples
  • Electric field of a uniformly charged spherical shell: By spherical symmetry, choose a concentric spherical Gaussian surface. For r greater than the shell radius, E = (1/4πε0)·Q/r^2 as if all charge were concentrated at centre; for r inside a thin conducting shell, E = 0.
  • Infinite uniformly charged plane: Using a pillbox Gaussian surface and planar symmetry, the magnitude of field on either side is E = σ/(2ε0) directed away from the plane (σ is surface charge density).
  • Long uniformly charged straight wire: With cylindrical symmetry use a coaxial Gaussian cylinder to get E(ρ) = λ/(2πε0 ρ) (λ is linear charge density), field decreases as 1/ρ.
  • Uniformly charged solid sphere (insulating): For r ≤ R (inside), E = (1/4πε0)·(Q r / R^3) (i.e., E ∝ r); for r ≥ R, E = (1/4πε0)·Q/r^2. This follows from spherical symmetry and Gauss's law with Q_enclosed ∝ r^3.
  • Charged ring on its axis: No full spherical/cylindrical symmetry—use Coulomb's law and superposition: on axis at distance x from center, E_x = (1/4πε0)·(Q x)/(x^2 + a^2)^(3/2), where a is ring radius. Symmetry gives field along axis only.
🧮 Formulas
  1. \[Coulomb's law (point charge): F = (1/4πε0)·(q1 q2 / r^2) r̂\]
    \[and field E = (1/4πε0)·(q / r^2) r̂\]
  2. \[Superposition (continuous distribution): E(r) = (1/4πε0) · ∫ (dq · r̂') / r'^2 where r' is vector from source element to field point\]
  3. \[Gauss's law (integral form): ∮ E · dA = Q_enclosed / ε0\]
  4. \[Electric flux: Φ = ∫ E · dA\]
  5. \[Field of infinite line charge: E(ρ) = λ / (2πε0 ρ) (radial direction)\]
  6. \[Field of infinite plane sheet: E = σ / (2ε0) (on each side\]
    \[perpendicular to plane)\]

Key Concepts

Electric charge
A fundamental property of matter that causes it to experience electric forces; comes in two signs (positive, negative). SI unit: coulomb (C).
Quantization of charge
Electric charge exists in integer multiples of the elementary charge e (≈1.602×10⁻¹⁹ C).
Conservation of charge
The total electric charge in an isolated system remains constant; charge can be transferred but not created or destroyed.
Coulomb's law
The electrostatic force between two point charges q1 and q2 separated by distance r is F = (1/4πε₀)·(q1q2/r²) along the line joining them (attractive if opposite signs, repulsive if same sign).
Permittivity of free space (ε₀)
A physical constant that appears in Coulomb's law and Gauss's law; ε₀ ≈ 8.854×10⁻¹² F/m (farads per metre).
Superposition principle
The net electric field (or force) at a point due to multiple charges is the vector sum of fields (or forces) produced by each charge independently.
Electric field (electric field intensity)
A vector field E representing force per unit positive test charge: E = F/q₀. SI unit: N/C (or V/m).
Electric field due to a point charge
For a point charge q at distance r, the field is E = (1/4πε₀)·(q/r²) directed radially away from q if q>0, toward q if q<0.
Electric field of continuous charge distributions
Fields from extended charge distributions (line, surface, volume) are found by integrating contributions dE = (1/4πε₀)·(dq/r²) along the distribution.
Electric field lines
Imaginary lines drawn so tangent at any point gives field direction; density of lines indicates field strength; lines start on positive and end on negative charges.
Electric flux
A measure of the number of electric field lines passing through a surface: Φ = ∫E·dA; for uniform field and flat surface Φ = E A cosθ. Unit: N·m²/C.
Gauss's law
The net electric flux through any closed surface equals the enclosed charge divided by ε₀: ∮E·dA = Q_enclosed/ε₀.
Infinite line charge (Gauss law application)
For an infinitely long straight line with linear charge density λ, the radial field at distance r is E = λ/(2πε₀ r).
Infinite plane sheet of charge
An infinite uniformly charged plane with surface charge density σ produces a uniform field E = σ/(2ε₀) on each side, independent of distance.
Electric field of a uniformly charged spherical shell
Outside the shell: E = (1/4πε₀)·(Q/r²) (like a point charge). Inside a thin conducting spherical shell in electrostatic equilibrium: E = 0.
Electric dipole
A pair of equal and opposite charges +q and −q separated by small distance d; a basic neutral charge configuration with a directional property.
Electric dipole moment
A vector p = q·d pointing from negative to positive charge; magnitude p = qd. It quantifies dipole strength. Unit: C·m.
Torque on a dipole in a uniform electric field
A dipole in uniform field E experiences torque τ = p × E (magnitude τ = pE sinθ) tending to align p with E.
Equipotential surface
A surface on which electric potential is the same at every point; no work is done moving a charge along an equipotential.

Practice Questions

  1. State the laws of quantization and conservation of electric charge. / विद्युत आवेश के क्वांटमीकरण तथा संरक्षण के नियम लिखिए।
    Show answer

    Quantization: any charge q = n·e where n is an integer and e = 1.6×10⁻¹⁹ C; Conservation: total charge of an isolated system remains constant (charge can only be transferred). / क्वांटमीकरण: कोई भी आवेश q = n·e जहाँ n पूर्णांक तथा e = 1.6×10⁻¹⁹ C; संरक्षण: विलगित निकाय का कुल आवेश नियत रहता है (आवेश केवल स्थानांतरित होता है)।

  2. State Coulomb's law in vector form and define the constant k. / सदिश रूप में कूलॉम का नियम लिखिए तथा नियतांक k को परिभाषित कीजिए।
    Show answer

    F₂₁ = (1/4πε₀)(q₁q₂/r²)r̂, where k = 1/4πε₀ ≈ 8.99×10⁹ N·m²/C² and r̂ points from q₁ to q₂. / F₂₁ = (1/4πε₀)(q₁q₂/r²)r̂, जहाँ k = 1/4πε₀ ≈ 8.99×10⁹ N·m²/C² तथा r̂ q₁ से q₂ की ओर है।

  3. Two charges q₁=+5.0 μC and q₂=-3.0 μC are 10 cm apart in air. Find the force and its nature. / वायु में q₁=+5.0 μC तथा q₂=-3.0 μC आवेश 10 cm की दूरी पर हैं। बल तथा उसकी प्रकृति ज्ञात कीजिए।
    Show answer

    F = (8.99×10⁹)(5×10⁻⁶)(3×10⁻⁶)/(0.10)² ≈ 13.5 N, attractive (opposite signs). / F = (8.99×10⁹)(5×10⁻⁶)(3×10⁻⁶)/(0.10)² ≈ 13.5 N, आकर्षी (विपरीत चिह्न)।

  4. Define electric field and write the expression for the field of a point charge. / विद्युत क्षेत्र परिभाषित कीजिए तथा बिंदु आवेश के क्षेत्र का व्यंजक लिखिए।
    Show answer

    Electric field E = F/q₀ is the force per unit positive test charge; for a point charge E = (1/4πε₀)(q/r²)r̂, radial. / विद्युत क्षेत्र E = F/q₀ प्रति एकांक धन परीक्षण आवेश पर बल है; बिंदु आवेश के लिए E = (1/4πε₀)(q/r²)r̂, त्रिज्यीय।

  5. Derive the expression for the axial electric field of a short dipole and give its distance dependence. / लघु द्विध्रुव के अक्षीय विद्युत क्षेत्र का व्यंजक लिखिए तथा इसकी दूरी-निर्भरता बताइए।
    Show answer

    On the axis (θ=0), E_axial = (1/4πε₀)(2p/r³), directed along p; it varies as 1/r³ for r >> a. / अक्ष पर (θ=0), E_axial = (1/4πε₀)(2p/r³), p की दिशा में; r >> a के लिए यह 1/r³ के अनुसार बदलता है।

  6. Derive the torque and potential energy of a dipole of moment p in a uniform field E. / एकसमान क्षेत्र E में आघूर्ण p वाले द्विध्रुव का बल-आघूर्ण तथा स्थितिज ऊर्जा ज्ञात कीजिए।
    Show answer

    Torque τ = p × E, magnitude τ = pE sinθ; potential energy U = -p·E = -pE cosθ. / बल-आघूर्ण τ = p × E, परिमाण τ = pE sinθ; स्थितिज ऊर्जा U = -p·E = -pE cosθ।

  7. State Gauss's law and define electric flux. / गाउस का नियम लिखिए तथा विद्युत फ्लक्स परिभाषित कीजिए।
    Show answer

    Electric flux Φ = ∮E·dA measures field lines crossing a surface; Gauss's law: ∮E·dA = q_enc/ε₀, the net flux through a closed surface equals enclosed charge divided by ε₀. / विद्युत फ्लक्स Φ = ∮E·dA सतह को पार करती क्षेत्र रेखाओं को मापता है; गाउस नियम: ∮E·dA = q_enc/ε₀।

  8. Using Gauss's law, write the electric field for an infinite line charge, an infinite plane sheet, and just outside a charged conductor. / गाउस नियम का प्रयोग कर अनंत रेखीय आवेश, अनंत समतल चादर तथा आवेशित चालक के ठीक बाहर विद्युत क्षेत्र लिखिए।
    Show answer

    Line: E = λ/(2πε₀r); plane sheet: E = σ/(2ε₀); just outside a conductor: E = σ/ε₀ (normal to surface), zero inside. / रेखा: E = λ/(2πε₀r); समतल चादर: E = σ/(2ε₀); चालक के ठीक बाहर: E = σ/ε₀ (सतह के लंबवत), अंदर शून्य।

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