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Chapter 6 — Work Energy And Power

Class 11 · Physics

Overview

Chapter 6 — Work Energy And Power Master Diagram

This chapter introduces the core concepts of work, energy and power — fundamental quantities in mechanics that describe how forces cause motion and how that motion is quantified and transformed. Students learn precise definitions (work done by a constant and variable force), the work–energy theorem, kinetic and potential energy (gravitational and elastic), the distinction between conservative and non-conservative forces, and the principle of conservation of mechanical energy. The chapter also covers power (instantaneous and average) and practical problem-solving strategies using energy methods. Importance: Understanding work, energy and power gives students powerful tools to analyze mechanical systems more simply than force-by-force methods. Energy concepts unify many physical phenomena, make calculations easier for complicated force fields, and link to real-world applications such as engines, brakes, springs and machines. Key themes: (1) Quantitative definition of work and how to compute it for constant and variable forces; (2) Kinetic energy and the work–energy theorem as an alternative to Newtonian force analysis; (3) Potential energy, conservative forces and the relation F =…

Learning Objectives

  • Define work done by a constant force as the scalar (dot) product of force and displacement and state its SI unit.
  • Explain work done by a variable force and interpret it as the area under the force–displacement (F–x) graph.
  • Derive the work–energy theorem for a particle and use it to solve numerical problems involving change in kinetic energy.
  • Define kinetic energy and derive the expression K = 1/2 mv^2; calculate kinetic energy for given mass and speed.
  • Define gravitational potential energy near Earth's surface, derive U = mgh, and apply it in energy calculations.
  • Define elastic potential energy for a Hookean spring, derive U = 1/2 kx^2, and calculate energy stored for given k and x.
  • Explain conservative and non‑conservative forces, distinguish them by path dependence, and give representative examples.
  • Apply conservation of mechanical energy to solve problems where non‑conservative forces are absent.

Topics in this chapter

15 topics · tap a topic title to jump straight to it.

⚙️1

Work

Fig 1 — Educational Diagram: Work

Fig 1 — Educational Diagram: Work

⚡ PHYSICAL LAW / FORMULA

Work

Key Point: W = F · s = F s cos θ (constant force)

Definition: Work is the scalar quantity equal to the product of the component of a force along the direction of displacement and the magnitude of the displacement. It measures the energy transfer to or from a body by the action of a force.

SI unit: Joule (J) where 1 J = 1 N·m.

Work by a constant force: If a constant force F acts on a body and the body is displaced by a vector s, the work done is
W = F · s = F s cos θ,
where θ is the angle between the force and displacement vectors.

Work by a variable force: For a force that varies with position, work from r1 to r2 is the line integral
W = ∫r1r2 F(r) · dr.

Sign convention: Work can be positive, negative or zero.

  • Positive: force has a component along displacement (e.g., gravity doing positive work when object falls).
  • Negative: force has a component opposite to displacement (e.g., friction opposing motion).
  • Zero: force is perpendicular to displacement (e.g., centripetal force in uniform circular motion; carrying a suitcase horizontally while lifting force is vertical).

Special cases and useful results:

  • Work by gravity (near Earth): Wgrav = - mg Δy = mg (yi - yf) where Δy = yf - yi.
  • Work done to stretch/compress a spring (Hooke's law F = -kx): W = ∫0x kx' dx' = 1/2 k x2 (work done by an external agent to stretch from 0 to x). The spring force does -1/2 k x2 of work over that process.
  • Work–energy theorem: Net work done on a particle equals the change in its kinetic energy: Wnet = ΔK = (1/2) m vf2 - (1/2) m vi2.
  • Conservative vs non-conservative forces: Work by a conservative force is path-independent and the work over any closed path is zero. Gravity and elastic spring forces are conservative; friction is non-conservative.

How to compute work (steps): 1) Resolve forces into components along displacement. 2) Use W = ∫ F · dr for variable forces or W = F s cos θ for constant forces. 3) Pay attention to sign conventions.

📌 Examples
  • Lifting a book vertically upward by height h: external work done = +mgh (if displacement upward and force upward), gravity does W = -mgh.
  • Pushing a box on a frictionless horizontal floor with constant horizontal force F through distance s: W = F s (force parallel to displacement).
  • Carrying a suitcase at constant speed horizontally while supporting it (force upward = weight): The vertical force does zero mechanical work because displacement is horizontal (force ⟂ displacement).
  • Sliding a block with friction over distance s: work done by friction = -f_k s (negative, removes kinetic energy).
  • Stretching a spring by x: work done by external agent = +1/2 k x^2; spring force does -1/2 k x^2.
🧮 Formulas
  1. \[W = F · s = F s cos θ (constant force)\]
  2. \[W = ∫(r1 to r2) F(r) · dr (variable force)\]
  3. \[W_gravity = - m g Δy = m g (y_i - y_f)\]
  4. \[W_spring (external) = 1/2 k x^2 (from 0 to x)\]
  5. \[W_net = ΔK = (1/2) m v_f^2 - (1/2) m v_i^2\]
  6. \[For closed path, ΣW_conservative = 0 (conservative forces)\]
💪2

Work Done by a Variable Force

Fig 2.1 — Educational Diagram: Newton

Fig 2.1 — Educational Diagram: Newton's Laws of Motion & Free Body Diagrams

⚡ PHYSICAL LAW / FORMULA

Work Done by a Variable Force

Key Point: Infinitesimal work: dW = F · dr

Definition: When a force varies with position, the work done in moving a particle from point A to B is the integral of the force along the path. For a small displacement dr, the infinitesimal work is dW = F · dr (scalar product).

One-dimensional case: If the force acts along the x-axis and depends on x, the work done moving from x1 to x2 is

W = ∫(x1 to x2) F(x) dx

Derivation idea (Riemann sum): Divide the path into small segments Δxi where the force is approximately constant F(xi). The total work ≈ Σ F(xi) Δxi. In the limit Δxi → 0 this sum becomes the integral above. Graphically this is the area under the F vs x curve between x1 and x2.

Vector form and sign: In vector form, W = ∫(path) F · dr. The sign of W depends on the angle between F and dr: positive when component of force is along displacement, negative when opposite. For motion in one dimension, a negative F(x) over the interval gives negative work (area below the x-axis).

Example: Work done by a spring: For Hooke's law, the spring (restoring) force is F(x) = -k x (x measured from natural length). Work done by the spring in moving from x1 to x2 is

W_spring = ∫(x1 to x2) (-k x) dx = -1/2 k (x2^2 - x1^2).

If we compress a spring from 0 to x, the external agent must do W_ext = +1/2 k x^2 (equal in magnitude and opposite in sign to the work done by the spring).

Work-energy theorem: The net work done by all forces on a particle equals the change in its kinetic energy: W_net = ΔK = 1/2 m v2^2 - 1/2 m v1^2. This remains valid when forces are variable; compute each force's work by integration and sum.

Conservative vs nonconservative: For conservative forces (e.g., gravity, spring), work between two points depends only on endpoints, not path. For nonconservative forces (e.g., friction), work generally depends on the path taken.

Units: SI unit of work is joule (J) = N·m.

Practical notes for solving problems:

  • Identify the force as a function of position F(x) along the path.
  • Choose correct limits x1 and x2 and sign convention.
  • Compute integral W = ∫ F(x) dx or use known antiderivatives (polynomial, inverse-square, exponential, etc.).
  • For vector motion in 2D/3D, compute W = ∫ F_x dx + ∫ F_y dy + ... or evaluate the line integral F · dr.

Common variable-force examples include springs, gravitational force varying with radial distance (inverse-square), nonuniform friction or drag that depends on position, and forces in elastic materials varying with extension.

📌 Examples
  • Compressing a spring from equilibrium to extension x: work done by spring = -1/2 k x^2, work done by external agent = +1/2 k x^2.
  • Moving a mass from radius r1 to r2 under gravity (inverse-square): W = ∫(r1 to r2) (-GMm/r^2) dr = -GMm (1/r2 - 1/r1).
  • Pulling a variable-stiffness rubber band where the restoring force F(x) varies nonlinearly with extension; compute W by integrating F(x).
  • Pumping water from a tank where the weight of the water element varies with height: integrate the force (weight) times vertical displacement over layers.
  • A block moving over a surface with position-dependent friction coefficient μ(x): friction force F_f(x)=μ(x) N leads to W = -∫ μ(x) N dx.
  • Stretching a non-linear spring whose force law is F(x)=ax+bx^2: work = ∫(0 to X) (ax+bx^2) dx = 1/2 a X^2 + 1/3 b X^3.
🧮 Formulas
  1. \[Infinitesimal work: dW = F · dr\]
  2. \[One-dimensional variable force: W = ∫(x1 to x2) F(x) dx\]
  3. \[Spring (Hooke's law): F(x) = -k x\]
    \[W_spring = ∫(x1 to x2) (-k x) dx = -1/2 k (x2^2 - x1^2)\]
  4. \[Inverse-square gravity: W = ∫(r1 to r2) (-GMm/r^2) dr = -GMm (1/r2 - 1/r1)\]
  5. \[Work-energy theorem: W_net = ΔK = 1/2 m v2^2 - 1/2 m v1^2\]
  6. \[Discrete approximation: W ≈ Σ F(xi) Δxi (Riemann sum\]
    \[limit gives integral)\]
💪3

Work Done by a Spring (Elastic Force)

Fig 3.1 — Educational Diagram: Newton

Fig 3.1 — Educational Diagram: Newton's Laws of Motion & Free Body Diagrams

⚡ PHYSICAL LAW / FORMULA

Work Done by a Spring (Elastic Force)

Key Point: Hooke's law: F_spring = -k x

Definition and Hooke's law: For an ideal (linear) spring, the restoring force exerted by the spring is proportional to its displacement from the natural (equilibrium) length: F_spring = -k x, where k is the spring constant (N/m), x is displacement measured from equilibrium, and the minus sign indicates the force is opposite to the displacement.

Work done by the spring force (derivation): Work done by the spring when its end moves quasi‑statically from position x1 to x2 is the integral of the spring force over displacement:

W_spring = ∫_{x1}^{x2} F_spring(x) dx = ∫_{x1}^{x2} (-k x) dx = -½ k (x2^2 - x1^2) = ½ k (x1^2 - x2^2).

This formula shows the work done by the spring depends only on the initial and final displacements (path independent) — a signature of a conservative force.

Elastic potential energy: We can define the elastic potential energy stored in a spring as U(x) = ½ k x^2 (choosing U(0)=0). The change in spring potential energy between x1 and x2 is ΔU = U(x2) - U(x1) = ½ k (x2^2 - x1^2). The relation between work by the spring and change in potential is W_spring = -ΔU.

Sign conventions and physical interpretation: If the spring goes from x1=0 to x2=+a (stretching), F_spring is negative while displacement is positive, so W_spring = -½k a^2: the spring does negative work (it absorbs energy). An external agent must do +½k a^2 work to stretch the spring slowly; this work is stored as elastic potential energy. Conversely, when the spring returns from +a to 0 it does positive work +½k a^2 on the object, releasing the stored energy.

Conservative nature and energy conservation: Because spring force is conservative, mechanical energy is conserved when only the spring and conservative forces act: ΔK + ΔU = 0. Thus work done by nonconservative forces equals change in (K + U).

📌 Examples
  • Spring balance: weight stretches the spring; displacement is proportional to weight via k, and the balance measures force because the spring stores elastic potential energy.
  • Vehicle suspension: shock absorbers and springs store and dissipate energy from bumps; springs store elastic energy and return it, smoothing motion.
  • Trampoline: jumping stretches the mat and springs; elastic potential energy stored during landing is returned to launch the jumper upward.
  • Pogo stick and diver board: compression of springs stores energy which is later released to propel motion.
  • Mechanical watch mainspring: wound spring stores elastic potential energy that is slowly released to drive the mechanism.
🧮 Formulas
  1. \[Hooke's law: F_spring = -k x\]
  2. \[Work done by spring from x1 to x2: W_spring = ∫_{x1}^{x2} F_spring dx = -½ k (x2^2 - x1^2) = ½ k (x1^2 - x2^2)\]
  3. \[Elastic potential energy: U(x) = ½ k x^2 (with U(0) = 0)\]
  4. \[Relation: W_spring = -ΔU and ΔK + ΔU = 0 (if only spring force does work)\]
  5. \[Work done by external agent to quasi‑statically move from 0 to x: W_ext = +½ k x^2 (equal to stored U)\]
🍎4

Work Done by Gravity

Fig 4 — Educational Diagram: Work Done by Gravity

Fig 4 — Educational Diagram: Work Done by Gravity

⚡ PHYSICAL LAW / FORMULA

Work Done by Gravity

Key Point: Work (general): W = ∫_A^B F·dr

Definition: Work done by gravity is the work performed by the gravitational force on a mass when it undergoes a displacement. Gravity is a conservative force, so the work done depends only on the initial and final vertical positions (heights), not on the path taken.

Vector form and basic formula: Let Fg = −mg ĵ (taking +y upward). For a displacement Δr = (y_B − y_A) ĵ,

Wg = ∫AB F·dr = (−mg) ∫y_Ay_B dy = −mg(y_B − y_A) = mg(y_A − y_B).

Interpretation: If the object moves downward (y_B < y_A) the work done by gravity is positive (gravity does positive work and kinetic energy increases). If the object is lifted (y_B > y_A) gravity does negative work (it removes kinetic energy).

Relation with potential energy: Define gravitational potential energy near Earth as U = mgy (choice of zero arbitrary). Then

Wg = −ΔU = −(U_B − U_A) = m g (y_A − y_B).

Conservative property: For any closed path (returning to the same height) the net work done by gravity is zero: Wclosed = 0. Work by gravity depends only on vertical displacement, not on the shape of the path.

Work for motion along an incline: If a block moves a distance s along an incline of angle θ and the vertical drop is h = s sinθ, then

Wg = mg h = mg s sinθ (sign positive if motion is downwards).

General (radial) gravitational field — extension: For large distances where g varies (Newtonian gravity), the work by gravity moving a mass from radial distance r_A to r_B is

W = ∫r_Ar_B (−GMm/r^2) dr = GMm(1/r_B − 1/r_A).

Key points to remember:

  • Work by gravity depends only on vertical height change: W = mg(y_A − y_B).
  • Gravity does zero work for purely horizontal displacement at constant height.
  • If an object falls freely from height y_A to y_B, the work done by gravity equals the loss in gravitational potential energy and equals the gain in kinetic energy (neglecting non‑conservative forces): W = ΔK = −ΔU.
📌 Examples
  • Free fall: A ball dropped from rest at height h. Work by gravity = mg h (positive); this equals the ball's gain in kinetic energy at the bottom.
  • Lifting an object: Lifting a box upward by height h. Work done by gravity = −mg h (negative); you must do +mg h of work against gravity.
  • Horizontal carry: Carrying a bag around at constant height. Work by gravity = 0 because vertical displacement is zero.
  • Sliding down an incline: A block slides down a frictionless incline of height h. Work by gravity = mg h; same as if it had fallen vertically through h.
  • Pendulum swing between same heights: Gravity does zero net work over a full oscillation; energy is exchanged between kinetic and potential forms.
🧮 Formulas
  1. \[Work (general): W = ∫_A^B F·dr\]
  2. \[Gravity near Earth's surface (constant g): W_g = −mg(y_B − y_A) = mg(y_A − y_B)\]
  3. \[Relation with potential energy: W_g = −ΔU where U = m g y (near Earth)\]
  4. \[Inclined plane (vertical drop h = s sinθ): W_g = mg h = mg s sinθ\]
  5. \[Closed path (conservative force): W_closed = 0\]
  6. \[Newtonian gravity (variable g): W = ∫_{r_A}^{r_B} (−GMm/r^2) dr = GMm(1/r_B − 1/r_A)\]
💪5

Work Done by Friction and Non-conservative Forces

Fig 5.1 — Educational Diagram: Newton

Fig 5.1 — Educational Diagram: Newton's Laws of Motion & Free Body Diagrams

⚡ PHYSICAL LAW / FORMULA

Work Done by Friction and Non-conservative Forces

Key Point: Work (general): W = ∫_A^B F · ds

Overview: Work by friction and other non-conservative forces is the mechanical work that cannot be recovered as potential energy because it is converted into internal energy (usually heat), sound or deformation. Unlike conservative forces (e.g., gravity, spring force), work done by non-conservative forces depends on the path taken.

General definition: For any force F acting along a path from point A to point B, the work is
W = ∫AB F · ds. Non-conservative forces give path-dependent values for this integral.

Work done by kinetic (sliding) friction: Kinetic friction acts opposite to the direction of instantaneous displacement. For a constant kinetic friction force fk opposite to motion over a displacement s,

Wfric = − fk s.

Using fk = μk N (where N is the normal reaction), for a block on a horizontal surface N = mg and

Wfric = − μk m g s.

On an incline at angle θ where N = mg cos θ,

Wfric = − μk m g cos θ  s.

Integral form for variable or direction-dependent friction:

Wfric = −∫path fk(s) ds = −∫AB |ffric(s)| ds,

which highlights path dependence: longer path → greater magnitude of negative work.

Non-conservative forces and mechanical energy: If non-conservative forces do work Wnc on a system, the change in mechanical energy (kinetic + potential) equals that work:

Wnc = ΔEmech = ΔK + ΔU.

When friction is the only non-conservative force, Wfric < 0, so mechanical energy decreases and the magnitude |Wfric| is the energy converted to internal energy (heat):

Energy dissipated (as heat, etc.) = −Wfric = −Wnc.

Power dissipated by friction: Instantaneous power by friction P = Ffric · v. For kinetic friction opposite velocity, P = −fk v (negative, meaning mechanical power removed).

Static friction note: Static friction does no work if the point of contact does not move relative to the surface (no slipping). Example: a wheel rolling without slipping has zero work by the static friction force on the center-of-mass translation (but internal deformations/rolling resistance can still dissipate energy).

Microscopic origin: Friction converts ordered mechanical energy into microscopic random motion of molecules (thermal energy) through surface interactions and deformation.

Key conceptual points:

  • Work by friction is usually negative (it removes kinetic/mechanical energy).
  • Non-conservative forces are path-dependent; conservative are path-independent and associated with potential energy.
  • Wnc = ΔEmech is a useful bookkeeping relation: if Wnc < 0 mechanical energy decreases; if Wnc > 0 mechanical energy increases (e.g., engine doing positive work).

📌 Examples
  • A block of mass m slides distance s on a horizontal rough surface with coefficient of kinetic friction μk. Work by friction: W = −μk m g s; the mechanical energy lost becomes thermal energy.
  • A car braking to a stop: brake pads provide non-conservative work that removes kinetic energy; the work done by friction equals the decrease in kinetic energy and appears as heat in the pads and tyres.
  • A pendulum in air: air resistance (a non-conservative force) does negative work each swing, so amplitude decays — mechanical energy lost becomes thermal and sound.
  • Dragging a box up an incline with a pulling force: the work done by the pulling force is partitioned into increase in potential energy, work done against friction (dissipated), and change in kinetic energy (if any).
  • Rubbing hands: biochemical energy is converted into macroscopic work against friction; the work done by friction increases internal energy (warmth).
🧮 Formulas
  1. \[Work (general): W = ∫_A^B F · ds\]
  2. \[Work by constant kinetic friction: W_fric = −f_k s = −μ_k N s\]
  3. \[Normal on horizontal: N = m g ⇒ W_fric = −μ_k m g s\]
  4. \[Normal on incline: N = m g cosθ ⇒ W_fric = −μ_k m g cosθ · s\]
  5. \[Non-conservative work and mechanical energy: W_nc = ΔE_mech = ΔK + ΔU\]
  6. \[Energy dissipated (heat) by friction: E_dissipated = −W_fric (since W_fric < 0)\]
6

Kinetic Energy and Work–Energy Theorem

Fig 6 — Educational Diagram: Kinetic Energy and Work–Energy Theorem

Fig 6 — Educational Diagram: Kinetic Energy and Work–Energy Theorem

⚡ PHYSICAL LAW / FORMULA

Kinetic Energy and Work–Energy Theorem

Key Point: Work by constant force: W = F · s (if F and s are collinear).

Kinetic energy (KE) is the energy a body possesses due to its motion. For a particle of mass m moving with speed v, its kinetic energy K is defined as K = 1/2 m v2. KE is a scalar and its SI unit is the joule (J).

Work done by a force: If a constant force F acts on a particle producing a displacement s in the direction of the force, the work done is W = F · s. For a variable force or a curved path, infinitesimal work dW = F · ds and the total work is the line integral W = ∫ F · ds.

Derivation of KE formula and the work–energy theorem (constant force, straight line):

Consider a particle of mass m acted on by a net constant force F causing acceleration a. By Newton's second law, F = m a. If the particle's speed changes from u to v while it moves through displacement s under the action of F, the work done by the net force is

W = F s = m a s.

Using the kinematic relation v2 = u2 + 2 a s, we get a s = (v2 - u2)/2. Substituting,

W = m [(v2 - u2)/2] = (1/2) m v2 - (1/2) m u2 = K_final - K_initial = ΔK.

This result is the work–energy theorem: the net work done on a particle by all forces equals the change in its kinetic energy. In differential/integral form for a general (possibly variable) net force F,

dW = F · ds = d(1/2 m v2) and W_net = ∫ F · ds = ΔK.

Sign and interpretation:

  • Positive work (W > 0) increases kinetic energy (speed tends to increase).
  • Negative work (W < 0) decreases kinetic energy (speed tends to decrease).
  • If W = 0, kinetic energy is unchanged (e.g., force perpendicular to displacement).

Relation to conservation of mechanical energy: If the net work by non-conservative forces (like friction) is zero, the work done by conservative forces can be expressed as change in potential energy U with W_conservative = -ΔU. Then the work–energy theorem gives ΔK = -ΔU, or K + U = constant (mechanical energy conserved).

Applications: The theorem simplifies many problems because you can compute change in speed from work without solving the full force/acceleration differential equation. It is especially useful in braking, collisions (work-energy used with impulse-momentum), ramps, springs (elastic potential), and energy-transfer calculations.

Note: For extended bodies or rotating systems, there are analogous forms: translational KE = 1/2 M V_cm2, rotational KE = 1/2 I ω2, and work–energy relations include both translational and rotational kinetic energies.

📌 Examples
  • Car braking: Frictional force from brakes does negative work, reducing the car's kinetic energy; W_friction = &Delta;K = 1/2 m (v_final<sup>2</sup> - v_initial<sup>2</sup>).
  • Roller coaster: As the car descends, gravity does positive work increasing KE and reducing potential energy; at different heights KE + PE remains approximately constant if friction is negligible.
  • Bow and arrow: The archer does positive work on the string and arrow; elastic potential in the drawn bow converts to kinetic energy of the arrow (1/2 m v<sup>2</sup>).
  • Stopping distance: Using work–energy theorem, stopping distance s under constant braking force F is s = (1/2 m v<sup>2</sup>)/F.
  • Lifting an object then releasing: Work done by hand increases potential energy; when released, potential converts to kinetic as the object falls.
🧮 Formulas
  1. \[Work by constant force: W = F &middot\]
    \[s (if F and s are collinear).\]
  2. \[Work (general): W = integral F &middot\]
    \[ds (line integral along path).\]
  3. \[Kinetic energy: K = 1/2 m v<sup>2</sup> (SI unit: joule\]
    \[J).\]
  4. \[Work–energy theorem: W_net = &Delta\]
    \[K = K_final - K_initial = 1/2 m (v_f<sup>2</sup> - v_i<sup>2</sup>).\]
  5. \[Instantaneous form: dW = F &middot\]
    \[ds = d(1/2 m v<sup>2</sup>).\]
  6. \[Conservative force relation: W_conservative = -&Delta\]
    \[U => &Delta\]
    \[K + &Delta\]
    \[U = 0 (mechanical energy conserved).\]
7

Potential Energy

Fig 7 — Educational Diagram: Potential Energy

Fig 7 — Educational Diagram: Potential Energy

⚡ PHYSICAL LAW / FORMULA

Potential Energy

Key Point: Gravitational potential energy near Earth's surface: U = mgh (h = height above chosen zero).

Definition: Potential energy (PE) is the energy possessed by a body due to its position or configuration in a force field (usually a conservative force field). It is a scalar quantity measured in joules (J).

Physical idea: When a conservative force (for example gravity or an ideal spring force) can do work as an object changes position, we can associate a potential energy function U such that the work done by that force when moving the object between two points equals the decrease in U. In symbols, for a conservative force F, the change in potential energy when the system moves from A to B is ΔU = U(B) − U(A) = −W_cons(A→B).

Reference level: Only differences in potential energy have physical meaning. You choose a zero of potential energy (reference level) conveniently (e.g., ground, lowest point). Changing the reference shifts U by a constant but does not affect dynamics.

Relation to force: In one dimension, the conservative force is the negative spatial derivative of potential energy: F(x) = −dU/dx. In three dimensions, F = −∇U (the negative gradient). This relation tells how the shape of U(x) controls motion: the force pushes objects toward lower U.

Energy conservation: In the absence of non-conservative forces, mechanical energy is conserved: E = K + U = constant, where K is kinetic energy. As U increases, K decreases and vice versa.

Equilibrium and stability: Points where dU/dx = 0 are equilibrium points. If U has a local minimum there, the equilibrium is stable (small displacements produce restoring forces); if U has a local maximum, the equilibrium is unstable. Near a stable minimum U(x) ≈ U0 + (1/2)k(x−x0)^2, giving simple harmonic motion with effective spring constant k = U''(x0).

📌 Examples
  • A book lifted to a shelf: gravitational potential energy increases by mgh relative to the floor.
  • A pendulum at its highest point: maximum gravitational potential energy and zero kinetic energy.
  • A stretched spring (bow or toy launcher): elastic potential energy stored = 1/2 k x^2.
  • Water stored behind a dam: gravitational potential energy used to generate electricity.
  • A roller coaster at the top of a hill: high potential energy converts to kinetic energy as it descends.
🧮 Formulas
  1. \[Gravitational potential energy near Earth's surface: U = mgh (h = height above chosen zero).\]
  2. \[Gravitational potential energy for point masses: U(r) = −G M m / r (zero at r → ∞).\]
  3. \[Elastic (spring) potential energy: U = (1/2) k x^2 (x = displacement from natural length).\]
  4. \[Change in potential energy and conservative work: ΔU = −W_cons.\]
  5. \[Force from potential (1D): F(x) = −dU/dx. (Vector form: F = −∇U.)\]
  6. \[Mechanical energy conservation: E = K + U = constant (if no non-conservative work).\]
💪8

Conservative and Non-conservative Forces

Fig 8.1 — Educational Diagram: Newton

Fig 8.1 — Educational Diagram: Newton's Laws of Motion & Free Body Diagrams

⚡ PHYSICAL LAW / FORMULA

Conservative and Non-conservative Forces

Key Point: Work along a path: W_{A→B} = ∫_A^B F · dr

Definition: A force is conservative if the work it does on a particle moving between two points is independent of the path taken. Equivalently, the work done by a conservative force around any closed path is zero. A force is non-conservative if the work depends on the path and the work done around a closed path is not zero.

Key properties of conservative forces

  • Path independence: W(A→B) is the same for all paths joining A and B.
  • Zero work over a closed loop: ∫_closed F·dr = 0.
  • Existence of potential energy V(r): F = −∇V (so W(A→B) = V(A) − V(B)).
  • Mathematical condition (in a simply connected region): curl F = 0 (∇ × F = 0).

Key properties of non-conservative forces

  • Path dependent: W(A→B) depends on the path taken between A and B.
  • Nonzero work over closed loop: ∫_closed F·dr ≠ 0 (it often removes mechanical energy).
  • No single-valued potential energy function exists for the force.
  • Typically dissipative: converts mechanical energy into thermal/internal energy (friction, air drag).

Energy viewpoint

  • For conservative forces, mechanical energy (kinetic + potential) is conserved: E_mech = K + V = constant (if only conservative forces act).
  • If non-conservative forces do work W_nc, the change in mechanical energy equals that work: ΔE_mech = W_nc (usually negative for dissipative forces).

Simple examples (conceptual): Gravity, electrostatic force and ideal spring force are conservative. Friction, air resistance and viscous damping are non-conservative.

📌 Examples
  • Gravitational force (near Earth's surface): conservative. Potential energy V = mgh. Work from height h1 to h2 by gravity: W = mg(h1 − h2).
  • Elastic (spring) force: F = −kx, conservative. Potential energy V = 1/2 k x^2. Work by spring from x1 to x2: W = 1/2 k (x1^2 − x2^2).
  • Electrostatic (Coulomb) force: conservative. Has scalar potential; work depends only on endpoints.
  • Kinetic friction: non-conservative. Work done over displacement d: W_friction = −f_k d = −μ_k N d (energy dissipated as heat; depends on path length).
  • Air resistance (drag): non-conservative. Work depends on trajectory and speed; dissipates mechanical energy into heat.
🧮 Formulas
  1. \[Work along a path: W_{A→B} = ∫_A^B F · dr\]
  2. \[Closed-loop (conservative): ∮_closed F · dr = 0\]
  3. \[Potential relation (conservative): F = −∇V and W_{A→B} = V(A) − V(B)\]
  4. \[Condition for conservative field (simply connected): ∇ × F = 0\]
  5. \[Spring (Hooke): F = −kx\]
    \[V(x) = 1/2 k x^2\]
    \[W_{x1→x2} = 1/2 k (x1^2 − x2^2)\]
  6. \[Gravity near Earth: V = mgh\]
    \[Work by gravity from y1 to y2: W = mg(y1 − y2)\]
9

Conservation of Mechanical Energy

Fig 9 — Educational Diagram: Conservation of Mechanical Energy

Fig 9 — Educational Diagram: Conservation of Mechanical Energy

⚡ PHYSICAL LAW / FORMULA

Conservation of Mechanical Energy

Key Point: Total mechanical energy: E_mech = K + U = constant (when only conservative forces act)

Definition: The law of conservation of mechanical energy states that for a system on which only conservative forces (like gravity or ideal spring forces) act, the total mechanical energy — the sum of kinetic energy (K) and potential energy (U) — remains constant.

Why it holds: From the work–energy theorem, the net work done on a particle equals the change in its kinetic energy: W_net = ΔK. If the only forces are conservative, the work done by those forces can be expressed as minus the change in potential energy: W_cons = -ΔU. Hence ΔK = -ΔU, or Δ(K + U) = 0, so K + U = constant.

Derivation (single particle, conservative forces only):

  • Work–energy theorem: W_net = ΔK.
  • For conservative forces: W_cons = -ΔU.
  • Thus ΔK = -ΔU → Δ(K + U) = 0 → K + U = constant.

Interpretation: Mechanical energy is continuously exchanged between kinetic and potential forms. At an instant where potential energy is maximum, kinetic energy is minimum (and vice versa), but their sum stays fixed. The reference zero for potential energy is arbitrary — only differences in U matter.

When it fails or is modified: If non-conservative forces (friction, air resistance, inelastic deformation) do work, mechanical energy is not conserved; some mechanical energy is transformed into thermal energy or other forms. General relation: ΔE_mech = W_nc, or E_mech_final = E_mech_initial + W_nc (W_nc is typically negative for dissipative forces).

Common potential energies: Near Earth's surface: U_g = mgh. For an ideal spring: U_s = (1/2) k x^2. Kinetic energy: K = (1/2) m v^2.

📌 Examples
  • Simple pendulum (small angle): gravitational potential energy converts to kinetic energy and back; total mechanical energy constant (neglecting air resistance and friction at pivot).
  • Free fall: as a mass falls, U_g = mgh decreases and K = 1/2 mv^2 increases so that 1/2 mv^2 + mgh = constant. Leads to v^2 = v0^2 + 2g(h0 - h).
  • Roller coaster (idealized): a car at top with high potential energy speeds up as it descends, converting U to K; energy determines maximum possible heights (neglecting friction).
  • Mass on an ideal spring (SHM): spring potential (1/2 k x^2) converts to kinetic and back; total E = (1/2) k A^2 constant, where A is amplitude.
  • Bungee jump (approximate): gravitational potential converts to kinetic and then to spring potential of the cord; energy considerations estimate max extension (accounting for energy lost if cord is not ideal).
  • Block sliding on a rough incline (non-conservative present): mechanical energy decreases by amount of work done by friction; E_final = E_initial + W_friction.
🧮 Formulas
  1. \[Total mechanical energy: E_mech = K + U = constant (when only conservative forces act)\]
  2. \[Kinetic energy: K = (1/2) m v^2\]
  3. \[Gravitational potential (near Earth): U_g = m g h\]
  4. \[Spring potential: U_s = (1/2) k x^2\]
  5. \[Work by conservative force: W_cons = -ΔU\]
  6. \[Work–energy with non-conservative forces: ΔK = W_cons + W_nc ⇒ Δ(K+U) = W_nc ⇒ E_mech_final = E_mech_initial + W_nc\]
🔋10

Power

Fig 10 — Educational Diagram: Power

Fig 10 — Educational Diagram: Power

⚡ PHYSICAL LAW / FORMULA

Power

Key Point: Average power: P_avg = W / Δt

Definition: Power is the rate at which work is done or energy is transferred. It quantifies how quickly energy is converted from one form to another.

Average and Instantaneous Power:

  • Average power over a time interval Δt: P_avg = W / Δt, where W is work done in time Δt.
  • Instantaneous power is the limit as Δt → 0: P = dW/dt.

Mechanical expression (translational): If a force F acts on a particle moving with instantaneous velocity v, the instantaneous power delivered by the force is P = F · v = F v cosθ, where θ is the angle between F and v. This follows because dW = F · ds and v = ds/dt, so P = dW/dt = F · v.

Relation to kinetic energy: For a particle of mass m, the rate of change of kinetic energy equals the net power input: d/dt(1/2 m v^2) = m v a = F_net · v = P_net. This ties power to how fast the kinetic energy changes.

Rotational analogue: For rotation, torque τ and angular speed ω give power: P = τ ω. If a set of forces produces a torque τ and the body rotates with angular speed ω, the power transferred is τ times ω.

Sign convention: If force has a component opposite to velocity, P is negative (work done by the object on the agent). Positive P means the force does work on the object.

Units: SI unit of power is the watt (W): 1 W = 1 J/s. Common unit: horsepower (hp), 1 hp ≈ 746 W.

Useful notes:

  • For constant force along the displacement direction and constant speed v: P = F v.
  • Electrical expressions often used: P = V I = I^2 R = V^2 / R.
  • Mechanical power rating (e.g., motors) gives the maximum useful energy transfer per unit time; efficiency = (useful power out)/(power in).

Typical classroom derivations/problems: Show that a person lifting a mass m at constant speed v requires power P = mg v. Show that for a car with constant engine power P, the acceleration decreases as v increases because d/dt(1/2 m v^2) = P gives v dv/dt = P/m.

📌 Examples
  • Lifting a bucket: A person lifts a 10 kg bucket at constant speed 0.5 m/s. Power needed = P = m g v = 10 * 9.8 * 0.5 = 49 W.
  • Electric bulb: A 60 W bulb converts electrical energy into light and heat at a rate of 60 joules per second.
  • Car engine: If an engine delivers 50 kW and the car moves at 20 m/s, the force available for motion (ignoring losses) is F = P/v = 50000 / 20 = 2500 N.
  • Rotational power: An electric drill delivers torque τ = 2 N·m at angular speed ω = 100 rad/s. Power = τ ω = 200 W.
  • Braking: When brakes do negative work on a moving bicycle, the power associated with the braking force is negative, equal to the rate of kinetic energy loss.
🧮 Formulas
  1. \[Average power: P_avg = W / Δt\]
  2. \[Instantaneous power: P = dW/dt\]
  3. \[Mechanical (force and velocity): P = F · v = F v cosθ\]
  4. \[Relation to kinetic energy: P_net = d/dt(1/2 m v^2) = F_net · v\]
  5. \[Rotational power: P = τ ω (torque × angular speed)\]
  6. \[Electrical: P = V I = I^2 R = V^2 / R\]
⚙️11

Work in Two and Three Dimensions

Fig 11 — Educational Diagram: Work in Two and Three Dimensions

Fig 11 — Educational Diagram: Work in Two and Three Dimensions

⚡ PHYSICAL LAW / FORMULA

Work in Two and Three Dimensions

Key Point: W = F · Δr = |F| |Δr| cosθ

Basic idea: Work measures the energy transfer when a force acts through a displacement. In two or three dimensions both force and displacement are vectors, and only the component of force along the displacement does work. Work is a scalar quantity; SI unit: joule (J).

Vector (dot) product definition: If a constant force F acts while an object undergoes a displacement Δr, the work done is the dot product

W = F · Δr = |F| |Δr| cos θ

where θ is the angle between the force vector and the displacement vector. In component form (3D):

W = FxΔx + FyΔy + FzΔz

Work by a variable force (general path): If the force varies in space or the object moves along a curved path, work is given by the line integral of the force along the path C:

W = ∫C F · d r

Interpretation: break the path into infinitesimal displacements d r = (dx, dy, dz); the infinitesimal work is dW = F · d r and total work is the integral of dW along the path.

Conservative vs non-conservative forces: For conservative forces (e.g., gravity, ideal spring), work depends only on the initial and final positions, not on the path. For gravity near Earth (taking +y upward): Wgravity = -m g Δy (work done by the gravitational force on the object). For non-conservative forces (e.g., kinetic friction), work depends on the path and usually converts mechanical energy into heat.

Key practical points:

  • When the force is perpendicular to displacement, W = 0 (e.g., centripetal force acting perpendicular to instantaneous displacement).
  • If you carry an object horizontally at constant height, the vertical force you apply does no net work on the object (displacement vertical = 0); only horizontal components matter.
  • Work can be split: if multiple forces act, total work = sum of works by each force (work is additive).

Short worked idea (2D): A force F of magnitude 50 N acts at 30° above the horizontal and displaces an object by 4 m horizontally. Take displacement vector = (4,0). The work is W = F cos30° × 4 = 50 × (√3/2) × 4 ≈ 173.2 J.

Why use components: In 2D/3D problems it is often easiest to resolve F into components and use W = FxΔx + FyΔy (+ FzΔz in 3D). For curved motion, parametrize the path (x(t),y(t),z(t)) and compute W = ∫ (Fx dx + Fy dy + Fz dz).

Summary: Work in 2D and 3D is computed using the scalar (dot) product of force and displacement. For variable forces or curved paths use the line integral. Distinguish conservative forces (path-independent) from non-conservative ones (path-dependent).

📌 Examples
  • Pushing a crate: A constant force of 80 N acts at 20° above horizontal on a crate that moves 6 m horizontally. Work = F cos20° × 6 ≈ 80 × 0.9397 × 6 ≈ 451 J.
  • Carrying a suitcase: You carry a suitcase horizontally at constant height. Although you apply an upward force to balance weight, the displacement has no vertical component so the work done by your upward force on the suitcase is zero; only horizontal forces (if any) do work.
  • Object along a curved path: A particle moves along a semicircular path r(t). To find work by a force F(x,y), parametrize the path r(θ) and compute W = ∫ F · dr = ∫ (F_x dx + F_y dy) over θ. Example: gravity does same work as a straight drop equal to m g times vertical drop, independent of the curved path.
  • Inclined plane with constant push: A person pushes a box up a slope of height h along a path length s with force parallel to slope F. Work against gravity = m g h (path-independent). Work by push = F × s cos(0) = F s (if force is along slope).
🧮 Formulas
  1. \[W = F · Δr = |F| |Δr| cosθ\]
  2. \[Component form (3D): W = F_x Δx + F_y Δy + F_z Δz\]
  3. \[Variable force / curved path: W = ∫_C F · dr = ∫_C (F_x dx + F_y dy + F_z dz)\]
  4. \[Work done by gravity (near Earth): W_gravity = -m g Δy (taking upward as +y) or W = m g (y_initial - y_final)\]
  5. \[Work done by spring (conservative): W_spring = -½ k (x_f^2 - x_i^2)\]
  6. \[Property of conservative forces: ∮_closed F · dr = 0\]
📈12

Graphical Interpretation and Problem Solving Techniques

Fig 12 — Educational Diagram: Graphical Interpretation and Problem Solving Techniques

Fig 12 — Educational Diagram: Graphical Interpretation and Problem Solving Techniques

⚡ PHYSICAL LAW / FORMULA

Graphical Interpretation and Problem Solving Techniques

Key Point: Work by a variable force: W = ∫(x1 to x2) F(x) dx

Overview: Graphical interpretation links physical quantities to geometric features (area under curve, slope) so you can read work, energy and power directly from plots. In the Work–Energy chapter the most useful graphs are Force vs displacement (F–x), Potential energy vs displacement (U–x), Power vs time (P–t) and Kinetic/Energy vs time graphs. Understanding which geometric property (area, slope, intercept) corresponds to which physical quantity is the key.

What to read from common graphs:

  • F vs x (force vs displacement): Area under the curve between x1 and x2 gives work done by that force: W = ∫(x1 to x2) F(x) dx. For a constant force F, W = FΔx. For variable force, calculate area (geometric shapes or integral).
  • U vs x (potential energy vs displacement): Slope gives force with sign: F(x) = -dU/dx. Minima of U correspond to stable equilibrium; difference U(x2) − U(x1) is change in potential energy.
  • P vs t (power vs time): Area under the P–t curve from t1 to t2 equals energy delivered or consumed: ΔE = ∫(t1 to t2) P(t) dt.
  • K vs x or K vs t: Changes in kinetic energy shown on the graph connect to work by the work–energy theorem: ΔK = W_net.

Sign conventions and interpretation: Positive area means force has a component along displacement direction (work done by the force on the object); negative area means the force opposes motion (work done by the object on the force). For U–x, if dU/dx > 0 then the force is negative (opposes increasing x).

Problem‑solving techniques (stepwise):

  1. Identify which graph you have and what quantity you need (work, change in potential, energy delivered, force at a point).
  2. Decide whether the required operation is area under curve (integral) or slope of curve (derivative).
  3. If area is needed, split the region into simple geometric shapes (rectangles, triangles, trapezoids) or set up an integral when the curve is given analytically.
  4. Keep track of signs: work by a force along +x is positive; if displacement is opposite the force, area is negative.
  5. Use the work–energy theorem (W_net = ΔK) or energy conservation (K + U = constant) as shortcuts when multiple forces are present.
  6. Check units (N·m = J for work/energy; W·s = J for power-time areas; N = J/m for slope of U–x if inverted sign).
  7. For numerical graphs, approximate a curve by small trapezoids (trapezoidal rule) if no analytic form is given.

Common pitfalls: confusing area under F–t (impulse) with F–x (work); forgetting negative sign when using U–x; mixing up which axis corresponds to integration variable.

📌 Examples
  • Lifting a box: A 5 kg box is lifted vertically 2 m at constant speed. Graph: constant force F=mg vs displacement x from 0 to 2 m. Work = F·Δx = mg(2) = 5×9.8×2 = 98 J.
  • Compressing a spring: Spring constant k=200 N/m compressed by x=0.1 m. Graph: F vs x is a straight line (F=kx). Area under the line from 0 to 0.1 m is a triangle: W = 1/2 k x^2 = 0.5×200×0.01 = 1 J (work stored as elastic potential energy).
  • Variable force triangular region: A horizontal force varies linearly from 0 to 30 N while displacement increases from 0 to 3 m. Graph: triangle under F–x. Work = (1/2)×base×height = 0.5×3×30 = 45 J.
  • Engine power over time: A motor supplies power P(t) = 100 + 50t (W) for t from 0 to 4 s. Graph: P–t is a line; energy delivered = area = ∫0^4 (100+50t) dt = [100t + 25t^2]0^4 = 400 + 400 = 800 J.
  • Potential energy curve and equilibrium: A mass on a spring has U(x) = 1/2 k x^2. Graph U–x is a parabola; slope dU/dx = kx, so force F = -kx. The minimum (x=0) is stable equilibrium.
🧮 Formulas
  1. \[Work by a variable force: W = ∫(x1 to x2) F(x) dx\]
  2. \[Work by constant force: W = F·Δx (when F is along displacement)\]
  3. \[Work–energy theorem: W_net = ΔK = K_final − K_initial\]
  4. \[Power (instantaneous): P = dW/dt = F·v\]
  5. \[Energy from power vs time: ΔE = ∫(t1 to t2) P(t) dt\]
  6. \[Potential energy relation: F(x) = -dU/dx\]
13

Potential Energy Curves and Equilibrium

Fig 13 — Educational Diagram: Potential Energy Curves and Equilibrium

Fig 13 — Educational Diagram: Potential Energy Curves and Equilibrium

⚡ PHYSICAL LAW / FORMULA

Potential Energy Curves and Equilibrium

Key Point: Force from potential: F(x) = - dU/dx

What is a potential energy curve? A potential energy curve U(x) is a graph of the potential energy of a system as a function of a generalized coordinate x (position). For systems with conservative forces, the force is determined by the slope of this curve: F(x) = -dU/dx. The system's motion and equilibrium positions are understood from the shape of U(x).

Equilibrium points

  • An equilibrium point x0 satisfies dU/dx|_{x=x0} = 0 (horizontal tangent on the U vs x curve).
  • Stability criteria (using second derivative):
    • Stable equilibrium: d^2U/dx^2|_{x0} > 0. U(x) has a local minimum; small displacements produce a restoring force back toward x0.
    • Unstable equilibrium: d^2U/dx^2|_{x0} < 0. U(x) has a local maximum; small displacements grow away from x0.
    • Neutral (marginal) equilibrium: d^2U/dx^2|_{x0} = 0 (higher derivatives decide behavior); U is flat near x0.

Small oscillations about a stable equilibrium

Near a stable minimum x0 expand U(x) in a Taylor series: U(x) ≈ U(x0) + 1/2 U''(x0) (x - x0)^2. The system behaves like a simple harmonic oscillator with effective spring constant k = U''(x0). For a mass m, angular frequency ω = sqrt(k/m) and period T = 2π sqrt(m/k).

Energy viewpoint and turning points

For a conservative system with total energy E = K + U(x), motion is allowed only where U(x) ≤ E. Points where U(x) = E are turning points (kinetic energy zero). Plotting a horizontal line E on the U(x) graph visually shows accessible regions.

Physical interpretation of force

The force at each x is opposite the slope of U(x): if U increases with x (dU/dx > 0) the force is negative (pulls left); if U decreases with x (dU/dx < 0) the force is positive (pushes right).

📌 Examples
  • Mass on a spring: U(x) = 1/2 k x^2. Minimum at x = 0 (stable). Small oscillations give ω = sqrt(k/m).
  • Ball in a bowl: U(x) has a local minimum at the bottom — stable equilibrium; displace slightly and the ball oscillates.
  • Ball on top of a hill: U(x) has a local maximum — unstable equilibrium; any small perturbation makes it roll away.
  • Pendulum (small angles): effective potential near lowest point is approximately quadratic → small oscillations with ω ≈ sqrt(g/L).
  • Double-well potential (e.g., two stable positions separated by a barrier): shows two minima (stable) and a maximum (unstable) between them; used as a model in chemistry and physics for bistable systems.
🧮 Formulas
  1. \[Force from potential: F(x) = - dU/dx\]
  2. \[Equilibrium condition: dU/dx = 0\]
  3. \[Stability test: stable if d^2U/dx^2 > 0\]
    \[unstable if d^2U/dx^2 < 0\]
    \[neutral if d^2U/dx^2 = 0\]
  4. \[Taylor approx. near minimum x0: U(x) ≈ U(x0) + (1/2) U''(x0) (x - x0)^2\]
  5. \[Effective spring constant: k = U''(x0)\]
  6. \[Angular frequency for small oscillations: ω = sqrt(k/m) = sqrt(U''(x0)/m)\]
💪14

System of Particles and Internal Forces

Fig 14.1 — Educational Diagram: Newton

Fig 14.1 — Educational Diagram: Newton's Laws of Motion & Free Body Diagrams

⚡ PHYSICAL LAW / FORMULA

System of Particles and Internal Forces

Key Point: Total mass: M = Σ_i m_i

What is a system of particles? A system of particles is a collection of many particles (or bodies) considered together. Each particle i has mass m_i, position r_i(t) and velocity v_i(t). We study the motion of the whole system through quantities like total mass, total momentum and centre of mass (CM).

Centre of mass (CM): The position vector of CM is

R = (1/M) Σ m_i r_i,    where M = Σ m_i
Velocity and acceleration of CM:
V = dR/dt = (1/M) Σ m_i v_i
a_CM = dV/dt
The total linear momentum of the system is P = M V = Σ m_i v_i.

Internal and external forces: Each particle experiences forces. Forces due to agents outside the system are external forces (F_ext). Forces between particles of the system are internal forces (F_ij is force on i due to j). By Newton's 3rd law for pairwise interactions, F_ij = −F_ji (for equal and opposite forces along the line joining particles).

Equation of motion for the CM: Summing Newton's second law for all particles gives

M a_CM = Σ F_ext + Σ Σ F_ij.
Because Σ_i Σ_j F_ij = 0 (internal forces cancel in pairs), we get the important result
M a_CM = Σ F_ext.
Thus the net external force determines the acceleration of the CM; internal forces cannot change the motion of the CM. If Σ F_ext = 0, the total momentum P is conserved.

Kinetic energy: decomposition: The total kinetic energy of the system can be split into kinetic energy of the CM motion and kinetic energy relative to the CM:

K_total = Σ (1/2 m_i v_i^2) = (1/2) M V^2 + Σ (1/2 m_i u_i^2)
where u_i = v_i − V is the velocity of particle i relative to the CM. The first term is the kinetic energy of the whole system moving as if all mass were at the CM; the second is internal (or relative) kinetic energy.

Work–energy for a system: Multiplying each particle's equation of motion by its velocity and summing yields the rate form of work–energy theorem. In integrated form:

ΔK_total = W_ext + W_int.
Internal forces can do work that changes relative kinetic energy or can be associated with changes in internal potential energy. If internal forces are conservative (so we can define internal potential energy U_int), then
Δ(K_total + U_int) = W_ext.
So when only conservative internal forces act and external work is zero, mechanical energy (K_total + U_int) is conserved.

Consequences and typical behaviors:

  • Momentum conservation: If resultant external force = 0, total momentum P is constant.
  • Internal forces cannot change motion of CM, but they can redistribute energy among particles and convert kinetic energy to internal energy (e.g., heating during inelastic collisions).
  • For constant mass systems, motion of CM is governed solely by external forces; for variable-mass systems (rockets, raindrops collecting mass) additional terms appear—treat separately.

Summary: The key ideas are (1) define CM and total momentum, (2) internal forces cancel in the net force so CM motion is controlled only by external forces, (3) total kinetic energy splits into CM motion and internal motion, and (4) internal forces may change internal/relative energy but not the CM momentum; for conservative internal forces total mechanical energy plus potential is conserved when no external work is done.

📌 Examples
  • Two ice-skaters push off each other on frictionless ice: they move in opposite directions. No external horizontal force ⇒ total momentum conserved. Internal forces give them opposite momenta.
  • Recoil of a gun: explosion generates internal forces between bullet and gun; centre of mass of gun+bullet system moves according to external forces (often negligible), so recoil velocity ensures momentum conservation.
  • Billiard-ball collision: internal contact forces change individual kinetic energies; in elastic collision internal forces are conservative → total kinetic energy conserved; inelastic collision converts some kinetic energy into internal energy (heat/sound).
  • Explosion or firecracker: chemical internal energy converts into kinetic energy of fragments; if no external impulse, centre of mass of fragments continues original motion and total momentum is conserved.
  • Earth–Moon mutual attraction: gravitational forces are internal to the Earth–Moon system and act in pairs; CM of Earth+Moon moves under external forces (very small), while each body orbits their common CM.
🧮 Formulas
  1. \[Total mass: M = Σ_i m_i\]
  2. \[Centre of mass: R = (1/M) Σ_i m_i r_i\]
  3. \[CM velocity: V = dR/dt = (1/M) Σ_i m_i v_i\]
  4. \[Total momentum: P = Σ_i m_i v_i = M V\]
  5. \[Equation of motion for CM: M a_CM = Σ_i F_ext,i\]
  6. \[Kinetic energy decomposition: K_total = Σ (1/2 m_i v_i^2) = (1/2) M V^2 + Σ (1/2 m_i u_i^2)\]
    \[where u_i = v_i − V\]
🔬15

Units, Dimensions and Important Formulas

Fig 15 — Educational Diagram: Units, Dimensions and Important Formulas

Fig 15 — Educational Diagram: Units, Dimensions and Important Formulas

⚡ PHYSICAL LAW / FORMULA

Units, Dimensions and Important Formulas

Key Point: Work by constant force: W = F s cosθ (Unit: J; Dimension: [M L^2 T^−2])

Overview
This topic covers the SI units and dimensional formulas of physical quantities related to work, energy and power, how to use dimensional analysis to check equations, and the important formulas used in these concepts.

SI units and fundamental idea
The SI base units relevant here are: mass (kg), length (m) and time (s). Derived units used often in this chapter are:
1 J (joule) = 1 N·m = 1 kg·m2·s−2 (unit of work and energy)
1 W (watt) = 1 J·s−1 = 1 kg·m2·s−3 (unit of power)

Dimensions and dimensional formula
A dimensional formula expresses a quantity in terms of base dimensions M (mass), L (length), T (time). Dimensional homogeneity: both sides of any physically correct equation must have the same dimensions.

Common dimensional formulas (useful in this chapter)

  • Displacement, x: [L]
  • Velocity, v: [L T−1]
  • Acceleration, a: [L T−2]
  • Force, F: [M L T−2]
  • Work / Energy, W or E: [M L2 T−2]
  • Power, P: [M L2 T−3]
  • Momentum, p: [M L T−1]
  • Spring constant, k: [M T−2]

Dimensional analysis – uses and limitations
Uses: check correctness of derived equations, find form of a relation up to a dimensionless constant, identify possible dependent variables. Limitations: cannot determine dimensionless constants (like 1/2), cannot distinguish quantities with same dimensions (e.g., energy and torque), and cannot give numerical coefficients or functional forms with transcendental functions.

Important conceptual points

  • Work is scalar: W = F·s·cosθ (dot product of force and displacement).
  • Positive work adds energy to a body; negative work removes energy.
  • Work done by a variable force is the area under the force–displacement curve: W = ∫ F(x) dx.
  • Work–energy theorem: net work done on a particle = change in its kinetic energy, W_net = ΔK.
  • Mechanical energy (K + U) is conserved if only conservative forces act (no non‑conservative work like friction).
  • Power measures rate of doing work: instantaneous P = dW/dt = F·v.

📌 Examples
  • Lifting a 5 kg box by 2 m: Work = m g h = 5 × 9.8 × 2 = 98 J (energy transferred to gravitational potential).
  • Car braking: a car of mass 1000 kg with speed 20 m/s has kinetic energy 1/2 m v^2 = 0.5 × 1000 × 20^2 = 200,000 J — this energy is dissipated as heat by brakes.
  • Compressing a spring by 0.1 m with k = 200 N/m: Elastic PE = 1/2 k x^2 = 0.5 × 200 × 0.1^2 = 1 J.
  • Electric bulb rated 60 W running for 2 hours uses energy 60 × 2 = 120 Wh = 4.32 × 10^5 J.
  • Work by variable force: if F(x) = 10x N from x = 0 to x = 3 m, W = ∫0^3 10x dx = 10 × (1/2) × 3^2 = 45 J.
🧮 Formulas
  1. \[Work by constant force: W = F s cosθ (Unit: J\]
    \[Dimension: [M L^2 T^−2])\]
  2. \[Work by variable force: W = ∫_{x1}^{x2} F(x) dx\]
  3. \[Work–energy theorem: W_net = ΔK = (1/2) m v_f^2 − (1/2) m v_i^2\]
  4. \[Kinetic energy (translational): K = (1/2) m v^2\]
  5. \[Gravitational potential (near Earth): U_g = m g h\]
  6. \[Elastic potential (spring): U_s = (1/2) k x^2\]

Key Concepts

Work
Scalar quantity equal to the component of force along displacement times the displacement: W = F·s = Fs cosθ. Positive when force has component along displacement.
Work done by a constant force
When force is constant, work is W = F·Δr = FΔr cosθ (area under force–displacement graph is a rectangle).
Work done by a variable force
Work equals the integral of the force along the path: W = ∫_i^f F·dr (line integral for vector force).
Joule (unit of work and energy)
SI unit of work and energy. 1 J = 1 N·m = 1 kg·m^2·s^-2.
Kinetic energy
Energy of motion of a body: K = 1/2 mv^2, where m is mass and v is speed.
Work–energy theorem
Net work done on a particle equals the change in its kinetic energy: W_net = ΔK = K_f − K_i.
Power
Rate at which work is done or energy is transferred: P = dW/dt. SI unit is watt (W) = J/s.
Average power
Total work done divided by total time interval: P_avg = ΔW/Δt.
Instantaneous power
Power at an instant; for a particle P = F·v (force dot velocity) where F is net force and v is velocity.
Potential energy
Energy associated with position or configuration due to a conservative force. For 1D, F = -dU/dx.
Gravitational potential energy (near Earth)
Near Earth's surface U = mgh, where h is height above reference; change ΔU = mgΔh.
Elastic potential energy
Energy stored in a spring stretched or compressed by x: U = 1/2 k x^2 for an ideal Hookean spring.
Conservative force
Force for which work is path-independent and work around any closed loop is zero; a potential energy function exists.
Non-conservative force
Force for which work depends on the path; it converts mechanical energy into other forms (e.g., heat).
Mechanical energy
Sum of kinetic and potential energies of a system: E_mech = K + U.
Work done by gravity
For near-Earth gravity, W_g = mg (vertical displacement) = −ΔU (sign depends on chosen reference).
Work done by friction
Friction does negative work (opposes motion): W_f = −∫ f_fric · dr; it reduces mechanical energy into heat.
Hooke's law (spring force)
Restoring force of an ideal spring: F = −k x. Work done by spring between x1 and x2 is W_spring = 1/2 k (x1^2 − x2^2).
Potential energy function
Function U(r) whose negative gradient gives the conservative force: F = −∇U; differences in U give work by/from the force.
Law of conservation of mechanical energy
If only conservative forces do work, total mechanical energy E = K + U remains constant: ΔE = 0.

Practice Questions

  1. Define work and state the conditions under which work done by a force is zero. / कार्य को परिभाषित कीजिए तथा वे शर्तें बताइए जिनके अंतर्गत किसी बल द्वारा किया गया कार्य शून्य होता है।
    Show answer

    Work W = F·s = Fs cosθ is the product of the force component along displacement and the displacement magnitude; it is zero when F = 0, when s = 0, or when the force is perpendicular to displacement (θ = 90°), e.g. centripetal force in circular motion. / कार्य W = F·s = Fs cosθ विस्थापन की दिशा में बल घटक तथा विस्थापन परिमाण का गुणनफल है; यह शून्य होता है जब F = 0, या s = 0, या बल विस्थापन के लंबवत हो (θ = 90°), जैसे वृत्तीय गति में अभिकेंद्र बल।

  2. State and prove the work-energy theorem for a particle. / किसी कण के लिए कार्य-ऊर्जा प्रमेय लिखिए तथा सिद्ध कीजिए।
    Show answer

    The theorem states that net work done on a particle equals its change in kinetic energy: W_net = ΔK. For constant net force F = ma over displacement s, using v² = u² + 2as gives W = mas = m(v² − u²)/2 = (1/2)mv² − (1/2)mu² = ΔK. / प्रमेय कहती है कि किसी कण पर किया गया कुल कार्य उसकी गतिज ऊर्जा परिवर्तन के बराबर होता है: W_net = ΔK। अचर परिणामी बल F = ma के अंतर्गत विस्थापन s पर v² = u² + 2as का उपयोग करने पर W = mas = m(v² − u²)/2 = (1/2)mv² − (1/2)mu² = ΔK।

  3. Derive the expression for elastic potential energy stored in a spring stretched by x. / x तक खींची गई स्प्रिंग में संचित प्रत्यास्थ स्थितिज ऊर्जा का व्यंजक व्युत्पन्न कीजिए।
    Show answer

    The spring force is F = kx (restoring −kx); work done by an external agent to stretch quasi-statically from 0 to x is W = ∫₀ˣ kx' dx' = (1/2)kx², which is stored as elastic potential energy U = (1/2)kx². / स्प्रिंग बल F = kx है (प्रत्यानयन −kx); 0 से x तक मंद-स्थैतिक रूप से खींचने में बाह्य कारक द्वारा किया गया कार्य W = ∫₀ˣ kx' dx' = (1/2)kx² है, जो प्रत्यास्थ स्थितिज ऊर्जा U = (1/2)kx² के रूप में संचित होता है।

  4. Distinguish between conservative and non-conservative forces with one example each. / संरक्षी तथा असंरक्षी बलों में अंतर कीजिए, प्रत्येक का एक उदाहरण देते हुए।
    Show answer

    For a conservative force, work done is path-independent and zero over a closed loop, and a potential energy can be defined (e.g. gravity); for a non-conservative force, work depends on the path and is non-zero over a closed loop, dissipating mechanical energy (e.g. friction). / संरक्षी बल के लिए किया गया कार्य पथ से स्वतंत्र तथा बंद पाश पर शून्य होता है, एवं स्थितिज ऊर्जा परिभाषित की जा सकती है (जैसे गुरुत्व); असंरक्षी बल के लिए कार्य पथ पर निर्भर करता है तथा बंद पाश पर शून्य नहीं होता, यांत्रिक ऊर्जा का क्षय करता है (जैसे घर्षण)।

  5. A 2 kg block slides 5 m on a rough horizontal surface with μk = 0.2. Find the work done by friction. (g = 10 m/s²) / 2 kg का गुटका μk = 0.2 वाले खुरदरे क्षैतिज तल पर 5 m फिसलता है। घर्षण द्वारा किया गया कार्य ज्ञात कीजिए। (g = 10 m/s²)
    Show answer

    W_fric = −μk mg s = −0.2 × 2 × 10 × 5 = −20 J; this 20 J of mechanical energy is dissipated as heat. / W_fric = −μk mg s = −0.2 × 2 × 10 × 5 = −20 J; यह 20 J यांत्रिक ऊर्जा ऊष्मा के रूप में क्षयित हो जाती है।

  6. Using conservation of mechanical energy, find the speed of a body falling freely from rest through height h. / यांत्रिक ऊर्जा संरक्षण का उपयोग करके विरामावस्था से ऊँचाई h से स्वतंत्र रूप से गिरते पिंड की चाल ज्ञात कीजिए।
    Show answer

    With only gravity acting, K + U is constant: (1/2)mv² = mgh, so v = √(2gh). / केवल गुरुत्व कार्यरत होने पर K + U नियत रहता है: (1/2)mv² = mgh, अतः v = √(2gh)।

  7. Define instantaneous power and show that P = F·v. / तात्क्षणिक शक्ति को परिभाषित कीजिए तथा दर्शाइए कि P = F·v।
    Show answer

    Instantaneous power is the rate of doing work, P = dW/dt; since dW = F·ds and v = ds/dt, P = dW/dt = F·(ds/dt) = F·v = Fv cosθ. / तात्क्षणिक शक्ति कार्य करने की दर है, P = dW/dt; चूँकि dW = F·ds तथा v = ds/dt, अतः P = dW/dt = F·(ds/dt) = F·v = Fv cosθ।

  8. A motor lifts a 10 kg load at a constant speed of 0.5 m/s. Find the power required. (g = 9.8 m/s²) / एक मोटर 10 kg के भार को 0.5 m/s की अचर चाल से उठाती है। आवश्यक शक्ति ज्ञात कीजिए। (g = 9.8 m/s²)
    Show answer

    At constant speed the lifting force equals the weight, F = mg; so P = Fv = mgv = 10 × 9.8 × 0.5 = 49 W. / अचर चाल पर उठाने वाला बल भार के बराबर होता है, F = mg; अतः P = Fv = mgv = 10 × 9.8 × 0.5 = 49 W।

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