Overview
Introduction: Gravitation is the fundamental attractive force between all masses in the universe. This chapter covers Newton's Universal Law of Gravitation, Kepler's Laws of planetary motion, variation of acceleration due to gravity with altitude, depth, and latitude, gravitational potential and potential energy, escape speed, orbital speed, total energy of satellites, and geostationary vs. polar satellites.
Learning Objectives
- Understand Kepler's three laws of planetary motion and derive Kepler's third law from Newton's law of gravitation.
- State Newton's Universal Law of Gravitation and express it in vector form.
- Explain the significance of the universal gravitational constant G and acceleration due to gravity g.
- Derive the variation of acceleration due to gravity with height (h) above and depth (d) below Earth's surface.
- Define gravitational field, gravitational potential, and gravitational potential energy.
- Derive expressions for escape velocity from Earth's surface and orbital velocity of a satellite.
- Calculate total energy, kinetic energy, and potential energy of an orbiting satellite and understand binding energy.
- Distinguish between geostationary and polar satellites and state their applications.
Topics in this chapter
5 topics · tap a topic title to jump straight to it.
Kepler's Laws of Planetary Motion
Fig 1 — Educational Diagram: Kepler's Laws of Planetary Motion
Kepler's Laws of Planetary Motion
Key Point: Third Law (Law of Periods): T² ∝ a³ where T is the orbital period and a is the semi-major axis.
Johannes Kepler formulated three empirical laws describing planetary motion around the Sun based on Tycho Brahe's observations:
- First Law (Law of Orbits): All planets move in elliptical orbits with the Sun located at one of the two foci of the ellipse.
- Second Law (Law of Areas): The line joining any planet to the Sun sweeps out equal areas in equal intervals of time. This is a direct consequence of the conservation of angular momentum under a central force field (dA/dt = L / (2m) = constant).
- Third Law (Law of Periods): The square of the time period of revolution (T) of a planet is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit: T² ∝ a³ or T² / a³ = constant.
- Earth revolves around the Sun in an elliptical orbit with semi-major axis ≈ 1 AU in 1 year.
- Planets closer to the Sun (like Mercury) have much shorter orbital periods than distant planets (like Neptune).
- A planet moves fastest at perihelion (closest to Sun) and slowest at aphelion (farthest from Sun) due to Kepler's second law.
- \[Law of Areas: dA/dt = L / (2m) = constant\]
- \[Law of Periods: T² = (4π² / (G M_s)) a³\]
Universal Law of Gravitation & Gravitational Constant
Fig 2 — Educational Diagram: Universal Law of Gravitation & Gravitational Constant
Universal Law of Gravitation
Key Point: F = G (m₁ m₂) / r², where G = 6.674 × 10⁻¹¹ N m² kg⁻².
Newton's Law of Universal Gravitation: Every particle in the universe attracts every other particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Vector formulation: F₁₂ = - G (m₁ m₂ / r²) r̂₁₂. The force is always attractive, acts along the line joining the centers of the masses, and obeys Newton's third law (F₁₂ = - F₂₁).
Universal Gravitational Constant (G): G is a fundamental physical constant measured by Henry Cavendish using a torsion balance. G = 6.67430 × 10⁻¹¹ N m² kg⁻² (SI units) with dimensions [M⁻¹ L³ T⁻²].
- Gravitational attraction between two 1 kg masses separated by 1 meter is 6.67 × 10⁻¹¹ N.
- Gravitational force exerted by Earth (mass 5.97 × 10²⁴ kg) on an 80 kg person on the surface is ~784 N.
- \[F = G (m₁ m₂) / r²\]
- \[Vector form: F₁₂ = - (G m₁ m₂ / r²) r̂₁₂\]
- \[G = 6.674 × 10⁻¹¹ N m² kg⁻²\]
Acceleration due to Gravity (g) & its Variation
Fig 3 — Educational Diagram: Acceleration due to Gravity (g) & its Variation
Variation of Acceleration due to Gravity
Key Point: On surface: g = G M / R². At height h (h << R): g' = g (1 - 2h/R). At depth d: g' = g (1 - d/R).
Acceleration due to gravity on Earth's surface: g = G M_E / R_E², where M_E is Earth's mass and R_E is Earth's mean radius (~6371 km). Standard value of g = 9.8 m/s².
Variation with Altitude (Height h): g_h = G M_E / (R_E + h)² = g / (1 + h/R_E)². For small height h << R_E, expanding binomially gives g_h ≈ g (1 - 2h / R_E).
Variation with Depth (d): Assuming uniform Earth density ρ, g_d = g (1 - d / R_E). At the center of the Earth (d = R_E), g = 0.
Variation with Latitude (Rotation of Earth): Due to Earth's rotation at angular speed ω, effective g at latitude λ is g' = g - ω² R_E cos²λ. g is maximum at the poles (λ = 90°) and minimum at the equator (λ = 0°).
- At height h = R_E (equal to Earth radius), g' = g / 4 = 2.45 m/s².
- At depth d = R_E / 2 (halfway to Earth's center), g' = g / 2 = 4.9 m/s².
- At the center of Earth, acceleration due to gravity is exactly zero.
- \[g = G M_E / R_E²\]
- \[At height h: g_h = g / (1 + h/R_E)² ≈ g (1 - 2h/R_E) for h << R_E\]
- \[At depth d: g_d = g (1 - d/R_E)\]
- \[At latitude λ: g' = g - ω² R_E cos²λ\]
Gravitational Potential Energy & Potential
Fig 4 — Educational Diagram: Gravitational Potential Energy & Potential
Gravitational Potential & Potential Energy
Key Point: U(r) = - G M m / r (zero reference at r = ∞). Potential V(r) = - G M / r.
Gravitational Potential Energy (U): The work done in bringing a mass m from infinity to a distance r from a mass M under the action of gravitational force: U(r) = - G M m / r. The negative sign indicates that the gravitational force is attractive.
Gravitational Potential (V): The gravitational potential energy per unit mass at a point in space: V(r) = U(r) / m = - G M / r. SI unit: J/kg.
Relation with Gravitational Field (E): E = - dV/dr = - G M / r² r̂.
- Gravitational potential energy of a mass m on Earth's surface: U = - G M_E m / R_E = - m g R_E.
- Change in potential energy when moving mass m from surface to height h: ΔU = m g h / (1 + h/R_E) ≈ m g h for h << R_E.
- \[U(r) = - G M m / r\]
- \[V(r) = - G M / r\]
- \[ΔU = m g h / (1 + h/R_E)\]
Escape Speed & Earth Satellites
Fig 5 — Educational Diagram: Escape Speed & Earth Satellites
Escape Speed & Orbital Mechanics
Key Point: Escape velocity v_e = √(2 g R_E) ≈ 11.2 km/s. Orbital velocity v_o = √(g R_E) ≈ 7.92 km/s.
Escape Speed (v_e): The minimum speed required for a projectile to escape Earth's gravitational influence completely without further propulsion. By energy conservation: ½ m v_e² - G M_E m / R_E = 0 ⇒ v_e = √(2 G M_E / R_E) = √(2 g R_E). For Earth, v_e ≈ 11.2 km/s.
Orbital Speed of Satellite (v_o): For a satellite of mass m orbiting at radius r = R_E + h: Centripetal force = Gravitational force ⇒ m v_o² / r = G M_E m / r² ⇒ v_o = √(G M_E / r) = √[G M_E / (R_E + h)]. Near Earth's surface (h << R_E), v_o = √(g R_E) ≈ 7.92 km/s.
Time Period of Satellite (T): T = 2π r / v_o = 2π r^(3/2) / √(G M_E) = 2π √[(R_E + h)³ / (g R_E²)]. Near surface, T ≈ 84.6 minutes.
Energies of Orbiting Satellite:
- Kinetic Energy: K = ½ m v_o² = G M_E m / (2r)
- Potential Energy: U = - G M_E m / r
- Total Energy: E = K + U = - G M_E m / (2r)
- Binding Energy = - E = G M_E m / (2r)
Geostationary vs. Polar Satellites:
- Geostationary Satellite: Orbits in the equatorial plane from west to east with a time period T = 24 hours at an altitude h ≈ 35,800 km. Appears stationary relative to Earth; used for telecommunication and weather monitoring.
- Polar Satellite: Orbits in a north-south plane passing over the poles at lower altitude (h ≈ 500-800 km, T ≈ 100 min); used for remote sensing, environmental scanning, and military reconnaissance.
- Escape speed from Moon's surface is only ~2.38 km/s because Moon's mass and radius are smaller.
- A satellite at altitude 35,800 km has orbital period exactly equal to Earth's rotational period (24 hours), creating a geostationary orbit.
- Total mechanical energy of a bound satellite is always negative. If total energy becomes ≥ 0, the orbit becomes parabolic or hyperbolic and the object escapes.
- \[Escape velocity: v_e = √(2 G M_E / R_E) = √(2 g R_E) ≈ 11.2 km/s\]
- \[Orbital velocity: v_o = √(G M_E / r) = √[g R_E² / (R_E + h)]\]
- \[Time period: T = 2π √(r³ / (G M_E))\]
- \[Kinetic Energy K = G M_E m / (2r)\]
- \[Potential Energy U = - G M_E m / r\]
- \[Total Energy E = - G M_E m / (2r)\]
Related Laws & Principles
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